I am having trouble with logic gates(AND NOR,etc)
Can someone give me some advice to remember most logic gates

Answers

Answer 1
Logic gates take boolean input(s) and returns boolean output(s).

OR gate:
Two inputs, output is true if at least one input is 1.

AND gate:
Two inputs, output is true if both inputs are 1.

NOT gate:
One input, output is the reversed bit; 0 -> 1, 1 -> 0.

NAND gate:
Essentially a "Not AND" gate. The reverse of the AND gate.

NOR gate:
Essentially a "Not OR" gate. The reverse of the OR gate.

XOR gate:
Similar to an OR gate, outputs 1 if only one input is one.


These can be understood a lot better by looking at their respected truth tables.
Answer 2

A logic gate is an elementary building block of a digital circuit. Most logic gates have two inputs and one output. At any given moment, every terminal is in one of the two binary conditions low (0) or high (1), represented by different voltage levels.

There are seven basic logic gates: AND, OR, XOR, NOT, NAND, NOR, and XNOR.

The AND gate is so named because, if 0 is called "false" and 1 is called "true," the gate acts in the same way as the logical "and" operator. The following illustration and table show the circuit symbol and logic combinations for an AND gate. (In the symbol, the input terminals are at left and the output terminal is at right.) The output is "true" when both inputs are "true." Otherwise, the output is "false."

The OR gate gets its name from the fact that it behaves after the fashion of the logical inclusive "or." The output is "true" if either or both of the inputs are "true." If both inputs are "false," then the output is "false."

he XOR ( exclusive-OR ) gate acts in the same way as the logical "either/or." The output is "true" if either, but not both, of the inputs are "true." The output is "false" if both inputs are "false" or if both inputs are "true." Another way of looking at this circuit is to observe that the output is 1 if the inputs are different, but 0 if the inputs are the same.

 

The NAND gate operates as an AND gate followed by a NOT gate. It acts in the manner of the logical operation "and" followed by negation. The output is "false" if both inputs are "true." Otherwise, the output is "true."

The NOR gate is a combination OR gate followed by an inverter. Its output is "true" if both inputs are "false." Otherwise, the output is "false."

The XNOR (exclusive-NOR) gate is a combination XOR gate followed by an inverter. Its output is "true" if the inputs are the same, and"false" if the inputs are different.



Related Questions

How many amps are in a 3v battery?

Answers

in a 3 volt battery, there is 1 amp

Ipv6 includes a native information security framework (ipsec) that provides both data and control packets. true false

Answers

The statement that IPv6 includes a native information security framework (IPsec) that provides both data and control packets is false.
IPSec is a mandatory component for IPv6, and is used to natively protect IPv6 data as it is sent over the network,. and not control packets.
The IPv6 IPSec is a set of Internet standards that uses cryptographic security services to provide confidentiality ,data origin authentication and data integrity


What two types of icmp messages are received at the sending host executing the traceroute program?

Answers

Port unreachable and TTL (Time to Live) Expired messages are received at the sending host.

In cases when a packet reaches an end-host destined for a UDP port for which no host is associated, it generates an ICMP port unreachable in response. Also, an ICMP Port unreachable message can be generated in instances where the router could not find the server.

TTL expired on the other hand is used upon the execution of traceroute command. An ICMP message is sent out with a TTL value of 1 set in the IP header. The end host receiving a traceroute probe would send a TTL Expired ICMP when a single probe finally reaches it.






Final answer:

The "Time Exceeded" and "Destination Unreachable" messages are two types of ICMP messages received by a host running traceroute when a packet's TTL expires or the packet cannot be delivered.

Explanation:

The two types of ICMP messages received at the sending host executing the traceroute program are "Time Exceeded" messages and "Destination Unreachable" messages. The "Time Exceeded" message is received when a packet's time-to-live (TTL) value has reached zero before reaching its destination, prompting the intermediary router to send this message back to the source. The "Destination Unreachable" message is sent back if, for some reason, the packet could not be delivered to the destination host or if a communication port is not available.

Write a program that reads three numbers and prints "increasing" if they are in increasing order, "decreasing" if they are in decreasing order, and "neither" otherwise. here, "increasing" means "strictly increasing", with each value larger than its predecessor. the sequence 3 4 4 would not be considered increasing

Answers

You could assign values to variables and break it up into if else-if else statements.

Pseudocode:

if a < b and b < c:
    print("increasing")

else if a > b and b > c:
    print("decreasing")

else:
    print("neither")

Hope this helps.

Following are C++ programs to input value and print the message.

Program Explanation:

Defining header file.Defining the main method.Defining integer variable "a,b,c" that uses the input method to the input value.Defining if block that checks first variable value is less than second and third value, if it's true it will print "increasing" as a message.Defining else if block that checks second variable value is greater than first and third value, if it's true it will print "decreasing" as a message. In the else block, it will print the "neither" as a message.

Program:

#include <iostream>//header file

using namespace std;

int main()//main method

{

   int a,b,c;//defining integer variable

   cout<<"Enter numbers: "<<endl;//print message

   cin>>a>>b>>c;//imput value

   if (a < b && a < c)//using if block that check first variable value is less than second and third value

   {

   cout<<"increasing";//print message

   }

   else if(b>a&&b>c)//using else if block that check second variable value is greater than first and third value

   {

   cout<<"decreasing";//print message

   }

   else//else block

   {

   cout<<"neither";//print message

   }

   return 0;

}

Output:

Please find the attached file.

Learn more:

brainly.com/question/13143685

Blender questions
8. When adding objects, remember the object will always be placed at the position of the 3-D curser, so if the curser is off screen the object will also appear off screen. (1 point)

true

false



9. The 3-D curser is a powerful tool and a pivot point for all transformation. (1 point)

true

false

Answers

Blender questions
8. When adding objects, remember the object will always be placed at the position of the 3-D curser, so if the curser is off screen the object will also appear off screen. (1 point)

true

false

The correct answer is:
true



9. The 3-D curser is a powerful tool and a pivot point for all transformation. (1 point)

true

false

The correct answer is:
true
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