Answer:
hi there!
Explanation:
• Variation light and variation in temperatura
For me these are the problem, because they had to move some plant to the outdoors, because they don´t have enough space inside. So this changed of place could affect the plants.
Your lab group is experimenting with the diffusion of molecules across a membrane. Dialysis tubing is used as a model cell membrane, because is it semi-permeable, allowing small molecules to cross the membrane, but NOT larger molecules, like starch. A starch solution is placed in the dialysis tubing and then the dialysis tubing is placed in an iodine and water solution. Iodine is used as an indicator for the presence of starch. Normally, iodine is a yellow-brown color, but in the presence of starch, it turns a deep purple. After observing the experimental setup for 20 minutes, the iodine solution remains brown, but the starch solution inside the dialysis tubing is purple and swollen. Based on what you learned from the lab, starch is MOST likely to cross the cell membrane at which of the points indicated on the diagram? A) Starch crosses the cell membrane at A. B) Starch crosses the cell membrane at B. C) Starch crosses the cell membrane at D. D) Starch crosses the cell membrane at E.
Answer:
Starch crosses the cell membrane at E.
Explanation:
i did the USATestprep
Answer:
C) Starch requires ATP energy for transport and therefore cannot cross the dialysis tubing into the iodine solution.
Explanation:
I did the USAtestprep
Which statement is false? a. The number of double bonds in a fatty acid affects its melting point. b. Naturally occurring fatty acids usually have an even number of carbons. c. Wax esters contain long chain fatty acids and long chain alcohols. d. Triacylglycerols are polar due to their ester functional groups.
Answer:
d. Triacylglycerols are polar due to their ester functional groups.
Explanation:
Triacylglycerols are nonpolar due to the ester bond that forms between the glycerol polar hydroxyl (-OH) group and the fatty acid polar carboxylic acid (COOH) group. This leads to the release of a water molecule.
Which of the following might explain the lack of cloud formation? Choose one or more:
A. The air package rises too fast for condensation to occur.
B. It is too hot for adiabatic cooling to take place.
C. The air package never reaches its dew point.
D. There are too few aerosols present in the air package.
Answer:
The following might explain the lack of cloud formation
The air package never reaches its dew point. There are too few aerosols present in the air package.Explanation:
For the formation of the cloud the air in the higher position should have much colder than that of the surface. The vapours travels till it reaches the point where it has lower temperature as well as the pressure so that the water will condense into the droplets which will result in the formation of the cloud. When those vapours condenses to the liquid or to the solid it will release some of it energy to the air. For the formation of the cloud three things are mandatory and they are moisture, cooling air and the condensation nuclei. Also, for the formation of clouds, suspended particles like aerosols are required for the water to condense. As there are few aerosols, water doesn't get to condense.
The visceral and parietal pleural membranes are normally held together by
A. loose connective tissue.
B. dense connective tissue.
C. decreased pressure in the pleural cavity.
D. surfactant in the pleural cavity.
E. elastic connective tissue.
Answer:
C) decreased pressure in the pleural cavity.
Explanation:
The pleura is a membrane that surrounds the lung and consists of two membranes, the parietal and the visceral, which are continuous in the hilum region of the lung. The parietal and visceral membranes delimit, for each lung, an independent cavity fully lined by the mesothelium. Typically, this pleural cavity is virtual, containing only a thin layer of lubricating fluid (pleural fluid), allowing smooth sliding of these two membranes during respiration, preventing friction between the visceral and parietal mesothelium.
The visceral and parietal pleural membranes are usually held together due to decreased pressure in the pleural cavity.
The visceral and parietal pleural membranes are held together by the decreased pressure in the pleural cavity, enabling smooth lung function with minimal friction.
Explanation:The visceral and parietal pleural membranes are normally held together by decreased pressure in the pleural cavity. The pleural cavity, which surrounds the lungs, contains a small amount of fluid that allows the visceral and parietal layers of the pleura to slide effortlessly over each other with minimal friction, aiding in lung movement during breathing. This fluid and the resulting suction-like effect keep these membranes close together.
Comparing sequences between genes and between species allows evaluation of the rates of change. Which of the following have been observed: Select one or more:(A) introns have a higher mutation rate than exons.(B) non-synonymous mutations are found at a higher rate than synonymous mutations.
Answer:
A and B is correct.
Explanation:
Mutations are spontaneous variations to nucleotide sequences, therefore in two animals or two chromosomes they can not be identical by nature. Therefore, the introns interact with non-coding sequences and therefore their sequences are not established as consensus in nature and are therefore highly prone to mutations.
Hence both the statement are correct.
Answer:i think its b.)
Explanation:
It has been observed that cancer cells take in much more glucose than normal cells. In fact, labeled glucose can be used to detect cancerous tumors through PET scans. Explain the changes in the metabolism of cancer cells that cause them to use so much glucose. Include the following terms in your answer: flux, regulation, ATP, and oxygen.
Answer:
Explanation:
Cancer cells are characterized by higher proliferation and replication of cells than normal cells. This causes a high demand for energy and nutrients. Cancer cells also thrive under hypoxic or low oxygen environment and they depend highly on glucose consumption for ATP production, that it, glycolysis is the main pathway for generating energy. Glucose transporters (GLUT's) are integral membrane proteins that mediate the flux of glucose in cells and have been implicated in cancer. For example GLUT2 has been found to be up-regulated in human carcinoma cells.
What will happen to a red blood cell (RBC), which has an internal ion concentration of about 0.9 percent, if it is placed into a beaker of pure water?
Answer:
It wil swell and burst
Explanation:
"pure" water is only H2O so there are no solutes, because of osmosis, water will enter the red blood cell that does contain solutes until the cell and the surrounding environment (in this case the water) are iso-osmotic, this will never happen though because the water contains no solutes.
Which of the following is a true statement?
Mucus protects the stomach lining from digestive secretions.
Protease breaks down lipids into fatty acids and glycerol.
Lipase breaks down proteins in the small intestine.
Pepsin is an antibacterial agent that kills some bacteria.
Consider the cladogram representing most of the major categories of animals. Consider the point B in the cladogram. What characteristic might be used to separate the animals, beginning with the pigeon and moving to human, from the other animals?
A) contain jaws
B) endoskeleton with backbone
C) fur or hair
D) tetrapod
Answer: C. Fur is Hair
Explanation: i got it right
A woman heterozygous for A blood marries a man heterozygous for B blood.
What is the probability that they will produce offspring with AB blood?
a)0%
b)25%
c)50%
d)75%
Answer:
b) 25% is the right answer
Explanation:
A woman heterozygous for A blood group with genotype = Iᵃi
A man heterozygous for A with genotype = Iᵇi
so after cross between Iᵃ i x Iᵇ i
alleles man woman
Iᵃ i
Iᵇ IᵃIᵇ Iᵇi
i Iᵃi ii
so the offspring will be
25 % AB IᵃIᵇ 25 % A Iᵃi
25 % B Iᵇi 25 % O ii
The probability that a woman heterozygous for A blood and a man heterozygous for B blood will produce offspring with AB blood type is 25%.
Explanation:The subject of this question is genetics and it deals with the inheritance of blood types. For a woman heterozygous for blood type A (IAi) and a man heterozygous for B blood (IBi), their possible gametes (sperm and eggs) are IA, i and IB, i respectively. When we cross these possibilities, we get four possible combinations of genotypes in their offspring: IAIB (which is type AB Blood), IAi (Type A blood), IBi (Type B blood) and ii (Type O blood). Each of these outcomes has a 25% chance of occurring, because they are equally likely due to the principles of Mendelian genetics. Therefore the chance they will produce offspring with AB blood is 25%.
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Rhonda tells Jack that a solution is a type of mixture. Jack disagrees and responds that he does not think that a solution is a mixture.
Which explanation below explains who is correct?
A. Rhonda is correct because a solution is a type of mixture. It is a mixture because the substances are mixed together, and each substance loses its primary physical properties. The substances can each be easily seen.
B. Jack is correct because a solution is not a type of mixture. It is not a mixture because one of the substances settles at the bottom of the solution. Each substance keeps it primary physical properties.
C. Rhonda is correct because the substances keep their primary physical properties, but one dissolved into the other. Each substance is not easily seen.
D. Jack is correct because a solution is not a type of mixture because the substances stay mixed together and cannot be separated. Each substance loses its its primary physical properties.
Answer:
Jack is correct because a solution is not a type of mixture because the substances stay mixed together and cannot be separated. Each substance loses its primary physical properties.
Option: (D)
Explanation:
A mixture is composed of 'two or more different substances', physically combined and it is in the form of a solution, suspension or a colloid. A mixture may be homogeneous (salt and water) or heterogeneous (sand and water). A homogeneous mixture of two or more compounds is termed as solution. It has a solute and a solvent. The 'solute' is the substance dissolved in the solvent. Both lose their primary physical properties.At what point in the citric acid cycle do the methyl carbon from acetyl-CoA and the carbonyl carbon from oxaloacetate become chemically equivalent? Please reference specific steps in the citric acid cycle and draw structures of the intermediate in which the carbons are equivalent and the preceding molecule – labeling the inequivalent carbons.
Answer: at the formation of CITRATE
Explanation: details of the answer is in the attachments.
Citrate is a 6 Carbon compound formed from the reaction of methyl cabon of acetyl coAof(2c) and cabonyl carbon of oxaloacatate(4c).
The intermediate compound formed is CITRYL CoA.
_______ are involved in determining continuously varying or multiple factor traits.
Answer:
Polygene
Explanation:
Continuous variation occurs because of the effect of the combination of many genes (polygenes) which and is called polygenic inheritance. So in polygenic inheritance, each gene or trait contributes to the character. In discontinuous variation mainly alleles of a single gene are involved.
Polygenic trait inheritance can be influenced by the environment for example in cows the milk yield is not only affected by genes but also by environmental factors like weather, diet, etc. Some other examples of continuous variation are height, weight, shoe size, etc.
So polygenes are involved in determining multiple factor traits or continuous variation.
Which statement regarding ATP is false? Compared with other phosphate‑containing compounds in biochemistry, ATP has a higher free energy than nearly all of the others. Most enzymes that use ATP bind it in a form complexed with Mg2+. ATP concentrations in a cell are usually much higher than the equilibrium concentration for ATP hydrolysis. ATP can act as a group donor in adenylylation reactions.
Answer:
The correct answer will be option- ATP concentrations in a cell are usually much higher than the equilibrium concentration for ATP hydrolysis
Explanation:
Adenosine Triphosphate or ATP is known as the energy currency of the cell as it provides energy during the metabolic reactions.
The study on the structure of ATP revealed that it contains ribose sugar attached with three phosphates group bonded to each other via two phosphoanhydride bonds.
The metabolic reaction usually uses Magnesium bonded ATP as Magnesium covers the negative charge of the triphosphate which allows the ATP to bind hydrophobic clefts of the active site.
The ATP also transfers the adenyl group to the nucleophile which helps generate the pyrophosphate.
Which of the following statements about PCR is/are FALSE? There may be more than one correct answer.
A) PCR reactions contain DNA template, primers, deoxyribonucleotide triphosphates, and heat- resistant DNA polymerase
B) Each PCR cycle includes three steps: denaturation, annealing, and extension
C) After each PCR cycle, the amount of DNA increases in a linear manner
D) One limitation of PCR is that it requires prior knowledge of the sequence to be amplified
E) PCR is a very sensitive technique and can amplify target sequences present in extremely low copy number
F) The single-stranded DNA primers must anneal to opposite strands of template DNA at distant sites, with their 5′ ends directed toward each other
Answer: The answer is C
Explanation:
After each PCR cycle, the amount of DNA does not increase in a linear manner
Final answer:
The false statements about PCR are C) DNA increases linearly after each cycle, and F) primers must anneal at distant sites with 5' ends facing. In PCR, DNA increases exponentially, and primers anneal close to the target with 3' ends facing.
Explanation:
The student has asked which statements about Polymerase Chain Reaction (PCR) are false. The false statements are:
C) After each PCR cycle, the amount of DNA increases in a linear manner
F) The single-stranded DNA primers must anneal to opposite strands of template DNA at distant sites, with their 5′ ends directed toward each other
Statement C is false because the amount of DNA increases exponentially after each PCR cycle, not linearly. Each cycle doubles the amount of DNA being amplified. Statement F is also incorrect; the primers anneal to opposite strands of the template DNA at specific sites close to the target sequence, and they are oriented with their 3′ ends facing each other, not their 5′ ends.
PCR involves a cyclic process of denaturation, annealing, and extension which results in the exponential increase of the DNA target sequence. Heat-resistant DNA polymerase, such as Taq polymerase, is used for its ability to withstand the high temperatures needed for denaturation.
Increasing substrate concentration restores enzyme activity that has been blocked by ____(A) a noncompetitive inhibitor only.(B) neither a competitive nor a noncompetitive inhibitor.(C) both a competitive and a noncompetitive inhibitor.(D) a competitive inhibitor only.
Answer: Option D
Explanation: The structure of a competitive inhibitor resembles that of the substrate. It may thus combine with the enzyme to form enzyme-inhibitor (EI) complex rather than enzyme-substrate (ES) complex . However, increasing the substrate concentration and keeping the inhibitor concentration constant restores enzyme activity: as the active site releases the bound inhibitor to bind with the substrate.
I hope this helps
Increasing substrate concentration can only restore enzyme activity blocked by a competitive inhibitor, as this type of inhibition is reversible and concentration-dependent. Noncompetitive inhibitors bind to a different site and are not influenced by substrate concentration.
Explanation:Increasing substrate concentration restores enzyme activity that has been blocked by (D) a competitive inhibitor only. A competitive inhibitor binds reversibly to the enzyme's active site, competing with the substrate. Since both the substrate and inhibitor are competing for the same site, the presence of more substrate increases the chance that the substrate will bind instead of the inhibitor. This competition is concentration-dependent, and inhibition can be completely reversed by sufficiently increasing the substrate concentration.
On the other hand, a noncompetitive inhibitor binds to a different site on the enzyme, causing a conformational change that affects the active site and hence enzyme activity. Substrate concentration increases do not affect the binding of a noncompetitive inhibitor, so enzyme activity is not restored by increasing substrate concentration in the presence of a noncompetitive inhibitor.
Which of the following is true when describing the permissive effect of a hormone?a) a permissive hormone can cancel out the effect of another hormoneb) this means that two hormones have a greater effect than just onec) the hormone can act alone when having an effect on a tissued) is usually the result of a second hormone's exposure on target cells
Answer:
The correct answer is d) is usually the result of a second hormone's exposure on target cells
Explanation:
Permissiveness is described as the situation in which one hormone is not able to exert its full effect on the target cell and it requires the presence of another hormone to exert its full potential on the target cell.
Therefore the permissive effect is usually the result of the secondary hormone's presence or exposure on target cells. For example, thyroid hormone increases the effect of epinephrine on target cells by increasing its receptors on the target cell.
Without thyroid hormone, the epinephrine can not exert full effect on its target cell. Therefore the right answer is d.
Hormones mediate changes in target cells by binding to specific hormone receptors. The number of receptors that respond to a hormone determines the cell's sensitivity to that hormone. In the context of permissive effect, one hormone enhances the effect of another hormone.
Explanation:Hormones mediate changes in target cells by binding to specific hormone receptors. In this way, even though hormones circulate throughout the body and come into contact with many different cell types, they only affect cells that possess the necessary receptors. Receptors for a specific hormone may be found on many different cells or may be limited to a small number of specialized cells.
The number of receptors that respond to a hormone determines the cell's sensitivity to that hormone, and the resulting cellular response. Additionally, the number of receptors that respond to a hormone can change over time, resulting in increased or decreased cell sensitivity. In up-regulation, the number of receptors increases in response to rising hormone levels, making the cell more sensitive to the hormone and allowing for more cellular activity. When the number of receptors decreases in response to rising hormone levels, called down-regulation, cellular activity is reduced.
In the context of permissive effect, when one hormone has a permissive effect on another hormone, it means that the presence of the permissive hormone enhances the effect of the other hormone. It allows the other hormone to have a greater effect than it would have on its own. This is an example of the interaction between different hormones and their receptors in target cells.
What is the process of converting energy from a light - excited electron into ATP
Answer:
Photosynthesis
Explanation:
Photosynthesis is the process in which the energy will be converted from the light exited electron to phosphorylate the bond of ADP molecule to ATP.
Complex I, also called NADH dehydrogenase, is an entry point for electrons to the electron transport chain. Complex I transfers electrons from NADH to Q. The reduction of Q is linked to the active transport of protons out of the matrix. How many protons does complex I pump into the intermembrane space?
Final answer:
Complex I, or NADH dehydrogenase, of the electron transport chain pumps four protons into the intermembrane space for every two electrons it receives from NADH.
Explanation:
Complex I, also known as NADH dehydrogenase, is a crucial component of the electron transport chain in cellular respiration. Its role is to transfer electrons from NADH to coenzyme Q (ubiquinone), facilitating the conversion of ubiquinone to ubiquinol. Through the process of electron transfer, Complex I is able to pump protons from the mitochondrial matrix into the intermembrane space, thus contributing to the proton gradient used for ATP synthesis.
Importantly, Complex I is responsible for the translocation of four protons across the inner mitochondrial membrane for every two electrons it receives from NADH. This active transport of protons is crucial for the establishment and maintenance of the proton motive force that drives ATP synthesis via ATP synthase.
Kathy has been an administrative assistant for many years and spends many hours per day using the computer keyboard. She has recently been complaining about a burning sensation in her middle finger that sometimes extends to her elbow. Her doctor gave her a splint to wear on her wrist to immobilize it while she types. What condition is he attempting to treat
Answer: The Doctor is treating her for Carpal tunnel syndrome (CTS). It can be treated with Non Steroidal Anti-inflammatory Drugs (NSAIDS) and pain relief drugs
Explanation:
Carpal Tunnel Syndrome (CTS) is a disorder which is caused by the compression of the median nerve located in the wrist. As Kathy continually types on the keyboard the median nerve is being compressed for a longer time causing inflammation.
Carpal Tunnel is an area in the wrist where bones and ligaments create a small passage way for the median nerve. Carpal Tunnel Syndrome is therefore caused by the compression of the median nerve in the wrist. The symptoms include feelings of numbness, tingling, burning sensation over the surface of the thumb, forefinger, middle finger, half of the ring finger some feel pains from the wrist up to the arm.
They can be treated with Non Steroidal Anti-inflammatory Drugs (NSAIDS) and ibuprofen to treat the inflammation and for pain relief.
The doctor's use of a wrist splint to treat Kathy's symptoms is consistent with the management of Carpal Tunnel Syndrome, which is caused by compression of the median nerve.
Explanation:The doctor is treating Kathy for symptoms that are indicative of Carpal Tunnel Syndrome (CTS), a condition caused by the compression of the median nerve in the wrist. The use of a wrist splint aims to stabilize the wrist and minimize pressure on the nerve to relieve symptoms such as the burning sensation in Kathy's middle finger that extends to the elbow.
Contrasting this condition, tendinitis is another type of repetitive strain injury that could cause similar symptoms but has different treatment protocols, typically involving rest, icing, and anti-inflammatory medications. Carpal Tunnel Syndrome and its management often include using splints, corticosteroid injections, and surgery for more severe cases.
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Select the phrases that accurately describe properties of the most common form of the DNA double helix. a. The phosphodiester bonds between nucleotide residues run in opposite directions in the two strands. b. The sugar–phosphate backbone is exposed to the solvent, whereas the nitrogenous bases are in the interior of the double helix. c. Base pairs have a spacing of . d. A helical turn consists of about . e. DNA contains equal amounts of adenine and guanine (the purines) and equal amounts of cytosine and thymine (the pyrimidines).
The sugar and phosphate bond is placed outward of the DNA towards the solvent and the base of nitrogen is inside the helix.
Explanation:
The edges that are outward to the double helix formation of DNA are composed by sugar and phosphate molecules and make the backbone.
These two strands of DNA is placed in the opposite direction from the helix. But the nitrogen base is there inside the helix. It shapes like a ladder rung because of the hydrogen bond. This bond keeps the backbone held together.
Which of the following is true of stem cells? See Concept 20.3 (Page 429)
They can reproduce indefinitely in culture.
They can be found in both embryonic and adult tissues.
Their use is highly controversial.
They can differentiate to produce many different kinds of specialized cells.
All of the above.
Answer:
The correct answer is option - all of the above.
Explanation:
Stem cells are the cells that have the ability to differentiate and develop into all kinds of cells in the body of an individual organism. These cells helpful in several functions like developing cells of various types and repair them. Stem cells can be embryonic and adult stem cells.
These cells can be grow culture with proper media and result in reproduce indefinitely. Use of stem cells are consider as unethical by various researchers, communities and scientists
Thus, the correct answer is option - all of the above.
Answer:
The correct answer is- All of the above
Explanation:
Stem cells are the undifferentiated cells that can differentiate into different and specific types of cells. They can be found in embryo and in adults. The embryonic stem cell can form all the cell of the body as they are pluripotent but adult stem cell mainly differentiates into a particular type of cell.
Due to having inherent properties stem cells can reproduce indefinitely in a culture medium. There use is highly controversial because they can be used to develop human embryo unethically therefore most controversy occurs on the use of embryonic cells. So the correct answer is- all of the above.
How can a tumor suppressor gene lose its function? Check all that apply
a. Duplication
b. Aneuploidy leading to loss of the tumor suppressor gene
c. Aberrant DNA methylation
d. Gene mutation
Explanation:
Antioncogenes also called as tumor suppressor genes. The cell proliferation is controlled negatively by tumor suppressor genes. Antioncogenes maintains the replication and division process of cell. The antioncogenes prevent uncontrollable growth of cell. The mutation in the gene can lead to cancer.
The gene mutation can cause tumor suppressor gene to lose its function. The mutation in the tumor suppressor genes will code for certain proteins with loss of function in tumor suppression.
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After eating lettuce contaminated with EHEC (E. coli) , what physical/chemical barriers to infection will the pathogen encounter en route to the intestine and once it reaches the intestine, but before it can attach to epithelial cells of the intestine?
Choose all the correct options below:a. Defensinsb. Cytolytic T-cellsc. Activated macrophagesd. Perforinse. Lysozymef. Mucing. Stomach acidh. IgGi. gut microbiotaj. tight junctions of gastrointestinal epithelial layers
Defensins, lysozymes, mucin, stomach acid, gut microbiota, tight junctions of gastrointenstinal epithelial cells are the physical/chemical barriers to infection will the pathogen encounter en route to the intestine and once it reaches the intestine after eating lettuce contaminated with EHEC
Explanation:
The enterohemorrhagic strain of Escherichia coli (EHEC) grows in the intestines, produces the highly potent Shiga toxin. E.coli is a foodborne pathogen.
Innate immunity acts against the EHEC pathogens through physical and chemical barriers with certain non-specific responses.
Physical barriers include skin and mucous membrane. Chemical barriers include stomach acid, lysozyme, defensin.
Tight junctions are the watertight regions lining the gastrointestinal mucosal surface with tightly packed epithelial cells which prevent the flow of E. coli bacteria between the host compartments.
The mucous membranes covered with tight junctions secrete mucin and lysozyme.
Mucin blocks the pathogen’s ability to attach to the cell surfaces and thereby inhibits its invasion.
Lysozymes are mucosal enzymes which act against the pathogens trying to adhere to the gut epithelium.
Defensins are peptides that attack the cytoplasmic membrane of the pathogens and kill them
Stomach acid (HCl) reduces the pH of the gut and maintains an acidic environment, and thereby inhibits the entry of foodborne pathogens
Gut microbes are commensal organisms that aid immunity by:
Colonization and creating competition for space and food Secreting toxins which can kill the pathogenic organismsDuring the second set of photosynthetic reactions, called the Calvin cycle, all BUT ONE of the following occurs. A) Glucose is the end product of the Calvin cycle. B) By-products of the Calvin cycle include water vapor and oxygen. C) Carbon dioxide, a reactant of photo synthesis, is utilized during the Calvin cycle. D) ATP and NADPH, high energy molecules, are utilized to produce stored chemical energy.
Explanation:
False: B) By-products of the Calvin cycle include water vapor and oxygen
Photosynthesis is a chemical pathway that’s integral to producing energy in plants and other primary producers. Energy in the form of molecules of glucose is produced from light, water and carbon dioxide while oxygen (from the light reaction) is released.
Further Explanation:
This occurs in several complex steps, photosynthesis is a rate limited reaction, depends on several factors including carbon dioxide concentration, ambient temperature and light intensity; the energy is retrieved from photons, I.e. particles of light, and water is used as a reducing agent. This begins in the thykaloids, where pigment molecules like chlorophyll reside.
The chloroplast is a membrane-bound organelle found in plants. It contains several invaginations of a plasma membrane called the thylakoid membrane. This contains chlorophyll pigments, in stacks called granum, while the internal spaces of the organelle are called the lumen. Liquid surrounds the granum, forming the stroma.
Here, water is used as a reducing agent.
6CO2 + 6H20 + (energy) → C6H12O6 + 6O2
Carbon dioxide + water + energy= glucose + oxygen
Water supplies the chlorophyll in plant cell with replacement electrons for the ones removed from photosystem II. Additionally, water (H2O) split by light during photolysis into H+ and OH- acts as a source of oxygen along with functioning as a reducing agent; it reduces the molecule NADP to NADPH by providing H+ ions. NADP and NADPH are integral to the Calvin cycle where monosaccharides or sugars like glucose are produced after the modification of several molecules.
In the Calvin Cycle:
During the initial stage, three molecules of ribulose bisphosphate, RuBP are reduced and carbon is fixed from an inorganic CO2 to an organic form by the enzyme RuBisCO. With every molecule of CO2 fixed, 2 molecules of 3-phosphoglyceric acid are produced. 3-PGA is a 3 carbon molecule with a phosphate attached. Next, NADPH and ATP facilitate the addition of electrons to or reduction of 6 molecules of 3PGA to 6 molecules of G3P (glyeraldehyde 3-phosphate). The process uses 6 molecules of ATP and 6 of NADPH, after which the conversion of NADPH and ATP to ADP and NADP+ occur; these are returned to the light dependent reactions. A molecule of G3P, goes to the cytoplasm from this cycle, to form other complex molecules. Fixing sufficient carbon for this G3P export requires 3 revolutions of the cycle. Since two molecules of G3P are made per revolution, 3 turns make 6 G3Ps; 5 of these are used to regenerate RuBP for further fixation.Thus... no [tex]H_{2} O[/tex] or [tex]O_{2}[/tex] are produced...
Respiration in the mitochondria utilizes the oxygen waste for the production of ATP in the Krebs’s cycle via the oxidization of pyruvate( through the process of glycoysis). The electron transport chain, in which oxygen functions as the terminal electron acceptor occurs in both plants and animals.
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During the Calvin cycle, glucose is produced, carbon dioxide is utilized, and ATP and NADPH are used to create stored energy. However, water vapor and oxygen are not by-products of this part of photosynthesis.
Explanation:In the second set of photosynthetic reactions, the Calvin cycle, three important processes occur but one does not. A) Glucose is indeed the end product of the Calvin cycle. C) Carbon dioxide, a reactant of photosynthesis, is utilized during the Calvin cycle. D) ATP and NADPH, high energy molecules, are utilized to produce stored chemical energy. However, B) the by-products of the Calvin cycle are NOT water vapor and oxygen. These are the products of the light-dependent reactions of photosynthesis, not the Calvin cycle.
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Which of the following indicates that a muscle fiber is relaxed?
ATP molecules are bound to the heads of the myosin filaments.
Myosin heads are attached to actin filaments, forming cross bridges.
Calcium ions are bound to troponin, causing the protein to change shape.
Z lines are pulled toward the center of the sarcomere.
ATP molecules are bound to the heads of the myosin filaments
In relaxed form of the sarcomere, ATP is bound to its site on the myosin heads. It is when the ATP is hydrolyzed to ADP and Pi that the mysoin forms a cross ridge with the actin fiber. Upon hydrolysis the ADP + Pi exits the site and another ATP binds. This again causes the myosin head to disengage the actin fiber and the cycle is repeated.
Explanation:
During contraction of muscle calcium ions are usually released from their sarcoplasmic reticulum where they bind to troponin enabling tropomyosin to be exposed such that myosin can bind. Contraction of sarcomere causes the z lines to move closer together.
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The characters of "seed color" and "seed shape" showed independent assortment in Mendel's experiments because
A. the genes for these two characters were very close together on the same chromosome
B. these two characters were the product of the same gene
C. the genes for these two characters were on different chromosomes
D. the genes for both characters were sex-linked
E. either answer A or B could be correct
Answer:
C. the genes for these two characters were on different chromosomes
Explanation:
Mendel conducted several experiments with peas to demonstrate the mechanisms of heredity. He decided to use peas because they self-fertilize, have a short life cycle, are easily grown and produce large numbers of offspring. Peas, in addition to the advantages already mentioned, have simple characteristics to observe, such as the color and shape of the seed. Mendel analyzed seven of these characteristics that had no intermediates: seed texture, seed color, seed coat color, pod shape, pod color, flower position, and plant height.
Through his study, Mendel concluded that the characters "seed color" and "seed shape" showed an independent variety. This is because the genes related to these two traits are distant from each other in the chromosome and therefore have no dependence between them.
A child was in a diving accident. When brought into the emergency room, the doctor used sharp and blunt objects to determine if there was any sensation on the bottom of the foot and the lateral aspect of their palm. The child stated they could not feel the stimulus in either area. What nerves were most likely damaged?
Answer:
S1 and S3
Explanation:
The spine is composed of 33 vertebrae and has 31 pairs of nerves that are distributed throughout the body in an organized manner. Each nerve that leaves the spine is responsible for imparting sensitivity and strength to a particular area of the body, so whenever there is a compression or cut of a nerve, a particular area of the body is compromised.
When a person has a feeling of numbness in the foot, as shown in the above question, it is more likely that there is a change in the spine, specifically in the nerves S1 and S3. This is because nerve S1 is responsible for eversion of the foot, while nerve S3 is responsible for the intrinsic muscles of the foot.
You have added an irreversible inhibitor to a sample of enzyme and substrate. At this point, the reaction has stopped completely. What can you do to regain the activity of the enzyme? a. Removing the irreversible inhibitor should get the reaction working again.
b. Adding more substrate will increase the rate of reaction.
c. Adding more inhibitor should get the reaction up to speed again.
d. The enzyme is inactive at this point. New enzyme must be added to regain enzyme activity.
Answer:
The correct answer is d. The enzyme is inactive at this point. New enzyme must be added to regain enzyme activity.
Explanation:
This is because the inhibitor is irreversible, meaning that the enzyme is permanently modified, therefore, even if more substrate is added, the enzyme will no longer be able to work properly. If all of the inhibitor is consumed, adding more enzyme would regain the activity of the enzyme.
Irreversible inhibitor permanently inactivates enzymes. Removing the inhibitor, or adding more substrate or inhibitor will not recommence the enzyme’s activity. Only fresh, active enzyme will increase the rate of reaction.
Explanation:In biochemistry, an irreversible inhibitor permanently binds to an enzyme, rendering it incapable of catalyzing a reaction. As a consequence, the enzyme cannot regain its original function once it has encountered an irreversible inhibitor. Therefore, removing the irreversible inhibitor, adding more substrate or adding more inhibitor will not resurrect the enzyme’s activity.
The best answer is option D: The enzyme is inactive at this point. New enzyme must be added to regain enzyme activity. To increase the rate of reaction, fresh, active enzyme must be introduced to the system.
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Cellular respiration uses one molecules of glucose to produce approximately ___ molecules of ATP.
A. 36
B. 2
C. 4
D. 24
E. 12
Answer: 2 ATPs
Explanation:
In the overall reaction, glycolysis converts one six-carbon molecule of glucose into two three-carbon molecules of pyruvate.
The net products of this process are two molecules of ATP ( 4 ATP produced − 2 ATP used up).
Cellular respiration uses one molecules of glucose to produce approximately 36 molecules of ATP
What is cellular respirationDuring cellular respiration, one molecule of glucose is used to produce approximately 36 molecules of ATP (adenosine triphosphate). ATP is the energy currency of cells and is synthesized through the process of cellular respiration.
Although the exact number of ATP molecules produced can vary slightly depending on the specific conditions and efficiency of cellular respiration, the approximate yield of ATP from one glucose molecule is commonly estimated as 36 molecules.
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