Lithium-6 has a mass of 6.0151 amu and lithium-7 has a mass of 7.0160 amu. The relative abundance of Li-6 is 7.42% and the relative abundance of Li-7 is 92.58%. Based on this data alone, calculate the average atomic mass for lithium to the correct number of significant digits.

Answers

Answer 1
Average atomic mass is the weighted average atomic masses with regard to the relative abundance of the isotopes 
average atomic mass of Li = relative abundance of Li-6 x mass of Li-6 + relative abundance of Li-7 x mass of Li-7
average atomic mass of Li = (7.42% x 6.0151 a.m.u) + (92.58% x 7.0160 a.m.u)
                                           = 0.446 + 6.495
                                           = 6.941 amu
average atomic mass of Li is 6.941 amu
Answer 2

The average atomic mass for lithium, given that Lithium-6 has a mass of 6.0151 amu and lithium-7 has a mass of 7.0160 amu, is 6.9417 amu

How to determine the atomic mass of lithium?

From the question given above, the following data were obtained?

Mass of Lithium-6 = 6.0151 amuAbundance of Lithium-6 (1st%) = 7.42%Mass of lithium-7 = 7.0160 amuAbundance of lithium-7 (2nd%) = 92.58%Average atomic mass of lithium =?

Average atomic mass = [(Mass of 1st × 1st%) / 100] + [(Mass of 2nd × 2nd%) / 100]

= [(6.0151 × 7.42) / 100] + [(7.0160 × 92.58) / 100]

= 0.4463 + 6.4954

= 6.9417 amu

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Related Questions

In the third period of the periodic table sodium is followed by magnesium aluminum silicon and phosphorus which of these elements has the smallest atomic size ?

Answers

Answer:
            Phosphorous has the smallest atomic size.

Explanation:
                   As we know these elements belong to same period means there valence shell is the same. So moving from left to right along the period the shell number remains constant but the number of protons and electrons increases. So, due to increase in number of protons the nuclear charge increases hence attracts the valence electrons more effectively resulting in the decrease of atomic size.

Elements and their atomic radius are as follow,

Magnesium          0.160 nm

Aluminium           0.130 nm

Silicon                  0.118 nm

Phosphorus         0.110 nm

Differences in which property allows the separation of a sample of sand and sea water by filteration

Answers

Answer:
            Differences in Particle Size allows the separation of a sample of sand and sea water by filtration.

Explanation:
                     This is a very simple example which can be conducted at home. When Salt dissolved in water is filtered all the solution get passed through filter paper, while solution of sand and water on filtration separates the sand from water. This is because of the particle size. The size of Na⁺ and Cl⁻ ions are very small and can easily pass through the pores of filter paper, while the size of sand particles are very large and fails to pass through the pores of filter paper.

Filtration is a type of process in which components of a mixture are separated based in the size. The sea water and sand can be separated by filtration due to different particle size.

Seawater is a mixture of several substances, including salt, sand, and stones. The substances of seawater can be separated via filtration. The filter paper in this technique separates the substances based on the size of particles.

The filtration separates sand and seawater as:

Seawater and sand are dissolved in each other. When the filtration technique is performed, it separates out the water from sand. The size of the sand particles are larger than the pore size of filter paper, thus, it easily separates the sand from seawater.

Therefore, difference in the particle size allows the separation of seawater and sand.

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calculate the pressure in atm, if 0.00825 moles occupies 174 mL at -15 celcius.

Answers

Answer is: the pressure is 1.12 atm.
n(O₂) = 0.00825 mol, amount of substance.
V = 174 mL ÷ 1000 mL/L = 0.174 L, volume of gas.

T = 15°C = 288.15 K; temperature.
R = 0.08206 L·atm/mol·K, universal gas constant.
Ideal gas law: p·V = n·R·T.
p = n·R·T / V.
p = 0.00825 mol · 0.08206 L·atm/mol·K · 288.15 K / 0.174 L.
p = 1.12 atm.


The pressure is calculated using the Ideal Gas Law. Given the moles, volume in liters, and temperature in Kelvin, the pressure is approximately 0.100 atm. This calculation involves converting units and applying the gas constant.

To calculate the pressure in atmospheres (atm) given the number of moles, volume, and temperature, we need to use the Ideal Gas Law formula:

PV = nRT

Here:

P is the pressure in atm.V is the volume in liters. Since the given volume is in milliliters (174 mL), we need to convert it to liters:

        174 mL × 0.001 L/mL = 0.174 L.

n is the number of moles, which is 0.00825 moles.R is the ideal gas constant, which is 0.0821 (L atm)/(K mol).T is the temperature in Kelvin. We need to convert the temperature from Celsius to Kelvin:

        T = -15 °C + 273 = 258 K.

Now, we substitute the known values into the Ideal Gas Law equation:

P × 0.174 L = 0.00825 moles × 0.0821 (L atm)/(K mol) × 258 K

Simplify and solve for P:

P = (0.00825 moles × 0.0821 × 258) / 0.174

P ≈ 0.100 atm

Which phrase describes an al atom?
a.a negatively charged nucleus, surrounded by negatively charged electrons
b.a negatively charged nucleus, surrounded by positively charged electrons?

Answers

Answer:
            None of the given options describe any atom. The phrase which describe an atom is "a positively charged nucleus surrounded by negatively charged electrons".

Explanation:
                   Atom is a smallest indivisible particle which is made up of many sub particles. The main sub particles are Protons, Neutrons and Electrons. Protons are positively charged, neutrons doesn't carry any charge hence neutral and electrons are negatively charged. Protons and neutrons are present in nucleus, therefore making the nucleus positively charged, while, electrons revolve around the nucleus in orbit hence being negatively charged particles surrounds the positively charged nucleus.

An atom is defined as the microscopic particle having positively charged nucleus around which negatively charged electrons revolve. In aluminum atom, none of the options give are correct.

Aluminum is an atom made up of 13 electrons and 13 protons. In an atom, there are several sub-particles, which are:

Protons are the positively charged sub-particle that are present inside the nucleus.Electrons are the negatively charged sub-particles that revolves around the nucleus. Neutrons does not have any charge, and is found in the nuclei of atoms.

Therefore, the correct statement is that aluminum atom have positively charged nucleus around which electrons revolve. Hence, the given options are incorrect.

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Who was the first scientist to propose that the atom had a dense nucleus which occupied only a small fraction of the volume of the atom?

Answers

The first scientist was Ernest Rutherford

Ernest Rutherford was the first scientist to propose that the atom had a dense nucleus that occupied only a small fraction of the volume of the atom.

What are atomic models?

There are some models that are used to explain the arrangements of subatomic particles inside the atom based on the atomic theory of atoms known as the atomic models.

There are many types of atomic models proposed in past based on their individual assumptions and the experimentations

Rutherford's discovery demonstrated that the majority of an atom is essentially blank space and that the center only takes up a very small portion of the entire atom, which had an impact on Thomson's commonly accepted atomic model. 

Thus, Ernest Rutherford was the first scientist to propose that the atom had a dense nucleus that occupied only a small fraction of the volume of the atom.

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A rock contains uranium 238 which has a half life of 4.5 billion years. if the rock is crushed and heated, the half life in urainium-238 will

Answers

The answer is remain the same.If the rock is cut, crushed, or heated, the length of the half life of the uranium would remain the same since these factors have no effect on half-life.Even though chemical changes were affected by temperature, the physical state, pressure, concentration, the chemical environment within the molecule, and any other changing factors, the half-life of a radioactive substance is independent of these influences.

Crushing and heating a rock containing uranium-238 does not change its half-life, which remains 4.5 billion years.

The half-life of a radioactive isotope like uranium-238 is the time it takes for half of its atoms to decay into another element.

For uranium-238, this duration is 4.5 billion years.If a rock containing uranium-238 is crushed and heated, the half-life of the uranium-238 will remain the same.This is because the half-life is a fundamental property of the radioactive nucleus and is not affected by external conditions like crushing or heating.

To summarize, the process of crushing and heating the rock does not alter the radioactive decay process or the half-life of uranium-238, which will remain constant at 4.5 billion years.

What is a reaction with a positive enthaply spontaneous

Answers

When the reaction is exothermic but undergoes a decrease in entropy, it is the entalpy term which favors the reaction. In this case, a spontaneous reaction is dependent upon a term being small relative to another term.

What is the most abundant gas in our atmosphere?
1. oxygen
2. hydrogen
3. nitrogen
4. water

Answers

Nitrogen <---- Itś at 73% of Earths atmosphere.
3. Nitrogen. It's 73% of the Earth's atmosphere.

In the reaction 2co(g) + o2(g) â 2co2(g), what is the ratio of moles of oxygen used to moles of co2 produced? select one:

Answers

2CO(g)           +          1O2(g) --->          2CO2(g)
2 mol CO                1 mol O2             2 mol CO2

1 mole O2 to 2 moles CO2, or
1 mole O2 : 2 moles CO2.

What can the size and shape of a sand dune tell you about how it was formed?

Answers

It could tell you how much mass contains inside

which element is in the same "family" as chlorine (Cl) and fluorine (F)?
a. bromine (Br)
b. oxygen (o)
c. hydrogen (h)
d. lithium (Li)

Answers

Answer:  [A]:  "bromine (Br)"  .
__________________________________________________
Note:  "bromine" (Br) ; "chlorine" (Cl) ; and "fluorine" belong in the "halogen" family.  
___________________________________________________Refer to the Period Table of Elements (shown below).  

The vertical "columns" are referred to as:  "groups";  or, "families".   Refer to the "halogens"; or "halogen family" — circled in "black-color";  as follows:___________________________________________________

Bromine (Br) is in the same halogen family as chlorine (Cl) and fluorine (F) because they share similar chemical properties and have the same number of valence electrons. Option A is correct .

The element that is in the same 'family' as chlorine (Cl) and fluorine (F) is bromine (Br). These elements are part of the halogen family in the periodic table. Halogens are found in Group 17, and they share similar chemical properties, such as high reactivity and the tendency to form salts with metals.

For clarification, elements in the same group or family have the same number of valence electrons, which contributes to their similar chemical behavior. Bromine, like chlorine and fluorine, has seven valence electrons and forms similar types of compounds.

Oxygen (O), hydrogen (H), and lithium (Li) belong to different families: oxygen is a chalcogen, hydrogen is often placed in its own group due to its unique properties, and lithium is an alkali metal. Option A is correct .

Atoms that have a positive or negative electrical charge are called ________.

A. magnetic
B. isotopes
C. metals
D. ions

Answers

ions are atom with positive and negative electrical charge

Answer: ions

Explanation:

Why does inhaled air need to be warmed filtered and moistened?

Answers

Inhaled air is warmed, filtered, and moistened to protect the respiratory system from damage caused by cold, dry, and particulate-laden air. These processes maintain respiratory health by equilibrating the inhaled air to body conditions and acting as protective mechanisms against infection and irritation to the lungs and trachea.

Inhaled air needs to be warmed, filtered, and moistened as part of the respiratory process in mammals. When air is inhaled through the nasal cavity, it is warmed to body temperature, which helps in reducing the shock to the system that cold air might cause. The air is then humidified by picking up water from the mucus lining the respiratory tract, which serves to equilibrate the air to the body's conditions. This humidification is crucial as it prevents the dryness that could damage the delicate tissues within the respiratory system. Furthermore, as the air passes through the nasal passages, particulate matter is trapped by hairs, mucus, and cilia, effectively filtering out potential irritants or harmful substances. These processes collectively prevent damage to the trachea and lungs, serving as important protective mechanisms to maintain respiratory health. Moreover, this filtering also plays a role in warding off infection, which along with the warming and moistening actions, decreases sensitivity during breathing and prevents damage to the lungs.

An oxidation reaction occurs only in the presence of _____.

Answers

The answer is reduction reaction. For every oxidation reaction that takes place, a reduction reaction must also happen, no reduction can occur without oxidation and vice versa. In redox reaction, atoms or ions undergo changes in the electronic structure, involving the transfer of electrons between reactants.

Final answer:

An oxidation reaction requires the presence of an oxidizing agent.

Explanation:

Oxidation reaction are part of a larger set of reactions known as oxidation-reduction reactions, which involve the transfer of electrons. The term 'oxidation' itself originally referred to reactions involving molecular oxygen a key factor in these processes. However, the concept has broadened over time to cover any reaction where there is a loss of electrons, leading to an increase in the oxidation state of an element.

For example, compounds of elements in high oxidation states tend to act as oxidants and become reduced in chemical reactions. Every oxidation must be accompanied by a reduction. In chemical terms, the reducing agent is the species being oxidized because it loses electrons, whereas the oxidizing agent is the species being reduced, as it gains those electrons.

What will most likely happen if a sound wave moves from the air through a solid?

Answers

the wavelength of the associated sound will increase. 

Answer:

D

Explanation:

YOUR WELCOME

Identify the atom represented by this electron configuration and elaborate on its bonding properties.

1s22s22p63s23p64s23d5

A) .Chromium is a transition with a half full-valence orbital and can form up to six bonds. B) Antimony is a metalloid that can form five covalent bonds or three metallic bonds. C) Manganese is a transition metal that can form up to five stable ionic bonds D) Bromine is a non-metal that forms one ionic bond or a variable number of covalent bonds.

Answers

Answer:
            The given electronic configuration represents Manganese.

Explanation:
                   The given electronic configuration is....

                                  1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d⁵

As the valence shell is 4 in electronic configuration so it is present in 4rth period in periodic table. And according to definition of transition elements, transition elements has partially filled d-orbital. i.e.

                                                  (n - 1)d
As, n = 4
So,
                                                  (4 - 1)d

                                                      3d

So tracking 4rth period, we found Mn with given electronic configuration.
Also,
        "Manganese is a transition metal that can form up to five stable ionic bonds". It means that the five electrons present in d-orbital are transferred and Mn converts into Mn⁺⁵.

The electron configuration 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵ represents the element Chromium (Cr), a transition metal with a notably stable half-filled 3d subshell. Chromium can undergo hybridization and is capable of forming complex ions, including the ability to form up to six bonds in certain complexes. Option A is correct .

The electron configuration given is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵ which corresponds to the element Chromium (Cr). Chromium tends to have exceptions to predicted electron configurations due to enhanced stability associated with half-filled or completely filled subshells.

The presence of a half-filled 3d subshell alongside a singly occupied 4s orbital is more stable than expected configurations. As for bonding properties, Chromium is a transition metal known for its ability to exhibit variable oxidation states and form complex ions, primarily through its valence electrons in the 3d and 4s orbitals.

When forming bonds, it is common for transition metals like Chromium to undergo hybridization, combining their s, p, and d orbitals to form new hybrid orbitals that can result in different geometries and bonding capabilities.

For instance, the hybridization can result in d²sp³ hybrid orbitals, which can form octahedral complexes with ligands. In the case of Chromium (III), which has an electron configuration of 3d³ after losing its 4s electron and two 3d electrons, it can form up to six bonds, as seen in complexes such as the octahedral hexaamminechromium (III) cation.

How many kj of heat are needed to completely vaporize 1.30 moles of h2o? the heat of vaporization for water at the boiling point is 40.6 kj/mole?

Answers

The Kj of heat that  are needed to completely vaporize 1.30  moles of H2O  if  the heat of vaporization  for water is 40.6 Kj/mole  is calculated as  below

Q(heat) = moles x heat  of vaporization)

=1.30 mol  x40.6 kj/mol= 52.78 Kj  is needed

Explanation:

Heat of vaporization is defined as the amount of heat required to change one mole of a liquid into vapor state without any change in the temperature.

It is known that for 1 mole of water, latent heat of vaporization is 40.6 kJ/mol.

Therefore, heat of vaporization for 1.30 moles will be calculated as follows.

              [tex]1.30 moles \times 40.6 kJ/mol[/tex]

               = 52.78 kJ

Thus, we can conclude that the 52.78 kJ of heat are needed to completely vaporize 1.30 moles of [tex]H_{2}O[/tex].

Potassium chloride (KCl) is sometimes used to treat low blood potassium levels. Calculate the concentration of a saturated solution of potassium chloride at 20°C. Question continued-?
Hint: The formula for molarity, a common concentration unit, is M = moles/volume of solution expressed in units of mol/L. You will need to convert from grams of KCl to moles. Assume the volume of solution is 100 mL. Show your work!
Info: 36g of KCl is the max 100mL of water could hold at 20°C.

Answers

Molarity  is the most convenient way to express concentration.

Mathematically, molarity is expressed as [tex] \frac{\text{mass of solute(g)}}{\text{gram molecular weight X Volume of solution (l)}} [/tex]

In present case,
mass of solute (KCl) = 36 g
molecular weight of KCl = 74.55 g/mol
volume of solution = 100 ml = 0.1 l

∴ Molarity = [tex] \frac{36}{74.55X0.1} [/tex]
                 = 4.829 M
Thus, conc. of saturated KCl at 20 oC is 4.829 M 

Which or the following solutions would have the highest concentration of hydronium ion and why?
A)1.0×10^-3 M HCl
B)1.0×10^-3 M HC2 H3 O2
C)0.050 M HCl
D)0.050 M HC2 H3 O2

(I already know that the answer is C I just don't know why)

Answers

Answer is: C)0.050 M HCl.
Chemical reaction 1: HCl(aq) + H₂O(l) → H₃O⁺(aq) + Cl⁻(aq).
Chemical reaction 2: CH₃COOH(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CH₃COO⁻(aq).
Hydrochloric acid (HCl) is strong acid, which means that concencentration of hydronium ions are equal as concentration of hydrochloric acid:
A) c(HCl) = c(H₃O⁺) = 0.001 M.
C) c(HCl) = c(H₃O⁺) = 0.050 M is greater than A.
Acetic acid (CH₃COOH) is weak acid and does not dissociate completely as HCl, so concentration of hydronium ion in this solutions are very low.

A substance that is not soluble in a polar solvent is

Answers

I believe its a Nonpolar substance.

Which formula shown is incorrect for the name given? Which formula shown is incorrect for the name given? calcium nitrate: Ca(NO3)2 ammonium cyanide: NH4CN strontium carbonate: SrCO3 potassium acetate: KC2H3O2 lithium sulfate: LiSO4

Answers

Answer:

5.Lithium sulfate:[tex]LiSO_4[/tex]

Explanation:

We  have to find the formula which is incorrect for the name given

1.Calcium nitrate :[tex]Ca(NO_3)_2[/tex]

We know that Charge on calcium ion =+2

Charge on nitrate ion=-1

Therefore, the formula of calcium nitrate is [tex]Ca(NO_3)_2[/tex].

Hence, it is true.

2.Ammonium cyanide:[tex]NH_4CN[/tex]

Charge on ammonium ion=+1

Charge on cyanide ion=-1

Therefore, the formula of ammonium cyanide is [tex]NH_4CN[/tex].

Hence, it is true.

3.Strontium carbonate :[tex]SrCO_3[/tex]

Charge on strontium ion=+2

Charge on carbonate ion=-2

Therefore, the formula of strontium carbonate is [tex]SrCO_3[/tex].

Hence, option  is true.

4.Potassium acetate:[tex]KC_2H_3O_2[/tex]

Charge on potassium ion=+1

Charge on acetate ion=-1

Therefore , the formula of potassium acetate is [tex]KC_2H_3O_2[/tex].

Hence, option is true.

5.Lithium sulfate:[tex]LiSO_4[/tex]

Charge on  lithium ion=+1

Charge on sulfate ion=-2

Therefore, the formula of lithium sulfate is [tex]Li_2SO_4[/tex].

But given formula is [tex]LiSO_4[/tex].

Hence, option is false.

What is the molecular formula of a compound whose molar mass is 88 and whose percent composition is 54.5% carbon, 9.1% hydrogen, and 36.4% oxygen?

Answers

molecular formula is the actual composition of elements in the compound.
we can first find the empirical formula. empirical formula is the simplest ratio of whole number of elements in the compound .
for 100 g of compound 

                               C                            H                          O
mass                     54.5 g                     9.1 g                  36.4 g
number of moles   54.5 g/12 g/mol     9.1 g/1 g/mol       36.4 g / 16 g/mol 
                              = 4.54 mol              = 9.1 mol            = 2.28 mol
     divide by the least number of moles 
                               4.54 / 2.28  =1.99    9.1/2.28=3.99     2.28/2.28 = 1
numbers rounded off
C - 2
H - 4
O - 1
empirical formula - C₂H₄O
mass of empirical formula - (12*2) + (4*1) + (1*16) = 44 
mass of molecular formula - 88 g/mol

number of empirical units - 88 g/mol / 44 = 2
there are 2 empirical units 
molecular formula - 2 (C₂H₄O)
molecular formua - C₄H₈O₂

Answer:

C₄H₈O₂

Explanation:

An element found in another galaxy exists as two isotopes. if 80.0 percent of the atoms have an atomic mass of 80.00 atomic mass units and the other 20.0 percent have an atomic mass of 82.00 atomic mass units, what is the atomic mass of the element?

Answers

relative atomic mass of the element is the weighted average atomic mass of the element with regard to the abundance of the isotopes in nature.
atomic mass of the element is the sum of the products of the isotope mass by the percentage abundance of that isotope 
isotope 1 - abundance 80 % - 80.00 a.m.u
isotope 2 - abundance 20 % - 82.00 a.m.u 
atomic mass = 80.00 x 80% + 82.00 x 20% 
                     = 64.00 + 16.40 = 80.40 a.m.u
atomic mass of the element is 80.40 a.m.u

Explain how the molar mass of a gas affects the rate at which the gas diffuses and effuses

Answers

Diffusion  is defined as spreading of molecules of a substance, away from each other, throughout the space.

Effusion is the phenomena of escape of gas molecules through a very small orifice into an evacuated area. 

According to Graham's Law, rate of diffusion and effusion is inversely proportional to molecular mass.

Thus, with increase in molecular mass, rate of diffusion and effusion will decrease. 
Final answer:

The molar mass of a gas influences its diffusion and effusion rates, according to Graham's law of effusion. Lighter gas molecules diffuse and effuse faster than heavier ones due to their movement speed. The ratios of diffusion and effusion rates, both dependent on the molar mass, remain constant.

Explanation:

The molar mass of a gas significantly affects its diffusion and effusion rates due to the principles identified in Graham's law of effusion. According to this law, the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles. Hence, lighter gas molecules will effuse and diffuse at a faster rate as compared to heavier ones.

Furthermore, the average speed of gas molecules impacts the rate of effusion. As a consequence, heavier gas molecules, which move more slowly due to their larger mass, will diffuse and effuse slower compared to lighter molecules. This is because it is more challenging for heavier molecules to move between the molecules of the substance they are moving through.

Lastly, diffusion and effusion rates both depend on the molar mass of the gas involved. Although their rates are not identical, the ratios of their rates remain consistent. This is another way the molar mass of a gas influences its diffusion and effusion rates.

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A student pours exactly 26.9 mL of HCl acid of unknown molarity into a beaker. The student then adds 2 drops of the indicator and titrates the acid to neutrality using 43.7 mL of 0.13 M NaOH base.
a. Write and balance the neutralization reaction of the acid and base
b. What is the molarity of the acid?

Answers

a.
Acids react with bases and give salt and water and the products.

Hence, HCl reacts with NaOH and gives NaCl salt and H₂O as the products. The reaction is,
            HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

To balance the reaction equation, both sides hould have same number of elements.

Left hand side,                                             Right hand side,
             
H atoms = 2                                               H atoms = 2
            Cl atoms = 1                                               Cl atoms = 1
            Na atoms = 1                                               Na atoms = 1 
           O atoms = 1                                                   O atoms = 1

Hence, the reaction equation is already balanced.

b. 
Molarity (M)= moles of solute (mol) / Volume of the solution (L)
 
          HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

Molarity of NaOH = 0.13 M
Volume of NaOH added = 43.7 mL
Hence, moles of NaOH added = 0.13 M x 43.7 x 10⁻³ L
                                                 = 5.681 x 10⁻³ mol

Stoichiometric ratio between NaOH and HCl is 1 : 1

Hence, moles of HCl = moles of NaOH
                                    = 
5.681 x 10⁻³ mol

5.681 x 10⁻³ mol of HCl was in 26.9 mL.

Hence, molarity of HCl = 5.681 x 10⁻³ mol / 26.9 x 10⁻³ L
                                     = 0.21 M

Which is an acceptable Lewis structure for a diatomic nitrogen molecule?

Answers

Answer:
            Acceptable Lewis structure of Diatomic Nitrogen Molecule is as follow,

                                                      :N≡N:

Explanation:
                     
The given lewis structure is acceptable because each nitrogen atom has a complete octet and and the formal charge of each nitrogen atom is zero. So those lewis structures which has zero or least formal charges are said to be more stable and acceptable. The formal charge is calculated is,

Formal Charge  =  # of Valence e⁻s - [# of non-bonded e⁻ + 1/2 # of bonded                                           e⁻]

For N,

Formal Charge  =  5 - [ 2 + 6/2]

Formal Charge  =  5 - [ 2 + 3 ]

Formal Charge  =  5 - 5

Formal Charge  =  0

Same result will come for the second N atom.
Final answer:

The Lewis structure for a diatomic nitrogen molecule  would indicate a triple bond between the two nitrogen atoms, with each atom having a pair of lone electrons. The concept of resonance doesn't apply to this molecule.

Explanation:

The diatomic nitrogen molecule has a triple bond between the two nitrogen atoms. A Lewis structure, in this context, represents the arrangement of electrons in a molecule. The Lewis structure for N2 would therefore show the nitrogen atoms sharing three pairs of electrons - indicating the triple bond - with each nitrogen atom also having one pair of lone (non-bonding) electrons.

Using the concepts of resonance and electron-pair geometries, it's possible to show that the actual distribution of electrons is an average between various possible Lewis structures. However, the resonance only applies to molecules where it's not possible to depict the molecule's structure using a single Lewis structure, as in the case of nitrogen dioxide (NO2) and related compounds, not diatomic nitrogen.

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Draw the electron dot formula for the hypochlorite ion, clo-. how many nonbonding electron pairs are in a hypochlorite ion? 1 6 7 2 none of the above

Answers

Answer:
            There are nonbonding electron pairs are in a hypochlorite ion.

Explanation:
                   Lewis structure of ClO⁻ is drawn as,

1) Add valence electrons of both elements along with additional one electron present in the form of negative charge on molecular ion, so,

Valence e⁻ of Cl           =   7

Valence e⁻ of O            =   6

e⁻ for negative charge  =  1
                                      ------------
Total e⁻                             14

2) Draw both elements and connect them by single bond, and subtract 2 electrons from total valence electrons,
So,
                                         14  -  2  =  12

Now distribute remaining 12 electrons on both element in order to complete their octet.

Result:
           Each element gets three lone pair of electrons which are not involed in bonding. Therefore, overall 6 nonbonding electron pairs are present on ClO⁻ ion.

Write a nuclear reaction for the neutron-induced fission of u?235 to produce te?137 and zr?97. how many neutrons are produced in the reaction?

Answers

This is a neutron induced fission, therefore a neutron will be added to the U²³⁵ to cause the reaction, and thus it will be added to the left side. There will be unknown number of neutrons produced and thus we put this on the right hand side.
n₁ + U²³⁵ = Te¹³⁷ + Zr ⁹⁷ + xn1 ( n1 to mean a neutron of mass 1)
To balance the masses on both sides of the equation;
1 + 235 = 137 +97+ x
x = 2 
the end reaction will be
n₁ +U²³⁵ = Te¹³⁷ + Zr⁹⁷ + 2 n₁

This is a neutron induced fission, therefore a neutron will be added to the U²³⁵ to cause the reaction, and thus it will be added to the left side. There will be unknown number of neutrons produced and thus we put this on the right hand side.n₁ + U²³⁵ = Te¹³⁷ + Zr ⁹⁷ + xn1 ( n1 to mean a neutron of mass 1)To balance the masses on both sides of the equation;1 + 235 = 137 +97+ xx = 2 the end reaction will ben₁ +U²³⁵ = Te¹³⁷ + Zr⁹⁷ + 2 n₁


When bismuth-212 undergoes alpha decay, it becomes which of the following?


A asatine-208 + an alpha particle
B lead-210 + an alpha particle
C polonium-210 + and alpha particle
D thallium-208 + and alpha particle

Answers

Answer is: D thallium-208 + and alpha particle.
Nuclear reaction: ²¹²Bi → ²⁰⁸Tl + α (alpha particle).
Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.

explain why many compounds that contain one or more hydrogen atoms are not classified as arrhenius acids

Answers

Final answer:

Not all compounds containing hydrogen atoms are classified as Arrhenius acids because they do not release hydrogen ions when dissolved in water. Methane and acetic acid are examples of compounds that contain hydrogen atoms but are not classified as Arrhenius acids.

Explanation:

In order for a compound to be classified as an Arrhenius acid, it must release hydrogen ions (H+) when dissolved in water. However, not all compounds that contain hydrogen atoms are classified as Arrhenius acids because they do not release H+ ions. For example, methane (CH4) and acetic acid (CH3COOH) both contain hydrogen atoms but they are not classified as Arrhenius acids because their hydrogen atoms are not capable of ionizing.

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