Select all that apply.

A point located at (5, -2) undergoes two transformations. Its image is located at (-5, 2). What were the transformations?

The point was reflected over the y-axis and translated up 4 units.
The point was translated right 10 units and reflected over the x-axis.
The point was translated left 10 units and up 4 units.
The point was reflected over the y-axis and translated down 4 units.

Answer: The inequality that represents the temperature t in degrees Fahrenheit at any time on this day is [tex]t\leq 9[/tex] degree Fahrenheit.

Explanation:

It is given that on a winter’s day, 9 degrees Fahrenheit is the highest temperature recorded. It means the temperature on this day must be less than or equal to 9 degree Fahrenheit.

Let t represents the temperature in degrees Fahrenheit at any time on this day. Then,

[tex]t\leq 9[/tex]

Therefore, the inequality that represents the temperature t in degrees Fahrenheit at any time on this day is [tex]t\leq 9[/tex] degree Fahrenheit.

Answer:

[tex]t\leq 9^{0}F[/tex]

Step-by-step explanation:

We have been given that highest temperature recorded on a winter’s day is 9 degrees Fahrenheit and we are asked to write an inequality that represents the temperature t in degrees Fahrenheit at any time on this day.

Since we know that highest temperature can't exceed 9 degrees Fahrenheit on the given day and it will be less than or equal to 9.

Therefore, our inequality will be,[tex]t\leq 9^{0}F[/tex]

We have to identify the expression in which Additive inverse identity is applied.

Additive inverse property states that "The additive inverse of a number 'x' is a number that when it is added to 'x', yields zero".

Consider the first expression,

A. [tex] -329-164+513+206+(-164) [/tex]

There are no such numbers, which will yield zero on addition. Hence, additive inverse property is not applied here.

B. [tex] 1.6+0.2-1.8-0.5 [/tex]

There are no such numbers, which will yield zero on addition. Hence, additive inverse property is not applied here.

C. [tex] -\frac{7}{10}-\frac{3}{4}+1\frac{1}{2}+(-\frac{7}{10}) [/tex]

There are no such numbers, which will yield zero on addition. Hence, additive inverse property is not applied here.

D. [tex] 9\frac{3}{4}\+4\frac{5}{8}+(-9\frac{3}{4}+(2\frac{3}{5}) [/tex]

Here, [tex] 9\frac{3}{4} [/tex] when added to [tex] -9\frac{3}{4} [/tex] will yield zero. Therefore, [tex] -9\frac{3}{4} [/tex] is the additive inverse of [tex] 9\frac{3}{4} [/tex].

So, in option D, Additive inverse property is applied.

Answer:

I correct answer is: C

Step-by-step explanation:

About 42ft

I hope this helps! :)

Plz mark brainliest

Answer:

She waited for 20/r-20/s at the end of the line.

Step-by-step explanation:

The solution is, Time Sophie waits for Rana to arrive at finish point

=20/s - 20/r.

Speed is measured as distance moved over time. The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time. In this example, distance is in metres (m) and time is in seconds (s), so the units will be in metres per second (m/s).

Speed = Distance/ Time.

here, we have,

The speed of Sophie and Rana are given as s miles per hour and r miles per hour.

The distance traveled by Sophie and Rand are 20 miles each.

The time taken by Sophie and Rana to travel 20 miles can be calculated by the formula

Speed =distance/time

Or, Time =distance/speed

Time taken by Sophie to travel 20 miles =20/s

Time taken by Rana to travel 20 miles =20/r

Time Sophie waits for Rana to arrive at finish point =20/s - 20/r

To learn more on speed click:

brainly.com/question/28224010

#SPJ2

Answer:

the answer is 26 units

Step-by-step explanation:

The surface area of the triangular prism with dimensions of 10m, 9m, 6m, and 8m is 218m².

To find the surface area of a triangular prism, we need to find the sum of the areas of all its faces.

A triangular prism has two triangular bases and three rectangular lateral faces. Let's calculate the surface area:

1. The area of each triangular base can be found using the formula: 1/2 × base × height.

For the first base, the base is 10m and the height is 6m. So the area of the first base is 1/2 × 10m × 6m = 30m².

Similarly, for the second base, the base is 9m and the height is 8m.

So the area of the second base is 1/2 × 9m × 8m = 36m².

2. The area of each rectangular lateral face can be found using the formula: length × width.

The lengths of the lateral faces are 10m, 9m, and 6m.

The common width of the lateral faces is the height of the prism, which is 8m.

So the total area of the lateral faces is 10m × 8m + 9m × 8m + 6m × 8m = 152m².

3. Finally, the total surface area of the triangular prism is the sum of the areas of the bases and the lateral faces: 30m² + 36m² + 152m² = 218m².

Therefore the surface area of a triangular prism is 218m².

To find the volume of water needed to fill the pool to a depth of 2m, use the formula for the volume of a cylinder.

To determine the volume of water needed to fill the circular pool to a depth of 2m, you can use the formula for the volume of a cylinder:

V = πr²h

Given that the pool is circular, h = 2m, and to the nearest cubic meter, you would need:

Volume of water = π( r )²( 2 )

Answer:

20×1/4

Step-by-step explanation:

Answer:

This is super late but I want to help others who don't know the answer

Step-by-step explanation:

The answer is in the picture.

Thank me later :)

We will be using division property of exponents.

The property is as follows:

[tex] \frac{x^{a}}{x^{b}} =x^{a-b} [/tex]

This means if we have same base in both numerator and denominator, the exponents will get subtracted.

In our question we have

[tex] \frac{4^{1}}{4^{3} } =4^{1-3} [/tex]

[tex] \frac{4^{1}}{4^{3} } =4^{-2} [/tex]

Now we will use another property of exponents here:

[tex] x^{-a} =\frac{1}{x^{a} } [/tex]

So if we take reciprocal of the above expression we will get,

[tex] 4^{-2} =\frac{1}{4^{2} } [/tex]

Rewriting the final answer:

[tex] \frac{6^{3} }{4^{2} } [/tex]