ashley measure the shell she collect she records the measurements in the chart

The new yearly salary is $28,140.

Amount of raise.
5%=0.05 
Multiply the original salary times the percentage of the raise.

$26,800×0.05=$1,340

New salary .

$26,800+1,340=$28,140

HOPE THIS HELPS! :)

This question is based on the concept of percentage. Therefore new salary when there is 5% raise in 26,800 is 28,140. There are many uses of calculating percent.

Percent is a proportionate of a number. Percent is a dimensionless quantity that is it has no unit. Percent is always out of hundred whereas fraction is always from 1. It is represented with the sign %. There are many uses of calculating percent. It is used in calculating interest in bank. It used in calculating inflation rate.

Mathematically,

The new yearly salary  of a person is 28,140.

percentage of raise in salary is

5%=0.05

Multiply the original salary and  the percentage of the raise in salary

26,800×0.05=1,340

New salary =26,800+1,340=28,140

Therefore new salary when there is 5% raise in 26,800 is 28,140

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Answer:

Its D i just took the test

Step-by-step explanation:

Answer:

D. g=7 and h=3

Step-by-step explanation:

Final answer:

To solve the expression 2(√(80/5) - 5), we simplify the square root first, then subtract 5, and finally multiply by 2, which results in the solution -2.

Explanation:

To solve the expression 2(√(80/5) - 5), let's first simplify the square root and the division inside it.

We have √(80/5) = √16 = 4, since 80 divided by 5 is 16, and the square root of 16 is 4.

Next, we subtract 5 from 4: 4 - 5 = -1.

Finally, we multiply the result by 2: 2 * (-1) = -2.

Therefore, the solution to the expression 2(√(80/5) - 5) is -2.

The answer to the given question is: [tex]\[ 2\left(\frac{\sqrt{80}}{5} - 5\right) = \frac{2\sqrt{80}}{5} - 10 \][/tex]

To solve the expression step by step:

 1. First, simplify the square root within the parentheses. The number 80 can be factored into [tex]\( 16 \times 5 \)[/tex], and since [tex]\( \sqrt{16} = 4 \),[/tex] we can rewrite[tex]\( \sqrt{80} \) as \( 4\sqrt{5} \).[/tex]

[tex]\[ 2\left(\frac{4\sqrt{5}}{5} - 5\right) \][/tex]

2. Next, distribute the 2 across the terms inside the parentheses:

[tex]\[ 2 \times \frac{4\sqrt{5}}{5} - 2 \times 5 \][/tex]

 3. Simplify each term:

[tex]\[ \frac{8\sqrt{5}}{5} - 10 \][/tex]

 4. At this point, we have the simplified form of the expression. However, if we want to combine the terms into a single fraction, we need a common denominator. The second term, -10, can be written as [tex]\( \frac{-10 \times 5}{5}[/tex]) to get the common denominator of 5:

[tex]\[ \frac{8\sqrt{5}}{5} - \frac{50}{5} \][/tex]

 5. Now, subtract the two fractions:

[tex]\[ \frac{8\sqrt{5} - 50}{5} \][/tex]

 6. This is the final simplified form of the expression. It cannot be simplified further algebraically because [tex]\( 8\sqrt{5} \)[/tex] and 50 do not have common factors other than 1.

Therefore, the final answer is: [tex]\[ \boxed{\frac{8\sqrt{5} - 50}{5}} \][/tex]

[tex]\[ 2\left(\frac{\sqrt{80}}{5} - 5\right) \][/tex]

And the final simplified answer is: [tex]\[ 2\left(\frac{\sqrt{80}}{5} - 5\right) = \frac{2\sqrt{80}}{5} - 10 \][/tex]

Answer:

  the number decreased by 80%

Step-by-step explanation:

The percentage change can be computed using ...

  percent change = ((new value)/(old value) -1) × 100%

Putting the given numbers into this equation gives ...

  percent change = (6/30 -1) × 100% = -4/5 × 100%

  percent change = -80%

A negative sign on the percent change means the change was a decrease. The number of students who went to tutoring decreased by 80%.

Answer:

thanks

Step-by-step explanation:

Answer:

They just have 2 factors :/

Step-by-step explanation:

Bc yes

The formula for a parabola with roots at x=-8 and x=-4, and which passes through the point (0,-7), is y = -7/32(x + 4)(x + 8).

The formula we're looking for is in the form of a quadratic function, generally expressed as

y = ax² + bx + c. Our roots are -8 and -4, which we represent in the factors of the equation as (x + 4) and (x + 8). As coefficients multiply to a, we seek a that makes our function pass through the specific point (0, -7). Thus, we substitute the point into the function giving -7 = a(0+4)(0+8) leading us to a = -7/32. So, the equation of the parabola asked is

y = -7/32(x + 4)(x + 8).

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The area of the two designs are given as 52 square inches and 61.375 square inches.

In these the second design 61.375 square inches is having the greater area.

If 500 envelops are made then area of paper = 61.375x500 =30687.5 square inches.

If envelops having 52 square inches are made out of 30687.5 square inches of paper ,number of envelops made =30687.5 ÷ 52=590.144

590 small envelops can be made having area as 52 square inches.

It is 590-500=90 more than the larger envelops made.

In Juanita's science experiment, the attribute measured is the plant's height, a key phenotypic trait in studying plant growth, which she records in centimeters, using consistent and precise units for scientific reliability.

The attribute measured in Juanita's science experiment is the height of a plant, which is a phenotypic trait important in plant biology. Juanita is collecting data related to plant growth by observing and recording the plant's height in centimeters daily. This meticulous tracking allows for analysis of plant growth patterns over time and the effect of various treatments, such as different fertilizers or amounts of water. The typical unit of measurement for the height of a plant is in centimeters or meters, which are part of the metric system used in scientific research.

During a laboratory experiment like the one Juanita is conducting, it is essential to measure such variables with precision and consistency. Measurements should be recorded using uniform units and methods to ensure reliability in the results, which may include the plant height, recorded in centimeters, at regular intervals. A graph representing this data might portray the number of days since the start of the experiment along the X-axis and the plant's height along the Y-axis, thereby allowing a visual assessment of the plant's growth over time.

To calculate the percentage of players weighing 194 pounds or more from a box plot, we need to know where 194 pounds falls in relation to the quartiles on the plot. Without the box plot details, we cannot perform the needed analysis.

The student's question appears to concern the analysis of a box plot depicted in their materials to find the percentage of players weighing 194 pounds or more on a football team. However, to accurately answer this question, we need the specific details from the box plot, including the median (Q2), first quartile (Q1), third quartile (Q3), and any outliers if provided. From the box plot, we would determine where the weight of 194 pounds falls in relation to the quartiles. If 194 pounds is at or above Q3, then you would expect a lower percentage of players above this weight; if it is below Q3, then the percentage could be higher.

The approach typically involves identifying the number of players within each quartile and calculating the corresponding percentages. Without the specific box plot data, we cannot perform these calculations. Should you provide the box plot details, we can review the quartiles and calculate the exact percentage of players weighing 194 pounds or more.

Final answer:

The trace on the xy-plane of a sphere with center (-1, 3, -1) and radius 2 is a circle with center (-1, 3) and radius 2, represented by the equation (x + 1)² + (y - 3)² = 4.

Explanation:

The question asks to find the trace on the xy-plane of the sphere having a center at (-1, 3, -1) and a radius 2.

The trace on the xy-plane of a sphere is essentially the circle that is formed when the sphere intersects the xy-plane.

Since the center of the sphere is (-1, 3, -1), and the sphere intersects the xy-plane (z=0), we keep the x and y coordinates of the center the same for the circle, meaning the center of the circle will be (-1, 3). The radius of the circle remains the same as the sphere, which is 2.

The equation for a circle in the xy-plane with center (h, k) and radius r is given by (x - h)² + (y - k)² = r².

Therefore, plugging in the values for this specific circle gives us the equation (x + 1)² + (y - 3)² = 4.

This equation represents the trace of the sphere on the xy-plane.