Answer:
My answer is not correct, do not read
A solid right pyramid has a square base with an edge length of x cm and a height of y cm.
A solid right pyramid has a square base with an edge length of x centimeters and a height of y centimeters.
Which expression represents the volume of the pyramid?
One-thirdxy cm3
One-thirdx2y cm3
One-halfxy2 cm3
One-halfx2y cm3
Answer:
B
Step-by-step explanation:
One-thirdx2y cm3 i got it right on edg
The volume of the pyramid with a square base of side x and height (y) is (1/3)x²y cm³
How to calculate volume?Volume is the amount of space occupied by a three dimensional shape or object.
The area of the square base = x cm * x cm = x² cm²
The volume of the pyramid = (1/3) * area of square base * height = (1/3) * x² * y = (1/3)x²y cm³
The volume of the pyramid with a square base of side x and height (y) is (1/3)x²y cm³
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a table cost 5 times as much as a chair. for $40000 a trader can buy 20 more chairs than tables. find the cost of a chair and number of tables.
Answer:
Chair is $1600
Table are 5 pieces
Step-by-step explanation:
Let the cost of a chair be x then for a table, it will be 5x since table cost 5 times as much as a chair.
For $40000, chairs alone will be 40000/x while tables will be 40000/5x=8000/x
The difference between these numbers is 20 hence
40000/x-8000/x=20
32000/x=20
X=32000/20=1600
The cost of a chair is $1600
Table will be 5*1600=$8000
The number bought will be proved as follows
Chairs=40000/1600=25 pieces
Tables=40000/8000=5 pieces
Difference in number is 25-5=20
The number of passengers on coaches travelling along 12 popular scenic routes are 29 42 45 39 36 41 38,37.43,35 and 40 find the mean numbres of passengers on coaches
A manufacturer of hard safety hats for construction workers is concerned about the mean and the variation of the forces its helmets transmit to wearers when subjected to a standard external force. The manufacturer desires the mean force transmitted by helmets to be 800 pounds (or less), well under the legal 1000-pound limit, and desires σ to be less than 40. Tests were run on a random sample of n = 40 helmets, and the sample mean and variance were found to be equal to 825 pounds and 2350 pounds2 , respectively.Construct a 95% confidence interval for the population variance.
Answer:
Step-by-step explanation:
Hello!
You need to construct a 95% CI for the population variance of the forces the safety helmets transmit to wearers.
The variable of interest is X: Force a helmet transmits its wearer when an external force is applied (pounds)
Assuming this variable has a normal distribution, the manufacturer expects it to have a mean of μ= 800 pounds and a standard deviation of σ= 40 pounds
A test sample of n=40 was taken and the resulting mean and variance are:
X[bar]= 825 pounds
S²= 2350 pounds²
To estimate the population variance per confidence interval you have to use the following statistic:
[tex]X^2= \frac{(n-1)S^2}{Sigma^2} ~~X^2_{n-1}[/tex]
And the CI is calculated as:
[[tex]\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}}[/tex];[tex]\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}}[/tex]]
[tex]X^2_{n-1;1-\alpha /2}= X^2_{39;0.975}= 58.1[/tex]
[tex]X^2_{n-1;\alpha /2}= X^2_{39;0.025}= 23.7[/tex]
[[tex]\frac{39*2350}{58.1}[/tex];[tex]\frac{39*2350}{23.7}[/tex]]
[1577.45; 3867.09] pounds²
Using a confidence level of 95% you'd expect that the interval [1577.45; 3867.09] pounds² contains the value of the population variance of the force the safety helmets transmit to their wearers when an external force is applied.
I hope this helps!
An agricultural researcher plants 25 plots with a new variety of yellow corn. Assume that the yield per acre for the new variety of yellow corn follows a Normal distribution with unknown mean LaTeX: \mu and standard deviation LaTeX: \sigma = 10 bushels per acre.Q: Which of the following would produce a confidence interval with a smaller margin of error than the 90% confidence interval?A) Plant only 5 plots rather than 25, because 5 are easier to manage and control.B) Plant 10 plots rather than 25, because a smaller sample size will result in a smaller margin of error.C) Compute a 99% confidence interval rather than a 90% confidence interval, because a higher confidence level will result in a smaller margin of error.D) Plant 100 plots rather than 25, because a larger sample size will result in a smaller margin of error.
Answer:
Correct Answer: CA larger sample size results in a smaller margin error, i.e. with a plant of 100 plots instead of 25, the margin error will be smaller.
Compute a 99% confidence interval rather than a 90% confidence interval, because a higher confidence level will result in a smaller margin of error
What is Statistics?Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.
An agricultural researcher plants 25 plots with a new variety of yellow corn.
Assume that the yield per acre for the new variety of yellow corn follows a Normal distribution with unknown mean and standard deviation of 10.
We need to find a confidence interval with a smaller margin of error than the 90% confidence interval
n=25, x=150,s=10,a=0.95
Unknown mean u means we use t table.
[tex]150 ± t_{0.975} \frac{10}{\sqrt{25}}[/tex]
150±[tex]t_{0.975}[/tex]×2
Compute a 99% confidence interval rather than a 90% confidence interval, because a higher confidence level will result in a smaller margin of error
Hence, option C is correct. Compute a 99% confidence interval rather than a 90% confidence interval, because a higher confidence level will result in a smaller margin of error
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The average annual inflation rate in the United States over the past 98 years is 3.37% and has a standard deviation of approximately 5% (Inflationdata). In 1980, the inflation rate was above 13%. If the annual inflation rate is normally distributed, what is the probability that inflation will be above 13% next year
Answer:
2.68% probability that inflation will be above 13% next year
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 3.37, \sigma = 5[/tex]
If the annual inflation rate is normally distributed, what is the probability that inflation will be above 13% next year
This is the pvalue of Z when X = 13. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{13 - 3.37}{5}[/tex]
[tex]Z = 1.93[/tex]
[tex]Z = 1.93[/tex] has a pvalue of 0.9732
1 - 0.9732 = 0.0268
2.68% probability that inflation will be above 13% next year
Answer:
[tex]P(X>13)=P(\frac{X-\mu}{\sigma}>\frac{13-\mu}{\sigma})=P(Z>\frac{13-3.37}{5})=P(Z>1.926)[/tex]
And we can find this probability using the complement rule and the normal standard distirbution table or excel:
[tex]P(Z>1.926)=1-P(Z<1.926)=1-0.9729=0.0271[/tex]
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the annual inflation of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(3.37,5)[/tex]
Where [tex]\mu=3.37[/tex] and [tex]\sigma=5[/tex]
We are interested on this probability
[tex]P(X>13)[/tex]
And the best way to solve this problem is using the normal standard distribution and the z score given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
If we apply this formula to our probability we got this:
[tex]P(X>13)=P(\frac{X-\mu}{\sigma}>\frac{13-\mu}{\sigma})=P(Z>\frac{13-3.37}{5})=P(Z>1.926)[/tex]
And we can find this probability using the complement rule and the normal standard distirbution table or excel:
[tex]P(Z>1.926)=1-P(Z<1.926)=1-0.9729=0.0271[/tex]
What is the area of a circular cardboard piece needed for the base of a model of a volcano that’s is 20 centimeters tall and has a volume of 960 cubic centimeters
Answer: 144 square centimeters
Answer:
the answer is 144 centimeters
A recent report estimated that 25% of all college students in the United States have a sexually transmitted disease (STD). Due to the demographics of the community, the director of the campus health center believes that the proportion of students who have a STD is lower at his college. He tests H0: p = 0.25 versus Ha: p < 0.25.
The campus health center staff select a random sample of 50 students and determine that 18% have been diagnosed with a STD.
a) Is the sample size condition for conducting a hypothesis test for a population proportion satisfied?
Answer:
The sample size condition for conducting a hypothesis test for a population proportion is satisfied for this question.
Step-by-step explanation:
a) The sample size condition for conducting a hypothesis test for a population proportion is satisfied is when
np > 5 and n(1 - p) > 5
n = sample size = 50
p = proportion that have STD = 18% = 0.18
np = 0.18 × 5 = 9 > 5
n(1 - p) = 0.82 × 50 = 41 > 5
Hope this Helps!!!
Answer:
Step-by-step explanation:
Given :
What is the probability of picking A-day that begins with the letter s
Answer:
28 or 29%
Step-by-step explanation:
There are 7 days total, 2 of which start with “S”, divide the 2 by 7 to get your percentage of 28-29%
The probability of picking a day that begins with the letter s is 2/7.
What is probability?It is the chance of an event to occur from a total number of outcomes.
The formula for probability is given as:
Probability = Number of required events / Total number of outcomes.
Example:
The probability of getting a head in tossing a coin.
P(H) = 1/2
We have,
There are seven days in a week, and two of them start with the letter s: Sunday and Saturday.
Now,
The probability of picking a day that begins with the letter s.
= 2/7
Or,
= 0.2857
Or,
= 0.2857 x 100%
= 28.57%.
Thus,
The probability of picking a day that begins with the letter s is 2/7.
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Which of the following are like radicals? Check all of the boxes that apply.
Answer:
3x√x²y, –12x√x²y, x√yx², 2√x²y. or on Edge is A,B,D,F
Step-by-step explanation:
Got 100% on edge...
You see that country B can make 60 units of X and no Y at point j, or it can make no X and 30 Y at point f. So, if country B decides to produce point j instead of point f (if can do any point f through j) where it gives up units of Y it gets back X, how many units of X does it gain for each unit of Y given up
Answer:
Country B gaines 2 units of good X , per unit of Good Y sacrifised.
Step-by-step explanation:
Country B's production possibilities in form of goods (X,Y) are :
Point J [Only good X] = (60,0) Pont F [Only good Y] = (0,30)The country can produce 60 units of good X or 30 units of good Y, by complete specialisation in either good & not producing the other good.
The country has more (twice) advantage in producing good X. As, it can produce 2 times more good X, than good Y, from the same available resources.
If it decides to produce at point J, production specialising in Good X: It will produce only good X, no units of Y. This implies that - it gains 2 units of good X per unit of good Y sacrifised, as per their production potential ratio (60:30)
Can someone please help me solve this
Answer:
30
Step-by-step explanation:
Everything has to add up to 90.
Add EVERYTHING together.
3x + 33
3x + 33 = 90
90 - 33 = 57
57 / 3 = 19
19 = x
19 x 2 = 38
38 - 8 = 30
Answer:
The answer for ∠CDF is 30°.
Step-by-step explanation:
It ia given that complemetary angle is 90° so we can make an expression in terms of x :
It ia given that complemetary angle is 90° so we can make an expression in terms of x :∠AFB + ∠BFC + ∠CFD = 90°
32° + (x+9)° + (2x-8)° = 90°
In order to find ∠CFD, we have to find the value of x first so we have to move all the like-terms to one side :
32° + x + 9° + 2x - 8° = 90°
2x + x = 90° - 32° - 9° + 8°
3x = 57°
Then divide both sides by 3 :
3x ÷ 3 = 57° ÷ 3
x = 19°
We have already found the value of x. Now, the question ask us to find ∠CDF, (2x-8)°. We just have to substitute x value into the expression :
Let x = 19,
∠CDF = 2x - 8
= 2(19) - 8
= 30°
2x + 3y = 12 is an equation in slope intercept form.
True
False
Which are solutions of the linear equation?
Select all that apply.
3x + y = 10
(1, 6)
(2, 4)
(3, 1)
(4, –1)
(5, –5)
The solutions of the linear equation are; (2, 4), (3, 1) and (5, –5)
What is a linear equation?A linear equation is an equation that has the variable of the highest power of 1. The standard form of a linear equation is of the form Ax + B = 0.
The given linear equation is;
3x + y = 10
For (1, 6)
3x + y = 10
y = 10 - 3x
y = 10 - 3(1)
y = 10 -3 = 7
So, this is not the solution of the linear equation.
For (2, 4)
y = 10 - 3x
y = 10 - 3(2)
y = 10 -6 = 4
So, this is the solution of the linear equation.
For (3, 1)
y = 10 - 3x
y = 10 - 3(3)
y = 10 -9 = 1
So, this is the solution of the linear equation.
For (4, –1)
y = 10 - 3x
y = 10 - 3(4)
y = 10 -12 = -2
So, this is not the solution of the linear equation.
For (5, –5)
y = 10 - 3x
y = 10 - 3(5)
y = 10 -15 = -5
So, this is the solution of the linear equation.
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{71.NS.6b and 18.NS.6c} The three points (4,0), (-6,0), and (-6,-4) form three corners of a rectangle. Determine the coordinates of the fourth point.
Answer:
(4,-4)
Step-by-step explanation:
Diagonals of a rectangle share a common midpoint
(4-6)/2 , (0-4)/2 = (-6+x)/2, (0+y)/2
-2 = -6 + x
x = 4
-4 = y
We determined the fourth point of a rectangle by ensuring that the sides of the rectangle are parallel to the axes and the sides are equal in length. The fourth point of the rectangle formed by the points (4,0), (-6,0), and (-6,-4) is (4,-4).
Explanation:The fourth point of the rectangle should have the same x-coordinate as the point (4,0) and the same y-coordinate as the point (-6,-4). Therefore, the fourth point is (4,-4)
To better understand the reasoning, let's consider the points on a plane. We recall that rectangles have sides of equal length and parallel to the axes. Therefore, since the line connecting (4,0) and (-6,0) is parallel to the x-axis, the fourth point's x-coordinate has to be the same as the point on the opposite side of the rectangle, which is 4. Similarly, as the line connecting (-6,0) and (-6,-4) is parallel to the y-axis, the fourth point's y-coordinate has to equal the y-coordinate of the point on the opposite side (-6,-4), which is -4. Hence, the fourth point is (4,-4).
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write 0.1 as a fraction in simpliest form
Answer:
1/1000
Step-by-step explanation:
Graph the line with slope 1 passing through the point (1,1)
Answer:
start at (0,0) and go up 1, right 1, and mark a point and keep doing that
Step-by-step explanation:
Consider the following time series data: Month 1 2 3 4 5 6 7 Value 23 14 20 11 19 24 15 (a) Compute MSE using the most recent value as the forecast for the next period. If required, round your answer to one decimal place. What is the forecast for month 8? If required, round your answer to one decimal place. Do not round intermediate calculation. (b) Compute MSE using the average of all the data available as the forecast for the next period. If required, round your answer to one decimal place. Do not round intermediate calculation. What is the forecast for month 8? If required, round your answer to one decimal place. (c) Which method appears to provide the better forecast?
Answer:
a) MSE = 61.33
Forecast for 8th month = 15
b) MSE = 34.51
Forecast for 8th month = 18
c) The average method provides a better forecast because of its low MSE
Explanation:
Check the attached file for the solvings.
To answer this two-part question, you'll need to calculate the mean square errors (MSE) using two different forecasting methods: using the most recent value as a forecast and using the average of all data for a forecast. The one with lower MSE is the correct prediction. The forecast for the next month is always based on the previous value or average value depending on the method.
Explanation:To answer this question, you need to understand how mean square error (MSE) and forecasting work. For (a), we use the last value as the forecast for the next value and compute MSE. For (b), we use the average of all data as the forecast for the next value and calculate the MSE. Finally, we compare which method gives a lower MSE, therefore better forecasting.
For (a), the forecast values would be the previous month's data, i.e., forecast for month 2 is 23, month 3 is 14 and so on. To calculate MSE, you subtract each monthly value from its forecast, square the result and find the average of these squares. The forecast for month 8 would be the value of month 7 which is 15.
For (b), you calculate the average of all the data available and use it as a forecast for all the next periods. The MSE and forecast for month 8 can be calculated in a similar manner as in (a).
In step (c), compare the MSE calculated in step (a) and step (b). A lower MSE indicates a better forecast and consequently represents an accurate choice for a predictive model.
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Multiple-choice questions on Advanced Placement exams have five options: A, B, C, D, and E. A random sample of the correct choice on 400 multiple-choice questions on a variety of AP exams1 shows that B was the most common correct choice, with 90 of the 400 questions having B as the answer. Does this provide evidence that B is more likely to be the correct choice than would be expected if all five options were equally likely? Show all details of the test. The data are available in APMultipleChoice.
Answer:
Option B is not the most common correct choice.
Step-by-step explanation:
The multiple-choice questions on Advanced Placement exams have five options: A, B, C, D, and E.
The probability that any of these five option is the correct answer is:
[tex]p=\frac{1}{5}=0.20[/tex]
A random sample of 400 multiple-choice questions on Advanced Placement exam are selected.
The results showed that 90 of the 400 questions having B as the answer.
To test the hypothesis that option B is more likely the correct answer for most question, the hypothesis can be defined as:
H₀: All the options are equally probable, i.e. p = 0.20.
Hₐ: Option B is more likely the correct option, i.e. p > 0.20.
Compute the sample proportion as follows:
[tex]\hat p=\frac{90}{400}=0.225[/tex]
The test statistic is:
[tex]z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.225-0.20}{\sqrt{\frac{0.20(1-0.20)}{400}}}= 1.25[/tex]
The test statistic is 1.25.
Decision rule:
If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
Compute the p-value as follows:
[tex]p-value=P(Z>1.25)\\=1-P(Z<1.25)\\=1-0.89435\\=0.10565\\\approx 0.1057[/tex]
*Use a z-table.
The p-value is 0.1057.
The p-value of the test is quite large. Thus, the null hypothesis was failed to rejected.
Hence, it can be concluded that option B is not the most common correct choice.
Testing the hypothesis, it is found that since the p-value of the test is of 0.1056 > 0.05, it does not provide evidence that B is more likely to be the correct choice than would be expected if all five options were equally likely.
At the null hypothesis, it is tested if all of them are equally as likely, that is, the proportion of B is [tex]p = \frac{1}{5} = 0.2[/tex]. Thus:
[tex]H_0: p = 0.2[/tex]
At the alternative hypothesis, it is tested if B is more likely, that is, if the proportion of B is more than 0.2. Thus:
[tex]H_1: p > 0.2[/tex]
The test statistic is given by:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
In which:
[tex]\overline{p}[/tex] is the sample proportion. p is the proportion tested at the null hypothesis. n is the sample size.In this problem, the parameters are: [tex]p = 0.2, n = 400, \overline{p} = \frac{90}{400} = 0.225[/tex].
The value of the test statistic is:
[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]z = \frac{0.225 - 0.2}{\sqrt{\frac{0.2(0.8)}{400}}}[/tex]
[tex]z = 1.25[/tex]
The p-value of the test is the probability of finding a sample proportion above 0.225, which is 1 subtracted by the p-value of z = 1.25.
Looking at the z-table, z = 1.25 has a p-value of 0.8944.
1 - 0.8944 = 0.1056.
Since the p-value of the test is of 0.1056 > 0.05, it does not provide evidence that B is more likely to be the correct choice than would be expected if all five options were equally likely.
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A random telephone survey of 1,091 adults (aged 18 and older) was conducted by an online tax preparation and e-filing service. The survey results showed that 634 of those surveyed planned to file their taxes electronically. (Round your answers to the nearest whole number.) (a) Develop a descriptive statistic that can be used to estimate the percentage of all taxpayers who file electronically. % (b) The survey reported that the most frequently used method for preparing the tax return is to hire an accountant or professional tax preparer. If 60% of the people surveyed had their tax return prepared this way, how many people used an accountant or professional tax preparer
Answer:
a. The percentage of all taxpayers who file electronically is 58%
b. 654 people used an accountant or professional tax preparer preparing the tax return
Step-by-step explanation:
According to the given data, in order to estimate the percentage of all taxpayers who file electronically, we would have to make the following calculation:
percentage of all taxpayers who file electronically=634×100%=0.58
1,091
Hence, the percentage of all taxpayers who file electronically is 58%
In order to calculate how many people used an accountant or professional tax preparer for preparing the tax return, we would have to make the following calculation:
people used an accountant or professional tax preparer= 60%×1,091=654
100%
654 people used an accountant or professional tax preparer preparing the tax return.
Based on the list, how many different-color pants does Megan have to choose from?
Answer:
Whats on the list?????
Step-by-step explanation:
Fast-food restaurants spend much time studying the amount of time cars spend in their drive-thrus. Certainly, the faster the cars get service, the more opportunity for making money. According to a recent study by QSR magazine, Wendy’s has the best time, with a mean time spent in the drive thru of 138.5 seconds. Assuming drive-thru time is normally distributed with a standard deviation of 29 seconds, what proportion of cars spends between 120 and 180 seconds in Wendy's drive-thru? Write answer as decimal rounded to the thousandth.
Answer:
0.663
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 138.5, \sigma = 29[/tex]
What proportion of cars spends between 120 and 180 seconds in Wendy's drive-thru?
This is the pvalue of Z when X = 180 subtracted by the pvalue of Z when X = 120. So
X = 180
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{180 - 138.5}{29}[/tex]
[tex]Z = 1.43[/tex]
[tex]Z = 1.43[/tex] has a pvalue of 0.924
X = 120
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{120 - 138.5}{29}[/tex]
[tex]Z = -0.64[/tex]
[tex]Z = -0.64[/tex] has a pvalue of 0.261
0.924 - 0.261 = 0.663
Final answer:
0.662 when rounded to three decimal places.
Explanation:
To determine the proportion of cars that spend between 120 and 180 seconds in Wendy's drive-thru, we can use the properties of the normal distribution. Given that the mean time is 138.5 seconds and the standard deviation is 29 seconds, we can calculate the corresponding z-scores for both 120 seconds and 180 seconds.
Firstly, calculate the z-score for 120 seconds:
z = (X - µ) / σ = (120 - 138.5) / 29 ≈ -0.6379.
Next, calculate the z-score for 180 seconds:
z = (X - µ) / σ = (180 - 138.5) / 29 ≈ 1.4310.
By looking up these z-scores in a standard normal distribution table, we find that:
P(Z < 1.4310) ≈ 0.9236
P(Z < -0.6379) ≈ 0.2616.
To find the proportion of times between 120 and 180 seconds, we subtract the smaller probability from the larger:
P(120 < X < 180) = P(Z < 1.4310) - P(Z < -0.6379) ≈ 0.9236 - 0.2616 = 0.6620.
Dan rolls 2 fair dice and adds the results from each.
Work out the probability of getting a total that is a factor of 15
Answer:
[tex]\frac{1}{6}[/tex]
Step-by-step explanation:
The factors of 15 are numbers that can divide even through 15 without any remainders.
These numbers are 1, 3, 5 and 15;
When we roll two fair dice once, there are about 36 possible out comes and this is the sample space of rolling this fair dice.
1 2 3 4 5 6
1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)
2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)
3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)
4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)
5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)
6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)
The total that will give a factor of 15;
(1, 2) (2, 3) (1, 4) (2, 1) (3, 2) (4, 1)
Out of the 36 possible outcomes, we have 6 whose sum will give a factor of 15;
Probability of this = [tex]\frac{6}{36}[/tex] = [tex]\frac{1}{6}[/tex]
Can someone please answer this question I am confused
Answer:
Step-by-step explanation:
Suppose we conduct a hypothesis test to determine if an exercise program helps people lose weight. We measure the weight of a random sample of participants before and after they complete the exercise program. The mean number of pounds lost for the sample turns out to be 7.9 lbs. The hypotheses for the test are: H0: The program is not effective for weight loss. Ha: The program is effective for weight loss. The P-value for the test turns out to be 0.012. Which of the following is the appropriate conclusion, assuming that all conditions for inference are met and the level of significance is 0.05? (i) We reject H0---this sample does not provide significant evidence that the program is effective. (ii) We reject H0---this sample provides significant evidence that the program is effective. (iii) We fail to reject H0---this sample provides significant evidence that the program is not effective. (iv) We fail to reject H0---this sample does not provide significant evidence that the program is effective.
Answer: (ii) We reject H0---this sample provides significant evidence that the program is effective.
Step-by-step explanation:
The null hypothesis is
The program is not effective for weight loss.
The alternative hypothesis is
The program is effective for weight loss.
If the P-value for the test turns out to be 0.012, and the level of significance is 0.05, then
Alpha, 0.05 > p value, 0.012
Therefore, there is enough evidence to reject the null hypothesis. We then accept the alternative hypothesis.
The correct option is
(ii) We reject H0---this sample provides significant evidence that the program is effective.
Use StatKey or other technology to generate a bootstrap distribution of sample proportions and find the standard error for that distribution. Compare the result to the standard error given by the Central Limit Theorem, using the sample proportion as an estimate of the population proportion p.
Proportion of peanuts in mixed nuts, with n=94 and P =0.52
Round your answer for the bootstrap SE to two decimal places, and your answer for the formula SE to three decimal places.
Answer:
0.0515
Step-by-step explanation:
By the central limit theorem
when n increase distribution when data follows normal
Standard Error, SE of P is
[tex]SE = \sqrt{\frac{p(1-p)}{n} }[/tex]
Bootstrap Standard Error = [tex]\sqrt{\frac{p(1-p)}{n} }[/tex]
where n = 94 and p = 0.52
hence,
SE of Bootstrap = [tex]\sqrt{\frac{0.52(1-0.52)}{94} }[/tex]
[tex]=\sqrt{\frac{0.2496}{94} }\\\\=0.0515[/tex]
SE and the SE of Bootstrap are the same
Cual es la diferencia entre circulo y circunferencia
Consider a hypothesis test to decide whether the mean annual consumption of beer in the nation's capital is less than the national mean. Answer the following questions.
1. "The mean annual consumption of beer in the nation's captial is less than the national mean and the result of the hypothesis test does not lead to the conclusion that the mean annual consumption of beer in the nation's capital is less than the national mean" is a:________
a. Correct decision
b. Type II error
c. Type I error
2. "The mean annual consumption of beer in the nation's captial is less than the national mean and the result of the sampling leads to the conclusion that the mean annul consumption of beer in the nation's capital is less than the national mean" is a:_________
a. Correct decision
b. Type II error
c. Type I error
3. "The mean annual consumption of beer in the nation's captial is less than the national mean but the result of the sampling does not lead to the conclusion that the mean annual consumption of beer in the nation's capital is less than the national mean" is a:________
4. Correct decision
b. Type II error
c. Type I error
d. "The mean annual consumption of beer in the nation's captial is not less than the national mean and the result of the sampling does not lead to the conclusion that the mean annual consumption of beer in the nation's capital is less than the national mean" is a:________
a. Correct decision
b. Type II error
c. Type I error
Answer:
Step-by-step explanation:
Type I error occurs when the null hypothesis is rejected even when it is true.
Type II error occurs when the null hypothesis is not rejected even when it is false.
The null hypothesis is
The mean annual consumption = the national mean
The alternative hypothesis is
The mean annual consumption < the national mean
1) it is a type II error because the null hypothesis was not rejected even when it is false
2) it is a correct decision because the decision corresponds to the outcome
3) it is also a type II error
d) it is a correct decision because the null hypothesis is accepted when it is true
By interpreting the various scenarios related to hypothesis testing, it is determined that scenarios 1 and 3 represent Type II errors, while scenarios 2 and 4 represent correct decisions. This shows an understanding of statistical hypothesis tests.
Explanation:This problem falls within the discipline of statistical hypothesis testing, a method used to make statistical decisions using data. In the context of this problem, the null hypothesis states that the mean annual consumption of beer in the nation's capital is not less than the national mean.
'The mean annual consumption of beer in the nation's capital is less than the national mean and the result of the hypothesis test does not lead to the conclusion that the mean annual consumption of beer in the nation's capital is less than the national mean' is a Type II error. This is because the reality is that the consumption in the nation's capital is indeed less, but the test results failed to conclude this.'The mean annual consumption of beer in the nation's capital is less than the national mean and the result of the sampling leads to the conclusion that the mean annul consumption of beer in the nation's capital is less than the national mean' is a correct decision. This is because the reality and the test conclusion are in agreement.'The mean annual consumption of beer in the nation's capital is less than the national mean but the result of the sampling does not lead to the conclusion that the mean annual consumption of beer in the nation's capital is less than the national mean' is a Type II error. Even though in reality the consumption in the nation's capital is less, the test results failed to detect it.'The mean annual consumption of beer in the nation's capital is not less than the national mean and the result of the sampling does not lead to the conclusion that the mean annual consumption of beer in the nation's capital is less than the national mean' is a correct decision. This is because both reality and test results agree that the nation's capital's consumption is not below the national mean.Learn more about statistical hypothesis testing here:https://brainly.com/question/34698067
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Factor 16p^4 - 24p^3.
Answer:
8p^3(2p - 3) is the factor
Step-by-step explanation:
The value of a gold coin picturing the head of the Roman Emperor Vespasian is increasing at the rate of 5% per year. If the coin is worth $105 now, what will it be worth in 11 years?
Answer:
255.75
Step-by-step explanation:
Answer:
$179.59
Step-by-step explanation:
Step 1 Write the exponential growth function for this situation.
y = a(1 + r)t Write the formula.
= 105(1 + 0.05)t Substitute 105 for a and 0.05 for r.
= 105(1.05)t Simplify.
Step 2 Find the value in 11 years.
y = 105(1.05)t Write the formula.
= 105(1.05)11 Substitute 11 for t.
≈ 179.59 Use a calculator and round to the nearest hundredth.