Gases fill up any available space as they don't have a definite shape.

a. True

b. False

Answer:

84.0 g/mol

Explanation:

Molar mass of NaHCO₃ = ?

Solution:

Molar mass is the sum of masses of all atom present in formula.

Molar mass of sodium = 23 g/mol

Molar mass of hydrogen = 1.008 g/mol

Molar mass of carbon = 12 g/mol

Molar mas of Oxygen = 16 g/mol

Molar mass of NaHCO₃ = 23 + 1.008 + 12 + 16× 3

Molar mass of NaHCO₃ = 23 + 1.008 + 12 + 48

Molar mass of NaHCO₃ = 84.008 g/mol

To the nearest tenth = 84.0 g/mol

Answer:

84 g/mol.

Explanation:

Hello,

In this case, for us to compute such mass, we consider the atomic mass of sodium, hydrogen, carbon and oxygen as well as the three as the oxygen's subscript indicating there are three oxygens. Thus, the molar mass results

[tex]M=m_{Na}+m_{H}+m_{C}+*3m_{O}=23g/mol+1g/mol+12g/mol+3*16g/mol\\M=84g/mol[/tex]

Best regards.

Answer:

P₂ = 0.94 atm

Explanation:

Given data:

Initial volume = 16 cm³

Final volume after mixing the initial volume into 1cm³ = 16 cm³ + 1 cm³ (17cm³)

Initial pressure = 1 atm

Final pressure = ?

Solution:

P₁V₁ = P₂V₂

P₂ = P₁V₁ /V₂

P₂ = 1 atm × 16 cm³  / 17cm³

P₂ = 16 cm³ . atm / 17cm³

P₂ = 0.94 atm

Pressure will change from 1 atm to 0.94 atm.

Answer:

-2

Explanation:

Consider object is starting 12 units right from the reference point which is 0.

Assign the right direction positive sign.

when object is moving 14 units on left direction the position of object will be two units to the left side of reference point.

Assign the left direction negative sign position will be -2.

Answer:

The group two on the left side of periodic table have alkaline earth metals.

Explanation:

The group two elements are called alkaline earth metals. All elements have two valance electrons. This family include,

Beryllium

Magnesium

Calcium

Strontium

Barium

Radium

All of these combine with halogen atoms and formed salt.

These are shiny.

They have low densities.

These metals react with oxygen and form oxides.

Except strontium and magnesium all alkaline earth metals have one radioactive isotope.

All are these elements have low melting and boiling points.

The alkaline earth metals are located in Group II of the modern periodic table, including elements such as Beryllium, Magnesium, Calcium, Strontium, Barium, and Radium. They share common properties, including being shiny, silvery-white, and reactive.

The region which contains the alkaline earth metal family of elements is known as Group 2 or II on the modern periodic table. This group includes the elements Beryllium (Be), Magnesium (Mg), Calcium (Ca), Strontium (Sr), Barium (Ba), and Radium (Ra). These elements share similar properties such as they are all shiny, silvery-white and they are all reactive, but not as much as alkali metals in Group 1. They also have two electrons in their outer shell, therefore, they are eager to lose those electrons in order to reach a stable electron configuration.

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Answer:

289,406.25 ≈ 289,406

Explanation:

We can solve this question in 2 ways: Simple calculation and Using the formula.

Simple Calculation: The rate of increase is 5% per hour. And the initial count was 250,000. Therefore, in the first hour, the increase in the count would be 5% of 250,00, which is [tex]\frac{5}{100}[/tex]×250,000 = 12,500. Therefore,  at the end of the first hour, the count would be 250,000 + 12500 = 262,500. Now, for the 2nd hour, the intial count is 262,500 and the increase in count at the end of the 2nd hour would be 5% of 262,500 = [tex]\frac{5}{100}[/tex]×262,500 = 13,125. And the count at the end of the 2nd hour is 262,500+13,125 = 275,625. Similarly for the 3rd hour, the starting count is 275,625 and the increase in count at the end of the 3rd hour is [tex]\frac{5}{100}[/tex]×275,625 = 13,781.25. Thus, the total count at the end of 3rd hour is 275,625+13,781.25 = 289,406.25 ≈ 289,406.

Direct Formula (Actually, it is the compound interest formula): [tex]C(f) = C(i)(1 + \frac{r}{n})^{nT}[/tex] , where C(f) is final count, C(i) is the initial count, r is the rate of increase, n is the number of times rate of increase is applied in a time period, T is the number of time periods. Here, C(i) = 250,000, r is 5% = 0.05, n is one (because 5% increase happens once in one hour) and T is 3 hours.  Therefore, [tex]C(f) = 250000(1 + \frac{0.05}{1})^{3} = 250000(1.05)^{3} = 289406.25[/tex].

Answer:

KOH

Explanation:

Chemical reaction:

2K + 2H₂O →  2KOH + H₂

Element ratio of K.

K = 1

Because only potassium is present.

Element ratio of H₂O.

2 : 1

in water ratio of element is 2 : 1 because two hydrogen and one oxygen atom present.

Element ratio of KOH

1 : 1 : 1

in KOH elemental ratio is 1 : 1 : 1 because one potassium one hydrogen and one oxygen atom are present.

Element ratio of H₂.

2

Just two atoms of hydrogen are present.

Answer:

% (COOK)2H2O = 37.826 %

Explanation:

mix: (COOK)2H2O + Ca(OH)2 → CaC2O4 + H2O

∴ mass mix = 4.00 g

∴ mass (CaC2O4)H2O = 1.20 g

∴ Mw (COOK)2H2O = 184.24 g/mol

∴ Mw (CaC2O4)H2O = 146.12 g/mol

∴ r = mol (COOK)2H2O / mol (CaC2O4)H2O = 1

⇒ mass (COOK)2H2O = (1.20 g (CaC2O4)H2O)×(mol (CaC2O4)H2O / 146.12 g (CaC2O4)H2O)×(mol (COOK)2H2O/mol (CaC2O4)H2O)×(184.24 g (COOK)2H2O/mol (COOK)2H2O)

⇒ mass (COOK)2H2O = 1.513 g

⇒ % (COOK)2H2O = ( 1.513 g / 4 g )×100

⇒ % (COOK)2H2O = 37.826 %

Final answer:

The percentage of the 4.00 g mixture that is potassium oxalate is 37.75%.

Explanation:

When attempting to determine what percentage of a 4.00 g mixture is potassium oxalate, we begin by using the information provided about the mass of calcium oxalate hydrate recovered.

Given:

Mass of calcium oxalate hydrate recovered = 1.20 g

Molar mass of calcium oxalate hydrate = 146.12 g/mol

Mole:mole ratio of potassium oxalate to calcium oxalate = 1:1

We can calculate the number of moles of calcium oxalate hydrate:

\( \text{Moles of calcium oxalate} = \frac{1.20\,g}{146.12\,g/mol} = 0.00821\,mol \)

Since the ratio of potassium oxalate to calcium oxalate is 1:1, moles of potassium oxalate will be the same, 0.00821 mol.

Now we calculate the mass of the potassium oxalate hydrate:

\( \text{Mass of potassium oxalate} = 0.00821\,mol \times 184.24\,g/mol = 1.51\,g \)

To find the percentage of the mixture that is potassium oxalate:

\( \text{Percentage of potassium oxalate} = \frac{1.51\,g}{4.00\,g} \times 100\% = 37.75\% \)

Therefore, 37.75% of the 4g mixture is potassium oxalate.

Answer:

102.807 kPa

Explanation:

There are some assumptions to be made in the answer. The air inside the balloon acts as an ideal gas at a given temperature conditions.

Using the combined ideal gas equation.

[tex]PV = nRT\\[/tex]

P= absolute pressure of air inside the balloon.

V= volume of air inside the balloon (6.23 L= 6.23 * 10⁻³ m³)

n= moles of gas(air). (0.250 mol)

R= Universal gas constant ( 8.314 J / mol·K)

T= Temperature in Kelvin

T= 35 + 273.15 = 308.15 K

So, [tex]P = \frac{nRT}{V}[/tex]

[tex]P = \frac{0.250 * 8.314 * 308.15}{6.23 * 10^{-3} }[/tex]

P= 102.807 * 10³ Pa

P= 102.807 kPa

Answer: 103 for Edmentum users !

Answer:

C.  nonmetal.

Explanation:

It is not ionic because it did not conduct electricity.

There is only one liquid metal  at room temperature and that is mercury, which will conduct electricity.

A salt is usually solid at room temperature and if it is in solution will conduct electricity.

Answer:

titan

Explanation:

is a carbon oxoacid and a chalcocarbonic acid. It has a role as a mouse metabolite. It is a conjugate acid of a hydrogencarbonate. Bicarbonate, or hydrogen carbonate, is a simple single carbon molecule that plays surprisingly important roles in diverse biological processes.

Answer:

Dissolves limestone and other rocks.

Explanation:

you didnt give any choices so i did the best i could

Answer:

Area near a sea having flat land and low relief.

Explanation:

Just think of a beach, that's a coastal plain, it's usually flat land with low relief.

Final answer:

A coastal plain best describes an area near a sea having flat land with low relief, like the Gulf-Atlantic Coastal Plain, which has gradual slopes and can include estuaries like Chesapeake Bay.

Explanation:

The term coastal plain describes an area near a sea having flat land and low relief. It is characterized by a landscape that slopes very gradually toward the sea, with a rate of elevation change so subtle that it could be just a few feet or even inches per mile. An example of a coastal plain is the Gulf-Atlantic Coastal Plain, which extends across various eastern states in the US and includes notable features such as the entire state of Florida, as well as other areas along the Gulf of Mexico and the Atlantic Ocean. Coastal plains can often be swampy due to their flat nature which doesn't allow water to drain away quickly. They are also where coastal plain estuaries, or drowned river valleys, can be found, such as Chesapeake Bay and Delaware Bay.

Answer:

V₂ = 30 L

Explanation:

Given data:

Initial pressure = 30 psi (30 /14.696 = 2 atm)

Initial volume = 15 L

Final volume = ?

Final pressure = 1 atm

Solution;

P₁V₁ = P₂V₂

V₂ = P₁V₁  / P₂

V₂ = 2 atm .  15 L /  1 atm

V₂ = 30 L

Answer:

The correct answers are given below

Explanation:

1 An increase of one in atomic number and no change in the mass number.

2 All the above statements are correct.

3  A decrease of one in atomic number and a decrease of four in mass number.

4 Have a high neutron to proton ratio.

The 3 liters closed container.

Explanation:

We have the ideal gas law:

PV = nRT

where:

P =  pressure

V = volume

n = number of moles

R = gas constant

T = temperature

The number of moles n₁ (which is 1 mole) from the 2 liter (V₁) container are equal to:

n₁ = PV₁ / RT

The number of moles n₂ from the second container ( (V₂) are equal to:

n₂ = PV₂ / RT

From the data given in the problem we know that:

n₂ =  3 × n₁

We replace the n's:

PV₂ / RT =3 × PV₁ / RT

(PV₂ / RT) × (RT / P) = 3 × V₁

V₂ = 3 × V₁

V₂ = 3 × 2

V₂ = 6 liters

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Final answer:

To hold 3 moles of an ideal gas at the same temperature and pressure as 1 mole in a 2-liter container, a 6-liter container is needed. This is based on Avogadro's law, which is a part of the ideal gas law.

Explanation:

The initial query pertains to how much volume would be required to contain 3 moles of an ideal gas under the same temperature and pressure conditions as a 2-liter container holding 1 mole. To find this, we apply the ideal gas law, which states that at constant temperature and pressure, the volume of a gas is directly proportional to the number of moles. Given that 1 mole of the gas occupies 2 liters, it follows that 3 moles would require a volume that is three times larger, thus requiring a 6-liter container.

According to Avogadro's law, which is part of the ideal gas law, at the same temperature and pressure, equal volumes of all gases contain the same number of moles. Therefore, to hold 3 moles of the ideal gas at the same temperature and pressure as 1 mole in 2 liters, we would need a container with a volume of 6 liters. This principle also explains why at standard temperature and pressure (STP), 1 mole of an ideal gas occupies 22.4 liters.

Answer:

1.6 ×10⁻¹ kj

Explanation:

Given data:

Mass of chloroethane = 0.38 g

Heat absorbed = ?

Solution:

Molar mass of chloroethane = 64.51 g/mol

Molar heat of vaporization = 26.4 kj/mol

Number of moles:

Number of moles = mass/ molar mass

Number of moles = 0.38 g/ 64.51 g/mol

Number of moles = 0.006 mol

Heat absorbed:

0.006 mol × 26.4 kj/mol

0.16 kj

or 1.6 ×10⁻¹ kj

Answer:

1.6 ×10⁻¹ kj

Explanation:

Answer:

perennial

Explanation:

Answer:hydrocarbon

Explanation:it reacts with oxygen to produce water and carbodioxide.

Answer:

hydrocarbon

Explanation:

a p e x :)

Answer:

Multiply the acceleration by the time the object is being accelerated. For example, if an object falls for 3 seconds, multiply 3 by 9.8 meters per second squared, which is the acceleration from gravity. The resultant velocity in this case is 29.4 meters per second.

Explanation:

dont have one

Dalton proposed the atomic theory, Thomson discovered the electron and proposed the Plum Pudding Model, Rutherford conducted the gold foil experiment and concluded the existence of a dense, positively charged nucleus, and Bohr introduced the concept of energy levels or shells in the atom.

Dalton: John Dalton proposed the atomic theory, which states that atoms are indivisible and indestructible building blocks of matter. He believed that all atoms of the same element are identical and each element is made up of atoms with unique properties.

Thomson: J.J. Thomson discovered the electron and proposed the Plum Pudding Model, which suggested that atoms are composed of a positively charged mass with negatively charged electrons embedded in it.

Rutherford: Ernest Rutherford conducted the famous gold foil experiment and concluded that atoms have a small, dense, positively charged nucleus at the center and electrons moving around it in a vast empty space.

Bohr: Niels Bohr introduced the idea of energy levels or shells in the atom. He proposed that electrons exist in fixed orbits around the nucleus and can jump between energy levels by absorbing or emitting energy in discrete amounts.

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Answer:

True

Explanation:

Ionic bonds are stronger than covalent bonds because, there is mutual attraction between oppositely charged ions while a Covalent Bond is a bond that results from a sharing of electrons between nuclei.

SrCO₃ + H₂SO₄ → SrSO₄ + H₂O + CO₂

We are required to complete the chemical equation given;

strontium carbonate + sulfuric acid → ??

SrCO₃ + H₂SO₄ → SrSO₄ + H₂O + CO₂

The reaction between strontium carbonate and sulfuric acid produces strontium sulfate, carbon dioxide, and water. The balanced chemical equation would be: SrCO3(s) + H₂SO₄ (aq) → SrSO4 (aq) + CO₂(g) + H₂O(l).

The reaction between strontium carbonate and sulfuric acid is a type of acid-carbonate reaction, which generally results in the formation of a salt, carbon dioxide, and water. Although the reaction for strontium carbonate and sulfuric acid is not provided, we can deduce it from similar reactions. For instance, the reaction of sulfuric acid with calcium carbonate is shown by the equation:

CaCO3(s) + H₂SO₄ (aq) → CaSO4 (aq) + H₂O(l) + CO₂(g) ↑

Based on this example, the balanced chemical equation for the reaction between strontium carbonate and sulfuric acid likely follows a similar pattern and would be written as:

SrCO3(s) + H₂SO₄ (aq) → SrSO4 (aq) + CO₂(g) + H₂O(l)

This equation indicates that when strontium carbonate (SrCO3) reacts with sulfuric acid (H₂SO₄), they produce strontium sulfate (SrSO4), carbon dioxide (CO₂), and water (H₂O).

0.111 J/g°C

We are given;

But, density of pure water = 1 g/mL

We are required to determine the specific heat of the metal;

Q = m × c × ΔT

For water, ΔT = 23.68 °C - 21° C

                       = 2.68 °C

Thus;

Q = 45.2 g × 4.184 J/g°C × 2.68°C

    = 506.833 Joules

We know that, Q =  m × c × ΔT

For the unknown metal, ΔT = 101° C - 23.68 °C

                                              = 77.32°C

Assuming the specific heat capacity of the unknown metal is c

Then;

Q = 58.932 g × c × 77.32°C

   = 4556.62c Joules

4556.62c Joules = 506.833 Joules

c = 506.833 ÷4556.62

  = 0.111 J/g°C

Thus, the specific heat capacity of the unknown metal is 0.111 J/g°C

The empirical formula of the compound is C₃H₃S.

Explanation:

molecular weight of CO₂ = 44 g/mole

molecular weight of H₂O = 18 g/mole

Knowing the molecular weights of the compounds we devise the following reasoning:

if in           44 g of CO₂ there are 12 g of C

then in  5.48 g of CO₂ there are X g of C

X = (5.48 × 12) / 44 = 1.49 g C

if in           18 g of H₂O there are 2 g of H

then in    1.13 g of H₂O there are Y g of H

Y= (1.13 × 2) / 18 = 0.126 g H

mass of compound = mass of C + mass of H + mass of S

mass of S = mass of compound - mass of C - mass of H

mass of S = 2.95 - 1.49 - 0.126 = 1.33 g S

Now to find the empirical formula of the compound we use the fallowing algorithm:

we devise each mass by the molar weight of the element:

for C   1.49 / 12 = 0.124

for H   0.126 / 1 = 0.126

for S   1.33 / 32 = 0.0416

now we divide the result by the lowest number which is 0.0416

for C    0.124 / 0.0416 ≈ 3

for H    0.126 / 0.0416 ≈ 3

for S    0.0416 / 0.0416 = 1

The empirical formula of the compound is C₃H₃S.

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The answer is Agriculture

The leading source of pollutants found in rivers surveyed for the 1998 report that you read was; Agriculture.

The National Water Quality Inventory Report to Congress in 1998 was one that summarized information reported by the states in that same year by describing the condition of their waters that were accessed as it was required under Section 305(b) of the Clean Water Act.

The report had many sections such as;

Monitoring and Assessment

- Rivers and Streams

- Lakes, Ponds, and Reservoirs

- Coastal Resources - Tidal Estuaries, Shoreline Waters, and Coral Reefs

- Wetlands

- Ground Water Quality

- Public Health and Aquatic Life concerns

- Costs and Benefits of Water Quality Protection

Now, from the report as seen online, it was discovered that the leading source of pollutants found in rivers is Agriculture.

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Answer:

The percent by mass of water in the hydrate is 45.4%

The percent by mass of the anhydrous salt in the hydrate is 54.6%

Explanation:

The percent by mass of water in the hydrate is 69.23% and the percent by mass of the anhydrous salt in the hydrate is 54.44%.

To find the percent by mass of water in the hydrate, we can use the following formula:

percent by mass of water = (mass of water)/(mass of hydrate) * 100%

Mass of water = 7 moles of H₂O * 18 g/mol

= 126 g

Mass of hydrate = 1 mole of FeSO₄ • 7H₂O

= 278 g

Plugging these values into the formula, we get:

percent by mass of water = (126 g)/(278 g) * 100%

= 45.56%

We can also find the percent by mass of the anhydrous salt in the hydrate by subtracting the percent by mass of water from 100%.

percent by mass of anhydrous salt = 100% - 45.56%

= 54.44%

Therefore, the percent by mass of water in the hydrate is 69.23%, and the percent by mass of the anhydrous salt in the hydrate is 54.44%.

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Answer:

C. Gamma rays

Explanation:

Answer:

C. Gamma rays

Explanation:

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