A small stock brokerage firm wants to determine the average daily sales (in dollars) of stocks to their clients.A sample of the sales for 36 days revealed average daily sales of $200,000. Assume that the standard deviation of the population is known to be $18,000.

a. Provide a 95% confidence interval estimate for the average daily sale.

b. Provide a 97% confidence interval estimate for the average daily sale.

Answer:

[tex]W(h)=0.0006h^3-20[/tex].

A Person who is 5 feet, 8 inches tall weighs about 168.7 lbs.

Step-by-step explanation:

We know the rate of change of weight W​ (in pounds) with respect to height h​ (in inches)

[tex]\frac{dW}{dh}=0.0018h^2[/tex]

This is a separable equation. A separable equation is a first-order differential equation in which the expression for [tex]\frac{dy}{dx}[/tex] can be factored as a function of x times a function of y. In other words, it can be written in the form

[tex]\frac{dy}{dx}=g(x)f(y)[/tex]

[tex]\frac{dW}{dh}=0.0018h^2\\\\dW=(0.0018h^2)dh\\\\\int dW=\int (0.0018h^2)dh\\\\W=0.0006h^3+C[/tex]

To find the value of C, we use W(80​) = 287.2 lbs

[tex]287.2=0.0006(80)^3+C\\0.0006\left(80\right)^3+C=287.2\\307.2+C=287.2\\307.2+C-307.2=287.2-307.2\\C=-20[/tex]

Thus,

[tex]W(h)=0.0006h^3-20[/tex]

Convert the 5 feet into inches

[tex]5 \:ft \:\frac{12 \:in}{1\:ft} = 60 \:in[/tex]

Add 60 in and 8 in, to find the total height of the person

h = 68 in

Substitute h = 68 in into [tex]W(h)=0.0006h^3-20[/tex] to find the weight:[tex]W(68)=0.0006(68)^3-20=168.7[/tex]

A Person who is 5 feet, 8 inches tall weighs about 168.7 lbs.

To find the weight function W(h) and the weight of a person who is 5 feet, 8 inches tall, we need to integrate the given rate of change formula and substitute the values into the equation.

To find the weight function W(h), we need to integrate the given rate of change formula dW/dh = 0.0018[tex]h^2[/tex].

Integrating both sides, we get:

∫ dW = ∫ 0.0018[tex]h^2[/tex] dh

Integrating, we have:

W(h) = 0.0018 * (1/3) * [tex]h^3[/tex] + C

To find the value of C, we use the given information W(80) = 287.2 pounds.

Substituting the values, we have:

287.2 = 0.0018 * (1/3) * [tex]80^3[/tex] + C

Simplifying the equation, we solve for C and find:

C = 287.2 - 0.0018 * (1/3) * [tex]80^3[/tex]

Now, we can write the weight function W(h) as:

W(h) = 0.0018 * (1/3) * [tex]h^3[/tex] + (287.2 - 0.0018 * (1/3) * [tex]80^3[/tex])

To find the weight of a person who is 5 feet, 8 inches tall, we need to convert the height to inches.

5 feet is equal to 60 inches, and 8 inches is 8 inches. So, the total height is 60 + 8 = 68 inches.

Substituting the value into the weight function, we have:

W(68) = 0.0018 * (1/3) * [tex]68^3[/tex] + (287.2 - 0.0018 * (1/3) * [tex]80^3[/tex])

Simplifying the equation, we find the weight of a person who is 5 feet, 8 inches tall.

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Answer:

7

Step-by-step explanation:

substitute 2 for x

3(2^2) - 5

3 * 4 - 5

12 - 5 = 7

Answer:

Step-by-step explanation:

7....

Answer:

0.622

Step-by-step explanation:

According to the question,

62.2% of the respondents from Hawaii said that they had exercised more than 30 minutes a day for 3 days out of the week.

So, value of the sample proportion of people from Hawaii who exercised for at least 30 minutes a day for 3 days in a week is given by,

[tex]\frac {62.2}{100}[/tex]

= 0.622  

Answer:

a)[tex]2 + 3 + 5 + 6 = 16[/tex]

b)[tex]8a + b-9[/tex]

c)[tex]8a - 28b + 15c[/tex]

Step-by-step explanation:

We are given the following in the question:

1. Equivalent expression

[tex]2 + 3 + 5 + 6[/tex]

Since all the terms are like terms, we can write,

[tex]2 + 3 + 5 + 6 = 16[/tex]

2. Sum of given expression

[tex](8a - 2b - 4) \text{ and } (3b - 5)\\ (8a - 2b - 4) + (3b -5)\\= 8a -2b -4 + 3b -5\\\text{Collecting the like terms}\\8a + (-2b+3b) + (-4-5)\\= 8a + b-9[/tex]

3. Standard form of the expression

[tex]4(2a) + 7(-4b) + (3 \times c \times 5)\\=(8a) + (-28b) + (15c)\\=8a - 28b + 15c[/tex]

which is the required standard form of the given expression.

Answer:

12920

Step-by-step explanation :

distance covered = d =  ∫[tex]\int\limits^a_b ({sqrt{f'(t)^{2} +g'(t)^2\\}}) \, dt[/tex]

a = t = 20

b = t = 0

f'(t) = 646 : f'(t)² = 417316

g'(t) = 5 : g'(t)² = 25

d = [tex]\int\limits^a_b {646} \, dt[/tex]

t = 20 &  t = 0

d = 646t

d = 646*20 = 12920

The problem is about calculating distance based on movement rates represented by mathematical functions in an imaginary game. This is done by integrating the given functions over the stipulated time period and then summing the distances covered in each direction.

In this mathematical scenario where you and your best friend Janine are functions, you are given an identity f(t)=(t2+10)323 which represents your East/West movement, and Janine's identity is given by g(t)=5t which represents North/South movement. To calculate the units of distance you two cover between t=0 to t=20, we need to integrate the rate of movement of each function over that time period.

Step 1: Integrate your function f(t) from t=0 to t=20. This will give the total distance you moved in the East/West direction.

f(t) = ∫(0 to 20) (t2+10)323 dt

Step 2: Integrate Janine's function g(t) from t=0 to t=20. This will give the total distance Janine moved in the North/South direction.

g(t) = ∫(0 to 20) 5t dt

Step 3: The total distance covered will then be the summation of the distances covered in each direction, as calculated above.

Remember, these are integrations because the functions f(t) and g(t) represents the rate of movement (velocity), and integrating velocity over time gives distance.

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Answer:

.Option A

Step-by-step explanation:

Given that an instructor was interested in seeing if there was a difference in the average amount of time that men and women anticipate studying for an Introduction to Statistics course in the summer.

Minitab results are

[tex]Difference = mu (F) - mu (M)\\T-Test of difference = 0 (vs not =): T-Value = 0.23 \\P-Value = 0.817 \\DF = 46[/tex]

Since p value >0.05 our alpha significant level we accept null hypothesis that

difference in means =0

With a p-value of 0.817, that there is no statistically significant evidence of a difference in average anticipated amount of time studying between the men and women

.Option A

The 99% confidence interval for the percentage of girls born using this method is 86.7% - 93.3%.

Step-by-step calculation:

1. Calculate the sample proportion of girls:

Divide the number of girls by the total number of babies:

Sample proportion ([tex]\hat p[/tex]) = 270 girls / 300 babies = 0.9

2. Determine the z-score for a 99% confidence level:

Using a z-score table or calculator, find the z-score that corresponds to a 99% confidence level. This value is approximately 2.576.

3. Calculate the margin of error:

Margin of error (E) = z-score × [tex]\sqrt {(\hat p(1 - \hat p) / n)[/tex]

E = 2.576×√(0.9 × 0.1 / 300) ≈ 0.033

4. Construct the confidence interval:

Lower limit = [tex]\hat p[/tex] - E = 0.9 - 0.033 = 0.867

Upper limit = [tex]\hat p[/tex] + E = 0.9 + 0.033 = 0.933

5. Interpretation:

We are 99% confident that the true proportion of girls born using this method lies between 86.7% and 93.3%.

6. While the upper limit suggests a potential increase in girls, the confidence interval remains wide, and further studies are needed for a conclusive effectiveness claim.

The tetrahedron passes through the intercepts (5, 0, 0), (0, 2, 0), and (0, 0, 10). Parameterize the surface (call it [tex]\Sigma[/tex]) by

[tex]\vec r(u,v)=(1-v)\langle5,0,0\rangle+v\left((1-u)\langle0,2,0\rangle+u\langle0,0,10\rangle\right)[/tex]

[tex]\vec r(u,v)=\langle5(1-v),2(1-u)v,10uv\rangle[/tex]

with [tex]0\le u\le1[/tex] and [tex]0\le v\le1[/tex]. Take the normal vector to [tex]\Sigma[/tex] to be

[tex]\vec r_v\times\vec r_u=\langle20v,50v,10v\rangle[/tex]

Then the flux of [tex]\vec F(x,y,z)=\langle x,y,z\rangle[/tex] across [tex]\Sigma[/tex] is

[tex]\displaystyle\iint_\Sigma\vec F\cdot\mathrm d\vec S=\int_0^1\int_0^1\langle5(1-v),2(1-u)v,10uv\rangle\cdot\langle20v,50v,10v\rangle\,\mathrm du\,\mathrm dv[/tex]

[tex]=\displaystyle\int_0^1\int_0^1100v\,\mathrm du\,\mathrm dv=\boxed{50}[/tex]

Answer: the equation is

4x^2 + 4x - 12

Step-by-step explanation:

A quadratic equation is an equation in which the highest power of the unknown is 2.

The general form of a quadratic equation is expressed as

ax^2 + bx + c

Where

a is the leading coefficient

c is a constant

Assuming we want to write the quadratic equation in x, from the information given, the roots which are given are -2 and 1 and the leading coefficient is 4.

Therefore, the linear factors of the quadratic equation will be (x+2) and (x-1)

the equation becomes

(x+2)(x-1)

= x^2 - x +2x - 3

= x^2 + x - 3

Given a leading coefficient of 4, we will multiply the quadratic expression by 4. It becomes

4(x^2 + x - 3)

= 4x^2 + 4x - 12

Final answer:

The quadratic equation with roots -2 and 1 and a leading coefficient of 4 is 4x^2 - 12x + 8 = 0.

Explanation:

To write a quadratic equation with roots -2 and 1 and a leading coefficient of 4, we need to use the fact that if α and β are roots of a quadratic equation, then the equation can be expressed in the form:

a(x - α)(x - β) = 0

Here, α is -2 and β is 1, and the leading coefficient, a, is 4. Therefore, we can write:

4(x + 2)(x - 1) = 0

Multiplying it out, we have:

4(x2 - 1x - 2x + 2) = 0

Combining like terms, we get:

4x2 - 12x + 8 = 0, which is the desired quadratic equation.

Answer:

195 mm

Step-by-step explanation:

There are 10 mm in one cm. This is due to metric prefix rules

Answer: We can conclude that the average containers are mislabelled.

Step-by-step explanation:

From the question, the significant level of 0.01 or 1% given is less than 0.05 or 5%. So we say it is significant.

Answer:

Step-by-step explanation:

Hello!

You want to test two samples of batteries to see is the mean voltage of these battery types are different.

Sample 1 (type K)

n₁= 37

sample mean x₁[bar]= 8.54

standard deviation S₁= 0.225

Sample 2 (Type Q)

n₂= 58

sample mean x₂[bar]= 8.69

standard deviation S₂= 0.725

1. The test hypothesis are:

H₀: μ₁ = μ₂

H₁: μ₁ ≠ μ₂

2. I'll apply the Central Limit Theorem and approximate the distribution of the sample means to normal so that I can use an approximate Z statistic for this test.

Z: (x₁[bar] - x₂[bar]) - (μ₁ - μ₂) ≈ N(0;1)

        √ (S₁²/n₁) + (S₂²/n₂)

[tex]Z_{H0}[/tex]= (8.54 - 8.69) / [√ (0.225²/37) + (0.725²/58)]

[tex]Z_{H0}[/tex]= -1.468 ≅ -1.47

3. This is a two tailed test, so you'll have two critical values

[tex]Z_{\alpha/2} = Z_{0.025} = - 1.96[/tex]

[tex]Z_{1 - \alpha/2} = Z_{0.975} = 1.96[/tex]

You'll reject the null hypothesis if [tex]Z_{H0}[/tex] ≤ -1.96 or if [tex]Z_{H0}[/tex] ≥ 1.96

You'll not reject the null hypothesis if -1.96 < [tex]Z_{H0}[/tex] < 1.96

4.

Since the value [tex]Z_{H0}[/tex] = -1.47 is in the acceptance region, the decision is to not reject the null hypothesis.

I hope it helps!

Answer:

Step-by-step explanation:

Answer:

a) 8.5

b) between 7.7 and 9.3.

c)Both using a sample of size 400 (instead of 81) and using a 90% level of confidence (instead of 95%) are correct.

(e) 144

Step-by-step explanation:

Explanation for a)

The point estimate for the population mean μ is the sample mean, x ¯ . In this case, to estimate the mean number of weekly hours of home-computer use among the population of U.S. adults, we used the sample mean obtained from the sample, therefore x ¯ = 8.5.

Explanation for b)

The 95% confidence interval for the mean, μ, is x ¯ ± 2 ⋅ σ n = 8.5 ± 2 ⋅ 3.6 81 = 8.5 ± . 8 = ( 7.7 , 9.3 ) .

Explanation for c)

In general, a more concise (narrower) confidence interval can be achieved in one of two ways: sacrificing on the level of confidence (i.e. selecting a lower level of confidence) or increasing the sample size

Explanation for d)

We would like our confidence interval to be a 95% confidence interval (implying that z* = 2) and the confidence interval length should be 1.2, therefore the margin of error (m) = 1.2 / 2 = .6. The sample size we need in order to obtain this is: 144.

There are 125,970 ways to select the players who will travel to an away game. There are 79,833,600 ways to select the starting line-up. With a restriction on the center position, there are 12 ways to select the starting line-up.

(a) The coach must select 12 players to travel to an away game:

There are 20 members on the basketball team, and the coach needs to select 12 players to travel. This is a combination problem, since the order doesn't matter. The formula for calculating combinations is: nCr = n! / (r! * (n-r)!), where n is the total number of players and r is the number of players to be selected.

Using this formula, we can calculate the number of ways to select the traveling players: 20C12 = 20! / (12! * (20-12)!) = 125,970 ways.

(b) The coach must select her starting line-up:

There are 12 players who will travel, and the coach needs to select 5 players for the starting line-up. This is a permutation problem, since the order does matter. The formula for calculating permutations is: nPr = n! / (n-r)!, where n is the total number of players and r is the number of players to be selected.

Using this formula, we can calculate the number of ways to select the starting line-up: 12P5 = 12! / (12-5)! = 12! / 7! =  79,833,600 ways.

(c) The coach must select her starting line-up, with a restriction on the center position:

There are 12 players who will travel, and only 3 players who can play center. The remaining 4 positions have no restrictions. We can calculate the number of ways to select the starting line-up by first selecting the center player (3 ways), and then selecting the players for the other positions (4P4 = 4 ways).

Therefore, the total number of ways to select the starting line-up with the restriction on the center position is: 3 * 4 = 12 ways.

[tex]f(x)=e^{x^2+2x}\implies f'(x)=2(x+1)e^{x^2+2x}[/tex]

[tex]f[/tex] has critical points where the derivative is 0:

[tex]2(x+1)e^{x^2+2x}=0\implies x+1=0\implies x=-1[/tex]

The second derivative is

[tex]f''(x)=2e^{x^2+2x}+4(x+1)^2e^{x^2+2x}=2(2x^2+4x+3)e^{x^2+2x}[/tex]

and [tex]f''(-1)=\frac2e>0[/tex], which indicates a local minimum at [tex]x=-1[/tex] with a value of [tex]f(-1)=\frac1e[/tex].

At the endpoints of [-2, 2], we have [tex]f(-2)=1[/tex] and [tex]f(2)=e^8[/tex], so that [tex]f[/tex] has an absolute minimum of [tex]\frac1e[/tex] and an absolute maximum of [tex]e^8[/tex] on [-2, 2].

So we have

[tex]\dfrac1e\le f(x)\le e^8[/tex]

[tex]\implies\displaystyle\int_{-2}^2\frac{\mathrm dx}e\le\int_{-2}^2f(x)\,\mathrm dx\le\int_{-2}^2e^8\,\mathrm dx[/tex]

[tex]\implies\boxed{\displaystyle\frac4e\le\int_{-2}^2f(x)\,\mathrm dx\le4e^8}[/tex]

Answer:

6 times we need to transmit the message over this unreliable channel so that with probability 63/64.

Step-by-step explanation:

Consider the provided information.

Let x is the number of times massage received.

It is given that the probability of successfully is 1/2.

Thus p = 1/2 and q = 1/2

We want the number of times do we need to transmit the message over this unreliable channel so that with probability 63/64 the message is received at least once.

According to the binomial distribution:

[tex]P(X=x)=\frac{n!}{r!(n-r)!}p^rq^{n-r}[/tex]

We want message is received at least once. This can be written as:

[tex]P(X\geq 1)=1-P(x=0)[/tex]

The probability of at least once is given as 63/64 we need to find the number of times we need to send the massage.

[tex]\frac{63}{64}=1-\frac{n!}{0!(n-0)!}\frac{1}{2}^0\frac{1}{2}^{n-0}[/tex]

[tex]\frac{63}{64}=1-\frac{n!}{n!}\frac{1}{2}^{n}[/tex]

[tex]\frac{63}{64}=1-\frac{1}{2}^{n}[/tex]

[tex]\frac{1}{2}^{n}=1-\frac{63}{64}[/tex]

[tex]\frac{1}{2}^{n}=\frac{1}{64}[/tex]

By comparing the value number we find that the value of n should be 6.

Hence, 6 times we need to transmit the message over this unreliable channel so that with probability 63/64.

Answer:

A. AAS

Step-by-step explanation:

The vertical angles are congruent, the adjacent marked angles are congruent, and the marked sides on the far side of both angles are congruent. This geometry matches the conditions for Angle-Angle-Side (AAS) congruence.

The distance from earth to sun is 91,673,351.94 miles  

Given that the earth, moon, and sun form a right triangle shown in figure

The figure is attached below

Point A represents moon

Point B represents sun

Point C represents earth

The right angle is the angle at the moon. This is represented by point A in right angle triangle

Given that angle at earth is 89.85 degree

Angle BCA = 89.85 degree

Distance between earth and moon = AC = 240,000 miles

Since, Right angled triangle is formed we can use trigonometric identities

[tex]\cos \theta=\frac{B a s e}{\text {Hypotenuse}}[/tex]

The angle θ means angle created on earth

i.e. angle BCA = θ = 89.85 degree

[tex]\cos \left(89.85^{\circ}\right)=\frac{A C}{B C}[/tex]

Let BC = d, which is the distance between Earth and the sun

[tex]\mathrm{D}=\frac{240,000}{\cos (89.85)}=91,673,351.94 \mathrm{miles}[/tex]

So the distance from earth to sun is 91,673,351.94 miles  

To estimate the distance from the Earth to the Sun when the Moon is exactly half full and the Earth, Moon, and Sun form a right triangle, we can use the concept of similar triangles. By setting up a proportion and using the tangent function, we can calculate that the estimated distance is approximately 243,480,000 miles.

To estimate the distance from the Earth to the Sun, we can use the concept of similar triangles. When the Moon is exactly half full, the Earth, Moon, and Sun form a right triangle, with the right angle at the Moon. We know that the angle formed by the Sun, Earth, and Moon is 89.85 degrees.

We can use this information to set up a proportion between the distance from the Earth to the Moon and the distance from the Earth to the Sun. Let x be the distance from the Earth to the Sun. We can use the tangent function to find x:

Tan(89.85) = (240,000 miles) / x

Solving for x, we get:

x = (240,000 miles) / Tan(89.85)

Using a calculator, we find that x is approximately 243,480,000 miles.

Answer:

0.08x + 0.09y = 1700,     where x is the amount that has 8% interest

                                               y is the amount that has 9% interest

                              -------equation (1)

x+y = 19000

x = 19000 - y ,         -------equation   (2)

substitute (2) into (1):

0.08(19000 - y) + 0.09y = 1700

1520-0.08y+0.09y = 1700

so, y = 18000

x = 19000-y=1000

(1000,   18000) is the answer    

Just to let you know I’m in 7th grade

The problem can be solved by creating a system of linear equations that represent the conditions given in the problem. Solve this system of equations to determine the amounts invested in each of the two accounts.

This is a problem of algebra, specifically a type of word problem called a system of linear equations. You have a total of $19,000 invested across two accounts. Let's denote the amount invested at 5% as x and the amount invested at 9% as y. So, we can write two equations:

The next step is to solve this system of equations. Multiply the first equation by 0.05 (so it matches 5% in the second equation), then subtract the resulting equation from the second equation to eliminate x. By doing this, you find the value for y (money in the 9% account). Once you have the value for y, you can substitute it into the first equation to find the value for x (money in the 5% account).

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Answer:

the lower value of the interval = 35.26

Step-by-step explanation:

The mean number is u = 40.1

n = 16

the mean number called x is 38.1

the standard deviation = 5.8

given a 95% Confidence Interval

The lower value of the confidence interval is?

solution

There is a infinite population and the standard deviation of the population is known,

the below formula is used for determining an estimate of the confidence limits of the population mean, i.e.

x ± ( zₐσ)/ √n

For a 95% confidence level, the value of za is taken from the confidence interval table = 1.96.

the confidence limits of the population=

x ± ( zₐσ)/ √n

38.1 ± (1.96*5.8)/ √16

38.1 ± 11.368/4

38.1 ± 2.842

40.942 or 35.258

 Thus, the 95% confidence limits are 40.942 or 35.258

this prediction is made with confidence that it will be correct nine five times out of 100.

finally, the lower value of the interval = 35.26

Answer:

In think the answer is 42,000

Step-by-step explanation:

Final answer:

To determine how many people will be drinking Coke in Turlock five weeks from now, multiply the percentage of Coke drinkers (60%) by the town's population (70,000). This gives us 0.60 * 70,000 = 42,000 people drinking Coke.

Explanation:

The question involves a numerical problem where we have to determine how many people will be drinking Coke in Turlock five weeks from now if the current population is 70,000 and 60% of them drink Coke. To find the answer, we simply need to calculate 60% of 70,000.

Calculation steps:

Convert 60% to a decimal by dividing 60 by 100, which gives us 0.60

Multiply 0.60 by the total population of Turlock, which is 70,000

The calculation will be 0.60 * 70,000

Now, let's do the calculation:

0.60 * 70,000 = 42,000

Therefore, if the population of Turlock stays constant at 70,000 and the cola drinking habits remain the same, approximately 42,000 people will be drinking Coke five weeks from now.

Answer:

The sides of the container should be 3 cm and height should be 6 cm to minimize the cost

Step-by-step explanation:

Data provided in the question:

costs  for the material used on the side = $3/cm²

costs for the material used for the top lid and the base = $6/cm²

Volume of the container = 54 cm³

Now,

let the side of the base be 'x' and the height of the box be 'y'

Thus,

x × x × y = 54 cm³

or

x²y = 54

or

y = [tex]\frac{54}{x^2}[/tex]  ............(1)

Now,

The total cost of material, C

C = $3 × ( 4 side area of the box ) + $6 × (Area of the top and bottom)

or

C = ( $3 × 4xy ) + ( $6 × (x²)  )

substituting the value of y in the above equation, we get

C = [tex]3x\times4\times\frac{54}{x^2}+2\times6x^2[/tex]

or

C = [tex]\frac{648}{x}+12x^2[/tex]

Differentiating with respect to x and putting it equals to zero to find the point of maxima of minima

thus,

C' = [tex]-\frac{648}{x^2}+2\times12x[/tex] = 0

or

[tex]2\times12x=\frac{648}{x^2}[/tex]

or

24x³ = 648

or

x = 3 cm

also,

C'' = [tex]+\frac{2\times648}{x^3}+2\times12[/tex]

or

C''(3) = [tex]+\frac{2\times648}{3^3}+2\times12[/tex] > 0

Hence,

x = 3 cm is point of minima

Therefore,

y = [tex]\frac{54}{x^2}[/tex]               [from 1]

or

y = [tex]\frac{54}{3^2}[/tex]

or

y = 6 cm

Hence,

The sides of the container should be 3 cm and height should be 6 cm to minimize the cost

Answer:

(A) 0.4196

(B) 0.2398

(C) 0.0020

Step-by-step explanation:

Given,

Total songs = 15,

Liked songs = 6,

So, not liked songs = 15 - 6 = 9

If any 5 songs are played,

Then the total number of ways =  [tex]^{15}C_5[/tex]

(A) Number of ways of choosing 2 liked songs = [tex]^6C_2\times ^9C_3[/tex]

Since,

[tex]\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}[/tex]

Thus, the probability of choosing 3 females and 2 males = [tex]\frac{ ^6C_2\times ^9C_3}{^{15}C_5}[/tex]

[tex]=\frac{\frac{6!}{2!4!}\times \frac{9!}{3!6!}}{\frac{15!}{10!5!}}[/tex]

= 0.4196

Similarly,

(B)

The probability of choosing 3 liked songs = [tex]\frac{ ^6C_3\times ^9C_2}{^{15}C_5}[/tex]

[tex]=\frac{\frac{6!}{3!3!}\times \frac{9!}{2!7!}}{\frac{15!}{10!5!}}[/tex]

= 0.2398

(C)

The probability of choosing 5 liked songs = [tex]\frac{ ^6C_5\times ^9C_0}{^{15}C_5}[/tex]

[tex]=\frac{\frac{6!}{5!1!}}{\frac{15!}{5!10!}}[/tex]

≈ 0.0020

Answer:

Remember, if [tex]\{x_1,x_2,...,x_k\}[/tex] is a basis for a subspace W of [tex]\mathbb{R}^n[/tex] then [tex]\{q_1,q_2,...,q_k\}[/tex] is an orthonormal basis of W, where

[tex]q_i=\frac{1}{||v_i||}[/tex] and [tex]v_i[/tex] is defined as:

[tex]v_1=x_1\\v_2=x_2-\frac{v_1\cdot x_2}{v_1\cdot v_1}v_1\\v_k=x_k-\frac{v_1\cdot x_k}{v_1\cdot v_1}v_1 - \cdots - \frac{v_{k-1}\cdot x_k}{v_{k-1}\cdot v_{k-1}}v_{k-1}[/tex]

Then, to find a orthonormal basis of [tex]\{x_1=(8, -6, 0), x_2=(5, 1, 0), x_3=(0, 0, 2)\}[/tex] we will find first the [tex]v_i[/tex]'s.

[tex]v_1=x_1[/tex]

[tex]v_2=x_2-\frac{v_1\cdot x_2}{v_1\cdot v_1}v_1=(5,1,0)-\frac{(8,-6,0)\cdot (5,1,0)}{(8,-6,0)\cdot (8,-6,0)}(8,-6,0)=\\=(5,1,0)-\frac{17}{50}(8,-6,0)=(\frac{57}{25},\frac{76}{25},0)[/tex]

[tex]v_3=x_3-\frac{v_1\cdot x_3}{v_1\cdot v_1}v_1-\frac{v_2\cdot x_3}{v_2\cdot v_2}v_2=\\=(0,0,2)-\frac{(8-6,0)\cdot (0,0,2)}{(8,-6,0)\cdot (8,-6,0)}(8,-6,0) -\frac{(\frac{57}{25},\frac{76}{25},0)\cdot (0,0,2)}{(\frac{57}{25},\frac{76}{25},0)\cdot (\frac{57}{25},\frac{76}{25},0)}(\frac{57}{25},\frac{76}{25},0)=\\=(0,0,2)-0-0=\\=(0,0,2)[/tex]

Therefore, [tex]\{v_1=(8,-6,0),v_2=(\frac{57}{25},\frac{76}{25},0),v_3=(0,0,2)\}[/tex] is a ortogonal basis for [tex]\mathbb{R}^3[/tex]. But we need a orthonormal basis. Then is enough find the corresponding unit vector of the ortogonal basis found.

[tex]q_1=\frac{1}{||v_1||}v_1=\frac{1}{\sqrt{100}}(8,-6,0)\\q_2=\frac{1}{||v_2||}v_2=\frac{1}{\frac{19}{5}}(\frac{57}{25},\frac{76}{25},0)=\frac{5}{19}(\frac{57}{25},\frac{76}{25},0)\\q_3=\frac{1}{||v_3||}v_3=\frac{1}{2}(0,0,2)[/tex]

Hence

[tex]\{q_1=({\frac{8}{\sqrt{100}},\frac{-6}{\sqrt{100}},0), q_2=(\frac{3}{5},\frac{4}{5},0), q_3=(0,0,1)\}[/tex] is a orthonormal basis for [tex]\mathbb{R}^3[/tex]

Final answer:

To transform the given basis B into an orthonormal basis using the Gram-Schmidt orthonormalization process, we can follow the steps outlined.

Explanation:

To apply the Gram-Schmidt orthonormalization process to the given basis B = {(8, −6, 0), (5, 1, 0), (0, 0, 2)} in Rn, we'll follow these steps:

By applying this process to B, we find that U1 is (8/10, -6/10, 0), U2 is (1/2, 7/10, 0), and U3 is (0, 0, 2/√10).

Answer:

Step-by-step explanation:

a. The tangent of the central angle is the ratio ...

  tan(θ) = (2.423 km)/(0.942 km) . . . . . definition of tangent

  θ = arctan(2.423/.942) ≈ 1.200 radians

__

b. The length of the arc is ...

  s = rθ = (2.6 km)(1.2 radians) = 3.12 km

_____

The attached output from a graphics program shows the angle as 68.76°. Multiplying by π/180°, we can convert that to radians:

  θ = 68.76π/180 = 216.0/180 = 1.200 radians

To solve this, we use trigonometry and the relationships between parts of a circle. The angle subtended at the center of the trail by Natalie's path is 0.966 radians. The distance Natalie has skied since starting is 2.512 km.

The subject of this question is Mathematics, specifically Trigonometry, which deals with angles, lengths, and relationships in triangles. With a radius of 2.6 km, as Natalie moves along the circular ski trail, she traces out an arc and subtends an angle at the center of the circle.

(a) To find the angle she's covered in radians: consider the endpoint of her path which forms a triangle with the center of the circle and the initial position (3-o'clock). The angle she's subtended can be found using trigonometry (inverse tangent). The tangent of the angle equals the vertical component (2.423 km) divided by the horizontal component (2.6 km - 0.942 km). Giving us:
Angle in radians = tan-inverse of (2.423/1.658) = 0.966 radians.

(b) The distance she's covered along the circumference of the trail is the length of the arc she has skied, given by:
Arc length = radius * angle (in radians).
So, Distance covered = 2.6 km * 0.966 = 2.512 km.

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The null hypothesis is that the population mean is equal to or less than 76, while the alternative hypothesis is that it is greater than 76. The standardized test statistic is 2.089, and the P-value is approximately 0.022. Therefore, we reject the null hypothesis and conclude that there is enough evidence to support the claim.

The null hypothesis, denoted as H0, states that the population mean (mu) is equal to or less than 76. The alternative hypothesis, denoted as H1, states that the population mean (mu) is greater than 76. To test the claim, we can perform a one-sample t-test.

The standardized test statistic, also known as the t-value, can be calculated using the formula t = (x - mu) / (s / sqrt(n)), where x is the sample mean, mu is the population mean under the null hypothesis, s is the sample standard deviation, and n is the sample size. Plugging in the values x = 77.5, mu = 76, s = 3.3, and n = 29 into the formula gives us a t-value of 2.089 (rounded to two decimal places).

The P-value of the test statistic can be determined by comparing the t-value to the critical value of the t-distribution with (n - 1) degrees of freedom at the given level of significance (alpha). Since the alternative hypothesis is one-sided (mu > 76), we need to find the right-tail area of the t-distribution. Consulting a t-table or using statistical software, we find that the P-value is approximately 0.022 (rounded to three decimal places).

To make a decision, we compare the P-value to the significance level (alpha). If the P-value is less than alpha, we reject the null hypothesis. In this case, the P-value is 0.022, which is less than alpha = 0.01. Therefore, we reject the null hypothesis and conclude that there is enough evidence to support the claim that the population mean (mu) is greater than 76.

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The null and alternative hypotheses can be set, and the t-value can be calculated using the provided sample statistics. The P-value and the decision to reject or fail to reject the null hypothesis cannot be determined without further calculations.

The null and alternative hypotheses can be defined as follows:

The standardized test statistic (t-value) can be calculated using the formula:

t = (x - mu) / (s / sqrt(n))

Using the given sample statistics:

t = (77.5 - 76) / (3.3 / sqrt(29)) = 1.69 (rounded to two decimal places)

The P-value for the test statistic can be found using a t-distribution table or a statistical software. The P-value represents the probability of obtaining a t-value as extreme as the calculated one, assuming the null hypothesis is true. Since the P-value is not provided in the question, it cannot be determined without further calculations.

To decide whether to reject or fail to reject the null hypothesis, compare the P-value to the significance level (alpha). If the P-value is less than alpha, reject the null hypothesis. If the P-value is greater than or equal to alpha, fail to reject the null hypothesis.

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Answer:

the anwser is c

Step-by-step explanation:

Answer:

The correct answer is A

Step-by-step explanation:

A) CA because corresponding parts of congruent triangles are congruent.

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

Answer:

a) [tex]df_{num}=k-1=5-1=4[/tex]

b) [tex]df_{den}=N-k=77-5=72[/tex]

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have [tex]p[/tex] groups and on each group from [tex]j=1,\dots,p[/tex] we have [tex]n_j[/tex] individuals on each group we can define the following formulas of variation:  

[tex]SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2 [/tex]

[tex]SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2 [/tex]

[tex]SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2 [/tex]

And we have this property

[tex]SST=SS_{between}+SS_{within}[/tex]

The degrees for the numerator are [tex]df_{num}=k-1=5-1=4[/tex], where k represent the number of groups on this case k =5.

The degrees for the denominator are [tex]df_{den}=N-k=77-5=72[/tex], where N represent the total number of people N=17+15+16+18+11=77.

And the total degrees of freedom are given by: [tex]df_{tot}=df_{num}+df_{den}=N-1=4+72=76[/tex]

Final answer:

The degrees of freedom for the F-statistic in a one-way ANOVA with five populations and sample sizes of 17, 15, 16, 18, and 11 are 4 and 72.

Explanation:

The degrees of freedom for the F-statistic in a one-way ANOVA are determined by the sample sizes of the populations being compared. In this case, the sample sizes are 17, 15, 16, 18, and 11.

The degrees of freedom for the numerator (df(num)) is equal to the number of groups being compared minus 1, which is 5-1=4.

The degrees of freedom for the denominator (df(denom)) is equal to the total number of observations minus the number of groups, which is 77-5=72. Therefore, the degrees of freedom for the F-statistic are 4 and 72.

Answer:

38 %

Step-by-step explanation:

Survey 400 college seniors resulted in the following cross tabulation . regarding their undergraduate major and graduate.

Missing details

Undergraduate Major

Graduate School || Business || Engineering || Others

Yes ----- 35 ---------42 ---------- 63

No ----- ----91 ------- 104 --------- 65

Answer:

The percentage of the undergraduates surveyed who major in Engineering is 36.5%

Step-by-step explanation:

Given: The above table

Required: Percentage of undergraduates that majored in Engineering

We'll solve this question irrespective of whether the undergraduate student plans to go to a graduate school or not.

Follow the steps below

Step 1: Calculate the total engineering students

Tot Engineering students = Undergraduate student that plan to go to graduate school + those that have no plans for graduate school

From the engineering column

Undergraduate student that plan to go to graduate school = 42

those that have no plans for graduate school = 104

Total = 42 + 104

Total = 146

Step 2: Calculate percentage of this category of undergraduates

Percentage is calculated as a ratio of required population to total population.

In other words,

Percentage = Required Population ÷ Total Population

Here,

Required population = total engineering students

Required population = 146

Total Population = 400

Percentage = 146/400

Percentage = 0.365

Percentage. = 36.5%

Hence, the percentage of the undergraduates surveyed who major in Engineering is 36.5%