The price of a certain computer stock t days after it is issued for sale is p(t)=100+20t−6t^2 dollars. The price of the stock initially rises, but eventually begins to fall. During what period of time does the stock price rise?
0 < t < ____?
If you owned the stock, after how many days would you sell it? ____ days

Answers

Answer 1

Answer:

0 < t < [tex]\frac{5}{3}[/tex]

After 1.67 days the stocks would be sold out.

Step-by-step explanation:

The price of a certain computer stock after t days is modeled by

p(t) = 100 + 20t - 6t²

Now we will take the derivative of the given function and equate it to zero to find the critical points,

p'(t) = 20 - 12t = 0

t = [tex]\frac{20}{12}[/tex]

t = [tex]\frac{5}{3}[/tex] days

Therefore, there are two intervals in which the given function is defined

(0, [tex]\frac{5}{3}[/tex]) and ([tex]\frac{5}{3}[/tex], ∞)

For the interval (0, [tex]\frac{5}{3}[/tex]),

p'(1) = 20 - 12(1) = 20

For the interval ([tex]\frac{5}{3}[/tex], ∞),

p'(2) = 20 - 12(2) = -4

Positive value of p'(t) in the interval (0, [tex]\frac{5}{3}[/tex]) indicates that the function is increasing.

0 < t < [tex]\frac{5}{3}[/tex]

Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.

Answer 2
Final answer:

The price of the computer stock rises for the first 5/3 days after it is issued. Ideally, if you owned the stock, you should sell it after 5/3 days to maximize your profit.

Explanation:

The price of the stock becomes maximum when the rate of change of the price is 0. To find when that is, we need to take the derivative of the price function, which is p'(t) = 20 - 12t, and set it equal to 0. Solving for t, we get t = 20/12 = 5/3. So, the price of the stock rises for t in (0, 5/3) days. Therefore, if you owned the stock, you should sell it after 5/3 days to maximize your profit.

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Related Questions

Henry was buying meals for his family. He bought 3 meals that included a chicken, corn, and a drink and spent a total of $20.25. He paid 6% sales tax. How much did each meal cost before tax?

Answers

Answer:

The price of each meal cost before tax is $ 6.367

Step-by-step explanation:

Given as :

The total price of three meals = $ 20.25

The sales tax included in the total price = 6 %

So, Let the cost of meal before sales tax = x

Or, x + 6 % of x = $ 20.25

or, x + 0.06 x = $ 20.25

Or, 1.06 x = $ 20.25

∴  x = [tex]\frac{20.25}{1.06}[/tex]

I.e x = $ 19.10

Or, price of three meals before tax = $ 19.10

so, The price of each meal = [tex]\frac{19.10}{3}[/tex] = $ 6.367

Hence The price of each meal cost before tax is $ 6.367   answer

A normal distribution is observed from the times to complete an obstacle course. The mean is 69 seconds and the standard deviation is 6 seconds. Using the Empirical Rule, what is the probability that a randomly selected finishing time is greater than 87 seconds?

Answers

Answer:

P ( z > 87 ) < 0,0015        

P ( z > 87 ) < 0,15 %

Step-by-step explanation:

Applying the simple rule that:

μ ± 3σ  , means that between

μ - 9  = 60   and

μ + 9 = 78

We will find 99,7 of the values

And given that  z(s) = 87 > 78  (the upper limit of the above mention interval ) we must conclude that the probability of find a value greater than 87 is smaller than 0.0015 ( 0r 0,15 %)

Final answer:

To determine the probability of a finish time greater than 87 seconds, we apply the Empirical Rule and find it equates to 3 standard deviations above mean, resulting in a probability of 0.15%.

Explanation:

The question revolves around the use of the Empirical Rule to determine the probability in a normal distribution. The mean time to complete an obstacle course is given as 69 seconds with a standard deviation of 6 seconds. According to the Empirical Rule:

   

To find out the probability of a finishing time being greater than 87 seconds, we first determine how many standard deviations above the mean this is:

(87 - 69) / 6 = 3

This indicates that 87 seconds is 3 standard deviations above the mean. Using the Empirical Rule, if 99.7% of the data falls within three standard deviations, this would leave 0.3% (or 0.003 in decimal form) of the data outside, which would be the tails of the distribution (both ends combined). Since we are looking for the area above 87 seconds, we only consider one tail, hence, we divide the 0.3% equally for each tail to get 0.15% (or 0.0015 in decimal form) for the probability that a randomly selected finish time is greater than 87 seconds.

18 - 24i write in trigonometric form

Answers

[tex]\boxed{18-24i=30(cos(5.36)+isin(5.36))}[/tex]

Explanation:

Unlike 0, we can write any complex number in the trigonometric form:

[tex]z=r(cos\alpha+isin\alpha)[/tex]

We have the complex number:

[tex]18-24i[/tex]

So [tex]r[/tex] can be found as:

[tex]r=\sqrt{x^2+y^2} \\ \\ \\ Where: \\ \\ x=18 \\ \\ y=-24 \\ \\ r=\sqrt{18^2+(-24)^2} \\ \\ r=\sqrt{324+576} \\ \\ r=\sqrt{900} \\ \\ r=30[/tex]

Now for α:

[tex]\alpha=arctan(\frac{y}{x}) \\ \\ Since \ the \ complex \ number \ lies \ on \ the \ fourth \ quadrant: \\ \\ \alpha=arctan(\frac{-24}{18})=-53.13^{\circ}  \ or \ 360-53.13=306.87^{\circ}[/tex]

Finally:

[tex]Convert \ into \ radian: \\ \\ 360^{\circ}\times \frac{\pi}{180}=5.36rad \\ \\ \\ Hence: \\ \\ \boxed{18-24i=30(cos(5.36)+isin(5.36))}[/tex]

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a. Consider the following algorithm segment: for i := 1 to 4, for j := 1 to i, [Statements in body of inner loop. None contain branching statements that lead outside the loop.] next j, next i. How many times will the inner loop be iterated when the algorithm is implemented and run?
b. Let n be a positive integer, and consider the following algorithm segment: for i := 1 to n, for j := 1 to i, [Statements in body of inner loop. None contain branching statements that lead outside the loop.], next j, next i. How many times will the inner loop be iterated when the algorithm is implemented and run?

Answers

The number of times the inner loop be iterated when the algorithm is implemented and run is 10.

We are given that;

i := 1 to 4, for j := 1

Now,

a. The inner loop will be iterated 10 times when the algorithm is implemented and run.

| i | j | Iterations |

|---|---|------------|

| 1 | 1 | 1          |

| 2 | 1 | 2          |

| 2 | 2 | 3          |

| 3 | 1 | 4          |

| 3 | 2 | 5          |

| 3 | 3 | 6          |

| 4 | 1 | 7          |

| 4 | 2 | 8          |

| 4 | 3 | 9          |

| 4 | 4 | 10         |

b. The number of iterations of the inner loop depends on the value of i. For each i, the inner loop runs from j = 1 to j = i.

So, the total number of iterations is the sum of i from i = 1 to i = n. This is a well-known arithmetic series, which can be written as:

[tex]$\sum_{i=1}^n i = \frac{n(n+1)}{2}$[/tex]

This is the formula for the number of iterations of the inner loop.

Therefore, by algorithm the answer will be 10.

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a. The inner loop will be iterated 10 times when the algorithm is implemented and run.

b. The total number of iterations for the inner loop when the algorithm is implemented and run will be (n^2 + n)/2.

a. In the given algorithm segment, we have two nested loops. The outer loop runs from 1 to 4, and the inner loop runs from 1 to i. Let's analyze how many times the inner loop will be iterated.

For i = 1, the inner loop will run once.

For i = 2, the inner loop will run twice.

For i = 3, the inner loop will run three times.

For i = 4, the inner loop will run four times.

Therefore, the total number of iterations for the inner loop can be calculated by summing the iterations for each value of i:

1 + 2 + 3 + 4 = 10

b. In this algorithm segment, we have the same nested loops as in part a, but the range of the outer loop is from 1 to n, where n is a positive integer.

The inner loop iterates from 1 to i, where i takes the values from 1 to n. So, for each value of i, the inner loop will run i times.

To determine the total number of iterations for the inner loop, we need to sum the iterations for each value of i from 1 to n:

1 + 2 + 3 + ... + n

This is an arithmetic series, and the sum of an arithmetic series can be calculated using the formula:

Sum = (n/2)(first term + last term)

In this case, the first term is 1, and the last term is n. Substituting these values into the formula, we get:

Sum = (n/2)(1 + n) = (n^2 + n)/2

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Help me!!! 100 points !!

Answers

Answer:

200000 times larger, its not in scientifc notation it should be 1.3*10^9, and the answer is 1.824*10^15,or182400000000000

Step-by-step explanation:

Answer:

Step-by-step explanation:

To find how many times larger, divide the CEO's salary by the teachers to get

5 000 000 / 25 000 = 200

this in scientific notation is 2.00 * 10^2

d - is not in scientific notation because there is more than one digit before the decimal place

1.3 * 10 ^9

e - 1.748 * 10^15

PLEASE HELP!!!
A total of 517 tickets were sold for the school play. They were either adult tickets or student tickets. There were 67 more student tickets sold than adult tickets. How many adult tickets were sold?

Answers

Answer:

  225 adult tickets were sold

Step-by-step explanation:

You are asked to find the number of adult tickets sold. It is convenient to let a variable represent that quantity. We can call it "a" to remind us it is the number of adult tickets (not student tickets).

The number of student tickets is 67 more, so can be represented by (a+67). The total number of tickets sold is the sum of the numbers of adult tickets and student tickets:

  (a) + (a+67) = 517

  2a + 67 = 517 . . . . . collect terms

  2a = 450 . . . . . . . . . subtract 67

  a = 225 . . . . . . . . . . divide by 2

There were 225 adult tickets sold.

_____

Check

The number of student tickets sold is ...

  a+67 = 225 +67 = 292

And the total number of tickets sold is ...

  225 + 292 = 517 . . . . . answer checks OK

I need help with my math homework. The questions is: Find all solutions of the equation in the interval [0,2π).
√3 tan(x- π/8)-1=0

Answers

Answer:

[tex]\frac{7\pi}{24}[/tex] and [tex]\frac{31\pi}{24}[/tex]

Step-by-step explanation:

[tex]\sqrt{3} \tan(x-\frac{\pi}{8})-1=0[/tex]

Let's first isolate the trig function.

Add 1 one on both sides:

[tex]\sqrt{3} \tan(x-\frac{\pi}{8})=1[/tex]

Divide both sides by [tex]\sqrt{3}[/tex]:

[tex]\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}[/tex]

Now recall [tex]\tan(u)=\frac{\sin(u)}{\cos(u)}[/tex].

[tex]\frac{1}{\sqrt{3}}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}[/tex]

or

[tex]\frac{1}{\sqrt{3}}=\frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}}[/tex]

The first ratio I have can be found using [tex]\frac{\pi}{6}[/tex] in the first rotation of the unit circle.

The second ratio I have can be found using [tex]\frac{7\pi}{6}[/tex] you can see this is on the same line as the [tex]\frac{\pi}{6}[/tex] so you could write [tex]\frac{7\pi}{6}[/tex] as [tex]\frac{\pi}{6}+\pi[/tex].

So this means the following:

[tex]\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}[/tex]

is true when [tex]x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi[/tex]

where [tex]n[/tex] is integer.

Integers are the set containing {..,-3,-2,-1,0,1,2,3,...}.

So now we have a linear equation to solve:

[tex]x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi[/tex]

Add [tex]\frac{\pi}{8}[/tex] on both sides:

[tex]x=\frac{\pi}{6}+\frac{\pi}{8}+n \pi[/tex]

Find common denominator between the first two terms on the right.

That is 24.

[tex]x=\frac{4\pi}{24}+\frac{3\pi}{24}+n \pi[/tex]

[tex]x=\frac{7\pi}{24}+n \pi[/tex] (So this is for all the solutions.)

Now I just notice that it said find all the solutions in the interval [tex][0,2\pi)[/tex].

So if [tex]\sqrt{3} \tan(x-\frac{\pi}{8})-1=0[/tex] and we let [tex]u=x-\frac{\pi}{8}[/tex], then solving for [tex]x[/tex] gives us:

[tex]u+\frac{\pi}{8}=x[/tex] ( I just added [tex]\frac{\pi}{8}[/tex] on both sides.)

So recall [tex]0\le x<2\pi[/tex].

Then [tex]0 \le u+\frac{\pi}{8}<2 \pi[/tex].

Subtract [tex]\frac{\pi}{8}[/tex] on both sides:

[tex]-\frac{\pi}{8}\le u <2 \pi-\frac{\pi}{8}[/tex]

Simplify:

[tex]-\frac{\pi}{8}\le u <\pi (2-\frac{1}{8})[/tex]

[tex]-\frac{\pi}{8}\le u<\frac{15\pi}{8}[/tex]

So we want to find solutions to:

[tex]\tan(u)=\frac{1}{\sqrt{3}}[/tex] with the condition:

[tex]-\frac{\pi}{8}\le u<\frac{15\pi}{8}[/tex]

That's just at [tex]\frac{\pi}{6}[/tex] and [tex]\frac{7\pi}{6}[/tex]

So now adding [tex]\frac{\pi}{8}[/tex] to both gives us the solutions to:

[tex]\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}[/tex] in the interval:

[tex]0\le x<2\pi[/tex].

The solutions we are looking for are:

[tex]\frac{\pi}{6}+\frac{\pi}{8}[/tex] and [tex]\frac{7\pi}{6}+\frac{\pi}{8}[/tex]

Let's simplifying:

[tex](\frac{1}{6}+\frac{1}{8})\pi[/tex] and [tex](\frac{7}{6}+\frac{1}{8})\pi[/tex]

[tex]\frac{7}{24}\pi[/tex] and [tex]\frac{31}{24}\pi[/tex]

[tex]\frac{7\pi}{24}[/tex] and [tex]\frac{31\pi}{24}[/tex]

Design a rectangular milk carton box of width $$w, length $$l, and height $$h, which holds $$128 cubic cm of milk. The sides of the box cost $$1 cent per square cm and the top and bottom cost $$2 cents per square cm. Find the dimensions of the box that minimize the total cost of materials used.

Answers

To minimize the cost of a rectangular milk carton that holds 128 cubic cm, we need to calculate the dimensions that minimize the surface area cost. By setting up an optimization problem and using calculus, we can find the values of length, width, and height that satisfy the volume constraint and result in the lowest cost.

Minimizing Cost for a Rectangular Milk Carton

To find the dimensions of a rectangular milk carton with a given volume that minimize the cost of materials used, we can set up an optimization problem using calculus. First, we know the volume of the milk carton must be $$128 cm^3$, which gives us the constraint:

V = lwh = 128

Next, we need to express the cost function in terms of the dimensions of the box. The sides of the box cost $$1 cent per square cm, while the top and bottom cost $2 cents per square cm. Thus, the total cost, C, in cents, is:

C = 2lw + 2wh + 2lh + (4 * l * w)

To minimize the cost, we would take the partial derivatives with respect to l, w, and h, set them equal to zero, and solve the system of equations while taking into account the volume constraint. This involves the method of Lagrange multipliers or directly substituting the volume constraint into the cost function to eliminate one variable and then taking the derivative with respect to the other variables.

By finding the derivative of the cost function and setting it to zero, you can determine the values of l, w, and h that will result in the minimum cost while respecting the volume constraint. Since this is an applied problem, it is important to check that the resulting values are practical, meaning they should be positive and make sense for a milk carton.

Due to a manufacturing error, four cans of regular soda were accidentally filled with diet soda and placed into an 18 pack. Suppose that two cans are randomly selected from the 18 pack.a. Determine the probability that both contain diet soda. (Round to four decimal places as needed.)b. Determine the probability that both contain regular soda. (Round to four decimal places as needed.)Would this be unusual?A. YesB. Noc. Determine the probability that exactly one is diet and exactly one is regular. (Round to four decimal places as needed.)

Answers

Final answer:

The probability of drawing two diet sodas is 0.0392, two regular sodas is 0.5948, and one of each is 0.3660. It would be unusual to select two diet sodas.

Explanation:

To answer this question, we will be using combinatorial probability. The pack contains 4 cans of diet soda and 14 cans of regular soda (18 in total).

a. The probability that both cans are diet soda can be calculated as follows: There are 4 ways to choose the first can of diet soda and 3 ways to choose the second one. Thus, there are 4 * 3 = 12 favorable outcomes. There are 18 ways to choose the first can and 17 ways to choose the second, totaling 18 * 17 = 306 possible outcomes. Hence, the probability is 12/306 = 0.0392b. The probability that both cans are regular soda can be calculated similarly: There are 14 ways to select the first can of regular soda and 13 ways to select the second one. So, there are 14 * 13 = 182 favorable outcomes. Using the same total possible outcomes, the probability is 182/306 = 0.5948c. The probability that one is a diet soda and one is a regular soda can also be calculated: There are 4 ways to select the diet soda and 14 ways to select the regular soda. Thus, there are 4 * 14 = 56 favorable outcomes. However, since the soda can be selected in any order (regular then diet or diet then regular), we double these outcomes, resulting in 112. Hence, the probability is 112/306 = 0.3660

Unusual results are typically those that have low probability. So in this context, it would be unusual to select two diet sodas (a).

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Final answer:

The probabilities of selecting two cans of diet soda, regular soda, and one of each (diest and regular) from an 18 pack are 0.0235, 0.5378, and 0.3878, respectively.

Explanation:

These types of calculations fall under the category of combinatorics, specifically combinations. We are interested in the number of ways we can select cans from a total of 18 where order does not matter.

a. The probability that both randomly selected cans are diet soda is calculated by the formula: (Number of ways to select diet soda) / (Total ways to select two cans). Here we have 4 cases in which we could select diet soda and 18 ways to select any two cans from the pack. Hence, we calculate the probability as:

(4/18) * (3/17) = 0.0235

b. In a similar manner, the probability that both randomly selected cans are non-diet soda (regular soda) is calculated as:

(14/18) * (13/17) = 0.5378

These results are not unusual as there are more regular soda cans in the pack, hence the probability of picking two regular soda cans is higher.

c. The probability that exactly one is diet and exactly one is regular, we have two cases: selecting diet soda first and then regular soda second or selecting regular soda first then diet soda. Hence we calculate the probability as:

(4/18) * (14/17) + (14/18) * (4/17) = 0.3878

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Two gardeners can do the weekly yard maintenance in 8 minutes if they work together. The older gardener takes 12 minutes more than the younger gardener to finish the job by himself. How long does it take for each gardener to do the weekly yard maintainence individually?

Answers

Answer:

Let x be the time taken( in minutes ) by younger gardener,

So, the one minute work of younger gardener = [tex]\frac{1}{x}[/tex]

Also, the time taken by older gardener = (x+12) minutes ( given ),

So, the one minute work of older gardener = [tex]\frac{1}{x+12}[/tex]

Total work done in one minute = [tex]\frac{1}{x}+\frac{1}{x+12}[/tex]

Now, total time taken = 8 minutes,

Total work done in one minute = [tex]\frac{1}{8}[/tex]

Thus,

[tex]\frac{1}{x}+\frac{1}{x+12}=\frac{1}{8}[/tex]

[tex]\frac{x+12+x}{x^2+12x}=\frac{1}{8}[/tex]

[tex]\frac{2x+12}{x^2+12x}=\frac{1}{8}[/tex]

[tex]16x + 96 = x^2+12x[/tex]

[tex]x^2 -4x -96=0[/tex]

[tex]x^2 - 12x + 8x - 96=0[/tex]

[tex]x(x-12) + 8(x-12)=0[/tex]

[tex](x+8)(x-12)=0[/tex]

By zero product product property,

x + 8 =0 or x - 12 =0

⇒ x = -8 ( not possible ), x = 12

Hence, the time taken by younger gardener = 12 minutes,

And, the time taken by older gardener = 12 + 12 = 24 minutes.

Mary scored a total of 27 points in a basketball game. During the game, all her points came from 3-point shots and 2-point shots. The number of 3-point shots she made is 4 more than her 2-point shots. How many 3-point shots and 2-point shots did she make?

A) 2 three-point shots and 6 two-point shots
B) 3 three-point shots and 7 two-point shots
C) 6 three=point shots and 2 two-point shots
D) 7 three-point shots and 3 two-point shots

Answers

Answer:

D

Step-by-step explanation:

7x3=21 and 3x2=6

21+6=27

D) The number of three point shots is 7 and the number of two points shots is 3.

What are Linear Equations?

Linear equations are equation involving one or more expressions including variables and constants and the variables are having no exponents or the exponent of the variable is 1.

Given that,

Mary scored a total of 27 points in a basketball game, all from 3-point shots and 2-point shots.

Let x be the number of 3-point shots and y be the number of 2-point shots.

3x + 2y = 27 [Equation 1]

The number of 3-point shots she made is 4 more than her 2-point shots.

x = y + 4 [Equation 2]

Substitute [Equation 2] in [Equation 1].

3(y + 4) + 2y = 27

3y + 12 + 2y = 27

5y = 15

y = 3

x = y + 4 = 3 + 4 = 7

Hence the option is D) 7 three-point shots and 3 two-point shots.

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Two bicycles are traveling along perpendicular roads. Bicycle A is traveling due east at 4 mi/hr, and bicycle B is travelling due north at 6 mi/hr. At noon, when bicycle A reaches the intersection, bicycle B is 9 mi away and moving toward the same intersection If t is the number of hours after noon, the bicycles are closest together when t isA. 0B. 27/26C. 9/5D. 3/2E. 14/13

Answers

Answer:

Step-by-step explanation:

Given

speed of cyclist A is [tex]v_a=4 mi/hr[/tex]

speed of cyclist B is [tex]v_b=6 mi/hr[/tex]

At noon cyclist B is 9 mi away

after noon Cyclist B will travel a distance of 6 t and cyclist A travel 4 t miles in t hr

Now distance of cyclist B from intersection is 9-6t

Distance of cyclist A from intersection is 4 t

let distance between them be z

[tex]z^2=(9-6t)^2+(4t)^2[/tex]

Differentiate z w.r.t time

[tex]2z\frac{\mathrm{d} z}{\mathrm{d} t}=2\times (9-6t)\times (-6)+2\times (4t)\times 4[/tex]

[tex]z\frac{\mathrm{d} z}{\mathrm{d} t}=(-6)(9-6t)+4(4t)[/tex]

[tex]\frac{\mathrm{d} z}{\mathrm{d} t}=\frac{16t+36t-54}{z}[/tex]

Put [tex]\frac{\mathrm{d} z}{\mathrm{d} t}\ to\ get\ maximum\ value\ of\ z[/tex]

therefore [tex]52t-54=0[/tex]

[tex]t=\frac{54}{52}[/tex]

[tex]t=\frac{27}{26} hr [/tex]

The set of integers is closed under the operation of addition.


A: Which equation illustrates this concept?


B: Which statement correctly explains this concept?


Select one answer for question A and one answer for question B.


A: 2+27=29

A: 34÷4=172

A: 1−3=−2

A: 2⋅6=12

B: The sum of the integers 2 and 27 is the integer 29, which demonstrates that integers are closed under addition.

B: The quotient of the integers 34 and 4 is the integer 172, which demonstrates that integers are closed under addition.

B: The difference of the integers 1 and 3 is not an integer, −2, which does not demonstrate that integers are closed under addition.

B: The product of the integers 2 and 6 is not an integer, 12, which does not demonstrate that integers are closed under addition.

Answers

Answer:

A: 2+27=29

B: The sum of the integers 2 and 27 is the integer 29, which demonstrates that integers are closed under addition.

Step-by-step explanation:

Since, closed property of addition for a set A is defined as,

∀ x, y ∈ A ⇒ x + y ∈ A,

Set of integer is closed under multiplication,

If Z represents the set of integer,

Then 2, 27 ∈ Z  ⇒ 2 + 27 = 29 ∈ Z,

Hence, the equation illustrates given statement,

2+27 = 29

The statement that correctly explains given statement,

The sum of the integers 2 and 27 is the integer 29, which demonstrates that integers are closed under addition.c

One container of Tums® costs 4.00 dollars. Each container has eighty 1.00 g tablets. Assume each Tums® is 40.0 percent CaCO₃ by mass. Using only Tums®, you are required to neutralize 0.500 L of 0.400 M HCl. How much does this cost? Assume you are able to purchase individual tablets. Express your answer in dollars.

Answers

Answer:

The total cost is 1.25 dollars.

Step-by-step explanation:      

The reaction between HCl and CaCO₃ is giving by:

2HCl(aq) + CaCO₃(s)   →   CaCl₂(aq) + CO₂(g) + H₂O(l) (1)

0.500L     M: 100.01g/mol        

0.400M

According to equation (1), 2 moles of HCl react with 1 mol of CaCO₃, so to neutralize HCl, we need the next amount of CaCO₃:

[tex] m CaCO_{3} = (\frac{1 \cdot mol HCl}{2}) \cdot M_{CaCO_{3}} = (\frac{0.500L \cdot 0.400 \frac {mol}{L}}{2}) \cdot 100.01 \frac{g}{mol} = 10.001 g [/tex]      

The CaCO₃ mass of each tablet is:

[tex] m CaCO_{3} = 1 g_{tablet} \cdot \frac{40g CaCO_{3}}{100g_{tablet}} = 0.4g [/tex]

Hence, the number of tablets that we need to neutralize the HCl is:

[tex] number_{tablets} = ( \frac{1 tablet}{0.4 g CaCO_{3}}) \cdot 10.001g CaCO_{3} = 25 [/tex]  

Finally, if every 80 tablets costs 4.00 dollars, 25 tablets will cost:

[tex] cost = (\frac {4 dollars}{80 tablets}) \cdot 25 tablets = 1.25 dollars [/tex]

So, the total cost to neutralize the HCl is 1.25 dollars.

I hope it helps you!

A paint manufacturer uses a machine to fill gallon cans with paint​ (1 galequals128 ​ounces). The manufacturer wants to estimate the mean volume of paint the machine is putting in the cans within 0.5 ounce. Assume the population of volumes is normally distributed.​(a) Determine the minimum sample size required to construct a 90​% confidence interval for the population mean. Assume the population standard deviation is 0.80 ounce.​(b) The sample mean is 127 ounces. With a sample size of 8​, a 90​% level of​ confidence, and a population standard deviation of 0.80 ​ounce, does it seem possible that the population mean could be exactly 128 ​ounces? Explain.

Answers

Answer:

a) To determine the minimum sample size we need to use the formula shown in the picture 1.

E is the margin of error, which is the distance from the limits to the middle (the mean) of the confidence interval. This means that we have to divide the range of the interval by 2 to find this distance.

E = 0.5/2 = 0.25

Now we apply the formula

n = (1.645*0.80/0.25)^2 = 27.7 = 28

The minimum sample size would be 28.

b) To answer the question we are going to make a 90% confidence interval. The formula is:

(μ - E, μ + E)

μ is the mean which is 127. The formula for E is shown in the picture.

E = 0.80*1.645/√8 = 0.47

(126.5, 127.5)

This means that the true mean is going to be contained in this interval 90% of the time. This is why it doesn't seem possible that the population mean is exactly 128.

(a) Minimum sample size needed for a 90% confidence interval is 7.

(b) With a sample mean of 127 ounces, 128 ounces seems unlikely for the population mean.

To solve this problem, we can use the formula for the confidence interval of the population mean:

[tex]\[ \text{Confidence Interval} = \text{Sample Mean} \pm Z \left( \frac{\text{Population Standard Deviation}}{\sqrt{\text{Sample Size}}} \right) \][/tex]

Where:

- Sample Mean = 127 ounces

- Population Standard Deviation = 0.80 ounce

- Z = Z-score corresponding to the desired confidence level

- Sample Size = n

(a) To determine the minimum sample size required for a 90% confidence interval:

We first need to find the Z-score corresponding to a 90% confidence level. We'll use a Z-table or a calculator. For a 90% confidence level, the Z-score is approximately 1.645.

[tex]\[ \text{Margin of Error} = Z \left( \frac{\text{Population Standard Deviation}}{\sqrt{\text{Sample Size}}} \right) \][/tex]

Given that the margin of error is 0.5 ounce, we can rearrange the formula to solve for the sample size:

[tex]\[ 0.5 = 1.645 \left( \frac{0.80}{\sqrt{n}} \right) \][/tex]

Solving for ( n ):

[tex]\[ \sqrt{n} = \frac{1.645 \times 0.80}{0.5} \][/tex]

[tex]\[ \sqrt{n} = 2.632 \][/tex]

[tex]\[ n = (2.632)^2 \][/tex]

[tex]\[ n \approx 6.92 \][/tex]

Since the sample size must be a whole number, we round up to the nearest whole number. Therefore, the minimum sample size required is 7.

(b) To determine if it's possible that the population mean could be exactly 128 ounces with a sample mean of 127 ounces, a sample size of 8, and a 90% confidence level:

[tex]\[ \text{Confidence Interval} = 127 \pm 1.645 \left( \frac{0.80}{\sqrt{8}} \right) \][/tex]

[tex]\[ \text{Confidence Interval} = 127 \pm 1.645 \left( \frac{0.80}{\sqrt{8}} \right) \][/tex]

[tex]\[ \text{Confidence Interval} = 127 \pm 1.645 \left( \frac{0.80}{2.828} \right) \][/tex]

[tex]\[ \text{Confidence Interval} = 127 \pm 1.645 \times 0.283 \][/tex]

[tex]\[ \text{Confidence Interval} = 127 \pm 0.466 \][/tex]

The confidence interval is ( (126.534, 127.466) ).

Since 128 ounces is not within the confidence interval, it seems unlikely that the population mean could be exactly 128 ounces.

i have a couple questions with my geometry homework which is due tomorrow, could someone try answering them? I've been trying to solve them for the past hour.

Answers

Answer:

  2.  100°              22.  7

  18.  6                  23.  9

  19.  8                  24.  65°

  20.  55°             25.  AB = (1/2)DF

  21.  6                 26.  AB ║ DF

Step-by-step explanation:

Please be aware that the triangle measurements shown for problems 18–20 and 22–24 cannot exist. In the first case, the angle is closer to 48.6° (not 35°), and in the second case, the angle is closer to 51.1°, not 25°. So, you have to take the numbers at face value and not think too deeply about them. (This state of affairs is all too common in geometry problems these days.)

_____

2. You have done yourself no favors by marking the drawing the way you have. Look again at the given conditions. You will find that x+2x must total a right angle, so x=30°. Angle P is the complement of 40°, so is 50°. Then the sum of x and angle P is 30° +50° = 80°, and the angle of interest is the supplement of that, 100°.

__

18–20. Perpendicular bisector NO means  ∆NOL ≅ ΔNOM. Corresponding parts have the same measures, and angle L is the complement of the marked angle.

__

21. ∆ODA ≅ ∆ODB by hypotenuse-angle congruence (HA), so corresponding parts are the same measure. DB = DA = 6.

__

22–24. ∆VPT ≅ ∆VPR by LL congruence, so corresponding measures are the same. Once again, the angle in question is the complement of the given angle.

__

25–26. You observe that A is the midpoint of DE, and B is the midpoint of FE, so AB is what is called a "midsegment." The features of a midsegment are that it is ...

half the length of the base (DF)parallel to the base

Just took pictures to make it easier.

Answers

Answer:

8. [tex]\displaystyle \frac{9[x + 5]}{x - 14}[/tex]

7. [tex]\displaystyle -\frac{2x - 1}{2[3x - 5]}[/tex]

6. [tex]\displaystyle \frac{2[x - 4]}{5[x + 3]}[/tex]

5. [tex]\displaystyle \frac{2x + 7}{x + 3}[/tex]

4. [tex]\displaystyle 3x^{-1}[/tex]

Step-by-step explanation:

All work is shown above from 8 − 4.

I am joyous to assist you anytime.

The Glee Club sold a total of 150 tickets to their spring concert. Student tickets cost $5.00 each and adult tickets cost $8.00 each. If they had $1,020 in ticket sales, how many adult tickets did they sell?

Answers

Answer: 60 student tickets were sold

90 adult tickets were sold

Step-by-step explanation:

Let x represent the total number of student tickets sold.

Let y represent the total number of adult tickets sold.

The Glee Club sold a total of 150 tickets to their spring concert. This means that

x + y = 150

x = 150 - y

Student tickets cost $5.00 each and adult tickets cost $8.00 each. If they had $1,020 in ticket sales,then,

5x + 8y = 1020 - - - - - -1

Substituting x = 150 - y into equation 1, it becomes

5(150 - y) + 8y = 1020

750 - 5y + 8y = 1020

- 5y + 8y = 1020 - 750

3y = 270

y = 270/3 = 90

x = 150 - 90 = 60

Farmer bob's square plot ofland is slowly eroding away. Worried about the future of his farm. Farmer Bob measures the rate of erosion and finds that the length of each side of his square plot is decreasing at the constant rate of 2 feet/year. If he currently owns 250,000 square feet of land, what is the current rate of change of the area of Farmer Bob's land?
a) Farmer bob is losing 2,000 square feet of land per year
b) losing 1,000,000 square feet of land per year
c) losing 1,000 square feet of land per year
d) losing 4 square feet of land per year

Answers

Answer:

Option A.

Step-by-step explanation:

Area of a square is

[tex]A=x^2[/tex]               .... (1)

where, x is side length.

The length of each side of his square plot is decreasing at the constant rate of 2 feet/year.

[tex]\dfrac{dx}{dt}=2[/tex]

It is given that bob currently owns 250,000 square feet of land.

Fist find the length of each side.

[tex]A=250000[/tex]

[tex]x^2=250000[/tex]

Taking square root on both sides.

[tex]x=500[/tex]

Differentiate with respect to t.

[tex]\dfrac{dA}{dt}=2x\dfrac{dx}{dt}[/tex]

Substitute x=500 and [tex]\frac{dx}{dt}=2[/tex] in the above equation.

[tex]\dfrac{dA}{dt}=2(500)(2)[/tex]

[tex]\dfrac{dA}{dt}=2000[/tex]

Farmer bob is losing 2,000 square feet of land per year.

Therefore, the correct option is A.

Let xij = gallons of component i used in gasoline j. Assume that we have two components and two types of gasoline. There are 8,000 gallons of component 1 available, and the demand gasoline types 1 and 2 are 11,000 and 14,000 gallons respectively. Write the supply constraint for component 1.
a) x21 + x22 = 8000
b) x12 + x22 = 8000
c) x11 + x12 = 8000

Answers

Answer:

c) x11 + x12 = 8000

Step-by-step explanation:

Xij = Gallons of the ith component used in the  jth Gasoline type

This invariably  tells us what component is in which gasoline type.

The gasoline types are:

Gasoline  1  = 11,000 gallons

Gasoline 2 = 14,000 gallons

Assuming two(2) components types:

Component 1

Component 2

The possible combinations Xij are :

                          Gasoline 1                     Gasoline 2

Component 1          X11                                X12

           

Component 2         X21                               X22

From the above , it is clear that the supply constraint for component 1 across the gasoline types is given by    X11  &  X12

Mathematically, since there are 8,000 gallons of Component 1, the supply constraint is given by:

X11 + X12 = 8000

Final answer:

The supply constraint for component 1, given the available gallons and the usage in two types of gasoline, is represented by the equation x11 + x12 = 8000.

Explanation:

The supply constraint for component 1 when formulating an equation that represents the total usage of component 1 in both types of gasoline should reflect the total availability of component 1. Since there are 8,000 gallons of component 1 available, the correct mathematical representation of the supply constraint for component 1 is:

x11 + x12 = 8000

This equation means that the sum of gallons of component 1 used in gasoline type 1 (x11) and gasoline type 2 (x12) must equal the total available gallons of component 1, which is 8,000 gallons.

Let X, Y , Z be three random variables which satisfy the following conditions: Var(X) = 4, Var(Y ) = 9, Var(Z) = 16. Cov(X, Y ) = −2, Cov(Z, X) = 3, and Y and Z are independent. Find: (a) Cov(X + 2Y, Y − Z). (b) Var(3X − Y ). (c) Var(X + Y + Z)

Answers

Answer:

13,57,31

Step-by-step explanation:

Given that X, Y , Z be three random variables which satisfy the following conditions:

Var(X) = 4, Var(Y ) = 9, Var(Z) = 16. Cov(X, Y ) = −2, Cov(Z, X) = 3,

Var(y,z) =0 since given as independent

To find

[tex]a) Cov (x+2y, y-z)\\ \\= cov (x,y) +cov (2y,y) -cov (x,z) -cov(2y,z)\\= cov (x,y) +2cov (y,y) -cov (x,z) -2cov(y,z)\\=-2+2 var(y) -3-0\\= -2+18-3\\=13[/tex]

b) [tex]Var(3X − Y ).\\= 9Var(x)+var(y) -6 covar (x,y)\\= 36 +9+12\\= 57[/tex]

c) Var(X + Y + Z)[tex]=Var(x) = Var(Y) +Var(z) +2cov (x,y) +2cov (y,z) +2cov (x,z)\\= 4+9+16+(-4) +6\\= 31[/tex]

Note:

Var(x+y) = var(x) + Var(Y) +2cov (x,y)

Var(x+2y) = Var(x) +4Var(y)+4cov (x,y)

Carmen received a $100 bill as a birthday gift. She bought a book online for $24.95. Then she bought a backpack for $39.75 at a variety store. How much money did she have left after making her purchases

Answers

Answer:35.3

Step-by-step explanation:

100-24.95-39.75=35.3

Final answer:

Carmen spent a total of $64.70 on a book and a backpack and had $35.30 left from her original $100 after her purchases.

Explanation:

To calculate how much money Carmen had left after making her purchases, we first need to add the cost of the book and the backpack to find the total amount spent. She spent $24.95 on the book and $39.75 on the backpack. Add these two amounts together to find the total spent:

Book: $24.95Backpack: $39.75Total spent: $24.95 + $39.75 = $64.70

Next, subtract the total spent from the original $100 bill:

Original amount: $100.00Total spent: $64.70Money left: $100.00 - $64.70 = $35.30

Therefore, Carmen has $35.30 left after her purchases.

If​ A, B, and C are the measures of the angles of any triangle and if​ a, b, and c are the lengths of the sides opposite the corresponding​ angles, then which of the following expressions does not represent the area of the​ triangle?
A. (1/2)bcsinA
B. (1/2)acsinB
C. (1/2)acsinA
D. (1/2)absinC

Answers

Answer:

C. (1/2)acsinA

Step-by-step explanation:

Given is that, A, B, and C are the measures of the angles of a triangle and a, b, and c are the lengths of the sides opposite the corresponding​ angles.

So, the expression that does not represent the area of the​ triangle is :

C. (1/2)acsinA

A certain company currently has how many employees?
(1) If 3 additional employees are hired by the company and all of the present employees remain, there will be at least 20 employees in the company.
(2) If no additional employees are hired by the company and 3 of the present employees resign, there will be fewer than 15 employees in the company.

Answers

Answer: The company currently has 17 employees

Step-by-step explanation:

Let X represent the number of current employees in the company

From the first information, it can be expressed mathematically as

X + 3 ≥ 20

X ≥ 20 - 3

X ≥ 17

From the second information, it can be expressed mathematically as

X - 3 < 15

X < 15 + 3

X < 18

From the above solutions, it can be deduced that

17 ≤ X < 18

The only number that fulfils this criteria is 17.

Therefore, X = 17

The graph of function f a shown. Use the zeros and the turning points of the graph to find the rule for f.​

Answers

Answer:

  f(x) = x(x +4)(x -3)

Step-by-step explanation:

Zeros at -4, 0, and 3 tell you the factorization is ...

  f(x) = a(x +4)(x)(x -3)

Then f(2) = a(6)(2)(-1) = -12a.

The graph shows f(2) = -12, so a=1. That makes the function rule:

  f(x) = x(x +4)(x -3)

__

If you want it multiplied out, it will be

  f(x) = x^3 +x^2 -12x

Final answer:

To find the rule for function f(x) using zeros and turning points, analyze the graph. In this case, with a horizontal line between 0 and 20, there are no zeros or turning points as the function doesn't cross the x-axis or change direction.

Explanation:

To find the rule for a function f(x) using its zeros and turning points, we analyze the graphical representation of the function. If the graph is a horizontal line, such as when f(x) = 20 for all 0 ≤ x ≤ 20, the function does not have any zeros or turning points within that interval, as it does not cross the x-axis nor does it change direction. Considering this particular function, we conclude that the graph is indeed a horizontal line with no turning points or zeros between x=0 and x=20.

In the general process of graphing, to illustrate the change in f(x) as x varies, we plot specific (x,y) data pairs and use these to determine trends. For functions that are not constant, like the one described above, zeros are the x-values where the function crosses the x-axis (f(x) = 0), and turning points are found where the slope of the function changes sign, which can be determined by examining the first and second derivatives of the function. However, in this scenario, the horizontal nature of the graph precludes the presence of such features.

1. In a survey sample of 83 respondents, about 30.1 percent of the sample work less than 40 hours per week. Calculate a 68 percent confidence interval for the proportion of persons who work less than 40 hours per week.

Answers

Answer:

A 68 percent confidence interval for the proportion of persons who work less than 40 hours per week is (0.251, 0.351), or equivalently (25.1%, 35.1%)

Step-by-step explanation:

We have a large sample size of n = 83 respondents. Let p be the true proportion of persons who work less than 40 hours per week. A point estimate of p is [tex]\hat{p} = 0.301[/tex] because about 30.1 percent of the sample work less than 40 hours per week. We can estimate the standard deviation of [tex]\hat{p}[/tex] as [tex]\sqrt{\hat{p}(1-\hat{p})/n}=\sqrt{0.301(1-0.301)/83} = 0.0503[/tex]. A [tex]100(1-\alpha)%[/tex] confidence interval is given by [tex]\hat{p}\pm z_{\alpha/2}\sqrt{\hat{p}(1-\hat{p})/n[/tex], then, a 68% confidence interval is [tex]0.301\pm z_{0.32/2}0.0503[/tex], i.e., [tex]0.301\pm (0.9944)(0.0503)[/tex], i.e., (0.251, 0.351). [tex]z_{0.16} = 0.9944[/tex] is the value that satisfies that there is an area of 0.16 above this and under the standard normal curve.

Final answer:

To calculate the 68 percent confidence interval for the proportion of persons working less than 40 hours per week from a sample of 83 respondents with a sample proportion of 30.1 percent, we use the formula for the confidence interval for a proportion. The resulting interval is approximately 25.06% to 35.14%.

Explanation:

To calculate a 68 percent confidence interval for the proportion of persons who work less than 40 hours per week from a sample of 83 respondents, where 30.1 percent work less than 40 hours, we use the formula for a confidence interval for a proportion:

In this formula:

p is the sample proportion (0.301 in this case).z* is the z-value corresponding to the desired confidence level (for 68 percent confidence, use the z-value corresponding to one standard deviation from the mean in a standard normal distribution, which is approximately 1).n is the sample size (83).

Plugging the values into the formula we get:

0.301±1*sqrt((0.301(0.699)/83))

Calculating the square root part, we have:

0.301±1*sqrt((0.301*0.699)/83)
= 0.301±1*sqrt(0.210699/83)
= 0.301±1*sqrt(0.002539)
= 0.301±1*0.05039
= 0.301±0.05039

The confidence interval is thus:

0.301-0.05039 to 0.301+0.05039
= 0.25061 to 0.35139

Hence, with a 68 percent confidence level, we can say that the true proportion of the population that works less than 40 hours per week is estimated to be between 25.06% and 35.14%.

Charles and Lisa were having a apple eating contest. They ate eighteen apples between the two of them. Lisa ate two more apples than Charles. How many apples did Lisa eat?

A.
6


B.
10


C.
12


D.
15


Answers

Answer:10

Step-by-step explanation:

ok they are 18 apples

and they ate them

one ate two more thatn the other one

so we can say that one of them is x(charles)

and the one who ate two more is x+2(lisa)

so we get this

x+x+2=18

2x+2=18

2x+18-2

2x=16

x=8

so charles ate 8

and lisa 10(8+2)

Answer:

1000% its 10

Step-by-step explanation:

Giving a test to a group of students, the grades and gender are summarized below A B C Total Male 6 18 3 27 Female 13 20 12 45 Total 19 38 15 72 If one student is chosen at random,
If one student is chosen at random,
Find the probability that the student got a B:
Find the probability that the student was female AND got a "C":
Find the probability that the student was female OR got an "B":
If one student is chosen at random, find the probability that the student got a 'B' GIVEN they are male:

Answers

Answer:

P(Got a B) = [tex]\frac{19}{36}[/tex]

P(Female AND got a C) = [tex]\frac{1}{6}[/tex]

P(Female or Got an B =  [tex]\frac{7}{8}[/tex]

P(got a 'B' GIVEN they are male) =  [tex]\frac{9}{19}[/tex]

Step-by-step explanation:

Given:

       A B C Total

Male 6 18 3 27

Female 13 20 12 45

Total 19 38 15 72

We know that the probability = The number of favorable outcomes ÷ The total number of possible outcomes.

Total number = 72

1) If one student is chosen at random, Find the probability that the student got a B:

Got B = 38

P(Got a B) = [tex]\frac{38}{72}[/tex]

Simplifying the above probability, we get

P(Got a B) = [tex]\frac{19}{36}[/tex]

2) Find the probability that the student was female AND got a "C":

Female AND got a C = 12

P(Female AND got a C ) = [tex]\frac{12}{72}[/tex]

Simplifying the above probability, we get

P(Female AND got a C) = [tex]\frac{1}{6}[/tex]

3) Find the probability that the student was female OR got an "B":

Female OR got an B = Total number of female + students got B - Female got 20

= 45 + 38 - 20

= 73 - 20

= 63

P(Female OR got an B ) =  [tex]\frac{63}{72}[/tex]

P(Female or Got an B =  [tex]\frac{7}{8}[/tex]

4) If one student is chosen at random, find the probability that the student got a 'B' GIVEN they are male:

Total number of students who got B  = 38

Student got a B given they are male = 18

P(got a 'B' GIVEN they are male) =  [tex]\frac{18}{38}[/tex]

P(got a 'B' GIVEN they are male) =  [tex]\frac{9}{19}[/tex]

Final answer:

The probability study includes: Probability of a student getting 'B' is 0.528; a student being female and getting 'C' is 0.167; being female or getting 'B' is 0.875 and the probability of a male getting 'B' is 0.667.

Explanation:

To answer these questions, we need to use the concept of probability in mathematics. Probability is calculated by dividing the number of desired outcomes by the total number of outcomes.

For the probability that the student got a 'B', we divide the total number of 'B' grades (38) by the total number of students (72). This results in a probability of 38/72 or 0.528. The probability that the student was female AND got a 'C': we have 12 students fitting this description, and a total of 72 students. So, the probability would be 12/72 or 0.167. The probability that the student was female OR got a 'B', we add the number of females (45) to the number of B's (38), subtract the overlap (girls who got B's, 20). That leaves us with 45 + 38 - 20 = 63. We divide this by total students, 72, for a probability of 63/72 or 0.875. The probability that the student got a 'B' GIVEN they are male: Here we focus only on the boys, of whom there are 27. 18 of these received a 'B', giving us a probability of 18/27 or 0.667.

Learn more about Probability here:

https://brainly.com/question/32117953

#SPJ3

Paper depot is swnding out 28 trucks to deliver paper to customers today. Each truck is being loaded with 3 cases of paper. 283 of all the cases are plain white paper. How many cases of all types of paper will be delivered today?

Answers

Answer:

84 cases

Step-by-step explanation:

Given that:

Number of trucks: 28

Paper cases each truck can load = 3

Total cases of white paper = 283

So the cases delivered will be = 28 *3 = 84 cases will be delivered today

i hope it will help you!

An insurance agent receives 16% commission on every premium paid. how much commission is paid on a policy with a premium of $497.69? $31.10 $79.63 $311.06 $796.30

Answers

Answer:

  $79.63

Step-by-step explanation:

You can figure this by estimating. 16% is a little less than 20%, which is 1/5. $497.69 is almost $500. So, 1/5 of that is almost $100, and a little less than that is about $80. The closest answer choice is $79.63.

__

If you want to figure it exactly, you can do the multiplication ...

  16% of $497.69 = 0.16 × $497.69 = $79.6304 ≈ $79.63

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