Below you can see the energy levels of the Helium atom. The right axis is a quantum number related to angular momentum (do not worry too much about that). An electron is in the state 2s and after a little while it decays back to the ground state. What is the energy of the photon emitted?

Answer:

1.5m

Explanation:

Velocity=1500m/s

Frequency=1000hz

Wavelength =velocity ➗ frequency

wavelength =1500 ➗ 1000

Wavelength=1.5m

The wavelength of a sound, given a frequency of 1000 Hz and a speed of 1500 m/s, is 1.5 meters as determined by using the formula Wavelength = Speed / Frequency.

In the field of Physics, the wavelength of a sound is calculated using the speed of sound and its frequency. The speed at which sound travels is given as 1500 m/s, and the frequency of sound as 1000 Hz. The formula used to calculate wavelength is Speed = Frequency x Wavelength. In this case, rearranging to find wavelength gives us, Wavelength = Speed Frequency. Therefore, the wavelength of the sound is 1500m/s / 1000Hz, which equals 1.5 meters.

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Answer:

The width would decrease

Explanation:

The width of central maximum of screen is proportional to wavelength of light and wavelength of light in water is less than that of air

If the apparatus were submerged in water, the width of the central peak as a part of the light diffraction pattern would decrease. This is because water slows down light more than air does - reducing the wavelength and therefore narrowing the central peak.

If the entire apparatus were submerged in water, the width of the central peak would indeed change. This is due to the phenomenon of diffraction, which describes the way waves spread out when they pass through an opening. The central peak referred to in the question is a part of the diffraction pattern observed when light passes through a slit.

When diffraction occurs, a pattern of bright and dark spots, or 'fringes', is created. The width of these fringes is determined by the wavelength of the light and the size of the opening. If we were to submerge the entire apparatus in water, the diffraction pattern would change. This is because water has a higher refractive index than air, meaning it slows down the light more. As a result, the wavelength of the light in water becomes smaller compared to that in air. According to the formula for diffraction, the smaller the wavelength, the narrower the central peak. So in conclusion, if the apparatus were submerged in water, the width of the central peak would decrease.

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Please ignore that i attempted this question

Answer:

Velocity after collision will be 20 m/sec

Explanation:

We have given mass of arrow [tex]m_1=0.5kg[/tex]

Mass of arrow [tex]v_1=60m/sec[/tex]

Mass of apple [tex]m_2=1kg[/tex]

Apple is at rest so velocity of apple [tex]v_2=0m/sec[/tex]

According to conservation of momentum

Momentum before collision is equal to momentum after collision

[tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]

[tex]0.5\times 60+1\times 0=(0.5+1)v[/tex]

[tex]1.5v=30[/tex]

v = 20 m/sec

Answer:

Explanation:

The system is made up of three body system which are the boulder, earth and the moon also the sum of potential ad kinetic energies are assumed to be the same also note that the boulder was launched from the moon at an initial velocity

A ) Minimum speed of the boulder for it to reach the earth = 2.3 km/s

B) ignoring air resistance the impact speed on earth of a boulder launched at this minimum speed = 11 km/s

find attached the solution in details

Answer:

car1: a=3.1m/s^2 , car2: a=6.1m/s^2

(a) 1/2*3.1*t^2= 1/2*6.1*(t-0.9)^2

1.55t^2= 3.05(t^2-1.8t+0.81)= 3.05t^2-5.49t+2.4705

1.5t^2-5.49t+2.4705= 0

t= 3.13457 = 3.14[s] after.

(b) d= 1/2*3.1*3.13457^2= 15.23[m] approx.

(c) car1: v=at = 3.1*3.13457= 9.717m/s

car2: v=at = 6.1*(3.13457-0.9)= 13.631m/s

13.631-9.717= 3.914 = 3.91[m/s] faster than car1.

At the time after 3.14 seconds, car1 is overtaken by car2, this will happen after 15.23 meters and car2 is 3.914 m/s faster than car1.

In mechanics, acceleration is the measure of how quickly an object's velocity changes in relation to time. The quantity is a vector. An object's acceleration is determined by the direction of the net force exerted on it.

Acceleration is a vector quantity since it has a magnitude and a direction. A vector quantity is also velocity. Acceleration is defined as the change in velocity vector over a time interval divided by the time interval.

There are several types of acceleration :

(a)

1/2 × 3.1×  t²

⇒ 1/2 × 6.1 × (t-0.9)²

⇒1.55t²= 3.05 (t² - 1.8t + 0.81)

⇒ 3.05t² -5.49t + 2.4705

=1.5t² -5.49t +2.4705= 0

t= 3.14 seconds.

(b)

d= 1/2 × 3.1 × 3.14²

= 15.23 meters

(c)

car1: v=at

⇒3.1 × 3.14

= 9.717 m/s

car2:

v=at

⇒ 6.1 × (3.14 - 0.9)

= 13.631 m/s

13.631-9.717= 3.914 m/s

Hence, car2 is 3.914 m/s faster than car1.

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Answer:

Explanation:

Given that,

The spring constant

K = 1N/m

Frequency of motion

f = 14Hz

We want calculate the mass m?

The frequency of spring system is related to the mass by

From w = √k/m

Where w = 2πf

f = 1/2π √k/m

Where,

w is angular frequency in rad/s

m is mass of object attached in kg

k is the spring constant in N/m

f Is the frequency in Hz

Then, make m subject of formula

Multiply both sides by 2π

2πf = √k/m

Square both sides

4π²f² = k/m

Then, k= 4π²f² × m

m = k / 4π²f²

m = 1 / (4π² × 1.4)

m = 1 / 55.27

m = 0.0181 kg

m= 18.1 g

The mass of the object attached in 18.1 g or 0.0181 kg

Final answer:

To find the mass attached to a spring with a known frequency of 1.4 Hz and a spring constant of 1 N/m, we use the formula for the frequency of a spring-mass system, resulting in a mass of approximately 0.081 kg.

Explanation:

The question asks about finding the mass attached to a spring when the frequency of motion is known, assuming no friction. The formula to determine the frequency of a spring-mass system is given by f = (1/2π)∙(k/m)^½, where f is the frequency in hertz, k is the spring constant in Newtons per meter, and m is the mass in kilograms. Given the frequency of 1.4 Hz and a spring constant of 1 N/m, we rearrange the formula to solve for m: m = k / (2πf)^². Substituting the given values, we calculate the mass as follows: m = 1 / (2π(1.4))^² ≈ 0.081 kg. Therefore, the mass attached to the spring is approximately 0.081 kilograms.

Answer:

(a). [tex]{\vec{p} =(1.6*10^{-22}\bold{i}+1.6*10^{-22}\bold{j})m \cdot C.}[/tex]

(b). [tex]U = 4.8*10^{-20}J.[/tex]

Explanation:

(a).

The electric dipole moment of the charges is

[tex]\vec{p} = q \vec{r}[/tex]

In our case

[tex]\vec{r} = (1.0*10^{-3}\bold{i}+1.0*10^{-3}\bold{j})m[/tex]

and

[tex]q =1.6*10^{-19}C[/tex];

therefore, the dipole moment is

[tex]\vec{p} =1.6*10^{-19}C *(1.0*10^{-3}\bold{i}+1.0*10^{-3}\bold{j})m[/tex]

[tex]\boxed{\vec{p} =(1.6*10^{-22}\bold{i}+1.6*10^{-22}\bold{j})m \cdot C.}[/tex]

(b).

The work done [tex]U[/tex] by an external electric field [tex]\vec{E}[/tex] is

[tex]U = -\vec{p}\cdot \vec{E}[/tex]

[tex]U = [1.6*10^{-22}\bold{i}+1.6*10^{-22}\bold{j}] \cdot[300\bold{i}][/tex]

[tex]\boxed{U = 4.8*10^{-20}J.}[/tex]

Answer:

The new angular speed is 2/3omega

Explanation:

See attached handwritten document for more details

Answer:

2ω/3

Explanation:

The moments of inertia of the 1st disk is:

[tex]I_1 = (2MR^2)/2 = MR^2[/tex]

The moments of inertia of the 2nd disk is:

[tex]I_2 = MR^2/2[/tex]

So the total moments of inertia of the system of 2 disks after the drop is:

[tex]I = I_1 + I_2 = MR^2 + MR^2/2 = 1.5MR^2[/tex]

Using law of angular momentum conservation we have the following equation for before and after the drop

[tex]I_1\omega = I\omega_2[/tex]

[tex]\omega_2 = \omega\frac{I_1}{I} = \omega\frac{MR^2}{1.5MR^2} = 2\omega/3[/tex]

Answer:

Explanation:

Heat capacity = mass x specific heat

heat capacity ∝ mass

∝ volume

heat capacity ∝ volume

H₁ / H₂ = V₁ / V₂

H₁ and H₂ are heat capacity corresponding to volume V₁ and V₂.

312 / 100000  = 1 / V₂

V₂ = 100000 / 312

= 320.51 cubic foot.

Answer:

the second wave will be heard at [tex]2*10^{-3} \ sec[/tex] after the first sound wave.

Explanation:

Given that:

two speakers are placed 500 meters away from each other and a person is standing in the middle;

that implies that the distance of the speed of the wave travelling  is divided into two equal which is 250 m

Now; from the first speaker, time to reach sound wave is;

[tex]t_1 = \frac{250}{v_1}[/tex]

[tex]t_1 = \frac{250}{343}[/tex]

[tex]t_1 = 0.728 \ sec[/tex]

Also from the second speaker; time to reach sound wave is;

[tex]t_2 = \frac{250}{v_2}[/tex]

[tex]t_2 = \frac{250}{342}[/tex]

[tex]t_2 =0.730 \ sec[/tex]

[tex]t_2 - t_1 = (0.730 - 0.728 )\ sec[/tex]

[tex]= 0 .002 \ sec\\\\= 2*10^{-3} \ sec[/tex]

Thus, the second wave will be heard at [tex]2*10^{-3} \ sec[/tex] after the first sound wave.

Complete Question

The complete question is shown on the first uploaded image s

Answer:

The container that had more heat transfer is container B

Explanation:

     From the question we are told that

            The initial temperature of water i both container is [tex]\theta_i = 20^oC[/tex]

 generally the rate of heat transfer is mathematically represented as

                                     [tex]Q = mc\Delta T[/tex]

  in the  question we can see that the temperature is same for the both water in the container but their masses are the same and from the equation we can see that each parameter varies directly with the  rate of heat transfer so it then mean that the water in container B would have more heat transfer because its mass is greater.

The container with more water had more heat transferred to it, as the heat required to change the temperature of a substance is proportional to its mass and specific heat capacity.

The question addresses a scenario involving two water containers with different volumes heated to certain temperatures and asks which container had more heat transferred to it. This is a classic example in the study of calorimetry, where heat transfer results in temperature changes. To determine which container received more heat, the concept of heat capacity and the formula Q = mcΔT (where Q is heat energy, m is mass, c is specific heat capacity, and ΔT is the change in temperature) can be applied.

In this case, since both containers started at room temperature and reached their respective final temperatures, the amount of heat absorbed or lost is directly proportional to the mass (volume of water) and their specific heat capacity. Given that water's specific heat capacity is constant, the container with the larger volume of water would require a larger amount of heat to reach its final temperature.

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Answer:

0.000507 kg/m

Explanation:

L = Length of string

T = Tension

[tex]\mu[/tex] = Mass density of string

E denotes the E string

D denotes the D String

Frequency is given by

[tex]f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}[/tex]

So

[tex]f\propto \sqrt{\dfrac{1}{\mu}}[/tex]

[tex]\dfrac{f_D}{f_E}=\sqrt{\dfrac{\mu_E}{\mu_D}}\\\Rightarrow \mu_E=\dfrac{f_D^2}{f_E^2}\mu_D\\\Rightarrow \mu_E=\dfrac{146.83^2}{329.63^2}\times 0.00256\\\Rightarrow \mu_E=0.000507\ kg/m[/tex]

The mass density of the E string is 0.000507 kg/m

Answer:

A gas turbine, also called a combustion turbine, is a type of continuous and internal combustion engine. The main elements common to all gas turbine engines are:

an upstream rotating gas compressor

a combustor

a downstream turbine on the same shaft as the compressor.

A fourth component is often used to increase efficiency (on turboprops and turbofans), to convert power into mechanical or electric form (on turboshafts and electric generators), or to achieve greater thrust-to-weight ratio (on afterburning engines).

The basic operation of the gas turbine is a Brayton cycle with air as the working fluid. Atmospheric air flows through the compressor that brings it to higher pressure. Energy is then added by spraying fuel into the air and igniting it so the combustion generates a high-temperature flow. This high-temperature high-pressure gas enters a turbine, where it expands down to the exhaust pressure, producing a shaft work output in the process. The turbine shaft work is used to drive the compressor; the energy that is not used for compressing the working fluid comes out in the exhaust gases that can be used to do external work, such as directly producing thrust in a turbojet engine, or rotating a second, independent turbine (known as a power turbine) which can be connected to a fan, propeller, or electrical generator. The purpose of the gas turbine determines the design so that the most desirable split of energy between the thrust and the shaft work is achieved. The fourth step of the Brayton cycle (cooling of the working fluid) is omitted, as gas turbines are open systems that do not use the same air again.

Gas turbines are used to power aircraft, trains, ships, electrical generators, pumps, gas compressors, and tanks.[1]

Explanation: As applied above.

Answer:

0.05 W/m°C

Explanation:

Surface area of box, A = 1.47 m²

thickness of wall, d = 3.91 cm = 0.0391 m

Power of heater, P = 15.9 W

difference in temperature, ΔT = 8.4 °C

Let K is the thermal conductivity.

Heat flows per unit time is given by

[tex]H=\frac{KA\Delta T}{d}[/tex]

[tex]15.9=\frac{K\times 1.47\times 8.4}{0.0391}[/tex]

K = 0.05 W/m°C

Thus, the thermal conductivity of the box is 0.05 W/m°C.

Answer: The ray that passes through the focal point on the way to the lens will refract and travel parallel to the principal axis. ... All three rays should intersect at exactly the same point.

Explanation: Once these incident rays strike the lens, refract them according to the three rules of refraction for converging lenses.

When a light ray parallel to the principal axis passes through a converging lens, it is bent towards the principal axis and converges to a point called the focal point.

When a light ray parallel to the principal axis passes through a converging lens, it is bent towards the principal axis and converges to a point. This point is known as the focal point of the lens. The path of the light ray after passing through the lens depends on the distance of the object from the lens and the focal length of the lens.

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Answer:

d₂ = 1.466 m

Explanation:

In this case we must use the rotational equilibrium equations

        Στ = 0

        τ = F r

we must set a reference system, we use with origin at the easel B and an axis parallel to the plank , we will use that the counterclockwise ratio is positive

      + W d₁ - w_cat d₂ = 0

      d₂ = W / w d₁

      d₂ = M /m d₁

      d₂ = 5.00 /2.9    0.850

      d₂ = 1.466 m

Explanation:

The time period of the simple pendulum that consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field is given by :

[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

l is length of simple pendulum

g is acceleration due to gravity.

It is clear that, the time period is independent of the mass. Also, the period is proportional to the square root of the length of the wire.

Hence, the correct options are (B) and (F).

Answer:

1) Stunt car A experiences a large stopping force over a short period of time.

2 stunt car B experiences a small stopping force over a longer period of time

3) stunt car A will sustain more damage than stunt car B

Explanation:

the mass and speed of both stunt cars are equal.

Mass = 43.3kg

Speed = 70.7 m/s

Their initial momentum = mv = 43.3 x 70.7 = 3061.31 kg-m/s

Their final momentum will be equal to zero since they come to a complete stop.

The rate of change of momentum = 3061.31 - 0 = 3061.31 kg-m/s

Rate of change of momentum = impulse

Impulse = force times time duration of impact

I = f x t

From this equation, the answers it can be seen that a shorter time duration of impact will produce a large force and vice versa.

Answer:

Explanation:

FIND THE SOLUTION BELOW

Answer:

a) v = (-338.1î + 725ĵ) km/h

b) Velocity of the wind = (-838.1î + 725ĵ) km/h

Magnitude of the wind = 1108.17 km/h

Direction = -40.9°; that is, 40.9° in the clockwise direction from the positive x-axis.

Explanation:

a) Airplane is flying 800 km/h in a direction 25° west of North.

Velocity of the plane = (vₓ, vᵧ)

vₓ = v cos θ

vᵧ = v sin θ

v = magnitude of the velocity = 800 km/h

θ = angle the velocity makes with the positive x-axis = 90° + 25° = 115°

vₓ = v cos θ

vₓ = 800 cos 115° = - 338.1 km/h

vᵧ = v sin θ

vᵧ = 800 sin 115° = 725 km/h

v = (-338.1î + 725ĵ) km/h

b) What speed and direction should the wind be in order for the airplane to now fly 500 km/h due east

Relative velocity of airplane with respect to the wind

= (velocity of the airplane) - (velocity of the wind)

Note that the velocities on the right hand side are with respect to earth's frame of reference.

Relative velocity of airplane with respect to the wind = 500 km/h east = (500î) km/h

velocity of the airplane = (-338.1î + 725ĵ) km/h

velocity of the wind = ?

500î = (-338.1î + 725ĵ) - (velocity of the wind)

(velocity of the wind) = (-338.1î + 725ĵ) - 500î

= (-838.1î + 725ĵ) km/h

Velocity of the wind = (-838.1î + 725ĵ) km/h

Magnitude = √[(-838.1)² + (725²)] = 1108.17 km/h

Direction = tan⁻¹ (725 ÷ -838.1) = -40.9°

Hope this Helps!!!

Answer:

To increase the frequency the spring constant k should be increased.

Explanation:

In simple harmonic motion, the frequency is expressed as;

f = (1/2π)√(k/m)

where;

k is spring constant

m is mass of the object

From the frequency formula i wrote, It’s obvious that frequency depends on only the spring constant and mass while Amplitude(A) and phase angle(ϕ) are not related and would have no effect on the frequency. Thus, by inspection, an increase in spring constant increases frequency while an increase in mass decreases frequency

Answer:

Explanation:

The given solution of silver oxide = 58 ml of 13.5 M of silver oxide

When we increase its volume , its molar concentration becomes less . To calculate the concentration of diluted solution , we can apply the following relation .

S₁ V₁ = S₂ V₂ .

S₁ is molar strength when volume is V₁ . S₂ is molar strength when volume is V₂

Puting the given values in the formula above ,

58 x 13.5 M = V₂ x 5

V₂ = 58 x 13.5 / 5

= 156.6 ml .

= 157 ml after rounding off.

Complete Question

(10 points) Consider a single crystal of some hypothetical metal that has the FCC crystal structure, and its critical resolved shear stress is 3.42 MPa. The crystal is oriented such that a tensile stress is applied at an angle of 39.2 degrees to the slip plane. Slip can occur in two directions( 18.4 and 74.2 degrees to the tensile force).

(a) (5 points) Which direction, is slip favored?

b)  (5 points)  What is the yield strength of this crystal during this tensile test ?

Answer:

a

the slip would occur 18.4° to the tensile force

b

The yield strength is    [tex]\sigma_y = 4.65\ MPa[/tex]

Explanation:

From the question we are told that

    The Resolved shear force is [tex]\sigma = 3.2MPa[/tex]

     The angle in which the tensile stress is applied is [tex]\O = 39.2^o[/tex]

      The first direction of slip is [tex]\theta _ 1 =18.4^o[/tex]

      The second direction of the slip is [tex]\theta_2 = 74.2^o[/tex]

Generally the condition for direction in which slip is likely to occur(

direction in which slip is favored )   is that  [tex](cos( \O) cos (\theta) )[/tex]

Must be Maximum for that direction

   Since [tex]Cos (\O)[/tex] is constant for both direction we would  look at the the cos of the the angle for both direction

      [tex]Cos (\theta_ 1) = Cos(18.4^o) =0.9488[/tex]

      [tex]Cos (\theta_ 2) = Cos(74.2^o) =0.2722[/tex]

From this calculation we can see that the slip would occur 18.4° to the tensile force

   Generally critical resolved shear stress is mathematically represented as

           [tex]\sigma = \sigma_y * (cos(\O) cos(\theta_1))[/tex]

Where [tex]\sigma_y[/tex] is the  yield strength

Making  [tex]\sigma_y[/tex] the subject

       [tex]\sigma_y = \frac{\sigma }{[cos (\O) cos(\theta_1)]}[/tex]

Substituting value

             [tex]\sigma_y = \frac{3.4*10^{6}}{cos (39.2) (cos 18.4)}[/tex]

                 [tex]\sigma_y = 4.65\ MPa[/tex]

Answer:

0.54 A

Explanation:

Parameters given:

Number of turns, N = 15

Area of coil, A = 40 cm² = 0.004 m²

Change in magnetic field, ΔB = 5.1 - 1.5 = 3.6 T

Time interval, Δt = 2 secs

Resistance of the coil, R = 0.2 ohms

To get the magnitude of the current, we have to first find the magnitude of the EMF induced in the coil:

|V| = |(-N * ΔB * A) /Δt)

|V| = | (-15 * 3.6 * 0.004) / 2 |

|V| = 0.108 V

According to Ohm's law:

|V| = |I| * R

|I| = |V| / R

|I| = 0.108 / 0.2

|I| = 0.54 A

The magnitude of the current in the coil of wire is 0.54 A

Answer: 33.69 degrees

Explanation:

Given

Distance between the two mirrors, = 6 cm

Length of the two mirrors, = 24 cm

Assuming the laser is shone from just clear of the left edge of the bottom mirror,

a)

Tan L = (O/A)

Tan L = (6 / 12)

Tan L = 0.5

L = Tan^-1 (0.5)

L = 26.57 degrees

(90 - 26.57) = 63.43 deg. to the normal.

Tan L = (6 / [24/6])

Tan L = (6 / 4)

Tan L = 1.5

L = Tan^-1 (1.5)

L = 56.31 degrees

(90 - 56.31) = 33.69 deg. to the normal.

Thus, the angle at which, with respect to the mirror, the laser beam hits the mirrors in each way is 33.69 degrees

Answer:

86degrrss

Explanation:

tan L =BC/AB

= 3/12 = 1/4

L= tan^-1 0.25

=4.0 degrees

= 90-4= 86degrees

The far point of a woman's eyes is -2 meters and the near point is 50 cm.

The far point and near point of a woman's eyes can be determined using the power of her bifocal glasses. The power of a corrective lens is the reciprocal of the focal length in meters (P = 1/f). The upper half of the bifocal glasses has a power of -0.500 diopters, which corrects for far vision, and the lower half has a power of +2.00 diopters, which corrects for near vision.

To find the far point, we use the power for far vision. Since her far correction is -0.500 diopters, this means that her far point is:

Far Point (FP) = 1/P = 1/(-0.500 D) = -2 meters

The negative sign indicates that the woman is myopic (nearsighted), and can clearly see objects up to a distance of 2 meters.

To find the near point, we consider the power for near vision. The near correction is +2.00 diopters, which means that her near point is:

Near Point (NP) = 1/P = 1/(+2.00 D) = 0.50 meters or 50 cm

Thus, the woman's near point is 50 cm, which is the closest distance at which she can see objects clearly without the need for further accommodation.

The far point of the woman's eyes is at infinity, and the near point is 50.0 cm in front of her eyes.

To understand why, let's consider the purpose of bifocal glasses. The upper half of the lens with a power of -0.500 diopters is used to correct the woman's far vision. Since the power of the lens is negative, it is designed to diverge light slightly so that the woman can focus on distant objects (at infinity) when looking through the upper half of the lens. This implies that her far point, without the glasses, would be slightly beyond infinity, but with the glasses, it is effectively at infinity.

The lower half of the lens has a power of +2.00 diopters, which is used to correct her near vision. This positive power converges light, allowing the woman to focus on close objects. The power in diopters (P) is the reciprocal of the focal length (f) in meters. Therefore, we can calculate the focal length of the near vision correction as follows:

[tex]\[ P = \frac{1}{f} \] \[ f = \frac{1}{P} \] \[ f = \frac{1}{2.00 \text{ diopters}} \] \[ f = 0.500 \text{ meters} \] \[ f = 50.0 \text{ cm} \][/tex]

This focal length represents the near point of her eyes when she is wearing the glasses. It means that with the glasses on, she can focus clearly on objects that are 50.0 cm away from her eyes when looking through the lower half of the lens.

In summary, the far point of her eyes with the glasses is at infinity, and the near point is 50.0 cm away. This is consistent with the typical use of bifocal glasses, which is to enable clear vision at both distant and near objects.

Answer:

Explanation:

Energy of photon = h c / λ , h is planks constant , c is velocity of light and λ is wave length

= 6.626 x 10⁻³⁴ x 2.998 x 10⁸ / 236 x 10⁻⁹

= .08417 x 10⁻¹⁷ J

Kinetic energy of photoelectron = 1.99 e V

= 1.99  x 1.602 x 10⁻¹⁹ J

= 3.18798 x 10⁻¹⁹

= .03188 x 10⁻¹⁷ J

Diff of energy = .08417 - .03188 x 10⁻¹⁷

= .05229 x 10⁻¹⁷ J

This will be the work function of the metal

If λ be the maximum wave-length required

h c /  λ =  .05229 x 10⁻¹⁷

6.626 x 10⁻³⁴ x 2.998 x 10⁸ /  λ  = .05229 x 10⁻¹⁷

λ  = 6.626 x 10⁻³⁴ x 2.998 x 10⁸  / .05229 x 10⁻¹⁷

= 379.89 x 10⁻⁹ m

= 379.89 nm .

Answer:

Please see the attached picture for the complete answer.

Explanation:

Answer:

The the percent of theoretical dry air provided is 35.71%

Explanation:

Refer to attached handwritten document for calculation

Answer:

B. Submerged

Explanation: