The probability that Little Joe, who has no brothers, is an only child is calculated using conditional probability and results in a 1/4 chance.
The question asks us to find the probability that Little Joe, who has no brothers, is an only child. The sample space for the number of children in a family can be defined as {1, 2, 3, 4}, since each of these outcomes has an equal probability of 1/4. We will define event A as Little Joe being an only child, and event B as the family having no additional male children. Since Little Joe is a boy and has no brothers, cases with more than one male child should not be a part of our conditional sample space.
To solve this, we are looking at the conditional probability P(A|B). The probability that Little Joe is an only child given he has no brothers is P(A|B) = P(A and B) / P(B). We can determine that P(A and B) is simply the probability that there is one child and that child is a boy (Little Joe), which is 1/4. Event B can happen in three scenarios: Little Joe is an only child, Little Joe has one sister, or Little Joe has two or three sisters, and each scenario has an equal probability. Therefore, P(B) = 1/4 (only child) + 1/4 (one sister) + 1/4 (two sisters) + 1/4 (three sisters), which adds to 1/4 * 4 = 1.
The answer therefore is P(A|B) = (1/4) / 1 = 1/4. There is a 1/4 chance that Little Joe, who has no brothers, is an only child.
Using the critical value rule, if a two-sided null hypothesis is rejected for a single mean at a given significance level, the corresponding one-sided null hypothesis (i.e., the same sample size, the same standard deviation, and the same mean) will ______________ be rejected at the same significance level.
Answer:
Using the critical value rule, if a two-sided null hypothesis is rejected for a single mean at a given significance level, the corresponding one-sided null hypothesis will "always" be rejected at the same significance level.
Step-by-step explanation:
Consider the provided statement.
As the value of p is less than the significance level, therefore always reject the null hypothesis. Where p is exact level of significance.
Therefore, the answer to the statement is "Using the critical value rule, if a two-sided null hypothesis is rejected for a single mean at a given significance level, the corresponding one-sided null hypothesis (i.e., the same sample size, the same standard deviation, and the same mean) will always be rejected at the same significance level."
If a two-sided null hypothesis is rejected at a given significance level, the corresponding one-sided null hypothesis will also be rejected at the same significance level, because the two-sided test is more stringent.
Explanation:Using the critical value rule, if a two-sided null hypothesis is rejected for a single mean at a given significance level, the corresponding one-sided null hypothesis will also be rejected at the same significance level.
This is because when performing a two-sided test, we are testing both ends of the distribution, thus it requires a stricter criteria to reject the null hypothesis than a one-sided test. Since we have already rejected it under a stricter evaluation, we will definitely reject it under a less strict one.
Consider an example where you are using a significance level of 5 percent (α = 0.05). Suppose that your computed t-statistic is 2.2. This value is greater than the critical value for a two-tailed test from the t29 distribution, which is 2.045. Therefore, you reject the two-sided null hypothesis.
Consequently, when comparing your t-statistic (2.2) with the critical value for a one-sided test (which will be less stringent than that for a two-tailed test), you also reject the one-sided null hypothesis.
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The coefficient of x^3y^4 in (3x+2y)^7 is
Answer:
The coefficient is 15120.
Step-by-step explanation:
Since, by the binomial expansion formula,
[tex](x+y)^n=\sum_{r=0}^n^nC_r x^{n-r} y^r[/tex]
Where, [tex]^nC_r=\frac{n!}{r!(n-r)!}[/tex]
Thus, we can write,
[tex](3x+2y)^7 = \sum_{r=0}^n ^7C_r (3x)^{7-r} (2y)^r[/tex]
For finding the coefficient of [tex]x^3y^4[/tex],
r = 4,
So, the term that contains [tex]x^3y^4[/tex] = [tex]^7C_4 (3x)^3 (2y)^4[/tex]
[tex]=35 (27x^3) (16y^4)[/tex]
[tex]=15120 x^3 y^4[/tex]
Hence, the coefficient of [tex]x^3y^4[/tex] is 15120.
Answer:[tex][/tex]
Coefficient of [tex]x^3y^4[/tex] in [tex](3x+2y)^7[/tex] is 15120
Step-by-step explanation:
We know that [tex](x+y)^{n}[/tex]) can be expanded in (n+1) terms by using binomial theorem and each term is given as
[tex]n_C_{r}x^{n-r}y^{r}[/tex]
Here value of r is taken from n to 0
we have to determine the coefficient of [tex]x^3y^4[/tex] in [tex](3x+2y)^7[/tex]
in this problem we have given n=7
We have to determine the coefficient of [tex]x^3y^4[/tex]
it means in the expansion we have to find the the 3rd power of x and therefore
r=n-3
here n=7
therefore, r=7-3=4
Hence the coefficient of [tex]x^3y^4[/tex] can be determine by using formula
[tex]n_C_{r}x^{n-r}y^{r}[/tex]
here n=7, r=4
[tex]7_C_{4}x^{7-4}y^{4}[/tex]
=[tex]\frac{7\times 6\times 5\times 4}{1\times 2\times 3\times 4} (3x)^3(2y)^4[/tex]
=[tex]15120x^3y^4[/tex]
Therefore the coefficient of [tex]x^3y^4[/tex] in [tex](3x+2y)^7[/tex] is 15120
If ( 43.65 ) ( 8.79 ) / x = ( 0.4365 ) ( 87.9 ) then value of x is:
(a) .01 (b) 0.1 (c) 1 (d) 10 (e) 100
Need step-by-step solution
i will mark your answer Brainliest
Answer:
(d) 10
Step-by-step explanation:
Multiply by x and divide by its coefficient:
(43.65)(8.79) = (0.4365)(87.9)x
(43.65)(8.79)/((0.4365)(87.9)) = x
At this point, any calculator can give you the answer. It is, perhaps, more satisfying to work out the answer without a calculator.
x = (43.65)/(0.4365) × (8.79)/(87.9)
In the first quotient, the numerator is 100 times the denominator; in the second, the denominator is 10 times the numerator.
x = (100) × (1/10) = 100/10
x = 10
_____
Moving the decimal point to the right 1 place multiplies the numerical value by 10.
The value of x in the given equation that satisfies the condition is 10.
Explanation:In this question, we're given a mathematical expression in which the value of x is unknown. We're looking for the value of x that satisfies the equation:
( 43.65 ) ( 8.79 ) / x = ( 0.4365 ) ( 87.9 )
To solve this equation for x, we can start by noting the similarity between the left and right sides. We have larger numbers on the left side that appear, in reduced form, on the right side.
Follow these steps:
Multiply 43.65 and 8.79 to get 383.985.Multiply 0.4365 and 87.9 to get 38.3985.Divide 383.985 by 38.3985 to get 10.So, the correct option would be (d) 10.
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54% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is (a) exactly five, (b) at least six, and (c) less than four.
Answer:
[tex]P(5)=0.238[/tex]
[tex]P(x\geq 6)=0.478[/tex]
[tex]P(x<4)=0.114[/tex]
Step-by-step explanation:
In this case we can calculate the probability using the binomial probability formula
[tex]P(X=x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{n-x}[/tex]
Where p is the probability of obtaining a "favorable outcome " x is the number of desired "favorable outcome " and n is the number of times the experiment is repeated. In this case n = 10 and p = 0.54.
(a) exactly five
This is:
[tex]x=5,\ n=10,\ p=0.54.[/tex]
So:
[tex]P(X=5)=\frac{10!}{5!(10-5)!}*0.54^x*(1-0.54)^{10-5}[/tex]
[tex]P(5)=0.238[/tex]
(b) at least six
This is: [tex]x\geq 6,\ n=10,\ p=0.54.[/tex]
[tex]P(x\geq 6)=P(6) + P(7)+P(8)+P(9) + P(10)[/tex]
[tex]P(x\geq 6)=0.478[/tex]
(c) less than four
This is: [tex]x< 4,\ n=10,\ p=0.54.[/tex]
[tex]P(x<4)=P(3) + P(2)+P(1)+P(0)[/tex]
[tex]P(x<4)=0.114[/tex]
This question is based on the probability. Therefore, the required probabilities are : (a) [tex]P(5) = 0.238[/tex], (b)[tex]P(x \geq 6) = 0.478[/tex] and (c) [tex]P(x <4) = 0.114[/tex].
Given:
54% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults.
We have to find the probability that the number of U.S. adults who have very little confidence in newspapers is (a) exactly five, (b) at least six, and (c) less than four.
According to the question,
[tex]P(5) = 0.238\\P(x \geq 6) = 0.478\\P(x <4) = 0.114[/tex]
In this we have to calculate the probability using the binomial probability formula,
[tex]P(X=x) = \dfrac{n!}{x!(n-x)!} \times p^{x} \times (1-p)^{n-x}[/tex]
Where, p is the probability of obtaining a "favorable outcome ", x is the number of desired "favorable outcome " and n is the number of times the experiment is repeated. In this case n = 10 and p = 0.54.
(a) exactly five
x=5, n= 10, p = 0.54
[tex]P(X=5)= \dfrac{10!}{5!(10-5)!} \times 0.5^{x} \times (1-0.54)^{10-5}[/tex]
P(X=5) = 0.238
(b) at least six
[tex]x\geq 6, n=10, p=0.54\\P(x\geq 6) = P(6) + P(7) + P(8) + P(9)+P(10)\\P(x\geq 6) = 0.478[/tex]
(c) less than four
[tex]x< 6, n=10, p=0.54\\P(x< 4) = P(3) + P(2) + P(1) + P(0)\\P(x< 4) = 0.114[/tex]
Therefore, the answers are : (a) [tex]P(5) = 0.238[/tex], (b)[tex]P(x \geq 6) = 0.478[/tex]
and (c) [tex]P(x <4) = 0.114[/tex].
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Eliminate the parameter and obtain the standard form of the rectangular equation. Hyperbola: x = h + b tan(θ), y = k + a sec(θ) Use your result to find a set of parametric equations for the line or conic. (When 0 ≤ θ ≤ 2π. Set your center at the origin. Enter your answers as a comma-separated list of equations.) Hyperbola: vertices: (0, ±2); foci: (0, ± 5 )
The standard form of the hyperbola is derived using trigonometric identities and substituted values. The given hyperbola has vertices (0,±2) and foci (0,±5), which yields a = 2, and c = 5. Using these, the standard form of the hyperbola would be y²/4 - x²/21 = 1, and the parametric equations are x = sqrt(21) tan(θ), y = 2 sec(θ).
Explanation:To eliminate the parameter and obtain the standard form of the rectangular equation for a hyperbola, use the properties of trigonometric identities and apply the Pythagorean identity tan²(θ) + 1 = sec²(θ). Now, express tan(θ) and sec(θ) in terms of x and y, and substitute these into the Pythagorean identity to obtain the equation of the hyperbola.
In this case, tan(θ) = (x - h) / b and sec(θ) = (y - k) / a. Substitute these into the Pythagorean identity to get ((x - h) / b)² + 1 = ((y - k) / a)². Rearrange to obtain ({(x - h)²}/{b²}) - ({(y - k)²}/{a²}) = 1. This is the standard form of the hyperbola equation centered at (h, k).
For the specific hyperbola given with vertices (0,±2) and foci (0,±5), you can determine that a = 2, and c = 5. Using the relationship c² = a² + b² (for hyperbolas), you can find b = sqrt(c² - a²) = sqrt((5)² - (2)²) = sqrt(21).
So, the standard form of the equation would be y²/4 - x²/21 = 1. The parametric equations revert back to the original equation with specific values, i.e., x = sqrt(21) tan(θ) and y = 2 sec(θ).
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NEED HELP ASAP!!!!!!!!!!!!
Answer:
p(0) = 800
p(8) = 997
Step-by-step explanation:
p(t) = 800 * (1.028)^t
The current price is when t=0
p(0) = 800 * (1.028)^0
= 800(1)
= 800
The price in 8 years
p(8) = 800 * (1.028)^8
=997.7802522414861936754688
To the nearest dollar
= 998
Answer:
[tex]p(0)=\$\ 800[/tex]
[tex]p(8)=\$\ 998[/tex]
Step-by-step explanation:
The function that the mode in the price is a function of exponential growth
[tex]p(t)=800(1.028)^t[/tex]
If t represents time in years, then to find the current price we do [tex]t = 0[/tex]
Then:
[tex]p(t=0)=800(1.028)^0[/tex]
[tex]p(0)=800(1)[/tex]
[tex]p(0)=\$\ 800[/tex]
To find the price after 8 years substitute t = 8 in the equation
[tex]p(t=8)=800(1.028)^8[/tex]
[tex]p(8)=\$\ 998[/tex]
Identify the radius and center.
x^2 + y^2 + 4y -21 =0
Answer:
radius 5
center (0,-2)
Step-by-step explanation:
The goal is to get to [tex](x-h)^2+(y-k)^2=r^2 \text{ where } (h,k) \text{ is the center and } r \text{ is the radius }[/tex].
We will need to complete the square for both parts.
That is we need to use:
[tex]u^2+bu+(\frac{b}{2})^2=(u+\frac{b}{2})^2[/tex].
First step is group the x's and y's together and put the constant on the opposing side. The x's and y's are already together. So we need to add 21 on both sides:
[tex]x^2+y^2+4y=21[/tex]
Now the x part is already done.
If you compare y^2+4y to [tex]u^2+bu+(\frac{b}{2})^2=(u+\frac{b}{2})^2[/tex]
on the left side we have b is 4 so we need to add (4/2)^2 on both sides of [tex]x^2+y^2+4y=21[/tex].
[tex]x^2+y^2+4y+(\frac{4}{2})^2=21+(\frac{4}{2})^2[/tex]
Now we can write the y part as something squared still using my completing the square formula:
[tex]x^2+(y+\frac{4}{2})^2=21+2^2[/tex]
[tex]x^2+(y+2)^2=21+4[/tex]
[tex](x-0)^2+(y+2)^2=25[/tex]
The center is (0,-2) and radius is [tex]\sqrt{25}=5[/tex]
The answer is:
Center: (0,-2)
Radius: 2.5 units.
Why?To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
Where,
"h" and "k"are the coordinates of the center of the circle and "r" is its radius.
So, we need to complete the square for both variable "x" and "y".
The given equation is:
[tex]x^2+y^2+4y-21=0[/tex]
So, solving we have:
[tex]x^2+y^2+4y=21[/tex]
[tex]x^2+(y^2+4y+(\frac{4}{2})^{2})=21+(\frac{4}{2})^{2}\\\\x^2+(y^2+4y+4)=21+4\\\\x^2+(y^2+2)=25[/tex]
[tex]x^2+(y^2-(-2))=25[/tex]
Now, we have that:
[tex]h=0\\k=-2\\r=\sqrt{25}=5[/tex]
So,
Center: (0,-2)
Radius: 5 units.
Have a nice day!
Note: I have attached a picture for better understanding.
could someone explain and help
Answer:
80°
Step-by-step explanation:
The sum of the two angles (red and blue) is 145°, so you have ...
(4x +5)° +(6x -10)° = 145°
10x = 150 . . . . . . . . divide by °, add 5, simplify
x = 15 . . . . . . . . . . . divide by 10
Then the measure of the angle of interest is ...
m∠XMN = (6x -10)° = (6·15 -10)° = 80°
2- suppose a ball is thrown upward to a height of h0 meters . each time the ball bounces, it rebounds to a fraction r of its previous height . let hn be the hight after the nth term biunces. cosider the following value of h0 and r
a- find the first 4 terms of the sequence of heights(hn)
b- find a general expression for the nth term of the sequence (hn)
h0=20 , r=0.5
Answer:
a) 40, 50, 55, 57.5
b) [tex]S_n=h_0+2h_0\sum_{n=1}^{\infty}r^n[/tex]
Step-by-step explanation:
h₀ = Initial height of the ball =20
r = Rebound fraction = 0.5
a) The series of bouncing balls is given by
Sₙ=h₀+2h₀(r¹+r²+r³+r⁴.........rⁿ)
S₁=h₀+2h₀r¹=20+2×20×0.5=40
S₂=h₀+2h₀(r¹+r²)=20+2×20×(0.5+0.5²)=50
S₃=h₀+2h₀(r¹+r²+r³)=20+2×20×(0.5+0.5²+0.5³)=55
S₄=h₀+2h₀(r¹+r²+r³+r⁴)=20+2×20×(0.5+0.5²+0.5³+0.5⁴)=57.5
b) General expression for the nth term of the sequence
[tex]S_n=h_0+2h_0\sum_{n=1}^{\infty}r^n[/tex]
Final answer:
The first 4 heights after each bounce form a geometric sequence with the first term h₀ being 20 meters and subsequent terms being 10, 5, and 2.5 meters. The general expression for the nth term (hn) is given by the formula hₙ = 20 * (0.5)ⁿ
Explanation:
Given an initial height h₀ of 20 meters and a rebound fraction r of 0.5, the sequence of heights after each bounce forms a geometric sequence.
The first height is h₀ which is 20 meters. Subsequent heights can be found by multiplying the previous height by the rebound fraction r.
Third term : h2 = h= 10 * 0.5 = 5 meters
General Expression for the nth Term (b)
The nth term (hₙ) of the sequence can be found using the formula for the nth term of a geometric sequence:
hₙ = h₀ * rⁿ
For this particular sequence:
hₙ = 20 * (0.5)ⁿ
he head librarian at the Library of Congress has asked her assistant for an interval estimate of the mean number of books checked out each day. The assistant provides the following interval estimate: from 740 to 920 books per day. If the head librarian knows the population standard deviation is 150 books checked out per day, how large a sample did her assistant use to determine the interval estimate?
Answer:
At 95% confidence level, she used 11 people to estimate the confidence interval
Step-by-step explanation:
The bounds of the confidence interval are: 740 to 920
Mean is calculated as the average of the lower and upper bounds of the confidence interval. So, for the given interval mean would be:
[tex]u=\frac{740+920}{2}=830[/tex]
Margin of error is calculated as half of the difference between the upper and lower bounds of the confidence interval. So, for given interval, Margin of Error would be:
[tex]E=\frac{920-740}{2}=90[/tex]
Another formula to calculate margin of error is:
[tex]E=z\frac{\sigma}{\sqrt{n}}[/tex]
Standard deviation is given to be 150. Value of z depends on the confidence level. Confidence Level is not mentioned in the question, but for the given scenario 95% level would be sufficient enough.
z value for this confidence level = 1.96
Using the values in above formula, we get:
[tex]90=1.96 \times \frac{150}{\sqrt{n} }\\\\ n = (\frac{1.96 \times 150}{90})^{2}\\\\ n=11[/tex]
So, at 95% confidence level her assistant used a sample of 11 people to determine the interval estimate
Final answer:
The sample size used by the assistant to determine the interval estimate is 7.
Explanation:
To determine how large a sample the assistant used to determine the interval estimate, we need to use the formula for the margin of error:
Margin of Error = Critical Value × Standard Deviation / sqrt(Sample Size)
In this case, the margin of error is half the width of the interval estimate, which is (920 - 740) / 2 = 90.
Using a z-table, the critical value for a 95% confidence level is approximately 1.96.
By substituting the given values into the formula, we can solve for the sample size:
90 = 1.96 × 150 / sqrt(Sample Size)
Simplifying the equation, we get:
sqrt(Sample Size) = 1.96 × 150 / 90
Sample Size = (1.96 × 150 / 90)^2 = 6.83
Since we cannot have a fraction of a sample, we round up to the nearest whole number.
Therefore, the assistant used a sample size of 7 to determine the interval estimate.
An inverted pyramid is being filled with water at a constant rate of 50 cubic centimeters per second. The pyramid, at the top, has the shape of a square with sides of length 6 cm, and the height is 14 cm. Find the rate at which the water level is rising when the water level is 6 cm.
The rate at which the water level is rising when the water level is 6 cm is 8.33 cm/s.
Explanation:We can find the rate at which the water level is rising by using similar triangles. Let the height of the water level be h (in cm). Since the pyramid is inverted, the volume of water inside the pyramid is given by V = (6-h)^2 * h. Taking the derivative of both sides with respect to time, we get dV/dt = 50. Solving for dh/dt, we find that the rate at which the water level is rising is dh/dt = 50 / (12 - h).
When the water level is 6 cm, we substitute h = 6 into the equation to find the rate at which the water level is rising. dh/dt = 50 / (12 - 6) = 50 / 6 = 8.33 cm/s. Therefore, when the water level is 6 cm, the rate at which the water level is rising is 8.33 cm/s.
What's the annual percentage yield for money invested at the rate of 3.2% compounded continuously?
Answer:__________ %
Convert your answer into a percentage. Round your answer to 2 decimal places.
Answer:
The Annual percentage yield is 3.25%.
Step-by-step explanation:
Given : Money invested at the rate of 3.2% compounded continuously.
To find : What's the annual percentage yield?
Solution :
Money invested at the rate of 3.2% compounded continuously.
The compounded continuously formula is
[tex]A=Pe^{rt}[/tex]
Where, P is the principal P=1
t is the time t=1
r is the interest rate r=3.2%=0.032
Substitute the value in the formula,
[tex]A=Pe^{rt}[/tex]
[tex]A=1\times e^{0.032}[/tex]
[tex]A=1.0325[/tex]
The Annual percentage yield is
[tex]APY=(A-1)\times 100[/tex]
[tex]APY=(1.0325-1)\times 100[/tex]
[tex]APY=0.0325\times 100[/tex]
[tex]APY=3.25\%[/tex]
Therefore, The Annual percentage yield is 3.25%.
Maria needed 88 gallons of gas to fill her car's gas tank. The mileage odometer read 40 comma 00040,000 miles. When the odometer read 40 comma 18040,180, Maria filled the tank with 99 gallons. At the end of the trip, she filled the tank with 1616 gallons, and the odometer read 40 comma 48440,484 miles. How many miles per gallon did she get for the entire trip?
Answer:
about 29,748.3
Step-by-step explanation:
4000040000 - 4018040180 = 18000180
(11 gallons were used there^)
4018040180 - 4048440484 = 30400304
1616+11 = 1627 total gallons
18000180 + 30400304 = 48400484
48400484/ 1627 = 29,748.3
caps hock Guess and Check (or use Algebra) to solve #3 & # 4 3. Plato has 36 coins in nickels, dimes, and quarters. The number of nickels is three less than twice the number of dimes. The total value of the coins is $5.20. How many of each type of coin does Plato have? mel 36 coinsin d
4. Katy bought a ski hat that was marked down 35% to $15.60. What was the price of the hat before the markdown? (Hint: She was in Oregon where they do not have sales tax). 35 9. douon 15.60 5. Sele amo ont 621.06
Answer:
Part 1:
Let the nickels be = n
Let the dimes be = d
Let the quarters be = q
Plato has 36 coins in nickels, dimes, and quarters. So, equation forms:
[tex]n+d+q=36[/tex] .....(1)
The number of nickels is three less than twice the number of dimes.
[tex]n=2d-3[/tex] ....(2)
The total value of the coins is $5.20.
[tex]0.10d+0.05n+0.25q=5.20[/tex] .... (3)
Substituting n=2d-3 in (1) and (3)
[tex]2d-3+d+q=36[/tex]
=> [tex]3d+q=39[/tex] ....(4)
[tex]0.10d+0.05(2d-3)+0.25q=5.20[/tex]
=> [tex]0.10d+0.10d-0.15+0.25q=5.20[/tex]
=> [tex]0.20d+0.25q=5.35[/tex] ...(5)
Multiplying (4) by 0.25 and subtracting (5) from (4)
[tex]0.75d+0.25q=9.75[/tex] now subtracting (5) from this we get;
[tex]0.55d=4.4[/tex]
=> d = 8
Substituting d = 8 in [tex]3d+q=39[/tex]
[tex]3(8)+q=39[/tex]
[tex]24+q=39[/tex]
=> q = 15
Substituting values of d and q in [tex]n+d+q=36[/tex], we get n
[tex]n+8+15=36[/tex]
[tex]n=36-23[/tex]
=> n = 13
Therefore Plato has 13 nickels, 15 quarters and 8 dimes.
-----------------------------------------------------------------------------------------
Part 2:
Let the original price of the ski hat be = x
Original price was marked down by 35% means value was lowered by 35%.
So, we can calculate as:
[tex]x-\frac{35x}{100}=15.60[/tex]
=> [tex]\frac{65x}{100}=15.60[/tex]
=> [tex]65x=1560[/tex]
x = 24
Hence, the original price was $24 but after 35% marking down, it was available for $15.60.
A card is drawn at random from a standard deck of 52 cards. Find the following conditional probabilities. a) The card is a spade, given that it is black. b) The card is black, given that it is a spade. c) The card is a seven, given that it is black. d) The card is a king, given that it is a face card.
To find the conditional probabilities, you need to use the definition of conditional probability. Given that a card is black, the probability that it is a spade is 1/2. Given that a card is a spade, the probability that it is black is 2. Given that a card is black, the probability that it is a seven is 1/13. Given that a card is a face card, the probability that it is a king is 1/3.
Explanation:To find these conditional probabilities, we need to use the definition of conditional probability:
P(A|B) = P(A and B) / P(B)
a) The card is a spade, given that it is black:
In a standard deck of cards, there are 26 black cards and 13 spades. So, P(S|B) = P(S and B) / P(B) = 13/26 / 26/52 = 1/2
b) The card is black, given that it is a spade:
P(B|S) = P(B and S) / P(S) = 26/52 / 13/52 = 26/13 = 2
c) The card is a seven, given that it is black:
In a standard deck of cards, there are 4 black sevens and 26 black cards. So, P(7|B) = P(7 and B) / P(B) = 4/26 / 26/52 = 1/13
d) The card is a king, given that it is a face card:
In a standard deck of cards, there are 4 kings and 12 face cards. So, P(K|F) = P(K and F) / P(F) = 4/52 / 12/52 = 1/3
13. Determine whether B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} is a basis of R3.
Answer: Yes, the given set of vectors is a basis of R³.
Step-by-step explanation: We are given to determine whether the following set of three vectors in R³ is a basis of R³ or not :
B = {(-1, 1,-1), (1, 0, 2), (1, 1, 0)} .
For a set to be a basis of R³, the following two conditions must be fulfilled :
(i) The set should contain three vectors, equal to the dimension of R³
and
(ii) the three vectors must be linearly independent.
The first condition is already fulfilled since we have three vectors in set B.
Now, to check the independence, we will find the determinant formed by theses three vectors as rows.
If the value of the determinant is non zero, then the vectors are linearly independent.
The value of the determinant can be found as follows :
[tex]D\\\\\\=\begin{vmatrix} -1& 1 & -1\\ 1 & 0 & 2\\ 1 & 1 & 0\end{vmatrix}\\\\\\=-1(0\times0-2\times1)+1(2\times1-1\times0)-1(1\times1-0\times1)\\\\=(-1)\times(-2)+1\times2-1\times1\\\\=2+2-1\\\\=3\neq 0.[/tex]
Therefore, the determinant is not equal to 0 and so the given set of vectors is linearly independent.
Thus, the given set is a basis of R³.
A pile of 42 coins worth $4.90, consisting of nickels and quarters. How many nickels are there?
Answer:14
Step-by-step explanation:
A nickel is 5 cents (20% of dollar)
and a quarter is 25 cents (25% of dollar)
We have given a pile of 42 coins worth of $4.90
Let x be the no nickels and
y be the no of quarter
therefore
x+y=42 -----1
[tex]\frac{x}{4}[/tex]+[tex]\frac{y}{20}[/tex]=4.90 ---2
Solving [tex]\left ( 1\right )&\left ( 2\right )[/tex] we get
x=14 & y=28
Therefore no of nickels is 14 & no of quarters is 28
A cable provider wants to contact customers in a particular telephone exchange to see how satisfied they are with the new digital TV service the company has provided. All numbers are in the 443 exchange, so there are 10 comma 000 possible numbers from 443-0000 to 443-9999. If they select the numbers with equal probability: a) What distribution would they use to model the selection? b) What is the probability the number selected will be an even number? c) What is the probability the number selected will end in 666?
Answer:
a) uniform
b) 1/2
c) 1/1000
Step-by-step explanation:
a) "numbers with equal probability" have a uniform distribution.
__
b) Even numbers make up 1/2 of all numbers.
__
c) There are ten such numbers in the range, so the probability is ...
10/10000 = 1/1000
The selection of telephone numbers can be modeled using a Uniform distribution. The probability of selecting an even number is 1/2, while the chance of selecting a number ending in 666 is 0.001.
Explanation:The questions asked can be explained using probability theory, a branch of mathematics.
a) To model the selection of the telephone numbers, one would use a Uniform distribution. This is because every number in the range has an equal chance of being selected.
b) The probability that the selected number is even relies on the last digit of the telephone number. As the last digit could be 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9, each with equal probability, the chance that it is even (0, 2, 4, 6, or 8) is 1/2 or 50%.
c) The probability that the selected number ends in 666 is much lower. Since there are 10,000 possible numbers, and only 10 of them end in 666 (443-0666, 443-1666, etc. through 443-9666), the probability is 10 in 10,000 or 0.001 (0.1%).
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A fair coin is flipped 4 times. What is the probability that at least two heads are flipped?
The probability of flipping at least two heads in four tosses of a fair coin is calculated using the binomial distribution, and the total probability is found to be 0.6875 or 68.75%.
To calculate the probability of flipping at least two heads in a series of four coin tosses with a fair coin, we need to consider all the possible outcomes in which we can get at least two heads. The different numbers of heads that can be obtained are 0, 1, 2, 3, or 4. To find the probability of each specific event, we use the binomial distribution formula, which for flipping two heads is:
P(2 heads) = (4 choose 2) × (0.5)² × (0.5)² = 6 × 0.25 × 0.25 = 0.375.
We can also find the probabilities of obtaining three and four heads:
P(3 heads) = (4 choose 3) × (0.5)³ × (0.5)¹ = 4 × 0.125 × 0.5 = 0.25,
P(4 heads) = (4 choose 4) × (0.5)⁴ = 1 × 0.0625 = 0.0625.
Next, we add these probabilities together to get the total probability of flipping at least two heads:
Total probability = P(2 heads) + P(3 heads) + P(4 heads) = 0.375 + 0.25 + 0.0625 = 0.6875.
Therefore, the probability of flipping at least two heads in four tosses of a fair coin is 0.6875 or 68.75%.
A genetic experiment with peas resulted in one sample of offspring that consisted of 447447 green peas and 172172 yellow peas. a. Construct a 9090% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?
Answer:
The results do not contradict expectations.
Step-by-step explanation:
Given that a genetic experiment with peas resulted in one sample of offspring that consisted of 447 green peas and 172 yellow peas.
Proportion of yellow peas = [tex]\frac{172}{172+447} =27.79%[/tex]
Std error = 0.25(0.75)/sq rt 619
=0.0174
Proportion difference = 0.2779-0.25=0.0279
Test statistic = 0.0279/0.0174 =1.603
p value = 0.1089
For two tailed we have p value >0.10
Hence accept null hypothesis.
The results do not contradict expectations.
y = −(x + 4)2 − 7 vertex
Answer:
The vertex (h,k) is (-4,-7).
Step-by-step explanation:
I assume you are looking for the vertex [tex]y=-4(x+4)^2-7[/tex].
The vertex form of a quadratic is [tex]y=a(x-h)^2+k[/tex] where the vertex is (h,k) and a tells us if the parabola is open down (if a<0) or up (if a>0). a also tells us if it is stretched or compressed.
Anyways if you compare [tex]y=-4(x+4)^2-7[/tex] to [tex]y=a(x-h)^2+k[/tex] , you should see that [tex]a=-4,h=-4,k=-7[/tex].
So the vertex (h,k) is (-4,-7).
Answer:
The vertex is [tex](-4,-7)[/tex]
Step-by-step explanation:
The vertex form of a parabola is given by:
[tex]y=a(x-h)^2+k[/tex], where (h,k) is the vertex and [tex]a[/tex] is the leading coefficient.
The given parabola has equation:
[tex]y=-1(x+4)^2-7[/tex]
When we compare to the vertex form, we have
[tex]-h=4\implies h=-4[/tex] and [tex]k=-7[/tex].
Therefore the vertex is (-4,-7)
Find the slope of the line through the pair of points by using the slope formula. (-4,3) and (-2, -4) The slope of the line is (Type an integer or a simplified fraction.)
Answer: [tex]-3\dfrac{1}{2}[/tex].
Step-by-step explanation:
We know that the slope of a line passing through points (a,b) and (c,d) is given by :_
[tex]m=\dfrac{d-b}{c-a}[/tex]
The given points : (-4,3) and (-2, -4)
Now, the slope of the line passing through points (-4,3) and (-2, -4) is given by :-
[tex]m=\dfrac{-4-3}{-2-(-4)}\\\\\Rightarrow\ m=\dfrac{-7}{-2+4}\\\\\Rightarrow\ m=\dfrac{-7}{2}=-3\dfrac{1}{2}[/tex]
The slope of a line passing through points (-4,3) and (-2, -4) is [tex]-3\dfrac{1}{2}[/tex].
In Problems 25-28 use (12) to verify that the indicated function is a solution of the given differential equation. Assume an appropriate interval / of definition of each solution. - 3 dt dy 25. x dx 3xy 1: y-e|. = e3r t
the answer is 17. the answer is 17
1. Suppose you take a coin and flip it 4 times in a row. After each flip you record whether the coin landed heads or tails. What is the probability you’ll get at least 2 heads?
Answer:
25%
Step-by-step explanation:
Great question, since a regular coin has two sides one heads and one tails. That gives us a 50% probability of it landing on either side of the coin. Since we would like to know the probability of getting 2 heads in a row, we would need to multiply the probability of the first toss landing on heads with the second toss landing on heads, like so...
[tex]\frac{1}{2} *\frac{1}{2} =\frac{1}{4}[/tex]
So we can see that the probability of us getting two heads in a row is that of \frac{1}{4}[/tex] or 25%.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Find a parametric representation for the surface. The part of the plane z = x + 3 that lies inside the cylinder x2 + y2 = 9. (Enter your answer as a comma-separated list of equations. Let x, y, and z be in terms of s and/or θ.)
You can use
[tex]x=u\cos v[/tex]
[tex]y=u\sin v[/tex]
[tex]z=u\cos v+3[/tex]
with [tex]0\le u\le3[/tex] and [tex]0\le v\le2\pi[/tex].
The parametric equations for the part of the plane z = x + 3 that lies inside the cylinder x² + y² = 9 can be written as x = 3cos(θ), y = 3sin(θ), and z = 3cos(θ) + 3.
Explanation:The parametric representation of a surface can be found by expressing the variables x, y, and z in terms of parameters. Given the cylinder equation x² + y² = 9, we can express x and y in terms of a single parameter θ as follows:
x = 3cos(θ)y = 3sin(θ)Here we've used the parametric equations for a circle of radius 3. Moving further with the given plane equation z = x+3, we substitute x from our parametric equations above:
z = 3cos(θ) + 3So, the parametric representation for the given surface is:
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Mr. Smith is purchasing a $ 100000 house. The down payment is 20 % of the price of the house. He is given the choice of two mortgages:
a) a 30-year mortgage at a rate of 7 %.
Find: (i) the monthly payment: $ (ii) the total amount of interest paid: $
b) a 15-year mortgage at a rate of 7 %.
Find: (i) The monthly payment:$ (ii) the total amount of interest paid: $
The price of the house = $ 100000
The down payment is 20 % of 100000 means [tex]0.20\times100000=20000[/tex] dollars
So, loan amount will be = [tex]100000-20000=80000[/tex] dollars
Case A:
30-year mortgage at a rate of 7 %
p = 80000
r = [tex]7/12/100=0.005833[/tex]
n = [tex]30\times12=360[/tex]
EMI formula is :
[tex]\frac{p\times r\times(1+r)^n}{(1+r)^n-1}[/tex]
Putting the values in formula we get;
[tex]\frac{80000\times0.005833\times(1+0.005833)^360}{(1+0.005833)^360-1}[/tex]
= [tex]\frac{80000\times0.005833\times(1.005833)^360}{(1.005833)^360-1}[/tex]
Monthly payment = $532.22
So, total amount paid in 30 years will be = [tex]532.22\times360=191599.20[/tex]
Interest paid will be = [tex]191599.20-100000=91599.20[/tex] dollars
Case B:
15-year mortgage at a rate of 7 %.
Here everything will be same as above. Only n will change.
n = [tex]15\times12=180[/tex]
Putting the values in formula we get;
[tex]\frac{80000\times0.005833\times(1+0.005833)^180}{(1+0.005833)^180-1}[/tex]
= [tex]\frac{80000\times0.005833\times(1.005833)^180}{(1.005833)^180-1}[/tex]
Monthly payment = $719.04
Total amount paid in 15 years will be = [tex]719.04\times180=129427.20[/tex]
Interest paid will be = [tex]129427.20-100000=29427.20[/tex] dollars
To find the monthly payment and total amount of interest paid for each mortgage, use the formula A = P(1+r/12)^(12n) / (12n), where A is the monthly payment, P is the principal, r is the interest rate, and n is the number of months.
Explanation:To find the monthly payment and total amount of interest paid for each mortgage option, we can use the formula for calculating the monthly mortgage payment:
A = P(1+r/12)^(12n) / (12n)
where A is the monthly payment, P is the principal (price of the house minus the down payment), r is the interest rate (expressed as a decimal), and n is the number of months in the mortgage term.
For option a) the 30-year mortgage, we have:
P = 100000 - (0.2 * 100000) = $80000
r = 0.07
n = 30 * 12 = 360
Plugging these values into the formula, we get:
A = (80000(1+(0.07/12))^(12 * 30)) / (12 * 30) = $532.09
To calculate the total amount of interest paid, we subtract the principal from the total payment over the life of the mortgage:
Total Interest Paid = (360 * 532.09) - 80000 = $93891.24
For option b) the 15-year mortgage, we have:
P = 100000 - (0.2 * 100000) = $80000
r = 0.07
n = 15 * 12 = 180
Plugging these values into the formula, we get:
A = (80000(1+(0.07/12))^(12 * 15)) / (12 * 15) = $754.56
To calculate the total amount of interest paid, we subtract the principal from the total payment over the life of the mortgage:
Total Interest Paid = (180 * 754.56) - 80000 = $75822.80
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8 Line in the xy-plane contains points from each of Quadrants II, III, and IV, but no points from Quadrant I. Which of the following must be true? A) The slope of line is undefined. B) The slope of line is zero. C) The slope of line is positive. D) The slope of line is negative. CONTINUE
Answer:
The correct option is D.
Step-by-step explanation:
The slope of a line is the change in y with respect to x.
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
If the slope of a line is undefined it means it is a vertical line and a vertical line can not passes through three quadrants. So, option A is incorrect.
If the slope of a line is 0 it means it is a horizontal line and a horizontal line can not passes through three quadrants. So, option B is incorrect.
If the slope of a line is positive it means the value of y increases as x increases.
Since it is an increasing line, therefore after a certain period both x and y will positive. It means the line will passes through first quadrant. So, option C is incorrect.
If the slope of a line is negative it means the value of y decreases as x increases. It can passes through each of Quadrants II, III, and IV.
Therefore the correct option is D.
3. (6 Points). Solve the initial value problem y'-y.cosx=0, y(pi/2)=2e
Answer:
[tex]y=2e^{sin(x)}[/tex]
Step-by-step explanation:
Given equation can be re written as
[tex]\frac{\mathrm{d} y}{\mathrm{d} x}-ycos(x)=0\\\frac{\mathrm{d} y}{\mathrm{d} x}=ycos(x)\\\\=> \frac{dy}{y}=cox(x)dx\\\\Integrating \\ \int \frac{dy}{y}=\int cos(x)dx \\\\ln(y)=sin(x)+c[/tex]............(i)
Now it is given that y(π/2) = 2e
Applying value in (i) we get
ln(2e) = sin(π/2) + c
=> ln(2) + ln(e) = 1+c
=> ln(2) + 1 = 1 + c
=> c = ln(2)
Thus equation (i) becomes
ln(y) = sin(x) + ln(2)
ln(y) - ln(2) = sin(x)
ln(y/2) = sin(x)
[tex]y= 2e^{sinx}[/tex]
You invest $1600 in an account paying 5% interest compounded daily. What is the account's effective annual yield? Assume 360 days in a year.
The account's effective annual yield is ___% (Round to two decimal places as needed)
Answer:
5.13%.
Step-by-step explanation:
Amount accumulated in 1 year
= 1600(1 + 0.05/360)^360
= $1682.03
Account's effective annual yield
= 82.03 * 100 / 1600 %
= 5.13%.
The account's effective annual yield (EAY) for an investment of $1600 with a 5% interest rate compounded daily (assuming a 360-day year) is approximately 5.12% when rounded to two decimal places.
The student has invested $1600 in an account that offers 5% interest compounded daily with the assumption of a 360-day year. To find the effective annual yield, we use the formula for compound interest and the definition of effective annual yield (EAY), which accounts for the compounding effect:
EAY = (1 + r/n)n - 1
Where:
In this case:
Now, substituting the values, we get:
EAY = (1 + 0.05/360)360 - 1
Calculating this out:
EAY = (1 + 0.0001388888889)360 - 1
EAY
to find the EAY:
EAY = ((1 + (0.05/360))^360) - 1
After calculating the above expression, the approximate effective annual yield comes out to be:
EAY = 0.05116 or 5.116%
Therefore, after rounding to two decimal places as required, the effective annual yield of the account is 5.12%.
Prove that if AB= 0and A is invertible then B= 0
Answer with Step-by-step explanation:
Since we have given that
AB = 0 and A is invertible so, AA⁻¹ = I
So, Consider,
[tex]AB=0[/tex]
Multiplying A⁻¹ on both the sides, we get that
[tex]A^{-1}AB=A^{-1}0\\\\(AA^{-1})B=0\\\\IB=0\\\\B=0[/tex]
Hence proved.