Belle Corp. has a selling price of $50 per unit, variable costs of $40 per unit, and fixed costs of $100,000. What sales revenue is needed to break-even?

I need help working out this problem. I get confused on the process.

Answers

Answer 1

Answer:

$500 000

Step-by-step explanation:

 Let r = revenue

and c = costs

and n = number of units. Then

r = 50n and

c = 40n + 100 000

At the break-even point,

r = c

50n = 40n + 100 000

10n = 100 000

    n = 10 000

The break-even point is reached at 10 000 units. At that point,

r = 50n =50 × 10 000 = 500 000

A sales revenue of $500 000 is needed to break even.

Answer 2
Final answer:

Belle Corp. needs to achieve a sales revenue of $500,000 to cover both its variable and fixed costs and thus reach the break-even point.

Explanation:

To calculate the breakeven point of Belle Corp., we need to understand that breakeven is the point where total costs (fixed and variable) equal total sales revenue. The formula for calculating the breakeven point in units is Total Fixed Costs / Contribution Margin per Unit. The contribution margin per unit is the Selling Price per Unit minus the Variable Cost per Unit.

For Belle Corp.,

Selling Price per unit = $50Variable Cost per unit = $40Contribution Margin per unit = Selling Price per unit - Variable Cost per unit = $10Fixed Costs = $100,000Breakeven point in units = Fixed Costs / Contribution Margin per unit = 10,000 units.

To calculate sales revenue necessary to breakeven, we multiply the breakeven point in units by the selling price per unit. Therefore, Sales revenue needed to break-even = Breakeven units * Selling Price per unit = 10,000 units × $50 = $500,000.

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Related Questions

Suppose you just received a shipment of eleven televisions. Three of the televisions are defective. If two televisions are randomly​ selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not​ work?

Answers

Answer:  The probability that both televisions work : 0.5329

The  probability at least one of the two televisions does not​ work : 0.4671

Step-by-step explanation:

Given : The total number of television : 11

The number of defective television : 3

The probability that the television is defective : [tex]p=\dfrac{3}{11}\approx0.27[/tex]

Binomial distribution formula :-

[tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex], where P(X) is the probability of getting success in x trials, p is the probability of success and n is the total trials.

If two televisions are randomly​ selected, then the probability that both televisions work:

[tex]P(0)=^2C_0(0.27)^0(1-0.27)^{2-0}=(1)(0.73)^2=0.5329[/tex]

The probability at least one of the two televisions does not​ work :

[tex]P(X\geq1)=1-P(0)=1-0.5329=0.4671[/tex]

Exihibit a counterexample for the following. Every prime number is odd.

Answers

A counter example would be the number 2.

2 is a prime number, because it only has two factors ( itself and 1)

Yet 2 is also an even number, because it can be exactly divided by two.

So the number 2 proves that not every prime number is odd.

Find the cosine of the angle between the planes −1x+3y+1z=0 and the plane 5x+5y+4z=−4

Answers

Answer:

The he cosine of the angle between the planes is [tex]\frac{14}{11\sqrt{6}}[/tex].

Step-by-step explanation:

Using the definition of the dot product:

[tex]\cos\theta =\frac{\overrightarrow{a}\cdot \overrightarrow{b}}{|\overrightarrow{a}||\overrightarrow{b}|}[/tex]

The given planes are

[tex]-1x+3y+1z=0[/tex]

[tex]5x+5y+4z=-4[/tex]

The angle between two normal vectors of the planes is the same as one of

the angles between the planes. We can find a normal vector to each of the

planes by looking at the coefficients of x, y, z.

[tex]\overrightarrow{n_1}=<-1,3,1>[/tex]

[tex]\overrightarrow{n_2}=<5,5,4>[/tex]

[tex]\overrightarrow{n_1}\cdot \overrightarrow{n_2}=(-1)(5)+(3)(5)+(1)(4)=14[/tex]

[tex]|n_1|=\sqrt{(-1)^2+(3)^2+(1)^2}=\sqrt{11}[/tex]

[tex]|n_2|=\sqrt{(5)^2+(5)^2+(4)^2}=\sqrt{66}[/tex]

The cosine of the angle between the planes

[tex]\cos\theta =\frac{\overrightarrow{n_1}\cdot \overrightarrow{n_2}}{|\overrightarrow{n_1}||\overrightarrow{n_2}|}[/tex]

[tex]\cos\theta =\frac{14}{\sqrt{11}\sqrt{66}}[/tex]

[tex]\cos\theta =\frac{14}{11\sqrt{6}}[/tex]

Therefore the cosine of the angle between the planes is [tex]\frac{14}{11\sqrt{6}}[/tex].

Final answer:

To find the cosine of the angle between two planes, calculate the dot product of their normal vectors.

Explanation:

To find the cosine of the angle between two planes, we need to determine the normal vectors of the planes and then calculate the dot product of the two normal vectors. The dot product of two vectors is equal to the product of their magnitudes and the cosine of the angle between them.

Given the planes -x+3y+z=0 and 5x+5y+4z=-4, the normal vectors are (-1,3,1) and (5,5,4) respectively.

Calculating the dot product of the two normal vectors, we get: (-1)(5) + (3)(5) + (1)(4) = 0. Therefore, the cosine of the angle between the planes is 0.


Prove or disprove:

a) Any positive integer can be written as the sum of the squares of two integers

b) For every integer n, the number 3(n2 + 2n + 3) ? 2n2 is a perfect square

Answers

Step-by-step explanation:

a). Let [tex]x^{2}+y^{2}=4[/tex]

     [tex]y^{2}=4-x^{2}[/tex]

Now since [tex]y^{2}[/tex] is a square of an integer, its value is [tex]\geq[/tex] 0.

Therefore, [tex]4-x^{2}[/tex] ≥ 0, since x is an integer

where [tex]4-x^{2}[/tex] = 1,2,3,...

and x = 1

But as x = [tex]\sqrt{2}, \sqrt{3}[/tex],... cannot be integer

∴ [tex]y^{2}=4-x^{2}[/tex]

   [tex]y^{2}=4-1[/tex]

   [tex]y = \sqrt{3}[/tex]

              = 1.732      which is not an integer

Thus, any positive integer cannot be written as the sum of the squares of the two integers.

b). Let n be an integer

∴ [tex]3(n^{2}+2n+3)-2n^{2}[/tex]

On solving we get,

 [tex]3n^{2}+6n+9-2n^{2}[/tex]

 [tex]n^{2}+6n+9[/tex]

 [tex]n^{2}+3n+3n+9[/tex]

 [tex]n(n+3)+3(n+3)[/tex]

  [tex](n+3)(n+3)[/tex]

  [tex](n+3)^{2}[/tex]

which is a perfect square

Hence proved.

Answer:

Step-by-step explanation:

a). Let

   

Now since  is a square of an integer, its value is  0.

Therefore,  ≥ 0, since x is an integer

where  = 1,2,3,...

and x = 1

But as x = ,... cannot be integer

 

 

             = 1.732      which is not an integer

Thus, any positive integer cannot be written as the sum of the squares of the two integers.

b). Let n be an integer

On solving we get,

 

 

which is a perfect square

Hence proved.

Solve the congruence 169x 25 (mod 330)

Answers

First solve the congruence [tex]13y\equiv1\pmod{330}[/tex]. Euclid's algorithm shows

330 = 25 * 13 + 5

13 = 2 * 5 + 3

5 = 1 * 3 + 2

3 = 1 * 2 + 1

=> 1 = 127 * 13 - 5 * 330

=> 127 * 13 = 1 mod 330

so that [tex]y=127[/tex] is the inverse of 13 modulo 330. Then in the original congruence, multiplying both sides by 127 twice gives

[tex]127^2\cdot13^2x\equiv127^2\cdot5^2\pmod{330}\implies x\equiv127^2\cdot5^2\equiv403,225\equiv295\pmod{330}[/tex]

Then any integer of the form [tex]x=295+330n[/tex] is a solution to the congruence, where [tex]n[/tex] is any integer.

Final answer:

Using the Chinese Remainder Theorem, the final solution to the congruence is x = 9 + 330k, where k is an integer.

Explanation:

To solve the congruence 169x ≡ 25 (mod 330), we can use the Chinese Remainder Theorem. First, we factor 330 into its prime factors: 330 = 2 × 3 × 5 × 11. Next, we solve the congruences 169x ≡ 25 (mod 2), 169x ≡ 25 (mod 3), 169x ≡ 25 (mod 5), and 169x ≡ 25 (mod 11) separately.

For the congruence 169x ≡ 25 (mod 2), since 169 ≢ 1 (mod 2), we can ignore it. For the congruence 169x ≡ 25 (mod 3), we can rewrite it as x ≡ 1 (mod 3). For the congruence 169x ≡ 25 (mod 5), we can rewrite it as 4x ≡ 0 (mod 5), and since gcd(5, 4) = 1, we can divide both sides by 4 to get x ≡ 0 (mod 5). Lastly, for the congruence 169x ≡ 25 (mod 11), we can rewrite it as 5x ≡ 3 (mod 11), and solve for x which will give us x ≡ 9 (mod 11).

Using the Chinese Remainder Theorem, we can combine these solutions to get x ≡ 9 (mod 330). Therefore, the solution to the congruence is x = 9 + 330k, where k is an integer.

Determine the payment to amortize the debt. (Round your answer to the nearest cent.) Monthly payments on $170,000 at 4% for 25 years.

Answers

Answer:

The payment would be $ 897.32.

Step-by-step explanation:

Since, the monthly payment of a loan is,

[tex]P=\frac{PV(r)}{1-(1+r)^{-n}}[/tex]

Where, PV is the present value of the loan,

r is the monthly rate,

n is the total number of months,

Here,

PV = $170,000,

Annual rate = 4 % = 0.04

So, the monthly rate, r = [tex]\frac{0.04}{12}=\frac{1}{300}[/tex]  ( 1 year = 12 months )

Time in years = 25,

So, the number of months, n = 12 × 25 = 300

Hence, the monthly payment of the debt would be,

[tex]P=\frac{170000(\frac{1}{300})}{1-(1+\frac{1}{300})^{-300}}[/tex]

[tex]=897.322628506[/tex]

[tex]\approx \$ 897.32[/tex]

QUESTION 20 5.0 Calculate the standard deviation for the following set of numbers: 73, 76, 79, 82, 84, 84, 97

Answers

Answer:

7.16.

Step-by-step explanation:

The variance is ∑ (x - m)^2 / N   and the standard deviation is the square root of this.

m is the mean of the data . Here it is  82.14.

Construct a table:

x    (x - m)     (x - m)^2

73    -9.14       83.54

76     -6.14      37.70

79      -3.14        9.86

82      -0.14        0.02

84       1.86        3.46  

84        1.86        3.46

97       14.86    220.82

Total:             358.86

Variance =  358.86 / 7 =  51.27

Standard deviation = √51.27 = 7.16.

What is a rational number between 9.5 and 9.7

Answers

Answer:

9.6 is one such number

Step-by-step explanation:

There are infinitely many.

If we are looking at decimals which I think that might be easier here, you are looking for ones that terminate or repeat (same pattern over and over).

So we are looking for a number between 9.5 and 9.7 that is a decimal that either terminates or repeats.

That number could be 9.6.  That one is probably the easier one to see.

There are many more like these possibilities:

1)  9.6

2) 9.5001

3) 9.51

4) 9.54

5) 9.669

Answer:

9.57

Step-by-step explanation:

Because 9.56763865854637984..... (rounded 9.57) It is irrational because it has no pattern

A researcher studied the radioactivity of asbestos. She sampled 81 boards of asbestos, and found a sample mean of 193.2 bips, and a sample standard deviation of 49.5 bips. (a) Obtain the 94% confidence interval for the mean radioactivity. (b) (i) According the interval that you got, is 200 bips a plausible value for the true mean? (ii) What about 210 bips?

Answers

Answer:

a) Confidence interval is (182.86,203.54).

b) (i) Yes, 200 bips is a true mean as it lie in the interval.

(ii) No, 210 bips is not a true mean as it doesn't lie in the interval.

Step-by-step explanation:

Given : A researcher studied the radioactivity of asbestos. She sampled 81 boards of asbestos, and found a sample mean of 193.2 bips, and a sample standard deviation of 49.5 bips.

To find : (a) Obtain the 94% confidence interval for the mean radioactivity. (b) (i) According the interval that you got, is 200 bips a plausible value for the true mean? (ii) What about 210 bips?

Solution :

a) The confidence interval formula is given by,

[tex]\bar{x}-z\times \frac{\sigma}{\sqrt{n}} <C.I<\bar{x}+z\times \frac{\sigma}{\sqrt{n}}[/tex]

We have given,            

The sample mean [tex]\bar{x}=193.2[/tex] bips

s is the standard deviation [tex]\sigma=49.5[/tex] bips

n is the number of sample n=81

z is the score value, at 94% z=1.88

Substitute all the values in the formula,

[tex]193.2-1.88\times \frac{49.5}{\sqrt{81}} <C.I<193.2+1.88\times \frac{49.5}{\sqrt{81}}[/tex]

[tex]193.2-1.88\times 5.5 <C.I<193.2+1.88\times 5.5[/tex]

[tex]193.2-10.34 <C.I<193.2+10.34[/tex]

[tex]182.86 <C.I<203.54[/tex]

Confidence interval is (182.86,203.54).    

b) (i) According the interval [tex]182.86 <C.I<203.54[/tex]

200 bips a plausible value for the true mean as it lies in the interval.

(ii) 210 bips not lie in the confidence interval so it is not a true mean.

Final answer:

To obtain the 94% confidence interval for the mean radioactivity, use the formula: CI = X ± (Z * σ / √n). The 94% confidence interval for the mean radioactivity is (181.05, 205.35). To determine if a value is plausible, check if it falls within the confidence interval.

Explanation:

To obtain the 94% confidence interval for the mean radioactivity, we'll use the formula:

CI = X ± (Z * σ / √n)

Where X is the sample mean, Z is the z-score corresponding to the desired confidence level, σ is the sample standard deviation, and n is the sample size.

For a 94% confidence level, the z-score is approximately 1.88. Plugging in the values:

CI = 193.2 ± (1.88 * 49.5 / √81) = 193.2 ± 12.15

The 94% confidence interval for the mean radioactivity is (181.05, 205.35).

(b) (i) To determine if 200 bips is a plausible value, we check if it falls within the confidence interval. Since 200 is within the interval (181.05, 205.35), it is a plausible value. (ii) Similarly, we check if 210 bips falls within the interval. Since 210 is not within the interval, it is not a plausible value.

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The brain volumes ​(cm cubed​)of 50 brains vary from a low of 904cm cubedto a high of 1490cm cubed.Use the range rule of thumb to estimate the standard deviation s and compare the result to the exact standard deviation of 174.7cm cubed​,assuming the estimate is accurate if it is within 15 cm cubed.The estimated standard deviation is 146.5cm cubed.​(Type an integer or a decimal. Do not​ round.)Compare the result to the exact standard deviation.

Answers

Answer:

The Range Rule of Thumb says that the range is about four times the standard deviation. So, if you need to calculate it, you need to divide range (Maximum - Minimum) with 4, S=[tex]\frac{R}{4}[/tex].

Step-by-step explanation:

R=1490 - 904

S = 586 / 4 = 149.5

If you compare the exact standard desviation (149.5 cm) with the estimated (146.5 cm), it is a difference of 3 cm, is not neccesary round the result.

Hope my answer has been useful.

Answer:

x_bar = 1197 cm^3 , s.d_e = 146.5 cm^3

Outside the 15 cm^3 tolerance. Not a good estimation.

Step-by-step explanation:

Given:

- Lowest value of brain volume L = 904 cm^3

- Highest value of brain volume H = 1490 cm^3

- Exact standard deviation s.d_a = 174.7 cm^3

Find:

Use the range rule of thumb to estimate the standard deviation s and compare the result to the exact standard deviation of 174.7 cm^3 assuming the estimate is accurate if it is within 15 cm^3.

Solution:

- The rule of thumb states that the max and min limits are +/- 2 standard deviations about the mean x_bar. Hence, we will set up two equations.

                           L = x_bar - 2*s.d_e

                           H = x_bar + 2*s.d_e

Where, s.d_e is the estimated standard deviation.

- Solve the two equations simultaneously and you get the following:

                          x_bar = 1197 cm^3 , s.d_e = 146.5 cm^3

- The exact standard deviation is s.d_a = 174.7 cm^3

So, the estimates differs by:

                           s.d_a - s.d_e = 174.7 - 146.5 = 28.2 cm^3

Hence, its outside the tolerance of 15 cm^3. Not a good approximation.

A 3 foot wide brick sidewalk is laid around a rectangular swimming pool. The outside edge of the sidewalk measures 30 feet by 40 feet. What is the perimeter, in feet, of the swimming pool?

Answers

Answer with Step-by-step explanation:

A 3 foot wide brick sidewalk is laid around a rectangular swimming pool.

The outside edge of the sidewalk measures 30 feet by 40 feet.

Length of swimming pool=(30-3-3) feet

                                          =24 feet

Breath of swimming pool=(40-3-3) feet

                                         = 34 feet

Perimeter of swimming pool=2(24+34) feet

(since perimeter of rectangle=2(l+b) where l is the length and b is the breath of the rectangle)

Perimeter of swimming pool=116 feet

Hence, Perimeter of swimming pool is:

116 feet

Final answer:

To find the perimeter of the swimming pool, subtract twice the width of the 3 feet sidewalk from the total length and width of the area, which is 40 and 30 feet respectively. This gives you the length and width of the pool. Then, add these dimensions together and multiply by 2 to find the perimeter, which is 116 feet.

Explanation:

The subject of your question involves the concept of perimeter in math. To find the perimeter of the swimming pool itself, we need to subtract the width of the sidewalk from the total length and width measurements. Since the sidewalk is 3 feet wide and it is built around the pool, we need to account for this on both sides of the length and the width.

First, you subtract twice the width of the sidewalk from both the length and the width of the total area, which includes the pool and the sidewalk. So, the length of the pool would be 40 feet (total length) - 2*3 feet (two widths of the sidewalk) = 40 feet - 6 feet = 34 feet.

Similarly, the width of the pool would be 30 feet (total width) - 2*3 feet (two widths of the sidewalk) = 30 feet - 6 feet = 24 feet.

Then, you add the length and the width together and multiply by 2 to find the perimeter. The perimeter of the swimming pool would therefore be 2 * (34 feet + 24 feet) = 2 * 58 feet = 116 feet.

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Find dy/dx and d2y/dx2. x = cos(2t), y = cos(t), 0 < t < π dy dx = Correct: Your answer is correct. d2y dx2 = Correct: Your answer is correct. For which values of t is the curve concave upward? (Enter your answer using interval notation.) Incorrect: Your answer is incorrect.

Answers

Final answer:

The first and second derivatives of the given functions can be found using the chain rule of differentiation. The slope of the curve can be determined using these derivatives and to find out where the curve is concave upwards, the second derivative should be greater than zero.

Explanation:

To find the first and second derivatives dy/dx and d2y/dx2, we first need to use the chain rule. The chain rule states that the derivative of a composite function is the derivative of the outside function multiplied by the derivative of the inside function.

For dy/dx = dy/dt * dt/dx. Since y = cos(t), dy/dt = -sin(t). And since x = cos(2t), dx/dt = -2sin(2t). Thus, dy/dx = [-sin(t)] / [-2sin(2t)].Now, let's find d2y/dx2 which is the derivative of dy/dx with respect to x. So, d2y/dx2 = d/dx (dy/dx). Here, please use the quotient rule and chain rule again for differentiation.

For a curve to be concave upward, the second derivative needs to be greater than zero. So, you need to set your second derivative function greater than zero and solve for t within the given interval 0 < t < π.

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The first derivative is  [tex]\frac{dy}{dx} =\frac{1}{2cos(t)}[/tex] , and the second derivative is [tex]\frac{d^2y}{dx^2} = \frac{-1}{4cos^2tsin(2t)}[/tex]. The curve is concave upward in the interval (0, π/2).

We begin by finding the derivatives of x and y with respect to t.

Given x = cos(2t), differentiate to get:

[tex]\frac{dx}{dt} = -2sin(2t)[/tex]

Given y = cos(t), differentiate to get:

[tex]\frac{dy}{dt} = -sin(t)[/tex]

Using the chain rule,

[tex]\frac{dy}{dx} =\frac{dy}{dt} \frac{dt}{dx} = -sin(t) \cdot \frac{(-1)}{2sin(2t)} = \frac{1}{2cos(t)}[/tex]

Next, we need to find d²y/dx².

Start by finding the derivative of dy/dx with respect to t:

Given, [tex]\frac{dy}{dx} =\frac{1}{2cos(t)}[/tex] differentiate to get:

[tex]\frac{d(\frac{dy}{dx}) }{dt} = \frac{sin(t)}{2cos^2t}[/tex]

Using the chain rule again:

[tex]\frac{d^2y}{dx^2}= \frac{\frac{d(\frac{dy}{dx})}{dt} }{\frac{dx}{dt}} = \frac{-1}{4cos^2tsin(2t)}[/tex]

To determine where the curve is concave upward, we need d²y/dx² > 0.

Since sin(2t) is periodic, we look for values of t where sin(2t) is positive.

This is true for the interval (0, π/2). Thus, the curve is concave upward in the interval (0, π/2).

A player scored 100100 points in a single professional basketball game. He made a total of 6262 ​baskets, consisting of field goals​ (worth two​ points) and foul shots​ (worth one​ point). Find the number of field goals and the number of foul shots that the player made.

Answers

Answer:

Step-by-step explanation:

Two accounts each began with a deposit of exist10,000. Both accounts have rates of 6.5%, but one account compounds interest once a year while the other account compounds interest continuously. Make a table that shows the amount in each account and the interest earned after one year, five, years, ten years, and 20 years. (Round ALL values to the nearest Dollar AND DO NOT include Dollar Signs)

Answers

Answer:

Step-by-step explanation:

Given data

principal P = $10000

rate (r) = 6.5%

to find out

amount in account and the interest earned after one year, five, years, ten years, and 20 years

solution

we know the formula for compounds interest continuously i.e.

amount = principal [tex]e^{rt}[/tex]     ..............1

and

compounds interest annually i.e.

amount = principal [tex](1+r/100)^{t}[/tex]  ..................2

here put value principal rate and time period 1, 5 10 and 20 years

and we get the  amount for each time period        

than for interest = amount - principal we get interest    

as that we calculate all value

i put all value in table here

Final answer:

To calculate the future value of two accounts both starting with $10,000 at a 6.5% interest rate, one compounding annually and the other continuously, we use the formulas for annual and continuous compounding to compare the total amount and interest earned over 1, 5, 10, and 20 years. The continuous compounding results in higher amounts as shown in the provided table.

Explanation:

To compare the growth of two accounts with an initial deposit of $10,000 at an annual interest rate of 6.5%, with one account compounding annually and the other compounding continuously, we can use the following formulas:

For annual compounding: A = P(1 + r/n)^(nt)For continuous compounding: A = Pe^(rt)

Where:
A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money).
r = the annual interest rate (in decimal form).
n = the number of times that interest is compounded per year.
t = the time in years.
e = the base of the natural logarithm, approximately equal to 2.71828.

To make the calculations for both accounts after 1, 5, 10 and 20 years, we will round all values to the nearest dollar and not include dollar signs as per the student's request.

Annual Compounding

Here, n is 1 since interest compounds once per year.

Continuous Compounding

Using the formula for continuous compounding, we do not need a value for n.

Let's look at the calculations:

TimeAnnual Compounded AmountContinuous Compounded AmountInterest Earned (Annual)Interest Earned (Continuous)1 year$10,695$10,709$695$7095 years$13,612$13,747$3,612$3,74710 years$18,504$18,907$8,504$8,90720 years$34,262$35,861$24,262$25,861

From the table, we can conclude that continuous compounding results in a higher total amount and interest earned over time compared to annual compounding for the same interest rate.

he volume of a cone of radius r and height h is​ one-third the volume of a cylinder with the same radius and height. Does the surface area of a cone of radius r and height h equal​ one-third the surface area of a cylinder with the same radius and​ height? If​ not, find the correct relationship. Exclude the bases of the cone and cylinder.

Answers

Answer:

The surface area of a cone of radius r and height h not equal​ to one-third the surface area of a cylinder with the same radius and​ height.

Relationship is [tex]S_c=(\frac{\sqrt{(r+h)}}{2h})S_C[/tex]

Step-by-step explanation:

Given : The volume of a cone of radius r and height h is​ one-third the volume of a cylinder with the same radius and height.

To find : Does the surface area of a cone of radius r and height h equal​ one-third the surface area of a cylinder with the same radius and​ height?

If​ not, find the correct relationship. Exclude the bases of the cone and cylinder.

Solution :

Radius of cone and cylinder is 'r'.

Height of cone and cylinder is 'h'.

The volume of cone is [tex]V_c=\frac{1}{3}\pi r^2 h[/tex]

The volume of cylinder is [tex]V_C=\pi r^2 h[/tex]

[tex]\frac{V_c}{V_C}=\frac{\frac{1}{3}\pi r^2 h}{\pi r^2 h}[/tex]

[tex]V_c=\frac{1}{3}V_C[/tex]

i.e. volume of cone is one-third of the volume of cylinder.

Now,

Surface area of the cone is [tex]S_c=\pi r\sqrt{(r+h)}[/tex]

Surface area of the cylinder is [tex]S_C=2\pi rh[/tex]

Dividing both the equations,

[tex]\frac{S_c}{S_C}=\frac{\pi r\sqrt{(r+h)}}{2\pi rh}[/tex]

[tex]\frac{S_c}{S_C}=\frac{\sqrt{(r+h)}}{2h}[/tex]

[tex]S_c=(\frac{\sqrt{(r+h)}}{2h})S_C[/tex]

Which clearly means [tex]S_c\neq \frac{1}{3}S_C[/tex]

i.e. The surface area of a cone of radius r and height h not equal​ to one-third the surface area of a cylinder with the same radius and​ height.

The relationship between them is

[tex]S_c=(\frac{\sqrt{(r+h)}}{2h})S_C[/tex]

A slot machine has three slots; each will show a cherry, a lemon, a star, or a bar when spun. The player wins if all three slots show the same three items. If each of the four items is equally likely to appear on a given spin, what is your probability of winning? (Enter your probability as a fraction.)

Answers

Answer:

1/16

Step-by-step explanation:

Lets say you are trying to get the cherry when you are spinning. That means that in each slot there is a 1/4 chance of getting the cherry because out of 4 choices only one is the cherry. That is only for one slot and there are 3 slots. That means you take the probability for each slot which is 1/4 and multiply them together. Then you get 1/4*1/4*1/4 since there are 3 slots which is 1/64. However that is only for the cherry and there are 4 different items that you could get. This means there is 1/64 chance for each of the 4 items which is 1/64+1/64+1/64+1/64 which is 4*1/64 which is 1/16.

Final answer:

The probability of winning the slot game is calculated by multiplying the probabilities of each independent event. In this case, the probability of the same item appearing in all three slots is 1 * 1/4 * 1/4, which results in a winning probability of 1/16 or 0.0625.

Explanation:

The subject of this question is the probability of winning in the context of a slot machine game. In this scenario, the slot machine has four different items (cherry, lemon, star, bar) and each item is equally likely to appear on a spin. The player wins if all three slots display the same item.

Firstly, for the first slot, any one of the four items could appear, so the odds are simply 1 (it is certain an item will appear). For the first item to then appear in the second and third slots (i.e., for all three slots to show the same item), with each slot being an independent event, the probability is 1/4 for each subsequent slot.

Therefore, the probability of winning is given by the product of probabilities for each independent event, i.e., 1 * 1/4 * 1/4 = 1/16. Hence, the player's probable chance of winning in a single spin is 1 in 16 or 0.0625 in decimal form.

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If a resistor follows Ohm’s Law, what does the slope represent when you plot V as a function of I (with V on the y-axis)? What about when you plot I as a function of V (with I on the y-axis)?

Answers

Answer:

Resistance

Conductance

Step-by-step explanation:

In any graph the slope represents the ratio of y axis to x axis.

So, in the first case the voltage (V) is on the y axis and current (I) on the x axis. Here the slope is V/I = R. Therefore, slope represents resistance.

In the second case current (I) is on the y axis and voltage (V) is on the x axis. Here the slope formed will be I/V = 1/R = G. Therefore, slope represents conductance.

Final answer:

In physics, particularly when discussing Ohm's Law, the slope of a V versus I plot represents the resistance of the resistor, and conversely, the slope of an I versus V plot signifies the conductance. These relationships illustrate the fundamental interplay between current, voltage, and resistance in electrical circuits.

Explanation:

If a resistor follows Ohm’s Law, when plotting V (voltage) as a function of I (current), with V on the y-axis, the slope of the graph represents the resistance (R) of the resistor. This is directly derived from Ohm's Law, V = IR, which shows that voltage (V) is equal to the current (I) multiplied by the resistance (R). The slope in this context is R, because the graph shows how much voltage is needed to achieve a certain current flow, exhibiting a linear relationship. This slope is a constant value for ohmic devices, showcasing that the resistance does not change with varying voltage or current in these cases.

Conversely, when plotting I as a function of V, with I on the y-axis, the slope represents the conductance (the reciprocal of resistance). From the equation I = V/R, we could also interpret that the slope in a graph of I versus V would represent 1/R, indicating how current changes in response to changes in voltage. This also demonstrates a linear relationship for ohmic devices, where the conductance remains constant.

In essence, these plots offer a visual representation of Ohm's Law in action, and the slope on these graphs provides valuable information about the resistor’s resistance or conductance, highlighting the fundamental relationship between voltage, current, and resistance in an electrical circuit.

Find the scalar and vector projections of b onto a. a = 4, 7, −4 b = 3, −1, 1 scalar projection of b onto a vector projection of b onto a

Answers

Answer:

[tex]comp_{\vec{a}}\vec{b}=0.11 [/tex]

[tex]proj_{\vec{a}}\vec{b}=\left ( \frac{4}{81},\frac{7}{81},\frac{-4}{81} \right )[/tex]  

Step-by-step explanation:

a=(4,7,-4) b=(3,-1,1)

Scalar projection of b onto a

[tex]comp_{\vec{a}}\vec{b}=\frac{a\cdot b}{|a|}[/tex]

[tex]a\cdot b=\left ( 4\times 3 \right )+\left ( 7\times -1 \right )+\left ( -4\times 1 \right )=1[/tex]

[tex]|a|=\sqrt{4^2+7^2+4^2}=9[/tex]

[tex]comp_{\vec{a}}\vec{b}=\frac{a\cdot b}{|a|}=\frac{1}{9}\\\Rightarrow comp_{\vec{a}}\vec{b}=0.11 [/tex]

Vector projection of b onto a

[tex]proj_{\vec{a}}\vec{b}=\frac{a\cdot b}{|a|^2}\cdot a[/tex]

[tex]\frac{a\cdot b}{|a|}=\frac{1}{9}[/tex]

[tex]\frac{a\cdot b}{|a|^2}\cdot a=\frac{1}{81}\left ( {4},{7},{-4} \right )[/tex]

[tex]proj_{\vec{a}}\vec{b}=\left ( \frac{4}{81},\frac{7}{81},\frac{-4}{81} \right )[/tex]  

Final answer:

The scalar projection of vector b onto vector a is calculated as 1/9 and the vector projection is calculated as (4/81, 7/81, -4/81).

Explanation:

The scalar projection of vector b onto a is calculated as the dot product of b and a divided by the magnitude of a.

So, first we calculate a.b = (4*3) + (7*-1) + (-4*1) = 12 - 7 - 4 = 1.

The magnitude of a is the square root of the sum of squares of its components, √(4^2 + 7^2 + -4^2) = √81= 9.

Therefore, the scalar projection is 1/9.

For vector projection, we multiply the scalar projection by the vector a divided by its magnitude, essentially scaling the a vector by the scalar projection.

This gives us (1/9) * (4/9, 7/9, -4/9) = (4/81, 7/81, -4/81).

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In this problem, y = c1 cos 4x + c2 sin 4x is a two-parameter family of solutions of the second-order DE y'' + 16y = 0.
If possible, find a solution of the differential equation that satisfies the given side conditions. The conditions specified at two different points are called boundary conditions. (If not possible, enter NOT.) y(0) = 0, y(π/8) = 4.

Answers

Answer:

y=4 sin(4x)

Step-by-step explanation:

So you are given y(0)=0.  This means when x=0, y=0.

So plug this in:

0=c1 cos(4*0)+c2 sin(4*0)

0=c1 cos(0)   +c2 sin(0)

0=c1 (1)          +c2 (0)

0=c1               +0

0=c1

So our solution looks like this after applying the first boundary condition:

y=c2 sin(4x).

Now we also have y(pi/8)=4.  This means when x=pi/8, y=4.

So plug this in:

4=c2 sin(4*pi/8)

4=c2 sin(pi/2)

4=c2 (1)

4=c2

So the solution with the given conditions applies is y=4 sin(4x) .

Testing:

y'=16 cos(4x)

y''=-64 sin(4x).

y''+16y=0

-64 sin(4x)+16(4 sin(4x))

-64 sin(4x)+64 sin(4x)

0

So the solution still works.

The solution of the differential equation y'' + 16 y = 0 is,

y = 4 sin4x

Here,

The second-order differential equation is,  y'' + 16y = 0.

And, y = c₁ cos 4x + c₂ sin 4x  is a two-parameter family of solutions of the second-order DE y'' + 16y = 0.

We have to find the solution of the differential equation that satisfies the given side conditions,   y(0) = 0, y(π/8) = 4.

What is Differential equation?

A differential equation is a mathematical equation that relates some function with its derivatives.

Now,

y = c₁ cos 4x + c₂ sin 4x is a two-parameter family of solutions of the second-order DE y'' + 16y = 0.

Apply given conditions y(0) = 0,   y(π/8) = 4 on y = c₁ cos 4x + c₂ sin 4x.

We have given y(0) = 0,

This means x = 0, y = 0

So put this in  y = c₁ cos 4x + c₂ sin 4x.

We get,

0 = c₁ cos 4*0 + c₂ sin 4*0

0 = c₁

c₁ = 0

Hence equation become,

y = c₂ sin4x

And, y(π/8) = 4 , this means that x = π/8 , y = 4

So put in equation y = c₂ sin4x we get,

4 = c₂ sinπ/2

c₂ = 4

Hence, the solution become after putting the value of c₁ = 0 and c₂ = 4,

y = c₁ cos 4x + c₂ sin 4x

y= 4 sin4x

So, The solution of the differential equation y'' + 16 y = 0 is,

y = 4 sin4x

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The slope of a graph representing the number of calories that Chad burns (y-axis) with respect to the number of times he works out (x-axis) is 230. Which point will lie on the graph? A. (19, 4,370) B. (18, 3,960) C. (18, 4,730) D. (19, 3,960)

Answers

Answer:

Option A. (19, 4,370)

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]y/x=k[/tex] or [tex]y=kx[/tex]

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem

The relationship between the number of calories that Chad burns (y-axis) with respect to the number of times he works out (x-axis) represent a proportional variation

so

[tex]y=kx[/tex]

we have that

[tex]k=230[/tex] ----> the constant is equal to the slope

substitute

[tex]y=230x[/tex] ----> linear equation that represent the situation

If a point lie on the graph, the the point must satisfy the linear equation

Verify each case

case A) (19,4,370)

For x=19, y=4,370

substitute in the equation

[tex]4,370=230(19)[/tex]

[tex]4,370=4,370[/tex] ----> is true

therefore

The point lie on the graph

case B) (18,3,960)

For x=18, y=3,960

substitute in the equation

[tex]3,960=230(18)[/tex]

[tex]3,960=4,140[/tex] ----> is not true

therefore

The point does not lie on the graph

case C) (18,4,730)

For x=18, y=4,730

substitute in the equation

[tex]4,730=230(18)[/tex]

[tex]4,730=4,140[/tex] ----> is not true

therefore

The point does not lie on the graph

case D) (19,3,960)

For x=19, y=3,960

substitute in the equation

[tex]3,960=230(19)[/tex]

[tex]3,960=4,370[/tex] ----> is not true

therefore

The point does not lie on the graph

Answer:

It would be A

Step-by-step explanation:

its not the same for everyone but the number is (19, 4,370)

Identify the vertex for (x-3)2 – 1.
Question 4 options:
One of the options below is the answer



(-3, -1)


(-3, 1)


(3, 1)


(3, -1)

Answers

Answer:

D.  (3, -1).

Step-by-step explanation:

The vertex for ( x - a)^2 + b  is (a, b).

Comparing (x - 3)^2 - 1 with this we get:

a = 3 and b = -1.

Answer: Last Option

(3, -1)

Step-by-step explanation:

We have the following quadratic function:

[tex]f(x) =(x-3)^2 - 1[/tex]

By definition for a quadratic function in the form:

[tex]f (x) = a (x-h) ^ 2 + k[/tex]

the vertex of the function is always the point (h, k)

Note that for this case the values of h, a, and k are:

[tex]a = 1\\h = 3\\k = -1[/tex]

Therefore the vertex of the function [tex]f(x) =(x-3)^2 - 1[/tex] is the point

(3, -1)


Kayla needs $14,000 worth of new equipment for his shop. He can borrow this money at a discount rate of 10% for a year.

Find the amount of the loan Kayla should ask for so that the proceeds are $14,000.

Maturity = $

Answers

Answer:

$15400

Step-by-step explanation:

Principle amount, P = $14000

Time, T = 1 year

Rate of interest, R = 10%

We know that maturity amount,

[tex]A = P\left (1+\frac{R}{100} \right )^{n}[/tex]

where n is number of years

[tex]A = P\left (1+\frac{R}{100} \right )^{n}[/tex]

[tex]A = 14000\left (1+\frac{10}{100}\right )^{1}[/tex]

[tex]A = 14000\left (1+\frac{1}{10}\right )[/tex]

[tex]A = 14000\left (\frac{11}{10}\right )[/tex]

[tex]A = 15400[/tex]

The maturity amount is $15400

Kayla should take out a loan of $12,727.27 to have $14,000 after accounting for a 10% discount rate over one year.

Kayla needs to determine the amount she must borrow so that after accounting for the interest rate of 10%, she will have proceeds of $14,000 to invest in new equipment for her shop. The equation to calculate this is the present value (amount borrowed) equals the future value (amount after interest) divided by one plus the interest rate to the power of the period, which in this case is one year.

Using this formula:

Amount Borrowed = $14,000 / (1 + 0.10)1

Amount Borrowed = $14,000 / 1.10

Amount Borrowed = $12,727.27

Therefore, Kayla should ask for a loan of $12,727.27 to receive $14,000 after one year.

A standard six-sided die is rolled. What is the probability of rolling a number greater than or equal to 3? Express your answer as a simplified fraction or a decimal rounded to four decimal places.

Answers

The numbers on a six sided die are: 1, 2, 3, 4 ,5 ,6

There are 4 numbers that are either equal to 3 or greater than 3: 3, 4, 5 ,6

The probability of getting one is 4 chances out of 6 numbers, which is written as 4/6.

4/6 can be reduced to 2/3 ( simplified fraction)

Final answer:

The probability of rolling a number greater than or equal to 3 on a six-sided die is 2/3 or 0.6667 when rounded to four decimal places.

Explanation:

To find the probability of rolling a number greater than or equal to 3 on a standard six-sided die, we count the favorable outcomes and then divide this number by the total number of possible outcomes. The sample space, S, of a six-sided die is {1, 2, 3, 4, 5, 6}.

Numbers greater than or equal to 3 are 3, 4, 5, and 6. So, there are 4 favorable outcomes. The total number of possible outcomes is 6 (since there are 6 sides on the die).

The probability is thus the number of favorable outcomes (4) divided by the total number of possible outcomes (6), which simplifies to 2/3 or approximately 0.6667 when rounded to four decimal places.

Find the value of x.


A) x = 2

B) x = 3

C) x = 33

D) x = 52

Answers

Answer:

B) x = 3

Step-by-step explanation:

The given triangle has three angles:

∠R, ∠S and ∠T

The exterior angle theorem says that

∠S+∠T = ∠R

Putting the values of angles

(57+x) + 25x = 45x

57 + x + 25x = 45x

57+26x = 45x

57 = 45x - 26x

57 = 19x

x = 57/19

x = 3

Hence, the correct answer is:

B) x = 3 ..

Answer:

B

Step-by-step explanation:

X = 3

For the month of January in a certain​ city, 42​% of the days are cloudy. Also in the month of January in the same​ city, 41​% of the days are cloudy and rainy. What is the probability that a randomly selected day in January will be rainy if it is cloudy​?

Answers

Answer: 0.9762

Step-by-step explanation:

Let A be the event that days are cloudy and B be the event that days are rainy for January month .

Given : The probability that the days are cloudy = [tex]P(A)=0.42[/tex]

The probability that the days are cloudy and rainy = [tex]P(A\cap B)=0.41[/tex]

Now, the conditional probability that a randomly selected day in January will be rainy if it is cloudy is given by :-

[tex]P(B|A)=\dfrac{P(B\cap A)}{P(A)}\\\\\Rightarrow\ P(B|A)=\dfrac{0.41}{0.42}=0.97619047619\approx0.9762[/tex]

Hence, the probability that a randomly selected day in January will be rainy if it is cloudy  = 0.9762

the probability that a randomly selected day in January will be rainy if it is cloudy is approximately 97.62%.

The question asks us to find the probability that a day will be rainy given that it is cloudy. From the information provided, we know that in this city, 42% of the days in January are cloudy, and 41% are both cloudy and rainy. To find the probability that it is rainy given that it is cloudy, we use the concept of conditional probability.

The formula for conditional probability is P(A|B) = P(A u2229 B) / P(B), where P(A|B) is the probability of A given B, P(A \\u2229 B) is the probability of both A and B occurring, and P(B) is the probability of B occurring.

Let A be the event that it is rainy and B be the event that it is cloudy. Therefore, P(A|B) = P(A u2229 B) / P(B) = 0.41 / 0.42 = 0.9762 or 97.62%.

Hence, the probability that a randomly selected day in January will be rainy if it is cloudy is approximately 97.62%.

Find the absolute maximum and minimum values of the function over the indicated​ interval, and indicate the​ x-values at which they occur. f left parenthesis x right parenthesisequalsx squared minus 6 x minus 9​; left bracket 0 comma 7 right bracket

Answers

Answer:

The absolute minimum value of the function over the​ interval [0,7] is -18.

Step-by-step explanation:

The given function is

[tex]f(x)=x^2-6x-9[/tex]

Differentiate f(x) with respect to x.

[tex]f'(x)=2x-6[/tex]

Equate f'(x)=0  to find the critical points.

[tex]2x-6=0[/tex]

[tex]2x=6[/tex]

[tex]x=3[/tex]

The critical point is x=3.

Differentiate f'(x) with respect to x.

[tex]f''(x)=2[/tex]

Since f''(x)>0 for all values of x, therefore the critical point is the point of minima and the function has no absolute maximum value.

3 ∈ [0,7]

Substitute x=3 in the given function to find the absolute minimum value.

[tex]f(3)=(3)^2-6(3)-9[/tex]

[tex]f(3)=9-18-9[/tex]

[tex]f(3)=-18[/tex]

Therefore the absolute minimum value of the function over the​ interval [0,7] is -18.

Final answer:

The maximum value of the function f(x) = x² - 6x - 9 over the interval [0, 7] is 2, which occurs at x = 7, and the minimum value is -9, which occurs at both x = 0 and x = 3.

Explanation:

The function given is f(x) = x² - 6x - 9. To find the maximum and minimum values of this function over the interval [0, 7], we first need to find the critical points of the function. These occur where the derivative of the function is zero or undefined. The derivative of f(x) is f'(x) = 2x - 6. Setting this equal to zero and solving for x gives x = 3. Since this value is within our interval, it is a critical point of the function.

Next, we evaluate the function at the endpoints of the interval and at our critical point. We have f(0) = -9, f(3) = -9, and f(7) = 2. This shows that the maximum value of the function over the interval is 2, which occurs at x = 7, and the minimum value is -9, which occurs at both x = 0 and x = 3.

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The mean speed of a sample of vehicles along a stretch of highway is 67 miles per​ hour, with a standard deviation of 3 miles per hour. Estimate the percent of vehicles whose speeds are between 58 miles per hour and 76 miles per hour.​ (Assume the data set has a​ bell-shaped distribution.)

Answers

Answer:

99.85%

Step-by-step explanation:

Most of today's student calculators have probability distribution functions built in.  Here we are to find the area under the standard normal curve between 58 mph and 76 mph, if the mean speed is 67 mph and the std. dev. is 3 mph.

Here's what I'd type into my calculator:

normalcdf(58, 76, 67, 3)

The result obtained in this manner was 0.9985.  

This states that 99.85% of the vehicles clocked were traveling at speeds between 58 mph and 76 mph.

Answer: 99.9%

Step-by-step explanation:In a normal distribution (bell-shaped distribution), the percent that is between the mean and the standard deviations are:

between the mean and mean + standard deviation the percentage is = 34.1%

between the mean + standard deviation and mean + 2 times the standard deviation is = 13.6%

between the mean + 2 times the standard deviation and the mean + 3 times the standard deviation is: 2.14%

And is the same if we subtract the standard deviation.

So in the range from 58 to 67, we can find 3 standard deviations, and in the range from 67 to 76, we also can find 3 standard deviations:

58 + 3 + 3 + 3 = 67

67 + 3 + 3 + 3 = 76

So the total probability is equal to the addition of all those ranges:

2.14% + 13.6% + 34.1% + 34.1% + 13.6% + 2.14% = 99.9%

So 99.9% of the cars have velocities in the range between 58 miles per hour and 76 miles per hour

Seven friends want to play a game. They must be divided into two teams with three people in each team and one leader. In how many ways can they do it?

Answers

Answer:70

Step-by-step explanation:

Given

total of  7 friends need to be divided in two groups with 3 member each and  1 leader

leader can be chosen out of 7 person in [tex]^7C_1[/tex] ways

And 3 person out of remaining 6 persons in [tex]^6C_3[/tex] ways

thus a total of [tex] ^7C_1\times ^6C_3[/tex]  ways is possible

If order is not matter then

[tex]\frac{140}{2} [/tex] ways are possible

5. The differential equation y 00 − xy = 0 is called Airy’s equation, and is used in physics to model the refraction of light. (a) Assume a power series solution, and find the recurrence relation of the coefficients. [Hint: When shifting the indices, one way is to let m = n − 3, then factor out x n+1 and find an+3 in terms of an. Alternatively, you can find an+2 in terms of an−1.] (b) Show that a2 = 0. [Hint: the two series for y 00 and xy don’t “start” at the same power of x, but for any solution, each term must be zero. (Why?)] (c) Find the particular solution when y(0) = 1, y 0 (0) = 0, as well as the particular solution when y(0) = 0, y 0 (0) = 1.

Answers

Not sure why, but I wasn't able to post my solution as text, so I've written it elsewhere and am posting screenshots of it here.

In the fifth attachment, the first solution is shown above the second one.

Paul has just purchased a $1.250.000 home and made a $400,000 down payment The balance can be amortized at 3% for 30 years What are the monthly payments? (5 marks) Tay

Answers

Answer:

The monthly payment is $3583.63 ( approx )

Step-by-step explanation:

Given,

The total cost of the home = $1,250,000

There is a downpayment of $400,000,

Thus, the present value of the loan, PV =  1250000 - 400,000 = $ 850,000

Annual rate = 3 % = 0.03,

So, the monthly rate, r = [tex]\frac{0.03}{12}=\frac{1}{400}[/tex]

And, time ( in years ) = 30

So, the number of months, n = 12 × 30 = 360

Hence, the monthly payment of the loan,

[tex]P=\frac{PV(r)}{1-(1+r)^{-n}}[/tex]

[tex]=\frac{850000(\frac{1}{400})}{1-(1+\frac{1}{400})^{-360}}[/tex]

[tex]=3583.6342867[/tex]

[tex]\approx \$3583.63[/tex]

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