How many grams of cacl2 are needed to make 713.9 g of a solution that is 29.0% (m/m) calcium chloride in water? note that mass is not technically the same thing as weight, but % (m/m) has the same meaning as % (w/w)?

A sample of a compound contains 60.0 g C and 5.05 g H.

divide by molar mass of C(12) and H(1) to get molar ratio

C: 60/12=5 and H: 5/1=5

so C:H=5:5=1:1

total molar mass=78

divide by 1C+1H to find the formula: 78/(12+1)=78/13=6

compound is C6H6

Answer:

False

Explanation:

You definitely won't see this nor need this but the Law of Conservation of Mass states that matter can neither be created nor destroyed in a chemical reaction.

I believe  the answer is false

Answer is: 325.5 mL of the stock solution.

c₁(AgNO₃) = 0.675 M.

V₂(AgNO₃) = 0.879 L.
c₂(AgNO₃) = 0.250 M.
V₁(AgNO₃) = ?
c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - volume to be diluted.
V₂ - final volume after dilution.
c₁ · V₁ = c₂ · V₂.
V₁(AgNO₃) = c₂ · V₂ ÷ c₁.
V₁(AgNO₃) = 0.250 M · 0.879 L ÷ 0.675 M.
V₁(AgNO₃) = 0.325 L · 1000 mL = 325 mL.

To make 0.879 l of 0.250 m silver nitrate from a 0.675 m stock solution, use the relationship between initial and final concentrations and volumes (M1V1 = M2V2). By substituting the given values and solving for V1, we can find the needed volume of the stock solution in liters and then convert that volume to milliliters by multiplying by 1000.

To answer this question, we need to use the formula related to molarity (M = moles/liters), which is M1V1 = M2V2. It is a relationship between the initial concentration (M1) and volume (V1) of stock solution and the final concentration (M2) and volume (V2) of dilute solution.

In this case, the student wishes to make 0.879 l (V2) of 0.250 m (M2) silver nitrate by diluting a stock solution of 0.675 m (M1) silver nitrate. Substituting these values into the formula M1V1 = M2V2, we can find the volume of the stock solution needed (V1).

So, the calculation would be: (0.675 M) V1 = (0.250 M)(0.879 L).

To solve for V1, divide both sides by 0.675 M and the result is: V1 = (0.250 M)(0.879 L) / 0.675 M. This gives the volume of the stock solution you need to use in liters. To convert this to milliliters (since the question asked for the volume in milliliters), multiply by 1000.

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The intermolecular forces between Br2 and CCl4 are London dispersion forces, as both substances are nonpolar molecules.

The intermolecular forces that exist between Br2 and CCl4 are London dispersion forces. These are the weakest type of intermolecular force and exist between all molecules, irrespective of whether they are polar or nonpolar. Br2 and CCl4 both are nonpolar molecules, so they don't exhibit dipole-dipole attractions, which are typically stronger than dispersion forces.

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Bed load - Large boulders carried along by a river

Headwater - The beginning of a river

Suspended load - Small rocks carried along by a river

Flood plain - A strip of land next to a river that is often very fertile

(APEX Verified 2020)

The pH of the second solution, given that the mixture of the two solution has a pH of 5, is 4.05

How to calculate the pH of the second solution?

First, we shall obtain the hydogen ion, [tex]H^+[/tex] of the first solution and the mixture solution. Details below:

For first solution:

[tex]H^+ = Antilog (-4)\\\\H^+ = 0.0001\ M\\\\[/tex]

For mixture solution:

[tex]H^+ = Antilog (-5)\\\\H^+ = 0.00001\ M\\\\[/tex]

Now, we shall obtain the [tex]H^+[/tex] of the second solution. Details below:

[tex]H^+[/tex] of second solution = [tex]H^+[/tex] of first solution -  [tex]H^+[/tex] of mixture solution

= 0.0001 - 0.00001

= 0.00009 M

Finally, we shall calculate the pH of the second solution. Details below:

pH = -Log Hydrogen ion [tex]H^+[/tex]

pH = -Log 0.00009

pH = 4.05

Answer:

Alcoholic fermentation

Explanation:

Alcoholic fermentation is an anaerobic process executed by yeasts, molds and some bacteria, which cause chemical changes in organic substances.

Alcoholic fermentation has the biological function of supplying energy to microorganisms in the absence of oxygen. To achieve this, the glucose molecules are dissociated and in this way the energy required to survive is obtained, producing ethanol and CO2 as products.

Final answer:

The molarity of a solution created by dissolving 24 g of NaCl in 475 mL of water can be calculated by converting the mass to moles, finding the solution's volume in liters, and dividing the moles by the volume. The result is approximately 0.864 M.

Explanation:

To calculate the molarity of a solution in which 24 g of NaCl is dissolved to make 475 mL of solution, follow these steps:

The volume of 576 grams of SO₂ gas at STP is approximately [tex]\( 200 \, \text{L}} \).[/tex]

To find the volume of 576 grams of SO₂ gas at STP (Standard Temperature and Pressure), we can use the ideal gas law equation:

[tex]\[ PV = nRT \][/tex]

Where:

- P is the pressure (at STP, [tex]\( P = 1 \)[/tex] atm)

- V is the volume of the gas

- n is the number of moles of gas

- R is the ideal gas constant [tex](\( R = 0.0821 \, \text{Latm/(molK)} \))[/tex]

- T is the temperature in Kelvin (at STP, [tex]\( T = 273.15 \)[/tex] K)

First, calculate the number of moles [tex]\( n \)[/tex] of SO₂ gas:

1. Calculate the molar mass of SO₂:

  - Atomic mass of S = 32.07 g/mol

  - Atomic mass of O = 16.00 g/mol (there are 2 oxygen atoms)

  - Molar mass of SO₂ = [tex]\( 32.07 + 2 \times 16.00 = 64.07 \)[/tex] g/mol

2. Convert grams of SO₂ to moles:

[tex]\[ n = \frac{\text{mass}}{\text{molar mass}} = \frac{576 \, \text{g}}{64.07 \, \text{g/mol}} \approx 9.00 \, \text{mol} \][/tex]

Now, use the ideal gas law to find the volume V:

[tex]\[ V = \frac{nRT}{P} \][/tex]

[tex]\[ V = \frac{9.00 \, \text{mol} \times 0.0821 \, \text{Latm/(molK)} \times 273.15 \, \text{K}}{1 \, \text{atm}} \][/tex]

[tex]\[ V \approx 200 \, \text{L} \][/tex]

The final concentration of the solution prepared by diluting 35.0 ml of 12.0 M HCl to a final volume of 1.20 L is 0.35 M.

The final concentration of a solution prepared by diluting 35.0 ml of 12.0 M HCl to a final volume of 1.20 L can be calculated using the formula for dilution: M1V1 = M2V2. In this formula, M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

Firstly, we convert the initial volume from ml to litres because the final volume is given in litres. So, 35.0 ml = 0.035 L. Therefore, the equation becomes: 12.0 M * 0.035 L = M2 * 1.20 L.

On rearranging the equation to solve for M2, the result is 0.35 M.

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Answer : The correct answer is Name = Thallium (Th) , atomic mass = 210 and atomic number = 81 .

Alpha decay :

When atomic nucleus emits an alpha particle that process is known as alpha particle decay . The symbol of alpha particle is [tex] _2^4He [/tex] , where 4 is atomic mass ( 2 protons + 2 neutrons ) and 2 atomic number .

When alpha particle is released the resultant nuclei (daughter nuclei) have 4 less atomic mass and 2 less atomic number .

Example for nuclear equation of alpha decay can be expressed as:

[tex] ^{230}_{90}Th \rightarrow _2^4He + ^{226}_{88}Ra [/tex]

Given :

Radioisotope = Bi Atomic mass = 214 Atomic number = 83

When it will release alpha particle , atomic mass will be decreased by 4 and atomic number by 2 .

Atomic mass = 214 - 4 = 210 Atomic number = 83-2 = 81

The atom with atomic number 81 is Thallium (Tl) . Hence the daughter nuclei so produced is [tex] ^{210}_{81}Tl [/tex]

The nuclear reaction can be written as :

[tex] ^{214}_{83}Tl \rightarrow ^4_2He + ^{210}_{81}Tl [/tex]

2 is the coefficient that correctly balance the formula equation: NH4NO2 → N2 + H2O.

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Answer: When an electron jumps from one state to another, the electron must gain or lose just the right amount of energy to actually travel the distance between the orbits.

Explanation:

Bohr in his structure of atom explained that protons which are positively charged particles and neutrons which are neutral particles,  are contained in the center of an atom called as nucleus.

The electrons which are negatively charged particles revolve around the nucleus in fixed orbit or shell or energy levels which are termed as quantized. These energy levels are stable and are stationary along with different energy value.  The electron remains in the state until energy is absorbed or released.

The electrons absorb energy when it moves from lower energy state to higher energy state. The electrons lose energy when it moves from higher energy state to lower energy state and thus emit radiations corresponding to the energy gap.

Thus the statement  when an electron jumps from one state to another, the electron must gain or lose just the right amount of energy to actually travel the distance between the orbits is incorrect because energy is absorbed when electron jumps from one state to another.

The energy is lost when electron falls from one state to another.

Answer: An electron in a stationary state does not emit radiation

Explanation:

I put that on usa test prep and it says correct. the other person who answered this is wrong

Answer is: atomic number of resulting atom is 88.
Alpha particle is nucleus of a helium-4 atom, which is made of two protons and two neutrons.
Nuclear reaction: ²³²Th → ²²⁸Ra + α (alpha particle).

Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.

Crude oil components are separated based on their boiling points using fractional distillation in a refinery.

The various components of crude oil are separated in a refinery based on differences in their boiling points. This process, known as fractional distillation, takes advantage of the fact that different compounds in crude oil have different boiling points.

In a refinery, crude oil is heated in a furnace and the vaporized oil is then passed through a tall column called a fractionating column. As the vapor rises through the column, it cools down, and the compounds with higher boiling points condense and are collected at different levels in the column.

For example, at the bottom of the column, heavy compounds like bitumen and fuel oil are collected, while lighter compounds like gasoline and kerosene are collected at higher levels. This allows the refinery to separate and collect various components of crude oil for further processing.

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Answer:  Engineers can design better bridges because they know how metal changes shape.

Explanation:  Physical Properties are those properties which are also regarded as observable because they can be easily seen or observe through naked eyes like melting point etc.

These are those properties which do not change chemical identity of the species.

Thus out of the given options, only physical property is the change of shape of metal.

And the rest one represents the chemical property as chemical property are the one which changes the chemical identity of the substance.

According to the Arrhenius theory a substance that yields hydrogen ions as the only ion in an aqueous solution is Acid.

Acids are those substances which are having pH range from 0 to 7.

According to the Arrhenius theory of acid and base, acids are those compounds which donate H⁺ ion or proton in the aqueous medium and bases are those substances which donate OH⁻ ion in the aqueous medium.

Example of Arrhenius acids are HCl, CH₃COOH, HNO₃, etc.

Hence, those substance which yields H⁺ ions is acids.

To know more about acids, visit the below link:

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The chef would need to add approximately 555.2 moles of salt NaCl to 1.0 kg of water to raise its boiling point to 105°C.

To determine how many moles of salt NaCl are needed to raise the boiling point of 1.0 kg of water to 105°C, we can use the concept of boiling point elevation and the colligative property of solutions.

Given data.

- Mass of water, [tex]\( m = 1.0 \) kg = \( 1000 \) g\\[/tex]

- Desired boiling point of water,[tex]\( T_{\text{new}} = 105 \)°C[/tex]

- Boiling point constant for water,[tex]\( K_b = 0.25 \) °C/m[/tex]

- Van't Hoff factor for NaCl [tex]\( i \) = 2 since NaCl dissociates completely into Na+ and Cl- ions in water[/tex]

First, calculate the change in boiling point [tex]\( \Delta T_b \)[/tex] using the formula for boiling point elevation

[tex]\[ \Delta T_b = i \cdot K_b \cdot m_{\text{salt}} \][/tex]

where.

- [tex]\( i \)[/tex] is the Van't Hoff factor,

- [tex]\( K_b \)[/tex] is the boiling point elevation constant,

- [tex]\( m_{\text{salt}} \)[/tex] is the molality of the salt in the solution.

To find [tex]\( m_{\text{salt}} \)[/tex], rearrange the equation:

[tex]\[ m_{\text{salt}} = \frac{\Delta T_b}{i \cdot K_b} \][/tex]

Calculate [tex]\( \Delta T_b \):[/tex]

[tex]\[ \Delta T_b = T_{\text{new}} - T_{\text{normal}} = 105 \text{°C} - 100 \text{°C} = 5 \text{°C} \][/tex]

Substitute the values into the equation.

[tex]\[ m_{\text{salt}} = \frac{5 \text{ °C}}{2 \cdot 0.25 \text{ °C/m}} \][/tex]

[tex]\[ m_{\text{salt}} = \frac{5}{0.5} \][/tex]

[tex]\[ m_{\text{salt}} = 10 \text{ mol/kg} \][/tex]

This molality [tex]10 mol/kg[/tex] represents the number of moles of salt per kilogram of solvent water.

To find the moles of salt [tex]\( n_{\text{salt}} \)[/tex] needed.

[tex]\[ n_{\text{salt}} = m_{\text{salt}} \cdot \frac{m_{\text{water}}}{M_{\text{water}}} \][/tex]

where.

[tex]- \( m_{\text{water}} \) is the mass of water[/tex],

[tex]- \( M_{\text{water}} \) is the molar mass of water.[/tex]

Calculate [tex]\( M_{\text{water}} \)[/tex].

[tex]\[ M_{\text{water}} = 18.015 \text{ g/mol} \][/tex]

Convert [tex]\( m_{\text{water}} \) to grams[/tex].

[tex]\[ m_{\text{water}} = 1000 \text{ g} \][/tex]

calculate [tex]\( n_{\text{salt}} \)[/tex].

[tex]\[ n_{\text{salt}} = 10 \text{ mol/kg} \cdot \frac{1000 \text{ g}}{18.015 \text{ g/mol}} \]\\[/tex]

[tex]\[ n_{\text{salt}} = 10 \cdot \frac{1000}{18.015} \text{ mol} \][/tex]

[tex]\[ n_{\text{salt}} \approx 555.2 \text{ mol} \][/tex]