. Alfonso pushes a box on a well waxed (frictionless) floor to the right with a 20 N force causing it to accelerate at 1.5 m/s2 . What is the mass of the box?

Answers

Answer 1
Newtown's 2nd law:

F = m*a
F: force, m: mass, a: acceleration

Solve for m.
Answer 2

Answer:

The answer is m = 13.33Kg

Step by Step Explanation:

1- Taking into account Newton's second law (also known as the fundamental law of dynamics) we know that force is directly proportional to the mass and acceleration of a body.

2- This law is represented by the formula f = m.a where (f) represents force, (m) mass and (a) acceleration.

3- Having this formula, we can clear the mass (m) and replace the data given in the problem.

f = m.a

[tex]m = \frac{f}{a} \\m = \frac{20N}{1.5m/s^{2} } \\m = 13.33 kg[/tex]


Related Questions

If an object 70 millimeters high is placed 40 millimeters from a converging lens and the image is formed 120 millimeters in front of the lens on the same side as the object, what’s the height of the image?

Answers

The basic proportion we have to use is:
[tex]d_o:d_i = h_o:h_i[/tex]
where [tex]d_o[/tex] is the distance of the object from the lens (40 mm), [tex]d_i[/tex] the distance of the image from the lens (120 mm), [tex]h_o[/tex] the height of the object (70 mm) and [tex]h_i[/tex] the height of the image (that we have to find). Solving for [tex]h_i[/tex] we find
[tex]h_i = \frac{d_i \cdot h_o}{d_o} = \frac{(120 mm)(70 mm)}{40 mm}=210 mm [/tex]
so, the height of the image is 210 mm.

on Earth, how many grams of mass does it take to produce a force of 1 newton?

Answers

The weight of an object of mass m is equal to:
[tex]W=mg[/tex]
where [tex]g=9.81 m/s^2 [/tex] is the gravitational acceleration.

If we require a mass m to produce a force of 1 N, it means its weight is 1 N. Therefore, the required mass is:
[tex]m= \frac{W}{g}= \frac{1N}{9.81 m/s^2}=0.10 kg [/tex]

APEX!!! PLEADE HELP!!!!

A 60 kg man is moving at 2 m/s. What is his kinetic energy?

A. 240j
B. 120j
C. 60j
D. 30j

Answers

Hello there!

We need to use the formula for kinetic energy.

K.E = 0.5 * mv²

M represents the mass which is 60kg

V is the velocity which represents the speed of the moving which is 2 m/s

K.E  = 0.5 * 60 * 2²

K.E =  0.5 * 60 * 4

K.E = (30)(4)

K.E = 120

Remember that the answer should always be stated in Joules (J) which is the standard unit of measurement for Kinetic Energy.

Thus,

The correct answer is option B 120j

As always, I am here to help!

What does the index of refraction directly measure? the angle between the incident ray and the normal line the angle between the refracted ray and the normal line the bending of light in a medium the reflection of light in a medium

Answers

The bending of light in a medium

Answer:

The answer is The bending of light in a medium.

Explanation:

The refractive index is the dimensionless number that expresses the relationship between the speed of light in the air and the speed of light in the densest medium, that is, the refractive index directly measures the ratio of the velocity of the light in a vacuum and the speed of light in a medium. This phenomenon occurs because the light rays follow a rectilinear path, but when they pass from one means of transport to another, it is refracted, because the light has a velocity distance according to the density of the material it passes through. The refractive index has variables that affect the measurement, which are temperature, wavelength and pressure.

Does a physicist studies cells and life cycles?

Answers

Hey there!

No, that would be a biologist. Biologists study biology, or life. They're focused on life cycles, cells, evolution, and so much more.

Physicists focus on physics. They learn about forces, motion, and the study of the universal forces like gravity, momentum, and speed. Just like mathematics, they study patterns and look for new discoveries to be found in the fields of science, physics, and even mathematics.

Hope this helps!

Final answer:

Physicists may delve into biological concepts through biophysics, but the study of cells and life cycles is principally a field within biology, focused on by cell biologists.

Explanation:

No, A physicist primarily studies the fundamental principles governing the universe, such as energy, force, and matter. While physics does impact biological systems by explaining behaviors of molecules in cells or assisting in the creation of medical technology, the study of cells and life cycles specifically falls within the realm of biology.

Cell biology is a branch of biology focusing on the study of cellular structures and functions and is fundamentally concerned with the life cycle of cells. Physicists may contribute to this field through biophysics or biomedical applications, such as using physics principles to describe properties of cell membranes or developing diagnostic tools like MRI machines. However, the everyday work of studying cells and their life cycles is typically performed by biologists rather than physicists.

Why does the plot show vertical jumps at the melting and boiling points?

Answers

I think this happens because during melting or boiling at constant temperature, the entropy dramatically increases because energy is removed from the system during the change. Entropy increases with increase in temperature, entropy increases steadily with increasing temperature up to the melting point of the solid, where the entropy increases further due to addition of freedom of molecules which increases the randomness of the substance. At boiling point of liquid, another abrupt increase in entropy occurs, this results from increased volume available to the atoms or molecules as they enter the gaseous state. 

The work input = _____. Fi × di Fi ÷ di Fo × do Fo ÷ do

Answers


I believe the work input= Fi × di. Work input is work done on a machine equal to the effort force times the distance through which the force is applied. On the other hand the work output is the work that is done by a machine equals resistance force times the distance through which the force is applied.

an example of a Destructive force is the formation of mountains True or False?

Answers

Hey there!

An example of a Destructive force is the formation of mountains.

This statement is false, an example of a destructive force would not be the formation of mountains.

Hope this helps you.
Have a great day!

A uniform bridge 20.0m long and weighing 4.00 x 10^5 N is supported by two pillars located 3.00m from each end. If a 1.96 x 10 ^4N car is parked 8.00m from one end of the bridge. How much force does each pillar exert?

Answers

Final answer:

The left support exerts a force of 2.0392 x 10⁵ N and the right support exerts a force of 2.1568 x 10⁵ N on the bridge. This is calculated by considering the total weight supported by the bridge and the location of the car.

Explanation:

The problem you are asking about relates to static equilibrium, a concept in Physics. To find the force exerted by each pillar, we must first find the total weight supported by the bridge. The total weight is the sum of the weight of the bridge itself (4.00 x 10⁵ N) and the weight of the car (1.96 x 10^4 N), which gives us a total of 4.196 x 10⁵ N.

The location of the car changes the balance of these forces. The first pillar is 8m from the car and the second pillar is 12m from the car. To find the force on each pillar, we apply the principle that the sum of the moments about any point in a system in equilibrium is zero. Using the left pillar as the point, the moments of the bridge's weight and the car's weight are counterbalanced by the force of the right pillar:

Force_right_pillar = (Bridge_weight * Bridge_mid_point + Car_weight * Distance_from_left_pillar) / Total_bridge_length = ((4.00 x 10⁵ N * 10m) + (1.96 x 10⁴ N * 8m)) / 20m = 2.1568 x 10⁵ N.

The force exerted by the left pillar is then the total weight minus the force on the right pillar: Force_left_pillar = Total_weight - Force_right_pillar = 4.196 x 10⁵ N - 2.1568 x 10⁵ N = 2.0392 x 10⁵ N. So, the left support exerts a force of 2.0392 x 10⁵ N, and the right one exerts a force of 2.1568 x 10⁵ N.

Learn more about Static Equilibrium here:

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The forces exerted by the pillars supporting a 20.0m long and [tex]4.00 * 10^5 N[/tex] bridge with a [tex]1.96 * 10^4 N[/tex] car parked 8.00m from one end are approximately [tex]2.13 * 10^5 N[/tex] and [tex]2.07 * 10^5 N[/tex].

To find the forces exerted by each pillar on the uniform bridge, we need to consider the torque (moment of force) and the equilibrium conditions of the bridge.

Here is the step-by-step solution:

Given Data:

Length of the bridge (L) = 20.0 mWeight of the bridge [tex](W_{bridge}) = 4.00 * 10^5 N[/tex]Weight of the car [tex](W_{car}) = 1.96 * 10^4 N[/tex]Distance of each pillar from the end = 3.00 mPosition of the car from one end = 8.00 m

The two pillars provide upward forces labeled as [tex]F_L[/tex] and [tex]F_R[/tex].

1. Identify the distances to center of mass:

Center of mass of bridge from left end = 10.0 mPosition of car from left end = 8.0 m

2. Set up equilibrium equations:

Since the bridge is in static equilibrium, the sum of the forces and the sum of the torques must be zero.

Sum of Vertical Forces:

[tex]F_L + F_R - W_{bridge} - W_{car} = 0\\F_L + F_R = 4.00 * 10^5 N + 1.96 * 10^4 N\\F_L + F_R = 4.196 * 10^5 N[/tex]

Sum of Torques about the left pillar (taking counterclockwise as positive):

[tex]-(W_{bridge} * 7.0 m) - (W_{car} * 5.0 m) + (F_R * 14.0 m) = 0\\-(4.00 * 10^5 N * 7.0 m) - (1.96 * 10^4 N * 5.0 m) + (F_R * 14.0 m) = 0\\-2.8 * 10^6 Nm - 9.8 * 10^4 Nm + 14 F_Rm = 0\\14 F_R = 2.898 **10^6 Nm\\F_R = 2.898 * 10^6 Nm / 14 m\\F_R = 2.07 * 10^5 N\\[/tex]

Substitute F_R back into the sum of the forces equation:

[tex]F_L + 2.07 * 10^5 N = 4.196 * 10^5 N\\F_L = 4.196 * 10^5 N - 2.07 * 10^5 N\\F_L = 2.126 * 10^5 N\\[/tex]

Result:

The forces exerted by the pillars are approximately:

[tex]F_L = 2.13 * 10^5 N\\F_R = 2.07 * 10^5 N[/tex]

Match the terms

Term Definition

Chromosphere A) Layer of the sun where energy is transferred by thermal conduction.

Photosphere B) Contains the sun's outer shell from which light energy is radiated.

Radiative zone C) Layer of the sun that is known for its red color and can only be seen during eclipses

Corona D) The plasma that surrounds the sun

Answers

Explanation :

(1) Chromosphere: It is a layer above the photosphere. The temperature in chromosphere increases  from  [tex]6000^0\ C[/tex] to [tex]20,000^0\ C[/tex]. This layer is known for its red color and can only be seen during eclipses.

(2) Photosphere: It is the outer layer of the star which contains sun's outer shell from which light energy is radiated.

(3) Radiative zone: it is a layer of sun where energy is transmitted towards via radiative diffusion or conduction.

(4) Corona: It is a plasma that surrounds the sun and the other stars.

Hence, this is the required definitions.

Answer:bdca

Explanation:

Give an example to explain that motion is relative in nature

Answers

Consider a long train moving at speed v. Now consider a passenger throwing a ball inside this train, towards the back of the train, with same velocity v (but in the opposite direction of the train movement). 

- A passenger inside the train will see the ball moving with speed v
- For an observer outside the train, however, the ball will appear as still. In fact, for him the ball will have a speed v (given by the movement of the train) -v (velocity of the ball but moving in the opposite direction), so the net velocity will be v+(-v)=0. 

Newton concluded that some force had to act on the moon because

Answers

Think in gravity, the moon is orbiting the Earth because of gravitational pull/force. Without this gravitational pull, the moon will just move in a straight line (Newton's first law).

Newton concluded that some force had to act on the moon because it is constantly accelerating towards Earth.

Without such a force, according to Newton's First Law, the Moon would continue in a straight path instead of orbiting the Earth. In 1666, he recognized that this centripetal force was necessary to maintain the Moon's circular path. He also theorized that the gravitational force must be proportional to the masses of the Earth and the Moon and that it follows an inverse-square relationship with distance.

Newton's insight was that the same force that causes an apple to fall to the ground also keeps the Moon in orbit around the Earth. This led him to deduce the Law of Universal Gravitation. According to Newton's Second Law, the moon's acceleration towards Earth indicated a centripetal force, which he later defined in his Principia using his laws of motion and the newly formulated concept of gravitational force.

Furthermore, Newton discovered that the gravitational force between any two bodies not only follows the Universal Law of Gravitation but also forms an action-reaction pair, satisfying his Third Law of Motion. This was a crucial realization for Newton to fully explain the motion of the planets and the gravitational pull between the Earth and the Moon.

A 0.025m radius toy top is spinning at a rate of 150rpm, what is the angular velocity? What is the linear velocity of the paint on the outside edge?

Answers

a) The angular velocity of the disk is 150 rpm (revolutions per minute). We can convert it into proper units, i.e. radiants per seconds, keeping in mind that:
[tex]1 rev = 2 \pi rad[/tex]
[tex]1 min = 60 s[/tex]
so the angular speed is
[tex]\omega = 150 \frac{rev}{min} = 150 \frac{2 \pi rad}{60 s} =15.7 rad /s[/tex]

b) The linear velocity is given by
[tex]v=\omega r[/tex]
since the radius is r=0.025 m, the linear velocity at the edge of the disk is
[tex]v= \omega r = (15.7 rad/s)(0.025 m)=0.39 m/s[/tex]

Which of the following refers to a combination of substances in which the components are evenly mixed?

A. Heterogeneous mixture
B. Ion
C. Compound
D. Homogeneous mixture

Answers

I believe it’s D. Homogenous mixture
It is rather A or D

Planet B has a tilt of 45 degrees. What seasonal changes would be expected on this planet?
A. Extreme temperature changes between seasons 
B. Little to no change in temperatures between seasons
 
C. Seasonal changes along the equator only
 
D. Seasonal changes at the poles only

Answers

... Extreme temperature changes between seasons.

... Extreme changes in length of daylight and darkness.

... Larger areas around both poles where daylight/darkness
can last more than a whole day. 
Altogether, these areas cover half of the planet. 

Answer:

Extreme temperature changes between seasons

Explanation:

If our Earth is at a rotational degree of 23 degrees, then the planet is going to experience bigger changes between how hot and how cold it is going to be.

A college student holds a pail full of water by the handle and whirls it around in a vertical circle at a constant speed. the radius of this circle is 0.95 m. what is the minimum speed that the pail must have at the top of its circular motion if the water is not to spill out of the upside-down pail

Answers

Here we have a circular motion. In that type of motion two new forces appear: centrifugal and centripetal. Centrifugal force tries to move object away frome the center of rotation. Centripetal force is the reason why object moves in a circle.

According to Newton's first law, in order for water not to spill out total force acting on water must be equal to zero. Forces acting on the water are gravitational and centrifugal.
[tex]0= F_{g} + F_{c} \\ - [tex]F_{g} = F_{c} \\ m*g= \frac{m* v^{2} }{r} \\ g= \frac{ v^{2} }{r} \\ v^{2} =g*r \\ v= \sqrt{g*r} \\ v= \sqrt{9.81*0.95} \\ v= \sqrt{9.3195} \\ v=3.1 m/s[/tex] [/tex]

Forces have opposite signs as they act in opposite directions. But their value is the same so we can ignore signs:

a doghouse has a mass of 98 kg, and the coefficient of friction between it and the ground is 0.95. what is the maximum force of friction between the doghouse and the ground?

Answers

Answer:

Maximum force of friction, F = 912.38 N

Explanation:

It is given that,

Mass of doghouse, m = 98 kg

Coefficient of friction between doghouse and the ground, μ = 0.95

We have to find the maximum force of friction between the doghouse and the ground. It is given by :

F = μ N

N = normal force = mg

F = μmg

F = 0.95 × 98 kg × 9.8 m/s²

F = 912.38 N

Hence, this is the required solution.

Which are examples of projectile motion? Check all that apply. a kicker punting a football a car traveling along a highway a free throw in basketball a ball rolling downhill a person throwing darts

Answers

A projectile is any object that is cast, fired, flung, heaved, hurled, pitched, tossed, or thrown.

A kicker punting a football, a free throw in basketball and a person throwing darts are some examples of projectile motion.

What is a projectile motion?

It is the movement of any item or material when it is launched from the planet's surface and takes any curving course while being affected by the pull of gravity of the planet.

This movement style The only force affecting our objects is gravity. Different projectile kinds are available.

A football is thrown upward, being kicked and imparting speed at an angle from the horizontal, or just being dropped and allowed to fall independently are all examples of the initial velocity.

Thus, a kicker punting a football, a free throw in basketball and a person throwing darts are some examples of projectile motion.

Learn more about projectile motion from here,

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explain the role that the ant and the acacia tree play in their symbiotic relationships

Answers

The presence of mutualistic ants greatly reduces bacterial abundance on surfaces of acacia leaves and has a visibly positive effect on plant health

The current in an electron beam in a cathode ray tube is 7.0 X 10^-5 A. A beam of electrons is aimed at a screen. How much charge hits the screen in 5.0S?

A- 2.8X10^3 C

B-5.6X10^-2 C

C-3.5X10^-4 C

D-5.3X10^-6 C

Answers

The current I is defined as the quantity of charge Q that flows in the tube in the unit of time t:
[tex]I = \frac{Q}{t} [/tex]
In our problem, we have [tex]I=7\cdot 10^{-5} A[/tex] and the time is t=5.0 s. Therefore we  can find the charge that hits the screen during this time:
[tex]Q=It =7\cdot 10^{-5} A \cdot 5.0 s=3.5X10^{-4} C[/tex]

Lena would like to be able to know her exact location on a map as she travels across the country. Which technology would best help Lena?

Answers

D) GPS, because it uses satellites that provide position and velocity data 

2. A 200-kg boulder has 39,200 joules of gravitational potential energy. What height is it at?


3. A 1-kg model airplane has 12.5 joules of kinetic energy and 98 joules of gravitational potential energy. What is its speed? What is its height?

Answers

We have that the gravitational energy is given by: U=mgh where m is the mass of the object (in kg), g is the gravitational acceleration and h is the height of the object (in meters). Hence, h=U/(m*g) where g=9.8 m/s^2. Thus, h=20 m if we substitute.
Similarly, substituting in b, we have that the height of the model plane is 10 m. The kinetic energy is given by: K=[tex] \frac{1}{2} *m*u^2[/tex] where u is the speed of the object. Hence, solving for u we have u=[tex] \sqrt{2K/m} [/tex]. Substituting, we have that u=5m/s.

As per the first question we have to calculate the height at which the boulder is present.

we have been given the mass of the boulder [m] as 200 kg.

The gravitational potential energy is given as 39,000 Joule.

The gravitational potential energy at a height ' h'  from the surface earth is given as P.E= mass×height×acceleration due to gravity

The value of g=9.8 m/s^2

   Hence height [h][tex]=\frac{P.E}{mg}[/tex]

                              =[tex]\frac{39000}{200*9.8} metre[/tex]

                              =19.8979 metre

As per the second question we have to calculate the sped and height of the model airplane.

the mass of model airplane is 1 kg

The kinetic energy [K.E] of the airplane is 12.5 joule

we have K.E[tex]=\frac{1}{2} mass*speed^2[/tex]

                K.E[tex]=\frac{1}{2}mv^2[/tex]

                 [tex]v^2=\frac{2K.E }{m}[/tex]

                  [tex]v^2=\frac{2*12.5}{1}[/tex]

                    [tex]v=\sqrt{25}[/tex]

                      v=5 m/s

Again we have to calculate the height [h]

The potential energy is given as 98 Joule.

we know that P.E= mgh

                        tex]h=\frac{P.E}{mg}[/tex]  

                       =[tex]\frac{98}{1*9.8} metre[/tex]

                       =10 metre


A weightlifter raises a 200-kg barbell through a height of 2 m in 2.2 s. the average power he develops during the lift is

Answers

Power is calculated as work per unit time, and work in turn is calculated as force multiplied by distance. In this case, the force required is equivalent to the weight of the barbell multiplied by acceleration due to gravity.
P = W/t = Fd/t = mgd/t = (200 kg)(9.81 m/s^2)(2 m)/2.2 s = 1783.64 Watts.

Answer:

Power, P = 1781.81 watts

Explanation:

It is given that,

Mass of the barbell, m = 200 kg

It is lifted to a height of, h = 2 m

Time taken, t = 2.2 s

We need to find the develops during the lift. We know that the pwer developed by an object is equal to the rate of doing work. Mathematically, it is given by :

[tex]P=\dfrac{W}{t}[/tex]

[tex]P=\dfrac{mgh}{t}[/tex]

[tex]P=\dfrac{200\times 9.8\times 2}{2.2}[/tex]

P = 1781.81 watts

So, the average power developed during the lift is 1781.81 watts. Hence, this is the required solution.

A flea jumps straight up to a maximum height of 0.540 m . what is its initial velocity v0 as it leaves the ground?

Answers

For an uniformly accelerated motion, we can write
[tex]2ah=v_f^2-v_0^2[/tex]
where [tex]a=g=-9.81 m/s^2[/tex] is the acceleration of this motion, which in this problem is the gravitational acceleration, with a negative sign because it points downward, against the direction of the motion; h=0.540 m is the distance covered by the flea, and [tex]v_0[/tex] is the initial velocity. 

At the maximum height, the velocity is zero, so [tex]v_f =0[/tex]. Therefore we  can solve to find [tex]v_0[/tex]:
[tex]v_0 = \sqrt{2ah}= \sqrt{2(9.81 m/s^2)(0.540 m)} =3.25 m/s[/tex]

What is the angle between a light ray and its wavefront?

Answers

always 90 degrees                               .                        .                               .

find the mass of a flying discus that has a net force of 1.05 newtons and accelerates at 3.5 m/s^2

Answers

f=ma
m=1.05/3.5= 0.3kg

One’s behavior cannot be affected by one’s subconscious

Answers

That statement is false

Our subconscious tend to give a strong influence to our behaviours even if we are not feeling it directly.

For example, let's say that there is a boy that hurt by cats and it's ingrained in his head that cats possess high level of danger to him. Even after that boy grow up, his subsconcious would most likely cause a certain level of paranoia that make him either scared of cats or simply annoyed by seeing them.

Answer:

False is the correct answer

Explanation:

Peace and Love

Why can an object still be seen when it is at absolute zero?

Answers

As the temperature goes down, the chaotic motion (velocity) of atoms start decreasing. If the temperature hits the absolute zero (which, in reality, is impossible to achieve), the atoms of the body would freeze, making the body still and stiff. One thing to note here is that the atoms do not get destroyed when the temperature reaches the absolute zero. That is the reason why the object can still be seen when it is at absolute zero.

A 150 kg hoop rolls along a horizontal floor so that the hoop's center of mass has a speed of 0.130 m/s. how much work must be done on the hoop to stop it?

Answers

The work needed is equal to the KE of the hoop which is = 150 * 0.130^2 / 2 ...(1) 
Let the following be:r be the radiuscenter of mass in the moment of inertia is denoted by:
I = 150 r^2 kg m^2. 
The angular velocity relative to the center of mass is: 
w = 0.130 / r rad / s. 
Rotational KE = Iw^2 / 2 
= (150 * r^2) (0.130 / r)^2 / 2 
= 150 * 0.130^2 / 2 J ...(2) 
Adding (1) and (2): 
Total KE = 130 * 0.130^2 
= 2.2 J.

If you shook the end of a rope up and down 5 times each second, what would be the period of the waves set up in the rope?

Answers

Shooking the rope up and down 5 times per seconds means that there are 5 cycles of the wave (or 5 crests) in one second, and so its frequency is [tex]f=5 Hz[/tex]. 

The period T is the reciprocal of the wave's frequency, therefore it is
[tex]T= \frac{1}{5 Hz}=0.20 s [/tex]

Final answer:

Shaking the rope at 5 times per second sets up waves with a frequency of 5 Hz. The period of these waves, which is the inverse of frequency, would be 0.2 seconds.

Explanation:

When you shake the end of a rope up and down 5 times each second, you are creating waves with a certain frequency. The frequency is the number of complete waves that pass a given point in one second, and it is measured in hertz (Hz). Since you're shaking the rope 5 times per second, the frequency of the waves set up in the rope is 5 Hz.

The period of a wave is the time it takes for one complete wave cycle to pass a point. It is the inverse of the frequency. To calculate the period (T), you would use the formula:

T = 1 / f, where 'f' is the frequency.

So in this case:

T = 1 / 5 Hz = 0.2 seconds.

Therefore, the period of the waves set up in the rope is 0.2 seconds.

Other Questions
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