Answer:
20
Step-by-step explanation:
Use the distance equation to find the length of each side:
d = √((x₂ − x₁)² + (y₂ − y₁)²)
where (x₁, y₁) and (x₂, y₂) are the points (the order doesn't matter).
AB:
d = √((-2 − (-2))² + (-2 − 4)²)
d = 6
BC:
d = √((4 − (-2))² + (-2 − (-2))²)
d = 6
AC:
d = √((-2 − 4)² + (4 − (-2))²)
d = 6√2
So the perimeter is:
AB + BC + AC
6 + 6 + 6√2
≈ 20
Please help with these partial sum questions??
a. If c is a constant then the sum of such constants is the same as multiplication of constants. Therefore [tex]\Sigma_{k=1}^{n}c=nc[/tex]
b. [tex]\Sigma_{k=1}^{n}k=1+2+3+\dots+\infty=\infty[/tex]
c. [tex]\Sigma_{k=1}^{n}k^2=1+4+9+\dots+\infty=\infty[/tex]
d. [tex]\Sigma_{k=1}^{n}k^3=1+8+27+\dots+\infty=\infty[/tex]
Hope this helps.
r3t40
HELP!
What is the solution set of |2x + 1| > 5?
A {x|1 < x < –3}
B {x|–1 < x < 3}
C {x|x > 2 or x < –3}
D {x|x < 2 or x > –3}
Answer:
Answer choice C
Step-by-step explanation:
When the values of x are greater than 2, the solution works. When the values oclf x are less than 3, the solution also works. :)
Answer:
C
Step-by-step explanation:
Inequalities of the form | x | > a have solutions of the form
x < - a OR x > a, thus
2x + 1 < - 5 OR 2x + 1 > 5 ( subtract 1 from both sides of both )
2x < - 6 OR 2x > 4 ( divide both sides of both by 2)
x < - 3 OR x > 2
Solution set is
{ x | x > 2 or x < - 3 } → C