Heart failures are due to either natural occurrences (87%) or outside factors (13%). Outside factors are related to induced substances (73%) or foreign objects (27%). Natural occurrences are caused by arterial blockage (56%), disease (27%), and infection (e.g., staph infection) (17%).(a) Determine the probability that a failure is due to induced substance.(b) Determine the probability that a failure is due to disease or infection.

Answer: 1

Step-by-step explanation:

[(√4 + 3)² – 9] / (√9 – 1)³ * 2 =

[(2 + 3)² – 9] / (3 – 1)³ * 2 =

[(5)² – 9] / (2)³ * 2 =

[25 – 9] / 8 * 2 =

[16] / 16 = 1

Answer:

The concentration of the drug is 5ug/uL

Step-by-step explanation:

The first step of the problem is the conversion of the quantities of the drug in mg and mL to ug and uL.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

Unit conversion problems, like this one, is an example of a direct relationship between measures.

First step: Conversion of 125mg to ug

Each mg has 1,000ug. So:

1mg - 1,000ug

125mg - xug

x = 1,000*125

x = 125,000 ug

Second step: Conversion of 25 mL to uL

Each mL has 1,000uL. So:

1mL - 1,000uL

25mL - x uL

x = 25*1,000

x = 25,000uL

Concentration:

[tex]C = \frac{125,000 ug}{25,000uL} = 5ug/uL[/tex]

The concentration of the drug is 5ug/uL

The concentration of the drug in terms of  μg/μL is 5 μg/μL

The given parameters are:

125 mg of drug in each 25 mL

The concentration (k) of the drug is then calculated as:

[tex]k = \frac{125 mg}{25mL}[/tex]

Divide

[tex]k = 5\frac{mg}{mL}[/tex]

The units of the injection and the drug is in mill-.

So, the concentration can be rewritten as:

[tex]k = 5\frac{\mu g}{\mu L}[/tex]

Hence, the concentration of the drug in terms of  μg/μL is 5 μg/μL

Read more about concentration at:

https://brainly.com/question/14485544

Answer:

length of the third side may be either 3.4 m or 2.8 m.

Step-by-step explanation:

Measure of two sides of a right triangle are 1.4 m and the other side is 3.1 m.

then we have to find the measure of third side.

If the third side of the triangle is its hypotenuse then

(Third side)² = (1.4)² + (3.1)²

Third side = [tex]\sqrt{(1.4)^{2}+(3.1)^{2}}[/tex]

                 = [tex]\sqrt{1.96+9.61}[/tex]

                 = [tex]\sqrt{11.57}[/tex]

                 = 3.4 m

If the third side is one of the perpendicular sides of the triangle and 3.1 m is hypotenuse, then

(Third side)² + (1.4)² = (3.1)²

(Third side)²= (3.1)² - (1.4)²

Third side = [tex]\sqrt{(3.1)^{2}-(1.4)^{2}}[/tex]

                 = [tex]\sqrt{9.61-1.96}[/tex]

                 = [tex]\sqrt{7.65}[/tex]

                 = 2.76 m

                 ≈ 2.8 m

Therefore, length of the third side may be either 3.4 m or 2.8 m.

Answer: Ok, we have two numbers, and one of them is an odd integer, and the other is even.

Lets call M to the odd integer and N the even.

We know that a even integer can be written as 2k, where k is a random integer, and a odd integer can be written as 2j + 1, where j is also a random integer.

then M = 2k, N= 2j+1

then the product of M and N is: M*N = 2*k*(2*j + 1) = 2*(k*2*j + k)

is obvious to see that (k*2*J + k) is a integer, because k and j are integers.

then if we call g = ( k*2*J + k), we can write M*N=2g, and we already know that this is an even number. So M*N is a even integer.

Answer:

a) False. b) False. c) No, it's Rational. d) pi=355/113 e) 5i (for Complex Set of Numbers)

Step-by-step explanation:

a) Since there is the empty set. And an axiom assures us the existence of this Set. "There is a set such no element belongs to it"

∅ has no elements.

b) A perfect number is a positive integer equals to the sum of proper divisions

The smallest is 6. Since the proper divisors of 6={3,2,1}. 6=1+2+3

28 is a perfect number, but not the smallest. It is perfect since

28 proper divisors={14,7,4,2} 28=1+2+3+4+5+6+7

c) No, An Irrational number cannot be written as a fraction a/b where "a" and "b" are integers. 1.5 is a rational one, since 3/2 =1.5

d)

[tex]\pi[/tex]=22/7 -1/791= 355/113

e)  Not for Real Numbers, since it is not defined for Real numbers. But for the set of Complex 5i

Answer:

405.26%

Step-by-step explanation:

We have been given that in 1970 the male incarceration rate in the U.S. was approximately 190 inmates per 100,000 population. In 2008 the rate was 960 inmates per 100,000 population.

[tex]\text{Percent increase}=\frac{\text{Final amount}-\text{Initial amount}}{\text{Initial amount}}\times 100[/tex]

[tex]\text{Percent increase}=\frac{960-190}{190}\times 100[/tex]

[tex]\text{Percent increase}=\frac{770}{190}\times 100[/tex]

[tex]\text{Percent increase}=4.052631578947\times 100[/tex]

[tex]\text{Percent increase}=405.2631578947\%[/tex]

[tex]\text{Percent increase}\approx 405.26\%[/tex]

Therefore, the percent increase in the male incarceration rate during the given period is 405.26%.

Answer:

[tex]18234=2\times 3\times 3\times 1013[/tex]

Step-by-step explanation:

We are given that a number 18234

We have to find the prime factorization of the number

Prime factorization : The number written  is in  the product of prime numbers is called prime factorization.

In order to find the prime factorization we will find the factors of given number

[tex]18234=2\times 3\times 3\times 1013[/tex]

Hence, the prime factorization of [tex]18234=2\times 3\times 3\times 1013[/tex]

Answer:

Both lights flash at 1:00

Step-by-step explanation:

they flash together every 2*7=14 minutes

in 60 minutes there are 4*14=56 minutes

they flash together at 1:56

more minutes brings you to 2:00

they flash together at 2:10 (4+10=14)

that leaves 50 minutes left in the hour

they flash three times which uses up 42 minutes

this brings you to 2:52 (10+42=52)

8 more minutes brings you to 3:00

in 6 more minutes (8+6=14) it will be 3:06 and they will flash together

Answer:

The area of triangle is 25 square units.

Step-by-step explanation:

Given information: Vertices of the triangle are (2,1), (10,-1), and (-1,8).

Formula for area of a triangle:

[tex]A=\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|[/tex]

The given vertices are (2,1), (10,-1), and (-1,8).

Using the above formula the area of triangle is

[tex]A=\frac{1}{2}|2(-1-8)+10(8-1)+(-1)(1-(-1))|[/tex]

[tex]A=\frac{1}{2}|2(-9)+10(7)+(-1)(1+1)|[/tex]

[tex]A=\frac{1}{2}|-18+70-2|[/tex]

On further simplification we get

[tex]A=\frac{1}{2}|50|[/tex]

[tex]A=\frac{1}{2}(50)[/tex]

[tex]A=25[/tex]

Therefore the area of triangle is 25 square units.

Answer:

4

Step-by-step explanation:

8 *4 is the same as 4*8; commutative property

Answer:

[tex]4[/tex]

Step-by-step explanation:

8 x 4 is exactly the same as 4 x 8, both equaling 32.

No matter how insert 4 and 8, it will always be the same

[tex]x \times y = y \times x [/tex]

^^^

Answer:

[tex](a)\ y(t)\ =\ -2e^{-2t}+3[/tex]

[tex](b)\ y(t)\ =\ 4e^{-2t}-3[/tex]

Step-by-step explanation:

(a) Given differential equation is

   Y'+2Y=6

=>(D+2)y = 6

To find the complementary function, we will write

D+2=0

=> D = -2

So, the complementary function can be given by

[tex]y_c(t)\ =\ C.e^{-2t}[/tex]

To find the particular integral, we will write

[tex]y_p(t)\ =\ \dfrac{6}{D+2}[/tex]

          [tex]=\ \dfrac{6.e^{0.t}}{D+2}[/tex]

           [tex]=\ \dfrac{6}{0+2}[/tex]

           = 3

so, the total solution can be given by

[tex]y_(t)\ =\ C.F+P.I[/tex]

         [tex]=\ C.e^{-2t}\ +\ 3[/tex]

[tex]y_(0)=C.e^{-2.0}\ +\ 3[/tex]

but according to question

1 = C +3

=> C = -2

So, the complete solution can be given by

[tex]y_(t)\ =\ -2.e^{-2.t}\ +\ 3[/tex]

(b) Given differential equation is

   Y'+2Y=-6

=>(D+2)y = -6

To find the complementary function, we will write

D+2=0

=> D = -2

So, the complementary function can be given by

[tex]y_c(t)\ =\ C.e^{-2t}[/tex]

To find the particular integral, we will write

[tex]y_p(t)\ =\ \dfrac{-6}{D+2}[/tex]

           [tex]=\ \dfrac{-6.e^{0.t}}{D+2}[/tex]

           [tex]=\ \dfrac{-6}{0+2}[/tex]

           = -3

so, the total solution can be given by

[tex]y_(t)\ =\ C.F+P.I[/tex]

         [tex]=\ C.e^{-2t}\ -\ 3[/tex]

[tex]y_(0)\ =C.e^{-2.0}\ -\ 3[/tex]

but according to question

1 = C -3

=> C = 4

So, the complete solution can be given by

[tex]y_(t)\ =\ 4.e^{-2.t}\ -3[/tex]

Answer:

The gcd(123,76) is equal to 1. The linear combination is [tex]1=-21 \cdot 123+34 \cdot 76[/tex]

The 361x+2109y = 1000 does not have integer solutions because the gcd(2109, 361) is equal to 19 and [tex]19\not| \:1000[/tex]

Step-by-step explanation:

Point a:

The greatest common divisor (GCD) of two numbers is the largest numbers that divide them both. The Euclidean algorithm is an efficient method for computing the GCD without explicitly factoring the two integers.

These are the steps:

The division algorithm is an algorithm in which given 2 integers n and d, it computes their quotient q and remainder r, where [tex]0\leq r<|d|[/tex]. Let's say we have to divide n (dividend) by d (divisor):

To compute gcd(123,76), divide the larger number by the smaller number, using the division algorithm we have:

[tex]\frac{123}{76} = 123-76 =47[/tex]

At this point, we cannot subtract 76 again. Hence 1 is the quotient ( we subtract 76 from 123 one time) and 47 is the remainder. We can express this as a linear combination [tex]123=76 \cdot 1+47[/tex].

Using the same reasoning and the steps of the Euclidean algorithm we have:

[tex]gcd(123,76)=\\123=76 \cdot 1 +47\\76=47 \cdot 1 +29\\47=29 \cdot 1 +18\\29=18 \cdot 1 +11\\18=11 \cdot 1 +7\\11=7\cdot 1 +4\\7= 4\cdot 1+3\\4 = 3 \cdot 1 +1\\3 = 1 \cdot 3 +0[/tex]

The gcd(123,76) is equal to 1.

To represent 1 as a linear combination of the integers 123 and 76, we start with the next-to-last of the above equations and successively eliminate the remainders 3, 4, 7, 11, 18, 29, and 47.

[tex]1=4-3 \cdot 1\\1=4-(7-4 \cdot 1) \cdot 1\\1=2\cdot 4 - 7\cdot 1\\1=2\cdot(11 -7 \cdot 1) -7 \cdot 1\\1=2\cdot 11 -7 \cdot 3\\1=2\cdot 11 -(18-11\cdot 1) \cdot 3\\1=5\cdot 11-3\cdot 18\\1=5\cdot (29-18\cdot 1)-3\cdot 18\\1=5\cdot 29 -8\cdot 18\\1=5\cdot 29 -8\cdot (47-29\cdot 1)\\1=13\cdot 29 -8\cdot 47\\1=13 \cdot (76-47 \cdot 1)-8\cdot 47\\1=13 \cdot 76 -21 \cdot 47\\1=13 \cdot 76 -21 \cdot (123-76\cdot 1)\\1=-21 \cdot 123+34 \cdot 76[/tex]

Point b:

We can use this theorem:

When ax + by = c is solvable. Given integers a, b, and c with a and b not both 0, there exist integers x and y such that ax + by = c if and only if (a,b) | c

In this particular expression 361x+2109y = 1000 we need to find the gcd(2109, 361) and check if gcd(2109, 361) | 1000 is true.

[tex]2109=361\cdot 5 +304\\361 = 304 \cdot 1 +57\\304= 57\cdot 5 +19\\57=19\cdot 3 +0[/tex]

The gcd(2109, 361) is equal to 19. We can see that 19 does not divide 1000 ([tex]19\not| \:1000[/tex]), that is the reason 361x+2109y = 1000 does not have integer solutions.

Answer:

Ans. For option 1, you would pay a total of $14,677.64 and for the second option, you would pay $14,000.

Step-by-step explanation:

Hi, we need to find the amount of the equal payments that you need to make every month, given the problem´s conditions. First, let´s find the effective montly rate of this credit.

[tex]EffectiveMonthlyRate=\frac{Rate(Compounded Monthly)}{12}[/tex][tex]EffectiveMonthlyRate=\frac{0.036}{12} =0.003[/tex]

This means that the rate is 0.3% effective monthly

The period of time for this obligation is 3 years, but since the payments are made every month, we need to use 36 months instead of 3 years.

Now, we are ready to find the amount of money that you need to pay every month, for 36 months in order to pay for your car. We use the following formula.

[tex]PresentValue=\frac{A((1+r)^{n}-1) }{r(1+r)^{n} }[/tex]

Since you made a down payment of $2,000, we will only need to finance $12,000. This is the way everything should look like.

[tex]12,000=\frac{A((1+0.003)^{36}-1) }{0.003(1+0.003)^{36} }[/tex]

Let´s solve for A (annuity)

[tex]12,000=\frac{A(0.11386764 }{0.003416 }[/tex]

[tex]12,000==A(34.0757554)[/tex]}

[tex]\frac{12,000}{34.0757554} =A=352.17[/tex]

The total amount paid if you take this option is:

[tex]Amount Paid=2,000+352.17*36=14,677.64[/tex]

In the case of option 2 (0% loan-pay same amount every month for 36 months), there is no need for any calculations (because you pay $14,000 in total), but if you want to know how much to pay every month, you just go ahead and divide 14,000 by 36 which is $388.89. But at the end, this way you will pay $14,000.

Best of luck.

Final answer:

To find the number of which 18 percent is equal to 36 percent of 18, you set up the equation 0.36 × 18 = 0.18 × x and solve for x to find that x equals 36.

Explanation:

The student has asked: "36 percent of 18 is 18 percent of what number?" To solve this equation, we need to set it up as follows:

Let's assume the number we are searching for is x. Then, according to the question,

0.36 × 18 = 0.18 × x

Now, we can solve for x by dividing both sides of the equation by 0.18:

x = (0.36 × 18) / 0.18

After doing the calculation:

x = 6.48 / 0.18

x = 36

So, 36 percent of 18 is 18 percent of 36.

Answer:

a) 23 x 36 (mod 55) = 3 (mod 55)

b) 23 x 36 (mod 55) = 23 (mod 91)

Step-by-step explanation:

The Chinese Remainder Theorem lets us split a composite modulo into its prime components and solve for smaller numbers.

a) Using the Chinese Remainder Theorem, we have that 55 = 11 x 5

Since 11 and 5 are relatively prime numbers, we can use the Theorem and rewrite 23 x 36 mod 55 as: 23 x 36 (mod 11) and 23 x 36 (mod 5).

First we will work with 23 x 36 (mod 11)

[tex](23)(36)(mod 11) = (1)(3) (mod 11)[/tex] (Since 23 is congruent to 1 modulo 11 and 36 is congruent to 3 modulo 11)

Now we do the same with 23 x 36 (mod 5)

[tex](23)(36) (mod 5) = (3)(1) (mod5) = 3 (mod 5)[/tex]

Now we will use the Chinese Remainder Theorem to solve this pair of equations:

x = 3 (mod 11) and x = 3(mod 5)

[tex]x=5y+3\\5y+3=3(mod 11)\\5y=0(mod 11)\\y=0 (mod 11)\\y=11z\\x=5(11z)+3\\x=55z + 3\\x=3(mod 55)\\[/tex]

b) We are going to use the same procedure from a)

91 = 13 x 7

29 x 51 (mod 91) = 29 x 51 (mod 13) and 29 x 51 (mod 7)

29 x 51 (mod 13) = 3 x 12 (mod 13) = 36 (mod 13) = 10 (mod 13)

29 x 51 (mod 7) = 1 x 2 (mod 7) = 2 (mod 7)

Our pair of equations is x = 10 (mod 13) and x = 2 (mod 7)

[tex]x= 7y + 2\\7y + 2 = 10(mod13)\\7y= 8(mod13)\\y= 3 (mod 13)\\y=13y+3\\x=7(13y+3) + 2\\x=91y +21+2\\x=91y+23\\x= 23 (mod 91)[/tex]

Hey!

-------------------------------------------------

Solution:

9 + 22 = x + 1

9 + 22 - x = x + 1 - x

31 - x = 1

31 - x  31 = 31 - 1

x = 30

-------------------------------------------------

Answer:

x = 30

-------------------------------------------------

Hope This Helped! Good Luck!

Answer:

x = 30

Step-by-step explanation:

9 + 22 = x + 1

9 + 22 = 31

31 = x + 1

-1 -1

30 = x

x = 30

Answer:

[tex]y(x)=C_{1}cos2x+C_{2}sin(2x)[/tex]

Step-by-step explanation:

It is a linear homogeneous differential equation with constant coefficients:

y" + 4y = 0

Its characteristic equation:

r^2+4=0

r1=2i

r2=-2i

We use these roots in order to find the general solution:

[tex]y(x)=C_{1}cos2x+C_{2}sin(2x)[/tex]

Answer:

The probability that the European proyect is not succesfull is 0.1

Step-by-step explanation:

Since A and B are independent, A' and B' are independent too.

The probability of B' is P(B')=1-P(B) = 1 - 0.9 = 0.1

Answer:

The scale for a model that is 30 inches long is 449.2 inches.

The scale for a model that is  2 feet long is 561.5 feet.

Step-by-step explanation:

Consider the provided information.

The USS Enterprise was 1,123 feet in length.

Part (A) What is the scale for a model that is 30 inches long?

1 feet = 12 inches.

First  convert the length of USS enterprise in inches.

1×1,123 feet = 12×1,123 inches

1,123 feet = 13476 inches

Divide original length with the length of model.

The scale for the model is:

[tex]\frac{13476}{30}=449.2\ inches[/tex]

Hence, the scale for a model that is 30 inches long is 449.2 inches.

Part (B)  What is the scale for a model that is 2 feet long?

Since, both the units are in feet, so simply divide original length with the length of model.

The scale for the model is:

[tex]\frac{1123}{2}=561.5\ feet[/tex]

Hence, the scale for a model that is  2 feet long is 561.5 feet.

Answer:

It will take 0.1175 years or the number of employees at this company  to increase by 10%.

Step-by-step explanation:

We are given that the number of employees at a certain company is described by the  function [tex]P(t)= 300 (1.5)^{2t}[/tex]

Initial no. of employees = 300

Increase% = 10%

So, New no. of employees = [tex]300+\frac{10}{100} \times 300[/tex]

                                            = [tex]330[/tex]

Now we are supposed find how long does it take for the number of employees at this company to increase by 10%.

So, [tex]330= 300 (1.5)^{2t}[/tex]

[tex]\frac{330}{300}= (1.5)^{2t}[/tex]

[tex]1.1= (1.5)^{2t}[/tex]

[tex]t=0.1175[/tex]

So, it will take 0.1175 years or the number of employees at this company  to increase by 10%.

Answer:

Calculated weight of water = 10.01 g

percentage error = 0.1%

Step-by-step explanation:

Given:

Weight of graduate = 35.825 g

Weight of graduate + Water = 45.835 g

Now,

The weight of water = ( Weight of graduate + Water ) - Weight of graduate

or

The weight of water = 45.835 - 35.825

or

The weight of water = 10.01 g

Now,

The percentage of error = [tex]\frac{\textup{Calculated value - Actual value}}{\textup{Actual value}}\times100[/tex]

or

The percentage error = [tex]\frac{\textup{10.01 - 10}}{\textup{10}}\times100[/tex]

or

The percentage error = 0.1%

The weight of the water is 10.010 g, and the percentage of error from the expected 10 g is 0.1%

To calculate the weight of the water and express any deviation from 10 g as a percentage of error, follow these steps:

1. Calculate the weight of the water:

  The weight of the water can be determined by subtracting the weight of the empty graduate from the weight of the graduate with water.

[tex]\[ \text{Weight of water} = \text{Weight of graduate and water} - \text{Weight of empty graduate} \][/tex]

  Given:

  - Weight of empty graduate = 35.825 g

  - Weight of graduate with water = 45.835 g

[tex]\[ \text{Weight of water} = 45.835 \, \text{g} - 35.825 \, \text{g} = 10.010 \, \text{g} \][/tex]

2. Calculate the deviation from 10 g:

[tex]\[ \text{Deviation} = \text{Weight of water} - 10 \, \text{g} \][/tex]

3. Calculate the percentage of error:

[tex]\[ \text{Percentage of error} = \left( \frac{\text{Deviation}}{10 \, \text{g}} \right) \times 100\% \][/tex]

[tex]\[ \text{Percentage of error} = \left( \frac{0.010 \, \text{g}}{10 \, \text{g}} \right) \times 100\% = 0.1\% \][/tex]

Therefore, the weight of the water is 10.010 g, and the percentage of error from the expected 10 g is 0.1%.

Answer with Step-by-step explanation:

We are given two input A and B

A AND B=[tex]A\cdot B[/tex]

If A=0 and B=0 then [tex]A\cdot B=0[/tex]

If A=0 and B=1 then [tex]A\cdot B=0[/tex]

If A =1 and B=0 then [tex]A\cdot B=0[/tex]

If A=1 and B=1 then [tex]A\cdot B=1[/tex]

A OR B=A+B

If A=0 and B=0 then A+B=0+0=0

If A=0 and B=1 then A+B=0+1=1

If A =1 and B=0 then A+B=1+0=1

If A=1 and B=1 then A+B=1+1=1

If A=0 and B=1 or A=1 and B=0 then A AND B=0 but A OR B=1

This is the main difference A AND B and A OR B.

Answer:

(a) 498501

(b) 251001

Step-by-step explanation:

According Gauss's approach, the sum of a series is

[tex]sum=\frac{n(a_1+a_n)}{2}[/tex]         .... (1)

where, n is number of terms.

(a)

The given series is

1+2+3+4+...+998

here,

[tex]a_1=1[/tex]

[tex]a_n=998[/tex]

[tex]n=998[/tex]

Substitute [tex]a_1=1[/tex], [tex]a_n=998[/tex] and [tex]n=998[/tex] in equation (1).

[tex]sum=\frac{998(1+998)}{2}[/tex]

[tex]sum=499(999)[/tex]

[tex]sum=498501[/tex]

Therefore the sum of series is 498501.

(b)

The given series is

1+3+5+7+...+ 1001

The given series is the sum of dd natural numbers.

In 1001 natural numbers 500 are even numbers and 501 are odd number because alternative numbers are even.

[tex]a_1=1[/tex]

[tex]a_n=1001[/tex]

[tex]n=501[/tex]

Substitute [tex]a_1=1[/tex], [tex]a_n=1001[/tex] and [tex]n=501[/tex] in equation (1).

[tex]sum=\frac{501(1+1001)}{2}[/tex]

[tex]sum=\frac{501(1002)}{2}[/tex]

[tex]sum=501(501)[/tex]

[tex]sum=251001[/tex]

Therefore the sum of series is 251001.

To find the sum of the sequences using Gauss's approach, we create pairs from the sequence that each have the same sum and then multiply the number of pairs by this common sum. For 1 to 998, this results in 499 pairs each summing to 999. For 1, 3, 5, ... to 1001, there are 501 pairs each summing to 1002.

The student is asking how to find the sum of two sequences using Gauss's approach, which does not involve the use of formulas. This approach, also known as Gauss's trick, involves pairing numbers from opposite ends of a sequence and then multiplying the number of pairs by the common sum of each pair to find the total sum.

Let's illustrate this for the sequences given:

For the sequence 1, 2, 3, ..., 998, we pair the first and last numbers (1 and 998), the second and second-to-last numbers (2 and 997), and so on until we reach the middle of the list. Each pair sums up to 999. Since there are 998 numbers in total, there will be 998/2 = 499 pairs. The sum of the sequence is 499 * 999.

For the sequence 1, 3, 5, ..., 1001, we recognize that this is an arithmetic series with a common difference of 2. We can pair the first and last terms (1 and 1001) to get a sum of 1002. Since the sequence has (1001-1)/2 + 1 terms, we will have (1000/2) + 1 = 501 pairs. Thus, the sum of the sequence is 501 * 1002.

Gauss's approach to summing an arithmetic series can be visualized by considering the example of summing the first n natural numbers, which results in the formula (n² + n)/2.

Linda's total cost for college for this academic year is calculated as $12,800, encompassing both tuition and textbooks. This is part of an observed trend in increasing higher education costs.

Cost of Tuition: Linda is paying $600 per credit hour for 20 credit hours (10 each semester), so $600 * 20 = $12,000 in total for tuition.

Cost of Textbooks: She is also spending $400 per semester for textbooks, so $400 * 2 = $800 in total for textbooks.

Total Cost: Thus, Linda's total cost for the academic year would be the sum of these two costs, i.e, $12,000 + $800 = $12,800. The costs of tuition, textbooks and other expenses are part of the rising trend of higher education costs. Despite this, the value of education still remains high, as it can lead to better job prospects and higher earning potential in the future.

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Answer:

5g of norgestel are used in making 10,000 tablets.

0.5g of ethinyl estradiol are used in making 10,000 tablets.

Step-by-step explanation:

This problem can be solved as a rule of three problem.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

Unit conversion problems, like this one, is an example of a direct relationship between measures.

First step: Grams of norgestrel

Each tablet contais 0.5mg of norgestrel. How many miligrams are in 10,000 tablets?

1 tablet - 0.5 mg

10,000 tablets - x mg

x = 10,000*0.5

x = 5,000 mg

Now we have to convert 5,000 mg to g. Each g has 1,000 mg. So:

1g - 1,000 mg

xg - 5,000 mg

1,000x = 5,000

[tex]x = \frac{5,000}{1,000}[/tex]

x = 5g,

5g of norgestel are used in making 10,000 tablets.

Final step: Grams of ethinyl estradiol

50ug = 0.05 mg.

So

1 tablet - 0.05mg

10,000 tablets - xg

x = 10,000*0.05

x = 500 g

Now we have to convert 500 mg to g. Each g has 1,000 mg. So:

1g - 1,000 mg

xg - 500 mg

1,000x = 500

[tex]x = \frac{500}{1,000}[/tex]

x = 0.5g,

0.5g of ethinyl estradiol are used in making 10,000 tablets.

Answer:

[tex]\text{Customer that bought only one paper}=33[/tex]

[tex]\text{Customer that bought something other than either of the two papers}=7[/tex]

Step-by-step explanation:

We have been given that at a newsstand, out of 46 customers, 27 bought the Daily News, 18 bought the Tribune, and 6 bought both papers.

[tex]\text{Customer that bought only Daily news}=27-6[/tex]

[tex]\text{Customer that bought only Daily news}=21[/tex]

[tex]\text{Customer that bought only Tribune}=18-6[/tex]

[tex]\text{Customer that bought only Tribune}=12[/tex]

The customer that bought only one paper would be the sum of customers, who bought only Daily news or Tribune.

[tex]\text{Customer that bought only one paper}=21+12[/tex]

[tex]\text{Customer that bought only one paper}=33[/tex]

Therefore, 33 customers bought only one paper.

[tex]\text{Customer that bought something other than either of the two papers}=46-(27+18-6)[/tex]

[tex]\text{Customer that bought something other than either of the two papers}=46-(45-6)[/tex]

[tex]\text{Customer that bought something other than either of the two papers}=46-39[/tex]

[tex]\text{Customer that bought something other than either of the two papers}=7[/tex]

Therefore, 7 customers bought something other than either of the two papers.

Answer: 2014

Step-by-step explanation:

LED: -25x + 6y = 20

CFL: 15x + 2y = 322

we need to find which year it was the same to know where LED lighting surpassed  CFL lighting

-25x + 6y = 20

15x + 2y = 322 (-3)

-25x + 6y = 20

-45x - 6y = -966    

-70x = -946

x = 13.51

The nearest year would be 14 which is 2014

By solving the system of equations, we find that the interest in ED lighting surpassed CFL lighting around the year 2014.

To find out when the interest in ED lighting surpassed CFL lighting, we'll need to solve the system of equations given by:

LED: -25x + 6y = 20
CFL: 15x + 2y = 322

We can use substitution or elimination methods to solve this system of equations. For the elimination method, multiply the first equation by 2 and the second equation by 6 to make the y-coefficients equal:

-50x + 12y = 40
90x + 12y = 1932

Now, subtract the first equation from the second:

140x = 1892. Hence, x = 1892/140 = 13.51

So, the interest in ED lighting surpassed CFL lighting in the year 2013.51. Since we round to the nearest year, we can say that this happened around the year 2014.

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Answer:

  3.  about 7.48 hours

  4.  about 1.8892 hours

Step-by-step explanation:

Both of these questions make use of the relation ...

  time = distance / speed

3. time = (965 mi)/(129 mi/h) ≈ 7.48062 h ≈ 7.48 h

__

4. time = (612.1 mi)/(324 mi/h) ≈ 1.889198 h ≈ 1.8892 h

(We have rounded the time to sufficient precision so that the distance at the given speed rounds to the number given.)

Answer:

C. 800

Step-by-step explanation:

[tex]\sqrt{100} =10; \ \sqrt{400}=20; \ \sqrt{144}=12; \ \sqrt{800}=28.284271247461900976033774484194.[/tex]

Answer:

a) injective but not surjective. b) neither injective nor surjective.

Step-by-step explanation:

A function is injective if there aren't repeated images. To check if a function is injective we are going to suppose that for two values in the domain the image is equal, then we need to find that the two values are equal.

a) f : N → N with f(n) = n+2.

suppose that for n and m natural numbers, f(n)=f(m). Then

n+2 = m+2

n+2-2 = m

n = m.

Then, f(n) is injective.

Now, a function is surjective if every term m in the codomain there exists a pre-image of that element, that is to say, there exists an n such that f(n) = m. That is, the range of the function is equal to the codomain.

In this case, f(n) is not surjective. For example, if we would have that

n+2 = 1

n = 1-2

n = -1

but -1 is not a natural number, then for m=1 we don't have a pre image in f.

b) f: P({1, 2, 3}) → N with f(A) = |A|  (amount of elements in the subset A).

Now, for {1,2,3} we can have subsets of 0, 1, 2 or 3 elements. Then, the range of the function f is {1, 2, 3} (0 is not included because 0 is not natural). Then, the range is not all the natural numbers and therefore the function is not surjective.

Now, let's check if f is injective. Let {1} and {2} subsets of {1, 2, 3}. Then

f({1}) = |{1}| = 1.

f ({2}) = |{2}| = 1.

We have two different subsets with the same image, then f is not injective.