What is the slope of the line that contains the points (-1, 2) and (3, 3)?​

the assumption being, that there's a 7% sales tax on any item in the store.

so if you buy the jacket, you pay 25.5 plust 7% of 25.5.

and if you buy the shoes for price say "s", then you pay "s" plus 7% of "s".

whatever those two amounts are, they must be $60, because that's all you have in your pocket anyway.

[tex]\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of 25.5}}{\left( \cfrac{7}{100} \right)25.5}\implies 0.07(25.5)~\hfill \stackrel{\textit{7\% of "s"}}{\left( \cfrac{7}{100} \right)s}\implies 0.07s \\\\[-0.35em] ~\dotfill[/tex]

[tex]\bf \stackrel{\textit{jacket}}{25.5}+\stackrel{\textit{jacket's tax}}{0.07(25.5)}+\stackrel{\textit{shoes}}{s}+\stackrel{\textit{shoe's tax}}{0.07s}~~=~~\stackrel{\textit{in your pocket}}{60} \\\\\\ 25.5+1.785+s+0.07s=60\implies 27.285+1.07s=60 \\\\\\ 1.07s=60-27.285\implies 1.07s=32.715\implies s=\cfrac{32.715}{1.07}\implies s\approx 30.57[/tex]

Answer:

[tex]2\ miles[/tex]

Step-by-step explanation:

we know that

The distance around the park is equal to the perimeter of the rectangular park

The perimeter is equal to

[tex]P=2(L+W)[/tex]

we have

[tex]L=\frac{3}{4}\ mi[/tex]

[tex]W=\frac{1}{4}\ mi[/tex]

substitute the values

[tex]P=2(\frac{3}{4}+\frac{1}{4})[/tex]

[tex]P=2(\frac{4}{4})[/tex]

[tex]P=2\ mi[/tex]

Answer:

3 219⁄1000 km. [2 mi.]

Step-by-step explanation:

P = 2l + 2w

P = 2[¾] + 2[¼]

P = 1½ + ½

P = 2

I am joyous to assist you anytime.

This statement would be true: if the vertex of an angle is at the center of the circle, then it would be the central angle.

Answer:

-1

Step-by-step explanation:

To find the slope of a line given two points, you can use [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are points on the line.

Or you could just line up the points vertically and subtract them vertically, then put 2nd difference over first.

Like so:

 (  2   ,     1   )

-(    1  ,     2   )

--------------------

    1          -1

So the slope is -1/1 or just -1.

Answer:

A. f and h

Step-by-step explanation:

For a linear function the First Differences of the y-values must be a constant. i.e. if we take the difference between any two consecutive y values or values of f(x) it should be the constant. For this rule to work, x values must change by the same number every time, which is true for all three given functions.

For function f:

The values of f(x) are: 5,8,11,14

We can see the difference in consecutive two values is a constant i.e. 3, so the First Difference is the same. Hence, function f is a linear function.

For function g:

The values of g(x) are: 8,4,16,32

We can see the difference among two consecutive values is not a constant. Since the first differences are not the same, this function is not a linear.

For function h:

The values of h(x) are: 28, 64, 100, 136

We can see the difference among two consecutive values is a constant i.e. 36. Therefore, function h is a linear function.

To identify the linear relationships in the tables, we need to look for constant rates of change. Functions f and g have this property, while h does not.

In order to identify which functions represent linear relationships, we need to look for patterns in the tables. A linear relationship is characterized by a constant rate of change.

Looking at the tables, we can see that functions f and g have a constant difference between the values in the input column (x) and the output column (y). However, function h does not have a constant rate of change, so it does not represent a linear relationship.

Therefore, the correct answer is A. f and h, as these two functions represent linear relationships.

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The perimeter of the walls is  6 + 6 + 8 + 8 = 28 feet.

The perimeter of the window is 2 + 2 + 1.5 + 1.5 = 7 feet.

Total = 28 + 7 = 35 feet of tape.

I would say B.35 is the answer.

Answer:

The answer is C

Step-by-step explanation:

Answer:

Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.

Step-by-step explanation:

Both linear and nonlinear associations could increase along the whole data set. That's why Joseph and the fourth option are incorrect.

Answer:

The answer would be 14

Step-by-step explanation:

you just divide 28,00 by 200 and that gives you 14

Answer:

y - 15000 = 12500(x-3)

Answer:

D) 1/27

Step-by-step explanation:

The question is: 3^(-3).

Note that there is a negative sign in the number at the power place. This means that you must flip the number, and in this case, put it over 1. The rest is solved as usual:

3^-3 = 1/(3^3) = 1/(3 * 3 * 3) = 1/27

1/27, or D) is your answer.

~

Answer:

128 units^3

Step-by-step explanation:

[tex]v = \frac{b \times b \times h}{3} = \\ = \frac{8 \times 8 \times 6}{3} = \\ = 128 \: {units}^{3} [/tex]

Step-by-step explanation:

base areas x height / 3

a^2 . h / 3

8^2 . 6 / 3

= 128 units^3

iyi ödevler

have a good lesson

Answer:

A=10753.5715 m^2.

Step-by-step explanation:

The area of a triangle with the information SAS given is:

A=1/2 * (side) * (other side) * sin(angle between)

A=1/2 * (204.61)*(120.32) * sin(60.881)

A=10753.5715 m^2.

SAS means two sides with angle between.

Answer: [tex]10,753.57\ m^2[/tex]

Step-by-step explanation:

You need to use the SAS area formula. This is:

[tex]A=\frac{a*b*sin(\alpha)}{2}[/tex]

You know that the  triangular field has sides of 120.32 meters and 204.61 meters and the angle between them measures 60.881°. Then:

[tex]a=120.32\ m\\b=204.61\ m\\\alpha =60.881\°[/tex]

Substituting these values into the formula, you get that the area of this triangle is:

[tex]A=\frac{(120.32\ m)(204.61\ m)*sin(60.881\°)}{2}\\\\A=10,753.57\ m^2[/tex]

Answer:

The expression is (x,y) -----> (x-3,y-2)

Step-by-step explanation:

we have that

A(1,5) ----> A'(-2,3)

so

The rule of the translation is equal to

(x,y) -----> (x',y')

(x,y) -----> (x-3,y-2)

That means-----> the translation is 3 units at left and 2 units down

Answer:

X is parallel to Z

X || Z

Step-by-step explanation:

This is called the transitive property.

It says something like:

If f is related to g and g is related to h, then f is related to h.

The parallel relationship is transitive.

That is,

if X is parallel to Y and Y is parallel to Z, then X is parallel to Z.

If pressure is constant

then PV= nRT

is equivalent to V= ( nR/P) T

V= kT ( where k is constant nR/P)

As V is directly proportional to T

So V1/T1 = V2/T2

Answer:

The correct answer

Step-by-step explanation:

Answer:

Option C 89

Step-by-step explanation:

In this problem we  know that

KJ=KR+RJ

we have

KJ=95 units

KR=6 units

substitute and solve for RJ

95=6+RJ

subtract 6 both sides

RJ=95-6=89 units

Answer:

The correct option is C.

Step-by-step explanation:

We need to find the length of line segment  RJ.

From the given figure it is clear that line segment KJ is the sum of line segments KR and RJ.

[tex]KJ=KR+RJ[/tex]

The length of line segment KJ is 95 units and the length of KR is 6 units.

Substitute KJ=95 and KR=6 in the above equation.

[tex]95=6+RJ[/tex]

Subtract 6 from both the sides.

[tex]95-6=6+RJ-6[/tex]

[tex]89=RJ[/tex]

The length of segment RJ is 89 units. Therefore the correct option is C.

Answer:

9a^2 +  3ab  - 6b^2

Step-by-step explanation:

(3a-2b)(3a+3b)

First term of each grouping is 3a and 3a.

Multiply those you get 9a^2.

Outer term of each grouping is 3a and 3b.

Multiply those you get 9ab.

Inner term of each grouping is -2b and 3a.

Multiply those you get -6ab.

Last term of each grouping is -2b and 3b.

Multiply those you get -6b^2.

Add up all your products from above.

9a^2+9ab+-6ab+-6b^2

There are like terms here.  The 9ab+-6ab which is 3ab.

So you can write your expression now as:

9a^2 + 3ab  +-6b^2

9a^2 +  3ab  - 6b^2

Step-by-step explanation:

[tex]\text{Use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd:\\\\(3a-2b)(3a+3b)\\\\=(3a)(3a)+(3a)(3b)+(-2b)(3a)+(-2b)(3b)\\\\=9a^2+9ab-6ab-6b^2\qquad\text{combine like terms}\\\\=9a^2+3ab-6b^2[/tex]

Answer:

201.143 (approx.) cm²

area of circle = (pi)x(radius)^2

= 22/7 x (8)^2

=22/7 x 64

= 1408/7

= 201.142857143

= 201.143 cm^2 (approx.)

Answer:

the approximate area of circle is 201 cm²

D is the correct option.

Step-by-step explanation:

From, the given figure, the diameter of the circle is 16 cm.

The radius is half of the diameter.

Hence, the radius of circle is 16/2 = 8 cm

The area of a circle is given by

[tex]A=\pi r^2[/tex]

Substituting the value of r and π

[tex]A=3.14(8)^2\\\\A=200.96\\\\A\approx201[/tex]

Therefore, the approximate area of circle is 201 cm²

D is the correct option.

Answer:

3x yrs old

Step-by-step explanation:

Answer:

x ≥ 0

Step-by-step explanation:

The domain of the function is the inputs, or in this case, the x values.

The inputs are  x greater than or equal to zero all the way to infinity.

Answer:

Step-by-step explanation:

The domain includes 0 and all real numbers greater than 0:  x ≥ 0

Answer:

[tex]\large\boxed{(g\circ f)(2)=1296}[/tex]

Step-by-step explanation:

[tex](g\circ f)(x)=g\bigg(f(x)\bigg)\\\\f(x)=-x+8,\ g(x)=x^4\\\\(g\circ f)(x)=\g\bigg(f(x)\bigg)=(-x+8)^4\\\\(g\circ f)(2)\to\text{put x = 2 to the equation}\ (g\circ f)(x):\\\\(g\circ f)(2)=(-2+8)^4=(6)^4=1296[/tex]

[tex]\bf \begin{cases} f(x)=&-x+8\\ g(x)=&x^4\\ (g\circ f)(x) =& g(~~f(x)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(2)=-(2)+8\implies f(2)=\boxed{6} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{(g\circ f)(2)}{g(~~f(2)~~)}\implies g\left( \boxed{6} \right) = (6)^4\implies \stackrel{(g\circ f)(2)}{g(6)} = 1296[/tex]

The length and width of the rectangular field are determined using algebra by setting up and solving two equations which represent the relationships between the length, width, and perimeter of the field. The dimensions are found to be 46 yards for the width and 137 yards for the length.

The dimensions of the rectangular playing field can be found using algebra, specifically the formulas for the dimensions and perimeter of a rectangle. The problem can be translated into two equations reflecting the relationships of the field's width and length to the perimeter.

The first equation is: L = 3W + 5, which represents the relationship that the length is 5 yards longer than triple the width.

The second equation is derived from the formula for the perimeter of a rectangle (P = 2L + 2W), which given the problem's perimeter of 346 yards gets us: 2L + 2W = 346.

Substitute the first equation into the second to solve for the width, then use that result to find the length. The solution indicates that the width of the rectangular playing field is 46 yards, and the length is 137 yards.

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Answer:

43.60

Step-by-step explanation:

12.36+31.24

Answer:

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}x+y+z=2&(1)\\2x+y-z=-1&(2)\\x=5-2z&(3)\end{array}\right\\\\\text{Substitute (3) to (1) and (2):}\\\\\left\{\begin{array}{ccc}(5-2z)+y+z=2\\2(5-2z)+y-z=-1&\text{use the distributive property}\end{array}\right\\\left\{\begin{array}{ccc}5-2z+y+z=2\\10-4z+y-z=-1\end{array}\right\qquad\text{combine like terms}\\\left\{\begin{array}{ccc}5+y-z=2&\text{subtract 5 from both sides}\\10+y-5z=-1&\text{subtract 10 from both sides}\end{array}\right[/tex]

[tex]\left\{\begin{array}{ccc}y-z=-3\\y-5z=-11&\text{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y-z=-3\\-y+5z=11\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad4z=8\qquad\text{divide both sides by 4}\\.\qquad\qquad \boxed{z=2}\\\\\text{Put it to the first equation:}\\\\y-2=-3\qquad\text{add 2 to both sides}\\\boxed{y=-1}\\\\\text{Put the values of}\ z\\text{to (3):}\\\\x=5-2(2)\\x=5-4\\\boxed{x=1}[/tex]

Answer:

probably sas

Step-by-step explanation:

sas because the 2 sides are congruent, but i don't have enough information to know for sure

Answer:

12

Step-by-step explanation:

[tex]\frac{Parts of Water}{Parts of Concentrate} =3[/tex]

3/1=3

9/3=3

36/12=3

Answer:

4/3

Step-by-step explanation:

I drew a picture in the attachment to show what we are looking at.

I found the point (-3,-4).  I drew my angle my triangle from the x-axis and the origin to the point.

The angle that is theta is the one formed by the x-axis and the hypotenuse of the triangle where this hypotenuse was formed from the line segment from the origin to the given point.

[tex]\tan(\theta)=\frac{\text{opposite to }\theta}{\text{adjacent to }\theta}=\frac{-4}{-3}=\frac{4}{3}[/tex]

So we could have said [tex]\tan(\theta)=\frac{y}{x}[/tex].

Answer: 4

Step-by-step explanation: 4 is the answer because an integer is any whole number, but not 0.

Answer:

[tex]f(g(x)) =\sqrt{6x^2-1}[/tex]

Step-by-step explanation:

Given

f(x) = √2x-5

and

g(x) = 3x^2+2

We have to find the composition of both function

f(g(x)) means that we have to put function g in place of x in function f.

[tex]f(g(x))= \sqrt{2*g(x)-5}\\ =\sqrt{2(3x^2+2)-5}\\=\sqrt{6x^2+4-5}\\=\sqrt{6x^2-1}[/tex]

..

The composite function f(g(x)) is given by f(g(x)) = √(6x^2 - 1).

To find the composite function f(g(x)), you need to substitute the expression for g(x) into the function f(x). Here's how you can do it step by step:

Start with the function g(x):

g(x) = 3x^2 + 2

Now, substitute this expression into the function f(x):

f(g(x)) = √(2(3x^2 + 2) - 5)

Simplify the expression inside the square root:

f(g(x)) = √(6x^2 + 4 - 5)

Further simplify the expression inside the square root:

f(g(x)) = √(6x^2 - 1)

So, the composite function f(g(x)) is given by:

f(g(x)) = √(6x^2 - 1)

for such more question on composite function

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