Sally and Maria were running around the track during PE. They were not happy and decided to stop and rest once they got to the bleachers. After a 10 minute rest, they started running again, but Sally tripped and fell. At what time during their run did Sally fall for a minute? A) at 4 minutes B) at 14 minutes C) at 15 minutes D) at 20 minutes

Answer:

Angular velocity, [tex]\omega_f=9.180\ rad/s[/tex]

Explanation:

It is given that

Initial angular velocity of the wheel, [tex]\omega_o=49\ rpm[/tex]

Since, 1 revolutions per minute =  0.10471 radians per second

[tex]\omega_o=49\ rpm=5.1307\ rad/s[/tex]

Angular acceleration of the wheel, [tex]\alpha =0.45\ rad/s^2[/tex]

Time taken, t = 9 s

Let [tex]\omega_f[/tex] is the final velocity of the wheel 9 seconds later. Using the equation of kinematics to find it :

[tex]\omega_f=\omega_o+\alpha t[/tex]

[tex]\omega_f=5.1307+0.45\times 9[/tex]

[tex]\omega_f=9.180\ rad/s[/tex]

So, the final angular velocity of the wheel is 9.180 rad/s. Hence, this is the required solution.

The bicycle wheel's angular velocity, in rpm is 87.68 rpm.

Given the following data:

Conversion:

1 rpm = 0.1047 rad/s

49 rpm = X rad/s

Cross-multiplying, we have:

[tex]X = 49[/tex] × [tex]0.1047[/tex]

X = 5.1303 rad/s

To find the bicycle wheel's angular velocity, in rpm, we would use the first equation of kinematics:

[tex]w_f = w_o + at[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]w_f = 5.1303 + 0.45(9)\\\\w_f = 5.1303 + 4.05[/tex]

Final angular velocity = 9.1803 rad/s

Next, we would convert the value in rad/s to rpm:

Conversion:

1 rpm = 0.1047 rad/s

X rpm = 9.1803 rad/s

Cross-multiplying, we have:

[tex]9.1803 = 0.1047X\\\\X = \frac{9.1803}{0.1047}[/tex]

X = 87.68 rpm.

Final angular velocity = 87.68 rpm.

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Answer:

c. 14700 N

Explanation:

The gravitational force acting on the car in a free-body diagram depends on the car's mass and gravitational constant. Without the mass or the context provided by the diagram, it is impossible to definitively answer the question.

In order to determine the gravitational force acting on the car in this free-body diagram, you first need to understand the underlining principles of force. The force of gravity on an object is determined by the object's mass and the gravitational constant, typically represented by the formula F=mg. However, without further information such as the mass of the car or the free-body diagram referenced in the question, it's not possible to definitively answer this question. The options a) 5800N, b) 755N, c) 14700N, or d) 13690N could be potential answers depending on the mass of the car, the scale of the diagram, and the context of the problem.

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Final answer:

To calculate power, divide energy in joules by time in seconds. The light bulb with 100 joules of work done in 2.5 seconds has a power of 40 watts.

Explanation:

The student is asking how to determine the power of a light bulb based on the work done over time. The formula to calculate power is:

P = W / t

where P is power in watts (W), W is energy in joules (J), and t is time in seconds (s). In this case, the light bulb does 100 joules of work in 2.5 seconds. So, applying the formula:

P = 100 J / 2.5 s = 40 W

Hence, the power of the light bulb is 40 watts.

Fluorine is more electronegative than oxygen because the effective nuclear charge of fluorine is greater than that of oxygen.

Electronegativity is the tendency of an atom to attract electrons. The effective nuclear charge is the net positive charge experienced by an electron in an atom. Fluorine has a smaller atomic radius than oxygen. This means that the electrons in the outer orbitals of fluorine are closer to the nucleus than the electrons in the outer orbitals of oxygen.

The closer the electrons are to the nucleus, the stronger the attractive force between the electrons and the nucleus. This means that the effective nuclear charge of fluorine is greater than that of oxygen. Therefore, fluorine is more electronegative than oxygen.

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Answer: Horizontal component of arrow :40.955 m/s

Vertical component of arrow :28.675 m/s

Explanation:

The initial speed of the arrow = u = 50 m/s

The horizontal component of the arrow =[tex]u_x=u\cos\theta [/tex]

The horizontal component of the arrow =[tex]u_y=u\sin\theta [/tex]

Angle between the velocity vector and x component = 35°

Horizontal component of arrow :

[tex]\cos\theta=\frac{u_x}{u}[/tex]

[tex]\cos35^o=0.8191=\frac{u_x}{50}[/tex]

[tex]u_x=0.8191\times 50=40.955 m/s[/tex]

Vertical component of arrow :

[tex]\sin\theta=\frac{u_y}{u}[/tex]

[tex]\sin35^o=0.5735=\frac{u_y}{50}[/tex]

[tex]u_y=0.5735\times 50=28.675 m/s[/tex]

Horizontal component of arrow :40.955 m/s

Vertical component of arrow :28.675 m/s

According to law of conservation of energy, the thermal energy of the drill is 35J.

The law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.

Total energy = Kinetic energy + Sound energy+ Thermal energy

100 = 45+20+ Thermal energy

Thermal energy = 35J

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Answer : [tex]v_{2} = 11.2\ km/s[/tex]

Explanation : The total energy of the meteoroids

Total Energy = Kinetic Energy + Potential Energy

[tex]E = \dfrac{1}{2}mv^{2} - \dfrac{GMm}{R}[/tex]

Total energy remain constant.

Now, for both meteoroids

[tex]\dfrac{1}{2}m(v_{2}^{2} - v_{1}^{2}) = GMm\left(\dfrac{1}{R}-\dfrac{1}{r}\right)[/tex]

Where, R = radius of the earth

r = distance of the moon

M = mass of the earth

m = mass of the meteoroid

[tex]v_{2}^{2} = 2GM\left(\dfrac{1}{R}-\dfrac{1}{r}\right)+ v_{1}^{2}.....(I)[/tex]

Now, put the values in equation (I)

[tex]v_{2}^{2} = 1 + 2\times6.67\times10^{-11}\times6\times10^{24}\left(\dfrac{1}{6.37} - \dfrac{1}{384}\right)\times10^{-6}[/tex]

[tex]v_{2}^{2} = 12361\times 10^{4}\ m/s[/tex]

[tex]v_{2} = 11118.003\ m/s[/tex]

[tex]v_{2} = 11.2\ km/s[/tex]

Hence, this is the required solution.

The speed of the meteorite at its impact on Earth will be [tex]\boxed{11.1\,{{{\text{km}}}\mathord{\left/{\vphantom{{{\text{km}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex]  or [tex]\boxed{11088.24\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] .

Further Explanation:

The meteorite in the outer space at a particular distance from the Earth has its energy stored in the form of the kinetic energy as well as the potential energy.

The kinetic energy of the meteorite is given by:

[tex]{E_k} = \frac{1}{2}m{v^2}[/tex]

The potential energy of the meteorite at a particular height from Earth is given by:

[tex]{E_p} =  - \frac{{GMm}}{r}[/tex]

Here, [tex]M[/tex]  is the mass of the Earth, [tex]m[/tex]  is the mass of satellite and [tex]r[/tex]  is the distance of the meteorite from the centre of the Earth.

The total energy of the meteorite is given as:

[tex]\begin{aligned}{E_T}&={E_k} + {E_p}\\&=\frac{1}{2}m{v^2}-\frac{{GMm}}{r}\\\end{aligned}[/tex]

As the meteorite moves from the moon’s orbit towards the Earth, the potential energy of the meteorite gets converted into the kinetic energy.

Using conservation of energy for the meteorite from the moon’s orbit to the Earth’s surface:

[tex]\begin{aligned}\frac{1}{2}mv_1^2-\frac{{GMm}}{r}&=\frac{1}{2}mv_2^2-\frac{{GMm}}{R} \hfill\\v_1^2-v_2^2&=2GM\left({\frac{1}{r}-\frac{1}{R}}\right) \hfill\\{v_2}&=\sqrt {v_1^2-2GM\left({\frac{1}{r}-\frac{1}{R}}\right)}\hfill\\\end{aligned}[/tex]

Here, [tex]{v_1}[/tex]  is the speed of the meteorite in moon’s orbit, [tex]r[/tex]  is the distance of the moon’s orbit from centre of Earth and [tex]R[/tex]  is the radius of Earth.

The meteorite passes the moon’s orbit at the speed of [tex]1\,{{{\text{km}}}\mathord{\left/{\vphantom{{{\text{km}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] .

We know that the distance of the Moon’s orbit from the centre of Earth is  [tex]3.84 \times{10^5}\,{\text{km}}[/tex] and the radius of the Earth is [tex]6371\,{\text{km}}[/tex] .

Substitute the values in the equation of Energy.

[tex]\begin{aligned}v_{f}&=\sqrt{(1)^{2}-2(6.67\times10^{-11})(5.97\times10^{24})\left(\dfrac{1}{384}-\dfrac{1}{6.37}\right)10^{-6}}\\&=\sqrt{1.229\times10^{8}}\text{ m/s}\\&=11088.24\text{ m/s}\\&\approx11.1\text{ km/s}\end{aligned}[/tex]

Thus, the speed of the meteorite striking the Earth is [tex]\boxed{11.1\,{{{\text{km}}}\mathord{\left/{\vphantom{{{\text{km}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex]  or [tex]\boxed{11088.24\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex]  .

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Answer Details:

Grade: College

Subject: Physics

Chapter: Gravitation

Keywords:

Meteorite, moon’s orbit, 1km/s, two meteorite, heading for, speed of impact, 11.1 km/s, 384000 km, total energy, heading straight.

The negative charge should be placed 41 m from +1.0 C charged object

Electric charge consists of two types i.e. positively electric charge and negatively electric charge.

There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :

[tex]\large {\boxed {F = k \frac{Q_1Q_2}{R^2} } }[/tex]

F = electric force (N)

k = electric constant (N m² / C²)

q = electric charge (C)

r = distance between charges (m)

The value of k in a vacuum = 9 x 10⁹ (N m² / C²)

Let's tackle the problem now !

Given:

Q₁ = +1.0 C

Q₂ = +2.0 C

R₁ = x

R₂ = 100 - x

q = -1.0 × 10⁻³ C

Unknown:

x = ?

Solution:

In order to produce a total force = 0, the electric forces acting on this negative charge must be in the opposite direction and equal in magnitude.

We assume the distance of this negative charge to the positive charge +1.0 C is x, then:

[tex]F_1 = F_2[/tex]

[tex]k\frac{Q_1q}{R_1^2} = k\frac{Q_2q}{R_2^2}[/tex]

[tex]\frac{Q_1}{R_1^2} = \frac{Q_2}{R_2^2}[/tex]

[tex]\frac{1}{x^2} = \frac{2}{(100 - x)^2}[/tex]

[tex]\sqrt{\frac{1}{x^2}} = \sqrt{\frac{2}{(100 - x)^2}}[/tex]

[tex]\frac{1}{x} = \frac{\sqrt{2}}{100 - x}[/tex]

[tex]100 - x = \sqrt{2}x[/tex]

[tex]x + \sqrt{2}x = 100[/tex]

[tex]x ( 1 + \sqrt{2} ) = 100[/tex]

[tex]x = \frac{100}{1 + \sqrt{2}}[/tex]

[tex]x = 100(\sqrt{2} - 1) ~ m[/tex]

[tex]x \approx 41 ~ m[/tex]

Grade: High School

Subject: Physics

Chapter: Static Electricity

Keywords: Series , Parallel , Measurement , Absolute , Error , Combination , Resistor , Resistance , Ohm , Charge , Small , Forces

Answer:

Its 0.4kg

Explanation:

Answer:

19

Explanation:

Fluorine-19.

The isotope of fluorine with 9 protons and 10 neutrons is named Fluorine-19. This is because the mass number of an isotope equals the sum of its protons and neutrons, and in this case, 9 (protons) + 10 (neutrons) = 19. The atomic number of fluorine is 9, which means any atom of fluorine will always have 9 protons. A normal (most commonly occurring) atom of fluorine also has a mass number of 19, deriving from 9 protons and 10 neutrons. This makes Fluorine-19 the only stable and naturally-occurring isotope of fluorine.

This term shows the mass of the space shuttle

We know that the mass of the Earth is 5.972 × 10^24 kg. Similarly the sum of  mass of earth and the mass of shuttle must be a greater number as compared to the number given. It simply means that the mass of earth is itself 5.972 × 10^24 kg and the value given is 3 × 105 kg so it is obvious that if was the sum then it must be greater than the mass of earth. Therefore we can say that this not the mass of earth, neither the sum of mass of earth and shuttle, but this is only the mass of space shuttle which is the last multiple choice.

Answer:

The answer is D

Explanation:

Answer:

The steady state theory

Explanation:

According to the steady state model of the universe, the universe is continuously expanding while maintaining average density as constant. According to the theory, matter is continuously being formed and creating new stars and galaxies while the old ones are becoming un-observable. There is no beginning or end of time.

On the other hand, the big bang theory describes that the entire matter of the universe was confined in a point and with the big bang, this point started expanding. This happened about 13.8 billion years ago. Of course the density and temperature of the universe was very high at the beginning. In the initial few minutes of the big bang, the universe expanded rapidly which resulted in the decrease in its density and temperature. After million years, the universe transparent for radiation to freely travel through space. Cosmic Microwave background is the remnant of this early universe and is a strong evidence of the Big Bang Theory. The number of quasars were greater in past than present which shows that universe is evolving with time.

The amount of kinetic energy gained after it has moved 0.5 m is calculated as [tex]4\times10^{-15}\ J[/tex].

Given:

Electric field, [tex]E = 50000\ V/m[/tex]

Displacement, [tex]d= 0.5\ m[/tex]

Kinetic energy is a term used in physics to refer to the energy that an item has as a result of motion. It's a fundamental idea that explains how an object's motion and energy state are connected.

The particle physics community frequently refers to energy in terms of electron volts , especially when addressing the energies of atomic and subatomic particles. An electron is said to have one electron volt of kinetic energy when it accelerates through an electric potential difference of one volt.

The kinetic energy is given as:

[tex]KE = eV\\KE = e\timesE\timesd\\KE = 1.6\times10^{-19}\times50000\times0.5\\KE = 4\times10^{-15}\ J[/tex]

Hence, the amount of kinetic energy gained after it has moved 0.5 m is calculated as [tex]4\times10^{-15}\ J[/tex].

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The boy on the bicycle is approaching the brick wall at a speed of 5.88 m/s. This is calculated using the formula for the Doppler effect which describes a frequency shift due to relative motion of the source and the observer.

This problem deals with the Doppler effect, which is a shift in frequency perceived by an observer due to relative motion between the source of a wave (here, the bicycle horn) and the observer (the bicyclist hearing the reflected sound from the wall). In this case, we can use the formula for the Doppler effect when both the source and observer are moving towards each other:

f' = f (v + vo) / (v - vs)

where f' is the observed frequency (408 Hz), f is the source frequency (400 Hz), v is the speed of sound (340 m/s), vo is the observer's speed (the boy's speed) and vs is the source's speed (in this case, zero, since the wall is stationary).

Setting up the equation gives us:

boy, gives us vo = 5.88 m/s. Thus, the boy is riding his bicycle towards the wall at a speed of 5.88 m/s.

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Using the Doppler effect principle, the speed of the boy on the bicycle relative to the air is approximately 6.8 m/s.

The scenario given in the problem is a classic example of the Doppler Effect: the change in frequency or wavelength of a wave in relation to an observer moving relative to the wave source. In this case, we have the frequency of the sound wave as observed in the stationary frame (400 Hz) and in the moving frame (the boy on the bicycle, 408 Hz). The speed of sound in air is given as 340 m/s.

The observed frequency f is related to the source frequency f0 and the speed of the observer v with respect to the medium (air in this case) by the formula: f = f0*(v + v0) / v, where v0 is the speed of the source of the wave.

Substituting the given values into the equation gives 408 Hz = 400 Hz * (340 m/s + v) / 340 m/s. Solving the equation yields the speed of the boy on the bicycle relative to the air, which comes out to be approximately 6.8 m/s.

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Answer: D.

Explanation: Glucose levels are only option that relates to realistic diagnosis

Rest of the answers-

a DNA analysis to identify genetic abnormalities

a physical exam to look for tumors

a study to observe David’s social behaviors

a test to check David’s glucose levels

The magnitude of the charge on each plate of a 4.50 μF capacitor connected to a 12.0 V battery is 54 μC.

To find the magnitude of charge stored on each plate of a capacitor when a voltage is applied, you can use the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage applied. Given a capacitor with a capacitance (C) of 4.50 μF and a voltage (V) of 12.0 V, we can calculate the charge (Q) as follows:

Q = CV = (4.50 μF) (12.0 V) = (4.50 × 10-6 F) (12.0 V) = 54 × 10-6 C = 54 μC

Therefore, the magnitude of the charge on each of the plates of the capacitor is 54 μC.

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To find the charge stored on a capacitor with given capacitance and voltage, use the formula Q = C × V. Substituting 4.50 μF and 12.0 V into the equation yields a charge of 5.40 × 10⁻⁵ C on each plate.

To determine the charge stored on a capacitor's plates, we use the formula:

Q = C × V

Where:

In this case, we have a capacitance C = 4.50 μF (which is 4.50 × 10⁻⁶ F) and a voltage V = 12.0 V.

By substituting these values into the formula, we get:

[tex]Q = 4.50 \times 10^{-6} \, \text{F} \times 12.0 \, \text{V}[/tex]

Q = 5.40 × 10⁻⁵C

Therefore, the magnitude of the charge on each of the plates is 5.40 × 10⁻⁵ C.

Explanation:

Law of conservation of energy: The energy of the system can neither be created nor destroyed. It can be transformed from one form to another.

In a closed system, the energy remains conserved. It is isolated from the surrounding.

For example, the ball is rolling from the inclined plane. At the top of the inclined plane, the potential energy is maximum. When the ball starts rolling then the kinetic energy starts increases. Here, the potential energy is converted into kinetic energy. The energy transformation takes place.

The fetus relies upon its mother as it develops. These are some of the things it needs:

The developing fetus also needs its waste substances removing.

The fetus is protected by the uterus and the amniotic fluid, a liquid contained in a bag called the amnion.