Answer:
the answer is letter d
Polyatomic ions are named similarly to monatomic ions in ionic compounds. No changes are made to the ending of the polyatomic ion. The name of the compound is formed by combining the cation and the anion.
Explanation:Compounds containing polyatomic ions are named similarly to those containing only monatomic ions, except there is no need to change to an -ide ending, since the suffix is already present in the name of the anion. For example, if we have the compound NaNO3, it is named as sodium nitrate. Similarly, CaCO3 is named as calcium carbonate, and NH4Cl is named as ammonium chloride.
In ionic compounds, polyatomic ions are named similarly to monatomic ions. The ending of the polyatomic ion remains unchanged. The name of the compound is formed by combining the cation and the anion.
For example, in the compound sodium nitrate (NaNO3), the polyatomic ion is nitrate (NO3-). The name of the compound is formed by combining the cation (sodium, Na+) and the anion (nitrate, NO3-).
Similarly, in calcium carbonate (CaCO3), the polyatomic ion is carbonate (CO3^2-). The name of the compound is formed by combining the cation (calcium, Ca^2+) and the anion (carbonate, CO3^2-).
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3.4000*10^-6 + 5.7000*10^-3
Answer:
0.0057034 or 5.7034 * 10^-3
HELPPPPPPPPPPPPPPPPPPPP MEEEEEEEEEEEEEEEE PLZZZZZ WITHHHHH SCIENCE 13. Evaluate: What type of bonding does a material most likely have if it has a high melting point, is solid at room temperature, and easily dissolves in water?
14. Explain the following statement: All compounds are substances, but not all substances are compounds.
15. Suppose you have a found an unknown substance in a laboratory. It has the formula H2O2 written on the bottle. Is it water? How do you know?
13 An Ionic Bond
these are the characteristics of an ionic bond compounds like NaCl have these characteristics
14 substances could be compounds or elements hence not all substances are compounds
15 It is not water. The chemical composition of water is H2O not H202
(H202 is hydrogen peroxide and is toxic)
AgNO3(aq)+Na3PO4(aq) ionic equation
Answer:
3Ag⁺ + 3NO₃⁻ + 3Na⁺ + PO₄³⁻ → Ag₃PO₄(s) + 3Na⁺ + 3NO₃⁻
Explanation:
An ionic equation is a chemical equation where the electrolytes in aqueous solution are expressed as dissociated ions.
For the reaction:
3AgNO₃(aq) + Na₃PO₄(aq) → Ag₃PO₄(s) + 3 NaNO₃(aq)
AgNO₃(aq), Na₃PO₄(aq) and NaNO₃(aq) are dissociated in water thus:
AgNO₃(aq) → Ag⁺ + NO₃⁻
Na₃PO₄(aq) → 3Na⁺ + PO₄³⁻
NaNO₃(aq) → Na⁺ + NO₃⁻
The ionic equation is:
3Ag⁺ + 3NO₃⁻ + 3Na⁺ + PO₄³⁻ → Ag₃PO₄(s) + 3Na⁺ + 3NO₃⁻
I hope it helps!
How are precipitation and temperature different between the polar and tropical climate zones? Explain.
Answer:
Earth has tremendous diversity of its ecosystems. Different regions are referred to as climate biomes to understand patterns of weather, biology, and natural events.
Explanation:
The greatest difference between tropical and polar climates is the difference in temperature. Tropical climates are located near the Equator and receive more sun year-round than anywhere else on Earth, while polar climates are the farthest from the Equator and receive the least sunlight and heat of any part of the globe. This makes the winters of polar climates fierce and the summers short, while practically every day in a tropical climate is hot. While both climates might bring to mind precipitation (such as rain in the tropics and snow at the poles), both can also be quite dry. Antarctica is considered the largest desert in the world, since almost no snow falls toward the center of the continent. Tropical deserts, such as the Namib of Africa, are extremely hot and dry, making it difficult for any life to survive.
Answer: In the polar climate zone, it is very cold and dry, receiving less precipitation every year. The tropical climate zone has very warm and hot temperatures all year round, receiving much rain.
Explanation: I read the lesson and it makes sense
2.00 L of nitrogen gas at a temperature of 210 K are cooled down until the new volume is 1.25 L. If the pressure and number of gas particles do not change, to what temperature was the gas cooled?
131 K
1.19 x 10-2 K
7.62 x 10-3 K
336 K
Please answer ASAP!!
Answer:
131 K
Explanation:
The only variables are volume and temperature, so we can use Charles' Law:
V1/T1 = V2/T2
Data:
V1 = 2.00 L; T1 = 210 K
V2 = 1.25 L; T2 = ?
Calculation:
2.00/210 = 1.25/T2
Multiply each side by the lowest common denominator (210T2)
2.00T2 = 1.25 ×210
2.00T2 = 262.5
T2 = 262.5/2.00 = 131 K
The gas was cooled to 131 K.
What is the molar mass of potassium oxide, K2O?
A. 47.0 g
B. 110.0 g
C. 94.0 g
D. 55.0 g
Answer:
The molar mass of potassium oxide, aka K20 would be option C. 94.0g
Explanation:
The molar mass of potassium oxide (K₂O) is 94.20 g/mol, matching option C (94.0 g).
To find the molar mass of potassium oxide (K₂O), we need to sum the molar masses of the constituent elements.
The atomic mass of Potassium (K) is 39.10 g/mol.Since there are 2 potassium atoms in K₂O, the total mass for potassium is 2 × 39.10 g/mol = 78.20 g/mol.The atomic mass of oxygen (O) is 16.00 g/mol. Summing these values yields: 78.20 g/mol + 16.00 g/mol = 94.20 g/mol.Therefore, the molar mass of potassium oxide (K₂O) is 94.20 g/mol, which is closest to option C (94.0 g).
Using the conversion factor convert 1.56 ng NH3 to moles.
Answer:
9.02×10⁻¹¹ mol NH₃
Explanation:
Convert nanograms to grams:
1.56 ng NH₃ × (1 g / 10⁹ ng) = 1.56×10⁻⁹ g NH₃
Convert grams to moles:
1.56×10⁻⁹ g NH₃ × (1 mol NH₃ / 17.3 g NH₃) = 9.02×10⁻¹¹ mol NH₃
The answer is 9.02×10⁻¹¹ mol NH₃
How to convert grams to moles?Convert nanograms to grams:
1.56 ng NH₃ × (1 g / 10⁹ ng) = 1.56×10⁻⁹ g NH₃
Convert grams to moles:
1.56×10⁻⁹ g NH₃ × (1 mol NH₃ / 17.3 g NH₃) = 9.02×10⁻¹¹ mol NH₃
A mass of a substance in grams is numerically equal to its molecular weight. Example: A gram-mole of salt (NaCl) is 58.44 grams.
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How can one tell how much of each reactant will be used in a reaction?
A. The coefficients tell the ratio of grams of reactants used in the reaction
B. The molar masses of the molecules tell how many moles of each reactant are used
C. The molar masses of the molecules tell how many grams of each reactant are used
D. The coefficients tell the ratio of moles of reactants used in the reaction
Answer:
D. The coefficients tell the ratio of moles of reactants used in the reaction
Explanation:
The molar ratio is central to all stoichiometric calculations.
To get the mass of Compound B that reacts with compound A, you must
Convert the mass of A to moles Use the molar ratio from the balanced equation to find the moles of B Convert moles of B to grams.You must get over the "mole hill."
A nanotechnology equipment requires 7.40 x 10^18 atoms of potassium. What is the mass of this sample?
Answer:
4.81×10⁻⁴ g K
Explanation:
Convert atoms to moles:
7.40×10¹⁸ atoms K × (1 mol K / 6.02×10²³ atoms) = 1.23×10⁻⁵ mol K
Convert moles to mass:
1.23×10⁻⁵ mol K × (39.1 g K / mol K) = 4.81×10⁻⁴ g K
3. What do we call atoms of the same elements with different mass numbers?
Answer:
Isotopes
Explanation:
We call atoms of the same elements with different mass numbers isotopes.
A chemical factory is making soda ash (NA2CO3) from sodium bicarbonate. The production manager calculates they will make 80 tons of soda ash in the next 8 hour shift. At the end of the shift they weigh the produced soda ash at 74.3 tons. What was their percent yield?
Answer:
[tex]\boxed{\text{ 93 \%}}[/tex]
Explanation:
[tex]\text{\% yield} = \dfrac{\text{actual yield}}{\text {theoretical yield}} \times\text{100 \%}[/tex]
Data:
[tex]\begin{array}{rcr}\text{Actual yield} & = & \text{74.3 T}\\\text{Theoretical yield} & = & \text{80 T}\\\end{array}[/tex]
Calculation:
[tex]\text{\% yield} = \dfrac{\text{74.3 T}}{\text {80 T}} \times\text{100 \%} = \textbf{93 \%}}\\\\\text{The percent yield was } \boxed{\textbf{93 \%}}[/tex]
Which substance is less soluble in hot water than in cold water?
A KBr
B NaNO3
C CO2
D Naci
Answer:
CO2
Explanation:
it is a gas and solubable in colder weather/temperature
The solubility of CO2 is lesser at higher temperature than it is at a lower temprature.
Solubility of a gasThe solubility of a gas in water is an exothermic process. This implies that the higher the temperature, the lower the solubility of the gas.
As such, we know that CO2 is the only gas in the list hence the solubility of CO2 is lesser at higher temperature than it is at a lower temprature.
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Radiocarbon dating can be used to determine the age of
A a sample less than a million years old
B a sample less than 100,000 years old
C a sample less than 50,000 years old
- D a sample less than five million years old
Answer:
Radiocarbon dating can be used to determine the age of a sample less than 50,000 years old - C
What is the classification for this reaction?
SO 3 + H20 - H250 4
Why does magnesium oxide have a high melting point?
Please give as much information as possible?
Magnesium oxide is an ionic compound ( because it consists of a metal and a non-metal)
In ionic compounds, electrons from the outer shell exchange between the atoms so that they each get a full outer shell. Once these electrons are exchange, the atoms will become ions. One ion will have a positive charge, and the other ion will have a negative charge. The positive and negative ions then bond strongly together in a lattice structure, due to the electrostatic forces of attraction.
These electrostatic forces of attraction are very strong and require a lot of energy to break, as such the compound will have a high melting point.
__________________________________________
Now lets look at the ionic bonding between magnesium and oxygen:
In the outer shell of Magnesium, there are 2 electrons.
In the outer shell Oxygen, there are 6 electrons.
Magnesium gives it's two electrons to Oxygen, so that the Oxygen now has a full outer shell of 8 electrons. However, since Oxygen gained two electrons, it will form a negatively charged ion with a charge of -2.
Since Magnesium lost the two electrons, it's second shell (which has 8 eletrons) now becomes the outer shell. So Magnesium also now has a full outer shell. But since it has lost two electrons, it becomes a positively charged ion with a charge of + 2.
The positive Magnesium ion and negative Oxygen ion and now strongly attracted to each other, and form a strong ionic compound (magnesium oxide) with a lattice structure.
The electrostatic forces of attraction between the positive Magnesium and negative Oxygen are so strong that a lot of heat and energy are needed to break them.
Therefore magnesium oxide has a high melting point.
3. Sodium carbonate (Na2CO3) is formed from the reaction between
O A a weak acid and a strong base
B a strong acid and a strong base
C a strong acid and a weak base
OD a weak acid and a weak base
Na2C03 is formed through the reaction of
NaOH and H2CO3 namely sodium hydroxide and carbonic acid
NaOH -> strong base
H2CO3-> weak acid
Answer:
A. a weak acid and a strong base
Explanation:
An acid-base reaction is a chemical reaction between an acid and a base to form salt and water. The reaction is also known as a neutralization reaction.
An acid is a compound that when in aqueous solution it dissociate to form an hydrogen ion(H+).
A base is a compound that when in aqueous solution it produces an hydroxide ion(OH-) .
A strong acid is an acid that completely dissociate in an aqueous solution.
A strong base is a base that completely dissociate in an aqueous solution.
The reaction that produce a salt like sodium carbonate is a chemical reaction between a weak acid and a strong base. The chemical reaction can be represented as follows
H2CO3 + 2NaOH → Na2CO3 + 2H2O
H2CO3 is a weak acid as it partially dissociate in aqueous solution.
NaOH is a strong base as it completely dissociate in aqueous solution.
5. Assuming the temperature is held constant, how could you increase the pressure inside a
container by a factor of 37
Answer:
Decrease the volume or increase the number of moles by a factor of 37.
Explanation:
If the contents are a gas,
pV = nRT
If T is constant
[tex]p \propto \dfrac{n}{V}[/tex]
There are two ways to increase the pressure inside the container.
1. Decrease the volume
If you decrease the volume by a factor of 37, the pressure will increase by the same factor.
2 Increase the number of moles
If you add 36 times the number of moles, you will have 37n moles. Increasing the amount of gas by a factor of 37 increases the pressure by the same factor.
To increase the pressure inside a container by a factor of 37 while keeping the temperature constant, the volume of the gas must be reduced to 1/37th of its original volume, as per Boyle's Law, which states that pressure and volume are inversely proportional.
Assuming the temperature is held constant, to increase the pressure inside a container by a factor of 37, you must reduce the volume of the gas. This is based on Boyle's Law, which states that, for a given mass of gas at constant temperature, the pressure of the gas is inversely proportional to its volume. This means if you want to increase the pressure inside the container, you have to decrease the volume of the container correspondingly.
For instance, if the original pressure of the gas is P, and the volume is V, to increase the pressure by a factor of 37 (making it 37P), you would need to reduce the original volume (V) to V/37. This is because P1*V1 = P2*V2, where P1 and V1 are the initial conditions and P2 and V2 are the final conditions, assuming no change in the amount or temperature of the gas.
Calculate q, the heat released in each reaction.
Use the equation q = cmåt.
(Use c = 4.18 J/g.°C and the total mass, m.)
Record to 2 significant figures.
Reaction 1:
Reaction 2:
RETRY
Answer:
its write for the first person who did it
Explanation:
Answer:
Reaction 1: 3700
Reaction 2: 3200
pt 2
Reaction 1: 0.00823
Reaction 2: 0.00397
pt 3
reaction 1: -450
reaction2: -81
Explanation:
How did Bohr propose the particles within atom are arranged
A. Protons and electrons form the nucleus with neutrons orbiting it
B. Protons make up the atoms nucleus with electrons and neurons orbiting it
C. Protons and neutrons from the nucleus of the atom with electrons orbiting it
D. Neutrons make up the atoms nucleus with electrons and protons orbiting it
Answer:
Protons and neutrons form the nucleus of the atom with electrons orbiting it.- C.
The correct answer is C. Protons and neutrons form the nucleus of the atom with electrons orbiting it
Explanation:
Bohr model was proposed by Niels Bohr in 1913 to explain the structure of atoms, in this Bohr stated electrons (particles negatively charge) orbit the nucleus that contains both neutrons (neutral particles) and protons (positively charged particles). Additionally, according to this model electrons were placed in different levels of energy and orbit the nucleus constantly, resembling planets in the Solar System, although the Bohr model was the first one that integrated principles related to energy levels and changes in energy in electrons. Thus, Bohr proposed "Protons and neutrons form the nucleus of the atom with electrons orbiting it".
A sample of helium has a temperature of 450 K. The gas is cooled to 248.9 K at which time the gas occupies 103.4 L? Assume pressure is constant at 3 atm. What was the original volume of the gas
Answer:
[tex]\boxed{\text{163.3 L}}[/tex]
Explanation:
The pressure is constant, so, to calculate the volume, we can use Charles' Law:
\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}
Data:
V₁ = ?; T₁ = 450 K
V₂ = 103.4 L; T₂ = 284.9 K
Calculation:
[tex]\dfrac{ V_{1}}{450} = \dfrac{ 103.4}{284.9}\\\\{ V_{1}} = 450 \times \dfrac{103.4}{284.9}\\\\ = \textbf{163.3 L}\\\text{The original volume of the helium was $\boxed{\textbf{163.3 L}}$}[/tex]
The original volume of the gas is 186.94 Liters
Further Explanation;
Charles' Law Charles's law states that the volume of a fixed mass of a gas is directly proportional to absolute temperature at constant pressure.That is;[tex]V\alpha T[/tex]
[tex]P=kT[/tex], where k is a constant
At different temperatures and pressure then;
[tex]\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }[/tex]
In the Question;
We are given
[tex]V_{1} = ?\\T_{1} = 450\\V_{2} = 103.4 l\\T_{2} =248.9K[/tex]
Therefore;
[tex]V_{1} =\frac{V_{2} T_{1} }{T_{2} }[/tex]
[tex]V_{1} =\frac{(103.4 L)(450 K)}{(248.9K)}[/tex]
[tex]V_{1} = 186.94Liters[/tex]
Other Gas laws Boyle's law Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at a constant temperature.That is;
[tex]P\alpha \frac{1}{V}[/tex]
[tex]P\alpha \frac{k}{V}[/tex], where k is a constant
Combined gas lawCombined gas law combines both Boyle's law and Charles's law.It states that the volume of a fixed mass of a gas is directly proportional to absolute temperature and inversely proportional to pressure.That is;[tex]\frac{P_{1}V_{1} }{T_{1} } = \frac{P_{2}V_{2} }{T_{2} }[/tex]
Pressure LawPressure Law states that the pressure occupied by a gas is directly proportional to absolute temperature.
Keywords: Combined gas laws, Boyle's law and Charles's law
Learn more about:Boyles’s law: brainly.com/question/1158880Gay-Lussac’s law: brainly.com/question/2438000Charles’s law:brainly.com/question/2438000Combined gas law: brainly.com/question/2441061Level: High school
Subject: Chemistry
Topic: Gas laws
Sub-topic: Charles's law
Classify each of the following chemical reactions.
S+02 → SOZ
CaCl2 + 2AgNO3 → Ca(NO3)2 + 2AgC1
Zn+CuSO4 → Cu+ ZnSO4
2Na2O → 4Na+02
The chemical reaction has been the formation of product with the reaction of reactants. The chemical reaction has been differentiated as synthesis, decomposition, replacement reaction.
Types of Chemical reactionThe following reaction has been classified as:
[tex]\rm S+O_2\;\rightarrow SO_2[/tex]The reaction has been following the synthesis of the product with a mixture of reactants. Thus, it has been given as the synthesis reaction.
[tex]\rm CaCl_2+2\;AgNO_3\;\rightarrow Ca(NO_3)_2\;+\;2\;AgCl[/tex]There has been replacement of Ca by Ag in calcium chloride and replacement of Ag by Ca in silver nitrate. There has been two replacement. Thus, the reaction has been a double replacement reaction.
[tex]\rm Zn\;+\;CuSO_4\;\rightarrow\;Cu\;+\;ZnSO_4[/tex]The reaction has replacement of Cu by Zn in copper sulfate. It has been a single replacement, thus the reaction has been a single replacement reaction.
[tex]\rm 2\;Na_2O\;\rightarrow\;4\;Na\;+\;O_2[/tex]There has breakdown of the compound for the formation of product. Thus, the reaction has been a decomposition reaction.
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Answer:
synthesis and combustion
double replacement
single replacement
decomposition only
Explanation:
in that order, i got it correct
A 35.40 gram hydrate of sodium carbonate, Na2CO3•nH2O, is heated to a constant mass. Its final weight is 30.2 g. What is formula for the hydrate?
Answer:
Na₂CO₃•H₂O
Explanation:
After it is heated, the remaining mass is the mass of sodium carbonate.
30.2 g Na₂CO₃
Mass is conserved, so the difference is the mass of the water:
35.4 g − 30.2 g = 5.2 g H₂O
Convert masses to moles:
30.2 g Na₂CO₃ × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 0.285 mol Na₂CO₃
5.2 g H₂O × (1 mol H₂O / 18.0 g H₂O) = 0.289 mol H₂O
Normalize by dividing by the smallest:
0.285 / 0.285 = 1.00 mol Na₂CO₃
0.289 / 0.285 = 1.01 mol H₂O
The ratio is approximately 1:1. So the formula of the hydrate is Na₂CO₃•H₂O.
Na₂CO₃•H₂O
Further explanationGiven:
A 35.40 g hydrate of sodium carbonate, Na₂CO₃•nH₂O, is heated to a constant mass.Its final weight is 30.2 g.Question:
What is the formula for the hydrate?
Problem-solving:
We will solve problems related to The Law of Definite Proportion (Proust's Law).
"The ratio of the masses of elements in each compound is always constant. Put differently, a given compound invariably contains a similar proportion of elements by mass."
The heating reaction of the hydrate of sodium carbonate is as follows:
[tex]\boxed{ \ Na_2CO_3.nH_2O \xrightarrow{\text{heat}} Na_2CO_3 + nH_2O \ }[/tex]
Condition:
Before heating: 35.40 g of Na₂CO₃•nH₂O (hydrate)After heating: 30.20 g of Na₂CO₃ (anhydrate)The mass of H₂O that has left the compound is [tex]\boxed{ \ 35.40 - 30.20 = 5.2 \ g \ }[/tex][tex]\boxed{ \ Na_2CO_3.nH_2O \xrightarrow{\text{heat}} Na_2CO_3 + nH_2O \ }[/tex]
35.4 g 30.2 g 5.2 g
We want to determine the amount of water (with the symbol n) so that the formula for the hydrate can be known.
Recall that [tex]\boxed{ \ Moles = \frac{Mass \ (g)}{Mr} \ }[/tex]
Let us prepare the number of moles of Na₂CO₃ and H₂O respectively.
Mr Na₂CO₃ = 106 g/mol ⇒ [tex]\boxed{ \ moles = \frac{30.2}{106} \rightarrow \boxed{ \ 0.285 \ } \ }[/tex] Mr H₂O = 18 g/mol ⇒ [tex]\boxed{ \ moles = \frac{5.2}{18} \rightarrow \boxed{ \ 0.289 \ }\ }[/tex]Finally, we use the mole ratio to write the formula. Find the water-to-anhydrate mole ratio.
[tex]\boxed{ \ Na_2CO_3 \ : \ H_2O = 1 \ : \ n \ }[/tex]
[tex]\boxed{ \ H_2O \ : \ Na_2CO_3 = n \ : \ 1 \ }[/tex]
[tex]\boxed{ \ n \ : \ 1 = 0.289 \ : \ 0.285 \ }[/tex]
[tex]\boxed{ \ n = \frac{0.289}{0.285} \times 1 \ }[/tex]
Thus, the value of n after rounding is [tex]\boxed{ \ n = 1 \ }[/tex]
Substitute n = 1 into Na₂CO₃•nH₂O.
Therefore, the formula for the hydrate is [tex]\boxed{\boxed{ \ Na_2CO_3.H_2O \ }} [/tex]
Learn moreThe law of multiple proportions (Dalton’s law) https://brainly.com/question/10590259 Conservation of mass https://brainly.com/question/9473007The chemical formula of a compound https://brainly.com/question/834909Keywords: 35.40 gram, hydrate of sodium carbonate, Na₂CO₃•nH₂O, heating, a constant mass, its final weight, 30.2 g, what is the formula for the hydrate? the law of definite proportion, Proust's law, anhydrate, the mole ratio
Consider the following reversible reaction.
CO(g) + 2H2(g)
CH3OH(g)
What is the equilibrium constant expression for the given system?
A.Keg = [CO][H2]2
[CH3OH)
B.Keg = (СН3ОН)(CO)(H2)2
C.Keg=
[CO][H2]
[CH3OH]
D.Keg= [Ch3OH] [CO][H2]
Answer:
Explanation:
For any system in equilibrium, the molar concentration of all the species on the reactant side are related to those on the product side by a constant known as the equilibrium constant [tex]K_{eq}[/tex].
For a given reaction:
aA + bB ⇄ cC
[tex]K_{eq}[/tex] = [tex]\frac{[C]^{c} }{[A]^{a} [B]^{b} }[/tex]
The reaction equation is given as:
[tex]CO_{g}[/tex] + 2H₂[tex]_{g}[/tex] ⇆CH₃OH [tex]_{g}[/tex]
Note: All the species are in gaseous phase.
[tex]K_{eq}[/tex] = [tex]\frac{[CH_{3}OH ]}{[CO] [H_{2}] }[/tex]
Answer: [tex]K_c=\frac{[CH_3OH]{[CO][H_2]^2}[/tex]
Explanation:
Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. It is expressed as [tex]K_{eq}[/tex]
[tex]CO(g)+2H_2(g)\rightarrow CH_3OH(g)[/tex]
The equilibrium constant in terms of concentration is written as :
[tex]K_eq=\frac{[CH_3OH]{[CO][H_2]^2}[/tex]
Thus the correct answer choice is B.
What happens when a gas becomes ionized?
A. Deposition Occurs
B. Sublimation Occurs
C. It becomes a liquid
D. A plasma is formed
Answer:
A. Deposition Occurs
Explanation:
When a gas becomes ionized, deposition occurs.
Answer: Option (D) is the correct answer.
Explanation:
A plasma is defined as the state of matter in which gas exists in hot ionized formed that has similar number of positively charged ions and negatively charged electrons.
Whereas deposition is the change from gaseous to liquid or solid state in which particles come closer to each other.
Sublimation means direct conversion of solid into gaseous phase without undergoing liquid phase.
Thus, we can conclude that when a gas becomes ionized then a plasma is formed.
6. How to calculate the mass of copper that can be plated out of a 1.0 M Cu(NO3)2 solution using a current of 0.75 A for 5.0 minutes?
Answer:
Approximately 0.074 grams.
Explanation:
Look up the relative atomic mass of copper on a modern periodic table: [tex]\rm 63.546[/tex]. Look up the Faraday's Constant: [tex]F \approx \rm 96485.33212\;C\cdot mol^{-1}[/tex]. This constant gives the amount of electrical charge on each mole of electrons.How does the electroplating works for copper? Copper exists as copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] in the copper(II) nitrate [tex]\rm Cu{(NO_3)}_2[/tex] solution. It takes two moles of electrons to reduce one mole of copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] to metallic copper [tex]\rm Cu[/tex].
[tex]\rm Cu^{2+}\;(aq) + 2\;e^{-} \to Cu\;(s)[/tex]. (Reduction half of the ionic equation.)
What are the steps for finding the mass of copper that has been deposited.Start by finding the charge on the electrons that have been supplied to this electrochemical cell. After that,
Find the number of moles of electrons that have been supplied based on the charge supplied; Find the number of moles of copper that have been reduced based on the number of moles of electrons supplied; andFind the mass of copper based on the number of moles of copper atoms reduced.What's the charge [tex]Q[/tex] on the electrons supplied to this electrochemical cell?For a constant direct current [tex]I[/tex], the charge [tex]Q[/tex] that has been delivered in time [tex]t[/tex] is equal to
[tex]Q = I \cdot t[/tex].
In case
[tex]I[/tex] is in Amperes [tex]\mathrm{A}[/tex] and[tex]t[/tex] is in seconds [tex]\mathrm{s}[/tex],[tex]Q[/tex] will be in Coulombs [tex]\mathrm{C}[/tex] (which is the same as [tex]\mathrm{A\cdot s}[/tex].)
For this electrochemical cell,
[tex]Q = I\cdot t = \rm 0.75\;A \times 300\;s = 225\;C[/tex].
How many moles of electrons were supplied to this electrochemical cell?The Faraday's Constant gives the size of charge (in Coulombs) on one mole of electrons.
[tex]F \approx \rm 96485.33212\;C\cdot mol^{-1}[/tex].
[tex]\displaystyle n(\mathrm{e^{-}}) = \frac{Q}{F} = \rm \frac{225\;C}{96485.33212\;C\cdot mol^{-1}}\approx 0.00233196\;mol[/tex].
How many moles of copper atoms have been deposited?Assume that copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] are in excess. Refer to the reduction half-equation, it takes two moles of electrons to deposit one mole of metallic copper.
[tex]\displaystyle \frac{n(\mathrm{Cu})}{n(\mathrm{e^{-}})} = \frac{1}{2}[/tex].
[tex]n(\mathrm{e^{-}})=\rm 0.00233196\;mol[/tex]. As a result,
[tex]\displaystyle n(\mathrm{Cu}) = n(\mathrm{e^{-}})\cdot \frac{n(\mathrm{Cu})}{n(\mathrm{e^{-}})} = \rm 0.00233196\;mol\times \frac{1}{2} = 0.00116598\; mol[/tex].
What's the mass of that many copper atoms?The Relative atomic mass of copper is [tex]63.546[/tex].
[tex]\begin{aligned}m(\mathrm{Cu})& = n(\mathrm{Cu}) \cdot M(\mathrm{Cu})\\& = \rm 0.00116598\; mol\times 63.546\; g\cdot mol^{-1}\\&\rm \approx 0.074\;g\end{aligned}[/tex].
Final answer:
The mass of copper that can be plated from a 1.0 M Cu(NO3)2 solution using 0.75 A for 5 minutes is calculated by converting the charge passed to moles of electrons, determining the moles of copper, and then converting it to mass, resulting in approximately 0.0740 grams.
Explanation:
To calculate the mass of copper that can be plated out of a 1.0 M Cu(NO3)2 solution using a current of 0.75 A for 5.0 minutes, we apply Faraday's laws of electrolysis and use the molar mass of copper.
Firstly, calculate the total charge passed through the solution using the formula Q = It, where Q is the charge in Coulombs, I is the current in Amperes, and t is the time in seconds. For 0.75 A over 5.0 minutes (or 300 seconds), we obtain Q = (0.75 A) × (300 s) = 225 Coulombs.
Next, convert the charge to moles of electrons using the charge of one mole of electrons, known as Faraday's constant (approximately 96485 C/mol). Thus, moles of electrons = 225 C / 96485 C/mol ≈ 0.00233 mol.
Since the copper plating involves Cu2+ ions gaining two electrons to become copper atoms (Cu2+ + 2e− → Cu), the moles of copper plated will be half the moles of electrons. So, 0.00233 mol / 2 = 0.001165 mol of copper.
Finally, calculate the mass of copper by multiplying the moles of copper by its molar mass (63.55 g/mol for Cu). Thus, mass of copper = 0.001165 mol × 63.55 g/mol ≈ 0.0740 g.
Therefore, the mass of copper that can be plated out using these conditions is approximately 0.0740 grams.
An insulated container that measures temperature change is a _______. It is used to calculate change in _________ (which is DH.)
the D is a triangle
Answer:
An insulated container that measures temperature change is a calorimeter. It is used to calculate change in enthalpy (which is ΔH.)
Explanation:
Enthalpy characterize a system from the energy point of view and it depends on the changes in the temperature of the system, the pressure (which is held constant) and the volume of the system (you know this because is an isolated system. Using a calorimeter is a key step in calculating the enthalpy, let's say for a chemical reaction.
that equal volumes of gas under the same conditions have equal numbers of molecules. This concept is a very important one, as it will be used often in future studies.
Answer:
This one is easy. It's the Avogadros' Hypothesis or Avogadros' Law, where the equal volumes of gases in SAME conditions have an equal amount of molecules!
Answer:
Avagadro’s law states at constant temperature and pressure, volume is directly proportional to the number of molecules of the gas.
For example
At STP that is standard temperature and pressure at which T = 273K and P = 1 atm
Volume occupied by 1 mole ([tex]6.022\times 10^{23}[/tex] gas molecules) of any gas is equal to 22.4L
That is
1 mole = 22.4L
2 mole = 44.8 L
3 mole = 67.2 L
So 1 mole of [tex]CO_2[/tex] gas =22.4L ([tex]6.022\times 10^{23}[/tex] gas molecules)
1 mole of [tex]H_2[/tex] gas =22.4L ([tex]6.022\times 10^{23}[/tex] gas molecules)
1 mole of [tex]Cl_2[/tex] gas =22.4L ([tex]6.022\times 10^{23}[/tex] gas molecules)
The ideal gas constant, R has several different values that could be used. Which quantity causes these differences?
pressure
temperature
volume
moles
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Answer:
[tex]\boxed{\text{Pressure and volume}}[/tex]
Explanation:
The measure of R is always the same, but the numbers may differ depending on the units you use.
For example, in SI units, R = 8.314 Pa·m³K⁻¹mol
If your measurement uses different units, you must either convert your units to SI or use a value of R consistent with your units.
If you use bars and litres, R = 0.083 14 bar·L·K⁻¹mol⁻¹.
If you use kilopascals and litres, R = 8.314 kPa·L·K⁻¹mol
If you use atmospheres and litres, R = 0.082 06 L·atm·K⁻¹mol⁻¹.
If you use Torr and cubic centimetres, R = 62 368 Torr·cm³ K⁻¹mol⁻¹.
The only units that don't change are "K⁻¹mol⁻¹".
[tex]\text{The quantities that affect the value of R are }\boxed{\textbf{pressure and volume}}[/tex]
why is specific heat capacity more useful then heat capacity when comparing two materials
Answer:
Explanation:
Specific heat capacity can be defined as the heat required to raise the temperature of a unit mass of a substance by 1kelvin.
The heat capacity on the other hand, expresses the heat required to raise the temperature of asubstance by 1kelvin.
When we use specific heat capacity, we are particular about the amount of heat that would be needed to actually cause a temperature change in a unit of a substance. This suggests that even if we don't have a complete substance, we can be sure that by knowing the mass of a unit of a body one can easily estimate how much heat is required to raise its temperature. The specific heat is fundamental in calculating the heat capacity of a body. Without the value of the specific heat, we cannot evalutate the heat capacity of a body.
A meteorologist wants to create a visual aid different gases in earths atmosphere which type of chart or graph would best convey the data
Answer:
A pie chart
Explanation:
A pie chart would be the ideal type of chart to create this visual aid. A pie chart is simpler visually and easily understood. It can show data as portions or percentages of a whole. Since what they want is to present the different gases found in Earth's atmosphere, they can show what percentage of the different gases make up the atmosphere.
It is simpler because the size of each portion or "slice" of the pie chart itself can reveal a lot about the data without even reading the numbers.
Answer:
Pie chart
Explanation: