B. A car slowing as it reaches a stop light
Explanation:
According to Newton's second law, the net force exerted on an object is equal to the product between its mass and its acceleration:
[tex]F=ma[/tex]
where
F is the net force
m is the mass of the object
a is its acceleration
This means that when an object is experiencing unbalanced forces ([tex]F\neq 0[/tex]), it must have a non-zero acceleration. Therefore, let's analyze the different options:
A. A box resting on a horizontal floor --> FALSE. Here the acceleration is zero, so no unbalanced forces.
B. A car slowing as it reaches a stop light --> TRUE. Since the car is slowing down, its velocity is changing, so the acceleration is non-zero and there are unbalanced forces.
C. A car with its cruise control set to 50 mph --> FALSE. Here the velocity is constant, so no acceleration and no unbalanced forces.
D. A rocket sitting on the launch pad --> FALSE. Here the rocket is stationary, so no acceleration, and no unbalanced forces.
Learn more about Newton's second law:
brainly.com/question/3820012
#LearnwithBrainly
An object experiences unbalanced forces when the resultant force on it is non-zero. A car slowing as it reaches a stop light experiences unbalanced forces due to the brakes exerting a force, causing it to decelerate. Hence, the correct answer is B. A car slowing as it reaches a stop light.
In the question, we are asked to determine in which situation an object is experiencing unbalanced forces. An object experiences unbalanced forces when the resultant force acting on it is non-zero, leading to a change in its motion. If we analyze the options given:
A box resting on a horizontal floor is not experiencing unbalanced forces, because it is at rest and there are no net forces acting to change its state of motion (assuming no frictional losses).A car slowing as it reaches a stop light is experiencing unbalanced forces because the brakes are exerting a force opposite to the direction of motion, causing the car to decelerate.A car with its cruise control set to 50 mph is travelling at a constant velocity, indicating that the forces are balanced.A rocket sitting on the launch pad is not experiencing unbalanced forces if it is stationary and not in the process of takeoff.Therefore, the correct answer is B. A car slowing as it reaches a stop light, because this is when it is experiencing a net force that is causing a change in its motion.
A body on the circular orbit makes an angular displacement given by ∅(t)=2t^2+5t+5. If time t is in seconds, calculate the angular velocity at t=2s
Answer:
Angular Velocity at 2 s= 13 rad/s
Explanation:
∅(t)=2[tex]t^{2}[/tex] + 5t + 5
where represents angular displacement at any given time t
Angular Velocity (ω)= [tex]\frac{\textrm{d ∅(t) }}{\textrm{dt}}[/tex]
ω=4t+ 5
Putting in t=2
ω=8+5=13 rad/s
Which sphere of Earth includes the continental ice sheets and glaciers? Biosphere Cryosphere Geosphere Hydrosphere
Answer:
C. Cryosphere
Explanation:
The definition for Cryo is:
Involving extreme Coldness and etc.
There are studies done on Cyro Freezing the body to preserve the body until there is a cure for a deadly disease. They do this as well to try to live in the future. Our technology hasn't been able to get the people alive yet, but when we do.
If you ever need to think of "Cryo" just think of Cryo Freezing.
Answer:
C.
Explanation:
Micha ran 2 miles north in 20 minutes. She then turned back and ran 1 mile in 15 minutes. To cool down, she walked the rest of the way home. It took her 20 minutes.
What was Micha's average velocity for her run north?
What was Micha's average velocity for the whole trip?
What was her average speed for her entire jog?
Answer:
Micha's average velocity for her run north, v₁ = 6.06 miles/hrMicha's average velocity for the whole trip, V = - 0.32 miles/hrThe speed of her jog is, s = 3.03 miles / hrExplanation:
Given data,
The distance Micha run towards the north, d₁ = 2 miles
The time taken by Micha to run 2 miles is, t₁ = 20 min
= 0.33 h
The displacement towards the south, d₂ = -1 mile
The running duration, t₂ = 15 min
= 0.25 h
Walked displacement, d₃ = -1 mile
The time period to cover that distance, t₃ = 0.33 h
1) The average velocity towards north,
v₁ = d₁ / t₁
= 2 / 0.33
= 6.06 miles/hr
Hence, Micha's average velocity for her run north, v₁ = 6.06 miles/hr
2) The average velocity for whole trip,
V = (v₁ + v₂ + v₃) / 3
The velocity towards south,
v₂ = d₂ / t₂
= -1 / 0.25 h
= -4 miles / hr
The walked velocity,
v₃ = d₃ / t₃
= -1 / 0.33
= - 3.03 miles/hr
∴ The average velocity,
V = (v₁ + v₂ + v₃) / 3
= (6.06 - 4 -3.03)/3
= - 0.32 miles/hr
Hence, Micha's average velocity for the whole trip, V = - 0.32 miles/hr
3) The average speed for her entire jog,
The velocity of her jog, v₃ = - 3.03 miles/hr
∴ Speed,
s = |v|
= 3.03 miles / hr
Hence, the speed of her jog is, s = 3.03 miles / hr
What two models are used to describe how light behaves
The two models used to describe light are the ray model, which is useful in geometric optics for large surfaces, and the wave model, which explains diffraction and color. At the atomic level, the particle model describing light as photons is also used.
Explanation:The two models used to describe how light behaves are the ray model and the wave model. The ray model of light simplifies its behavior to straight-line paths, which is particularly useful in geometric optics, where light's interaction with large surfaces—such as reflections from mirrors and refractions through lenses—is considered. The wave model, on the other hand, is essential for explaining phenomena like diffraction and the observation of colors, representing light as electromagnetic waves with different frequencies.
Furthermore, at the scale where light interacts on the level of individual atoms, the particle model of light, which describes light as photons, becomes more apparent. This model is crucial for understanding concepts like the photoelectric effect. Therefore, depending on the scale of the interaction and the nature of the observation, either model—or sometimes both—may be more appropriate for describing the behavior of light.
A bullet fired from a pistol with a barrel of 0.30 m travels at 800.0 m/s determine the time it takes the bullet to travel down barrel
The time taken is [tex]3.75\cdot 10^{-4}s[/tex]
Explanation:
The motion of the bullet is a uniform motion (=constant velocity), therefore we can use the following equation:
[tex]v=\frac{d}{t}[/tex]
where
v is the speed of the bullet
d is the distance covered
t is the time taken
For the bullet in this problem,
d = 0.30 m is the distance travelled
v = 800.0 m/s is the speed
Solving for t, we find the time taken:
[tex]t=\frac{d}{v}=\frac{0.3}{800}=3.75\cdot 10^{-4}s[/tex]
Learn more about speed:
brainly.com/question/8893949
#LearnwithBrainly
A mass of 2kg is at attached to a spring with constant 8N/m. It is then displaced to the point x=2. What time does it take for the block to travel to the point x=1?
Answer:
0.523598776 seconds
Explanation:
m =2 kg , k =8 N/m
[tex]w = \sqrt {\frac {k}{m}}[/tex]
[tex]w=\sqrt {\frac {8}{2}}= 2 rad/s[/tex]
x = xm cos(wt)
1 =2 cos(2t)
cos 2t=0.5
[tex]2t=cos^{-1} 0.5=1.047197551[/tex]
t=0.523598776 seconds
Final answer:
The time it takes for a 2kg mass attached to a spring with a spring constant of 8N/m to move from x=2 to x=1 is π/4 seconds, which is one-quarter of the period of oscillation in simple harmonic motion.
Explanation:
To calculate the time it takes for a 2kg mass attached to a spring with a spring constant of 8N/m to travel from the point displaced at x=2 to the point x=1, we must understand simple harmonic motion (SHM). In SHM, the angular frequency ω can be determined by the formula ω = √(k/m), where k is the spring constant, and m is the mass of the object attached to the spring. The period of oscillation is given as T = 2π/ω. It's important to note that the time taken to travel from x=2 to x=1 is one-quarter of the period, because the motion from the maximum displacement to the equilibrium position constitutes one-quarter of the cycle of oscillation.
Applying the given values:
Spring constant, k = 8 N/m
Mass, m = 2 kg
We calculate the angular frequency:
ω = √(k/m) = √(8/2) = 2 rad/s
The period of oscillation, T, is:
T = 2π/ω = 2π/2 = π seconds
The time taken to travel from x=2 to x=1 is one-quarter of this period:
Time = T/4 = π/4 seconds.
Maye is running an experiment to determine if a car with large tires will move faster than a car with small tires. her ramp is 0.7 m long she recording the following times on each of her trials: Trial 1:2.5 seconds, Trial 2: 2.75 seconds, Trial 3: 2.98 seconds. what was the average speed of her car?
Answer:
0.256 m/s
Explanation:
Speed is distance over time.
Find the speed of each trial and then find the average.
Trial 1: v = 0.7 m / 2.5 s = 0.280 m/s
Trial 2: v = 0.7 m / 2.75 s = 0.255 m/s
Trial 3: v = 0.7 m / 2.98 s = 0.235 m/s
v_avg = (0.280 m/s + 0.255 m/s + 0.235 m/s) / 3
v_avg = 0.256 m/s
Round as needed.
A 233 N weight object is pushed with a force of 474. If friction is 316 what is the net force on the object?
The net force on the object is equal to 158 N.
Explanation:
Net force is the sum of all the forces acting on an object. The forces might be acting in different direction. In some cases, there may be large forces acting on an object but in opposite direction and cancel out each other. The net force will be zero.
Net Force = F1 + F2 + F3 + ..... + Fn
Friction force is the force resisting the relative motion of an object. The frictional force can be because of the medium of a solid surface. As friction is a resistive force, its direction is always opposite to the force that is moving the object.
In the given problem, the force that is moving a 233 N object is F1 given as:
F1 = 474 N
While the frictional Force is F2 in a direction opposite to the motion of the object so we will use negative sign as a convention.
F2 = -316 N
Finding the net Force:
Net Force = F1 + F2
= 474 + (-316)
= 474 - 316
= 158 N
Learn more about Net Force from https://brainly.com/question/8375195
#learnwithBrainly
A net force of 50 N is applied to a 10 kg cart that is already moving at 3 m/s. The final velocity of the cart was 8 m/s. For How long was the force applied
Answer:
1 second
Explanation:
Assuming that the force is in the same direction as speed we can do the graphic.
Draw the forces present on the problem (weight and the net force).Newton's second law. The summation of the forces is equal to the product between mass and aceleration.[tex]F = m * a[/tex]Plan the equation on x direction (because the mass is moving on that way). The result would be: [tex]50 = 10 * a[/tex]From that equation we know that the aceleration is 5m/s2.Also, we know (because it is a uniform line movement) that the aceleration is related with the speed. [tex]s_{f} = s_{0} + a * t[/tex] Clearing the equation: [tex]\frac{s_{f} - s_{0} }{t} = a[/tex]And replacing: [tex]\frac{8-3}{t} = 5[/tex]So, the force is applied for 1 second.1. When a particle moves in a circle with constant speed, its acceleration is
A) constantly increasing.
constant in direction.
C) zero.
D) constant in magnitude.
E) constant in magnitude and direction.
Answer:
Its A.
Explanation:
6. Suzie hammers on a block of wood when she is 85 meters from a large brick wall. Each time she
she hits the block, she hears an echo 0.50 s later. With this information, show that the speed of
sound is 340 m/s.
Answer:
85 ÷ 0.50÷340=z z is the answer
A tumbleweed rolls from x = 25.6 m
to x = -14.4 m in 7.90 s. What was
its average velocity?
(Unit = m/s)
Answer:
-5.06 m/s
Explanation:
The formula to calculate average speed is
V = x2 - x1 / t2 - t1
The start point of the tumbleweed is 25.6m and the final point is -14.4 m
The start time is 0s and the final time is 7.9s
Replacing the values the result is -5.06m/s.
The result of the speed is negative because the direction of the speed is opposite to the direction of the tumbleweed.
Explain the role of gravity and inertia in keeping the moon in orbit? 15points pleaseee
Answer:
The gravity pulls the sun and the planets together, while keeping them apart. The inertia provides the tendency to maintain speed and keep moving. The planets want to keep moving in a straight line because of the physics of inertia. However, the gravitational pull wants to change the motion to pull the planets into the core of the sun. Together, this creates a rounded orbit as a form of compromise between the two forces.
Final answer:
Gravity acts as a centripetal force pulling the Moon towards Earth, while inertia gives the Moon its straight-line momentum. Together, they balance each other out, keeping the Moon in a stable elliptical orbit around Earth. The gravity gradient also affects the Moon's rotation and contributes to the equilibrium between Earth and the Moon.
Explanation:
Gravity and Inertia in Maintaining the Moon's Orbit
The Moon remains in orbit around the Earth due to the combined effects of gravity and inertia. Gravity, a fundamental force discovered by Isaac Newton, acts as a centripetal force that pulls the Moon towards the center of the Earth. Without this force, the Moon would move in a straight line into space. On the other hand, inertia is the tendency of an object to maintain its state of motion unless acted upon by an external force. The Moon has a momentum perpendicular to the gravitational pull of the Earth which would allow it to move in a straight line. These two forces together create a delicate balance that results in the Moon's smooth, elliptical orbit around the Earth.
The gravity gradient also plays a role in the Moon's rotation and orbital characteristics. This gradient explains why the Moon is slightly elongated towards the Earth and contributes to maintaining its stable orbit. Furthermore, the Earth and Moon stay in equilibrium since the gravitational force of attraction between them is perfectly balanced by the centrifugal force, stemming from their relative motion.
In summary, gravity acts to pull the Moon towards the Earth, while inertia contributes to the Moon's tendency to move forward. Together, these forces create the conditions for a stable, synchronous orbit, manifesting in phenomena such as synchronous rotation and the consistent face of the Moon that is always directed towards Earth.
What are the reactants in the following chemical equation NaCl+AgF=>NaF+AgCl
Answer:
NaCl,AgF
Explanation:
Chemical equations show the reactants and products, as well as other factors such as energy changes, catalysts, and so on. With these equations, an arrow is used to indicate that a chemical reaction has taken place. In general terms, a chemical reaction follows this format:
Reactants→Products
So the reactants of the given reaction are NaCl,AgF
The reactants in the chemical equation NaCl+AgF → NaF+AgCl are sodium chloride (NaCl) and silver fluoride (AgF).
Explanation:The reactants in the chemical equation NaCl+AgF → NaF+AgCl are sodium chloride (NaCl) and silver fluoride (AgF). In this reaction, a double displacement reaction, also known as a metathesis reaction, occurs where the elements in the reactants switch places, resulting in the formation of new compounds. The sodium ion (Na+) and the fluoride ion (F-) form sodium fluoride (NaF), while the silver ion (Ag+) and the chloride ion (Cl-) form silver chloride (AgCl), which is a precipitate, as illustrated in various silver reaction equations provided.
How can citizen -scientists help with the prediction of future earthquakes
Answer:
Avoid downed power lines and stay away from buildings and bridges from which heavy objects might fall during an aftershock. Stay away until local officials tell you it is safe. A tsunami is a series of waves that may continue for hours. Do not assume that after one wave the danger is over.
A ramp is used to load furniture onto a moving truck. The person does 1240 J of work pushing
the furniture up the ramp, and the ramp does 822 J of work. Calculate the efficiency of the
ramp.
Answer: 66.29%
Explanation:
Efficiency = work output / work input x 100 %
Work output = 822J
Work input = 1240 L
E = 822/1240 x 100
E = 0.6629 x 100
E = 66.29%
a wrench weighs 5.24 newtons on earth. when it is taken to the Moon, where g =1.16 m/s2 how much does it weigh?
The weight of a wrench on the Moon is 0.624 Newtons.
Weight of the wrench = 5.24 N
The gravitational acceleration on the moon = 1.16 m/s²
Gravitational acceleration on earth = 9.8 m/s².
Weight is calculated by the formula = W = m × g
First, we need to find the mass of the wrench on Earth using Earth's gravity:
m = W ÷ g
m= 5.24 N ÷ 9.8 m/s²
Then we use the mass of the wrench to calculate its weight on the Moon:
Weight on the moon = m × gravity on moon
By substituting the values, we get:
Weight on the moon = m × 1.16 m/s² = (5.24 N / 9.8 m/s²) ×1.16 m/s²
After calculating, the weight of the wrench on the Moon would be:
Weight on the moon = 0.624 N
Select the correct answer.
Thirst is a sign of dehydration.
A.
True
B.
False
Reset
Next
Answer:
this is a trap ur done
A 150kg motorcycle starts from rest and accelerates at a constant rate along a distance of 350m. The applied force is 250N and the coefficient of kinetic friction is 0.03.
A - Find the net force applied to the motorcycle.
B - Find the acceleration of the motorcycle.
C - What is its speed at the end of 350m?
D - Find the elapsed time of this acceleration.
[Explain and Show Work]
A) The net force on the motorbike is 205.9 N
B) The acceleration of the motorbike is [tex]1.37 m/s^2[/tex]
C) The final speed is 5.2 m/s
D) The elapsed time is 3.80 s
Explanation:
A)
There are two forces acting on the motorbike:
- The applied force, F = 250 N, forward
- The frictional force, [tex]F_f[/tex], backward
The frictional force can be written as
[tex]F_f = \mu mg[/tex]
where
[tex]\mu=0.03[/tex] is the coefficient of kinetic friction
[tex]m=150 kg[/tex] is the mass of the motorbike
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
Therefore the net force is given by
[tex]\sum F = F - F_f = F - \mu mg[/tex]
And substituting, we find
[tex]\sum F=250 - (0.03)(150)(9.8)=205.9 N[/tex]
2)
The acceleration of the motorbike can be found by using Newton's second law, which states that the net force is equal to the product between mass and acceleration:
[tex]\sum F = ma[/tex]
where
m is the mass
a is the acceleration
In this problem, we have
[tex]\sum F = 205.9 N[/tex] is the net force
m = 150 kg is the mass
Solving for a, we find the acceleration:
[tex]a=\frac{\sum F}{m}=\frac{205.9}{150}=1.37 m/s^2[/tex]
C)
Since the motion of the motorbike is a uniformly accelerated motion, we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For this motorbike, we have:
u = 0 (it starts from rest)
[tex]a=1.37 m/s^2[/tex]
s = 350 m
Solving for v,
[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(1.37)(9.8)}=5.2 m/s[/tex]
4)
For this part of the problem, we can use the following suvat equation:
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the elapsed time
Here we have:
v = 5.2 m/s
u = 0
[tex]a=1.37 m/s^2[/tex]
Solving for t, we find
[tex]t=\frac{v-u}{a}=\frac{5.2-0}{1.37}=3.80 s[/tex]
Learn more about Newton's laws of motion and accelerated motion:
brainly.com/question/11411375
brainly.com/question/1971321
brainly.com/question/2286502
brainly.com/question/2562700
brainly.com/question/9527152
brainly.com/question/11181826
brainly.com/question/2506873
brainly.com/question/2562700
#LearnwithBrainly
Answer:
This is a great question
*copy and paste for my physics homework* lol
a 30kg child who is running at 4m/s jumps onto a stationary 10kg skateboard. what is the approximate speed of the child and skateboard
Answer:
v=3 m/s
Explanation:
the formula for this problem is
V = v 1 ( m 1 / m 1 + m 2 )
we if we substitute ans solve we get this the answer as 3 m/s
Child and stationary skateboard move with same speed, as child jumps onto skateboard. Approximate speed of child and skateboard is 3 m/s.
What is conservation of momentum?Momentum of a object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity.
When the two objects collides, then the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.
Thus by the law of conservation of momentum,
[tex](m_1u_1)+(m_2u_2)=(m_1+m_2)v[/tex]
Here, [tex]m_1,m_2[/tex] are the masses of two bodies and [tex]u_1,u_2[/tex] are the initial velocities.
Given information-
The mass of the child is 30 kg.
The speed of the child is 10 m/s.
The mass of the skateboard is 10 kg.
Let the speed of the child and skateboard is [tex]v[/tex] m/s.
As the the child and jumps down onto a stationary skateboard then, the speed of child and skateboard should be same.
Thus by the conservation of momentum,
[tex](m_cu_c)+(m_su_s)=(m_c+m_s)v[/tex]
As the initial velocity of the skateboard is 0. Put the values in the above formula as,
[tex](30\times4)+(10\times 0)=(30+10)v\\120+0=40v\\v=3\rm m/s[/tex]
Thus the approximate speed of the child and skateboard is 3 m/s.
Learn more about the conservation of momentum here;
brainly.com/question/7538238
a piece of metal with a mass of 15.3 grams has a temperature of 50.0°C. When the metal is placed in 80.2 grams of water at 21.0°C, the temperature rises by 4.3°C. What is the specific heat capacity of the metal?
Final answer:
The specific heat capacity of the metal can be calculated using the equation q = m*c*ΔT. By substituting the given values into the equation and rearranging, we can find that the specific heat capacity of the metal is approximately 0.33 J/g°C.
Explanation:
The specific heat capacity of a substance is the amount of energy required to raise the temperature of 1 gram of the substance by 1°C. In this question, we can use the equation:
q = m*c*ΔT
Where q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
Given that the metal has a mass of 15.3 grams and the temperature rises by 4.3°C, and the water has a mass of 80.2 grams and the temperature rises by 4.3°C, we can substitute these values into the equation to find the specific heat capacity of the metal:
qmetal = mmetal * cmetal * ΔTmetal
qwater = mwater * cwater * ΔTwater
The specific heat capacity, cmetal, can then be calculated by rearranging the equation:
cmetal = (qmetal - mwater * cwater * ΔTwater) / (mmetal * ΔTmetal)
Plugging in the given values, we find that the specific heat capacity of the metal is approximately 0.33 J/g°C.
While taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40. meters per second on a runway that is 70. meters long. What is the magnitude of the acceleration of the jet? Group of answer choices
The acceleration of the jet is [tex]11.4 m/s^2[/tex]
Explanation:
Since the jet motion is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the jet in this problem, we have
u = 0 (it starts from rest)
v = 40 m/s (final velocity)
s = 70 m (length of the runway)
Solving for a, we find the acceleration:
[tex]a=\frac{v-u}{t}=\frac{40^2-0}{2(70)}=11.4 m/s^2[/tex]
Learn more about acceleration:
brainly.com/question/9527152
brainly.com/question/11181826
brainly.com/question/2506873
brainly.com/question/2562700
#LearnwithBrainly
The magnitude of the acceleration of the jet is approximately 11.43 m/s².While taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40.
To determine the magnitude of the acceleration of the jet, we can use the following kinematic equation:
v² = u² + 2as
where:
v is the final velocity (40 m/s),
u is the initial velocity (0 m/s, starting from rest),
a is the acceleration
and s is the displacement (70 m).
a = (v² - u²) / (2s)
a = (40² - 0²) / (2 × 70)
a = 1600 / 140
a ≈ 11.43 m/s²
Therefore, the magnitude of the acceleration of the jet is approximately 11.43 m/s².
To know more about acceleration:
https://brainly.com/question/2303856
#SPJ6
a bucket of mass 2kg is whirled in a vertical circle of radius 1.20M. at the lowest point of its motion the tension in the rope supporting the bucket is 25N. find the speed of the bucket
The speed of the bucket is 1.8 m/s
Explanation:
The bucket is in circular motion, therefore the net force acting on it is equal to the centripetal force:
[tex]F=m\frac{v^2}{r}[/tex]
where
m = 2 kg is the mass of the bucket
v is its speed
r = 1.20 m is the radius of the circle
At the lowest point of motion, there are two forces acting on the bucket:
The tension in the rope, T = 25 N, upward (same direction as the centripetal force, acting towards the centre of the circle)The force of gravity, [tex]mg[/tex], where [tex]g=9.8 m/s^2[/tex] is the acceleration of gravityTherefore the equation of motion for the bucket is:
[tex]T-mg=m\frac{v^2}{r}[/tex]
And solving for v, we find the speed of the bucket:
[tex]v=\sqrt{r(\frac{T}{m}-g)}=\sqrt{(1.20)(\frac{25}{2}-9.8)}=1.8 m/s[/tex]
Learn more about circular motion:
brainly.com/question/2562955
brainly.com/question/6372960
#LearnwithBrainly
QUICK: Using this energy transformation diagram of a battery drill, what is the drill’s thermal energy output?
Answer:
35
Explanation:
The students in Miss Washburn’s class use different methods to conduct
investigations. Which of the following is an example of an experiment?
Group of answer choices:
A) Determining the effect of sunlight on the growth of roses
B)Taking notes on where birds prefer to build nests
C) Making a scale model of the planets of the solar system
D) Recording the number of species of birds in an ecosystem
Answer:
b
Explanation:
mass×acceleration of a triangle =force
Answer:
The force acting on a body is always equal to the product of the mass of the body and its acceleration.
Explanation:
The force of a body is defined as the product of mass and acceleration of the body.
According to Newton's second law, wherever there is a change in momentum of the body for an interval of time, there is a force acting on it.
F = (mv - mu) / t
= m (v -u) /t
= m a
Where,
(v - u)/t - is the change in velocity of the body in the interval of time. It is equal to the acceleration of the body.
Hence, the equation for the force for any body becomes, F = m x a
Mg represents the element
Answer:
Mg is the symbol for Magnesium. Atomic #- 12
Explanation:
A ramp is used to load furniture onto a moving truck. The person does 1240 J of work pushing
the furniture up the ramp, and the ramp does 822 J of work. Calculate the efficiency of the
ramp.
Answer:
The efficiency of the ramp is, Eff = 6.63 %
Explanation:
Given,
The work done by the person pushing the furniture up the ramp is, W₁ = 1240 J
The work done by the ramp is, W₀ = 822 J
The efficiency of the ramp is given by the formula,
Eff = ( W₀ / W₁ ) x 100%
= ( 822 / 12400 ) x 100%
= 6.63 %
Hence, the efficiency of the ramp is, Eff = 6.63 %
Answer:
The efficiency of the ramp is, Eff = 6.63 %
Explanation:
What would happen to Mars (orbiting around the Sun, obviously) if its tangential velocity was reduced
to zero.
a. It would still continue to orbit the sun
b. It would escape the Sun's gravity and travel out of the Solar System
c. It would eventually crash into the Sun
d. None of the above
Answer:
It would eventually crash into the Sun
Explanation:
If the mars is orbiting around the sun, the gravitational force of attraction is between the sun and mars supply the necessary force required for the centripetal motion.
If a planet is in centripetal motion, it is constantly falling towards the sun with the acceleration equal to the gravitational strength at that point.
If the centripetal acceleration of the planet is removed, still the planet would accelerate linearly falling towards the sun.
Hence, if the planets tangential velocity was reduced to zero, It would eventually crash into the Sun
It takes four barbarians to turn the wheel below. How many barbarians would it take if the wheel radius were doubled and the axle radius stayed the same?
A. Fewer than four barbarians.
B. Exactly four barbarians.
C. More than four barbarians.
D. Not enough information.
Answer:
A. Fewer than four barbarians.
Explanation:
Mechanical advantage = wheel radius / axle radius
If the wheel radius doubles and the axle radius stays the same, then the mechanical advantage doubles. That means the effort force is half. So we expect it would take half as many barbarians to turn the wheel.
If the wheel radius were doubled and the axle radius stayed the same, it would take fewer than four barbarians.
What is mechanical advantage?Assuming there is no friction in the system, the ratio of the force that performs the useful work to the force applied is the theoretical mechanical advantage of a system.
The extent by which the mechanical advantage really differs from the theoretical value in actuality depends on the amount of friction.
Theoretically, for a wheel and axle system is:
the mechanical advantage = Radius of wheel/ radius of the axle.
As the wheel radius were doubled while the axle radius remains the same; the mechanical advantage of the system will become greater and fewer than four barbarians were needed now.
Learn more about mechanical advantage here:
https://brainly.com/question/16617083
#SPJ5