If a 3.00-l flask contains 0.400 mol of co2 and 0.100 mol of o2 at equilibrium, how many moles of co are also present in the flask?

Answers

Answer 1

The equilibrium constant is the proportion of the equilibrium concentration of the product to the reactants. The moles of CO present in a flask is 1.89 moles.

What are moles?

Moles are the product of the molar concentration and the volume of the solution. It is given in mol.

The balanced chemical reaction can be shown as:

[tex]\rm 2CO(g) + O_{2}(g) \rightarrow 2CO_{2}(g)[/tex]

The equilibrium constant is given as,

[tex]\rm K_{c} = \dfrac{[CO_{2}]^{2}}{[CO_{2}]^{2} [O_{2}]}[/tex]

The concentration of carbon dioxide is calculated as:

[tex]\dfrac{0.4 \;\rm mol}{3\;\rm L} = 0.13[/tex]

The concentration of oxygen is calculated as:

[tex]\dfrac{0.1 \;\rm mol}{3\;\rm L} = 0.03[/tex]

Substituting values in the formula of the equilibrium constant:

[tex]\begin{aligned}{1.4 \times 10^{2} &= \rm \dfrac{0.13^{2}}{ [CO]^{2} \times 0.03}\\\\\rm [CO] &= \sqrt{0.004} \\\\&= 0.63 \end{aligned}[/tex]

The moles of carbon monoxide will be  [tex]0.63 \times 3 = 1.89\;\rm moles.[/tex]

Therefore, 1.89 moles of carbon monoxide are present in the flask.

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Answer 2

The correct answer is that there are 0.200 moles of CO present in the flask at equilibrium.

To solve this problem, we need to consider the chemical equilibrium of the reaction involved, which is the decomposition of carbon dioxide (CO2) into carbon monoxide (CO) and oxygen (O2). The balanced chemical equation for this reaction is:

[tex]\[ \text{CO}_2(g) \rightleftharpoons \text{CO}(g) + \frac{1}{2}\text{O}_2(g) \][/tex]

According to the stoichiometry of the balanced equation, for every mole of CO2 that decomposes, one mole of CO is produced and half a mole of O2 is produced.

Given that we have 0.400 moles of CO2 and 0.100 moles of O2 in the flask, we can use the stoichiometry of the reaction to find out how many moles of CO are present. Since the reaction produces one mole of CO for every mole of CO2 that decomposes, we can calculate the moles of CO produced by the decomposition of CO2 as follows:

[tex]\[ \text{Moles of CO produced} = \text{Moles of CO2 decomposed} \][/tex]

However, we also know that the reaction produces half a mole of O2 for every mole of CO2 that decomposes. Therefore, the moles of O2 produced can be calculated as:

[tex]\[ \text{Moles of O2 produced} = \frac{1}{2} \times \text{Moles of CO2 decomposed} \][/tex]

Since we have 0.100 moles of O2, we can set up the equation:

[tex]\[ 0.100 = \frac{1}{2} \times \text{Moles of CO2 decomposed} \][/tex]

Solving for the moles of CO2 decomposed, we get:

[tex]\[ \text{Moles of CO2 decomposed} = 0.100 \times 2 = 0.200 \][/tex]

This means that 0.200 moles of CO2 have decomposed to produce 0.200 moles of CO and 0.100 moles of O2. Therefore, the moles of CO present in the flask at equilibrium is 0.200 moles.


Related Questions

In location B, what can you conclude about the sediments carried in the river?

Answers

they can cause it to flood...

They can form a delta, because the river location B leads into the Gulf of Mexico.

How many moles of copper are 4.57 x 1013 atoms of copper?

Answers

Hey there Adam!

Your correct answer to this question would be [tex](7.59 x \ 10-11 \ moles)[/tex]

I Hope this helps you!

Taking into account the definition of avogadro's number, 7.59×10⁻¹¹ moles of copper are 4.57×10¹³ atoms of copper.

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023×10²³ atoms are contained in 1 mole of copper, then 4.57×10¹³ atoms are contained in how many moles of copper?

amount of moles of copper= (4.57×10¹³ atoms × 1 mole)÷ 6.023×10²³ atoms

amount of moles of copper= 7.59×10⁻¹¹ moles

Finally, 7.59×10⁻¹¹ moles of copper are 4.57×10¹³ atoms of copper.

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Epirical formula of P4O10

Answers

I would say the answer is P2O5. Some teachers use PO2.5. I'm not one of them.

Enter a balanced equation for the reaction of Na2S and CdSO4.

Answers

this type of a reaction is a double displacement reaction. where the reactants displace each other. the cations and the anions the reactant compounds replace each other or in other words switch places. the anion of one compound will bond with the cation of the other compound and vice versa.

the equation for the above is 
Na₂S + CdSO₄ ---> CdS + Na₂SO₄
the numbers of atoms on both sides are balanced now 

Answer:  [tex]Na_2S+CdSO_4\rightarrow Cd_2S+Na_2SO_4[/tex]

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Double displacement reaction is one in which exchange of ions take place.

The balanced chemical reaction will be:

[tex]Na_2S+CdSO_4\rightarrow Cd_2S+Na_2SO_4[/tex]

Genes help determine a person's traits or characteristics. scientific investigations into genes have helped scientists solve major societal issues. which issue would most likely benefit from these investigations?

A. treating inherited diseases

B. improving nutrition

C. preventing food borne illness

D. accessing clean drinking water

Answers

It would be A)Treating Inherited Diseases
~Mathlete12321

Answer:

The correct answer is option A, that is, treating inherited diseases.

Explanation:

Genetic testing comprises testing the DNA, that is, the chemical database, which conducts instructions for the functions of the body. Investigation of genes can demonstrate modifications in the genes, which may lead to a disease or illness.  

If someone is exhibiting signs of a disease, which may be a result of genetic modifications, also known as mutated genes. Then in such cases, the examination of genes can show if one is exhibiting a suspected disorder. For example, genetic testing may be done to confirm a diagnosis of Huntington's disease or cystic fibrosis.  

What volume of a 0.716 m kbr solution is needed to provide 30.5 g of kbr?

Answers

Answer is: volume of KBr is 357 mL.
c(KBr) = 0,716 M = 0,716 mol/L.
m(KBr) = 30,5 g.
n(KBr) = m(KBr) ÷ M(KBr).
n(KBr) = 30,5 g ÷ 119 g/mol.
n(KBr) = 0,256 mol.
V(KBr) = n(KBr) ÷ c(KBr).
V(KBr) = 0,256 mol ÷ 0,716 mol/L.
V(KBr) = 0,357 L · 1000 mL/L = 357 mL.

Answer:

V_{solution}=0.355L

Explanation:

Hello,

Potassium bromide moles are computed as:

[tex]n_{KBr}=30.5gKBr*\frac{1molKBr}{119.9gKBr}=0.254gKBr[/tex]

Now, by recalling the molarity formula and solving for the volume, one obtains:

[tex]M=\frac{n_{KBr}}{V_{solution}} \\V_{solution}=\frac{n_{KBr}}{M}\\V_{solution}=\frac{0.254mol}{0.716mol/L}\\ V_{solution}=0.355L[/tex]

Best regards.

There are two steps in the extraction of copper metal from chalcocite, a copper ore. in the first step, copper(i) sulfide and oxygen react to form copper(i) oxide and sulfur dioxide: (s) (g) (s) (g) in the second step, copper(i) oxide and carbon react to form copper and carbon monoxide:

Answers

The net chemical equation is 2 [tex]Cu_2S[/tex] (s) + 3 [tex]O_2[/tex] (g) + 2 C (s) → 4 Cu (s) + 2 [tex]SO_2[/tex] (g) + 2 CO (g).

The net chemical equation for the production of copper from copper(I) sulfide, oxygen, and carbon involves a two-step process: oxidation of copper(I) sulfide with oxygen followed by reduction of copper(I) oxide with carbon, yielding copper metal, sulfur dioxide, and carbon monoxide.

The extraction of copper from its ore involves a two-step process. The first step is the oxidation of copper(I) sulfide (chalcocite) with oxygen to form copper(I) oxide and sulfur dioxide. The second step is the reduction of copper(I) oxide with carbon to obtain copper metal and carbon monoxide.

Step 1: Oxidation of Copper(I) Sulfide

2 [tex]Cu_2S[/tex] (s) + 3 [tex]O_2[/tex] (g) → 2 [tex]Cu_2O[/tex] (s) + 2 [tex]SO_2[/tex] (g)

Step 2: Reduction of Copper(I) Oxide

2 [tex]Cu_2O[/tex] (s) + 2 C (s) → 4 Cu (s) + 2 CO (g)

By adding the balanced equations from both steps together and eliminating the intermediate product, copper(I) oxide, which appears on both sides, we get the net chemical equation for the production of copper:

Net Chemical Equation

2 [tex]Cu_2S[/tex] (s) + 3 [tex]O_2[/tex] (g) + 2 C (s) → 4 Cu (s) + 2 [tex]SO_2[/tex] (g) + 2 CO (g)

The question is:

There are two steps in the extraction of copper metal from chalcocite, a copper ore. In the first step, copper(I) sulfide and oxygen react to form copper(I) oxide and sulfur dioxide. In the second step, copper(I) oxide and carbon react to form copper and carbon monoxide.

Write the net chemical equation for the production of copper from copper(I) sulfide, oxygen and carbon. Be sure your equation is balanced.

Suppose that a catalyst lowers the activation barrier of a reaction from 125 kj/mol to 57 kj/mol . by what factor would you expect the reaction rate to increase at 25 âc? (assume that the frequency factors for the catalyzed and uncatalyzed reactions are identical.)

Answers

Factor would you expect the reaction rate to increase at 25 C is [tex]1.8*10^{12}[/tex]

Explanation:

Suppose that a catalyst lowers the activation barrier of a reaction from 125 kj/mol to 57 kj/mol . Assume that the frequency factors for the catalyzed and uncatalyzed reactions are identical:  by what factor would you expect the reaction rate to increase at 25 C?

Catalysis is process of increasing the chemical reaction rate by adding a substance known as catalyst. Reaction rate is the speed at which a chemical reaction proceeds. Activation energy is the energy which must be provided to a chemical or nuclear system with potential reactants to result in chemical reaction, nuclear reaction, etc

The rates of reaction question in Kelvin [tex]25 C = 273 + 25 = 298 K[/tex]

The rate constants under catalysed and non‐catalysed conditions:

Catalysed: [tex]k_{cat} = A e^{\frac{-Ea(cat)}{RT} } = A e^{\frac{‐55000}{(8.314 x 298)}} = A e^{-22.2}[/tex]

Uncatalysed: [tex]k_{uncat} = A e^{\frac{-Ea(uncat)}{RT} } = A e^{\frac{‐125000}{8.314* 298} } = A e^{-50.4}[/tex]

Ratio of catalysed to uncatalysed reaction rates is

[tex]\frac{k_{cat}}{k_{uncat}} = \frac{Ae^{-22.2}}{Ae^{-50.4}}[/tex]

The A values are the same for both processes, therefore [tex]\frac{A}{A} = 1[/tex]

[tex]\frac{k_{cat}}{k_{uncat}} =\frac{e^_{-22.2}}{e^{-50.4}} = 1.8 * 10^{12}[/tex]

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The factor by which reaction rate is more in the presence of catalyst as compared to uncatalysed reaction is 1.8 × 10¹².

What is Arrhenius equation?

From the Arrhenius equation, we can calculate the effect of chnage in the activation energy as well as of temperature on the rate of the reaction.

Arrhenius equation will be represented as:

[tex]k = Ae^{-Ea/RT}[/tex], where

k = rate constant

A = frequency factor = 1 (given)

Ea = activation energy

R = universal gas constant = 8.314 J/ mol.K

T = temperature = 25 degree celsius = 298 K

Rate of reaction in the presence of catalyst will be calculated as:

Activation energy = 57 kJ/mol = 57000 J/mol

[tex]k1 = e^{-57000/8.314\times 298}[/tex] = [tex]e^{-22} \\[/tex]

Rate of reaction in the absence of catalyst will be calculated as:

Activation eneregy = 125 kJ/mol = 125000 J/mol

[tex]k2 = e^{-125000/8.314\times 298}[/tex] = [tex]e^{-50.4}[/tex]

Ratio of both the rates will be :

k1/k2 = [tex]e^{-22} \\[/tex] / [tex]e^{-50.4}[/tex] = 1.8 × 10¹²

Hence, the rate is 1.8 × 10¹² times more.

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A solution made by dissolving 14.2g of sucrose in 100g water exhibits a freezing point depression of 0.77 degrees. Calculate the molar mass of sucrose

Answers

Final answer:

To find the molar mass of sucrose based on the freezing point depression, we first determine the molality of the solution from the observed freezing point depression and the freezing point depression constant of water. Then we calculate the number of moles of sucrose and finally divide the mass of sucrose dissolving by the number of moles to obtain the molar mass, which is 343.0 g/mol.

Explanation:

To calculate the molar mass of sucrose using freezing point depression, we utilize the formula ΔTf = i * Kf * m, where ΔTf is the change in freezing point, i is the van't Hoff factor (for sucrose, i = 1 since sucrose does not dissociate into ions), Kf is the freezing point depression constant for the solvent (water in this case), and m is the molality of the solution.

First, we need to determine the molality (m) of the sucrose solution. The freezing point depression observed is 0.77 degrees Celsius, and the freezing point depression constant (Kf) for water is 1.86 K/kg/mol. The molality is calculated using the observed ΔTf and Kf:

m = ΔTf / (Kf * i)

m = 0.77°C / (1.86°C*kg/mol)

m = 0.414 mol/kg

Now, convert the mass of the water to kilograms:

100g water = 0.1kg water

Next, calculate the number of moles of sucrose using the molality and mass of solvent:

n (moles of sucrose) = molality * mass of water (in kg)

n = 0.414 mol/kg * 0.1 kg

n = 0.0414 mol

Finally, calculate the molar mass of sucrose (M) by dividing the mass of sucrose used by the number of moles:

M = mass of sucrose / number of moles

M = 14.2g / 0.0414 mol

M = 343.0 g/mol

Therefore, the molar mass of sucrose is 343.0 g/mol.

Phosphoric acid has 3 pka values, which are 2.1, 6.9, and 12.4. draw the protonated form of phosphoric acid associated with the reaction whose pka value is 12.4. draw only one resonance form. do not draw lone electron pairs.

Answers

As mentioned above, phosphoric acid has 3 pKa values, and after 3 ionization it gives 3 types of ions at different pKa values:

H₃PO₄(aq) + H₂O(l) ⇌ H₃O⁺(aq) + H₂PO₄⁻ (aq)         pKₐ₁ 


H₂PO₄⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HPO₄²⁻ (aq)       pKₐ₂


HPO₄²⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + PO₄³⁻ (aq)          pKₐ₃ 


At the highest pKa value (12.4) of phosphoric acid, the last OH group will lose its hydrogen. On the picture I attached, it is shown required protonated form of phosphoric acid before reaction whose pKa value is 12.4.


Fundamentally, how are ΔHrxnand ΔHfdifferent?Which part of the experiment demonstrated the change inenthalpy per mole of a reaction?

Answers

The heat of reaction, ΔHrxn, is the change in enthalpy in a chemical reaction. It is the difference in enthalpies of the products and reactants. The reaction enthalpy dictates the amount of energy absorbed or released during a reaction.

The heat of formation, ΔHf, is the the energy required to form a compound from its elements in their standard states.

The heat of reaction can be found by using the heat of formation of the products and reactants and finding the difference. The heat of formation tells us the energy per mole required to form the product. The heat of reaction will tell us the change in enthalpy per mole of a reaction.

Final answer:

The difference between ΔHrxn and ΔHf lies in their application; ΔHrxn measures the energy change in a reaction, while ΔHf pertains to the formation of a compound from its elements. The change in enthalpy per mole of a reaction is demonstrated experimentally through methods like calorimetry, which measures temperature changes.

Explanation:

Fundamentally, ΔHrxn and ΔHf differ in their application within thermodynamics. ΔHrxn, or the enthalpy change for a reaction, measures the overall energy change when reactants turn into products under constant pressure. This encompasses the total heat absorbed or released, calculated as the difference between the enthalpy of products and reactants. In contrast, ΔHf, or the standard enthalpy of formation, is the enthalpy change accompanying the formation of 1 mole of a substance from its elements in their most stable states, under standard conditions (1 bar, 298.15 K).

The part of the experiment that demonstrates the change in enthalpy per mole of a reaction typically involves measuring the temperature change of the surroundings or the system itself during a chemical reaction. This temperature change, coupled with the specific heat capacity of the system and the number of moles of reactants or products, allows us to calculate the enthalpy change. Therefore, experimental methods such as calorimetry can directly measure the enthalpy changes, providing insights into whether a reaction is endothermic or exothermic based on the ΔH values calculated.

What is the term for a solid that forms when two solutions are mixed? a precipitate a gas a suspension a solution

Answers

when a solid forms with two solutions are mixed it is a precipitate 

the term for a solid when two solutions are mixed is  a percipitate

which is a substance that could be found in air, water or soil that is harmful to humans or animals?
a.) fossil fuel
b.) pollutant
c.) smog
d.) carbon dioxide

Answers

Hello!

A substance that could be found in air, water or soil that is harmful to humans or animals is a Pollutant.

The other substances cannot be found in air, water or soil. Fossil fuels can only be found in soil, smog can only be found in the air, and carbon dioxide can be found in the water or air. 

Pollutants 
are substances that have harmful effects and damage the environment.  Some examples of pollutants are Carbon Monoxide (air), Lead (soil) and Insecticides (water). 

Have a nice day!

Answer:

Pollutant

Explanation:

took test

Calculate the concentration of chloride ions in a saturated lead

Answers

Final answer:

The concentration of chloride ions in a saturated lead solution can be calculated using the given solubility and the stoichiometry of the dissolution reaction. The concentration is determined to be 1.3 × 10-6 M.

Explanation:

The concentration of chloride ions in a saturated solution is determined by the solubility product constant, Ksp, and the solubility of the particular compound. Using the provided information, the concentration of chloride ions is given as [Cl] = 7.6 × 10-³ M initially. However, with further calculations by applying quadratic equation and taking into account the dissolution stoichiometry, it is found that the concentration of chloride ions in the solution is [Cl] = 1.3 × 10-6 M. The composition of chlorine in its isotopic form is also considered which consists of 75.76% 35Cl and 24.24% 37Cl. Hence, consider all these factors when calculating the concentration of ions in a solution.

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When vapors of a flammable or combustible liquid are mixed with air in the proportions in the presence of a source of ignition, rapid combustion or an explosion can occur. The proper proportion is called the _______________. A. Boiling range B. Flammable or explosive range C. Flash point

Answers

     When vapors of flammable or combustible liquid are mixed with air in proportions in the presence of a source of ignition it is called
-B. Flammable or explosive range

Answer: Option (B) is the correct answer.

Explanation:

When vapors of a flammable or combustible liquid are mixed together with air in the presence of a source of ignition in proportions rapid combustion or an explosion can occur. The proper proportion is called the flammable or explosive range.

Boiling range is defined as the range of temperature which is involved distillation of oil from the starting time to the time till it evaporates.

The lowest temperature at which an ignitable mixture can be formed from a liquid in air near its surface.

An aqueous solution of glucose behaves as an aldehyde because ________.

Answers

because It's cyclic hemiacetal and the predominant form is in equilibrium with the free aldehyde form. as glucose has an aldehyde group and five hydroxyl group and can form an intramolecular cyclic hemiacetal. In aqueous solution, glucose exists in open and closed forms.when the process of converting the close form to open form and them back to the close form the rotate of the c1 and c 2 happened, that rotation produces the two anomers α & β. So the equilibrium of α & β in solution is a resulting of this mutarotation. In glucose, the anomer β is more predominate than α anomer.

An aqueous solution of glucose behaves as an aldehyde because it's cyclic hemiacetal, the predominant form, is in equilibrium with the free aldehyde form.
Glucose is one of the sixteen aldohexose stereoisomers. Glucose has carbonyl and hydroxyl group, so glucose in aquatic solution form hemiacetal.

Write the equilibrium constant expression for this reaction: h2so4 (aq) → 2h+ (aq) + so−24 (aq)

Answers


when Kc = [the concentration of products]^(no.of its mol in the balanced equation)     /  [the concentration of the reactants]^(no.of mol in the balanced equation)
∴ The equilibrium constant expression for this reaction is:
Kc= [H+]^2 * [So4-2] / [H2SO4]

Answer:

[tex]Keq =\frac{[H+]^{2} [SO4^{2-}]^{2}  }{[H2SO4]}[/tex]

Explanation:

The equilibrium constant K is a parameter that relates the concentration of products to that of the reactants at equilibrium and under a given temperature.

Consider a hypothetical reaction:

xA + yB ↔ zC

where A and B are the reactants ;  C is the product

x and y are the coefficients of the reactants; z is the product coefficient

The equilibrium constant is given as:

[tex]Keq = \frac{[C]^{z} }{[A]^{x}[B]^{y}}[/tex]

The given reaction is:

[tex]H2SO4(aq)\rightleftharpoons 2H+(aq)+ SO_{4}^{2-}(aq)[/tex]

[tex]Keq =\frac{[H+]^{2} [SO4^{2-}]^{2}}{[H2SO4]}[/tex]

The vapor pressure of water at 25.0°c is 23.8 torr. determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.0 g of water to change the vapor pressure to 22.8 torr.42.a solution is prepared from 53.8 g of a nonvolatile, nondissociating solute and 85.0 g of water. the vapor pressure of the solution at 60°c is 132 torr. the vapor pressure of water at 60°c is 150. torr. what is the molar mass of the solute?ans:epts:1dif:difficultref:11.4chemistry | general chemistry | solutions | colligative properties | vapor pressure of a solution | vapor pressure loweringmsc: quantitative43.an ideal solution is formed from a mixture of the nonvolatile solute urea, co(nh2)2, and methanol, ch3oh. the vapor pressure of pure methanol at 20°c is 89 mmhg. if 4.4 g of urea is mixed with 39.9 g of methanol, calculate the vapor pressure of the methanol solution.a) 4.9 mmhgb)80 mmhgc)74 mmhgd) 15 mmhge)84 mmhg44.a salt solution sits in an open beaker. assuming constant temperature and pressure, the vapor pressure of the solution

Answers

Q: A
according to this formula, we can get the mole fraction of water (n):
P(solu) = n Pv(water)
when we have Pv(solu) = 22.8 and Pv(water) = 23.8 so by substitution:
22.8 = n * 23.8
n= 0.958
- we need to get the moles of glucose:
moles of water = 500 g(mass weight) / 18 (molar weight)= 27.7 mol
n = moles of water / ( moles of water + moles of glucose)
0.958   = 27.7 / ( 27.7+ moles of glucose)
0.958 moles of glucose + 26.5 = 27.7
0.968 moles of glucose = 1.2
moles of glucose = 1.253 mol
∴ the mass of glucose = no.of glucose moles x molar mass 
                                      = 1.253 x 180 = 225.5 g
Q: B
here we also need to get n (mole fraction of water )by using this formula:
Pv(solu) = n Pv(water)
when we have Pv(solu)=132 & Pv(water)=150 so, by substition:
132= n * 150
n = 0.88
so, mole fraction of solution = 1 - 0.88 = 0.12
and we can get after that the moles of water = (mass weight / molar mass)
- no.moles of water = 85 g / 18 g/mol = 4.7 moles
- total moles in solution = moles of water / moles fraction of water 
                                        = 4.7 / 0.88 = 5.34 moles 
∴ moles of the solution = total moles in solu - moles of water 
                                       = 5.34 - 4.7 = 0.64 moles solute
∴ the molar mass of the solute = mass weight of solute / no.of moles of solute
                                                    = 53.8 / 0.64 = 84 g/mole

Q: C

moles of urea (NH2)2 CO = mass weight / molar mass
                                           = 4.49 g / 60 g /mol
                                           = 0.07 mol
moles of methanol = mass weight / molar mass 
                                 = 39.9  g / 32  g/mol = 1.25 mol
moles fraction of methanol = moles of methanol / (moles of methanol + moles of urea )
moles fraction of methanol = 1.25 / ( 1.25+0.07) = 0.95
by substitution in Pv formula we will be able to get the vapour pressure of the solu :
Pv(solu) = n P°v
Pv(solu) = 0.95 * 89 mm Hg 
∴Pv(solu) = 84.55 mmHg


 

Which bond in the acetic acid molecule is the most polar?

Answers

The most polar bond in acetic acid is [tex]\boxed{{\text{O - H bond}}}[/tex].

Further explanation:

Electronegativity:

The tendency of an atom to attract the shared electrons in the bond towards itself is known as electronegativity. The more electronegative atom will more attract the bonding electrons towards itself than the less electronegative one.

Higher the electronegativity value of the element more will be its tendency to accept an electron towards itself.

A polar bond is defined as a covalent bond between two atoms where the electrons that form the bond are unequally distributed. This is reason for the positive charge at one end and the negative charge at other end.

The bond or the molecular polarities are related to the electronegativity of the atoms or the molecules. The polarity of a bond is given by the difference in electronegativity between the two atoms that form polar bond

The factors on which the polarity of bonds depends are as follows:

1) Relative electronegativity of participating atoms:

Since the bond polarity involves pulling of electrons towards itself, hence a more electronegative element will be able to attract the electrons more towards it. As a result, the electrons will definitely move towards the more electronegative element.

2) The spatial arrangement of various bonds in the atom:

The shared pair of electrons also experience pulling force from the other bonded and non-bonded pair of electrons. This results in different bond polarities between same participating atoms that are present in different molecules. For example, bond polarity of O-H bond in a water molecule and acetic acid molecule is different. This is due to the different spatial arrangements of various bonds in the molecule.

Acetic acid also called as ethanoic acid is a colorless organic compound. It consists of methyl group that is bonded to carboxyl group.

The structure of acetic acid is attached in the image.

In acetic acid, two oxygen atoms are present in which one oxygen atom is double-bonded to carbon atom, and another one is single bonded to the carbon atom. Also, oxygen is bonded to hydrogen.

As oxygen is electronegative, the two oxygen atoms draw electron density away from the O-H bond and make the bond polar. Also, the electronegativity difference between oxygen and hydrogen is high due to which electrons are attracted towards oxygen and make the bond most polar.

Hence, in acetic acid O-H bond is most polar.

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Organic compounds

Keywords: acetic acid, polar bond, polarity, electronegativity, O-H bond, CH3COOH, and carboxylic group.

Final answer:

The O-H bond in acetic acid is the most polar due to a large difference in electronegativity between oxygen and hydrogen.

Explanation:

The bond in the acetic acid molecule CH3COOH that is the most polar is the O-H bond. This polarization is due to the difference in electronegativity between oxygen (3.5) and hydrogen (2.1), which is 1.4 according to the Pauling scale. This significant difference leads to a highly polar covalent bond, meaning the electrons are more attracted to the oxygen atom, giving it a partial negative charge and the hydrogen a partial positive charge.

Sodium carbonate (Na2CO3) reacts with acetic acid (CH3COOH) to form sodium acetate (NaCH3COO), carbon dioxide (CO2), and water (H2O). A chemist carries out this reaction in a bomb calorimeter. The reaction causes the temperature of a bomb calorimeter to decrease by 0.985 K. The calorimeter has a mass of 1.500 kg and a specific heat of 2.52 J/g•K. What is the heat of reaction for this system?

Answers

Final answer:

The heat of reaction for this system can be calculated using the formula: Heat of reaction = mass of the calorimeter x specific heat of the calorimeter x change in temperature.

Explanation:

The heat of the reaction for this system can be calculated using the formula:

Heat of reaction = mass of the calorimeter x specific heat of the calorimeter x change in temperature.

Plugging in the given values:

mass of the calorimeter = 1.500 kgspecific heat of the calorimeter = 2.52 J/g•K (converting to kg: 2.52 J/g•K / 1000 g = 0.00252 J/kg•K)change in temperature = 0.985 K

Using the formula, we can calculate:

Heat of reaction = 1.500 kg x 0.00252 J/kg•K x 0.985 K = 0.0037072 J

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When 1,000 joules of coal is burned it only produces 500 joules of electricity. What happened to the other 500 joules of energy?

Answers

The law of conservation of energy state that energy can't be destroyed but it doesn't mean the machine to convert it all into desired energy.
In a coal plant, the coal is burned to convert its chemical energy into electrical energy. Some of the energy will be converted into side product like the thermal energy of the gas that appears on the chimney or the friction produced by turbines.
In this case, the coal plants have 50% efficiency because it can extract 500 joules of electricity from 1,000 joules worth of coal.

The missing 500 joules of energy when burning 1,000 joules of coal are lost to inefficiencies in the energy conversion process, including factors like heat loss.

When 1,000 joules of coal is burned and only 500 joules of electricity is produced, the missing 500 joules of energy are lost primarily due to inefficiencies in the energy conversion process. This is a result of the Second Law of Thermodynamics, which states that when energy is transformed or transferred, part of it assumes a form that cannot be used to do work (often manifested as heat). In the context of a coal-fired power station, the energy undergoes several conversions: chemical energy from the coal is converted to thermal energy (heat), which is then converted to mechanical energy (turbines spinning), and finally converted to electrical energy.

The lost 500 joules of energy in the process are dissipated as heat into the environment, sound, and other forms of energy that are not useful in generating electricity. This comes from the inefficiency of the power plant, where some of the energy is unavoidably lost due to factors like friction, heat loss through conduction, convection, and radiation, and other resistive processes within the power generation system. Therefore, the efficiency of the power station is around 50% as it is only able to convert half of the energy content of the coal into electricity. Ex. In the case provided, a coal power plant with 1,000 joules of input energy from burning coal and an output of 500 joules of electrical energy would have an efficiency of 50%. This percentage is a simplified representation of many real-world power stations' efficiency, which tends to be around 30%-40%. It is also important to note that efforts to increase the efficiency of power stations can lead to more sustainable energy practices by reducing both waste energy output into the environment, which has ecological consequences, and the amount of coal required, which affects the release of CO2 emissions.

If a translucent blue copper sulfate solution is mixed with another solution and changes to a translucent lighter blue color does that mean a physical change occurred or a chemical change?

Answers

The answer would depend on the color of the solution added. If the solution is clear, the lighter blue color could be caused by dilution of the copper sulfate.

Chemical reaction indicated by a change in color(blue to red), sedimentation, gas/bubbles, odor, and temperature changes. The lighter color(blue to lighter blue) is more likely to be physical changes than chemical

what kind of electrochemical cell might likely be used for a task such a electroplating?

Answers

an electrolytic cell
do you have any choices it would help 

Question 1 (10 points) Question 1 Unsaved
How much heat is needed to raise 0.30grams of Aluminum from 30 Celcius to 150 Celcius?

(Use 0.9J/gC for the specific heat of Aluminum)

Question 1 options:

120J


32.4J


0.9J


100J

Answers

The answer would be the last option

The equation from which heat can be calculated is represented as:

q=mc\Delta T

Where, q=Heat (J)

m=mass of aluminium(g)

Delta T=Change in temperature(⁰C)

c=specific heat (J/g ⁰C)

Here ,

m=mass of aluminium(g)=0.3 g

Delta T=Change in temperature(⁰C)=150-30⁰C=120⁰C

c=0.9J/gC

Putting all the values in the above equation,

q=mc\Delta T

q=0.3×0.9×120

q=32.4 J

So, heat required will be 32.4 J.

Which statement best compare how coal is formed to the way natural gas and oil are formed




How does a turbine work to produce energy for electricity

Answers

Question 13

The appropriate answer is B. Coal is a biochemically produced sedimentary rock composed almost entirely or organic carbon formed by the compression of swamp vegetation.
Oil is an organic fluid formed by the diagenesis of buried organic material that migrates into reservoirs in porus crustal rocks such as sandstone. Natural gas is the volatile fraction of oil that seeps through cracks into reservoirs.

Question 14

The appropriate answer is A. In the operation of a generator, a source of mechanical energy such as wind, water or steam spins the turbine. The turbine moves large electromagnets encased in coils and insulated wires. As the electromagnets move, the coiled wire cuts through a magnetic field, inducing an electric current in the wire.

Final answer:

Coal is formed from plant matter, while oil and natural gas are derived from marine organisms. A turbine produces electricity by spinning its blades with energy from different sources, transferring this motion to a generator.

Explanation:

The correct statement that compares the formation of coal to the way natural gas and oil are formed is: Coal results from the compressed remains of plant matter. Both oil and natural gas are compressed remains of marine organisms. So the correct answer is B. Coal, oil, and natural gas are all fossil fuels, but they form from different types of organic matter and under varying conditions of heat and pressure.

Coal is typically found as coal seams within rock layers and is formed from ancient swamp vegetation, whereas oil and natural gas originated from microorganisms in prehistoric water bodies and are often found together due to their similar formation processes.

A turbine works to produce energy for electricity by harnessing energy from various sources, such as the wind, water flow, or steam generated from the combustion of fossil fuels, to spin its blades. This motion is transferred to a generator, which converts the kinetic energy into electrical energy. The correct answer that describes this process is A: Energy from sources such as wind or from burning fossil fuels is used to spin the blades of the turbine. The turbine then powers a generator which produces electricity.

The picture below shows two galaxies. 



Which of these statements best describes a similarity between the two galaxies? (2 points)
Both have spiral arms.
Both revolve around a single point.
Both are formed by gravitational forces.
Both change their shape from time to time

Answers

The appropriate answer is C. Both are formed by gravitational forces. The first picture shows an elliptical galaxy. These galaxies can be round, nearly spherical or flattened disks. They contain very little dust or gas and the stars contained here are older than stars in other galaxies. The second picture shows a spiral galaxy that has a center made up of a thick mass of material and has flattened arms that rotate around the center. 

Galaxies are formed from the gravitational pull of massive objects in space. Some galaxies from around super massive black holes (spiral) or a group or collection or cluster of stars. 

Answer:

Both are formed by gravitational forces.

Explanation:

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The ph of 0.015 m hno2 (nitrous acid) aqueous solution was measured to be 2.63. what is the value of pka of nitrous acid?

Answers

Nitrous acid dissociates as follows:

HNO₂(s) ⇄ H⁺(aq) + NO₂⁻(aq) 
           
According to the equation, an acid constant has the following form:

Ka = [H⁺] × [NO₂⁻ ] / [HNO₂] 

From pH, we can calculate the concentration of H⁺ and NO₂⁻:

[H⁺] = 10^-pH = 10^-2.63 = 0.00234 M = [NO₂⁻]

Now, the acid constant can be calculated:

Ka = 0.00234 x 0.00234 / 0.015  = 3.66 x 10⁻⁴

And finally,

pKa = -log Ka = 3.44 


Why do some metals lose their shine over time but not gold ?

Answers

Some metals lose their shine because of corrosion, a galvanic process involving oxidation by substances like oxygen.

The reason some metals lose their shine over time is due to a process known as corrosion, which is a galvanic process that leads to the deterioration of metals through oxidation. Metals like iron rust and silver tarnish when exposed to air because of their reaction with oxygen, forming oxides on the surface. However, gold does not corrode easily due to its resistance to oxidation by common substances.

Aluminum, although reactive, forms an aluminum oxide coating that protects it from further corrosion, while copper reacts with carbon dioxide to form a green patina that serves as a protective layer. Precious metals such as gold and platinum, known for their corrosion resistance and durability, defy normal oxidation and maintain their luster over time. They are impervious to most elements and can be corroded by only a few special fluids.

The reform reaction between steam and gaseous methane ( ch4 ) produces "synthesis gas," a mixture of carbon monoxide gas and dihydrogen gas. synthesis gas is one of the most widely used industrial chemicals, and is the major industrial source of hydrogen. suppose a chemical engineer studying a new catalyst for the reform reaction finds that 159. liters per second of methane are consumed when the reaction is run at 294.°c and 0.86atm . calculate the rate at which dihydrogen is being produced. give your answer in kilograms per second. be sure your answer has the correct number of significant digits.

Answers

Answer is: rate of production of hydrogen is 0,01758 kg/s.
Chemical reaction: CH₄ + H₂O → CO + 3H₂.
V(CH₄) = 159 L.
p = 0,86 atm · 101,325 kPa/atm = 87,14 kPa.
T = 294°C = 567 K.
R = 8,314 J/K·mol.
Ideal gas law: p·V = n·R·T.
n(CH₄) = p·V  ÷ R·T.
n(CH₄) = 87,14 kPa · 159 L ÷ 8,314 J/K·mol · 567 K.
n(CH₄) = 2,93 mol.
From chemical reaction: n(CH₄) : n(H₂) = 1 : 3.
n(H₂) = 2,93 mol · 3 = 8,79 mol.
m(H₂) = 8,79 mol · 2 g/mol.
m(H₂) = 17,58 g · 0,001 kg/g = 0,01758 kg.

The rate of the dihydrogen production is 0.0175 kg/sec for the given reaction.

The given reaction

[tex]\bold {CH_4 + H_2O \rightarrow CO + 3H_2}[/tex]

One mole of Methane is react with one mole of water to form 1 mole of CO and 3 moles of Hydrogen.

The rate of hydrogen production can be calculated from ideal gas law

[tex]\bold {pV = nRT}[/tex]

Where,

p- pressure = 0,86 atm · 101,325 kPa/atm = 87,14 kPa.

V- volume of methane =  159 L

T -  temperature= 294°C = 567 K.

R - gas constant = 8,314 J/K·mol.

n - number of moles = ?

Put the values in the formula, sole it for n,

[tex]\bold{n(CH₄) = \dfrac {pV} {RT}}\\\\\bold {n(CH₄) = \dfrac {87,14 kPa \times 159 L} {8,314 J/K.mol \times 567 K}.}\\\\\bold {n(CH₄) = 2,93 mol}[/tex]

Since, the molar ratio of methane to hydrogen is 3:1.

SO,

[tex]\bold {n(H_2) = 2,93 mol \times 3 }\\\\\bold {n (H_2) = 8,79 mol.}\\[/tex]

Hence, the mass of the dihydrogen produced,

[tex]\bold{ m(H_2) = 8.79 mol \times 2 g/mol.}\\\\\bold {m(H_2) = 17.58 g \times 0.001 kg/g}\\\\\bold {m(H_2) = 0.01758 kg}[/tex]

Therefore, the rate of the dihydrogen production is 0.0175 kg/sec for the given reaction.

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how do you explain why the addition of silver nitrate to the Fe/SCN equilibrium had an effect on the equilibrium, even though neither silver ion nor nitrate ion is written as part of the equilibrium reaction?

Answers

Final answer:

Adding silver nitrate to the Fe/SCN equilibrium introduces a common ion, Ag+, which reacts with SCN- to form a precipitate, reducing SCN- concentration and shifting the equilibrium to compensate, thus affecting the system.

Explanation:

The addition of silver nitrate to the Fe/SCN equilibrium affects the equilibrium even though silver ion or nitrate ion isn't part of the equilibrium reaction because it leads to the formation of a precipitate, AgSCN, thus reducing the concentration of free SCN− in the solution.

This is an example of the common ion effect, where the addition of a common ion shifts the position of equilibrium according to Le Chatelier's Principle. As AgSCN is removed from the solution, the equilibrium shifts to the left to restore balance, decreasing the concentration of Fe(SCN)2+ and lightening the color of the solution.

Adding silver nitrate to the Fe/SCN equilibrium affects the equilibrium by removing SCN− ions through precipitation, causing a shift in the equilibrium to the left. This results in a lower concentration of Fe[tex](SCN)^2^+[/tex] and a lighter solution color.

When silver nitrate is added to the Fe/SCN equilibrium, it affects the equilibrium even though neither silver ion nor nitrate ion is directly part of the equilibrium reaction. This is because silver ion (Ag+) reacts with thiocyanate ion (SCN−) to form a precipitate of AgSCN: [tex]Ag^+ _(_a_q_)[/tex] + [tex]SCN^-_(_a_q_)[/tex] = AgSCN (s)

This reaction removes SCN− ions from the solution, thereby reducing its concentration. According to Le Chatelier's principle, the equilibrium will shift to counteract this decrease by shifting to the left, thus decreasing the concentration of Fe(SCN[tex])^2^+[/tex] and causing the solution to become lighter in color.

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