How many liters of H2 gas, collected over water at an atmospheric pressure of 752 mm Hg and a temperature of 21.0°C, can be made from 3.566 g of Zn and excess HCl? The partial pressure of water vapor is 18.65 mm Hg at 21.0°C.

Answer:

Explanation:

Liquids have the medium energy level of the three state. They have enough energy for the molecules to break free from their solid lattice but not enough to separate from being in groups of molecules, they move around slowly and randomly in groups, with a moderate level of kinetic energy to power them.

The liquid state, as explained by the kinetic-molecular theory, is where particles can move around each other due to sufficient kinetic energy but remain in close contact because of intermolecular forces, resulting in a definite volume but no fixed shape.

According to the kinetic-molecular theory, the liquid state is characterized by particles that have enough energy to partially overcome their intermolecular interactions. Despite these interactions, particles within a liquid can move around each other, allowing the liquid to take the shape of its container. However, because particles in a liquid are still in close contact, they do not compress easily, giving liquids a definite volume.

In liquids, the kinetic energy of the particles allows them to slide past one another smoothly, changing neighbors due to their mobility, while the intermolecular forces maintain the overall cohesion. This energetic state is more dynamic compared to a solid but less energetic than a gas, where the particles are much further apart. The properties of liquids, therefore, are a balance between the kinetic energy of the particles and the intermolecular forces present.

Answer:

0.036 g

Explanation:

0.036 g of water should be produced.

From the equation of reaction, 1 mole of HCl requires 1 mole of NaOH in order to produce 1 mole of H2O.

20 mL of 0.10 M HCl contains 20/1000 x 0.10 = 0.002 moles of HCl

46 grams of NaOH contains 46/40 = 1.15 moles of NaOH

It thus means that the HCl is a limiting reagent in the reaction.

From the equation:

1 mole  HCl will produce 1 mole of H2O.

0.002 HCl with therefore produce 0.002 x 1/1 = 0.002 mole of H2O

Mass of water produced = mole x molar mass

    0.002 x 18 = 0.036 g.

Hence, 0.036 g of water would be produced.

Answer:

1`. B)5.52

2. C) 1.0 x 10-5M

3. B) H+

4. C) 4.0

The pH of a solution with [H+] = 3.0 × 10–6 M is 5.52. A cup of black coffee with a pH of 5 has a hydrogen ion concentration of 1.0 × 10–5 M. The concentration of a solution's pH is indicated by H+.

The pH of a solution can be determined using the equation pH = -log[H+]. In the first question, the solution has a hydrogen ion concentration of 3.0 × 10–6 M, so the pH is calculated as -log(3.0 × 10–6) = 5.52. In the second question, a coffee with a pH of 5 has a hydrogen ion concentration of 1.0 × 10–5 M, which can be calculated using the same equation. The correct option is 1.0 × 10–5 M. In the third question, the hydrogen ion concentration is a characteristic of a solution's pH, so the correct option is H+.

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Explanation:

mass = Moles * molar mass

molar mass of BaSO4 = 112+32+64= 208

= 1.72*208 = 357.76

Answer:

See explanation below

Explanation:

To solve this problem, we need to use the Henderson - Hasselbach equation which is the following:

pH = pKa + log ([A⁻] / [HA])   (1)

Where:

[A⁻] = concentration of the acetate

[HA] = concentration of the acetic acid.

With the above expression, we can calculate the ratio of [A⁻] / [HA]. This concentration ratio will be used to calculate the individual concentrations. We know that a buffer is made as a mix of the acid and it's ion, in other words:

[HA] + [A⁻] = [Buffer]   (2)

So, with the concentration ratio, we can replace it here in (2) and then, we can calculate each concentration required.

First, let's use (1) to get the concentration ratio:

5 = 4.76 + log ([A⁻] / [HA])

5 - 4.76 = log ([A⁻] / [HA])

0.24 = log ([A⁻] / [HA])

[A⁻] / [HA] = 10⁰°²⁴

[A⁻] / [HA] = 1.7378

From this ratio, we can express either HA or A in function of the result. In this case, we will solve for A:

[A⁻] = 1.7378[HA]

With this expression, we can replace it in (2) to solve for [HA]:

[HA] + 1.7378[HA] = 0.2

2.7378[HA] = 0.2

Now all we have to do is replace this value in [A] to get the concentration:

[A⁻] = 1.7378 * 0.0731

Answer:

yes

Explanation:

Answer:

C₆H₆ + 3HNO₃ →  C₆H₃N₃O₆  +  3H₂O

Explanation:

The reaction is:

Benzene + Nitric acid → Water + ?

Let's determine the ? compound

Molar mass 213 g/mol

33.8g of C in 100 g of compound |

1.42 g of H in 100g of compound  | _  Percent composition

19.7 g of N in 100g of compound  |

45.1 g of O in 100g of compound  |

We propose these rule of three:

In 100 g of compound we have 33.8 g C, 1.42 g H, 19.7g N and 45.1g O

Therefore in 213g of compound we must have:

(213 .  33.8) / 100 = 72 g of C

(213 .  1.42) / 100 = 3 g of H

(213 .  19.7) / 100 = 42 g of N

(213 .  45.1) / 100 = 96 g of O

Now, we convert the mass to moles:

72 g of C . 1 mol / 12g = 6 C

3 g of H . 1 mol / 1g = 3 H

42 g of N . 1 mol / 14 g = 3 N

96 g of O . 1 mol / 16 g = 6 O

Molecular formula is C₆H₃N₃O₆. So the balanced reaction will be:

C₆H₆  +  3HNO₃ →  C₆H₃N₃O₆  +  3H₂O

Answer:

The mass of the precipitate will give the amount/concentration of Bromide ion present in the reaction setup, thereby indirectly giving the amount/concentration of NaBr (aq) that we started with.

Explanation:

[tex]AgNO3(aq) + NaBr(aq) \rightarrow AgBr(s) + NaNO3(aq)[/tex]

From the mass of AgBr precipitate formed, we can obtain the mass of Br originally in the NaBr sample we started with, using the percentage by mass of Br in the AgBr precipitate multiplied by the mass of precipitate obtained.

This answer can then be used in a similar method to obtain the mass of NaBr we started with.

Mass of Br in AgBr = (Mass of precipitate obtained) × [(molar mass of Br)/(molar mass of AgBr)]

Mass of NaBr we started with = (Mass of Br in precipitate) × [(Molar Mass of NaBr)/(Molar mass of Br)]

The mass of the precipitate will give the amount/concentration of Bromide ion present in the reaction setup, thereby indirectly giving the amount/concentration of NaBr (aq) that we started with.

Hope this Helps!!!

The mass of the silver bromide (AgBr) precipitate in a reaction with silver nitrate (AgNO₃) and sodium bromide (NaBr) gives an indication of the reaction’s efficiency and how much of the reactants have reacted due to the principle of conservation of mass.

In the given chemical reaction, the mass of the precipitate, which is silver bromide (AgBr), gives an indication of how much of the reactants have reacted. This is due to the principle of conservation of mass which states that mass cannot be created or destroyed in a chemical reaction. Therefore, the total mass of reactants before the reaction will equal the total mass of the products after the reaction.

If you knew the initial amounts of silver nitrate (AgNO₃) and sodium bromide (NaBr), you could calculate the theoretical yield of silver bromide (AgBr) using stoichiometry. Then, by comparing this theoretical yield with the actual mass of the precipitate formed, you could calculate the percentage yield of the reaction, which is a common measure of reaction efficiency.

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Answer:

Here After by Kate Brian

Explanation:

It is a really good story

The Goosebumps or RL.Stine book series is pretty interesting

1. For [tex]\([OH^-] = 10^{-12} \, M\)[/tex], the concentration of [tex]\([H_3O^+]\)[/tex] is [tex]\(10^{-2} \, M\)[/tex].

2. For [tex]\([OH^-] = 10^{-2} \, M\)[/tex], the concentration of [tex]\([H_3O^+]\)[/tex] is [tex]\(10^{-12} \, M\)[/tex].

Relationship Between [tex]\([H_3O^+]\) and \([OH^-]\)[/tex]:

The ion-product constant for water [tex](\(K_w\))[/tex] at 25 °C is [tex]\(1 \times 10^{-14} \, M^2\)[/tex].

[tex]\[ [H_3O^+] \times [OH^-] = K_w = 1 \times 10^{-14} \, M^2 \][/tex]

Case 1: [tex]\([OH^-] = 10^{-12} \, M\)[/tex]

[tex]\[ [H_3O^+] = \dfrac{K_w}{[OH^-]} = \dfrac{1 \times 10^{-14} \, M^2}{10^{-12} \, M} = 10^{-2} \, M \][/tex]

Case 2: [tex]\([OH^-] = 10^{-2} \, M\)[/tex]

[tex]\[ [H_3O^+] = \dfrac{K_w}{[OH^-]} = \dfrac{1 \times 10^{-14} \, M^2}{10^{-2} \, M} = 10^{-12} \, M \][/tex]

Answer:

Ethanol

Explanation:

2 C atoms and a single OH group.

Formula: C2H5OH

Answer:

A thermometer has a glass tube sealed at both ends and is partly filled with a liquid like mercury or alcohol. As the temperature around the thermometer's bulb heats up, the liquid rises in the glass tube. ... When it is hot, the liquid inside the thermometer will expand and rise in the tube

Explanation:

pls mark as brainliest

Answer: its pressure

Explanation: just trust me

Answer:

13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

Volume of the base (Vb) = 39mL

Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

6 x Va / 2 x 39 = 1/1

Cross multiply to express in linear form

6 x Va = 2 x 39

Divide both side by 6

Va = (2 x 39)/6

Va = 13mL

Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL

Answer:

The answer to your question is 58.7 g of Ca(OH)₂

Explanation:

Data

mass of Ca(OH)₂ = ?

mass of HNO₃ = 100 g

Process

1.- Write the balanced chemical reaction

              Ca(OH)₂ + 2HNO₃   ⇒   Ca(NO₃)₂  +  2H₂O

2.- Calculate the molar mass of the reactants

Ca(OH)₂  = 40 + 32 + 2 = 74 g

HNO₃ = 1 + 14 + 48 = 63 g

3.- Use proportions to calculate the mass of Ca(OH)₂

                  74 g of Ca(OH)₂ ----------------- 2(63) g of HNO₃

                    x                        ----------------- 100 g of HNO₃

                          x = (100 x 74) / 2(63)

                          x = 7400 / 126

                         x = 58.7 g

Answer: 17.71L

Explanation:

The volume can be calculated by using the ideal gas equation which is given as:

PV =nRT

Where P = Pressure, V= Volume, n= number of moles, R= gas constant and T = Temperature

From the above question :

P =5.4 ATM, V= ? n = 3.5 , R =0.082057 L atm /mol/K, T= 333K

PV = nRT

Make V subject of the formula we then have:

V= nRT/P

= 3.5 x 0.082507 L x 333 / 5.4

= 95.64 / 5.4 = 17.7L

Answer:

The answer is grass

Explanation:

Grass is a plant, meaning it undergoes photosynthesis to receive its energy from the sun.

Answer:

A-Grass

Explanation:

grass receives its energy from the sun in a process called photosynthesis, the chromophil in the plant foliage transforms sunlight into glucose and this chemical is converted into energy after several processes.

Answer:

a rection will most likely occur if the colliding partilces have the proper orientation and energy. The reactions occur becasue the molecules collide. But not all the collisions result in a reaction. The collisions have to meet some requirements

Explanation:

A reaction will most likely occur if the colliding partilces have the proper orientation and energy.

The chemical reaction is a process in which one or more substances, the reactants, are converted to one or more different substances, the products.

Chemical reactions require collisions between reactant species.

These reactant collisions must be of proper orientation and sufficient

energy in order to result in product formation.

The collisions have to meet some requirements.

Molecules must collide in order to react.

In order to effectively initiate a reaction, collisions must be sufficiently energetic (kinetic energy) to break chemical bonds; this energy is known as the activation energy.

Learn more about the chemical reaction here:

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