The forces that act upon a baseball player diving head-first into second base and sliding on the infield dirt are the Normal Force, Gravity Force, and Friction Force.
Explanation:When a baseball player dives head-first into second base and slows down while sliding on the infield dirt, several forces act upon the player. These forces include:
Normal Force: The ground exerts an upward force on the player, preventing them from sinking into the ground.Gravity Force: The force that pulls the player downward towards the center of the Earth.Friction Force: The force between the player and the infield dirt that opposes their motion and slows them down.Air Resistance Force: This force is negligible in this situation because the player is sliding on the ground.Therefore, the correct answers would be a. Normal Force, b. Gravity Force, d. Friction Force.
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You wad up a piece of paper and throw it into the wastebasket. How far will
your piece of paper travel if you throw it with a velocity of 4.3 m/s at an angle
of 65°? (Assume no air resistance and that the paper lands at the same
height you threw it from.)
Answer: 1.4m
Explanation:
Force
A.
Tell the forces at work in the diagram and for the sentences.
drag
lift
thrust
gravity
Force
Answer:
Upward force is lift.
Downward force is gravity.
Thrust act towards left.
Drag act towards right.
Explanation:
The forces acting on the airplane are:
1. Downward force which is due to Earth's gravitation and hence gravitation force acts in the downward direction.
2. Air applies a force in the upward direction in order to make the airplane float in air. This force is called lift force as it lift the airplane in the air.
3. Forward force acts on the airplane which is thrust force which causes the airplane to move forward.
4. The air resists the motion of the airplane and hence applies a force in the backward direction known as drag force.
The orbital period of a satellite is 2 x 106 s and its total radius is 2.5 x 1012 m.
The tangential speed of the satellite, written in standard notation, is
m/s.
Answer:
7,853,982 is the correct answer on Edge 2020
Explanation:
Answer: 7,853,982
Explanation:
All it's asking you is:
-- here's the radius of a circle
-- here's how long it takes to go around the circle
-- how fast are you traveling around the circle ?
I hope that's less scary.
_____________________________
Circumference of a circle =
(pi) x (diameter)
= (pi) x (2 x radius)
= (5 pi) x 10¹² meters .
Time to go around the circle = 2 x 10⁶ seconds
Speed = (distance) / (time)
= (5 pi x 10¹² m) / (2 x 10⁶ sec)
= 2.5 pi x 10⁶ m/s
= 7,853,982
When building a home what feature would be the most beneficial in the winter to keeping heat in a home and cold out
Answer:
insulation is what would keep the cold out and bring in heat
Water flow will be reduced in a pipe if the pipe is constricted. True False
The CORRECT answer is TRUE.
5L=__ML
Express your answer in scientific notation
5 x 109
5x 106
5x 103
Answer:
5000ml is the answer
Explanation:
multiply 5 time 1000
When you and a friend move a couch to another room you exert a force of 75 N over 5m how much work will you do
The work done is 375 J
Explanation:
The work done by a force in moving an object is given by
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement
[tex]\theta[/tex] is the angle between the direction of the force and the displacement
In this problem,
F = 75 N is the force applied to the couch
d = 5 m is the displacement
Assuming the force applied to the couch is parallel to the motion, [tex]\theta=0[/tex]
And so, the work done is
[tex]W=(75)(5)(cos 0)=375 J[/tex]
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Final answer:
When moving a couch with a force of 75 N over a distance of 5 meters, you and a friend will do a total of 375 Joules of work. The calculation is based on the formula Work = Force x Distance.
Explanation:
When you and a friend move a couch to another room and exert a force of 75 N over 5m, you can calculate the amount of work done with the formula Work = Force x Distance. In this scenario, since the force exerted is 75 N and you move the couch over a distance of 5 meters, the work done can be computed as:
Work = 75 N x 5 m = 375 Joules.
This means you and your friend will do a total of 375 Joules of work in moving the couch to another room, assuming the movement is in the direction of the applied force and that friction or other forces are not taken into account for this particular calculation.
Which of the following has the greatest number of particles A) 1 mole of Na B)22.990g of Na C) 1 mole of Be D) 9.012 g of Be E) all are the same
E) all are the same
Explanation:
Mole:
The mole(mol) is a unit of amount in chemistry. One mole of a substance refers to the mass of Avogadro's Number of particles of that substance. The number of particles in 12.00 g of Carbon(12) is called Avogadro's Number which is equal to 6.022 x 10²³.
A particle refers to an atom in case of an element or a molecule in case of a compound. Particles of different substance might vary in mass or size. Thus, equal number of particles of two different substances might have different masses in grams.
1 mole of Na has Avogadro Number of particles.
22.990 g of Na is equal to 1 mole of Na and has Avogadro Number of particles.
Similarly, 9.012 g of Be is also equal to 1 mole and has Avogadro Number of Be atoms.
Hence, the number of particles of all the three options are same.
Keyword: Avogadro Number
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E) all are the same
Explanation:The question requires we identify the amount of an element with the greatest number of particles.
We need to know that 1 mole of an element contains particles equivalent to the Avogadro's number, 6.022 × 10^23.That is, 1 mole of an element = 6.022 × 10^23 particlesIn this case;
Choice A
1 mole of Na
1 mole of Na contains 6.022 × 10^23 atoms
Choice B
22.990 g of Na
The molar mass of sodium is 22.99 g/mol
Therefore, 22.990 g of Na contains 6.022 × 10^23 atoms
Choice C
1 mole of Be
1 mole of Be contains 6.022 × 10^23 atoms
Choice D
9.012 g of Be
But, the molar mass of Be is 9.012 g
Thus; 9.012 g of Be contains 6.022 × 10^23 atoms
We can therefore, conclude that all the given choices are the same, they have equal number of particles.a 5.000 kg crate is accelerated from 5.000 m/s to 10.00m/s what is the amount of work needed to accelerate the crate to the nearest tenth of a joule
To find the work needed to accelerate the crate from 5.000 m/s to 10.00 m/s, we calculate the change in kinetic energy, which comes out to be 187.5 J when rounded to the nearest tenth.
Explanation:To determine the work done on the crate, we can use the work-energy principle which states that the work done on an object is equal to the change in its kinetic energy. The kinetic energy (KE) of an object is given by the equation KE = ½mv², where m is the mass and v is the velocity.
First, we calculate the initial kinetic energy (KEi) using the initial speed of 5.000 m/s:
KEi = ½ × 5.000 kg × (5.000 m/s)² = ½ × 5.000 × 25.00 = 62.50 J
Next, we calculate the final kinetic energy (KEf) using the final speed of 10.00 m/s:
KEf = ½ × 5.000 kg × (10.00 m/s)² = ½ × 5.000 × 100.0 = 250.0 J
The work done (W) on the crate is the change in kinetic energy, so:
W = KEf - KEi = 250.0 J - 62.50 J = 187.5 J
Therefore, the amount of work needed to accelerate the crate is 187.5 J, which can be rounded to the nearest tenth of a joule as 187.5 J.
Final answer:
The amount of work needed to accelerate the crate is 187.5 Joules (to the nearest tenth of a joule).
Explanation:
The amount of work needed to accelerate the crate can be calculated using the formula:
Work = Change in kinetic energy
First, calculate the initial kinetic energy:
Kinetic energy = (1/2) * m * v^2
= (1/2) * 5.000 kg * (5.000 m/s)^2
= 62.5 Joules
Next, calculate the final kinetic energy:
Kinetic energy = (1/2) * m * v^2
= (1/2) * 5.000 kg * (10.00 m/s)^2
= 250 Joules
Finally, calculate the change in kinetic energy:
Change in kinetic energy = Final kinetic energy - Initial kinetic energy
= 250 Joules - 62.5 Joules
= 187.5 Joules
Therefore, the amount of work needed to accelerate the crate is 187.5 Joules (to the nearest tenth of a joule).
If a ball is rolling at a velocity of 1.5 meters per second and has a momentum of 10.0 kg meters per second what is the mas6of the ball
The mass of the ball is 6.7 kg
Explanation:
The momentum of an object is defined as
[tex]p=mv[/tex]
where
p is the momentum
m is the mass of the object
v is its velocity
For the ball in this problem we have the following data:
v = 1.5 m/s (velocity)
p = 10.0 kg m/s (momentum)
Solving the equation for m, we find the mass of the ball:
[tex]m=\frac{p}{v}=\frac{10}{1.5}=6.7 kg[/tex]
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On Earth, you swing a simple pendulum in simple harmonic motion with a period of 1.6 seconds. What is the period of this same pendulum on the Moon? Assume the Moon’s acceleration due to gravity is 1/6 of the acceleration due to gravity on Earth.
The period of the pendulum in the Moon is 3.9 s
Explanation:
The period of a simple pendulum is given by the equation
[tex]T=2\pi \sqrt{\frac{L}{g}}[/tex] (1)
where
L is the length of the pendulum
g is the acceleration due to gravity
Here we have a pendulum whose period on Earth is
[tex]T_e = 1.6 s[/tex]
where on Earth, the acceleration due to gravity is
[tex]g_e = 9.8 m/s^2[/tex]
So eq.(1) can be written as
[tex]T_e = 2\pi \sqrt{\frac{L}{g_e}}[/tex] (2)
When the same pendulum is moved to the Moon, its length does not change, so its period on the Moon is given by
[tex]T_m = 2\pi \sqrt{\frac{L}{g_m}}[/tex] (3)
where
[tex]g_m = \frac{1}{6}g_e[/tex] is the acceleration due to gravity on the Moon (1/6 of that on the Earth)
Dividing eq.(3) by eq.(2), we get
[tex]\frac{T_m}{T_e}=\sqrt{\frac{g_e}{g_m}}=\sqrt{\frac{g_e}{\frac{1}{6}g_e}}=\sqrt{6}[/tex]
Therefore, the period of the pendulum on the moon is
[tex]T_m = \sqrt{6}T_e = \sqrt{6}(1.6)=3.9 s[/tex]
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before radiant energy can be converted to thermal energy,it must be changed to what
Answer:
The radiant energy is converted into electronic energy before it is transformed into thermal energy.
Explanation:
Radiant energy occurs in the form of "Electromagnetic radiation" and it can pass through all types of matter travelling through the universe. There are numerous advantages of radiant energy. When the radiant energy is incident upon a substance the energy from the sun light excites the electrons in the atom. This sets the atoms in vibrational motion.
Thermal energy is the kinetic energy of moving particles. The thermal energy increases with increase in movement and number of moving particles. When the atoms make a transition from electronically excited state to vibrational state, the energy transfer increases the temperature of the substance. This is felt as thermal energy. Hence, the radiant energy is changed into "electronic energy" before it is converted into "thermal energy".
1 - It is okay to use slang on a record as long as the auditor can interpret it.
True
False
2 - Never access social media accounts at work.
True
False
3 - Refrain from using profanity in the workplace.
True
False
4 - Chemical components contained in a product can be found in a(an) _______. A) chemical manual
B) procedures manual
C) Safety Data Sheet (SDS)
D) Material Data Sheet (MDS)
5 - To ensure a positive outcome it is essential for a group to be able to effectively communicate with one another within the workplace. What is this process known as?
A) Teamwork
B) Verbal communication
C) Groupthink
D) Planning
6 - _______ is a skill and behavior from a person trained to do their job well.
A) Teamwork
B) Professionalism
C) Planning
D) Communication
7 - These records are used to assist in providing a basis for quality improvement within the CS department.
A) Personnel monitors
B) CE educational records
C) Competencies
D) Training plans
8 - Employees in-services are an example of which of the following?
A) Personnel monitors
B) Continuing education records
C) Competencies
D) Training plans
9 - Which of the following organizations monitors exposure to hazardous materials?
A) EPA
B) OSHA
C) FDA
D) AAMI
10 - If a fire occurs, who should the staff rescue first?
A) Doctor
B) Tech
C) Patient
D) Nurse
Define momentum in term of mass and velocity
Answer:
Momentum: It is the quantity of motion of a moving body, measured as a product of its Mass and Velocity.
Explanation:
Definition of momentum :
Momentum is the quantity of motion of a moving body, measured as a product of its Mass and Velocity.
Momentum is denoted by pFormula for momentum is[tex]p = mass\times velocity[/tex]Its unit is kg-m/s.For example:
A bowling ball of large mass moving very slowly can have the same momentum as a cricket ball of small mass that is thrown with a very high velocity
A closed system changes from state 1 to state 2 while 40kj of heat is added and 60kj of work is done by the system. As system is returned to state 1, 20kj of work is done on it. what is the heat transferred during process 2-1
The heat transferred during the process from state 2 to state 1 in a closed system, after adding 40 kJ of heat and doing 60 kJ of work in state 1 to 2, then having 20 kJ of work done on it, is -80 kJ, meaning 80 kJ of heat is removed.
Given the information that a closed system changes from state 1 to state 2 while 40 kJ of heat is added and 60 kJ of work is done by the system, we can use the first law of thermodynamics to determine the heat transferred during the reverse process (state 2 to state 1). The first law of thermodynamics states that the change in internal energy (
Delta U
) of a system is equal to the heat added to the system (Q) minus the work done by the system (W), so:
Delta U = Q - W.
For the process 1 to 2:
Heat added (Q1 to 2) = +40 kJ
Work done by the system (W1 to 2) = -60 kJ
Therefore,
Delta U1 to 2 = 40 kJ - (-60 kJ) = 100 kJ.
Since the system returns to the initial state, the change in internal energy for the entire cycle is zero:
Delta U cycle =
Delta U1 to 2 +
Delta U2 to 1 = 0
So,
Delta U2 to 1 = -
Delta U1 to 2 = -100 kJ
For the process 2 to 1, we are given:
Work done on the system (W2 to 1) = +20 kJ
Using the first law again for process 2 to 1:
Delta U2 to 1 = Q2 to 1 - W2 to 1
-100 kJ = Q2 to 1 - 20 kJ
Q2 to 1 = -100 kJ + 20 kJ = -80 kJ.
Therefore, 80 kJ of heat is removed from the system during the process from state 2 to state 1.
An 3.3 kg bowling ball rolls with a velocity of 1.3 m/s and strikes a stationary 3.6 kg
bowling ball. The first ball stops after the collision. How fast does the second
bowling ball roll away after the collision?
The velocity of the second ball is 1.2 m/s
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system must be conserved before and after the collision, so we can write:
[tex]p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2[/tex]
where:
[tex]m_1 = 3.3 kg[/tex] is the mass of the first ball
[tex]u_1 = 1.3 m/s[/tex] is the initial velocity of the first ball
[tex]v_1 = 0[/tex] is the final velocity of the first ball
[tex]m_2 = 3.6 kg[/tex] is the mass of the second ball
[tex]u_2 = 0[/tex] is the initial velocity of the second ball
[tex]v_2[/tex] is the final velocity of the second ball
Re-arranging the equation and solving for v2, we find the velocity of the second ball after the collision:
[tex]v_2 = \frac{m_1 u_1}{m_2}=\frac{(3.3)(1.3)}{3.6}=1.2 m/s[/tex]
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You're driving your pickup truck around a curve that has a radius of 17 m.
How fast can you drive around this curve before a steel toolbox slides on the steel bed of the truck?
To find the maximum speed at which the toolbox will slide on the bed of the truck, we need to compare the maximum static frictional force between the toolbox and the truck bed to the maximum centrifugal force required to keep the toolbox in circular motion around the curve. By setting these forces equal to each other and using the equations for static friction and centripetal acceleration, we can calculate the maximum speed.
Explanation:When a toolbox slides on the back of a truck, the forces acting on the toolbox are the gravitational force pulling it downwards and the frictional force between the toolbox and the surface of the truck bed. In order for the toolbox to slide, the frictional force must be overcome. The maximum static frictional force can be calculated using the equation F_friction = μ * F_normal, where μ is the coefficient of static friction and F_normal is the normal force.
To calculate the maximum speed at which the toolbox will slide, we need to find the maximum centripetal force required to keep the toolbox in circular motion as the truck goes around the curve. The maximum centripetal force can be calculated using the equation F_centripetal = m * a_c, where m is the mass of the toolbox and a_c is the centripetal acceleration.
Setting the maximum static frictional force equal to the maximum centripetal force, we can find the maximum speed at which the toolbox will slide:
μ * F_normal = m * a_c
Since the toolbox is on a horizontal surface, the normal force is equal to the weight of the toolbox, which can be calculated using the equation F_normal = m * g, where g is the acceleration due to gravity. Substituting this in the equation above, we get:
μ * m * g = m * a_c
Simplifying and solving for a_c, we have:
a_c = μ * gNow, we can use the equation for centripetal acceleration to solve for the maximum speed:
a_c = v^2 / r
Solving for v, we have:
v = √(a_c * r)Substituting the values of the radius of the curve and the acceleration due to gravity, we can calculate the maximum speed at which the toolbox will slide.
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If an object is related from top of 200m high building find its velocity and time when it hits the ground.(g=(10m/s^2)
Answer:
The velocity at the ground is 63.25 m/s and time taken is 6.325 s.
Explanation:
Given:
As the object is released, the initial velocity is, [tex]u=0\ ms^{-1}[/tex]
Displacement of the object is, [tex]d=200\ m[/tex]
To find:
Velocity at the bottom, [tex]v=?[/tex]
Time to reach the bottom, [tex]t=?[/tex]
The acceleration of the object is due to gravity and hence equal to [tex]a=g=10\ m/s^2[/tex]
Now, using the following equation of motion:
[tex]v^2=u^2+2ad\\v^2=0+2(10)(200)\\v^2=4000\\\textrm{Taking square root both sides}\\v=\sqrt{4000}=63.25\ m/s[/tex]
Now, using the equation of motion relating time and velocity:
[tex]v=u+at\\63.25=0+10t\\t=\frac{63.25}{10}=6.325\ s[/tex]
Therefore, the velocity at the ground is 63.25 m/s and time taken is 6.325 s.
What is newton's third law second law first law ?
Answer:
first law: an object remains in uniform motion except an external force has acted upon it eg a ball in stable motion doesn't move until one moves or kicks it
second law:the body acted upon by an external force gains a momentum which is directly proportional to the applied force and acts in the direction of the force
third law: to every action there is an equal and opposite reaction eg if u push someone the person moves backward away from you and not towards you
Answer:
Newton's Second law of motion: "Force = mass × acceleration."
Newton's Third law of motion: "Every action has an equal and opposite reaction."
Explanation:
An example of Newton's third law is when a rocket is launched, the boosters apply force on the ground and the ground pushes back, which makes the rocket take off.
explain why a description of position depends on a refrence point.
Answer:
starting point you choose to describe the location, or position, of an object. A description of position depends on a reference point because if the reference point changes than the distance and direction can change. Before the weight was moving two forces were acting on it.ation:
What does the lens of an eye do to create an image?
A. focuses light on the cornea
B. focuses light on the retina
C. reflects light away from the retina
D. bends the cornea to correct vision
The eyes creates an image by focusing light on the retina.
The retina is the light sensitive part of the eyes. Images are formed when light is focused on the retina. The light sensitive nerve endings that are connected to the optic nerve conveys visual information to the brain.
Hence, the lens of the eye creates an image by focusing light on the retina of the eye.
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If the earth has a radius of 6.4 x 10^6 and it spins once per day, what is the centripetal force on a 100 kg man who is on the equator? This would make him weigh (less/more) by ____N
Answer:
The spinning of the Earth would make him to weigh less.
Explanation:
Given data,
The radius of the Earth, R = 6.4 x 10⁶ m
The rotational period, T = 86400 s
The mass of the man, m = 100 kg
The centripetal force at equator,
f = m v²/R
Since,
T = 2π/ω & v = Rω
v²/R = 4π²R/T²
Substituting in the equation for centripetal force,
f = 4π²mR/T²
Substituting the values,
f = 4π² x 100 x 6.4 x 10⁶ / 86400²
= 3.39 N
The centripetal force is directed along the radius towards the center, the centrifugal force acts opposite to it.
The gravitational force acting the man towards the center,
F = mg
= 100 x 9.8
= 980 N
The net force acting on the person,
F' = F - f
= 980 N - 3.39 N
= 976.61 N
Hence, this would make him to weigh less.
Earth's early atmosphere is almost unrecognizable compared to the atmosphere around us now. True False
It is TRUE that earth's early atmosphere is almost unrecognizable compared to the atmosphere around us now
Explanation:
The early atmosphere of earth was mainly composed of carbon dioxide (up to 200 times more than current levels), methane, ammonia, and hydrogen sulfide. Most of the atmosphere was mainly created from gases spewed up into the atmosphere by volcanic eruptions. This was approximately 4.6 billion years ago.
However, an event referred to as the Great Oxygenation Event (about 2.6 billion – 400 million years ago ) changed the composition of the atmosphere. This was due to the evolution of photosynthetic organism that took up most of the carbon dioxide from the atmosphere and evolved out oxygen. The oxygen oxidized a lot elements, minerals and compounds in the atmosphere (including methane) and on the crust surface (such as iron). This changed, drastically, the composition of the earth's atmosphere.
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Angela is analyzing the fracture pattern of a window she know it’s at the crack stop when they intersect knowing this what can she determine about the window
Answer:
The order in which the fractures occurred
I took the test
A planet will orbit its sun because the gravitational force of the sun pulls on
the planet. The gravitational force of the planet pulling on the sun is:
The gravitational force of the planet pulling on the sun is equal to the gravitational force of the sun pulling on the planet
Explanation:
We can solve this problem by applying Newton's third law, which states that:
"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"
In this problem, we can identify:
- The sun as object A
- The planet as object B
By applying Newton's third law, we can state that:
- The action is the gravitational force exerted by the sun on the planet
- The reaction is the gravitational force exerted by the planet on the sun
According to the law, the two forces are equal in magnitude and opposite in direction: so, we can conclude that
The gravitational force of the planet pulling on the sun is equal to the gravitational force of the sun pulling on the planet
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Answer:
Of the same magnitude
Explanation:
Which can cause blockage of the ear canal, leading to hearing loss? aging disease earwax noise
Explanation:
Earwax helps to protect your ears from infection so if you like chewing gum, this helps in removing the wax. But this might not happen at your young age. So if you grow and still likes chewing gum it will remove the wax completely thereby leading to loss on hearing
3. Coyotes and rabbits that live in the same area
a. are in direct competition with each other.
b. have a predator-prey relationship.
C. belong to the same population.
d. have the same niche.
Plz helppopo
Coyotes and rabbits that live in the same area have a predator-prey relationship.
WHAT IS PREDATION?Predation is a type of relationship between living organisms in which one organism called the predator kills and eats another organism called the prey for nutritional needs.
Living organisms require energy for their daily tasks but derive it in different ways.
Coyotes are carnivores i.e. they feed on flesh. Rabbits can be a prey for them. This means that coyotes and rabbits that live in the same area have a predator-prey relationship.
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E5. A 0.12-kg ball traveling with a speed of 45 m/s is brought
to rest in a catcher's mitt. What is the size of the impulse
exerted by the mitt on the ball?
The size of the impulse exerted on the ball is 5.4 kg m/s
Explanation:
The impulse exerted on an object is equal to the change in momentum of the object itself:
[tex]I=\Delta p = m(v-u)[/tex]
where:
I is the impulse
m is the mass of the object
v is the final velocity of the object
u is its initial velocity
In this problem, we have:
m = 0.12 kg is the mass of the ball
u = 45 m/s is the initial velocity of the ball
v = 0 is the final velocity (the ball is brought to rest)
Substituting into the equation, we find the impulse:
[tex]I=(0.12)(0-45)=-5.4 kg m/s[/tex]
where the negative sign means that the direction of the impulse is opposite to the initial direction of motion of the ball. Therefore, the size of the impulse is
[tex]I=5.4 kg m/s[/tex]
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A conservative force does the same work regardless of the path taken.
O
A. True
O
B. False
A conservative force is a force that when work is done against this force the work done does not depend on the path taken only the initial and final position.
Answer:
True
Explanation:
what happens when light travels from one medium to another with a different index of refraction at a zero degree angle of incidence?
Answer:
No Refraction takes places
Explanation:
When light travels from one medium to another at an angle of incidence 0 degree then no refraction takes place .
It is because according to Refraction law
[tex]n_{i}[/tex]sini = [tex]n_{r}[/tex]sinr
where [tex]n_{i} ,n_{r}[/tex] are the refractive index of medium of incidence and medium of refraction .
When i = 0 , left side of the equation becomes 0 and thus r (angle of refraction) must be zero. So No refraction takes place
Answer:
If the index of refraction of the medium is greater, the light slows down.