In two or more complete sentences explain how to balance the chemical equation and classify its reaction type

Answer:

0.133 M

Explanation:

The volume of the solution is given, so in order to find concentration, the number of moles must be found, since C = n/V.

The balanced reaction equation is:

HI + KOH ⇒ H₂O + KI

Thus, the moles of KOH added to neutralize all of the HI will be equal to the moles of HI that must have been present.

The amount of KOH that was added is calculated as follows.

n = CV = (0.145 mol/L)(45.7 mL) = 6.6265 mmol KOH = 6.6265 mmol HI

Since HI and KOH are related in a 1:1 molar ratio, the same amount of HI must have been present.

Finally, the concentration of HI is calculated:

C = n/V = (6.6265 mmol) / (50.0 mL) = 0.133 mol/L = 0.133 M

The final molarity of the hydroiodic acid solution is 0.133 M.

To determine the molarity of the hydroiodic acid (HI) solution, we can use the relationship between the moles of HI and KOH used in the titration process. The balanced equation for the neutralization reaction is:

HI(aq) + KOH(aq) → KI(aq) + H₂O(l)

The reaction shows a 1:1 molar ratio between HI and KOH. Given the volume and molarity of the KOH solution, we can calculate the moles of KOH used:

Moles of KOH = Molarity of KOH × Volume of KOH (in liters) = 0.145 M × 0.0457 L = 0.0066265 mol

Since the ratio is 1:1, the moles of HI will be the same as the moles of KOH, which is 0.0066265 mol. Now we can find the molarity of the HI solution using the volume of HI solution:

Molarity of HI = Moles of HI / Volume of HI (in liters) = 0.0066265 mol / 0.0500 L = 0.13253 M

Therefore, the molarity of the hydroiodic acid solution is 0.133 M (rounded to three significant figures).

Answer:

Problem 1 = 25.0 ml

Problem 2 = Increase in temperature

Problem 3 = 2,52 atm

Problem 4 =

Problem 5 = true

Problem 6 =

Explanation:

1) v2 = v1P1/P2 = (50 x 20)/40 = 25.0 ml

2.- An increase in temperature because there is a direct relationship among pressure and temperature.

3.- P2 = P1T2/T1 = (2.8 x 360) / 400 = 1008/400 = 2,52 atm

4.-   7.5 L

5.- True

6.- Boyle's law               C) Pressure and volume

Charles's law                 A) Temperature and volume  

Gay-Lussac's law           B) Pressure and temperature

The concept Boyle's law is used here to determine the new volume. The behaviour of the gases is mainly studied on the basis of gas laws. The new volume of the gas is 25.0 mL. The correct option is C.

The Boyle's law states that at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure. At constant temperature the product of pressure and volume of a given mass of gas is constant.

Mathematically the law can be expressed as:

1. V ∝ 1 / P

V = k. 1 / P

PV = k (Constant)

For two different gases, the equation is:

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

20.0 × 50.0 / 40.0

V₂ = 25.0 mL

The new volume of the sample of gas is 25.0 mL.

Thus the correct option is C.

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Answer:

C)

Explanation:

The fats can be saturated or unsaturated. Saturated fats have only simple bonds between atoms of carbon. The unsaturated fats have one or more double bonds between atoms of carbon.

When there are double bonds in the carbon chain, the molecule can have geometric isometric, if the carbons of the double bond have different binders. The isomers are named cis and trans. The cis molecule has the equivalent atoms or structures (the same or mass equivalent) on the same side of the plan of the molecule. The trans molecule has this equivalent atoms or structures in the opposite side of the plan of the molecule (see figure below)

It happens in a way to stabilize the molecule. So, the trans fat, because of its disposition, has straightened the hydrocarbon chain, almost like the saturated molecule, then, they have similar characteristics.

Hydrogen was the most common gas in the Earth's early atmosphere. The introduction of oxygen happened much later with the process of photosynthesis. Despite being present later, oxygen was not a primary component of the initial atmosphere.

The gas that was most likely present in Earth's earliest atmosphere was hydrogen. This is based on scientific research, which suggests that the early atmosphere of the Earth was predominantly composed of light gases like hydrogen and helium. Over time, the Earth's atmosphere evolved and changed due to various geological and biological processes.

For instance, the process of photosynthesis introduced oxygen into the atmosphere much later in Earth's history. It's also important to note that despite being present, oxygen was not one of the primary components of Earth's early atmosphere.

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Answer:

Based on the conditions given as vapor pressure is 256 torr,the methanol-water interactions are stronger than the methanol-methanol and water-water interactions is the correct option.

The solution of methanol and water is non-ideal as the actual vapor pressure is lower than the expected value from Raoult’s law, indicating that the solute-solvent interactions are stronger than those within the pure components.

A solution of methanol and water with a mole fraction of water of 0.312 and a total vapor pressure of 21 torr at 39.9 degrees C is not displaying ideal behavior. In an ideal solution, Raoult's law predicts that the total vapor pressure is the sum of the partial pressures of the components, each calculated as the product of the pure component's vapor pressure and its mole fraction in the solution.

In this case, if we assume the solution is ideal, the expected vapor pressure would be higher because methanol and water have vapor pressures of 256 torr and 55.3 torr, respectively. The given total vapor pressure (21 torr) is significantly less than the expected value calculated using Raoult’s law, indicating that the solution exhibits non-ideal behavior.

This observation implies that the intermolecular interactions between methanol and water are stronger than those in the pure substances (methanol with methanol and water with water). Thus, the interactions in the mixture reduce the tendency to escape to the vapor phase, resulting in a lower total vapor pressure than predicted for an ideal solution.

Final answer:

To exceed the FDA's assumed sodium intake limit of 2,300 mg per day for an adult, one would have to consume approximately 44.23 liters of softened water with a sodium concentration of 5.2×10⁻²% by mass.

Explanation:

The question pertains to the consumption of softened water and its sodium concentration relative to the FDA recommendations for sodium intake. The FDA's recommended limit is not specified in the question, so for this explanation, we will assume a commonly referenced guideline limit of 2,300 mg sodium per day for an adult. The concentration of sodium in the softened water is given as 5.2×10⁻²% by mass. Given this and the density of water (1.0 g/mL), we can calculate the volume of softened water consumed that would exceed the FDA's recommended sodium intake limit.

If the softened water contains 5.2×10⁻²% sodium by mass, this means there are 0.052 grams of sodium in every 100 grams of the softened water. Since 1 mL of water weighs 1 gram, this also means there are 0.052 grams of sodium per 100 mL of water.

To find the volume (V) of water that contains 2,300 mg (2.3 grams) of sodium, we set up the following equation:

V (in mL) × 0.052 g/100 mL = 2.3 g.

Solving for V, we get:

V = (2.3 g × 100 mL) / 0.052 g

V = 44,230.77 mL.

Therefore, one would have to consume approximately 44.23 liters of this softened water to exceed the FDA recommendation for sodium intake.

Answer:

26.18 g

Explanation:

The molar volume of oxygen at 1 atm and 0ºC is 22.4 L/mol.

If you want to react 7 L it means you will use

7/22.4 = 0.3125 moles of oxygen

the balanced equation is 3 Fe + 2 O2 = Fe3O4

which means that 2 moles of oxygen reacts with 3 moles of iron

If you have 0.3125 moles of oxygen, 0.468 moles of iron will be needed.

Iron molecular weight is 55.84 and than, 0.3125 moles corresponds to a mass of iron equal to 26.18

To determine the mass of iron required to react with 7.0 L of oxygen, we need to use the balanced equation and the molar ratios between iron and oxygen.

To determine the mass of iron required to react with 7.0 L of oxygen, we need to use the balanced equation and the molar ratios between iron and oxygen. The balanced equation for the reaction is:

4Fe + 3O2 → 2Fe2O3

From the equation, we can see that it takes 4 moles of iron to react with 3 moles of oxygen to produce 2 moles of Fe2O3. First, we need to convert the volume of oxygen to moles by using the ideal gas law. At 0 degrees Celsius and 1 atm, the volume can be calculated as follows:

V = nRT/P

V = (7.0 L)(0.0821 L/mol·K)(273 K) / (1 atm)

V = 17.109 moles

Next, we need to use the molar ratios to determine the moles of iron required. Since the ratio is 4 moles of iron to 3 moles of oxygen, we can set up a proportion:

4 moles Fe / 3 moles O2 = x moles Fe / 17.109 moles O2

Solving for x:

x = (4 moles Fe)(17.109 moles O2) / 3 moles O2

x = 22.812 moles Fe

Lastly, we can convert the moles of iron into grams using the molar mass of iron:

(22.812 moles)(55.85 g/mol) = 1276.06 grams

Therefore, approximately 1276.06 grams of iron is required to react with 7.0 L of oxygen to produce Fe3O4.

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Answer:

The answer to your question is: 85.458 amu

Explanation:

data

Rubidium-85   A = 84.9118 amu   abundance = 72.15%  

Rubidium - 87  A = 86.9092 amu abundance = 27.85%

Atomic weight = ?

Atomic weight = 84.9118(0.7215) + 86.9092(0.2785)

Atomic weight = 61.2538 + 24.2042

Atomic weight = 85.458 amu

Rubidium has two naturally occurring isotopes, rubidium -85 ( atomic mass = 84.9118 amu; abundance = 72.15%) and rubidium -87 (atomic mass = 86.9092; abundance = 27.85%). The atomic weight of rubidium is 85.46 amu.

To calculate the average atomic mass of element use this formula

Average Atomic Mass = f₁M₁ + f₂M₂

where,

f = Fraction of natural abundance of isotope

M = Mass number of isotope

Isotope Rubidium -85 (Atomic mass = 84.9118 amu and Abundance = 72.15)

Abundance = [tex]\frac{72.15}{100}[/tex]

                    = 0.7215

Isotope Rubidium- 87 (Atomic mass = 86.9092 amu and Abundance = 27.85%)

Abundance = [tex]\frac{27.85}{100}[/tex]

                    = 0.2785

Now put the value in above formula, we get:

Average Atomic Mass = f₁M₁ + f₂M₂

                                     = (84.9118 × 0.7215) + (86.9092 × 0.2785)

                                     = 61.26 + 24.20

                                     = 85.46 amu

Thus from the above conclusion we can say that Rubidium has two naturally occurring isotopes, rubidium -85 ( atomic mass = 84.9118 amu; abundance = 72.15%) and rubidium -87 (atomic mass = 86.9092; abundance = 27.85%). The atomic weight of rubidium is 85.46 amu.

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Answer:

Cyanosis

Explanation:

Cyanosis is purplish or bluish discolouration of skin or the mucous membranes. The presence of the cyanosis occurs due to the increased quantity of the deoxyhemoglobin and the haemoglobin is not combined with the oxygen. The tissues near the surface of the skin become to have low oxygen saturation. The first signs of the cyanosis can be seen on lips or fingers or finger nails.

Answer:

a) 1.43 g/L

b) 1.27 g/L

Explanation:

Oxygen is an ideal gas, so, using the ideal gas equation:

PV = nRT  

Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature (always in Kelvin!).

n = mass (m)/molar mass (MM), so:

[tex]PV = \frac{m}{MM}RT[/tex]

PVMM = mRT

[tex]PMM = \frac{m}{V} RT[/tex]

m/V is the density (d), so:

d = [tex]\frac{PMM}{RT}[/tex]

R = 0.082 atm.L/(mol.K) and MM of O2 = 2x 16 = 32 g/mol

a) for STP, P = 1 atm and T = 0ºC = 273 K

d = [tex]\frac{1x32}{0.082x273}[/tex]

d = 1.43 g/L

b) P = 1 atm and T = 35ºC + 273 = 308 K

d = [tex]\frac{1x32}{0.082x308}[/tex]

d = 1.27 g/L

As oxygen is an ideal gas, the ideal gas equation is as follows:

[tex]PV= nRT[/tex]

P = pressure, V = volume, n = number of moles, R = gas constant, and T = temperature. n= m/MM

Thus, answers for calculated densities are 1.43g/L and 1,27g/L.

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Answer:

Because they are normally dissolved in water

Explanation:

The phospholipids can act as molecules that are carry inside or outside the cells, to transport it they are dissolved in another hydrophilic media, in this way the hydrophilic part can be in the outside part of the group of moleucles stick together like in cell membranes that are conformed by a double lipidic layer, in which the hydrophobic part it in the inside part. The cells normally are surrounded by different water solutions as the blood or another solutions.

Answer:

The concentration of the hydroxide ion concentration for muriatic acid is 3.16 * 10^-12 M

Explanation:

Muriatic acid = HCl

pH = 2.5

pH = -log[H+]

pOH = 14 - pH

pOH = 14 - 2.5 = 11.5

pOH = -log [OH-]

11.5 = -log [OH-]

[OH-] = 10^-11.5

[OH-] = 3.16 * 10^-12 M

The concentration of the hydroxide ion concentration for muriatic acid is 3.16 * 10^-12 M

Answer:

The six most important chemical elements of life are c. Carbon, nitrogen, oxygen, hydrogen, phosphate, and sulfur

Explanation:

Oxygen is the most abundant element and carbon is part of living organisms. Nitrogen is also abundant and hydrogen is a simple element that is found in all living organisms as well. Therefore, all of these 4 should be present in the answer. This excludes answers: a, b and d. The differences between c and e is that c includes sulfur while e includes calcium. Both include phosphate which is part of DNA and RNA. This leaves to decide which one is found in the highest concentration. Calcium is part of bones and compositions of several living organisms but sulfur is found in essential amino acids and it is necessary for bacteria and other microorganisms. So, c would be the correct answer.

Final answer:

The six most important chemical elements of life are carbon, hydrogen, nitrogen, oxygen, phosphorus, and sulfur, which make up almost all of a cell's mass and are key components of biological molecules.

Explanation:

Important Chemical Elements of Life

The six most important chemical elements of life are commonly known as the building blocks of living organisms. They form essential structures within cells and are involved in a myriad of biological processes. The six elements are carbon (C), hydrogen (H), nitrogen (N), oxygen (O), phosphorus (P), and sulfur (S). Combined, they constitute approximately 99% of the dry weight of cells and are the major components of nucleic acids, proteins, carbohydrates, and lipids. According to the options provided in the student's question and including the information above, the correct answer to the question is option c: Carbon, nitrogen, oxygen, hydrogen, phosphate, and sulfur.

Each of these elements plays a critical role:

Answer:

C₅H₁₂

Explanation:

To obtain the answer for this question we need to do a combustion analysis. When a hydrocarbon is heated, it means that it reacts with oxygen (O₂) to produce two known products which are carbon dioxide (CO₂) and water (H₂O), and by knowing the masses of these products, we can know the proportions of the elements that initially were part of the hydrocarbon, in this case, the C/H ratio.

First, we propose the next reaction, assuming that all the hydrocarbon sample was combusted:

CxHy(s) + O₂(g) → xCO₂(g) + yH₂O(g)

Now, with the provided masses of the carbon dioxide and the water, we can calculate the molar amounts of carbon and hydrogen in the sample.

First we calculate the molar masses:

C = 12.011 x 1 = 12.011 g/mol

O = 15.99 x 2 = 31.99 g/mol

CO₂ = 12.011 + 31.99 = 44.001 g/mol

H = 1.008 x 2 = 2.016 g/mol

O = 15.99 x 1 = 15.99 g/mol

H₂O = 2.01 + 15.99 = 18.006 g/mol

Now we obtain the molar amounts of C and H using the obtaines masses of carbon dioxide and water:

mol C = 30.50g CO₂ x (1mol CO₂)/(44.001 g/mol)  x (1mol C)/(1mol CO₂) = 0.6931 mol C

mol H = 14.98g H₂O x (1mol H₂O)/(18.006 g/mol)  x (2mol H)/(1mol H₂O) = 1.6638 mol H

Finally, we can obtain the H/C molar ratio by identifying the smaller whole-number ratio for these molar amounts. For this we can first divide each molar amount by the smaller amount:

mol C = 0.6931/0.6931 = 1

mol H = 1.6638/0.6931 = 2.4

As we are still getting a decimal amount for the hydrogen, what we can do is multiply both molar amounts by the smaller whole multiple that can give us a whole number for the hydrogen's molar amount, in this case, that multiple would be 5:

mol C = 0.6931/0.6931 = 1 x 5 = 5

mol H = 1.6638/0.6931 = 2.4 x 5 = 12

Now we can write the empirical formula for the hydrocarbon, which is:

C₅H₁₂

Final answer:

To determine the empirical formula of the hydrocarbon, we need to calculate the moles of carbon and hydrogen in the sample. Once we have the moles of carbon and hydrogen, we can determine the empirical formula by finding the simplest whole number ratio between the two elements.

Explanation:

To determine the empirical formula of the hydrocarbon, we need to calculate the molar amounts of carbon and hydrogen in the sample. From the given masses of carbon dioxide (30.50 g) and water (14.98 g), we can determine the moles of carbon and hydrogen in the sample. The molar ratios of carbon and hydrogen in the compound will give us the empirical formula.

First, let's calculate the moles of carbon and hydrogen:

Moles of carbon = mass of carbon dioxide / molar mass of carbon dioxide

Moles of hydrogen = mass of water / molar mass of water

Once we have the moles of carbon and hydrogen, we can determine the empirical formula by finding the simplest whole number ratio between the two elements.

For example, if we find that the moles of carbon is twice the moles of hydrogen, the empirical formula would be CH2.

Answer:

104.11 of solution could be heated till boiling at 1atm

Explanation:

For calculating this value, we are going to calculate it according to water whose heat capacity is 4.184 J/gC. We are going to use the value of entalphy of solution of the NaOH (-44.51kJ/mol in water at 25 celsius).

So, we have a heat balance

[tex]Q_{water} = Q_{NaOH}\\ m_{H2O} Cp_{H2O}\Delta T = m{NaOH} \Delta H {solution}\\[/tex]

Now, we know we have to calculate the mass of water and we know that water was initially at 25ºC, so we are going to take it into 100ºC. We also know that the heat of solution is given at kJ mol, so we have to do a transformation of units so we have the correct answer. We are going to change kJ into J and moles into grams

[tex]-44.51 \frac{kJ}{mol} * \frac{1mol NaOH}{39.9gNaOH} *\frac{1000J}{1kJ} = -1115.54 \frac{J}{g} NaOH[/tex]

Now, changing the values into the heat balance we obtain

[tex]m_{water} = \frac{m_{NaOH}*\Delta H}{Cp*\Delta T}\\ m _{water} = 104.11 g H2O[/tex]

Answer:

98.086 g/mole

Answer: The empirical formula is [tex]SeO_2[/tex].

Explanation:

So, the mass of each element is given:

Mass of Se = 1.443 g

Mass of O = 0.5848 g

Step 1 : convert given masses into moles.

Moles of Se=[tex]\frac{\text{ given mass of Se}}{\text{ molar mass of Se}}= \frac{1.443g}{79g/mole}=0.018moles[/tex]

Moles of O = [tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{0.5848g}{16g/mole}=0.036moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Se = [tex]\frac{0.018}{0.018}=1[/tex]

For O =[tex]\frac{0.036}{0.018}=2[/tex]

The ratio of Se: O = 1: 2

Hence the empirical formula is [tex]SeO_2[/tex].

Answer:

The length (quantitative measurement) of the pencil is 5.5

Explanation:

Quantitative measurement are type of measurements which result in numbers    

with or without appropriate unit .

To obtain the length of the pencil , the pencil starts from 0 of the scale and ends at 5.5 , hence the value is 5.5.

Quantitative measurement in the picture is the LENGTH of the pencil shown in the picture.

The value of quantitative measurement obtained from the picture is 5.5 , therefore length of the pencil is 5.5 .

Answer:

7.1

Explanation:

equation to calculate pH is

[tex]pH=-Log_{10}(a_{H^+})=-Log_{10}(8*10^-8) = -Log_{10}(8)-Log_{10}(10^{-8})=-0.9+8=7.1 [/tex]

Answer:

1st: Light excites an electrom from photosystem II

2nd: Light excites an electrom from photosystem I

3rd: Electrons pass through an electron chain, which generates a H+ gradient used to make ATP

4th: Electron reduce NADP+ to NADPH

Explanation:

While the light simultaneously excites both photosystems, it must first occur in photosystem II and then be able to transfer the e-energized to photosystem I

1st Step:

Within the photosystems we find different photosynthetic pigments, that is, capable of absorbing light. These pigments are classified according to the maximum absorption wavelengths.

When the light hits the photosystems they absorb it and the delocalized -e (electrons) are energized or "excited".

Then these energized ones are transferred to molecules within the membrane that houses the pigments.

The e- that takes the photosystem I are provided by the photosystem II

2nd and 3rd Step:

The -e energized from photosystem II are transferred to a transport chain of -e within the membrane containing the pigments. As these -e circulate, they lose energy that is used to translocate H + (protons).

The accumulation of H + within the membrane generates an electrochemical gradient.

H + return to the stroma through the enzyme ATP synthase. This operation is called chemosmosis.

This enzyme uses H + to catalyze the synthesis of ATP (ADP + Pi), a process called phosphorylation.

4th Step:  

The e-energized of photosystem I are used to reduce NADP + and generate NADPH that are used in conjunction with ATP to generate "light independent reactions"

Those lost from photosystem I are replaced by e-de-energized from photosystem II, while those lost from photosystem II are replaced by e-released from water by photolysis.

Water is divided by the energy of light into H + (used in chemosmosis) and oxygen (released as a byproduct)

The correct order of the steps for the light reactions in photosynthesis is: Light excites an electron from photosystem II, electrons pass through an electron transport chain, excitation of an electron in photosystem I, and finally, the reduction of NADP+ to NADPH i.e. 2, 4, 1, 3.

The correct order of the steps for the light reactions in photosynthesis is:

This process starts with the absorption of light in photosystem II, which excites electrons. These electrons pass through an electron transport chain that uses the energy from the electrons to pump H+ ions and establish a gradient. This H+ gradient is used to synthesize ATP. Finally, light is absorbed by photosystem I which leads to the reduction of NADP+ to NADPH.

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The ion with a 2+ charge is the one with 10 protons, 9 neutrons, and 8 electrons because there are two more protons, which are positively charged, than electrons, which are negatively charged thus giving it a positive charge.

The correct answer is A: an ion with 10 protons, 9 neutrons, and 8 electrons. The charge of an ion is determined by the difference in the number of protons (positive charges) and electrons (negative charges). Note that the numbers of protons and electrons match exactly in a neutral atom. Therefore, an ion with 10 protons and 8 electrons would have a charge of 2+, since there are two more protons than electrons, giving it an overall positive charge.

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An ion with a charge of 2+ is an ion with 10 protons, 9 neutrons, and 8 electrons (option A).

To determine which ion has a charge of 2+, we need to understand that an ion with a 2+ charge has lost two electrons compared to its neutral state. Let's examine the options:

The correct answer is A, as it is the only ion with a 2+ charge.

a) The total weight of the resulting mixture is 128 grams.

b) The percentage of the resulting mixture is copper is 81.25% copper.

a) Weight of alloy with 52% copper = 50 grams

Weight of pure copper = 78 grams

Total weight of resulting mixture = Weight of alloy + Weight of pure copper

                                                      = 50 grams + 78 grams

                                                      = 128 grams

So, the resulting mixture contains 128 grams.

b) To find the percentage of copper in the resulting mixture, you can use the following formula:

Percentage of copper = (Total weight of copper / Total weight of mixture) × 100

Total weight of copper = Weight of copper in alloy + Weight of pure copper

                                      = (52% of 50 grams) + 78 grams

                                      = 26 grams + 78 grams

                                      = 104 grams

Now, Percentage of copper = (104 grams / 128 grams) × 100

                                               = 81.25%

So, the resulting mixture contains 81.25% copper.

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The resulting mixture weighs 104 grams and contains 25% copper.

To calculate the grams in the resulting mixture, we need to add the masses of the two components. The alloy contains 50 grams of a 52% copper alloy, which means it contains 0.52 * 50 = 26 grams of copper. The pure copper weighs 78 grams. Adding these two masses together, we get:

Total mass of resulting mixture = 26 grams + 78 grams = 104 grams

To calculate the percentage of copper in the resulting mixture, we need to divide the mass of copper by the total mass of the mixture and multiply by 100. Using the values we calculated earlier:

Percentage of copper in resulting mixture = (26 grams / 104 grams) * 100 = 25%

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Answer:

The answer to your question is below

Explanation:

The atom in a chemical bond that attracts electrons more strongly acquires a(n)__negative______ charge, and the other atom acquires a(n)_positive_______ charge. If the electron transfer is significant but not enough to form ions, the atoms acquire _dipoles_________ and charges. The bond in this situation is called a polar covalent bond.

Answer:

The mass chloride is 2.903 grams

Explanation:

Step1: calculate the moles of FeCl3

moles = molarity  x  volume  in liters

volume in liters = 100 ml /1000 =  0.1 L

molarity = 0.273  M  =  0.273  mol / L

moles   =   0.273  mol /L  x 0.1 L = 0.0273   moles

step 2:  find the moles of Cl

since there is  3  atoms of  cl in FeCl3

= 3 x 0.0273 =0.0819 moles

Step 3:  calculate  mass  of cl

 mass= moles  x molar mass

=0.0819 moles x 35.45 g/mol = 2.903 g

The mass of chloride in grams is 2.903 grams.

Mass is defined as the quantitative measure of inertia, a fundamental properties of all the matter.

It can also be defined as the amount of matter present in any object or matter.

First calculate moles of FeCl3

Moles = Molarity x Volume in liter

Molarity = 0.273 mole / liter

Volume = 100ml = 0.1 l

Moles = 0.273 x 0.1 = 0.0273 moles

For FeCl3 3 molecules of Cl is needed

So, Moles of Cl = 3 x 0.0273

                         = 0.0819 moles

Now calculate the mass of Cl

Mass = moles x molar mass

         = 0.0819 x 35.45

         = 2.903 grams

Thus, the mass of chloride in grams is 2.903 grams.

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Answer:

a. P atoms introduce additional mobile negative charges

Explanation:

Silicon atoms have a valency of 4, this means that there are 4 electrons in their outermost orbital. Thus, in silicon crystals, each Si atom is connected to 4 different Si atoms.

When we replace a few of these Si atoms with P atoms, which have a valency of 5, 4 out of these 5 outermost electrons will be bonded with the surrounding Si atoms. The fifth electron would not be bonded, meaning it would be free to move, acting as a mobile negative charge carrier (See the picture below).

Just to be clear, regarding option c), it's true that Ge atoms have more electrons that Si atoms, however that it's not a reason for an increase in conductivity.

When a small fraction of silicon (Si) atoms in a crystal are replaced with a different element, such as phosphorus (P) or germanium (Ge), the conductivity of the crystal increases. This increase in conductivity is due to P atoms introducing additional mobile negative charges, which allow electrons to move freely and contribute to the conductivity. This is known as n-type doping.

When a small fraction of silicon (Si) atoms are replaced with those of a different element, such as phosphorus (P) or germanium (Ge), the conductivity of the Si crystals increases. The correct reason for this increase in conductivity is that P atoms introduce additional mobile negative charges. These extra electrons from the P atoms are able to move freely within the crystal lattice, contributing to the conductivity of the material. This type of doping with impurities is called n-type doping, where the primary carriers of charge are negative electrons.

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Answer: The value of n =2.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadro's number}}=\frac{8.06\times 10^{20}}{6.023\times 10^{23}}=0.0013moles[/tex]

0.0013 moles of [tex]XeF_n[/tex] weigh = 0.227 grams

Thus 1 mole of [tex]XeF_n[/tex]  will weigh = [tex]\frac{0.227}{0.0013}\times 1=174.62[/tex]  grams

Molar mass of [tex]XeF_n[/tex] = [tex]1(131.3)+n(19)=174.62[/tex]

[tex]n=2[/tex]

Thus the value of n =2

The xenon fluoride compound is likely XeF2. This was deduced by relating the given mass and number of molecules of the compound to its molar mass and Avogadro's number. The calculated molar mass fits best with that of XeF2.

The subject of your question lies in the area of analytical chemistry, specifically in calculations involving the concept of the mole. Here we want to find the molecular formula for the xenon fluoride, XeFn using the data provided. We know the Avogadro's number which states that one mole of any substance contains 6.02 x 1023 molecules.

In this question, we're given that 8.06 x 1020 molecules of XeFn weigh 0.227 g. We can calculate the molar mass of this specific compound. To elaborate, if one mole weighs 'M' grams and contains 6.02 x 1023 molecules, then 0.227 g would have (0.227/M) moles or (0.227/M) x 6.02 x 1023 molecules. If we set this equal to 8.06 x 1020 and solve for 'M', the molar mass of the compound, we can calculate a value of approximately 169 g/mol.

Given that the molar mass of xenon (Xe) is about 131 g/mol and that of fluorine (F) is approximately 19 g/mol, we can reason that the molar mass of the compound XeFn is closest to that of XeF2, since 131 + 2(19) = 169 g/mol. Therefore, the xenon fluoride compound being referred to in the problem is XeF2.

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Answer:

D)  D

Explanation:

yes it is correct took the test

Answer:

The answer is A

Explanation:

I just got it correct on USA test Prep

Answer:

1.25 dollars.

Explanation:

The balanced reaction will be

[tex]2 HCL+CaCO_3----------> CaCl_2+H_2O+CO_2[/tex]

mole ratio of [tex]CaCO_3[/tex] and HCl is 1 : 2

mole of HCl will be as

0.500 L HCl × 0.4 mol/L = 0.2 mol HCl

moles of [tex]CaCO_3[/tex] will be as

0.2 mole HCl × 1 mol [tex]CaCO_3/2[/tex] mol HCl = 0.1 mol [tex]CaCO_3[/tex]

mass of [tex]CaCO_3[/tex] will be calculated as :

0.1 mol [tex]CaCO_3[/tex] × 100.1 g / 1 mol [tex]CaCO_3[/tex] = 10.01 g [tex]CaCO_3[/tex]

Now 40.0% [tex]CaCO_3[/tex] = [tex]\frac{40}{100}[/tex] = 0.4 [tex]CaCO_3[/tex]

mass of [tex]CaCO_3[/tex] / (80 tablets × 1 g /tablets × 0.4 = number of containers

[tex]\frac{10.01}{32}[/tex] = 0.3128125 (number of containers)

Cost = number of containers × $4.00

        = 0.3128125 × 4.00

       =  $1.25

Cost would be $1.25.

From the illustration, the total cost of Tumsr would be 1.25 dollars.

From the equation of the reaction:

CaCO₃ + 2HCl -----------> CaCl2 + CO2 + H2O

Mole ratio of CaCO₃ and HCl = 1:2

Mole of 0.5 L, 0.4 M HCl = 0.5 x 0.4 = 0.2 moles.

Equivalent mole of CaCO₃ = 0.2/2 = 0.1 moles

Mass of 0.1 mole CaCO₃ = 0.1 x 100.09 = 10 grams

Each Tumsr contains 40% CaCO₃ by mass. Meaning that each contains 0.4 grams.

        10/0.4 = 25 Tumsr

A container of Tumsr containing 80 tablets costs 4.00 dollars, each tablet will then cost:

    4/80 = 0.05 dollars

25 Tumsr will then cost = 0.05 x 25 = 1.25 dollars

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Answer:

B

It contains more protons than electrons.

Answer:

A  It contains more electrons than protons.

Explanation:

An atom basically consists of three entities protons, electrons and neutrons.  

While protons and neutrons are present inside the nucleus and contributes to the total mass of the atom, electrons remain outside the nucleus and only contribute -1 charge per electron.

In an atom, a proton has +1 charge and mass equivalent to 1 a.m.u, a neutron has 0 charge and mass equivalent to 1 a.m.u  and an electron has -1 charge and 0 mass (negligible).

Atomic number of an atom = number of electrons in that atom = number of protons in that atom.

In a neutral atom, the number of electrons are equal to the number of protons so their positive and negative charges counter balance each other thereby making the atom neutral.

But, if an atom gains an electron from an atom of any other element then it will acquire a net negative charge.

For example, a chlorine atom (Cl) when gains an electron it becomes Cl⁻.

                          Cl + e⁻    →     Cl⁻

Answer:

compound

Explanation:

Answer: homogeneous

Explanation :