The front of an A-frame house is in the shape of a triangle. The height of the house is 20 feet. The area of the front of the A-frame is 600 squared feet. Write and solve an equation to find the base of the A-frame house.

Check the picture below.

Answer:

1,600,000

Step-by-step explanation:

120,000,000 divided by 75 is 1,600,000

Answer:

did the math its 90,000,000

thats how much 75% is

Step-by-step explanation:

Answer:

You'd have to buy 3 shirts in order to use your coupon.

Step-by-step explanation:

Each shirt originally costs $17.99

One particular brand of shirts is on sale for 20% off the original price.

$17.99*0.2= $3.60 (amount taken off for each shirt)

Now subtract $3.60 from $17.99.

$17.99 - $3.60 = $14.39 (per shirt)

40 / 14.39 = 2.779 (round to 3)

You'd have to buy 3 shirts in order to use your coupon.

$14.39 * 3 = $43.17, in order to get $10 off you'd need to spend at least $40

Hey!

-----------------------------------------------------

Straight-Time Pay - someone works the minimum and gets paid for working those hours. This person doesn't work any overtime hours.

-----------------------------------------------------

Solution:

8.75 * 20 = 175

-----------------------------------------------------

Answer:

Jason's straight-time pay for the week is $175!

-----------------------------------------------------

Hope This Helped! Good Luck!

Answer:

Jason’s straight-time pay for the week is $175.

Step-by-step explanation:

Given : Jason Ayers works as a lifeguard earning $8.75 an hour for 20 hours per week.

To find : What is Jason’s straight-time pay for the week?

Solution :

Jason Ayers works as a lifeguard earning in an hour = $8.75

In a week Jason Ayers works for 20 hours.

i.e. Jason Ayers works as a lifeguard earning in 20 hour =[tex]\$8.75\times 20[/tex]

Jason Ayers works as a lifeguard earning in 20 hour = $175

Therefore, Jason’s straight-time pay for the week is $175.

Answer:

The sum of 3 + (-2) = 1 because it's just like 3 - 2

The sum of -6 + 3 = - 3 because the negative number is greater than positive number it's a negative.

For B you fill in Six negative, -6; three positive, 3. And you are left with three negative counters.

For A you are left with one positve counters.

Answer:

y = -2x -7

Step-by-step explanation:

Plug in and Solve.

The following is true in the diagram below:

∠XYZ

∠XYW

∠ZYW

[tex]\bar{YX}, \bar{YW}, \bar{YZ}[/tex]

Options A, B, and D are correct.

The angles between two lines are the angles formed by two intersecting lines, measured in degrees or radians.

Several different types of angles can be formed between two lines, including acute angles, right angles, and obtuse angles.

We have,

From the diagram,

There are 3 angles:

∠XYZ

∠XYW

∠ZYW

And,

In geometry, a line that has a starting point and no endpoint is called a ray. A ray is part of a line that starts at a particular point called the endpoint and extends infinitely in one direction.

It is also sometimes referred to as a half-line.

Rays are commonly denoted by an arrow pointing in the direction of the infinite extension, with the endpoint letter given first.

There are 3 rays:

YX, YW, and YZ

Thus,

The following is true:

∠XYZ

∠XYW

∠ZYW

[tex]\bar{YX}, \bar{YW}, \bar{YZ}[/tex]

Learn more about angles here:

https://brainly.com/question/7116550

#SPJ7

Answer:

Option G. 27.4 ft

Step-by-step explanation:

step 1

Calculate the maximum number of cans of paint Kieran can buy with $45

Let

x -----> the number of cans of paint

we know that

The number of cans of paints multiplied by it cost plus the cost of a rooler paint must be less than or equal to $45

so

[tex]9.75+17.00x \leq 45[/tex]

Solve the inequality for x

Subtract 9.75 both sides

[tex]17.00x \leq 45-9.75[/tex]

[tex]17.00x \leq 35.25[/tex]

Divide by 17 both sides

[tex]x \leq 2.07\ cans[/tex]

so

The maximum number of cans that Kieran can purchase is 2 cans

step 2

Find the maximum area covered with 2 cans of paint

we know that

One can of paint covers approximately 375 square feet

therefore

To find out the area covered with 2 cans multiply 375 by 2

[tex]375(2)=750\ ft^2[/tex]

step 3

Find the maximum possible length side of the wooden platform

we know that

The wooden platform is in the shape of a square

so

The area of a square is

[tex]A=b^{2}[/tex]

where

b is the length side of the square

we have

[tex]A=750\ ft^2[/tex]

substitute and solve for b

[tex]750=b^{2}[/tex]

square root both sides

[tex]b=27.4\ ft[/tex]

Answer:

Step-by-step explanation:

For any polynomial, we can determine the degree by finding the variable with the largest exponent. For the given polynomial:

[tex]5z^{3} - 2z^{4} -9z^{2} + z[/tex]

we can see that [tex]-2z^{4}[/tex] contains the variable with the highest exponent, 4, so the degree of this polynomial is 4.

Answer:

4

Step-by-step explanation:

khan academy help

Answer:

p=2

Step-by-step explanation:

−4p=11−19

−4p=−8

then you divide both sides by -4 and two negatives make a positive.

​​

Answer:

a and c

Step-by-step explanation:

Hey!

-----------------------------------------------

Question #3:

The associative property is where you have an equation and you can switch the numbers and it will still equal the same.

Answer: c) (x + 3) + 7 = x + (3 + 7)

-----------------------------------------------

Question #4:

The distributive property is where you have an equation and you multiply each addend and add them up.

Answer: c) distributive

-----------------------------------------------

Hope This Helped! Good Luck!

Answer:

low interest rate on a car loan

Answer:

B. low interest rate on a car loan

Answer: 393

I answered on monarch and it came out right.

Answer:

Part 1) [tex]cos(\theta)=(\frac{13}{85})[/tex]

Part 2) [tex]tan(\theta)=\frac{84}{13}[/tex]

Part 3) [tex]cot(\theta)=\frac{13}{84}[/tex]

Part 4) [tex]sec(\theta)=\frac{85}{13}[/tex]

Part 5) [tex]csc(\theta)=\frac{85}{84}[/tex]

Step-by-step explanation:

we know that

Angle [tex]\theta[/tex] lie on Quadrant I

so

[tex]sin(\theta)[/tex] is positive

[tex]cos(\theta)[/tex] is positive

[tex]tan(\theta)[/tex] is positive

[tex]cot(\theta)[/tex] is positive

[tex]sec(\theta)[/tex] is positive

[tex]csc(\theta)[/tex] is positive

step 1

Find the value of  [tex]cos(\theta)[/tex]

we have

[tex]sin(\theta)=\frac{84}{85}[/tex]

we know that

[tex]sin^2(\theta)+cos^2(\theta)=1[/tex]

substitute

[tex](\frac{84}{85})^2+cos^2(\theta)=1[/tex]

[tex](\frac{7,056}{7,225})+cos^2(\theta)=1[/tex]

[tex]cos^2(\theta)=1-(\frac{7,056}{7,225})[/tex]

[tex]cos^2(\theta)=(\frac{169}{7,225})[/tex]

[tex]cos(\theta)=(\frac{13}{85})[/tex]

step 2

Find the value of [tex]tan(\theta)[/tex]

we know that

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

we have

[tex]sin(\theta)=\frac{84}{85}[/tex]

[tex]cos(\theta)=(\frac{13}{85})[/tex]

substitute

[tex]tan(\theta)=\frac{(84/85)}{(13/85)}[/tex]

[tex]tan(\theta)=\frac{84}{13}[/tex]

step 3

Find the value of [tex]cot(\theta)[/tex]

we know that

[tex]cot(\theta)=\frac{1}{tan(\theta)}[/tex]

we have

[tex]tan(\theta)=\frac{84}{13}[/tex]

therefore

[tex]cot(\theta)=\frac{13}{84}[/tex]

step 4

Find the value of [tex]sec(\theta)[/tex]

we know that

[tex]sec(\theta)=\frac{1}{cos(\theta)}[/tex]

we have

[tex]cos(\theta)=(\frac{13}{85})[/tex]

therefore

[tex]sec(\theta)=\frac{85}{13}[/tex]

step 5

Find the value of [tex]csc(\theta)[/tex]

we know that

[tex]csc(\theta)=\frac{1}{sin(\theta)}[/tex]

we have

[tex]sin(\theta)=\frac{84}{85}[/tex]

therefore

[tex]csc(\theta)=\frac{85}{84}[/tex]

Answer:

When both integers have the same value, the difference is zero. The difference between a positive and a negative integer can be positive or negative. When you subtract a negative integer from a positive integer, the difference is always positive this might help

Step-by-step explanation:

Write a subtraction problem involving two positive integers with a negative difference.

1) When you subtract a positive integer from a negative integer, the difference is always negative.

For example : [tex]-7 - 3 = -10[/tex]

2) When you subtract a larger positive integer from a smaller integer, the difference is always negative.

For example : [tex]5-7=-2[/tex]

3) When you subtract two negative integers and the first integer (or minuend) is smaller than the second integer (or subtrahend), the difference is negative.

For example : [tex]-8 - (-2) = -6[/tex]

Answer:

19

Step-by-step explanation:

7-2(-6) which would equal 7+12 because negative times negative is positive

Answer: 19

Step-by-step explanation:

7 + [(- 2) (-6)]

-2 * -6 = 12

7 + 12 = 19

Answer:

0; 10; 20

Step-by-step explanation:

x is the independent variable

y is the dependent variable

y is dependent on x

a) For what value of the independent variable will the value of the function be equal to −6

y=0.3x−6

-6 = 0.3x-6

0=0.3x

x = 0

Therefore, if the independent variable is 0, the value of the function will be -6.

b) For what value of the independent variable will the value of the function be equal to −3

y=0.3x−6

-3 = 0.3x-6

0.3x = -3+6

0.3x = 3

x = 3/0.3

x = 10

Therefore, if the independent variable is 10, the value of the function will be -3.

c) For what value of the independent variable will the value of the function be equal to 0.

y=0.3x−6

0=0.3x-6

6 = 0.3x

x = 6/0.3

x = 20

Therefore, if the independent variable is 20, the value of the function will be 0.

Answer:

[tex]37[/tex]  [tex]crackers[/tex]

Step-by-step explanation:

Tins (or Tina)  ate 8 crackers for a snack  each day on school , then on Friday, she drops three and only eats 5.

Meaning that for 4 days, she ate 8 crackers not including Friday.

So meaning we have to multiply how many crackers she ate for those 4 days in total:

[tex]8 * 4[/tex]

[tex]==> 32[/tex]

Then on Friday, she only ate 5, so we add 5 for how many crackers she ate into how many we have right now:

[tex]32 + 5[/tex]

[tex]==> 37[/tex]

To find out how many crackers Tins ate on Friday, you can subtract the number of dropped crackers from the total number she normally eats.

In this question, the subject is mathematics and the grade level is middle school. The question asks about a student named Tins who eats 8 crackers for a snack each day at school. On Friday, she drops 3 crackers and only eats 5. To find out how many crackers she ate on Friday, we can subtract the number of dropped crackers from the total number she normally eats.

Number of crackers normally eaten: 8

Number of crackers dropped on Friday: 3

Number of crackers eaten on Friday: 8 - 3 = 5 crackers

https://brainly.com/question/26854035

#SPJ2

Answer:

You can!

It's 2\sqrt{3\\

Step-by-step explanation:

18 = 2*9

\sqrt{18} = 2\sqrt{3\\

The decimal equivalent of the fraction 13/16 is 0.8125. However, when you round this to the nearest tenth as the question specifies, you get 0.8.

To find the decimal equivalent of the fraction 13/16, you firstly divide 13 by 16. This will provide you with a decimal number. Then, since the question asks for the decimal to be rounded to the nearest tenth, you round the decimal number. To round, if the number on right of decimal is 5 or more, round up; if it's less than 5, round down. So 13 divided by 16 equals 0.8125, which when rounded to the nearest tenth gives you a result of 0.8.

https://brainly.com/question/28449508

#SPJ3

13/16 as a decimal rounded to the nearest tenth is 0.8.

To convert the fraction 13/16 to a decimal and round it to the nearest tenth, we can follow these steps:

4: Geraldine wanted custom keychains. The store she went to has a service fee of 5 dollars, then 8 dollars per key chain. Geraldine payed 37 dollars. How many key chains did she buy?

(She bought 4 keychains)

As for b, I need to see question 3 in order to answer

Answer:

2* (4x + 1)

Step-by-step explanation:

8x = 2 * 2 *2 * x

2 = 2* 1

GCF = 2

8x+2  =  2*2*2*x + 2*1 = 2* (4x + 1)

Answer:

[tex]\overline{QP} = \overline{SR}[/tex]

Step-by-step explanation:

Given: ∠PTQ ≅ ∠STR and TP, TQ, TR and TS are radii of the circle.

If  two angle are equal, then they are equal in size and their measurements are equal.

IF ∠PTQ ≅ ∠STR then they are also equal in their measurements.

Now, In ΔPTQ and ΔSTR

∠PTQ ≅ ∠STR  (vertically opposite angle)

[tex]\overline{TQ} \cong \overline{ST}[/tex]  (Radius of the circle are equal and congruent in length)

[tex]\overline{PT} \cong \overline{TR}[/tex]  (Radius of the circle)

∴ ΔPTQ ≅ ΔSTR (SAS postulate)

∴ [tex]\overline{QP}\cong \overline{SR}[/tex] (corresponding sides of congruent triangle are equal  and congruent).

You can use the fact that a closed figure made by connecting the adjacent end points of two equal and intersecting line segment is a rectangle.

Option A:  [tex]\overline{QP} \: \rm and \: \overline{SR}\\[/tex]correct choice since the line segment QP is and line segment SR are congruent.

Given that:

Since angle  PTQ and angle STR are congruent, thus we have:

PR and SQ as straight intersecting lines.

Due to angle PTS and angle QTR are opposite angles made by intersecting lines, we have them as congruent or say of equal measurement.

[tex]\angle PTS \cong \angle QTR[/tex]

Since [tex]\overline{TP} = \overline{TQ} = \overline{TR} = \overline{TS}[/tex], thus we have got:

[tex]\overline{PR} = \overline{SQ}[/tex] in measurement ( as PR is sum of PT and TR and same for SQ)

"A closed figure made by connecting the adjacent end points of two equal and intersecting line segment is a rectangle", we have PQRS as a rectangle.

As a rectangle have opposite sides parallel and equal, we have got:

[tex]\overline{PQ} \cong \overline{SR}[/tex]

Thus, Option A: [tex]\overline{QP} \: \rm and \: \overline{SR}\\[/tex] is the correct choice since the line segment QP is and line segment SR are congruent.

Learn more about rectangles here:

https://brainly.com/question/10046743

[tex]Hey~freckledspots!\\----------------------[/tex]

[tex]We~will~solve~for~i^{425}![/tex]

[tex]Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\[/tex]

[tex]Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------[/tex]

[tex]Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------[/tex]

[tex]Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------[/tex]

[tex]Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------[/tex]

[tex]Answer:\\\large\boxed{-1+i}\\----------------------[/tex]

[tex]Hope~This~Helped!~Good~Luck![/tex]

Answer:

[tex]i - 1[/tex]

Step-by-step explanation:

Complex Number System Rules

[tex]\sqrt{-1} = i \\ -1 = {i}^{2} \\ -i = {i}^{3} \\ 1 = {i}^{4} [Every \: multiple \: of \: four][/tex]

The Divisibilty Rule of 4 states that the last two digits of a number must be a multiple of four, so you will have this:

[tex]{i}^{425} + {i}^{14} + {i}^{-14} + {i}^{44} \\ \\ i - 1 - 1 + 1 = i - 1[/tex]

I am joyous to assist you anytime.

Answer: $49.5

Step-by-step explanation: If each song costs 0.99 cents then you multiply the number of songs you are buying by the cost. So that would be 0.99×50=49.5

Answer:

1,5

1,5 and

1,2,5,10

Step-by-step explanation: