Aaron's car is moving at speed of 30 m/s
His reaction time is given as 0.7 s
but when he is tired the reaction time is doubled
Now we need to find the distance covered by his car when he is tired during the time when he react to apply brakes
So here since during this time speed is given as constant so we can say that distance covered can be product of speed and time
So here we can use
[tex]d = v*t[/tex]
[tex]d = 30 * 1.4[/tex]
[tex]d = 42 m[/tex]
So the car will move to 42 m during the time when he apply brakes
During a crash test, an air bag inflates to stop a dummy’s forward motion. The dummy’s mass is 75kg. If the net force on the dummy is 825 N toward the rear of the car, what is the dummy’s acceleration?
Mass of the dummy m = 75 kg
Net Force on the dummy [tex]F_{net} = -825 N[/tex] since it is given that the force is towards the backside of the car.
Acceleration of the dummy a = ?
Using Newton's 2nd law of motion, we have
[tex]F_{net} = ma[/tex]
-825 = (75)a
Hence, [tex]a = \frac{-825}{75}[/tex]
Acceleration of the dummy is -11 [tex]m/s^{2}[/tex]
The negative sign indicates that the dummy is slowing at a rate of 11 [tex]m/s^{2}[/tex]
Answer:
Acceleration towards rear = 11 [tex]m/s^2[/tex]
Acceleration towards direction of movement of dummy = -11 [tex]m/s^2[/tex]
Explanation:
Mass of dummy = 75 kg
Force acted towards rear of the car = 825 N
We have Force acting on a body = Mass of body * Acceleration of body
Substituting the given values in the above equation we will get
825 = 75 * a
a = 11 [tex]m/s^2[/tex]
So acceleration towards rear = 11 [tex]m/s^2[/tex]
Acceleration towards direction of movement of dummy = -11 [tex]m/s^2[/tex]
what did bohr contribute to modern atomic theory
Answer:
Bohr atomic model
Explanation:
Bohr's atomic model:
Bohr's atomic model was proposed by Neil Bohr in 1913. In this atomic model Neil Bohr's modified the Rutherford Model and show how electrons in an atoms moves around the nucleus in stable orbits. According to Rutherford model electron's in atoms are filled in orbits and these electron moves around the nucleus in these orbits like planets moves around the sun in fixed orbit but Rutherford's model was unable to show the stability of orbits. To solve this problem, Bohr proposed a new model b. According to this model electrons move around the nucleus in fixed size orbits which have fixed energy and the electron with low energy is filled in smaller size orbit. Radiation are emitted from atoms only when transition of electron from higher energy orbit to lower energy orbit takes place.
How can the rate of a reaction be decreased?
A. Lowering the temperature.
B. Increasing the amount of reactants.
C. Having more surface area.
D. Adding a Catalyst.
A. Lowering the temperature.
The anser is going to be A.Lowering the temperature.
I HOPE THIS HELPS YOU OUT ALLOT
How to get displacement
What effects can occur when heat energy is added to a system?
Select all that apply.
increase in temperature
decrease in temperature
change of state
phase change
when heat energy is added to a system, change in system can be:
Increase in temperature: If system doesn't absorb the heat energy, then the effect will be increase in temperature.Change of state: If system absorbs the heat energy. And energy change in system can change the state of system.Phase change: If system absorbs the heat energy then the phase of system can be changed. For example liquid can be converted into vapors by adding heat energy to system.The largest number of neurons within the brain and spinal cord are responsible for the central nervous system’s complex internal communication and intervene between jnputs and output these are the
Interneurons.
Their role is to receive signals from from the Sensory Neurons, process them, and communicate the decision to the Motor Neurons. They play a good role in Reflex Arcs.
Two carts (m= 0.4 kg each) are placed on an aluminum track. The first cart pushed with the initial velocity of 1.5 m/s towards the second cart, which remains at rest until the collision. Determine the velocities if both carts after the collision.
here two cars are placed on an aluminium track
so there is no friction on two carts during their motion and hence there is no external force on them
now if there is no external force so momentum is conserved
[tex]m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f][/tex]
here
[tex]m_1 = m_2 = 0.4 kg[/tex]
[tex]v_{1i} = 1.5 m/s[/tex]
[tex]v_{2i} = 0[/tex]
now plug in all values in it
[tex]0.4 * 1.5 + 0 = 0.4* v_{1f} + 0.4*v_{2f}[/tex]
divide whole equation by mass 0.4
[tex]v_{1f} + v_{2f} = 1.5[/tex]
also be the equation of coefficient of restitution
[tex]e = 1 = \frac{v_{2f} - v_{1f}}{v_{1i} - v_{2i}}[/tex]
now we have
[tex]v_{2f} - v_{1f} = 1.5[/tex]
now by solving above equations we will have
[tex]v_{2f} = 1.5 m/s[/tex]
[tex]v_{1f} = 0[/tex]
so after collision speed of two carts is 0 m/s and 1.5 m/s after collision
what did bohr contribute to modern atomic theory
Bohr’s model showed that electron orbits had distinct radii.
Answer:
bohr developed a model of the atom that predicts how it will behave
Explanation:
a p e x :)
If two objects of unequal mass collide, both objects will continue to move in the direction ofL A. the smaller object's momentum B. the larger object's momentum C. the smaller object's resistance D. the larger object's resistance
Final answer:
Momentum determines the movement of two objects after a collision. The total momentum of a two-object system remains constant, generally resulting in motion towards the direction of the larger momentum. Option b
Explanation:
When two objects of unequal mass collide, the direction they will continue to move in after the collision is determined by the momentum they have. According to the principle of conservation of momentum, the total momentum of a system remains constant if no external forces are acting on it.
If we consider two cars with different masses in an inelastic collision, car 1 will slow down, losing some momentum, and car 2 will speed up, gaining momentum.
However, the momentum of the system (both cars) before and after the collision remains the same. The total momentum after the collision will move in the direction of the combined momentum of the two objects prior to the collision.
Generally, this would be in the direction of the object with the larger pre-collision momentum, but the exact direction and speed will depend on the masses and velocities of both objects. Option b
In which situation is work not being done?
AS
work done =W = F.d = F d cosФ (Ф is angle between force F and displacement d) If a body/object is moving on a smooth surface (friction-less surface ) .There is no force acting on that body. F=0 so W=FdcosФ= (0)dcosФ ⇒ W=0
Now if a body is facing some amount of force but under the action of force there is no displacement covered. d=0 so W =FdcosФ= F(0)cosФ ⇒W=0
example: A person is applying a force on rigid wall but wall remains at rest there is no displacement occurs in wall.
The third term upon which work done dependent is angle between force and displacement i.e Ф. If Ф=90° then W= FdcosФ= Fdcos90⇒ W=0 ( as cos 90°=0)
Answer: need more info
Explanation:
A stone falls freely from rest for 18 s. The acceleration due to gravity is 9.8 m/s 2. What was the stone’s displacement after that time? ans in m
-- At the end of 18sec, the stone's velocity is (9.8m/s² x 18s) = 176.4m/s downward.
-- Starting at 0 m/s and ending at 176.4m/s, its average velocity is 88.2m/s downward.
-- Falling for 18s at an average speed of 88.2m/s, it falls (88.2m/s x 18s) = 1,587.6 m .
-- Its displacement is 1,587.6 meters downward.
The stone's displacement after falling freely for 18 s under the acceleration due to gravity (9.8 m/s²) is 1587.2 meters.
Explanation:The displacement of an object in free fall can be determined using the equation of motion: S = ut + 0.5gt². In this case, the stone is dropped freely from rest, so the initial velocity (u) is 0 m/s. The acceleration due to gravity (g) is 9.8 m/s² and the time (t) is 18 s. Substituting these values into the equation, we get: S = 0 * 18 + 0.5 * 9.8 * (18)² = 0 + 0.5 * 9.8 * 324 = 1587.2 meters.
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The planets stay in orbit due to
A.kinetics
B.friction
C.gravity
D.mass
The planet stay in orbit due to gravity. because the gravity of the sun keeps the planets in their orbits,
dayshawn is traveling at 12 m/s away from the school. dayshaun's mom is looking for him because he is late coming home so she left the house and is driving toward the school at 5 m/s. The school is 6492 m from dayshauns house. at what position will dayshawn meet his mom and how long after she left the house did she find dayshaun? draw a motion map and solve. show your work
Speed of Dayshawn travelling towards his home is 12 m/s
Speed of her mom towards his school is 5 m/s
They both starts at same time so whenever they will meet on their path the sum of the distance covered by Dayshawn and distance covered by his mom must be equal to the total distance of school and home
Now let say they both meet after "t" time when they starts motion
so we can write the total distance between school and home as
[tex]d = v_1*t + v_2*t[/tex]
here d = 6492 m
[tex]v_1 = 12 m/s[/tex] = speed of dayshawn
[tex]v_2 = 5 m/s[/tex] = speed of his mom
now by solving the above equation
[tex]6492 = 12t + 5 t[/tex]
[tex]t = \frac{6492}{17}[/tex]
[tex]t = 381.9 s[/tex]
so they will meet after 381.9 s from start which will be 3.36 minutes from there start
Also at this time the distance covered by her mom will be
[tex]d_2 = v_2*t[/tex]
[tex]d_2 = 5* 381.9 = 1909.4 m[/tex]
so they will meet at distance 1909.4 m from their home
How are force, mass and acceleration related?
Newton's 2nd law of motion:
F = ma
F is force, m is mass, and a is acceleration.
Which is a chemical property that can be used to identify calcium carbonate?
A. white color
B. powered solid
C. melting point of 825 °C (1517 °F)
D. reacts with acids by producing gas bubbles
Answer:
could someone at least give one answer instead of a choice between two cause that is a 50/50 chance to get it correct on a test!!
Explanation:
In the absence of air resistance, objects fall at constant
In the absence of air resistance , object fall with same acceleration .
In the absence of air resistance, objects fall at constant acceleration.
Object falling in absence of air resistance is tantamount to object falling in a vacuum. The experiment was performed in Italy by a Physicist known as Galilio Galilian. He dropped two different objects of different masses in the absence of air and discovered that they both landed at the same time.
The objects falling in the absence of air resistance will experience a free fall. And the formula for free fall are :
h = 1/2g[tex]t^{2}[/tex][tex]v^{2}[/tex] = 2ghV = gtNon of the above formula depends on the mass of the object but the acceleration due to gravity and the height at which they are falling.
And since the acceleration due to gravity is constant, therefore, In the absence of air resistance, objects fall at constant acceleration due to gravity.
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Jim wants to learn more about the feeding habits of ants. What steps should he take in order to best study the patterns of ants?
how much work is done when you push a crate horizontally with 130 N across a 5.0-m
Complete solution is given below in attachment
Is thallium a solid liquid or gas
Thallium (Tl) is a solid at room temperature. It has a melting point of 304 degrees Celsius and a boiling point of 1,473 degrees Celsius.
Thallium (Tl) is a chemical element that is classified as a metal. At standard temperature and pressure conditions, thallium exists in a solid state. This means that it maintains a fixed shape and volume.
The state of matter of an element or compound is determined by its melting and boiling points.
However, at room temperature (around 25 degrees Celsius), thallium remains in its solid state. It has a metallic appearance and is relatively soft and malleable.
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A sailor in a small sailboat encounters shifting winds. She sails 2.00 km east, then 3.50 km southeast, and then an additional distance in an unknown direction. Her final position is 5.80 km directly east of the starting point (Fig. P1.72). Find the magnitude and direction of the third leg of the journey. Draw the vectoraddition diagram and show that it is in qualitative agreement with Your numerical solution.
Answer:
Third displacement = 2.81 m which is 61.70° north of east.
Explanation:
Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.
She sails 2 km east, displacement = 2 i
Then 3.50 km southeast, means 3.5 km 315⁰ to + ve X axis
Displacement = 3.5 cos 315 i + 3.5 sin 315 = 2.47 i - 2.47 j
Let third displacement be x i + y j
We have final displacement = 5.80 km east = 5.80 i
From summation we have total displacement = 2 i + 2.47 i - 2.47 j + x i + y j
= (4.47+x) i + (y - 2.47) j
Comparing both , we have 4.47+x = 5.80
x = 1.33
y-2.47=0
y = 2.47 j
So third displacement = 1.33 i + 2.47 j
Magnitude of third displacement = [tex]\sqrt{1.33^2+2.47^2} =2.81m[/tex]
θ = tan⁻¹(2.47/1.33) = 61.70°
So third displacement = 2.81 m which is 61.70° north of east.
Suppose you have 100kg of fresh strawberries. What would be the approximate mass of the strawberries after freeze-drying
The mass of strawberries after freeze-drying would be significantly less than their original mass, given that most of the water content is removed during the process. For 100 kg of fresh strawberries, the approximate mass after freeze-drying would be about 8.4 kg, assuming 91.6% water content.
The approximate mass of strawberries after freeze-drying can be calculated by considering the water content in the fresh strawberries. Fresh strawberries consist of about 91.6% water. During the freeze-drying process, most of this water is removed, hence reducing the mass significantly.
To estimate this change in mass, we can subtract the mass of water (91.6% of the original mass) from the total mass of the fresh strawberries (100 kg). Thus, the dried strawberries would approximately be 8.4% of their original mass, since the mass of fructose and other non-water components remain. This is an estimation and the actual number can be slightly higher or lower depending on the exact freeze-drying process and the specifics of the strawberries.
Therefore, after freeze-drying 100 kg of fresh strawberries, which originally consist of 91.6% water, the approximate mass of the strawberries would be about 8.4 kg.
How much is the force of gravity on Mr.Arbo if his mass is 74.8kg?
Answer:
Force due to gravity in earth = 74.8*9.8 = 733.04 N
Explanation:
We have mass of Mr. Arbo = 74.8 kg
Force of gravity = Weight = Mass * Acceleration due to gravity value of planet.
In earth acceleration due to gravity value = 9.8[tex]m/s^2[/tex]
So force due to gravity in earth = 74.8*9.8 = 733.04 N
A metal ball of mass 2 kg is supported by a massless inextensible string, 12 cm long. A
horizontal force displaces the ball by 30o
to the vertical so that the string remains taut. Find:
a) the horizontal force.
b) the tension in the thread.
(a) the horizontal force is 11.3 N
(b) The tension in the thread is 22.6 N
Draw a free body diagram for the suspended metal ball as shown in the figure. The tension T acts along the length of the thread, the force F is the horizontal force and its weight is mg, which acts vertically down wards.
Resolve the tension into two components- T cos 30 along the vertical and T sin30 along the horizontal as shown in the figure.
Apply the condition for equilibrium along the horizontal direction.
[tex]F=Tsin30........(1)[/tex]
Apply the condition for equilibrium along the vertical direction.
[tex]mg=Tcos30.......(2)[/tex]
Divide equation (1) by equation (2) and write an expression for F.
[tex]\frac{F}{mg} = tan30\\ F=mgtan30[/tex]
Substitute 2 kg for m and 9.81 m/s² for g.
[tex]F=mgtan30\\ =(2kg)(9.81m/s^2)(tan30^o)\\ =11.3N[/tex]
The horizontal force required to keep the ball taut is 11.3 N
From equation (2),
[tex]T=\frac{mg}{sin30} \\ =\frac{(2kg)(9.81m/s^2)}{sin30^o} \\ =22.6N[/tex]
Thus, the tension in the thread is 22.6 N
What can the arrow in a chemical reaction be translated to mean? Check all that apply
A. yields
B. accompanied by
C. react to form
D. added to
E. except
The arrow in a chemical reaction can be translated as the following:
A. yields
C. react to form
The arrrow in a chemical reaction is translated to mean a reactant combines to yield or react to form a product: Option A and C are correct.
Arrows in a chemical reaction are very important to differentiate between the reactants and the product.
They are used in chemical reactions to show that the reaction yields a particular product.
For instance, hydrogen reacts with oxygen to yield water as shown;
[tex]2H_2 + O_2 \rightarrow 2H_2O[/tex]
We can see that the arrow in the reaction shows that the reaction of hydrogen and oxygen element yields or react to form water.
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1. California sea lions can swim as fast as 40.0 km/h. Suppose a sea lion begins to chase a fish at this speed when the fish is 60.0 m away. The fish, of course, does not wait, and swims away at a speed of 16.0 km/h. How long would it take the sea lion to catch the fish?
2. A pet-store supply truck moves at 25.0 m/s north along a highway. Inside, a dog moves at 1.75 m/s at an angle of 35.0° east of north. What is the velocity of the dog relative to the road?
Please explain your work and give the formulas you used. Tysm <3!
Answer:
1) time t = 9 s
2) velocity v = 26.4 m/s 2.17° east of north
Explanation:
1
Given
velocity of sea lion [tex]v_s = 40.0 kmph[/tex]
velocity of the fish [tex]v-f = 16 kmph[/tex]
Distance between the fish and sea lion d = 60 m
Solution
Relative velocity of the sea lion with respect to the fish
[tex]v = v_s - v_f\\\\v = 40 - 16\\\\v = 24.kmph\\\\v = 24 \times \frac{1000}{60 \times 60} m/s\\\\v = 6.67 m/s[/tex]
Time
[tex]t = \frac{d}{v} \\\\t = \frac{60}{6.67} \\\\t = 9 s[/tex]
2
Given
velocity of the truck [tex]v_t = 25 m/s[/tex]
velocity of the dog [tex]v_d = 1.75 m/s[/tex]
Angle [tex]\theta = 35.0^o[/tex]
Solution
Dog moves in north east so
Component of velocity in East
[tex]v_{d,E} = v_dsin\theta\\\\v_{d,E} = 1.75 \times sin35\\\\v_{d,E} = 1.004 m/s[/tex]
Component of velocity in North
[tex]v_{d,N} = v_dcos\theta\\\\v_{d,N} = 1.75 \times cos35\\\\v_{d,N} = 1.434 m/s[/tex]
The velocity of Dog relative to the road = velocity of the dog relative to truck + velocity of the truck relative to the road
Y component
[tex]v_y = v_t + v_{d,N}\\\\v_y = 25 + 1.434\\\\v_y = 26.434 m/s[/tex]
X component
[tex]v_x = v_{d,E}\\\\V_x = 1.004 m/s[/tex]
Velocity
[tex]v = \sqrt{v_x^{2} +v_y^{2} } \\\\v = \sqrt{1.004^2 + 26.434^2} \\\\v = 26.4 m/s[/tex]
Direction
[tex]\phi = tan^{-1}\frac{v_x}{v_y} \\\\\phi = tan^{-1}\frac{1.004}{26.434} \\\\\phi = 2.17^o east of north[/tex]
For the time and velocity:
The sea lion will catch the fish in 0.42 seconds.
The velocity of the dog relative to the road is 26.41 m/s north.
How to find time and velocity?Question 1: Formula:
Relative velocity = vA - vB
The sea lion is moving at a relative velocity of 40.0 - 16.0 = 24.0 km/h faster than the fish.
The distance between the sea lion and the fish is 60.0 m, which is 0.160 km.
The time it takes the sea lion to catch the fish is:
time = distance / relative velocity
= 0.160 km / 24.0 km/h
= 0.007 h
= 0.42 seconds
Therefore, it would take the sea lion 0.42 seconds to catch the fish.
Question 2: Formula:
Relative velocity = vA + vB
The velocity of the dog relative to the road can be found by adding the velocity of the truck and the velocity of the dog.
The velocity of the truck is 25.0 m/s north.
The velocity of the dog can be broken down into two components: a northward component of 1.75 × cos(35.0°) = 1.41 m/s and an eastward component of 1.75 × sin(35.0°) = 1.18 m/s.
Therefore, the velocity of the dog relative to the road is 25.0 + 1.41 = 26.41 m/s north.
The direction of the velocity of the dog relative to the road is north.
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All objects in motion have what energy
Hello Undeadman12
All objects in motion would have kinetic energy
:)
Hi there.
Your Question: All objects in motion have what energy ?
Kinetic Energy is the answer, (I took this part from google) Mechanical energy is the energy that is possessed by an object due to its motion or due to its position. Mechanical energy can be either kinetic energy (energy of motion) or potential energy (stored energy of position).
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A small dingy is floating up to a pirate’s ship full of would be boarders. He angles his cannon downward at -15 degrees while 3.0m above the water. He fires his cannon at 95 m/s. The small boat of unfortunate crewmen is 20 m away. Do they survive their foolhardy errand?(please show work)
Speed of the cannon is 95 m/s
now we will find its two components
speed in horizontal direction is
[tex]v_x = 95 cos15[/tex]
[tex]v_x = 91.76 m/s[/tex]
speed in vertical direction is
[tex]v_y = 95 sin(-15)[/tex]
[tex]v_y = -24.6 m/s[/tex]
now the time taken by the cannon to reach the water surface will be find out by using kinematics
[tex]\Delta y = v_y * t + \frac{1}{2} at^2[/tex]
[tex]-3 = -24.6 * t - \frac{1}{2}9.8 * t^2[/tex]
[tex]4.9t^2 + 24.6 t - 3 = 0[/tex]
By solving above quadratic equation
[tex]t = 0.12 s[/tex]
now in the same time the horizontal distance moved by the cannon
[tex]d_x = v_x * t[/tex]
[tex]d_x = 91.76 * 0.12[/tex]
[tex]d_x = 10.93 m[/tex]
Since the distance of crewmen is 20 m so it will definitely safe as cannon will hit at distance 10.93 m
In an attempt to reduce our dependence on non–renewable resources, and cut down on the harm to the environment, we could burn ______ to produce electricity.
In an attempt to reduce our dependence on non-renewable resources, and cut down on the harm to the environment, we could burn biomass to produce electricity.
I'm in dire need of some help, The first correct response receives brainlest!
A 1,000 g ball and a 100 g ball are both dropped from a tower. both balls have the same size and there is no air resitance. Which one hits the ground first?
A. The 100 g mass hits the ground first
B. The 1000 g mass hits the ground first
C. They both hit at the same time
If they're dropped from the same height at the same time and there's no air resistance, the the lighter ball and the heavier ball, as well as a feather, a hammer, a bowling ball, a speck of dust, a school bus, and a battle ship, will all fall side-by-side and hit the ground at the same time.
We've known this for about 400 years, since Galileo. And we've known WHY for about 300 years, since Newton.
Why is it important to balance a chemical equation?
A. It is not important to balance a chemical equal
B. To make sure you have the correct products
C. To make sure you have the correct reactants
D. To obey the law of conservation of mass
The chemical equation of a chemical must be balanced to obey the law of conservation of mass. Therefore, option (D) is correct.
What is the balanced chemical equation?The equation in which the number of atoms of each element of reactants is equal to the number of atoms of each element of products is called a balanced chemical equation.
The law of conservation of mass obeys by a balancing of a chemical equation for a chemical reaction. According to this law, the mass of matter can neither be created nor be destroyed in a chemical reaction.
By following this law, the total mass of the elements on the reactant side should be equal to the total mass of elements on the product side in a balanced chemical equation.
An example of the balanced chemical equation is the formation of water:
2H₂ + O₂ → 2H₂O
On both sides of the arrow in the equation, the number of hydrogen and oxygen atoms is equal and so are their masses. Therefore this chemical equation obeys the law of conservation of mass.
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