The age of Noelle's dad is 6 less than 3 times Noelle's age. The sum of their ages is 74 . Find their ages. Provide your answer below: $$ Noelle: , Noelle's Dad

Answer:

Step-by-step explanation:

Independent samples t-test

Answer:

The person will pay $ 510 more as income tax per month .

Step-by-step explanation:

Given as :

The monthly income of person = $ 25000

The amount paid as income tax per year =$ 9000

So,The amount paid as income tax per month =$ [tex]\frac{9000}{12}[/tex] = $750

Or, x% is the income tax of the monthly income

I.e x % of 25000 = 750

∴ x % = [tex]\frac{750}{25000}[/tex]

Or, x =  [tex]\frac{750}{25000}[/tex] × 100

I.e x = 3 %

Now, since the income tax is increase by 0.5 % per month

So, x' = 3 % + 0.5 % = 3.5 %

And The monthly income increase by $ 11000

I.e New monthly income = $ 25000 + $ 11000 = $ 36000

Now, The income tax which the person pay now is 3.5 % of $ 36000

i.e The income tax which the person pay now = 0.035×36000 = 1260 per month

so, The income tax which the person pay now as per year = 1260 × 12 =        $ 15,120

∴ The increase income tax per month = $ 1260 - $ 750 = $ 510

Hence The person will pay $ 510 more as income tax per month . Answer

Final answer:

To calculate the additional income tax the person will pay per month, we add the tax increase due to the salary increase to the original increased tax after the 0.5% hike. The total increased monthly tax payment amounts to $930.

Explanation:

The question is asking how much more income tax a person will pay per month after their salary is increased and the government increased income tax by 0.5%. To find the additional income tax that a person will pay, we need to consider the initial monthly income, the new monthly income, the old annual tax amount, and the increased tax rate.

Originally, the person earned $25,000 per month and paid $9,000 in income tax yearly. With the 0.5% monthly increase in tax, we first need to calculate the monthly increase based on the initial salary. The monthly increase is 0.5% of $25,000, which is $125. Therefore, the new monthly tax without accounting for the salary increase is the old monthly tax plus the $125 increase.

The monthly tax paid before the income increase was $9,000 / 12 months = $750 per month. After the 0.5% monthly increase, the tax becomes $750 + $125 = $875 per month. But the person's monthly earnings were increased by $11,000, resulting in a new monthly income of $25,000 + $11,000 = $36,000.

To calculate how much more in income tax the person will pay on the additional $11,000 monthly earnings at the increased rate: 0.5% of $11,000 is $55. So the additional tax per month is $55. Therefore, the total increased monthly tax is $875 + $55 = $930.

The slope of a line perpendicular to the line with equation y=4x+1 is -1/4. This is found by taking the negative reciprocal of the original line's slope, which is 4.

The slope of a line that is perpendicular to a given line can be determined by taking the negative reciprocal of the slope of the given line.

Given the equation y=4x+1, we can see that the slope (m) is 4.

Therefore, a line that is perpendicular to this line would have a slope that is the negative reciprocal of 4, which is -1/4.

The concept of perpendicular lines in coordinate geometry implies that two lines are perpendicular if the product of their slopes is -1.

Our given line has a positive slope, hence the slope of its perpendicular counterpart must be negative. A positive slope indicates that the line moves up as we move from left to right, whereas a negative slope indicates that the line moves down.

The quadratic function is [tex]y=1x^{2} + (-8)x + 4[/tex]

Step-by-step explanation:

The quadratic function given is [tex]ax^{2} + bx + c=y[/tex]

and same quadratic function is passes through (-3​,37​), ​(2​,-8​), ​(-1​,13)

Replacing points one by one

we get,

For (-3​,37​) :

[tex]a(-3)^{2} + b(-3) + c=37[/tex]

[tex]9a + -3b + c=37[/tex] = equation 1

For (2​,-8​) :

[tex]a(2)^{2} + b(2) + c=(-8)[/tex]

[tex]4a + 2b + c=(-8)[/tex] =  equation 2

For ​(-1​,13)

[tex]a(-1)^{2} + b(-1) + c=(13)[/tex]

[tex]a + -1b + c=13[/tex] = equation 3

Solving the linear equation to get values of a,b,c

Subtract equation 2 with equation 3

we get,[tex](4a + 2b + c)-(a + -1b + c)=(-8)-13[/tex]

[tex](3a + 3b )=(-21)[/tex]

[tex](a + b )=(-7)[/tex]  = equation 4

Now, Subtract equation 1 with equation 2

we get,[tex](9a + -3b + c)-(4a + 2b + c)=(37)-(-8)[/tex]

[tex](5a - 5b )=(45)[/tex]

[tex](a - b )=(9)[/tex]  = equation 5

Now, Add equation 4 with equation 5

we get,[tex](a + b)+(a - b)=(-7)+(9)[/tex]

[tex](2a - 0b )=(2)[/tex]

[tex](a)=1[/tex]  

Replacing value of a in equation 5

[tex](a - b )=(9)[/tex]

[tex](1 - b )=(9)[/tex]

[tex](b)=(-8)[/tex]

Replacing value of a and b in equation 1

[tex]9a + -3b + c=37[/tex]

[tex]9(1) + -3(-8) + c=37[/tex]

[tex]9 + 24 + c=37[/tex]

[tex] c=4[/tex]

Thus,

The quadratic function [tex]y=1x^{2} + (-8)x + 4[/tex]

Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.

Step-by-step explanation:

The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,

a = - 16ft/s^2

While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.

This means that it travelled a distance,

s = 200 feet

We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.

Since the car came to a stop, its final velocity, v = 0

Applying Newton's equation of motion,

v^2 = u^2 + 2as

0 = u^2 - 2 × 16 × 200

u^2 = 6400

u = √6400

u = 80 ft/s

To find out how fast the car was traveling when the brakes were first applied, we need to solve a quadratic equation. After simplifying and rearranging the terms, we find that the car's initial velocity is not equal to 0, indicating that the car was already moving before the brakes were applied.

To determine how fast the car was traveling when the brakes were first applied, we can use the equation of motion relating distance, initial velocity, deceleration, and time. In this case, the given distance is 200 feet and the deceleration is 16 ft/s². Initially, the car was traveling at a certain velocity, which we need to find.

Using the equation x = xo + vot + 1/2at², where x is the final distance, xo is the initial position, vo is the initial velocity, a is the deceleration, and t is the time, we can plug in the known values and solve for vo:

200 ft = 0 + vo * t + 1/2 * (-16 ft/s²) * (t)²

Simplifying the equation and rearranging terms gives us a quadratic equation:

-8t² + vot - 200 = 0

Using the quadratic formula, we can solve for t:

t = (-vo ± √(vo² - 4 * (-8) * (-200))) / (2 * (-8))

Since the car is initially traveling, the positive root is used:

t = (-vo + √(vo² + 6400)) / (-16)

Simplifying the equation further:

t = (-vo + √(vo² + 6400)) / (-16)

Now we can solve for vo by substituting t = 0 into the equation:

0 = (-vo + √(vo² + 6400)) / (-16)

vo - √(vo² + 6400) = 0

Squaring both sides of the equation:

vo² - (vo² + 6400) = 0

Subtracting vo² from both sides of the equation:

-6400 = 0

This is a contradiction, which means that the car's initial velocity vo is not equal to 0. Therefore, the car was already moving when the brakes were first applied.

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Answer:

[tex]y = \frac{1}{2}x - 2[/tex]

Step-by-step explanation:

Given lines,

y = 2x - 5,

y = -x + 1

Subtracting these two equations,

0 = 3x - 6

[tex]\implies 3x = 6[/tex]

[tex]\implies x = \frac{6}{3}=2[/tex]

By first equation,

[tex]y=2(2) -5=4-5 = -1[/tex]

Thus, point of intersecting would be (2, -1).

Now, the equation of a line is y = mx + c,

Where,

m = slope of the line,

So, the slope of the line [tex]y=\frac{1}{2}x+4[/tex] is 1/2.

∵ two parallel lines have same slope.

Hence,

Equation of the parallel line passes through (2, -1),

[tex]y+1=\frac{1}{2}(x-2)[/tex]

[tex]y+1=\frac{1}{2}x - 1[/tex]

[tex]y = \frac{1}{2}x - 2[/tex]

The value of Bill Casler's CD (certificate of deposit) when it matures is $1060 and Bill receives $1036.36 from his friend.

First, we'll calculate the value of the CD (certificate of deposit) when it matures. To do this, we can use the formula for simple interest, which is PRT (Principal, Rate, Time). Here, P = $1000, R = 8% (or 0.08) and T = 9/12 years (converted to years).

So, the interest earned = 1000 * 0.08 * (9/12) = $60. The value of the CD when it matures would thus be the principal plus the interest earned, which is $1000 + $60 = $1060.

Now, for the second part of the question, we need to find out how much Bill received from his friend. The friend wants to earn a 10% annual simple interest return on his loan to Bill, so we'll equate the maturity value to the formula for simple interest. Here, P represents the amount loaned and we need to solve for P. Thus 1060 = P + P*0.10*(3/12).

Solving for P, we get P = $1036.36. So, Bill received $1036.36 from his friend.

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To find the value of the CD when it matures, use the simple interest formula. Add the interest earned to the principal to find the value. To find how much Bill received from his friend, set up an equation with the interest earned by the friend as 10% of the loan amount.

To find the value of the CD when it matures, we can use the formula for simple interest which is I = PRT, where I is the interest, P is the principal, R is the interest rate, and T is the time in years. In this case, P = $1000, R = 8%, and T = 9/12 years. Plugging the values into the formula, we get:
I = $1000  imes 0.08  imes (9/12)

I = $60

So, the interest earned is $60. To find the value of the CD when it matures, we simply add the interest to the principal:

Value = $1000 + $60

Value = $1060

For the second question, we need to find how much Bill received from his friend. Since the friend will earn a 10% annual simple interest return on his loan to Bill, we know that the interest earned by the friend is 10% of the amount he lent. Let's call this amount X. So, the interest earned by the friend is 10% of X. To find X, we can set up an equation:

10% of X = $1060

0.10X = $1060

X = $1060 / 0.10

X = $10,600

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Answer:

a) 80 ibs

b) 40 ibs

Step-by-step explanation:

Let X be the pound of the high quality bean at $6.50

(120-x) will be the pound of the cheaper bean at $2.50

6.5x + 2.5(120 - x) = 5.17(120)

6.5x + 300 - 2.5x = 620.4

Collect like terms

6.5x - 2.5x = 620.4 - 300

4x = 320.4

x = 320.4/4

x= 80.1

x = 80 ibs(to the nearest pounds)

For the cheaper bean we have 120 -x

= 120 - 80

= 40 ibs

Sarah would blend 80 ibs of quality bean and 40 ibs of cheaper bean

Sarah should blend 80 pounds of high quality beans and 40 pounds of cheaper beans to achieve her target blend of 120 pounds at $5.17 per pound.

Sarah Meeham needs to blend high quality and cheaper coffee beans to create a blend selling for $5.17 per pound, using a total of 120 pounds. Let x be the pounds of high-quality beans and 120 - x be the pounds of cheaper beans. Setting up the equation for the total cost of the blend, we have:

6.50x + 2.50(120 - x) = 5.17 \\times 120

Solving for x, we get:

6.50x + 300 - 2.50x = 620.4

4x = 320.4

x = 80.1

To the nearest pound, Sarah should blend 80 pounds of high quality beans and 120 - 80 = 40 pounds of cheaper beans.

Answer:

E(X) = 6.0706

Step-by-step explanation:

1) Define notation

X = random variable who represents the number of heads in the 10 first tosses

Y = random variable who represents the number of heads in range within toss number 4 to toss number 10

And we can define the following events

a= The first coin has been selected

b= The second coin has been selected

c= represent that we have 2 Heads within the first two tosses

2) Formulas to apply

We need to find E(X|c) = ?

If we use the total law of probability we can find E(Y)

E(Y) = E(Y|a) P(a|c) + E(Y|b)P(b|c) ....(1)

Finding P(a|c) and using the Bayes rule we have:

P(a|c) = P(c|a) P(a) / P(c) ...(2)

Replacing P(c) using the total law of probability:

P(a|c) = [P(c|a) P(a)] /[P(c|a) P(a) + P(c|b) P(b)] ... (3)

We can find the probabilities required

P(a) = P(b) = 0.5

P(c|a) = (3C2) (0.4^2) (0.6) = 0.288

P(c|b) = (3C2)(0.7^2) (0.3) = 0.441

Replacing the values into P(a|c) we got

P(a|c) = (0.288 x 0.5) /(0.288x 0.5 + 0.441x0.5) = 0.144/ 0.3645 = 0.39506

Since P(a|c) + P(b|c) = 1. With this we can find P(b|c) = 1 - P(a|c) = 1-0.39506 = 0.60494

After this we can find the expected values

E(Y|a) = 7x 0.4 = 2.8

E(Y|b) = 7x 0.7 = 4.9

Finally replacing the values into equation (1) we got

E(Y|c) = 2.8x 0.39506 + 4.9x0.60494 = 4.0706

And finally :

E(X|c) = 2+ E(Y|c) = 2+ 4.0706 = 6.0706

In this problem, we have to consider a conditional expected value for the flips of a randomly chosen misshapen coin. We start with a known result (2 heads in 3 flips) and then compute the expected outcome for the next 7 flips for both coins. The final answer is the average of these expectations.

This question involves the realm of probability theory and specific concept of expected value. Given two distinct coins with varying chances of landing on heads, we need to calculate the expected number of heads when one of these coins is randomly chosen and flipped 10 times.

The usual expected number of heads will be the sum of the individual expected values for each, which in turn is the product of the number of trials (10 flips) and the probability of success (landing on a head). However, the condition that two of the first three flips landed on heads slightly modifies this calculation process.

The main challenge here is that we start with a known result (2 heads in 3 flips), and we then have 7 additional flips with unknown results. Since we don't know which coin we have, we must consider the expected outcomes for both coins and then divide by 2. The theoretical probability does not predict short-term results, but gives information about what can be expected in the long term.

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Answer:

Step-by-step explanation:

Total number of students: 33 +47 +37 = 117 students

Students in 9th class = 37

So probabilty of selecting a 9th class student from a class of 117 students is:

=>(Total student in 9th class)/(Total student in the sample)

=>37/117 =>Ans

To find the probability of selecting a ninth-grade student from a school population, divide the number of ninth-grade students by the total population.

To find the probability that a randomly selected student is in the ninth-grade, we need to calculate the fraction of ninth-grade students out of the total population of students. Here's how:

The probability that the randomly selected student is in the ninth-grade is approximately 0.316, or 31.6%.

Answer:

Yes this makes sense

Step-by-step explanation:

When their is one outlier it makes the average spike which can present misleading data while with median the outlier is left relatively unaffected.

Answer:

Yes this makes sense.

Step-by-step explanation:

The given dataset consists of 15 apartment rents. A data value which is an outlier (much larger than the rest) will increase the overall mean value of the population but it may not affect the median. Let us take an example of 15 sample rent value in ascending order,

100,120,130,140,150,170,175,185,190,200,220,250,280,290,1000

Here , mean rent will become high due to the single high rent datapoint(1000) but the median won't be impacted.

Answer: (D) 3.21

Step-by-step explanation:

Let [tex]t_A=[/tex] Time taken by one outlet to fill the pool.

[tex]t_B=[/tex]Time taken by second outlet to fill the pool.

Given : The time taken by one outlet to fill the entire pool : [tex]t_A=[/tex] 9 hours

The time taken by second outlet to fill the entire pool : [tex]t_B=[/tex] 5 hours

Now , if both outlets are used at the same time, approximately what is the number of hours required to fill the pool (T) , then the time required to fill the pool will be :_

[tex]\dfrac{1}{T}=\dfrac{1}{t_A}+\dfrac{1}{t_B}\\\\\Rightarrow =\dfrac{1}{T}=\dfrac{1}{9}+\dfrac{1}{5}\\\\\Rightarrow\ \dfrac{1}{T}=\dfrac{9+5}{(9)(5)}=\dfrac{14}{45}\\\\\Rightarrow\ T=\dfrac{45}{14}=3.21428571429\approx3.21[/tex]

Hence, the approximate time taken by both outlets to fill the pool together = 3.21 hours.

Thus , the correct option is  (D) 3.21

The question is about rate, time and work. Using the given rates of the outlets, we determine the combined rate. We then use the time = work/rate formula to calculate the time it would take for both outlets to fill the pool, which comes out to approximately 3.21 hours.

This question is a typical problem in rate time and work, which is a common topic in mathematics especially algebra. The problem talks about two outlets with different rates filling a pool.

Let's consider the rate of the first outlet as 1/9 pool/hour and the second outlet as 1/5 pool/hour. If both outlets are working at the same time, their rates would add up. Hence, the combined rate would be 1/9 + 1/5 = 14/45 pool/hour.

To find how long it would take for both outlets to fill the pool, we use the equation time = work/rate. Plugging in our values, we get time = 1 pool / 14/45 pool/hour. Therefore, the time is amounts to approximately 3.21 hours.

Therefore, "the correct answer is (D) 3.21".

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Answer:

(d) a matched pairs experiment.

Step-by-step explanation:

The correct answer is option D that is d) a matched pairs experiment.

A matched pair experiment is special case of randomize block design. This experiment can be used when the statement has two treatment conditions and subjects are grouped into pair based on some treatment. For each pair, random treatments are assigned to the subjects. It is an improvement over complete randomized design.

This is an experiment because a treatment (the MP3 players) was assigned to different members of the sample(the assembly line workers) randomly.

This study is a d) matched pairs experiment where assembly line workers are given portable mp3 players to play their chosen music while working for one month and then work without music for another month, with the order determined randomly.

This study is a matched pairs experiment because each worker serves as their own control by experiencing both treatments, with the order of treatments determined randomly. In a matched pairs experiment, participants are paired up based on similar characteristics, and each pair is randomly assigned to different treatments. Here, the workers are matched based on their own preferences for the music they choose.

The workers are given portable mp3 players and can choose their own music, which serves as the treatment variable. The productivity of the workers is measured in two different months, one with music and one without music. By comparing the workers' productivity in the two months, the study aims to determine the effect of music on productivity.

Learn more about Type of Experiment Design here:

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Answer:

2l + 2w = 96 ..... eqn1

lw = 504 ...... eqn2

Step-by-step explanation:

To model this case where we have two unknowns l and w, we need two equations.

Firstly, the perimeter of a rectangle is given by

2l + 2w = p

Where l,w and p are length, width and perimeter of the rectangle respectively.

Hence,

2l + 2w = 96 ... eqn1

Secondly, the area of a rectangle is given by

Length × width = Area

Hence,

l × w = 504

lw = 504 ... eqn2

With these two equations the solutions to the length and width of the rectangular pool can be derived.

Answer:

D. 2l+2w=96

    lw=504

Step-by-step explanation:

Edge 2020 (got 100%)

Answer:

4.45

Step-by-step explanation:

cos(70)= BC/13

BC=13*cos(70)

BC= 4.45 cm

Answer: The answer is $49.10

Step-by-step explanation: Because it is .30 cents per extra minute

So you will take 47 for the minuets and multiply by .30 and get $14.10

Then you add $14.10 to your monthly fee of $35 and get $49.10

Answer:

A) 20ml

Step-by-step explanation:

You have a 2.5% solution (in 100 of the solution you have 2.5 of solvent), then if the dose that is being supplied to the cat is 5mg / kg it means:

if    1000 gr is equivalent to 100%

           5 gr is equivalent to X;    

X= (100%*5gr)/1000gr → X= 0.5%,  , Therefore the amount of milliliters that should be supplied of 2.5% is:

if   100ml  hava a concentration of 2.5,  how many mililiters are necesary in a concentration 0.5

X=(0.5%*100ml)/2.5% → X=20ml

Answer:1260 tickets were sold on the first game

Step-by-step explanation:

For the second game, the ratio of the number of sold tickets to number of unsold tickets is 13:2

Total ratio = 13+2 = 15

There were 240 unsold tickets for the second game. Let total number of tickets for the second game be x

This means that

240 = 2/15 × x

2x/15 = 240

2x = 15 × 240= 3600

x = 3600/2 = 1800

1800 tickets were sold for the second game. Assuming total number of tickets for the first game is equal to total number of tickets for the second game. Therefore,

Total number of tickets sold for the first game is 1800

The ratio of sold tickets to unsold tickets for the first game was 7:3.

Total ratio = 7+3 = 10

Number of sold tickets for the first game would be

7/10 × 1800 = 12600/10

= 1260 tickets

The mathematical solution involves understanding and applying the concept of ratios. From the information given, we deduce that 840 tickets were sold for the first baseball game.

The student's question is about a mathematics problem involving ratios. We know that the ratio of sold tickets to unsold tickets for the first game was 7:3, and for the second game, it was 13:2. We are also given that there were 240 unsold tickets for the second game.

Firstly, let's deal with the second game tickets. If we say the ratio 13:2 represents 13x:2x, where x is a common multiplier. Since the unsold tickets (2x) were 240, we can solve for x by the equation: 2x = 240. So, x = 240/2 = 120. However, we don't need the number of sold tickets for the second game now.

For the first game, we know the ratio of sold tickets to unsold tickets was 7:3. Yes, it's the same x because ratios are the same across the populated places. We can then figure out the number of sold tickets as 7x. So, just multiply 7 by our common multiplier 120 to get 840 tickets sold for the first game.

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Staement 1 and statement 4 are true

Staement 1: It is incorrect because thirds and eighths cannot be divided to make ninths

Statement 4: It is incorrect because a quotient cannot be greater than the number that is divided.

Given that, Eli evaluated 23 ÷ 38 and got an answer of 179.

Now, let us check the given statements

1) It is incorrect because thirds and eighths cannot be divided to make ninths

It seems right because when 3 is divided by 8, it will give an fractional value. So this statement is correct

2) It is correct because 38 of 23 is 179

It is wrong as 38 x 23 ≠ 179 and not even related to the question.

3) It is correct because 179 • 38 equals 23

It is wrong because 179 x 38 ≠ 23

4) It is incorrect because a quotient cannot be greater than the number that is divided.

It is right as the dividend can not be smaller than the quotient.

Hence, the 1st and 4th statements are right.

Answer:

  96 m²

Step-by-step explanation:

The figure is a trapezoid with bases of length 10 m and 22 m, and height 6 m. Putting these numbers into the formula for area of a trapezoid gives ...

  A = (1/2)(b1 +b2)h

  = (1/2)(10 m +22 m)(6 m) = 96 m²

The area of the figure is 96 m².

The answer is 240 chairs.

Answer:

  7h +11r = 350

Step-by-step explanation:

Let h and r represent minutes of hiking and running, respectively. Then calories burned by a 150-lb person doing these activities will total 350 when ...

  7h +11r = 350

_____

7 calories per minute are burned by hiking, so 7h will be the calories burned by hiking h minutes.

11 calories per minute are burned by running, so 11r will be the calories burned by running r minutes.

The total of calories burned in these activities will be 7h+11r, and we want that total to be 350.

Answer:

  2

Step-by-step explanation:

We can use the formula for the derivative of the arcsin function:

  f'(x) = 1/√(1 -x²)

Filling in x=(√3)/2, we get ...

  f'((√3)/2) = 1/√(1 -3/4) = 1/(1/2)

  f'((√3)/2) = 2

To find the value of f'(√3/2) for f(x) = sin⁻¹(x), we can use the chain rule and substitute the given value into the derivative expression.

To find the derivative of f(x) = sin⁻¹(x), we can use the chain rule. Let's denote u = x, then y = sin⁻¹(u). Taking the derivative of y with respect to u, we get dy/du = 1/√(1 - u²). Now, substituting u = √3/2, we can find the value of f'(√3/2) in simplest form.

Substituting u = √3/2 into the derivative, we have dy/du = 1/√(1 - (√3/2)²) = 1/√(1 - 3/4) = 1/√(1/4) = 1/√1/4 = 1/(1/2) = 2.

Therefore, the value of f'(√3/2) is 2.

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Answer:

Step-by-step explanation:

The relation between speed, time, and distance is ...

  speed = distance/time

Against the wind, the speed is ...

  (3310 mi)/(5 h) = 662 mi/h

With the wind, the speed is ...

  (3810 mi)/(5 h) = 762 mi/h

The jet stream adds to the speed in one direction, and subtracts in the other direction, so the difference in travel speeds is twice the speed of the jet stream:

  (762 mi/h -662 mi/h)/2 = jet stream speed = 50 mi/h

__

The speed of the plane is the average of the two speeds, or the sum of jet stream speed and the lower speed, or the difference of the higher speed and the jet stream speed. Any of these calculations will give the plane's speed in still air:

  (762+662)/2 = 662 +50 = 762 -50 = 712 . . . mi/h

Answer:

  431,646

Step-by-step explanation:

The problem statement tells us ...

  34,100 = 0.079 × (sold to date)

Dividing by 0.079, we get ...

  34,100/0.079 = (sold to date) ≈ 431,646

About 431,646 copies have been sold to date.

The total number of books sold to date is approximately 431,646. This was determined by using the percentage of the total sales represented by the first month's sales (7.9%) and the number of books sold in the first month (34,100 copies).

To solve this problem, we need to understand that the 34,100 books sold in the first month represent 7.9% of the total number of copies sold to date. In mathematics, percentage is a way of expressing a number as a fraction of 100. Here, we need to find the whole, where 7.9% is equivalent to 34,100 copies.

To do this, we use this formula:

So, the calculation would be:

The result we get from the calculator is approximately 431,646 copies. This means, approximately 431,646 copies were sold to date.

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For this case we have the following arithmetic sequence:

[tex]a_ {n} = 15 + 5 (n-1)[/tex]

To write in function form, we apply distributive property to the terms within parentheses:

[tex]f (n) = 15 + 5n-5[/tex]

Different signs are subtracted and the major sign is placed.

We simplify:

[tex]f (n) = 5n + 10[/tex]

Answer:

[tex]f (n) = 5n + 10[/tex]

Option C

The explicit formula for the arithmetic sequence an=15+5(n−1) in function form is f(n)=5n+10.

The explicit formula for the arithmetic sequence an=15+5(n−1) in function form is f(n)=5n+10 (Option C).

The arithmetic sequence is represented as an=15+5(n−1). This equation can be further simplified to an=15+5n-5, which eventually gives us an=5n+10. So the explicit formula for this arithmetic sequence in function form is option C, which is f(n)=5n+10. This function f(n), directly gives us the nth term of the arithmetic sequence.

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Final answer:

To determine the length of a Bengal tiger's tail, which is 30% of its total length of 96 cm, we calculate 30% of 96 to get a tail length of approximately 28.8 cm.

Explanation:

The question asks us to calculate the length of a Bengal tiger's tail given that it is 30% of its total length. If the total length of the tiger is 96 cm, we can find the length of the tail by calculating 30% of 96 cm.

To find 30% of 96, we convert the percentage into a decimal by dividing by 100 and then multiply by the total length:

30% = 30/100 = 0.3

0.3 x 96 cm = 28.8 cm

Therefore, the length of the Bengal tiger's tail is approximately 28.8 cm.

The maximum possible width of the fence is 7.5 feet.

It shows a relationship between two numbers or two expressions.

There are commonly used four inequalities:

Less than = <

Greater than = >

Less than and equal = ≤

Greater than and equal = ≥

We have,

Let's start by assigning variables to the length and width of the fence.

Let x be the width of the fence in feet, then the length of the fence is x + 10 feet

(since the length is at least 10 feet longer than the width).

Now,

The perimeter of the fence is the sum of the lengths of all its sides.

Since the fence has four sides of equal length,

The perimeter is 4 times the length of one side.

So,

The equation for the perimeter, P, in terms of x.

P = 4(x + x + 10)

  = 8x + 40

Now,

We know that Jake wants the perimeter to be no more than 100 feet,

So we can write an inequality:

8x + 40 ≤ 100

Solving for x:

8x ≤ 60

x ≤ 7.5

Therefore,

The maximum possible width of the fence is 7.5 feet.

Learn more about inequalities here:

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Final answer:

To find the maximum width for Jake's fence with the given constraints, set up inequalities with the perimeter and length requirements. Solving for the width, we find that the maximum possible width Jake can use is 20 feet.

Explanation:

Jake is constructing a fence around his property and wishes for the perimeter to not exceed 100 feet, while the length must be at least 10 feet longer than the width. Let's denote the width of the property as w and the length as l. According to the constraints:

The perimeter (2w + 2l) ≤ 100 feet

The length (l) ≥ w + 10 feet

Using these inequalities, we have:

2w + 2(w + 10) ≤ 100

2w + 2w + 20 ≤ 100

4w ≤ 80

w ≤ 20

The maximum possible width is therefore 20 feet.

Answer:

  783.9

Step-by-step explanation:

The same tool that gave you the answer to the second part will give you the answer to the first part.

_____

You will note the box is checked saying "Log Mode". This mode uses linear regression on the logarithms of the y-values. When the box is unchecked, regression is used on the actual y-values.

The latter method tends to favor matching the larger y-values at the expense of matching smaller ones. It gives a different equation.

Step-by-step explanation:

The domain of f(x) is all values of x for which f(x) is defined.

For f(x) to be defined, the expression under the radical must be non-negative.

Therefore, the domain is x ≥ 0, or in interval notation, [0, ∞).