In how many different orders can you line up 8 cards on a table? I'll FAN AND MEDAL!!!

Answers

Answer 1
To determine how many different orders in which you could line them up, you would need to perform a simple math problem. You would multiply 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1. This multiplication would give you 40320 different orders. You would multiply 8! because there are 8 different cards, and 8 different places in which they can be put in the order.

Related Questions

Amys class is selling books to raise money for a field trip. If each book sells for $7, how many books will they need to sell to raise $125?

Answers

You would start by setting up the equation:

7x=125 where x is equal to the number of books sold

x=17.9

Since you cannot sell .9 of a book, this must be rounded up to 18.
Therefore, Amy must sell 18 books.

Or an angle θ with the point (−20, −21) on its terminating side, what is the value of cosine?

Answers

cos(θ) = -20/√((-20)^2 +(-21)^2)
.. = -20/-√841 . . . . . . . . . . . . . . . . . θ is a 4th-quadrant angle, so cos(θ) > 0
.. = 20/29

The value of the cosine is 20/29.

Answer:

The value of cosine is [tex]\cos \theta=-\frac{20}{29}[/tex].

Step-by-step explanation:

It is given that an angle θ with the point (−20, −21) on its terminating side.

It means the right angle triangle is formed in third quadrant where length of the perpendicular is 21 and the base is 20.

According to the Pythagoras theorem,

[tex]hypotenuse^2=base^2+perpendicular^2[/tex]

[tex]hypotenuse^2=(20)^2+(21)^2[/tex]

[tex]hypotenuse^2=400+441[/tex]

[tex]hypotenuse^2=841[/tex]

Taking square root both the sides.

[tex]hypotenuse=\sqrt{841}[/tex]

[tex]hypotenuse=29[/tex]

In a right angled triangle,

[tex]\cos \theta=\frac{base}{hypotenuse}[/tex]

[tex]\cos \theta=\frac{20}{29}[/tex]

θ lie in the third quadrant and cosine is negative in third quadrant.

[tex]\cos \theta=-\frac{20}{29}[/tex]

Therefore the value of cosine is [tex]\cos \theta=-\frac{20}{29}[/tex].

A car dealership has seven cars in the lot. Unfortunately, the keys to the cars have been mixed up. The manager randomly grabs a key and tries to start a car salesman also randomly picks a different key and tries to start another car. What is the probability that both cars start?

Answers

To determine The probability of both of these occurring, you would multiply the probability of each together. So, there is a 1/7 chance of the first salesman getting the right key, and 1/6 chance of the second salesman getting the right key. 1/7 x 1/6= 1/42 chance of both occurring.

An airplane takes off from the ground and reaches a height of 500 feet after flying 2 miles. given the formula h = d tan θ, where h is the height of the plane and d is the distance (along the ground) the plane has flown, find the angle of ascent θ at which the plane took off.

Answers

First we convert everything to the same unit taking into account the following conversion:
 1 mile = 5280 feet
 So, we have:
 h = 500 feet
 d = 2 (5280) = 10560 feet
 Substituting in the given formula we have:
 h = d tan θ
 500 = 10560tan θ
 tan θ = 500/10560
 θ = Atan (500/10560)
 θ = 2.71 degrees.
 Answer:
 the angle of ascent θ at which the plane took off is: 
 θ = 2.71 degrees.

John let out 50 foot of kite string when he observes that his kite is directly above a point on the ground 30 feet away from him, how high is the kite ?

Answers

70 feet i believe confuseing to me

Answer:

the answer is 40 i had it on USATestPrep

Step-by-step explanation:

ion need one lml

Find the image of z(1,1) after two reflections first across L1 and then across L2

L1: y=2 L2: x-axis

L1: x=3 L2: y=2

Answers

I’m lab cooking up like rick s

In the right triangle shown, AC = BC = 7? What is AB?

Answers

Solve the right triangle shown in the figure
BC=2.7cm, AC=1.1cm, B wrong
so AB is the hypotenuse. It's an isocelels right traingle meaning the other two angles are 45 degrees. So AB = 7[tex] \sqrt{2} [/tex]. We know this because 45 45 is a special right triangle.

Speed = distance divided by time taken. car 1 travels 10 miles every 5 minutes. car 2 travels 30 miles every 20 minutes. what is the difference of speed between these two cars in mph?

Answers

car 1
2 miles............................1 minute
10 miles.........................5 minutes
20 miles.........................10 minutes
40 miles..........................20 minutes
car2
1.5 miles...........................1 minute
15miles.............................10 minutes
30 miles...........................20 minutes
the difference is 0.5 miles per minute

0.5*60=30 miles/hour

The quotient of a number and 2 is the same as the difference of the number doubled and 3

Answers

x/2=2x+3 is the expression you would use!

PLEASE MATH HELP WILL GIVE BRAINLIEST!!
The center of a circle is located at (-5, 2), and the radius of the circle is 5 units.

What is the equation of the circle in standard form?
Question 1 options:


(x−5)2 + ( y+2)2 = 10



(x+ 5)2 + (y−2)2 = 25



(x+5)2 + (y−2)2 = 10



(x−5)2 + (y+2)2 = 25

Answers

Hello,

Answer B

(x-(-5))²+(y-2)²=5²

(x+5)²+(y-2)²=25

A machine is set up to cut metal strips of varying lengths and widths based on the time (t) in minutes. The change in length is given by the function I(t)=t^2-squrt(t),, and the change in width is given by w(t)=t^2-2t^1/2. Which function gives the change in area of the metal strips?

Answers

If your choices are the following:
a. a(t) = t^4 + 2t 
b. a(t) = t^4 + 2t + 3t^(5/2) 
c. a(t) = t^4 - 3t^(5/2) + 2t` 
d. a(t) = t^4 + 2t - 2t^(1/2) + sqrt(t) 

The answer is letter c.a(t) = t^4 - 3t^(5/2) + 2t` 
Solution:
Area= length times width
Then to get the time, a=a(t), l=l(t), and w=w(t)
So, if Area= l times width
a(t)= l(t) • w(t)
a(t)=[t^2-squrt(t)] • [t^2-2t^1/2]
a(t) = [t^2 - t^(1/2)] • [t^2 - 2t^(1/2)]
=t^4 - 3t^(5/2) + 2t 

Answer:

'a(t)=t^4-3t^(5/2)+2t'

what is the vertex of the parabola

Answers

Let's consider the equation of parabola, y = a·(x - α)·(x - β)

where α, β are the x-intercepts.

From the given graph, the y-intercept is (0, -3).

From the given graph, the x-intercept are (-1, 0) and (3, 0) i.e. α = -1, β = 3.

So the equation of parabola would be now, y = a·(x + 1)·(x - 3)

We can plug the y-intercept (0, -3) in the equation to find value of 'a'.

-3 = a·(0+1)·(0-3)

-3 = -3a

a = 1

So the equation of parabola would be now, y = (x + 1)·(x - 3) = x² - 2x - 3

Comparing it with y = ax² + bx + c

The x-coordinate of vertex would be, [tex] x = \frac{-b}{2a} = \frac{-(-2)}{2(1)} =\frac{2}{2} = 1 [/tex]

the y-coordinate of vertex would be, y = (1)² - 2(1) - 3 = -4.

Hence, vertex would be (1, -4).

I️ need to find the answer

Answers

(a) m∠RQS = (1/2)m∠QPR = 37°

(b) m∠QPR = m(arc QR) = 74° . . . . . an arc has the same measure as its central angle

Michael takes a multiple-choice test with 5 answer choices for each question. If he randomly answers every question what is his expected score

Answers

I would say 20% chance because there are 5 question and getting one right is 20%. I don't really know how to explain. Hope this is right!

The vertex of this parabola is at (3, -2). When the x-value is 4, the y-value is 3. What is the coefficient of the squared expression in the parabola's equation?

Answers

the equation of a parabola in its vertex form is y=a(x-h)²+k, where (h, k) is the vertex of the parabola.
in this case, h=3, k=-2, so y=a(x-3)-2
plug (4,3) in the equation: 3=a(4-3)²-2, a=5
so the coefficient of the squared expression is 5.

Answer:[tex]\left ( y+2\right )^2=25\left ( x-3\right )[/tex]

Step-by-step explanation:

Given  

Vertex of Parabola is [tex]\left ( 3,-2\right )[/tex]

and parabola passes through [tex]\left ( 4,3\right )[/tex]

Let us take a parabola of the form

[tex]\left ( y-y_0\right )^2=4a\left ( x-x_0\right )[/tex]

And here [tex]\left ( x_0,y_0\right ) is \left ( 3,-2\right )[/tex]

therefore

[tex]\left ( y+2\right )^2=4a\left ( x-3\right )[/tex]

Now put [tex]\left ( 4,3\right)[/tex] as it lies on parabola

[tex]\left ( 3+2\right )^2=4a\left ( 4-3\right )[/tex]

[tex]a=\frac{25}{4}[/tex]

Thus Equation of parabola is

[tex]\left ( y+2\right )^2=25\left ( x-3\right )[/tex]

A contractor purchases 7 dozen pairs of padded work gloves for ​$94.92. He incorrectly calculates the unit price as ​$13.56 per pair for the expense report. What is the correct unit​ price? What is the​ error?

Answers

94.92/(7*12)=1.13 each pair
13.56-1.13=12.43 absolute error

The correct unit price for the work gloves is $1.13 per pair, and the error in the reported unit price is $12.43 per pair, as the contractor incorrectly reported it as $13.56 per pair.

The question is asking to calculate the correct unit price for the padded work gloves purchased by the contractor and to identify the error in the calculation provided in the expense report.

Firstly, let's determine the total number of pairs of gloves. Since 1 dozen represents 12 items, 7 dozen pairs of gloves will be [tex]7 \times 12 = 84[/tex] pairs of gloves.

Now, to find the correct unit price, we divide the total cost by the total number of pairs:

Unit Price = Total Cost / Total Number of Pairs

Unit Price = $94.92 / 84 pairs

Unit Price = $1.13 per pair

The incorrect unit price was calculated as $13.56 per pair. Therefore, the error in the calculation is:

Error = Incorrect Unit Price - Correct Unit Price

Error = $13.56 - $1.13

Error = $12.43 per pair

The contractor overestimated the unit price by $12.43 per pair.

If you flip three fair coins, what is the probability that you'll get all three tails?

Answers

probability of getting a tail = 1/2
pr(3 Tail) = 1/2 × 1/2 × 1/2
= 1/8

Let H be the event that head occurs and let T be the event that tail.

Then the complete Sample Space,S for the experiment given in the question is:

S={ HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}

As we can see the total number of elements in the sample space is 8. Let us represent this by the letter N.

Therefore, N=8

Now, the event of interest to us is TTT and it's occurrence is once. Let represent this by the letter E.

Therefore, E=1

Thus, the probability of the event E occurring is given as:

[tex] P(E)=\frac{E}{N}=\frac{1}{8} [/tex]

[tex] \frac{1}{8} [/tex] is the required answer. This can be represented in percentage too as:

[tex] \frac{1}{8}\times 100=12.5 [/tex]%

f(x) = (x − 3)(x + 3)[x − (2 − i)][x − (2 + i)] The function has real roots and imaginary roots.

Answers

The real roots are 3 and -3.
Imaginary roots:-
x - (2 - i) = 0
x = 2 -i  is one imaginary root and the other is  2 + i

Answer:

The function has

2 real roots and

2 imaginary roots.

please help asap! match equation to the graph

Answers

The answer is a)7x+7y=0

Answer:

B) -7x + 7y= -49

Step-by-step explanation:

Using the general equation for a line

y=mx+b

where m is the slope (positive if the line goes up from left to right and negative is it goes down from left to right)

and b is the point where the line crosses the y-axis

By th graph we can see that the line goes up from left to right, so the slope is positive, and that it crosses the y axis in -7, b= -7 and x is positive.

Solving for y in all the options

A) y = -x

B) y = x - 7

C) y = -x +7

D) y= x+7

the option that describes the line in the graph is B) -7x + 7y= -49 since when clearing for y we get y = x - 7 wich has a positive slope, and has an interception b = -7.

Please help! I'm very confused. 20 points.

Answers

1) Use the distributive property to eliminate parentheses.
.. 3(6x) -3(5) -7(3x) -7(10) = 0
.. 18x -15 -21x -70 = 0 . . . . . . finish multiplying terms
.. -3x -85 = 0 . . . . . . . . . . . . . collect like terms
.. -85 = 3x . . . . . . . . . . . . . . . .add 3x
.. -85/3 = x . . . . . . . . . . . . . . .divide by 3
.. -28 1/3 = x . . . . . . . . . . . . . write as mixed number


2) 5 -(6 +9x) = 9 -(4x -1)
.. 5 -6 -9x = 9 -4x +1 . . . . . eliminate parentheses using the distributive property
.. -1 -9x = 10 -4x . . . . . . . . . collect like terms
.. -1 = 10 +5x . . . . . . . . . . . . add 9x
.. -11 = 5x . . . . . . . . . . . . . . . subtract 10
.. -11/5 = x . . . . . . . . . . . . . . divide by 5
.. -2 1/5 = x . . . . . . . . . . . . . write as mixed number

A spinner has three sections. The table shows the results of spinning the arrow on the spinner 80 times. What is the experimental probability of the arrow stopping over Section 3? Section 1: 18 Section 2: 30 Section 3 :32

Answers

 the answer is 32/80 because the arrow stopped on section three 32 times out of the 80 spins

Answer: [tex]\dfrac{2}{5}[/tex]

Step-by-step explanation:

From the given table, The number of times arrow stops over Section 3  = 32

The total number of times spinner spins = 80

Now, the experimental probability of the arrow stopping over Section 3 is given by :-

[tex]P(S-3)=\frac{32}{80}\\\\\Rightarrow P(S-3)=\dfrac{2}{5}[/tex]

Hence, the experimental probability of the arrow stopping over Section 3  is [tex]\dfrac{2}{5}[/tex]

Crop researchers plant 15 plots with a new variety of corn. The yields in bushels per acre are: 138.0 139.1 113.0 132.5 140.7 109.7 118.9 134.8 109.6 127.3 115.6 130.4 130.2 111.7 105.5 Assume that bushels per acre. a) Find the 90% confidence interval for the mean yield for this variety of corn. b) Find the 95% confidence interval. c) Find the 99% confidence interval. d) How do the margins of error in (a), (b), and (c) change as the confidence level increases?

Answers

There is a relationship between confidence interval and standard deviation:
[tex]\theta=\overline{x} \pm \frac{z\sigma}{\sqrt{n}}[/tex]
Where [tex]\overline{x}[/tex] is the mean, [tex]\sigma[/tex] is standard deviation, and n is number of data points.
Every confidence interval has associated z value. This can be found online.
We need to find the standard deviation first: 
[tex]\sigma=\sqrt{\frac{\sum(x-\overline{x})^2}{n}[/tex]
When we do all the calculations we find that:
[tex]\overline{x}=123.8\\
\sigma=11.84[/tex]
Now we can find confidence intervals:
[tex]($90\%,z=1.645): \theta=123.8 \pm \frac{1.645\cdot 11.84}{\sqrt{15}}=123.8 \pm5.0\\($95\%,z=1.960): \theta=123.8 \pm \frac{1.960\cdot 11.84}{\sqrt{15}}=123.8 \pm 5.99\\ ($99\%,z=2.576): \theta=123.8 \pm \frac{2.576\cdot 11.84}{\sqrt{15}}=123.8 \pm 7.87\\[/tex]
We can see that as confidence interval increases so does the error margin. Z values accociated with each confidence intreval also get bigger as confidence interval increases.
Here is the link to the spreadsheet with standard deviation calculation:
https://docs.google.com/spreadsheets/d/1pnsJIrM_lmQKAGRJvduiHzjg9mYvLgpsCqCoGYvR5Us/edit?usp=sharing

a) For a 90% confidence interval: (117.838, 130.056)

b) For a 95% confidence interval: (117.543, 130.352)

c) For a 99% confidence interval: (113.816, 134.078)

d) As the confidence level increases, the margins of error also increase, resulting in wider confidence intervals, indicating greater certainty in the estimation of the true population mean yield.

To find the confidence intervals, we first calculate the sample mean and standard deviation of the yields. Then, we use the t-distribution with degrees of freedom (n-1) to determine the critical values for the given confidence levels. Finally, we use these critical values along with the sample mean and standard deviation to calculate the margins of error and construct the confidence intervals.

a) For a 90% confidence interval:

Sample mean = 123.947

Sample standard deviation = 11.669

Margin of error = t * [tex](s / sqrt(n)) = 1.761 * (11.669 / sqrt(15)) ≈ 6.109[/tex]

90% confidence interval: (123.947 - 6.109, 123.947 + 6.109) ≈ (117.838, 130.056)

b) For a 95% confidence interval:

Margin of error = [tex]2.145 * (11.669 / sqrt(15)) ≈ 7.404[/tex]

95% confidence interval: (117.543, 130.352)

c) For a 99% confidence interval:

Margin of error = [tex]2.947 * (11.669 / sqrt(15)) ≈ 10.131[/tex]

99% confidence interval: (113.816, 134.078)

d) As the confidence level increases, the margin of error also increases because the critical value from the t-distribution becomes larger, resulting in wider confidence intervals. This reflects the increased certainty associated with higher confidence levels.

The margins of error increase as the confidence level increases, indicating wider confidence intervals and greater certainty in the estimation of the true population mean yield.

When calculating the successive discounts of 15% and 10% on a $100 item, _____. a. take 10% of $85 b. take 10% of $90 c. take 15% of $85 d. take 25% of $100

Answers

It would be a, take 10% of $85 as the $15 is taken off first then the next discount is attached to the new price

Answrer

Option (a) is correct .

i.e  take 10% of $85

Reason

As given

15% and 10% on a $100 item i.e first applied 15 % discount on $ 100 and than apply 10% discount .

15 % is written in the decimal form

[tex]= \frac{15}{100}[/tex]

= 0.15

Amount becomes when 15 % discount on$100 = 100 - 0.15 × 100

                                                                              = 100 - 15

                                                                              = $ 85

Now apply 10 % discount on $ 85.

10 % is written in the decimal form

[tex]= \frac{10}{100}[/tex]

= 0.1

Amount becomes when 15 % discount on$100 = 85- 0.1 × 85

                                                                              = 85 - 8.5

                                                                              = $ 76.5

Therefore the option (a) is correct about the  successive discounts of 15% and 10% on a $100 item is $76.5 .




Please help asap!!!!!!!!!!18 points

Answers

a hope you get a good grade
I think it is C sorry if this doesnt help :'( :)

The area of a triangle is 40sq inches. If the base of the triangle is 10 inches what is it’s height?

Answers

area of a triangle= 1/2 base times height
substitute

40=1/2*10*x
40=5x
x=8

the height is 8 inches

Answer:

Step-by-step explanation: 8 inches

what are the solutions to the equion

plz answer right no it is 14

Answers

For this case we have the following equation:
 [tex]x^2 = 169[/tex]
 What we must do for this case is to clear the value of x.
 To do this, remember that when clearing you have two solutions.
 A solution is positive.
 A solution is negative.
 We have then:
 [tex]x = +/- \sqrt{169} x = +/- 13 [/tex]
 Therefore, the solutions are:
 [tex]x1 = 13 x2 = -13[/tex]
 Answer:
 
the solutions to the equation are:
 
[tex]x1 = 13 x2 = -13[/tex]

What is the value of x in the proportion StartFraction 6 x plus 1 over 7 EndFraction equals StartFraction 18 x minus 2 over 14 EndFraction?
A. 0
B. 3
C. two-thirds
D. one-fourteenth

Answers

The correct answer is:  [C]:  " two-thirds " .
____________________________________________________
" x =[tex] \frac{2}{3} [/tex] " ; which is:  " two-thirds " .
____________________________________________________
Explanation:
____________________________________________________

Given:  " [tex] \frac{6x + 1}{7} = \frac{18x-2}{14} [/tex] " ;  Solve for "x" ; 
____________________________________________________
First, multiply the first fraction by "[tex] \frac{2}{2} [/tex]" ;  
   { since: "[tex] \frac{2}{2} [/tex] = 1" ; and since any value, multiplied by "1" results in that exact same value.  By multiplying the first fraction by:                   "[tex] \frac{2}{2} [/tex]" , we can get the "denominator" in the first fraction equal to the "denominator" of the second fraction.

→ [tex] \frac{2}{2}*( \frac{6x + 1}{7})=\frac{2(6x+1)}{2(7)} =

    "\frac{2(6x+1)}{14} [/tex]" .
___________________________________________________________
Note the "distributive property of multiplication" :
_______________________________________________________
  a(b + c)  = ab  + ac ; 

  a(b – c)  = ab – ac .
_______________________________________________________
As such, take the "numerator" ; which is:

" 2(6x + 1) " ;  and expand:

→  =  (2*6x) + (2*1) =  " 12x + 2 " ;

Now, we can rewrite the entire expression:
________________________________________
    "[tex] \frac{12x+2}{14} [/tex]"  ;  and we can rewrite the entire equation:
________________________________________

→  " [tex] \frac{12x+2}{14} [/tex] = \frac{18x-2}{14} [/tex] " ;

Let us simplify this:  " 12x + 2 = 18x – 2 " ;  Solve for "x" ;
_____________________________________________________
   
  →  18x – 2 = 12x + 2 ; 

  →  Subtract "12x" from each side of the equation; and subtract "2" from each side of the equation:


  →  18x – 2 – 12x – 2 = 12x + 2 – 12x – 2 ; 

to get: 

       →  6x – 4 = 0  ; 

Add "4" to each side of the equation:

       →  6x – 4 + 4 = 0 + 4 ; 

to get:

       →  6x = 4  ;

Divide each side of the equation by "6" ;
  to isolate "x" on one side of the equation; & to solve for "x" ; 

→ 6x / 6  = 4 / 6  ;

→  x = 4/6 ;    "4/6" = "(4÷2)/(6÷2)" = "2/3" .

→  x = 2/3 ;    x =[tex] \frac{2}{3} [/tex] " ;  which is "two-thirds" ; 
         
                                            →  which is:  Answer choice:  [C]:  " two-thirds" .
__________________________________________________________

The correct value of x is [tex]\frac{2}{3}[/tex].

To find the value of x in the proportion [tex]\frac{6x+1}{7} = \frac{18x-2}{14}[/tex], follow these steps:

Cross-multiply to eliminate the fractions. Multiply 7 by (18x - 2) and 14 by (6x + 1):

7(18x - 2) = 14(6x + 1)

Expand both sides:

126x - 14 = 84x + 14

Move all terms involving x to one side and constant terms to the other side:

126x - 84x = 14 + 14

Simplify the equation:

42x = 28

Divide both sides by 42 to solve for x:

x = 28 ÷ 42 = [tex]\frac{2}{3}[/tex]

Therefore, the value of x is [tex]\frac{2}{3}[/tex] and the correct answer is option C.

Complete question: What is the value of x in the proportion [tex]\frac{6x+1}{7} = \frac{18x-2}{14}[/tex]?

A. 0

B. 3

C. [tex]\frac{2}{3}[/tex]

D. [tex]\frac{1}{14}[/tex]

If 5x^2 + y^4 = −9 then evaluate d^2y/dx^2 when x = 2 and y = 1. Round your answer to two decimal places.

Answers

The first derivative is found from
.. 10x +4y^3*dy/dx = 0
.. dy/dx = -5x/(2y^3)

Then
.. d^2y/dx^2 = d(dy/dx)/dx = (-5/2)(y^-3 -3xy^-4*dy/dx)

Evaluated at x=2, y=1
.. dy/dx = -5(2)/(2*1^3) = -5
.. d^2y/dx^2 = (-5/2)*(1^-3 -3*2*1^-4*(-5))
.. = (-5/2)(1 +30)
.. = -155/2 = -77.50

d^2y/dx^2 = -77.50 at the specified point.

PLEASE HELP ME WITH THIS QUESTION AND DON'T FORGET TO EXPLAIN

Answers

when n=0, d(n)=690. This is the y-intercept
All the functions given in the options are linear functions in the form y=mx+b, then we must find a function with independent term (y-intercept) b=690
The functions with b=690 are the first and third option.

For the slope (m), we can calculate it with 2 points of the table:
n1=0, d(n1)=690
n2=2, d(n2)=560

m=[d(n2)-d(n1)] / (n2-n1)
m=(560-690) / (2-0)
m= (-130) / 2
m=-65

Then the function must be:
d(n)=mn+b, m=-65, b=690
d(n)=-65n+690

Answer: Third option d(n)=-65n+690 
 

How many minutes greater is the software company's median than the bank's median?



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Answers

10.

The median is calculated by taking all values in a data set, placing them in order from least to greatest, and finding the value that is in the middle of the data set. In this case, the middle number (median) for Bank is 15. The middle number (median) for Software Company is 25. The difference between 25 and 15 is 10. So Software Company is 10 more minutes greater than Bank, 

Answer:

the answer is 10

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