Abby has an exercise wheel with and 11 inches diameterFor her guinea pig. What is the circumference of the exercise wheel to the nearest whole number? Use 3.14 for

Answer:

Step-by-step explanation:

Look at the picture.

9. The perimeter of the rectangle l × w:

P = 2l + 2w

Substitute l = 2x + 8 and w = x + 8:

P = 2(2x + 8) + 2(x + 8)     use the distributive property

P = (2)(2x) + (2)(8) + (2)(x) + (2)(8)

P = 4x + 16 + 2x + 16     combine like terms

P = (4x + 2x) + (16 + 16)

P = 6x + 32

10. Solve the equation:

6x + 32 = 158           subtract 32 from both sides

6x = 126     divide both sides by 6

x = 21

Put the value of x to the expression 2x + 8:

2(21) + 8 = 42 + 8 = 50

The approximate circumference of a circle with a diameter of 9 is 28.3 units, rounded to the nearest tenth, calculated using the formula C = πd.

The circumference of a circle can be calculated using the formula C = πd, where C is the circumference and d is the diameter of the circle. Given the diameter of 9, we can substitute this value into the formula to calculate the circumference.

Therefore, the circumference C is:

C = π × 9

Using the approximation for π as 3.14, we get:

C ≈ 3.14 × 9 = 28.26

So, the approximate circumference of the circle is 28.3 units, rounded to the nearest tenth.

Answer:

see explanation

Step-by-step explanation:

Using Pythagoras' identity

The square on the hypotenuse of a right triangle is equal to the sum of the squares on the other 2 sides.

Consider the right triangle on the right and calculate n

n² + 2² = 3²

n² + 4 = 9 ( subtract 4 from both sides )

n² = 5 ( take the square root of both sides )

n = [tex]\sqrt{5}[/tex]

If the triangle on the left is right then the square of the longest side must equal the sum of the squares on the other 2 sides.

The longest side is n = [tex]\sqrt{5}[/tex] ⇒ n² = ([tex]\sqrt{5}[/tex] )² = 5 and

([tex]\sqrt{2}[/tex] )² + ([tex]\sqrt{3}[/tex] )² = 2 + 3 = 5

Hence D is a right angle

Answer:

[tex]\large\boxed{y=3x-11}[/tex]

Step-by-step explanation:

[tex]\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\===================================\\\\y=3x-4\to m_1=3\\\\\text{Therefore}\ m_2=3.\\\\\text{We have the equation:}\ y=3x+b.\\\\\text{Put the coorsdinates of the point (2, -5) to the equation of the line}\\\\-5=3(2)+b\\-5=6+b\qquad\text{subtract 6 from both sides}\\-11=b\to b=-11[/tex]

Answer:

Step-by-step explanation:

[tex]1.\\\text{The length of semicircle:}\\\\l=\dfrac{1}{2}d\pi\\\\d-diameter\\\\d=2.2\\\\\text{substitute:}\\\\l=\dfrac{1}{2}(2.2)\pi=1.1\pi\approx(1.1)(3.14)=3.454\\\\\text{The perimeter of the figure:}\\\\P=2(3.8)+2.2+3.454=13.254[/tex]

[tex]2.\\P=2(3.32)+2x=6.64+2x[/tex]

[tex]6.\\\text{Look at the picture.}\\\\P=4(2)+2(1)=8+2=10[/tex]

Answer:

See below.

Step-by-step explanation:

You fill the 5 gallon up to the top then you pour 3 gallons into the 3 gallon jug, leaving 2 gallons in the  bigger jug.

You throw the contents of the 3 gallon jug away then transfer the 2 gallons from the bigger jug into the 3 gallon jug. So you have  2 gallons in the 3 gallon jug.

You then fill the 5 gallon jug and pour 1 gallon into the 3 gallon jug, so you are left with 4 gallons of water in the 5 gallon jug.

Answer:

The function f(x)=3x-10 has the greater value at x=8.

Step-by-step explanation:

In the table, x=8 corresponds to y=4.

In the function f(x)=3x-10 when x=8, y corresponds to f(8)=3(8)-10=24-10=14.

SInce 14>4 , the the function f(x)=3x-10 has a greater value at x=8 than the table does.

Answer:

   Slope of Function B = 2 x Slope of Function A

Step-by-step explanation:

step 1

Find the slope of the function A

we have

[tex]f(x)=x-9[/tex]

This is the equation of the line into point slope form

[tex]y=mx+b[/tex]

where m is the slope

b is the y-intercept

therefore

The slope of the function A is

[tex]m=1[/tex]

step 2

Find the slope of the function B

we have the points

(-1,-3) and (2,3)

The slope m is equal to

[tex]m=(3+3)/(2+1)=6/3=2[/tex]

step 3

Compare the slopes

[tex]SlopeA=1\\ SlopeB=2[/tex]

therefore

The slope of the function B is two times the slope of the function A

Answer:

slope of function a = -2

slope of function b = (1 + 5)/(2 + 1) = 6/3 = 2

slope of function b = - slope of function a.

Step-by-step explanation:

Answer:

[tex]\text{The point-slope equation of a line is:}[/tex]

[tex]C.\ y-y_0=m(x-x_0)[/tex]

[tex]m-\text{slope}\\\\(x_0,\ y_0)-\text{point on a line}[/tex]

tangent is less than 0 or tan(θ) < 0, is another way to say tan(θ) is negative, well, that only happens on the II Quadrant and IV Quadrant, where sine and cosine are different signs, so we know θ is on the II or IV Quadrant.

[tex]\bf sin(\theta )=\cfrac{\stackrel{opposite}{2}}{\stackrel{hypotenuse}{3}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases}[/tex]

[tex]\bf \pm\sqrt{3^2-2^2}=a\implies \pm\sqrt{5}=a\implies \stackrel{\textit{II Quadrant}}{-\sqrt{5}=a} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{-\sqrt{5}}}{\stackrel{hypotenuse}{3}}~\hfill[/tex]

Answer:

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

Then, the work consists in finding pairs (a,b) for which:

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

[tex]\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}[/tex]

I will use b =0.5, b = 1, b = 1.5, b = 2

[tex]b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236[/tex]

Then, four distinct complex numbers that have an absolute value of 3 are:

[tex]\dfrac{d}{dx}(\dfrac{\sin(3x)}{x})[/tex]

First we must apply the Quotient rule that states,

[tex](\dfrac{f}{g})'=\dfrac{f'g-g'f}{g^2}[/tex]

This means that our derivative becomes,

[tex]\dfrac{\dfrac{d}{dx}(\sin(3x))x-\dfrac{d}{dx}(x)\sin(3x)}{x^2}[/tex]

Now we need to calculate [tex]\dfrac{d}{dx}(\sin(3x))[/tex] and [tex]\dfrac{d}{dx}(x)[/tex]

[tex]\dfrac{d}{dx}(\sin(3x))=\cos(3x)\cdot3[/tex]

[tex]\dfrac{d}{dx}(x)=1[/tex]

From here the new equation looks like,

[tex]\dfrac{3x\cos(3x)-\sin(3x)}{x^2}[/tex]

And that is the final result.

Hope this helps.

r3t40

Answer:

[tex]\frac{3\cos(3x)}{x}-\frac{\sin(3x)}{x^2}[/tex]

Step-by-step explanation:

If [tex]f(x)=\frac{\sin(3x)}{x}[/tex], then  

[tex]f(x+h)=\frac{\sin(3(x+h)}{x+h}=\frac{\sin(3x+3h)}{x+h}[/tex].

To find this all I did was replace old input, x, with new input, x+h.

Now we will need this for our definition of derivative which is:

[tex]f'(x)=\lim_{h \rightarrow 0}\frac{f(x+h)-f(x)}{h}[/tex]

Before we go there I want to expand [tex]sin(3x+3h)[/tex] using the sum identity for sine:

[tex]\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b)[/tex]

[tex]\sin(3x+3h)=\sin(3x)\cos(3h)+\cos(3x)\sin(3h)[/tex]

So we could write f(x+h) as:

[tex]f(x+h)=\frac{\sin(3x)\cos(3h)+\cos(3x)\sin(3h)}{x+h}[/tex].

There are some important trigonometric limits we might need before proceeding with the definition for derivative:

[tex]\lim_{u \rightarrow 0}\frac{\sin(u)}{u}=1[/tex]

[tex]\lim_{u \rightarrow 0}\frac{\cos(u)-1}{u}=0[/tex]

Now let's go to the definition:

[tex]f'(x)=\lim_{h \rightarrow 0}\frac{\frac{\sin(3x)\cos(3h)+\cos(3x)\sin(3h)}{x+h}-\frac{\sin(3x)}{x}}{h}[/tex]

I'm going to clear the mini-fractions by multiplying top and bottom by a common multiple of the denominators which is x(x+h).

[tex]f'(x)=\lim_{h \rightarrow 0}\frac{x(\sin(3x)\cos(3h)+\cos(3x)\sin(3h))-(x+h)\sin(3x)}{x(x+h)h}[/tex]

I'm going to distribute:

[tex]f'(x)=\lim_{h \rightarrow 0}\frac{x\sin(3x)\cos(3h)+x\cos(3x)\sin(3h)-x\sin(3x)-h\sin(3x)}{x(x+h)h}[/tex]

Now I’m going to group xsin(3x)cos(3h) with –xsin(3x) because I see when I factor this I might be able to use the second trigonometric limit I mentioned.  That is xsin(3x)cos(3h)-xsin(3x) can be factored as xsin(3x)[cos(3h)-1].

Now the limit I mentioned:

[tex]\lim_{u \rightarrow 0}\frac{\cos(u)-1}{u}=0[/tex]

If I let u=3h then we have:

[tex]\lim_{3h \rightarrow 0}\frac{\cos(3h)-1}{3h}=0[/tex]

If 3h goes to 0, then h goes to 0:

[tex]\lim_{h \rightarrow 0}\frac{\cos(3h)-1}{3h}=0[/tex]

If I multiply both sides by 3 I get:

[tex]\lim_{h \rightarrow 0}\frac{\cos(3h)-1}{h}=0[/tex]

I’m going to apply this definition after I break my limit using the factored form I mentioned for those two terms:

[tex]f'(x)=\lim_{h \rightarrow 0}\frac{x\sin(3x)\cos(3h)-x\sin(3x)+x\cos(3x)\sin(3h)-h\sin(3x)}{x(x+h)h}[/tex]

[tex]f'(x)=\lim_{h \rightarrow 0}\frac{x\sin(3x)(\cos(3h)-1)+x\cos(3x)\sin(3h)-h\sin(3x)}{x(x+h)h}[/tex]

[tex]f'(x)=\lim_{h \rightarrow 0}\frac{x\sin(3x)(\cos(3h)-1)}{x(x+h)h}+\lim_{h \rightarrow 0}\frac{x\cos(3x)\sin(3h)-h\sin(3x)}{x(x+h)h}[/tex]

So the first limit I’m going to write as a product of limits so I can apply the limit I have above:

[tex]f’(x)=\lim_{h \rightarrow 0}\frac{\cos(3h)-1}{h} \cdot \lim_{h \rightarrow 0}\frac{x\sin(3x)}{x(x+h)}+\lim_{h \rightarrow 0}\frac{x\cos(3x)\sin(3h)-h\sin(3x)}{x(x+h)h}[/tex]

The first limit in that product of limits goes to 0 using our limit from above.

The second limit goes to sin(3x)/(x+h) which goes to sin(3x)/x since h goes to 0.

Since both limits exist we are good to proceed with that product.

Let’s look at the second limit given the first limit is 0. This is what we are left with looking at:

[tex]f’(x)=\lim_{h \rightarrow 0}\frac{x\cos(3x)\sin(3h)-h\sin(3x)}{x(x+h)h}[/tex]

I’m going to write this as a sum of limits:

[tex]\lim_{h \rightarrow 0}\frac{x\cos(3x)\sin(3h)}{x(x+h)h}+\lim_{h \rightarrow 0}\frac{-h\sin(3x)}{x(x+h)h}[/tex]

I can cancel out a factor of x in the first limit.  

I can cancel out a factor of h in the second limit.

[tex]\lim_{h \rightarrow 0}\frac{\cos(3x)\sin(3h)}{(x+h)h}+\lim_{h \rightarrow 0}\frac{-\sin(3x)}{x(x+h)}[/tex]

Now I can almost use sin(u)/u goes to 1 as u goes to 0 for that first limit after writing it as a product of limits.  

The second limit I can go ahead and replace h with 0 since it won’t be over 0.

So this is what we are going to have after writing the first limit as a product of limits and applying h=0 to the second limit:

[tex]\lim_{h \rightarrow 0}\frac{\sin(3h)}{h} \cdot \lim_{h \rightarrow 0}\frac{\cos(3x)}{(x+h)}+\frac{-\sin(3x)}{x(x+0)}[/tex]

Now the first limit in the product I’m going to multiply it by 3/3 so I can apply my limit as sin(u)/u->1 then u goes to 0:

[tex]\lim_{h \rightarrow 0}3\frac{\sin(3h)}{3h} \cdot \lim_{h \rightarrow 0}\frac{\cos(3x)}{(x+h)}+\frac{-\sin(3x)}{x(x)}[/tex]

[tex]3(1) \cdot \lim_{h \rightarrow 0}\frac{\cos(3x)}{(x+h)}+\frac{-\sin(3x)}{x(x)}[/tex]

So we can plug in 0 for that last limit; the result will exist because we do not have over 0 when replacing h with 0.

[tex]3(1)\frac{\cos(3x)}{x}+\frac{-\sin(3x)}{x^2}[/tex]

[tex]\frac{3\cos(3x)}{x}-\frac{\sin(3x)}{x^2}[/tex]

Answer: A is correct, (x-5, y-3) Hope this helps, mark brainliest please :)

Step-by-step explanation:

The green triangle is the original, and the blue is the duplicated translation, you know this by the ' mark on the blue S.

You can count the squares from one spot to the next to find how many it moved. It clearly is moved to the left and down though, which means it was subtracted from in both directions.

Answer:A

Step-by-step explanation:

Answer:

there are 4 pints

Step-by-step explanation:

64 / 16 = 4

64 fluid ounces of lemonade equals to 4 pints. This is done by dividing the total fluid ounces by the number of fluid ounces in one pint.

The question is asking to convert 64 fluid ounces of lemonade into pints. To do this, you should know that 1 pint is equal to 16 fluid ounces. So, you can divide the total fluid ounces by the number of fluid ounces in one pint. In this situation, divide 64 by 16, which equals 4 pints. Therefore, 64 fluid ounces of lemonade equals to 4 pints.

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Answer:

Option B

Step-by-step explanation:

the mean is the sum of each value of P(x) multiply for x

Mean= 23x0.16 + 25x0.09 + (26x0.18) + (31x0.12)+ (34x0.24) + (38x0.21)

Mean= 30.47

Answer:

B. 30.47

Step-by-step explanation:

The mean discrete random variable tells us the weighted average of the possible values given of a random variable. It shows the expected average outcome of observations. It's like getting the weighted mean. The expected value of X can be computed using the formula:

[tex]\mu_{x}=x_1p_1+x_2p_2+x_3p_3...+x_kp_k\\\\=\Sigma x_ip_i[/tex]

Using the data given in your problem, just pair up the x and P(x) accordingly and get the sum.

[tex]\mu_{x}=x_1p_1+x_2p_2+x_3p_3+x_4p_4+x_5p_5+x_6p_6\\\\\mu_{x}=(23\times 0.16) + (25\times 0.09) + (26\times 0.18) + (31\times 0.12) + (34\times 0.24) + (38\times 0.21)\\\\\mu_{x} = 30.47[/tex]

Answer:

Step-by-step explanation:

(f - g)(x) = f(x) - g(x)

f(x) = 3x + 2, g(x) = 2x - 2.

Substitute:

(f - g)(x) = (3x + 2) - (2x - 2) = 3x + 2 - 2x - (-2) = 3x + 2 - 2x + 2

combine like terms

(f - g)(x) = (3x - 2x) + (2 + 2) = x + 4

For this case we must find an expression equivalent to:

[tex]\sqrt [7] {x} * \sqrt [7] {x} * \sqrt [7] {x}[/tex]

By definition of properties of powers and roots we have:

[tex]\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}[/tex]

So, rewriting the given expression we have:

[tex]x ^ {\frac {1} {7}} * x ^ {\frac {1} {7}} * x ^ {\frac {1} {7}} =[/tex]

To multiply powers of the same base we put the same base and add the exponents:

[tex]x ^ {\frac {1} {7} + \frac {1} {7} + \frac {1} {7}} =\\x ^ {\frac {3} {7}}[/tex]

Answer:

Option 1

Answer: Option 1.

Step-by-step explanation:

We need to remember that:

[tex]\sqrt[n]{a^m}=a^{\frac{m}{n}}[/tex]

Then, having the expression:

[tex]\sqrt[7]{x}*\sqrt[7]{x} *\sqrt[7]{x}[/tex]

We can rewrite it in this form:

[tex]=x^{\frac{1}{7}}*x^{\frac{1}{7}} *x^{\frac{1}{7}}[/tex]

According to the Product of powers property:

[tex](a^m)(a^n)=a^{(m+n)}[/tex]

Then, the simplied form of the given expression, is:

[tex]=x^{(\frac{1}{7}+\frac{1}{7}+\frac{1}{7})}=x^\frac{3}{7}[/tex]

Answer:

Probably of getting both = 3/10 *100 = 30%

Step-by-step explanation:

According to the given statement we have four possible combinations:

Blue pants/white shirt, tan pants/white shirt, blue pants/blue shirt, blue pants/white shirt

.probability of getting tan pants = 2/4

probability of getting white shirt = 3/5

probably of getting both = 2/4 x 3/5 = 6/20 = 3/10

probably of getting both = 3/10 *100 = 30% ...

Answer: 35

Step-by-step explanation:

The measure of ∠Z is 35°

The correct answer is an option (D)

For given question,

We have been given a parallelogram WXYZ.

The measure of angle X is 35°

We know that, the opposite angles of parallelogram are equal.

⇒ ∠X = ∠Z

⇒ ∠Z = 35°

Therefore, the measure of ∠Z is 35°

The correct answer is an option (D)

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The given system of equation can be solved if x = 2/3 and y = -4/3.

So we need to find another system which can be solved by these values.

From the given 4 options lets find out which can be solved by x = 3/2 and y = -4/3

1.

y = -2y^2 -2 , x = y - 2

lets put the value of y here

y = -2(16/9)-2 = -32/9-2= -50/ 9

So not an equivalent equation.

2.

y = -2y^2 + 2 , x = y + 2

y = -2(16/9)+2=-32/9+2=-14/9

So not an equivalent system.

3.

y = -2y^2 - 8y - 8 , x = y + 2

y = -2(16/9)-8(-4/3)-8 = -32/9+32/3-8=64/9-8=-8/9

So not an equivalent system.

4.

y = -2y^2 + 8y - 8 , x = y -2

y = -2(16/9)+8(-4/3)-8=-32/9-32/3-8=-128/9-8=-22.22

So this is not an equivalent equation too

Answer:

C. [tex]\left \{ {{y=-2y^{2}-8y-8 } \atop {x=y+2}} \right.[/tex]

Step-by-step explanation:

Edge 2020

Answer:

(-0.23,5.77)

Step-by-step explanation:

The given system of equations is

[tex]y = - 34x - 2...(1)[/tex]

[tex]y = x + 6...(2)[/tex]

We equate both equations to get:

[tex]x + 6 = - 34x - 2[/tex]

Group similar terms to get:

[tex]x + 34x = - 2 - 6[/tex]

[tex]35x = - 8[/tex]

[tex]x = - \frac{8}{35} [/tex]

[tex]x \approx - 0.23[/tex]

Put this value into the second equation to get y

[tex]y = - 0.23 + 6 \approx 5.77[/tex]

(-0.23,5.77)

Answer:

C. No because Angie is not representative of the population in the algebra class

Step-by-step explanation:

I just took the test and this was correct

No, this is not an accurate predictor

Since Angie is the student of an  advanced statistics course but she gives the algebra test and scored 80%. We know that the advanced statistics is the higher level of math so it is not an accurate predictor.

An accurate predictor should be applied when the person is 100% confirmed to the related thing. So in the given situation, the student is not 100% confirm.

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Answer:

f(4) = 14

Step-by-step explanation:

f(x) = 3x+2

Let x=4

f(4) = 3(4)+2

    = 12+2

    = 14

Answer:

3/10

Step-by-step explanation:

These two events are independent, so the overall probability is the product of the individual probabilities.

12 blue sections out of 20

p(blue) = 12/20 = 3/5

There is an equal probability of the coin landing on heads or tails.

p(tails) = 1/2

p(blue & tails) = 3/5 * 1/2 = 3/10

Answer:

x=y2/8+y/2+9/2

Step-by-step explanation:

Given:

directrix: x=2

focus = (6,-2)

Standard equation of parabola is given by:

(y - k)2 = 4p (x - h)

where

directrix : x=h-p

focus=(h + p, k)

Now comparing the give value with above:

(h + p, k)= (6,-2)

k=-2

h+p=6

h=6-p

Also

directrix: x=h-p

h-p=2

Putting value of h=6-p in above

6-p-p=2

6-2p=2

-2p=2-6

-2p=-4

p=-4/-2

p=2

Putting p=2 in h-p=2

h=2+p

h=2+2

h=4

Putting k=-2, p=2, h=4 in standard equation of parabola we get:

(y - k)2 = 4p (x - h)

(y-(-2))^2 = 4(2) (x - 4)

(y+2)^2 = 8 (x - 4)

y2+4y+4=8x-32

y2+4y+4+32=8x

x=y2/8+4y/8+36/8

x=y2/8+y/2+9/2!

See the attached picture:

[tex]|\Omega|=6^2=36\\A=\{(3,5),(5,3),(4,4),(2,6),(6,2)\}\\|A|=5\\\\P(A)=\dfrac{5}{36}\approx13.9\%[/tex]

Answer:

6.95 pounds. Her dog weighs 6.95 more pounds than the total weight of both her cats.

Step-by-step explanation:

To find the total weight of her cats, add their weights together:

9.8+8.25

=18.05 pounds

Then to find the difference between the weight of her dog and the weight of her cats' total weight, you subtract the weight of the cats from the weight of the dog:

25-18.05

=6.95 pounds

Answer:

The answer is FEG and EGF

The pair of angles, FEG and FGE, are nonadjacent and complementary, which means their sum is 90° but they do not have a common side.

Two angles are said to be complementary if their sum is 90° and two angles are supplementary if their sum is 180°.

We know two angles are complementary when their sum is 90°, and we also know that two angles are adjacent if they share a common side.

Here we have a pentagon with five sides.

The pair of angles are nonadjacent and complementary meaning their sum is 90° but they do not share a common side they are,

∠FEG and ∠FGE, because ∠FEG + ∠FGE = 55° + 35° = 90°.

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Answer:

The opción b

Step-by-step explanation:

the profit is defined by

[tex]Profit=Gain-cost[/tex]

In this case [tex](F-g)(100)=[/tex] is the profit to sell 100 television and is calculated

[tex]F(x)-g(x)=4x+5000-(20x-500)=4x-20x+5000+500=-16x+5500=-16*(100)+5500=3900[/tex]

[tex]3900=3.9k[/tex]

Answer:

The answer You're looking for is B)$3.9K is the profit from 100 TV's

Step-by-step explanation: