Calculate the mass of Octane needed to release 6.20 mol Co2

Answers

Answer 1

Final answer:

To find the mass of octane required to produce 6.20 mol CO2, we use the stoichiometry of the combustion reaction and the molar mass of octane, resulting in a requirement of 88.56 grams of octane.

Explanation:

To calculate the mass of octane (C8H18) needed to produce 6.20 mol CO2, we first need the balanced chemical equation for the combustion of octane:

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O

This equation tells us that 2 moles of octane produce 16 moles of CO2. From this, we can find the molar ratio between octane and CO2, which is 2 moles of octane per 16 moles of CO2, or 1 mole of octane for every 8 moles of CO2.

Next, we use the molar mass of octane, which is 114.23 g/mol (C=12.01 g/mol x 8 + H=1.008 g/mol x 18). Given that we have 6.20 moles of CO2, we can calculate the moles of octane needed:

6.20 mol CO2 x (1 mol C8H18 / 8 mol CO2) = 0.775 mol C8H18

Finally, we convert moles of octane to mass:

0.775 mol C8H18 x 114.23 g/mol = 88.56 g C8H18

Therefore, 88.56 grams of octane are needed to produce 6.20 moles of CO2.


Related Questions

The ______________of matter depends upon how close the individual particles are together. A) identity B) mass C) state D) temperature

Answers

Actually it’s c because if the particles are extremely loose they’re most likely a gas if they lose but close they’re a liquid and if they’re organized.

Answer:

State

Explanation:

The state of matter depends on the closeness of the particles. Gases have particles that are very far apart and solids are close together. This is determined by the strength of attraction of these particles to one another.

Which state of matter is most likely represented in the diagram shown below?

A square is shown with the title State of Matter. An array of circles arranged neatly in rows and columns is shown. Tiny single arcs are shown near some circles near the outer edge of the array

Gas
Solid
Liquid
Plasma

Answers

I am actually taking this test right now and I think it is Solid please let me know if I am correct

its defiantly a solid, because the particles are packed in close together and it has a definite shape and volume. water is lose and not packed in like this. and with gas, the particles would juts fly everywhere and plasma is electricity and a wild card. so its definitely a solid, trust me

Consider a certain type of nucleus that has a half-life of 32 min. calculate the percent of original sample of nuclides remaining after 1.9 hours have passed

Answers

t1/2 = ln 2 / λ = 0.693 / λ
Where t1/2 is the half life of the element and λ is decay constant.

32 = 0.693 / λ 
λ   = 0.693 / 32          (1) 

Nt = Nο eΛ(-λt)          (2)

Where Nt is atoms at t time, λ is decay constant and t is the time taken.
t = 1.9 hours = 1.9 x 60 min

From (1) and (2),


Nt = Nο e⁻Λ(0.693/32)*1.9*60
Nt =  0.085Nο 

Percentage = (Nt/Nο) x 100%
                   = (0.085Nο/Nο) x 100%
                   = 8.5%

Hence, Percentage of remaining atoms with the original sample is 8.5%

Final answer:

To calculate the percent of nuclides remaining after 1.9 hours, given a half-life of 32 minutes, we find that about 3.56 half-lives have passed and approximately 9.09% of the original sample remains.

Explanation:

The question concerns the calculation of the remaining nuclides in a sample after a period of time, given the half-life of the substance. If the half-life of a certain type of nucleus is 32 minutes, we first need to calculate how many half-lives are in 1.9 hours. Since there are 60 minutes in an hour, 1.9 hours equals 114 minutes. Dividing 114 minutes by the half-life of 32 minutes gives us approximately 3.56 half-lives.

After each half-life, the amount of a radioactive material will halve. To find the remaining percent, we use the formula:

Percent Remaining = (1/2)number of half-lives passed

Therefore, for 3.56 half-lives passed, the calculation is as follows:

Percent Remaining = (1/2)3.56

Punching this into a calculator, we find that about 9.09% of the original sample remains after 1.9 hours have passed.

HELPPPP PLEASE ASAP!!!

Answers

Answer:

230
     Th
  90

Explanation:

The left side shows the element uranium with mass number 234 (superscript to the left of ths symbol) and atomic mass 92 (subscript to the left of the symbol).

So,  you have to find the mass number and atomic numbers missing on the right side which added to those shown for the helium atom reach 234 and 92.

This the the mathematics:

1) Mass number of U - mass number of He = 234 - 4 = 230 ⇒ the mass number of the missing element is 230.

2) atomic number of U - atomic number of He = 92 - 2 = 90 ⇒ the atomic number of the missing element is 90.

Now, you use the atomic mass to identify the element. You do it by simply searching in a periodic table. There you find that the atomic number 90 corresponds to thorium, whose symbol is Th.

Now you have that the product that completes the right side of the decay equation is:

230
     Th
  90


You adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30°C to 36°C. What's the velocity of the sound wave at this new temperature? A. 335.6 m/s B. 352.6 m/s C. 344.0 m/s D. 350.0 m/s

Answers

The equation relating the velocity of sound in air to the air temperature is: v = 331 + 0.6T, where T is the temperature in degrees Celsius. For this case, when T = 36 C:
v = 331 + 0.6(36) = 331 + 21.6 = 352.6 m/s, which is choice B

What is the change in atomic mass when an atom emits an alpha particle? A. decreases by 2 B. decreases by 1 C. decreases by 4 D. remains the same

Answers

Answer is "C"

alpha decay is an emission of ₂⁴He nucleus. If an element undergoes an alpha decay, the mass of the daughter nucleus formed is reduced by 4 compared to mass of parent atom and atomic number is reduced by 2 compared to atomic number of parent atom.

QUICK TIMES RUNNING OUT!


What method could you use to seperate oil from water? Remember that the both must still remain, they just have to be seperated.

Answers

1. You could drain off the oil as a supernatant, since oil is less dense than water.
2. You could attempt to evaporate the water since they have different boiling points (212 vs 572 F), and then condense it in a separate container using a distillation unit.

Identify the three ingredients used in a blast furnace to make pig iron.

Answers

Final answer:

The three ingredients used in a blast furnace to make pig iron are roasted ore, coke, and limestone.

Explanation:

In a blast furnace, the three ingredients used to make pig iron are:

Roasted Ore: The iron ore is heated in air to remove water and convert sulfides into oxides.Coke: This is a fuel made by heating coal in the absence of air. It provides the high temperature required for the reduction reactions.Limestone: Impure calcium carbonate (CaCO3) is added to remove impurities and form s_lag.

The combination of these three ingredients undergoes various reactions in different temperature zones of the blast furnace, resulting in the production of molten iron and s_lag.

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In which set are the substances arranged in order of decreasing solubility in water? (a) (c) al(oh)3 > mg(oh)2 > naoh cac03 > nahc03 > na2c03 (b) (d) bas04 > cas04 > mgs04 agcl > agbr > agl?

Answers

(A) Al(OH)₃ > Mg(OH)₂ > NaOH
polarity is increasing as the metallic character is increasing . So this order is not correct. NaOH as we all know is completely soluble in water.

(B) BaSO₄> CaSO₄ > MgSO₄
This one is also not correct because here also polarity is increasing so solubility should increase.

(C) CaCO₃> NaHCO₃ > Na₂CO₃
this is als not correct .Na₂CO₃ is more polar is completely soluble in water whereas CaCO₃ is insoluble.

(D) AgCl > AgBr > AgI
In D as we go from AgCl to AgI polarity is decreasing so solubility is decreasing .

Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 7.80 moles of magnesium perchlorate, Mg(ClO4)2.

Answers

 The number of moles of moles of  Magnesium,chlorine and oxygen atoms in 7.80 moles of Mg(ClO4)2 is calculated as below

find the total number of each atom in Mg(ClO4)2

that is mg = 1 atom
        Cl =  1x2 = 2 atoms
        O  = 4  x2 = 8 atoms

then multiply 7.80 moles with total number of each atom , to get the number moles of each atom
that is

Mg = 7.80 x1= 7.80  moles
cl =   7.80  x2=15.6  moles
O =  7.80 x8= 62.4 moles

In 7.80 moles of magnesium perchlorate (Mg(ClO4)2), there are approximately 7.80 moles of magnesium atoms, 15.60 moles of chlorine atoms, and 31.20 moles of oxygen atoms.

Magnesium perchlorate (Mg(ClO4)2) consists of one magnesium (Mg) atom, two chlorine (Cl) atoms, and eight oxygen (O) atoms per formula unit. To calculate the number of moles of each element in 7.80 moles of magnesium perchlorate, you can use the mole ratios from the chemical formula.

First, you have 7.80 moles of the entire compound. Since there is one magnesium atom in each formula unit, there are also 7.80 moles of magnesium atoms. Similarly, as there are two chlorine atoms in each formula unit, you have 2 * 7.80 = 15.60 moles of chlorine atoms. Lastly, since there are eight oxygen atoms in each formula unit, there are 8 * 7.80 = 62.40 moles of oxygen atoms. So, in 7.80 moles of magnesium perchlorate, you have approximately 7.80 moles of magnesium atoms, 15.60 moles of chlorine atoms, and 31.20 moles of oxygen atoms.

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Twice bill's number added to 17 is 7. What is his number

Answers

-5.

-5 * 2 = -10
-10 + 17 = 7
Let b=bills number
2b+17=7
Subtract 17 from both sides
2b=-10
Divide both sides by 2
b=-5
Bill’s number is -5

I hope this helps )

The equilibrium concentrations were found to be [br2] = 2.2 × 10−3 m, [cl2] = 3.0 × 10−2 m, and [brcl] = 1.5 × 10−2 m. write the equilibrium expression, and calculate the equilibrium constant for this reaction at this temperature.

Answers

[tex]Br_{2} + Cl_{2}---\ \textgreater \ 2BrCl K_{eq} = \frac{[BrCl]^{2}}{[Br_{2}][Cl_{2}]]} = \frac{[1.5*10^{-2}]^{2}}{[2.2*10^{-3}][3.0*10^{-2}]} =0.34*10=3.4 K_{eq}=3.4[/tex]

What is the noble gas configuration for silicon? [Ne] 3s2 3p1 [Ar] 4s1 [Kr] 5s1 [Ne] 3s2 3p2

Answers

Answer: The noble gas notation for silicon atom is [tex][Ne]3s^23p^2[/tex]

Explanation:

Noble gas notation is defined as the notation in which the configuration of an atom is written in terms of previous noble gas.

Silicon is the 14th element of the periodic table having 14 electrons.

The nearest noble gas to this element is neon.

So, the noble gas notation for silicon atom = [tex][Ne]3s^23p^2[/tex]

Write a balanced equation to show the reaction of gaseous ethane,c2h6 with gaseous oxygen to form carbon monoxide gas,co, and water vapor

Answers

2C2H6 + 5O2 = 4co + 6h2o

Answer: The balanced chemical equation is written below.

Explanation:

Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

If supply of oxygen gas is limited, it is known as incomplete combustion and carbon monoxide gas is also produced as a product.

The chemical equation for this reaction of ethene and oxygen gas follows:

[tex]2C_2H_6+5O_2\rightarrow 4CO+6H_2O[/tex]

By Stoichiometry of the reaction:

2 moles of ethene gas reacts with 5 moles of oxygen gas to produce 4 moles of carbon monoxide gas and 6 moles of water vapor.

Hence, the balanced chemical equation is written above.

Our good friend and pseudo scientist, homer simpson, attempts to analyze 300 mg of an unknown compound containing only c and h by burning it in excess oxygen. 540 mg of h2o is produced. you may assume that all the hydrogen in the compound ended up as water.

Answers

[tex] C_{x}H_{y} + O_{2} --\ \textgreater \ x CO_{2} + \frac{y}{2} H{2}O 540mg H_{2}O* \frac{1 mmol H_{2}O}{18 mg H_{2}O} =30 mmol H_{2}O \\ \\30 mmolH_{2}O -have - 60 mmol H \\ \\ 60 mmol H* \frac{1mg H}{1 mmol H} =60 mg H \\ \\300mg C_{x}H_{y} - 60 mg H= 240 mg C \\ \\ 240 mgC* \frac{1mmol}{12mg} =20 mmol C 20 mmol C: 60 mmol H=1 mol C : 3 mol H [/tex]

It is found that doubling the concentration of a quadruples the reaction rate and tripling the concentration of b triples the reaction rate. what is the overall order of the reaction?

Answers

Reactant A must be second order and reactant B first order. Overall = add them so 3rd order.

The reaction is second order with respect to reactant A and first order with respect to reactant B, giving an overall reaction order of 3.

To determine the overall order of a reaction, we need to find the individual orders with respect to each reactant.

1. Doubling the concentration of reactant A increases the reaction rate by a factor of four. This indicates that the reaction is second order with respect to A, because 2² = 4.

2. Tripling the concentration of reactant B increases the reaction rate by a factor of three. This means the reaction is first order with respect to B, because 3¹ = 3.

Therefore, the overall order of the reaction is the sum of the orders with respect to each reactant:

Order with respect to A: 2Order with respect to B: 1

The overall order = 2 + 1 = 3.

A 5.018 gram sample of a certain hydrate of magnesium sulfate, mgso4•xh2o, is heated until all the water is driven off. the resulting anhydrous compound weighs 2.449 grams. what is the formula of the hydrate?

Answers

Hydrate of magnesium sulphate undergoes dehydration upon action of heat. This process can be chemically represent as follows:

MgSO4.XH2O  → MgSO4 + XH20
       (5.018 g)      (2.449 g)     (2.569 g)

Number of moles of H2O evolved = [tex] \frac{2.569}{Molecular.weight} [/tex]
                                                      = [tex] \frac{2.569}{18} [/tex]
                                                      = 0.1427
Number of moles of MgSO4 generated after decomposition,
= [tex] \frac{2.449}{Molecular.weight} [/tex]
=[tex] \frac{2.449}{120.37} [/tex]
=0.0203

Now dividing  both these numbers by the smallest one to get the mole ratio that exists between MgSO4 and H20

For H2O, [tex] \frac{0.1427}{0.0203} [/tex] = 7.02 ~7

Thus, formula of hydrate is MgSO4.7H2O

Choose all the answers that apply. The sun: heats the earth evenly;can acclerate the water cycle;is closer to the earth during the summer;is the perfect distance from earth;causes surface waves

Answers

can accelerate the water cycle; is the perfect distance from earth

Answer:

Heats the earth evenly;can acclerate the water cycle;is the perfect distance from earth.

Explanation:

Radiation is the most important process of heat propagation, because it is through it that the heat of the sun reaches the earth. Without this process there would be no life on earth. While conduction and convection occur only in material media, radiation also occurs in a vacuum, so it is possible for the sun to heat the earth evenly.

The heat radiated by the sun heats the water of rivers, lakes, seas and oceans occurring the phenomenon of evaporation during the water cycle. At this point, the liquid state of water changes to its gaseous state as it moves from the earth's surface to the atmosphere. For this reason we can say that the sun can accelerate the water cycle.

Although the Earth's orbit around the Sun is an ellipse, not a circle, the distance from Earth to the Sun varies by only 3%, with the Earth being closest to the Sun from January 4-7 each year, depending on leap year. But it's easy to remember that the northern hemisphere of the earth is also closer to the sun in January and it's winter there, while it's summer in the southern hemisphere. So we cannot say that the earth is closer to the sun in summer, but between January 4th and 7th.

Living conditions on earth are a puzzle to astronomy. A little closer to the sun - and we'd be a greenhouse and toxic high-pressure gas plant like Venus. A little farther - and the gases would escape, the water would freeze, there would be at most microbes, as on Mars. The earth is the perfect distance to house water, oxygen, carbon and complex life forms.

Surface Waves are seismic waves that propagate to the Earth's surface and result from interference between P waves and S waves (called volumetric waves). It is to the surface waves that are due to the great destruction caused by the earthquakes. The sun does not interfere with the creation of these waves, which is a factor caused by the movement of the earth and other geological terms.

Compound j is optically active and has the molecular formula c6h10 and has a four carbon ring. on catalytic hydrogenation, j is converted to k (c6h12) and k is optically inactive. propose structures for j and k. (draw a three-dimensional formula for each using dashes and wedges around chiral centers.) j (draw one of the enantiomers):

Answers

Final answer:

Compound J, with the formula C6H10, could be a cyclobutane with two methyl groups creating a chiral center, which becomes a non-chiral cyclohexane (C6H12) upon hydrogenation.

Explanation:

The student's question is related to the identification of the structures of an optically active compound with the molecular formula C6H10, and its hydrogenated form C6H12.

Compound J must be a cycloalkane with a four-carbon ring to fit the given molecular formula and to be optically active, it should contain at least one chiral center. Given that hydrogenation leads to an optically inactive compound (K), it suggests that compound J had one or more chiral centers which become quenched upon hydrogenation.

One possible structure for J could be a cyclobutane ring with two methyl groups bonded to adjacent carbon atoms, creating a chiral center at one of those carbons. Upon hydrogenation, the double bonds are saturated, resulting in a compound with all single bonds, thus removing any chirality and creating an optically inactive compound (K).

The proposed structure for J could be represented as follows (for one of the enantiomers):

Cyclobutane ring with a chiral center (drawn using dashes and wedges).Two methyl groups (-CH3) attached to adjacent carbons.

And for compound K, after hydrogenation:

Cyclohexane (since the addition of H2 would give us C6H12, which is the formula for cyclohexane).No chiral centers as all carbons are in the plane of symmetry.

What is the consequence of deforestation?

Answers

loss of biodiversity

Answer:

The consequence of deforestation is discussed below.

Explanation:

One of the outcomes of deforestation is a waste of biodiversity. Deforestation also improves greenhouse gas discharges, disturbs the water series, improves soil erosion and reduces the physical attraction of a region.deforestation causes the Decline of nutrients in the clay that are obtained from the categorization of tree petals.

For a solution with an [oh−] of 10−8 m, what would be the value of [h+] , ph and poh, respectively? 1. 106 m, 6, 8 2. 10−6 m, 6, 8 3. 10−6 m, 8, 6 4. 10−14 m, 6, 8 5. 10−6 m, 6, 14 6. 10−14 m, 8, 6

Answers

Q1)pOH
the hydroxide ion concentration can be used to calculate the pOH of the solution 
pOH can be calculated using the following equation 
pOH = -log[OH⁻]
pOH = -log (10⁻⁸ M)
pOH = 8
therefore pOH of solution is 8

Q2) pH 
by knowing the pOH value we can calculate the pH value
since
pH + pOH = 14
and pOH = 8
therefore pH = 14 - 8
pH = 6

Q3)
pH scale is used to determine how acidic or basic a solution is
knowing the pH value we can calculate hydrogen ion concentration 
pH = -log[H⁺]
[H⁺] = antilog(-pH)
[H⁺] = antilog(-6)
[H⁺] = 10⁻⁶ M

answer is 2. 10⁻⁶ M, 6, 8

When atoms of two or more different elements bond, their properties ___________.
A. are the same as the largest atom in the compound
B. change
C. combine
D. None of these

Answers

When atoms of two or more different elements bond, their properties change.


So,
Option B is the correct one.

When atoms of two or more different elements bond, their properties change.

What is the difference between molecules and compounds?

When two or more atoms of the same element chemically combine, a molecule is created.

Examples: O₂, O₃, H₂

A compound is a type of molecule in which the atom types that make up the molecule differ from one another.

Examples: NaCl, H₂O

Properties of compound:Only chemical breakdown can separate compounds.Different atoms of elements are present in a defined ratio.

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The molecular mass of methyl ethanoate is 75.1 amu . calculate the molecular mass of propanoic acid, an isomer of methyl ethanoate. express your answer with the appropriate units.

Answers

Final answer:

The molecular mass of propanoic acid, an isomer of methyl ethanoate, is 74.09 amu, calculated by the sum of atomic masses of carbon, hydrogen, and oxygen in its molecular formula, C3H6O2.

Explanation:

To calculate the molecular mass of propanoic acid, an isomer of methyl ethanoate, we need to first understand that isomers are compounds with the same molecular formula but different structures, and hence, the same molecular mass. Propanoic acid's molecular formula is C3H6O2. Using the atomic masses of carbon (12.01 amu), hydrogen (1.01 amu), and oxygen (16.00 amu), we calculate the molecular mass as follows:

(3 × 12.01 amu) + (6 × 1.01 amu) + (2 × 16.00 amu) = 36.03 amu + 6.06 amu + 32.00 amu = 74.09 amu

Therefore, the molecular mass of propanoic acid is 74.09 amu.

Which equilibrium reaction will experience a shift towards the products in equilibrium position when the concentration of ni2+ is increased? view available hint(s) which equilibrium reaction will experience a shift towards the products in equilibrium position when the concentration of is increased? ni2+(aq)+6nh3(aq)⇌[ni(nh3)6]2+ [ni(h2o)6]2+(aq)+3en(aq)⇌[ni(en)3]2+(aq)+6nh3(aq) ni(oh)2(s)⇌ni2+(aq)+2oh−(aq) nis(s)⇌ni2+(aq)+s2−(aq)?

Answers

Answer is 
      Ni²(aq) + 6NH(aq) [Ni(NH)

When the concentration of Ni²⁺(aq) increases, according to the Le Chatelier’s principle system tries to become equilibrium by reducing the increased factor. To do that, the concentration of Ni²⁺(aq) should be reduced. Hence, the forward reacted should be promoted to reduce the Ni²⁺(aq) concentration.

The process by which complex compounds are decomposed by living systems is called
fermentation
distillation
oxidation
reduction

Answers

A. Fermentation

Hope this helps!
the answer is fermentation

a section of the periodic table is shown below which of the following statements is true?

Answers

Oxygen is more reactive than fluorine because oxygen needs only one electron to fill its outermost shell.
Neon is inert because its outermost shell is complete. Neon is already in noble gas configuration and it will be very difficult to change this, essentially making it inert.

Nitrogen is inert because its outermost shell has eight electrons. Nitrogen's outermost shell only has 3 electrons so it is generally unstable and wants to gain 3 more to be in noble gas configuration.

Oxygen is more reactive than fluorine because oxygen needs only one electron to fill its outermost shell. This is just completely false, Fluorine is the most reaction element there is.

Fluorine is more reactive than neon because fluorine has to lose only one electron to fill its outermost shell. Although fluorine is more reactive, this is because it only needs to GAIN one more electron, not lose one more.

Does the structure below exhibit geometric isomerism? ch3 tally1 ch3― c ―ch═ch―ch3 tally1 ch3

Answers

Answer:
            YES! The given compound exhibit Geometrical Isomerism.

Explanation:
                   In Geometrical Isomerism or Cis-Trans Isomerism, isomers possess same molecular formula, same structural formula with a double bond and with a only difference in the arrangement of atoms or group of atoms about the double bond in three dimensional space.
                   4,4-dimethylpent-2-ene (given problem) has two groups about the double bond i.e. Methyl (CH₃-) and tertiary Butyl [(CH₃)₃-C-]. In cis configuration both groups are at same side of the double bond, while in trans configuration both groups are located opposite to each other as shown below,

What is the rate of a reaction if the value of k is 0.01, [A] is 2 M, and [B] is 3 M? Rate = k[A]3[B]2

Answers

rate equation for the reaction is as follows
Rate = k [A]³[B]²
concentration of A = 2 M
concentration of B = 3 M
k - rate constant - 0.01
as this is a 5th order reaction, units for rate constant are M⁻⁴s⁻¹
substituting these values in the equation 

Rate = k [A]³[B]²
rate = 0.01 M⁻⁴s⁻¹ x (2 M)³ x (3 M)²
rate = 0.01 x 8 x 9 = 0.72
rate of the reaction is 0.72 M/s



Anthracene is a yellow, crystalline solid found in coal tar. complete this structure for anthracene, c14h10, by adding bonds and hydrogen atoms as necessary.what type of hybrid orbitals are utilized by carbon in anthracene?how many σ bonds and π bonds are there in an anthracene molecule? how many valence electrons occupy σ-bond orbitals and how many occupy π -bond orbitals?

Answers

Anthracene is a polycyclic aromatic hydrocarbon with chemical formula C₁₄H₁₀. The number of fused rings in Anthracene are three in number. This compound is colorful and is used in the formation of different dyes due to its property of deloclization of pi electrons. All the carbon atoms in Anthracene are sp² hybridized with a trigonal planar structure hence, the Anthracene is planar in nature.

Number of Sigma Bonds:

                                         There are 26 sigma bonds (colored in Blue) in Anthracene among which 10 sigma bonds are between carbon and hydrogen atoms while the remaining are between the carbon atoms.

Number of Pi-Bonds:

                                  There are 7 pi bonds in Anthracene (colored in red). All pi bonds are present between carbon and carbon atoms.

Number of Electrons in Sigma Bonds:

                                                             As one sigma bond is formed by 2 electrons hence, 26 sigma bonds will be formed by 52 electrons.

Number of Electrons in Pi Bonds:

                                                       As one pi bond is formed by the side wise overlap of two p orbitals hence one pi bond is formed by two electrons so, 7 pi bonds will be formed by 14 electrons.

The hybrid orbital that is utilized by the carbon in anthracene is [tex]\boxed{{\text{s}}{{\text{p}}^2}}[/tex] .

The anthracene molecule contains [tex]\boxed{{\mathbf{26}}{\text{ }}{\mathbf{sigma}}}[/tex] bonds and [tex]\boxed{{\mathbf{7}}{\text{ }}{\mathbf{\pi }}}[/tex]  bonds.

The number of valence electrons in sigma orbital is [tex]\boxed{{\mathbf{52}}}[/tex]  and pi-orbitals is [tex]\boxed{{\mathbf{14}}}[/tex] .

Further explanation:

The anthracene is a crystalline compound and it is yellow in color. It contains three fused rings of benzene thus it is a polyaromatic compound.it has a molecular formula [tex]{{\text{C}}_{{\text{14}}}}{{\text{H}}_{{\text{10}}}}[/tex].

Prediction of hybridization:

The hybridization can be determined by calculating the number of hybrid orbitals (X) which is to be formed by the atom. The formula to calculate the number of hybrid orbitals (X) as follows:

[tex]\boxed{{\text{X}}={\text{Number of bond pair}}+{\text{Number of lone pair}}}[/tex]

Here X is a steric number.

When X is 2 then hybridization is sp.

When X is 3 then hybridization is [tex]{\text{s}}{{\text{p}}^2}[/tex].

When X is 4 then hybridization is [tex]{\text{s}}{{\text{p}}^3}[/tex] .

The structure of anthracene is attached in the image.

Since all carbon atom in anthracene contains three bond pairs and no lone pair thus, the hybridization can be calculated as follows:

[tex]\begin{aligned}{\text{X}}&={\text{Number of bond pair}}+{\text{Number of lone pair}}\\&=3+0\\&=3\\\end{aligned}[/tex]

The value of X is 3, therefore, the hybridization of each carbon in anthracene is [tex]{\text{s}}{{\text{p}}^2}[/tex]  

The structure of anthracene contains 26 sigma bond and 7 pi bonds. (refer to the image attached).

The number of valance electron in sigma orbital is twice of the number of sigma bond present in the molecule because every sigma bond contains 2 electrons.

[tex]{\text{Valence electron in sigma orbital}} = 2\left({{\text{sigma bond}}}\right)[/tex]

In anthracene, number of sigma bond is 26, therefore,

[tex]\begin{aligned}{\text{Valence electron in sigma orbital}}&=2\left({{\text{sigma bond}}}\right)\\&=2\left({{\text{26}}}\right)\\&=52\\\end{aligned}[/tex]

The number of valance electron present in pi-orbital is twice of the number of pi bond present in the molecule because every pi-bond contains 2 electrons.

[tex]\begin{aligned}\text{Valence electron in }\pi\text{-orbital}&=2(\pi\text{-bond})\end{aligned}[/tex]

In anthracene, number of pi bond is 7, therefore,

[tex]\begin{aligned}\text{Valence electron in }\pi\text{-orbital}&=2(\pi\text{-bond})\\&=2(7)\\&=14\end{aligned}[/tex]

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Answer details:

Grade: Senior school

Subject: Chemistry

Chapter: Covalent bonding

Keywords: Anthracene, yellow crystalline, coal tar, structure of anthracene, C14H10, hybrid orbitals.

) what is the mass percent of a solution prepared by dissolving 18.9 grams of an unknown solid into 39.5 grams of water?

Answers

The  mass %  of  a solution  prepared  by   dissolving 18.9  grams  of  an unknown  solid into  39.5 grams of water is  calculated as  below


%(M/M) =  mass of the solute(unknown  salt)/ mass of the solvent(water)  x 100

 = 18.9 g/ 39.5 g x100  =47.85% (M/M)

Answer:

32.4%

Explanation:

Step 1: Given data

Mass of the solute = 18.9 g

Mass of the solvent = 39.5 g

Mass of the solution = Mass of the solute + Mass of the solvent = 58.4 g

Step 2: Calculate the mass percent of the solute in the solution

We use the following expression.

[tex]\% m/m =\frac{mass\ of\ the\ solute}{mass\ of\ the\ solution} \times 100\%=\frac{18.9g}{58.4g} \times 100\% =32.4\%[/tex]

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