Identify each substance as an acid or a base.
liquid drain cleaner, pH 13.5
milk, pH 6.6
DONE
Intro

Answer:

given that

....the mass of the metal is 20g(0.02kg)

....specific heat capacity(c) is 0.4J/g°C

....ΔT=??

heat(Q)=3.9KJ(3900J)

Q=mcΔT

ΔT= Q/mc

.....=3900÷(20g x 0.4J/g°C)

.....=487.5°C

Using the heat transfer formula Q = mcΔT, the change in temperature is calculated to be 487.5 °C. The metal absorbs 3.9 kJ of heat and has a specific heat capacity of 0.4 J/g°C.

To find the change in temperature for the 20 g piece of metal, we'll use the heat transfer formula:

Where:

Given:

Rearrange the formula to solve for ΔT:

Substitute the given values:

The change in temperature for the metal piece, given the provided data, is 487.5 °C.

Answer:

1 - 3

Explanation:

- Look to see where metals are on the periodic table then look at what group they are in. The group tells you the number of valence electrons. Ex. 1A has one valence electron.

- Hope this helped! If you need a further explanation please let me know.

The theoretical mass of ammonia is 56.6 grams when reaction is begun with 10.00 grams of each reactant.

Explanation:

Data given:

mass of reactants = 10 gram

The reactants are hydrogen and nitrogen gas.

Theoretical mass of ammonia =?

balanced chemical reaction is :

3 [tex]H_{2}[/tex] + [tex]N_{2}[/tex] ⇒ 2 N[tex]H_{3}[/tex]

Atomic mass of hydrogen gas = 2 grams/mole

atomic mass of nitrogen gas = 28 grams/mole

number of moles of each reactant is determined:

number of moles  = [tex]\frac{mass}{atomic mass of 1 mole}[/tex]

putting the values for hydrogen gas

number of moles = [tex]\frac{10}{2}[/tex]

number of moles = 5

number of moles of nitrogen gas = [tex]\frac{10}{28}[/tex]

                                                       = 0.35 moles

from the balanced equation,

3 moles of hydrogen gas reacted to give 2 moles of ammonia

5 moles of hydrogen will give x moles

[tex]\frac{2}{3}[/tex] = [tex]\frac{x}{5}[/tex]

3x =10

x = 3.33 moles

mass of ammonia produced = number of moles x atomic mass

                                               = 3.33 x 17

                                                 = 56.61 grams of ammonia produced from hydrogen

For nitrogen gas,

1 mole nitrogen gas reacted to give 2 moles of ammonia gas

0.35 moles will give x moles

[tex]\frac{2}{1} =\frac{x}{0.35}[/tex]

x = 0.7 moles of ammonia formed

mass = number of moles x atomic mass

         = 0.7 x 17

           = 11.9 grams

Thus the limiting reagent is hydrogen gas in the reaction.

The mass from limiting reagent is called theoretical yield = 56.61 grams

Answer:

The answer to your question is False

Explanation:

Chemical reaction

                               4Br  +  K    ⇒     4BrK

                     Reactants     Elements     Products

                            4             Bromine             4

                            1              Potassium          4

This chemical reaction is unbalanced because the number of Potassium in the reactants is lower than the number of Potassium in the products.

Correct balanced reaction

                               Br₂  +  2K  ⇒   2KBr

Answer:

The purpose of a cell wall is to keep everything inside safe.

Answer:

The CORRECT answer is C. it supports and protects the cell

Explanation:

I just did a assignment and yes this is correct think about it it is called the cell WALL. hope this helps :)

Answer:

decreased osmolality of extracellular fluids

Explanation:

When there is decreased osmolality of extracellular fluids, there will be Volume depletion, or extracellular fluid (ECF) volume contraction, which occurs as a result of loss of total body sodium. Causes include vomiting, excessive sweating, diarrhea, burns, diuretic use, and kidney failure. In this way, sodium loss always causes water loss.

Answer:

PCI3

Mass ratio = 3:10

And Atomic ratio = 1:3

Hope it will help.

This is an incomplete question, here is a complete question.

Hydrogen azide, HN₃, decomposes on heating by thefollowing unbalanced reaction:

[tex]HN_3(g)\rightarrow N_2(g)+H_2(g)[/tex]

If 3.0 atm of pure HN₃ (g) is decomposed initially,what is the final total pressure in the reaction container? Whatare the partial pressures of nitrogen and hydrogen gas? Assume thatthe volume and temperature of the reaction container are constant.

Answer : The partial pressure of [tex]N_2[/tex] and [tex]H_2[/tex] gases are, 4.5 atm and 1.5 atm respectively.

Explanation :

The given unbalanced chemical reaction is:

[tex]HN_3(g)\rightarrow N_2(g)+H_2(g)[/tex]

This reaction is an unbalanced chemical reaction because in this reaction number of hydrogen and nitrogen atoms are not balanced on both side of the reaction.

In order to balance the chemical equation, the coefficient '2' put before the [tex]HN_3[/tex] and the coefficient '3' put before the [tex]N_2[/tex] then we get the balanced chemical equation.

The balanced chemical reaction will be,

[tex]2HN_3(g)\rightarrow 3N_2(g)+H_2(g)[/tex]

As we are given:

The pressure of pure [tex]HN_3[/tex] = 3.0 atm

[tex]p_{Total}=2\times p_{HN_3}=2\times 3.0atm=6.0atm[/tex]

From the reaction we conclude that:

Number of moles of [tex]N_2[/tex] = 3 mol

Number of moles of [tex]H_2[/tex] = 1 mol

Now we have to calculate the mole fraction of [tex]N_2[/tex] and [tex]H_2[/tex]

[tex]\text{Mole fraction of }N_2=\frac{\text{Moles of }N_2}{\text{Moles of }N_2+\text{Moles of }H_2}=\frac{3}{3+1}=0.75[/tex]

and,

[tex]\text{Mole fraction of }H_2=\frac{\text{Moles of }H_2}{\text{Moles of }N_2+\text{Moles of }H_2}=\frac{1}{3+1}=0.25[/tex]

Now we have to calculate the partial pressure of [tex]N_2[/tex] and [tex]H_2[/tex]

According to the Raoult's law,

[tex]p_i=X_i\times p_T[/tex]

where,

[tex]p_i[/tex] = partial pressure of gas

[tex]p_T[/tex] = total pressure of gas  = 6.0 atm

[tex]X_i[/tex] = mole fraction of gas

[tex]p_{N_2}=X_{N_2}\times p_T[/tex]

[tex]p_{N_2}=0.75\times 6.0atm=4.5atm[/tex]

and,

[tex]p_{H_2}=X_{H_2}\times p_T[/tex]

[tex]p_{H_2}=0.25\times 6.0atm=1.5atm[/tex]

Thus, the partial pressure of [tex]N_2[/tex] and [tex]H_2[/tex] gases are, 4.5 atm and 1.5 atm respectively.

The final total pressure in the reaction container remains the same as the initial pressure. The partial pressure of nitrogen gas is 1.15 M multiplied by the total pressure, and the partial pressure of hydrogen gas is three times the partial pressure of nitrogen gas.

To determine the final total pressure and partial pressures of nitrogen and hydrogen gas in the reaction container, we need to use the given information about the equilibrium mixture. From the information provided, the equilibrium mixture at 500 °C contains 1.35 M H2, 1.15 MN2, and 4.12 x 10-1 M NH3.  

Since the volume and temperature of the container are constant, the total pressure in the container remains the same as the initial pressure of 3.0 atm.

The partial pressure of nitrogen gas (N2) can be calculated using its molar concentration and the total pressure using Dalton's law of partial pressures. According to the balanced equation N2(g) + 3H2(g) = 2NH3(g), the moles of N2(g) are equal to the moles of NH3(g). Therefore, the partial pressure of N2(g) is 1.15 M multiplied by the total pressure of 3.0 atm.

The partial pressure of hydrogen gas (H2) can be calculated using its molar concentration and the total pressure. Since there are three moles of H2(g) for each mole of NH3(g) according to the balanced equation, the partial pressure of H2(g) is 3 times the partial pressure of N2(g).

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Answer:

The mass of the air is 6920.71g

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Volume (V) = 5.0x10^3 L

Molar Mass of air (M) = 28.98 g/mol

Temperature (T) = 0.2°C

Pressure (P) = 1.07 atm

mass air (m) =?

Number of mole (n) =?

Recall:

Gas constant (R) = 0.082atm.L/Kmol

Step 2:

Conversion of celsius temperature to Kelvin temperature.

K = °C + 273

°C = 0.2°C

K = °C + 273

K = 0.2°C + 273

K = 273.2 K

Therefore, the temperature (T) = 273.2 K

Step 3:

Determination of the number of mole of air.

Applying the ideal gas equation PV = nRT, the number of mole n, can be obtained as follow:

PV = nRT

1.07 x 5.0x10^3 = n x 0.082 x 273.2

Divide both side by 0.082 x 273.2

n = (1.07 x 5.0x10^3)/(0.082 x 273.2)

n = 238.81 moles

Step 4:

Determination of the mass of air. This is illustrated below:

Number of mole of air = 238.81 moles

Molar Mass of air = 28.98 g/mol

Mass of air =.?

Mass = number of mole x molar Mass

Mass of air = 238.81 x 28.98

Mass of air = 6920.71g

Answer:

The answer to your question is C₂H₆O

Explanation:

Data

Molecular formula = C₆H₁₈O₃

Empirical formula = ?

Empirical formula is defined as the simplest ratio of the elements that form part of a molecule.

Process

To find the empirical formula find the greatest common factor of the subscripts.

                             6    18   3   2

                             3      9  3   3

                              1     3    1   3

                                     1

The GCF is 3, so factor 3 of the molecular formula

                         3 ( C₂H₆O)  

The result is the empirical formula C₂H₆O

Final answer:

The empirical formula for C6H18O3 is found by dividing the subscripts by their greatest common divisor, which in this case is 3. This yields C2H6O as the simplest whole-number ratio of the elements in the compound.

Explanation:

The empirical formula of a compound is the simplest whole-number ratio of atoms of each element in the compound. To determine the empirical formula for C6H18O3, we must find the greatest common divisor of the subscript numbers and divide them by that number. The greatest common divisor of 6, 18, and 3 is 3, so we divide each subscript by 3 to get the simplest ratio.

Dividing each subscript by 3, we get:

Carbon (C): 6 ÷ 3 = 2

Hydrogen (H): 18 ÷ 3 = 6

Oxygen (O): 3 ÷ 3 = 1

Therefore, the empirical formula is C2H6O.

Answer:

CO2 consists of individual molecules with one central carbon atom double bonded to two oxygen atoms. Silicon does not form double bonds with oxygen. CO2 is gas but SiO2 is a solid because SiO2 has a giant molecular structure. CO2 has a simple molecular structure, and because of this, CO2 is gas but SiO2 is solid at room temperature.

Answer:

Explanation:

Because of their structure . Silica has a  chain structure with e one silicon atom bonded to 4 oxygen atoms in the lattice. The structure is a long chain of tightly held atoms and this forms a solid.

The carbon dioxide molecule however as a linear structure and each  oxygen atom is bonded by double bonds. These double bonds are not as strong as the Si - O bonds in silica so will not form a chain structure.

Answer:

6.37 L

Explanation:

- Used combined gas law. Get rid of temperature since it is constant. (You could also keep it and get the same answer, but it is another step)

- Change C to K

- Change torr to atm

- Hope this helps! I would be glad to give you a step by step explanation. Please let me know if you want help on how to do these types of problems.

Answer: C

Explanation: This is what my mastering said

16H+(aq)+2MnO4-(aq)+10I-(aq)→5I2(aq)+2Mn2+(aq)+8H2O(l):

Ecell0 = +0.97 V.

The balanced equation is 16H⁺(aq)+2MnO₄⁻(aq)+10I⁻(aq)→5I₂(aq)+2Mn²⁺(aq)+8H₂O(l). The cell potential is Ecell0 = +0.97 V. The correct option is option C.

The potential difference of two half cells inside an electrochemical cell is measured by the cell potential, or Ecell. The capacity of electrons to go from one half cell to another is what determines the potential difference.

When one chemical is reduced and another is oxidized, a redox reaction takes place. The material loses one or maybe more electrons during oxidation, becoming positively charged as a result. In contrast, the material picks up electrons during reduction and then becomes negatively charged.

E cell = E° cathode -  E° anode

         = 1.51 - 0.54 V

          = 0.97 V

The balanced equation is 16H⁺(aq)+2MnO₄⁻(aq)+10I⁻(aq)→5I₂(aq)+2Mn²⁺(aq)+8H₂O(l).

Therefore, the correct option is option C.

To know more about cell potential, here:

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Answer:

C. Double Replacement

Explanation:

A. Wrong because SR uses a compound and element. This equation is a compound and compound.

B. Wrong because it does not have O2 in the formula. All combustion reactions must have O2.

C. Correct because it is a compound reacting with a compound.

D. Wrong because the reactants did not form a single product. ex. (x + y > xy)

E. Wrong because the equation did not start with a single compound and break down. ex. (xy > x + y)

The missing coefficients for the given chemical equation are found by balancing Al, SO₄, K, and OH groups, resulting in a balanced equation representing a double replacement reaction: Al₂(SO₄)₃(aq) + 6 KOH(aq)
ightarrow 2 Al(OH)₃(aq) + 3 K₂SO₄(aq).

The reaction in question is a classic example of a double replacement reaction, where the cations and anions of two ionic compounds switch places, forming two new compounds. To balance the skeleton equation, we should find the correct stoichiometric coefficients that maintain the conservation of mass for each element.

Start by writing the unbalanced equation with all reactants and products including their states:

Al₂(SO₄)₃(aq) + KOH(aq)
ightarrow Al(OH)₃(aq) + K₂SO₄(aq)

Now balance the elements step by step:

This yields the balanced chemical equation:

Al₂(SO₄)₃(aq) + 6 KOH(aq)
ightarrow 2 Al(OH)₃(aq) + 3 K₂SO₄(aq)

The type of reaction for the balance is option C, which is double replacement.

Answer:

chemical change

Explanation:

signs of a chemical change are a change in color and the formation of bubbles. The five conditions of chemical change: color change, formation of a precipitate, formation of a gas, odor change, temperature change.

Give me brainliest plz

CH₄ is the molecular formula for methane. The correct option is (C) molecular.

To answer the question, let's first understand what the different terms mean:

This means that CH₄ indicates the composition of a methane molecule, showing it consists of one carbon atom and four hydrogen atoms. It does not show how the atoms are bonded or arranged.

The new volume of the balloon is approximately 2.33 liters when additional helium is added.

To find the new volume of the balloon, we can use Avogadro's Law, which states that the volume of a gas is directly proportional to the number of moles of gas, provided the temperature and pressure are constant. The formula for Avogadro's Law is:

[tex]\frac{V_1}{n_1} = \frac{V_2}{n_2}[/tex]

where:

We can rearrange the formula to solve for V2:

V2 = (V1 * n2) / n1

Substituting the values, we get:

[tex]V_2 = \frac{(1.90 \, \text{L} \times 0.1130 \, \text{mol})}{0.0920 \, \text{mol}}[/tex]

V2 ≈ 2.33 L

Therefore, the new volume of the balloon is approximately 2.33 liters.

Answer:

Carbohydrates are metabolized by three pathways which are glycolytic pathway, oxidation of fatty acids, and the citric acid cycle. The NADH and FADH2 formed in these pathways are energy rich molecules because each contains a pair of electrons having a high transfer potential. When these electrons are used to reduced molecular oxygen to water, a large amount of free energy is liberated which is used to generate ATP. This process is known as oxidative phosphorylation.

Explanation:

There are two type of reaction that takes place in oxidative phosphorylation which are oxidation and reduction.

First, carbon fuels are oxidized in the citric acid to yield electrons with high transfer potential. Then, this electron motives force is converted into a proton motive force and this proton motive force is finally converted into phoshoryl transfer potential. The final phase of oxidative phosphorylation is carried out by ATP synthase, an ATP synthesizing assembly that is driven by the flow of protons back into the mitochondrial matrix.

Answer:

Carbohydrates is a macromolecules which is broken down into simpler substances like glucose which is used in the generation of energy in the process of cellular respiration.

Explanation:

Glycolysis is the first phase of respiration in which glucose molecule is broken down forming two molecules of pyruvate, two molecules of ATP, two molecules of NADH and two molecules of water. The second phase is Krebs cycle in which oxidation of acetyl-CoA occurs and energy is released in the form 2 ATP and carbondioxide. Electron transport chain is a third phase in which NADH, FADH and oxygen are the reactants producing 34 ATP and water. 34 ATP includes ATP of glycolysis and Krebs cycle.

Answer:

OK, This is my thinking, I hope this helps you out.

Let's do problem "a"

Step 1.  Write a balanced equation.

                                       2 HCl  +  Ba(OH)2  -------------->  BaCl2  + 2 HOH  

Step 2.  Underneath the HCl and Ba(OH)2 in the equation write what you are given and what you need to find out.

                                    2 HCl        +       Ba(OH)2  -------------->  BaCl2  + 2 HOH

                                 C = 0.130 mol/L    v = 56 mL

                                  V = ?                   C = 0.109 mol/L

Step 3.  They ALWAYS provide a way to calculate the number of moles of one of the substances.  In this case it is Ba(OH)2 because you have C and V

                         n = C X V            n = 0.109 x 56 = 6.104 millimoles

Step 4.  Use the equation to figure out how many moles of the unknown (HCl) you will need.

               the equation says you need TWICE as many moles as you have of Ba(OH)2.  So you will need 6.104 millimoles x 2 or 12.208 milimoles.

Step 5.  Now that yo have moles and concentration of HCl you can now calculate volume

                  C = n / V, so V = n / C

                                 12.208 millimoles / 0.130 mol/L = 93.9 mL

Use this method for all these kind of problems.  

In B) you will have to convert he g of NaOH into moles by 0.240 / 40.00 g/mol and then following trhe rest of the procedure.

C) is done the same way.  convert the g of Na2SO4 into moles first.

d) is almost the same as a) except this time when you find the moles of Ca(OH)2 you just have to convert the moles into mass by multiplying moles x Molar mass of Ca(OH)2.

Best of luck.

Explanation:

Answer:

b) It is either a proton or a neutron

Explanation:

the particle that is labeled with an X is a neutral atom or a proton which is symbolically represented as :

[tex]^A_z}}X[/tex]

where: z = atomic number of the element and it comprises of the number of protons(in the nucleus) and number of electron (in the particle)

A = atomic mass of the element  which is represented as the sum of the protons and neutrons (in the nucleus)

Answer:

Option B is correct.

It is either a proton or a neutron.

Explanation:

The image of the correct question is missing.

I would have attached it, but it might violate the brainly community guidelines.

The image contains a particle labelled as X that contains quarks.

Although, the sub atomic particles of an atom are well known and documented, there are further elementary particles that make up the sub atomic particles. They are more properly referred to as fundamental constituents of matter. They include quarks, leptons etc.

Quarks are fundamental constituents that make up protons and neutrons (The subatomic particles in the nucleus).

There are about six known different types of quarks. And they make up protons and neutrons in combinations.

Hence, it is easy to see why the particle X, that contains quarks, can only be a proton or a neutron.

Hope this Helps!!!

Answer:the horizontal rows in the periodic table are called periods

Explanation:Btw the vertical ones are called groups or families.

Answer:

It will have no effect

Explanation:

The loss of tin oxide to evaporation will have no effect on the empirical formula of a compound.

The empirical formula of any compound is the simplest formula of that compound by which the combining atoms can be represented.

This formula is not affect by physical changes.

According to the law of constant composition  "all pure samples of the same compound have the same element in the same proportion by mass".

Regardless of the mass loss or gain of any tin oxide compound, it will have the same empirical and molecular formula. The atoms are still combining in the ratio to give the product.

Answer:

Chemical Change

Explanation:

It changes color and produces vapor when the foil is added to the solution.

Answer:

The answer to your question is Chemical change.

Explanation:

Process

Chemistry classifies changes in two types: physical and chemical changes.

Physical changes occur when matter changes its physical state. Examples are evaporation, condensation, solidification, etc.

Chemical changes occur when matter reacts with another substance and it changes its original composition, a new molecule is formed.

From the description given we conclude that is is a chemical change.

Answer:

She has to mix 0.0550 moles of NaOH in a 550 mL solution to make a 0.100 M solution

Explanation:

Step 1: Data given

Concentration of the solution = 0.100 M

Number of moles NaOH = 0.0550 moles

Step 2: Calculate the volume of solution she needs

Concentration NaOH solution = number of moles NaOH / volume solution

Volume of the solution = Number of moles NaOH / Concentration NaOH solution

Volume of the solution = 0.0550 moles NaOH / 0.100 mol /L

Volume of the solution needed = 0.55 L

Volume of the solution needed = 550 mL

She has to mix 0.0550 moles of NaOH in a 550 mL solution to make a 0.100 M solution

Answer:

0.550

Explanation:

Answer:

for the water cycle

Explanation:

Answer: quarter moons

Explanation: Neap tides are especially weak tides. They occur when the gravitational forces of the Moon and the Sun are perpendicular to one another (with respect to the Earth). Neap tides occur during quarter moons. The Proxigean Spring Tide is a rare, unusually high tide.

Neap tides occur during the first and third quarter phases of the moon, when the gravitational forces of the sun and moon work against one another, resulting in a smaller tidal range.

Neap tides occur during the first quarter and the third quarter phases of the moon. Unlike spring tides, which occur during the new moon and full moon phases, neap tides are characterized by small tidal range due to the gravitational forces from the sun and the moon working against each other. During the first and third quarter moon phases, the moon and the sun are at a right angle relative to earth, which results in lower than average tidal bulges, hence causing the neap tides.

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Answer: i think the answer is

C. Chemists have learned how dangerous chemicals can be

Explanation:

Answer:

Chemists have improved our quality of life

Explanation:

Apex

Answer:

1. H2 is the limiting reactant.

2. 56666.67g ( i.e 56.67kg) of NH3 is produced.

Explanation:

Step 1:

The equation for the reaction. This is given below:

N2 + H2 —> NH3

Step 2:

Balancing the equation.

N2 + H2 —> NH3

The above equation can be balanced as follow :

There are 2 atoms of N on the left side and 1 atom on the right side. It can be balance by putting 2 in front of NH3 as shown below:

N2 + H2 —> 2NH3

There are 6 atoms of H on the right side and 2 atoms on the left side. It can be balance by putting 3 in front of H2 as shown below

N2 + 3H2 —> 2NH3

Now the equation is balanced.

Step 3:

Determination of the masses of N2 and H2 that reacted and the mass of NH3 produced from the balanced equation. This is illustrated below:

N2 + 3H2 —> 2NH3

Molar Mass of N2 = 2x14 = 28g/mol

Molar Mass of H2 = 2x1 = 2g/mol

Mass of H2 from the balanced equation = 3 x 2 = 6g

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 from the balanced equation = 2 x 17 = 34g

From the balanced equation above,

28g of N2 reacted with 6g of H2 to produce 34g of NH3

Step 4:

Determination of the limiting reactant. This is illustrated below:

N2 + 3H2 —> 2NH3

Let us consider using all the 10kg (i.e 10000g) of H2 to see if there will be any left of for N2.

From the balanced equation above,

28g of N2 reacted with 6g of H2.

Therefore, Xg of N2 will react with 10000g of H2 i.e

Xg of N2 = (28 x 10000)/6

Xg of N2 = 46666.67g

We can see from the calculations above that there are leftover for N2 as only 46666.67g reacted out of 50kg ( i.e 50000g) that was given. Therefore, H2 is the limiting reactant.

Step 5:

Determination of the mass of NH3 produced during the reaction. This is illustrated below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

6g of H2 reacted to produce 34g of NH3.

Therefore, 10000g of H2 will react to produce = ( 10000 x 34)/6 = 6g of 56666.67g of NH3.

Therefore, 56666.67g ( i.e 56.67kg) of NH3 is produced.

Answer:

H2 is the limiting reactant

56.2 kg of NH3 will be formed

Explanation:

Step 1: Data given

Mass of N2 = 50 kg = 50000 grams

Mass of H2 = 10 kg = 10000 grams

Molar mass of N2 = 28.0 g/mol

Molar mass of H2 = 2.02 g/mol

Molar mass NH3 = 17.03 g/mol

Step 2: The balanced equation

N2(g) + 3H2(g) → 2NH3(g)

Step 3: Calculate moles

Moles = mass / molar mass

Moles N2 = 50000 grams / 28.0 g/mol

Moles N2 = 1785.7 moles

Moles H2 = 10000 grams / 2.02 g/mol

Moles H2 = 4950.5 moles

Step 4: Calculate the limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

H2 is the limiting reactant.It will completely be consumed (4950.5 moles). Né is in excess. There will react 4950.5 / 3 = 1650.2 moles. There will remain 1785.7 - 1650.2 = 135.5 moles

Step 5: Calculate moles NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 4950.5 moles H2 we'll have 2/3 * 4950.5 = 3300.3 moles

Step 6: Calculate mass NH3

Mass NH3 = moles NH3 * molar mass NH3

Mass NH3 = 3300.3 moles * 17.03 g/mol

Mass NH3 = 56204 grams = 56.2 kg

Answer : The final  pressure of the balloon will be, 1369.6 torr

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]

or,

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1[/tex] = initial pressure = 923 torr

[tex]P_2[/tex] = final pressure = ?

[tex]V_1[/tex] = initial volume = 2.30 L

[tex]V_2[/tex] = final volume = 1.55 L

Now put all the given values in the above equation, we get:

[tex]923torr\times 2.30L=P_2\times 1.55L[/tex]

[tex]P_2=1369.6torr[/tex]

Thus, the final  pressure of the balloon will be, 1369.6 torr