Answer:
The scale doesn't start at 0. One could argue the maximum value should be 7, but this is a formatting choice.
Step-by-step explanation:
Answer:
The scale doesn't start at 0. One could argue the maximum value should be 7, but this is a formatting choice.
Step-by-step explanation:
A recent study conducted by the state government attempts to determine whether the voting public supports further increase in cigarette taxes. The opinion poll recently sampled 1500 voting age citizens. 1020 of the sampled citizens were in favor of an increase in cigarette taxes. The state government would like to decide if there is enough evidence to establish whether the proportion of citizens supporting an increase in cigarette taxes is significantly greater than .66. At \alpha = .05, we would reject the null hypothesis.
a. True
b. False
Answer:
b) False
Calculated value Z = 1.635 < 1.96 at 0.05 level of significance.
The null hypothesis is accepted.
Step-by-step explanation:
Explanation:-
Step:- (1)
Given data the opinion poll recently sampled 1500 voting age citizens.
Given sample size 'n' = 1500
Given data the opinion poll recently sampled 1500 voting age citizens in selected 1020 of the sampled citizens were in favor of an increase in cigarette taxes.
The sample proportion[tex]'p' = \frac{1020}{1500} = 0.68[/tex]
Given data the state government would like to decide if there is enough evidence to establish whether the proportion of citizens supporting an increase in cigarette taxes is significantly greater than .66
Population proportion 'P' =0.66
Q = 1-P
Q = 1-0.66 = 0.34
Null hypothesis :H₀: 'P' >0.66
Alternative hypothesis: H₀: 'P' <0.66
Level of significance ∝=0.05
Step:-(2)
The test statistic
[tex]Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }[/tex]
[tex]Z = \frac{0.68-0.66}{\sqrt{\frac{0.66 X 0.34}{1500} } }[/tex]
Z = 1.635
The calculated value Z = 1.635
The tabulated value Z = 1.96 at ∝=0.05 level of significance.
Therefore Z = 1.635 < 1.96 at 0.05 level of significance.
The null hypothesis is accepted.
The alternative hypothesis is rejected.
Conclusion:-
The null hypothesis is accepted at 0.05 level of significance.
The proportion of citizens supporting an increase in cigarette taxes is significantly greater than .66
A die is rolled twice.
What is the probability that the first roll was a 6 and the second roll was an odd number?
Answer:
1/12
Step-by-step explanation:
1/6 * 3/6 (First roll has a one in 6 chance, second 3 in 6)
1*3 / 36 =
3 / 36 =
1/12
Cards from an ordinary deck of 52 playing cards are turned face up one at a time. If the 1st card is an ace, or the 2nd a two, or the 3rd a three, or . . . , or the 13th a king, or the 14th an ace, or the 15th a two, and so on, we say that a match occurs. Compute the expected number of matches that occur.
Answer:
Expected number of matches that occur = 4 matches
Step-by-step explanation:
First of all, let X_i be the event that when we turn over card i if it matches the required cards face.
Thus, for example X_1 is the event that turning over one card results in an ace while X_2 is the event that turning over second card reveals a deuce.
The number of matched cards "N" is given by the sum of this indicator random variable as shown in the attached file;
The expected number of matches when cards are drawn from a standard 52-card deck is 4.
We define a match for each card position as X_i = 1 if a match occurs, and X_i = 0 otherwise. The expectation E(X_i) for each card is 1/13 because the probability of the ith card being an i-matched card (Ace in the 1st position, Two in the 2nd position, and so on up to King in the 13th, then repeat with Ace) is 1/13.
Given there are 52 cards, each having the same pattern of matching, the expected number of matches is computed as:
E(X) = E(X_1 + X_2 + ... + X_52) = E(X_1) + E(X_2) + ... + E(X_52)
Since E(X_i) = 1/13 for all i:
E(X) = 52 * (1/13) = 4
Therefore, the expected number of matches is 4.
A copy machine makes 36 copies per minute. How many copies does it make in four minutes and 45 seconds?
Answer: The copy machine makes 171 copies in 4 minutes and 45 seconds.
Step-by-step explanation:
Let's dissect the question. The copy machine makes 36 copies per minute.
36 per min.
To see how many copies it makes in 4 minutes and 45 seconds, we multiply 36 * 4.75. 45 seconds is 3/4ths of a minute, or 0.75 of a minute.
[tex]36 * 4.75=171[/tex]
It makes 171 copies in 4 minutes and 45 seconds.
Given the length of a word (wordLen) and the maximum number of consecutive vowels that it can contain (maxVowels), determine how many unique words can be generated. Words will consist of English alphabetic letters a through z only. Vowels are v: {a, e, i, o, u}; consonants are c: remaining 21 letters. In the explanations, v and c represent vowels and consonants.
Vowels are defined as sound repeated as a, e, i, o, u and the rest 21 letters are classified as consonants.
The given words are generated from English alphabet as a combination of Vowels and alphabets. Thus the combination of vowels and consonant help in the formation of words. There are n number of unique letters are formed.
1) Speed is fast = SPEEFAS
2) Minimum number of participants = MINIPART
3) Sum of excess = SUMCESS
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To find the number of unique words that can be generated with a given word length and maximum number of consecutive vowels, multiply the number of possible vowel arrangements by the number of possible consonant arrangements.
Explanation:To determine the number of unique words that can be generated given the length of a word (wordLen) and the maximum number of consecutive vowels (maxVowels), we need to consider the different possibilities for the arrangement of vowels and consonants in the word. Since vowels can be repeated consecutively up to maxVowels times, we can have up to maxVowels + 1 vowels in a row in any word. Similarly, we can have up to wordLen - maxVowels + 1 consonants in a row in any word. Therefore, the total number of unique words that can be generated is (maxVowels + 1) * (wordLen - maxVowels + 1).
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A precision instrument is guaranteed to be accurate to within 2 units. A sample of four instrument readings on the same object yielded the measurements 352, 350, 350, and 353. Give the attained significance level for testing the null hypothesis σ = 0.7 versus the alternative hypothesis σ > 0.7. (Round your answer to six decimal places.)
Answer:
[tex]\chi^2 =\frac{4-1}{0.7^2} 1.5^2 =13.776[/tex]
[tex]p_v =P(\chi^2 >13.776)=0.0032[/tex]
In order to find the p value we can use the following code in excel:
"=1-CHISQ.DIST(13.776,3,TRUE)"
If we compare the p value and the significance level assumed we see that [tex]p_v <\alpha[/tex] so on this case we have enough evidence in order reject the null hypothesis. And we can conclude that the true deviation i significantly higher than 0.7
Step-by-step explanation:
Notation and previous concepts
A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"
[tex]n=4[/tex] represent the sample size
We can calculate the sample deviation with this formula:
[tex]s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
[tex]\alpha[/tex] represent the confidence level
[tex]s =1.5 [/tex] represent the sample variance obtained
[tex]\sigma^2 =0.7[/tex] represent the value that we want to test
Null and alternative hypothesis
On this case we want to check if the population deviation is higher than 0.7, so the system of hypothesis would be:
Null Hypothesis: [tex]\sigma \leq 0.7[/tex]
Alternative hypothesis: [tex]\sigma >0.7[/tex]
Calculate the statistic
For this test we can use the following statistic:
[tex]\chi^2 =\frac{n-1}{\sigma^2_0} s^2[/tex]
And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.
[tex]\chi^2 =\frac{4-1}{0.7^2} 1.5^2 =13.776[/tex]
Calculate the p value
In order to calculate the p value we need to have in count the degrees of freedom , on this case 3. And since is a right tailed test the p value would be given by:
[tex]p_v =P(\chi^2 >13.776)=0.0032[/tex]
In order to find the p value we can use the following code in excel:
"=1-CHISQ.DIST(13.776,3,TRUE)"
Conclusion
If we compare the p value and the significance level assumed we see that [tex]p_v <\alpha[/tex] so on this case we have enough evidence in order reject the null hypothesis. And we can conclude that the true deviation i significantly higher than 0.7
a bag contains 3 red marbles, 8 blue marbles and 5 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 1000th. that both marbles drawn will be blue
Answer:
0.233
Step-by-step explanation:
There are a total of 16 marbles.
The probability the first marble is blue is 8/16.
Assuming the marble isn't replaced, the probability the second marble is blue is 7/15.
So the probability of both marbles being blue is 8/16 × 7/15 = 7/30 ≈ 0.233.
The probability of drawing two blue marbles without replacement is 0.233 to the nearest thousandth, calculated by multiplying the individual probabilities of the first and second draws.
Explanation:The probability of drawing two blue marbles from a bag without replacement involves a two-step calculation because the outcome of the first draw affects the second. Since there are 3 red, 8 blue, and 5 green marbles, the total number of marbles is 16. The probability of drawing a blue marble first is 8/16 or 1/2.
After drawing one blue marble, there would be 7 blue marbles left in a bag of 15 total marbles. The probability of drawing a blue marble on the second draw is then 7/15. To find the combined probability of both events occurring, we multiply the two probabilities: (1/2) × (7/15) = 7/30, which is approximately 0.233 to the nearest thousandth.
Thus, the probability of drawing two blue marbles in a row without replacement is 0.233 to the nearest thousandth.
Multiply 2 and 1 half by 3 and 1 third
Answer:
8 1/3
Step-by-step explanation:
2 1/2 * 3 1/3
Change each to an improper fraction
2 1/2 = (2*2 +1)/2 = 5/2
3 1/3 = (3*3+1)/3 = 10/3
5/2 *10/3 = 50/6
Divide the top and bottom by 2
25/3
Change to a mixed number
3 goes into 25 8 times with 1 left over
8 1/3
covert the units of weight 32IB 12oz = blank IB ? Help please as fast as you can
Answer:
32¾
Step-by-step explanation:
1 pound (lb) = 16 ounces
12 oz = 12/16 = 3/4 lb
32 pounds 12 oz
32 ¾ lb
In a group of 700 people, must there be 2 who have matching first and last initials? Why? (Assume each person has a first and last name.) Correct: Your answer is correct. . Let A be the set of 700 distinct people and let B be the 52 Incorrect: Your answer is incorrect. different unique combinations of first and last initials. If we construct a function from A to B, then by the Correct: Your answer is correct. principle, the function must be Correct: Your answer is correct. . Therefore, in a group of 700 people, it is Correct: Your answer is correct. that no two people have matching first and last initials.
Answer:
Yes, there are only 676 different possibilities, which is less than the number of people in the group.
Step-by-step explanation:
Assuming that the English alphabet has 26 different letters, the number of possible combinations of first and last name initials is:
[tex]n = 26*26\\n=676[/tex]
If we try to assign a different combination to each person in the group, it would only be possible to do it for the first 676 people, while the remaining 24 would have a repeated first and last initial. Therefore, the answer is yes, there must be 2 people who have matching first and last initials.
The Pigeonhole Principle in mathematics implies in a group of 700 people, there must be at least two people who have matching first and last initials.
Explanation:The concept of this problem involves understanding the Pigeonhole Principle in mathematics. Considering the English alphabet has 26 letters, we can have 26 possible first initials and 26 possible last initials. Therefore, there are 26x26=676 unique combinations of first and last initials. However, we have a group of 700 people which is more than 676. The Pigeonhole Principle states that if you try to distribute more items than there are containers, then at least one container must hold more than one item. Therefore, applying this principle, there must be at least two people among the group of 700 who have matching first and last initials because the number of people (700) is greater than the possible unique combinations of first and last initials (676).
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One number is eight more than twice another. If their difference is 25, what is the larger number?
17
42
35
Answer: The largest number was 42
How much interest is earned on a principal of $9.02 invested at an interest
rate of 8% for three years?
Final answer:
The interest earned on $9.02 at an 8% interest rate for three years is $2.16.
Explanation:
To calculate the amount of interest earned on a principal of $9.02 at an interest rate of 8% for three years, we would use the formula for simple interest: Interest = Principal imes Rate imes Time. Plugging in the values we get:
Interest = $9.02 imes 0.08 imes 3
Interest = $2.166. Therefore, the interest earned on the principal amount of $9.02 invested at an 8% interest rate for three years would be $2.16, after rounding to the nearest cent.
What is .54444 as a fraction?
Answer:
.54444 = .54444/1 = 5.4444/10 = 54.444/100 = 544.44/1000 = 5444.4/10000 = 54444/100000, any one of those works
Answer:
54/99
Step-by-step explanation:
Casey has a total of 18 pens. Twelve of these pens are blue, and the rest are red.
What is the ratio of blue pens to red pens?
Answer: For every 12 blue pens, she has 6 red pens 12:6
Simplifying this would be: 2:1
Answer:
3 : 1
Step-by-step explanation:
18 : 6
simplified ratio is
3 : 1
what should 2.33 be multiplied by to make a whole number
Answer:
You dont multiply anything, you just round
Step-by-step explanation:
basically, you round the 2.3 to the nearest whole number which is most likely 2 because 3 is under five so it doesnt round up
You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately σ = 39.9 σ=39.9. You would like to be 99% confident that your estimate is within 2 of the true population mean. How large of a sample size is required?
Answer:
large of a sample size n = 2645
Step-by-step explanation:
Explanation:-
The population standard deviation 'σ' = 39.9
Given data the estimate is within 2 of the true population mean so given the margin of error = 2
we know that margin of error is determined by
Margin of error = [tex]\frac{z_{\alpha }S.D }{\sqrt{n} }[/tex]
cross multiplication , we get
[tex]\sqrt{n} = \frac{2.578 X S.D}{M.E}[/tex]
[tex]\sqrt{n} = \frac{2.578 X 39.9}{2}= 51.4311[/tex]
squaring on both sides , we get
n = 2645.15
n = 2645
Conclusion:-
large of a sample size n = 2645
In a study of the relationship of the shape of a tablet to its dissolution time, 6 disk-shaped ibuprofen tablets and 8 oval-shaped ibuprofen tablets were dissolved in water. The dissolve times, in seconds, were as follows:
Disk: 269.0 249.3 255.2 252.7 247.0 261.6
Oval: 268.8 260.0 273.5 253.9 278.5 289.4 261.6 280.2
Can you conclude that the mean dissolve times differ between the two shapes?
Answer:
[tex]t=\frac{255.8-270.74}{\sqrt{\frac{(8.215)^2}{6}+\frac{(11.903)^2}{8}}}}=-2.788[/tex]
[tex]p_v =2*P(t_{(12)}<-2.788)=0.0164[/tex]
So the p value is a very low value and using any significance level for example [tex]\alpha=0.05, 0,1,0.15[/tex] always [tex]p_v<\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that we have significant difference in the means of the two groups
Step-by-step explanation:
Data given and notation
Disk:[269.0 249.3 255.2 252.7 247.0 261.6]
Oval:[ 268.8 260.0 273.5 253.9 278.5 289.4 261.6 280.2]
[tex]\bar X_{D}=255.8[/tex] represent the mean for the sample Disk
[tex]\bar X_{O}=270.74[/tex] represent the mean for the sample Oval
[tex]s_{D}=8.215[/tex] represent the sample standard deviation for the sample Disk
[tex]s_{O}=11.903[/tex] represent the sample standard deviation for the sample Oval
[tex]n_{D}=6[/tex] sample size for the group Disk
[tex]n_{O}=8[/tex] sample size for the group Oval
t would represent the statistic (variable of interest)
Concepts and formulas to use
We need to conduct a hypothesis in order to check if the means are different, the system of hypothesis would be:
Null hypothesis:[tex]\mu_{D} = \mu_{O}[/tex]
Alternative hypothesis:[tex]\mu_{D} \neq \mu_{O}[/tex]
If we analyze the size for the samples both are less than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:
[tex]t=\frac{\bar X_{D}-\bar X_{O}}{\sqrt{\frac{s^2_{D}}{n_{D}}+\frac{s^2_{O}}{n_{O}}}}[/tex] (1)
t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.
Calculate the statistic
We can replace in formula (1) the results obtained like this:
[tex]t=\frac{255.8-270.74}{\sqrt{\frac{(8.215)^2}{6}+\frac{(11.903)^2}{8}}}}=-2.788[/tex]
Statistical decision
For this case we don't have a significance level provided [tex]\alpha[/tex], but we can calculate the p value for this test. The first step is calculate the degrees of freedom, on this case:
[tex]df=n_{D}+n_{O}-2=6+8-2=12[/tex]
Since is a bilateral test the p value would be:
[tex]p_v =2*P(t_{(12)}<-2.788)=0.0164[/tex]
So the p value is a very low value and using any significance level for example [tex]\alpha=0.05, 0,1,0.15[/tex] always [tex]p_v<\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that we have significant difference in the means of the two groups
The diameter of a mason jar is 3 inches but can be as large as 3.03 inches and as small as 2.97 inches. Twenty-five samples of mason jars are taken and it is discovered that these components have a grand mean of 3.01 inches and a standard deviation of 0.02 inches. What is the probability of producing a bad product? (4pts)
Answer:
18.15% probability of producing a bad product
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 3.01, \sigma = 0.02[/tex]
What is the probability of producing a bad product?
Less than 2.97 or more than 3.03.
Less than 2.97
pvalue of Z when X = 2.97. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{2.97 - 3.01}{0.02}[/tex]
[tex]Z = -2[/tex]
[tex]Z = -2[/tex] has a pvalue of 0.0228
More than 3.03
1 subtracted by the pvalue of Z when X = 3.03. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{3.03 - 3.01}{0.02}[/tex]
[tex]Z = 1[/tex]
[tex]Z = 1[/tex] has a pvalue of 0.8413
1 - 0.8413 = 0.1587
Then
0.0228 + 0.1587 = 0.1815
18.15% probability of producing a bad product
A firework rocket is shot upward at a rate of 640ft/sec. Use the projectile formula h= -16t^2 +v0t to determine the times when the height of the firework will be 1,200 feet. Round your answer to the nearest whole number.
Answer:
2 seconds and 38 seconds
Step-by-step explanation:
h=-16t²-vot
1,200=-16t²-640t
turn this into standard form
16t²-640t+1200=0
now plug thes numbers into the quadratice formula
a 16 b -640 c 1200
solve with quadratic formula to get ≅2 and ≅38 seconds
Answer:
t≈2 seconds,t≈38 seconds
Step-by-step explanation:
h=−16t2+ v0t
Step 1. Solve the equation.
1,200= −16t^2+ 640t
We know the velocity, v0, is 640 feet per second.
The height is 1,200 feet. Substitute the values.
This is a quadratic equation. Rewrite it in standard form. Solve the equation using the quadratic formula.
ax^2 + bx + c . = 0
16t^2 −640t + 1,200 = 0
Identify the values of a, b, and c.
a=16, b=−640, c=1,200
Write the quadratic formula.
t=−b± √b2−4ac‾‾‾‾‾‾‾‾
2a
640+ √332,800‾‾‾‾‾‾‾‾ t= √640− √332,800‾‾‾‾‾‾‾
32 32
Rewrite to show two solutions.
t=640+332,800‾‾‾‾‾‾‾‾√32,t=640−332,800‾‾‾‾‾‾‾‾√32
Approximate the answer with a calculator.
t≈2 seconds,t≈38 seconds
Step 2. Check the answer. The check is left to you.
Step 3. Answer the question.
The firework will go up and then fall back down. As the firework goes up, it will reach 1,200 feet after approximately 2 seconds. It will also pass that height on the way down at 38 seconds.
Suppose a company that makes fitness watches samples 15 watches. They know the probability one of their watches fails, within 1 year of purchase, is 0.12. The chance one watch fails is independent of other watches. What type of distribution will best model the number of watches out of the 15 sampled that fail within 1 year
Answer:
Binomial probability distribution.
Step-by-step explanation:
For each watch, there are only two possible outcomes. Either it fails within 1 year of purchase, or it does not. The probability of a watch falling within 1 year of purchase is independent of other watches. So the type of of distribution will best model the number of watches out of the 15 sampled that fail within 1 year is the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
Solve the inequality.
x/3-x-1/2≥1 a. x≤-3 b. x≥-3 c. x≤3 d. x≥3
Answer:
x ≤-9/4
Step-by-step explanation:
x/3-x-1/2≥1
Multiply each side by 6 to get rid of the fractions
6(x/3-x-1/2)≥1*6
2x -6x -3≥6
Combine like terms
-4x-3≥6
Add 3 to each side
-4x-3+3≥6+3
-4x ≥9
Divide each side by -4, remembering to flip the inequality
-4x/-4 ≤9/-4
x ≤-9/4
On solving the inequality x/3 - x - 1/2 ≥ 1, we get x ≤ -3. Hence the correct option is A.
Solve the inequality: x/3 - x - 1/2 ≥ 1
Combine like terms: x/3 - (2x + 1)/2 ≥ 1
Get a common denominator: 2x/6 - 3(2x + 1)/6 ≥ 6/6
Simplify the equation: -4x - 3 ≥ 0
Solve for x: x ≤ -3
y=4x−2 (What does Y and X equal?
y=x+3
Answer:
x = 5/3
y = 14/3
Step-by-step explanation:
y=4x−2
y=x+3
Since they are both equal to y, we can set them equal to each other
4x-2 = x+3
Subtract x from each side
4x-2-x = x+3-x
3x-2 =3
Add 2 to each side
3x-2+2 = 3+2
3x =5
Divide each side by 3
3x/3 =5/3
x = 5/3
Now we need to find y
y = x+3
y =5/3+3
y = 5/3+9/3
y = 14/3
Answer:
x=5/3; y=14/3
Step-by-step explanation:
Subtract the following:
-4x+y=-2
-x+y=3
= -3x=-5
x=5/3
substitute x into one of the given equations.
y=5/3+3
y= 14/3
HELP PLEASE
Find the are of the circle.Leave your answer in terms of pie
A.9pi ft
B.324pi ft
C.18pi ft
D.81 pi ft
Answer:
A = 81 pi ft^2
Step-by-step explanation:
The area of a circle is found by
A = pi r^2
The radius is 9
A = pi 9^2
A = 81 pi ft^2
A marine sales dealer Önds that the average price of a previously owned boat is $6492. He decides to sell boats that will appeal to the middle 66% of the market in terms of price. Find the maximum and minimum prices of the boats the dealer will sell. The standard deviation is $1025, and the variable is normally distributed.
Answer:
The maximum price that the dealer will sell is $7471 and the minimum is $5513.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 6492, \sigma = 1025[/tex]
Middle 66%
50 - (66/2) = 17th percentile
50 + (66/2) = 83rd percentile
17th percentile
X when Z has a pvalue of 0.17. So X when Z = -0.955.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-0.955 = \frac{X - 6492}{1025}[/tex]
[tex]X - 6492 = -0.955*1025[/tex]
[tex]X = 5513[/tex]
83rd percentile
X when Z has a pvalue of 0.83. So X when Z = 0.955.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]0.955 = \frac{X - 6492}{1025}[/tex]
[tex]X - 6492 = 0.955*1025[/tex]
[tex]X = 7471[/tex]
The maximum price that the dealer will sell is $7471 and the minimum is $5513.
Consider the following time series data: Month 1 2 3 4 5 6 7 Value 23 14 20 11 19 24 15 (a) Compute MSE using the most recent value as the forecast for the next period. If required, round your answer to one decimal place. What is the forecast for month 8? If required, round your answer to one decimal place. Do not round intermediate calculation. (b) Compute MSE using the average of all the data available as the forecast for the next period. If required, round your answer to one decimal place. Do not round intermediate calculation. What is the forecast for month 8? If required, round your answer to one decimal place. (c) Which method appears to provide the better forecast?
Answer:
a) MSE = 61.33
Forecast for 8th month = 15
b) MSE = 34.51
Forecast for 8th month = 18
c) The average method provides a better forecast because of its low MSE
Explanation:
Check the attached file for the solvings.
To answer this two-part question, you'll need to calculate the mean square errors (MSE) using two different forecasting methods: using the most recent value as a forecast and using the average of all data for a forecast. The one with lower MSE is the correct prediction. The forecast for the next month is always based on the previous value or average value depending on the method.
Explanation:To answer this question, you need to understand how mean square error (MSE) and forecasting work. For (a), we use the last value as the forecast for the next value and compute MSE. For (b), we use the average of all data as the forecast for the next value and calculate the MSE. Finally, we compare which method gives a lower MSE, therefore better forecasting.
For (a), the forecast values would be the previous month's data, i.e., forecast for month 2 is 23, month 3 is 14 and so on. To calculate MSE, you subtract each monthly value from its forecast, square the result and find the average of these squares. The forecast for month 8 would be the value of month 7 which is 15.
For (b), you calculate the average of all the data available and use it as a forecast for all the next periods. The MSE and forecast for month 8 can be calculated in a similar manner as in (a).
In step (c), compare the MSE calculated in step (a) and step (b). A lower MSE indicates a better forecast and consequently represents an accurate choice for a predictive model.
Learn more about MSE and Forecasting here:https://brainly.com/question/33964002
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Based on the list, how many different-color pants does Megan have to choose from?
Answer:
Whats on the list?????
Step-by-step explanation:
Maryam showed the location of each vertex of a polygon on the grid below. On a coordinate plane, points are at (1, 3), (4, 1), (3, negative 3), (negative 1, negative 3), and (negative 2, 1). If the points are connected, which statements about the polygon are true? Check all that apply. The polygon has six sides. The polygon is a pentagon. The vertices of the polygon are (–2, 1), (1, 3), (4, 1), (3, –3), and (–1, –3). The polygon has five vertices. The polygon is a heptagon.
Answer:
bcd
Step-by-step explanation:
Answer:
B C D
Step-by-step explanation:
A report on a certain fast food restaurant states that μ, the mean order total, is $9. The manager of the restaurant believes the mean is higher. A random sample of orders will be selected. The sample mean x¯ will be calculated and used in a hypothesis test to investigate the belief. Which of the following is the correct set of hypotheses?A. H0:x¯=$9Ha:x¯≠$9B. H0:x¯=$9Ha:x¯>$9 C. H0:μ=$9Ha:μ≠$9 D. H0:μ=$9Ha:μ>$9 E. H0:μ=$9Ha:μ<$9
Answer:
Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = $9
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $9
Step-by-step explanation:
We are given that a report on a certain fast food restaurant states that μ, the mean order total, is $9. The manager of the restaurant believes the mean is higher.
A random sample of orders will be selected. The sample mean x¯ will be calculated and used in a hypothesis test to investigate the belief.
Let [tex]\mu[/tex] = the mean order total
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = $9
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $9
Here, null hypothesis states that the mean order total is equal to $9 and the manager claim's is not correct.
On the other hand, alternate hypothesis states that the mean order total is higher than $9 and the manager claim's is correct.
So, this would be the correct set of hypotheses for testing.
Based on the null hypothesis, the mean order to total is $9, and the manager's belief is wrong. Based on alternate hypothesis, the mean order total is more than $9, and the manager is right.
Given information:
A report on a certain fast food restaurant states that μ, the mean order total, is $9.
The manager of the restaurant believes the mean is higher.
So, according to the null hypothesis, [tex]H_0[/tex]
[tex]\mu=9[/tex]
And, according to alternate hypothesis, [tex]H_a[/tex]
[tex]\mu>9[/tex]
Therefore, based on the null hypothesis, the mean order to total is $9, and the manager's belief is wrong. Based on alternate hypothesis, the mean order total is more than $9, and the manager is right.
For more details about null hypothesis, refer to the link:
https://brainly.com/question/16313918
estimate 1.3 - (-2.5)
Answer:
3.8
Step-by-step explanation:
A quality inspector inspect random box of 50 tablets. He discovers 2 are defective. In an order of 2,000 tablets,how many are likely to be defective
Answer:
80
Step-by-step explanation:
So if 50 tablets are made and 2 are defective then it’s 50:2. That means for every 50 tablets are made 2 are defective. And since 50 goes into 2000 40 times, you would multiply 40 x 2 to get 80, the number defective tablets