Rob found that the coefficient of determination between the length of essays submitted to a teacher x and the score the teacher gave the essay y was about 0.661. What can we conclude?

Simplify as much as possible

1,750,932 x 2,355,435 = 4,124,206,515,420

4,124,206,515,420 x Y cannot be simplified anymore, therefore,

4,124,206,515,420 x Y is your answer

~Rise Above the Ordinary, Senpai

All we need to do here is simplify, since there is no given answer to y. The numbers you've provided are quite large, so I'd suggest just using a calculator, unless they're supposed to be decimals. The simplified answer to this is 412,320,615,420y.

344 180 274 358 64 121 32 96 151 275 93 49

Out of the 12 numbers above, 5 (in bold type) are 100 or less.

5/12 = 0.41666...

Answer: 0.417

The probability that an employee selected randomly has a birthday in the first 100 days is 0.417

Recall :

Probability = required outcome / Total possible outcomes

Total possible outcomes :

Required outcomes :

Therefore,

Therefore, the selection probability is 0.417

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I think your answer is B.

Answer:

Quadratic, because the height increases and then decreases.

Step-by-step explanation:

In an exponential function, the graph will either increase or decrease over the entire domain.  It does not change direction.

We can see from the table that the heights increase and then decrease; this means it cannot be an exponential function.

A quadratic function has a graph that is u-shaped.  It will start out either increasing or decreasing, and then after the maximum or minimum is reached, it changes direction.

We can see from the table that this is what the heights do; this means it is a quadratic function.

(2, 0) would be the new x - intercept.

The equation of a parabola can be written in vertex form as:

y = a(x - h)² + k

Here, h represents the x-coordinate of the vertex. The x-intercepts of the parabola are the points where the parabola crosses the x-axis (i.e., where y = 0).

Given that one x-intercept is at (-4, 0), we know that x-intercepts are symmetrically located around the vertex. If the vertex's x-coordinate h is increased by 6, the entire parabola shifts horizontally to the right by 6 units.

Since the x-intercept is affected by the shift in the vertex:

Before the shift: one of the x-intercepts is at -4.

After the shift by h, the new x-intercept will be located 6 units to the right of the original intercept.

Therefore, the new x-intercept will be at:

-4 + 6 = 2

Each friend received 10 ounces of pears after Dillion divided the 3 1/3 pound bag among them.

First, we need to convert the weight of the pears from pounds and thirds to decimal form.

To do this, we divide the 3 1/3 pounds by 16 (since there are 16 ounces in a pound):

3 1/3 pounds = 3 * (1 + 1/3) pounds = 3.333 pounds

Now we know that each friend received 3.333 pounds / 5 friends = .6666 pounds of pears. To convert this decimal into something more understandable, multiply it by 16 since there are 16 ounces in a pound:

.6666 pounds * 16 = 10 ounces

So, each friend received 10 ounces of pears.

Each friend received 10 ounces of pears after Dillion divided the 3 1/3 pound bag among them.

First, we need to convert the weight of the pears from pounds and thirds to decimal form.

To do this, we divide the 3 1/3 pounds by 16 (since there are 16 ounces in a pound):

3 1/3 pounds = 3 * (1 + 1/3) pounds = 3.333 pounds

Now we know that each friend received 3.333 pounds / 5 friends = .6666 pounds of pears. To convert this decimal into something more understandable, multiply it by 16 since there are 16 ounces in a pound:

.6666 pounds * 16 = 10 ounces

So, each friend received 10 ounces of pears.

Answer : A

Example: 5 × 8 = 40

A.  8 × 5 = 40

the commutative property of multiplication allows us to multiply the numbers in any order without changing the product. In example we have 5 * 8 . When we change the order it becomes 8 * 5. So here applies commutative property of multiplication.

B.  10 × 4 = 40

the commutative property of multiplication allows us to multiply the numbers in any order without changing the product. In example we have 5 * 8 . When we change the order it becomes 8 * 5. So here it does not applies commutative property of multiplication.

C.  20 × 2 = 40

the commutative property of multiplication allows us to multiply the numbers in any order without changing the product. In example we have 5 * 8 . When we change the order it becomes 8 * 5. So here it does not  applies commutative property of multiplication.

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

[tex]P(\text{ getting a commemorative stamp})=0.16[/tex]

and

[tex]P(\text{getting a special delivery stamp})=0.18[/tex]

So, we need to find,

[tex]P(\text{getting either a commemorative or a special delivery stamp})\\=P(\text{getting a commemorative stamp})+P({\text{ getting a special delivery stamp})[/tex]

(∵they are independent events .)

[tex]P(\text{getting either a commemorative or a special delivery stamp})\\=0.16+0.18\\=0.34[/tex]

So, option 'D' is correct.

its (a.) thats  it try it

Answer:

Deposit each quarter = $342.68

Step-by-step explanation:

Formula use in this problem:

[tex] FV=C\times \left [ \frac{(1+i)^n-1}{i} \right ]\times (1+i) [/tex]

Where,  

          FV is future value, FV=$3000

C is cash flow quarterly( need to find),C=?

I is rate of interest ( divide by 4), i=[tex] \frac{0.08}{4}=0.02 [/tex]

N number of cash flow, n=8

Substitute all these values into formula to solve for C

[tex] 3000=C\times \left [ \frac{(1+0.02)^8-1}{0.02} \right ]\times (1+0.02) [/tex]

[tex] C=\frac{3000\times 0.02}{[(1+0.02)^8-1]\times (1+0.02)}[/tex]

So, C=$342.68

Final answer:

To achieve $3000 in 2 years in an account with 8% interest compounded quarterly, you should deposit $364.11 each quarter.

Explanation:

To find out how much you need to deposit each quarter to have $3000 in 2 years in an account that pays 8% interest compounded quarterly, you would use the future value of a series formula given by:

S = R [((1 + i)^n - 1) / i]

Where:

S = the future value of the series (in this case, $3000)

R = the regular deposit amount per period (what we're solving for)

i = the interest rate per period (8% per year or 0.08 divided by 4 for quarterly = 0.02)

n = the total number of compounds over the period (2 years * 4 quarters/year = 8 compounds)

Plugging in our values:

$3000 = R [((1 + 0.02)^8 - 1) / 0.02]

$3000 = R * [((1.02)^8 - 1) / 0.02]

$3000 = R * 8.2432

So, solving for R, we get:

R = $3000 / 8.2432 = $364.11

Therefore, to have $3000 in 2 years with an account that pays 8% interest compounded quarterly, you need to deposit $364.11 at the start of each quarter.

2x+50=7x

50 = 5x

x = 10

2(10) + 50

20 + 50

= 70 degrees

The expression that could be Amina's result is [tex]x = \dfrac{12 \pm \sqrt{-8}}{4}[/tex]

Which expression could be Amina's result?

From the question, we have the following parameters that can be used in our computation:

The list of options

Also, we have that

Her result shows two solutions that are complex numbers with imaginary parts

This can be expressed as

[tex]x = \dfrac{a \pm i\sqrt{b}}{c}[/tex]

From the list of options, the expresion that are of the above form are

[tex]x = \dfrac{12 \pm \sqrt{-8}}{4}[/tex]

hence, the expression that could be Amina's result is [tex]x = \dfrac{12 \pm \sqrt{-8}}{4}[/tex]

Question

Amina used the quadratic formula to solve an equation. Her result shows two solutions that are complex numbers with imaginary parts. Which expression could be Amina's result?

Larry is 2365 feet above sea level. Hope this helps :o

Answer: the answer is b 2,741 sorry im late

Solution :

Given that in the right triangle , ∠A=30° and AB = 12√3 .

As the figure is missing and its not clearly mentioned that AB is the base or hypotenuse of the right triangle. So two cases arises-

Case 1: AB is the base for ∠A of  the right triangle (as shown in figure 1).

As we know from the trigonometric ratio that, [tex]cos(\theta) = \frac{base}{hypotenuse}[/tex]

Here , AB is the base and AC is the hypotenuse , and ∠A=30°

[tex]\Rightarrow cos(30)=\frac{AB}{AC} \\\\\Rightarrow AC=\frac{AB}{cos(30)}[/tex]

The value of [tex]cos(30)=\frac{\sqrt{3} }{2}[/tex]

[tex]\Rightarrow AC=12\sqrt{3}\times\frac{2 }{\sqrt{3} }\\\\\Rightarrow AC=24[/tex]

Hence, AC is 24 unit long.

Case 2: AB is the hypotenuse for ∠A of  the right triangle (as shown in figure 2).

As we know from the trigonometric ratio that, [tex]cos(\theta) = \frac{base}{hypotenuse}[/tex]

Here , AB is the hypotenuse and AC is the base, and ∠A=30°

[tex]\Rightarrow cos(30)=\frac{AC}{AB} \\\\\Rightarrow AC=AB\timescos(30)[/tex]

The value of [tex]cos(30)=\frac{\sqrt{3} }{2}[/tex]

[tex]\Rightarrow AC=12\sqrt{3}\times\frac{\sqrt{3}}{2}\\\\\Rightarrow AC=18[/tex]

Hence, AC is 18 unit long.

Answer:

y=8x/9

Step-by-step explanation:

Given that 8 euros were worth $9 and

24 euros were worth $27.

Let y represent the number of Euros and x no of dollars.

Given that the relation is of the form y = kx+C

When x=0 y =0,

i.e. C =0

Hence equation is of the form y = kx

Substitute x=8 and y =9

We get 9 = 8k

Or k =8/9

Hence relation is y=8x/9 is the relation between x and y.

WE can verify this for 27 dollars worth 24 euros.

24 =8/9(27) is true.

Thus equation is verified.

The digit in the hundred millions place is 9.

Final answer:

The digit in the hundred-millions place of the number 875,932,461,160 is 7.

Explanation:

The digit in the hundred-millions place of the number 875,932,461,160 is 7. Let's break down the places of the number:

So in the number 875,932,461,160, 7 is the digit in the hundred-millions place.

It is the transformation shown in (B)

(look at one point of the letter P and how it moves precisely 3 units. Also there is only the move, no flipping of the figure)

Answer is B.

B shows a translation of 3 units to the right

The answer is 32 Why?

Because since it's getting added by times 2 for every number the number after 16 would be 32 when doing 16 x 2 and since the last number being -16 was negative the number after it would be positive, also if you want it more straight forward the 32 cannot be negative because when you times a negative with a positive you get a positive. Hope this helps!  

The original price of the computer was $411. This was found by adding the reduction amount to the final price, i.e., $355 + $56.

This question is concerned with a simple arithmetic operation. It's provided that the price of the computer was reduced by $56 to $355. The original price should thus be the markdown plus the final price.

Performing this calculation:
Add the amount of reduction ($56) to the current price ($355).

The solution is:
$355 (final price) + $56 (reduction) = $411 (original price)

Therefore, the original price of the computer was $411

So, option D is ($411) correct .

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In a right triangle, the sum of the squares of the legs is the square of the hypotenuse.

So, you would have

[tex] a^2+b^2=c^2 [/tex]

If you plug the values, you have

[tex] (2\sqrt{3})^2+b^2=(2b)^2 [/tex]

So, you end up with a quadric equation in b:

[tex] 12+b^2=4b^2 \iff 3b^2=12 \iff b^2=4 \iff b=2 [/tex]

So, the three sides are

[tex] a=2\sqrt{3},\ b=2,\ c=4 [/tex]

(3x^2 + 2x + 7X^3) + (10x^2 + 6x + 9)

Combine all the like terms.

There is only one term with X^3 so that stays the same.

Add 3X^2 and 10x^2 to get 13x^2.

Add 2x and 6x to get 8x.

There is only one term with a variable, so that also stays the same.

Now place them in order from highest exponent to lowest:

7x^3 + 13x^2 + 8x + 9

The answer is A.

Answer:

The correct answers are 40, 120, 240, and 320

Step-by-step explanation:

.

Answer:

1 ,3 , 4, 6

Step-by-step explanation:

we are given

[tex]f(x)=2x^4-x^3+x-2[/tex]

we can check each options

option-A:

-1,1

we can plug x=-1 and x=1 and check whethet f(x)=0

At x=-1:

[tex]f(-1)=2(-1)^4-(-1)^3+(-1)-2[/tex]

[tex]f(-1)=0[/tex]

At x=1:

[tex]f(1)=2(1)^4-(1)^3+(1)-2[/tex]

[tex]f(1)=0[/tex]

so, this is TRUE

option-B:

0,1

we can plug x=0 and x=1 and check whethet f(x)=0

At x=0:

[tex]f(0)=2(0)^4-(0)^3+(0)-2[/tex]

[tex]f(0)=-2[/tex]

At x=1:

[tex]f(1)=2(1)^4-(1)^3+(1)-2[/tex]

[tex]f(1)=0[/tex]

so, this is FALSE

option-C:

-2,-1

we can plug x=-2 and x=-1 and check whethet f(x)=0

At x=-2:

[tex]f(-2)=2(-2)^4-(-2)^3+(-2)-2[/tex]

[tex]f(-2)=36[/tex]

At x=-1:

[tex]f(-1)=2(-1)^4-(-1)^3+(-1)-2[/tex]

[tex]f(-1)=0[/tex]

so, this is FALSE

option-D:

-1,0

we can plug x=-1 and x=0 and check whethet f(x)=0

At x=-1:

[tex]f(-1)=2(-1)^4-(-1)^3+(-1)-2[/tex]

[tex]f(-1)=0[/tex]

At x=0:

[tex]f(0)=2(0)^4-(0)^3+(0)-2[/tex]

[tex]f(0)=-2[/tex]

so, this is FALSE

1.  2a=9b  first we will divide the both sides with parameter b and get

2(a/b)=9 now we will divide both sides with number 2 and get

a/b=9/2 => a : b = 9 : 2

2. 6a-3b=5b first we will add to both sides number (+3) and get

6a=5b+3b => 6a=8b then divide the both sides with parameter b and get

6(a/b)=8 now we will divide the both sides with number 6 and get

a/b=8/6 if we simplify the fraction we get  

a/b=4/3 => a : b = 4 : 3

3.  a+b=3b we will add to the both sides parameter (-b) and get

a=3b-b => a=2b then divide the both sides with parameter b and get

a/b=2 => a/b=2/1 => a : b = 2 : 1

4.  a/5=b/7 first we will divide the both sides with paremeter b and get

a/(5b)=1/7 now we will multiply the both sides with number 5 and get

a/b=5/7 => a : b = 5 : 7

Good luck!!!

The ratio a:b in the four problems given are 9:2, 4:3, 2:1, and 5:7 respectively. This is achieved by isolating 'a' in each equation and simplifying the resulting expression.

Let's find the ratio between a:b for each of the problems you've provided:

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