The recommended dose for a brand nicotine patch is one 21-mg dose per day for 6 weeks, followed by 14 mg per day for 2 weeks, and then 7 mg per day for 2 more weeks. What total quantity, in grams, would a patient receive during this course of treatment?

Answer:

  A ∩ B: 1. The set of all elements of 'Uʻ that are elements of both 'A' and 'B'.

  A ∪ B: 2. The set of all elements of 'U' that are elements of either 'A' or 'B'.

Step-by-step explanation:

1. The "intersection" symbol (∩) signifies the members that are in both sets. For example, {1, 2} ∩ {1, 3} = {1}.

__

2. The "union" symbol (∪) signifies the members that are in either set. For example, {1, 2} ∪ {1, 3} = {1, 2, 3}.

Answer:

$925.20

Step-by-step explanation:

Loan Amount, P = $19,500

Rate of interest, r = 3.9%

Time, t = 6 years

Payment mode, n = Quarterly (4)

payment to amortize, EMI = ?

Formula: [tex]EMI=\dfrac{P\cdot \frac{r}{n}}{1-(1+\frac{r}{n})^{-n\cdot t}}[/tex]

where,

n = 4 , Rate of interest , r = 0.039

Put the values into formula

[tex]EMI=\dfrac{19500\cdot \frac{0.039}{4}}{1-(1+\frac{0.039}{4})^{-4\cdot 6}}[/tex]

[tex]EMI=915.20[/tex]

Hence, The payment to amortize the debt is $915.20

Answer:

[tex]\frac{(x-8)^2}{8^2}-\frac{(y-0)^2}{6^2}=1[/tex]

Step-by-step explanation:

∵ The equation of a hyperbola along x-axis is,

[tex]\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1[/tex]

Where,

(h, k) is the center,

a = distance of vertex from the center,

b² = c² - a² ( c = distance of focus from the center ),

Here,

vertices are (0,0) and (16,0), ( i.e. hyperbola is along the x-axis )

So, the center of the hyperbola = midpoint of the vertices (0,0) and (16,0)

[tex]=(\frac{0+16}{2}, \frac{0+0}{2})[/tex]

= (8,0)

Thus, the distance of the vertex from the center, a = 8 unit

Now,  foci are (18,0) and (-2,0).

Also, the distance of the focus from the center, c =  18 - 8 = 10 units,

[tex]\implies b^2=10^2-8^2=100-64=36\implies b = 6[/tex]

( Note : b ≠ -6 because distance can not be negative )

Hence, the equation of the required hyperbola would be,

[tex]\frac{(x-8)^2}{8^2}-\frac{(y-0)^2}{6^2}=1[/tex]

Answer:[tex]a = \frac{F}{m}[/tex]

[tex]v = \frac{m}{d}[/tex]

[tex]t = \frac{A - P}{Pr}[/tex]

[tex]h = \frac{2A}{a + b}[/tex]

[tex]W = \frac{P - 2L}{2}[/tex]

[tex]y = 2m - x[/tex]

[tex]y = -1.5x + 4[/tex]

[tex]t = \frac{v - u}{a}[/tex]

Step-by-step explanation:

[tex]F = ma[/tex]

[tex]\frac{F}{m} = \frac{ma}{m}[/tex]

[tex]\frac{F}{m} = a[/tex]

[tex]d = \frac{m}{v}[/tex]

[tex]vd = m[/tex]

[tex]\frac{vd}{d} = \frac{m}{d}[/tex]

[tex]v = \frac{m}{d}[/tex]

[tex]A = P + Prt[/tex]

[tex]A - P = Prt[/tex]

[tex]\frac{A - P}{Pr} = \frac{Prt}{Pr}[/tex]

[tex]\frac{A - P}{Pr} = t[/tex]

[tex]A = \frac{1}{2}h(a + b)[/tex]

[tex]2A = h(a + b)[/tex]

[tex]\frac{2A}{a + b} = \frac{h(a + b)}{a + b}[/tex]

[tex]\frac{2A}{a + b} = h[/tex]

[tex]P = 2(L + W)[/tex]

[tex]P = 2(L) + 2(W)[/tex]

[tex]P = 2L + 2W[/tex]

[tex]P - 2L = 2W[/tex]

[tex]\frac{P - 2L}{2} = \frac{2W}{2}[/tex]

[tex]\frac{P - 2L}{2} = W[/tex]

[tex]m = \frac{x + y}{2}\\2m = x + y\\2m - x = y[/tex]

[tex]3x + 2y = 8\\2y = -3x + 8\\\frac{2y}{2} = \frac{-3x + 8}{2}\\y = -1.5x + 4[/tex]

[tex]a = \frac{v - u}{t}\\at = v - u\\\frac{at}{a} = \frac{v - u}{a}\\t = \frac{v - u}{a}[/tex]

Answer:

[tex]\frac{1333}{2000}[/tex]

Step-by-step explanation:

We want to compute the probabily of being flipping coin1 in the third day. Observe that in day zero (the day were the coin to be flipped is chosen randomly with equal probability to be coin1 or coin2), day 1 and day 2 we will flip coin1 or coin2. So, there are 8 possible scenarios to consider:

[tex]S1=(1,1,1,1)\\S2=(1,1,2,1)\\S3=(1,2,1,1)\\S4=(1,2,2,1)\\S5=(2,1,1,1)\\S6=(2,1,2,1)\\S7=(2,2,1,1)\\S8=(2,2,2,1)[/tex]

Where S1 is the scenario where we flip coin1 everyday. S2 is the scenario where we flip coin1 the day zero and first day, coin2 the second day, and again coin1 the third day. S3,...,S8 are defined the same.

Observe that the probability to flip coin1 the third day is equal to the sum of [tex]P(S1)+P(S2)+...+P(S8).[/tex] To compute this probabilities we will define:

[tex]P(1,1)=[/tex]Probability to flip coin1 one day given that coin1 was flipped the day before.

[tex]P(1,2)=[/tex]Probability to flip coin2 one day given that coin1 was flipped the day before.

[tex]P(2,1)=[/tex]Probability to flip coin1 one day given that coin2 was flipped the day before.

[tex]P(2,2)=[/tex]Probability to flip coin2 one day given that coin2 was flipped the day before.

Then, using the question information, we can conclude that

[tex]P(1,1)=0.7, P(1,2)=0.3, P(2,1)=0.6, P(2,2)=0.4[/tex]

With this we can compute P(S1),...,P(S8) as follows:

[tex]P(S1)=\frac{1}{2}P(1,1)*P(1,1)*P(1,1)=\frac{1}{2}*(\frac{7}{10})^3=\frac{343}{2000}\\\\P(S2)=\frac{1}{2}P(1,1)*P(1,2)*P(2,1)=\frac{1}{2}*\frac{7}{10}*\frac{3}{10}*\frac{6}{10}=\frac{126}{2000}\\\\P(S3)=\frac{1}{2}P(1,2)*P(2,1)*P(1,1)=\frac{1}{2}*\frac{3}{10}*\frac{6}{10}*\frac{7}{10}=\frac{126}{2000}\\\\P(S4)=\frac{1}{2}P(1,2)*P(2,2)*P(2,1)=\frac{1}{2}*\frac{3}{10}*\frac{4}{10}*\frac{6}{10}=\frac{72}{2000}\\\\[/tex]

[tex]P(S5)=\frac{1}{2}P(2,1)*P(1,1)*P(1,1)=\frac{1}{2}*\frac{6}{10}*\frac{7}{10}*\frac{7}{10}=\frac{294}{2000}\\\\P(S6)=\frac{1}{2}P(2,1)*P(1,2)*P(2,1)=\frac{1}{2}*\frac{6}{10}*\frac{3}{10}*\frac{6}{10}=\frac{108}{2000}\\\\P(S7)=\frac{1}{2}P(2,2)*P(2,1)*P(1,1)=\frac{1}{2}*\frac{4}{10}*\frac{6}{10}*\frac{7}{10}=\frac{168}{2000}\\\\P(S8)=\frac{1}{2}P(2,2)*P(2,2)*P(2,1)=\frac{1}{2}*\frac{4}{10}*\frac{4}{10}*\frac{6}{10}=\frac{96}{2000}\\\\[/tex]

Finally, the probability to flip coin1 the third day is

[tex]P(S1)+...+P(S8)=\frac{1333}{2000}[/tex]

The probability that the coin flipped on the 3rd day after the initial flip is coin 1 is 65%.

To determine the probability that the coin flipped on the 3rd day after the initial flip is coin 1, let's analyze the scenario:

There is a 0.5 chance that we start with either coin 1 or coin 2 on the first day.

If we start with coin 1 and flip heads (with probability 0.7), we will flip coin 1 again on the second day.

If we start with coin 1 and flip tails (with probability 0.3), we will flip coin 2 on the second day.

If we start with coin 2 and flip heads (with probability 0.6), we will flip coin 1 on the second day.

If we start with coin 2 and flip tails (with probability 0.4), we will flip coin 2 on the second day.

To get to coin 1 on the third day, we have the following cases:

Start with coin 1, flip heads (0.5*0.7).

Start with coin 2, flip heads (0.5*0.6).

The total probability of flipping coin 1 on the third day is the sum of the probabilities of these two independent events: (0.5*0.7) + (0.5*0.6) = 0.35 + 0.3 = 0.65 or 65%.

Answer: 26 items

Step-by-step explanation:

Let x denotes the last year's output.

Given : A company has determined that it must increase production of a certain line of goods by 112 times last years production.

The new output will be 2885 items.

According to the above statement we have the following equation :-

[tex]112x=2885[/tex]

Divide both sides by 112, we get

[tex]x=25.7589285714\approx26[/tex]

Hence, the  last year's output =26 items

Answer:

The limit of this function does not exist.

Step-by-step explanation:

[tex]\lim_{x \to 3} f(x)[/tex]

[tex]f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.[/tex]

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

[tex]\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L[/tex]

and the limit does not exist if

[tex]\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)[/tex]

Evaluate the one-sided limits.

The left-hand limit

[tex]\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0[/tex]

The right-hand limit

[tex]\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6[/tex]

Because the limits are not the same the limit does not exist.

Answer:

☑ 30y²

☑ 30y² + x

Step-by-step explanation:

Polynomials contain indeterminates [variables] and operation performances, non-including negative exponents, fractional exponents, etcetera.

I am joyous to assist you anytime.

Answer:

the unpaid balance after the 5 years will be 125400.

Step-by-step explanation:

Given,

Principal amount, P = 190,000

rate,r = 3%

total time,t = 25 years

So, the total interest after 25 years will be,

[tex]I\ =\ \dfrac{P\times r\times t}{100}[/tex]

   [tex]=\ \dfrac{190,000\times 3\times 25}{100}[/tex]

    = 142500

amount will be paid in 3 years with same interest rate can be given by

[tex]I_p\ =\ \dfrac{P\times r\times t}{100}[/tex]

       [tex]=\ \dfrac{190,000\times 3\times 3}{100}[/tex]

       = 17100

So, the amount of interest to be paid= 142500 - 17100

                                                             = 125400

so, the unpaid amount of interest after the 5 years will be 125400.

Answer:

The answer is: There are only 143034 books left after the students return to their classroom

Step-by-step explanation:

Lets call X= Number of books left in the library after the students return to their classroom.

B=Total of Books in the library

S=Total of books taken by the 3rd grade students

If each student  of the 3rd grage class take 2 books, the total of book taken by the 3rd grade students would be:

S=2 books per student * Total of students of the 3rdgrade

S=2*21=42

Then we must substract Total of Books in the library minus Total of books taken by the 3rd grade students. That would be:

X=B-S

X=143076-42

X=143034

I hope that this answer will help you

Answer: 72

Step-by-step explanation:

Given : An experiment has 3 stages: A, B, and C.

If stage A has 6 outcomes, stage B has 4 outcomes, and stage C has 3 outcomes.

Then, by using the fundamental principle of counting (Total outcomes= product of all outcomes of each stage ) , we have

The number of outcomes the entire experiment have:-

[tex]6\times4\times3=72[/tex]

Hence, the number of outcomes the entire experiment =72

Final answer:

To find the total number of outcomes for an experiment with 3 stages having 6, 4, and 3 outcomes respectively, you multiply the outcomes of each stage together, resulting in 6 × 4 × 3 = 72 possible outcomes.

Explanation:

To determine how many outcomes the entire experiment has when an experiment has stages A, B, and C with different numbers of outcomes, you multiply the number of outcomes for each stage. Stage A has 6 outcomes, stage B has 4 outcomes, and stage C has 3 outcomes. Therefore, the total number of outcomes for the entire experiment is calculated as follows:

Stage A outcomes: 6

Stage B outcomes: 4

Stage C outcomes: 3

Multiply the outcomes of each stage:

Total outcomes = 6 (Stage A) × 4 (Stage B) × 3 (Stage C) = 72 possible outcomes.

This is similar to how the sample space is determined in other contexts, such as flipping a coin and rolling a die, where you would also multiply the number of outcomes to get the size of the sample space.

Answer:

Step-by-step explanation:

A has one red and blue marble and B has one red and blue marble.

Hence selecting one marble is equally likely with prob = 0.5

Since A and B are independent the joint event would be product of probabilities.

Let A be the amount A wins.

If each selects one, the sample space would be

             (R,R)  (R,B)  (B,R) (B,B)

Prob     0.25  0.25  0.25  0.25

A              3       -2     -2       1

E(A)      0.75   -0.5    -0.5   0.25   =    0

The game is a fair game with equal expected values for A and B.

It does not matter whether to be A or B

The game described is fair, as both A and B have an expected value of $1. This is calculated using the probability of each outcome times its respective payoff. There is no advantage in being either A or B.

The marble game presented in the question involves probability and expectation of winnings. First, we must figure out the possible outcomes. There are four possibilities: (1) both A and B present red marbles, (2) both present blue marbles, (3) A presents red and B presents blue, and (4) A presents blue and B presents red.

When calculating the expected payoff for each player, we assume that each possibility carries an equal weight, as the question doesn't offer any bias towards a certain color. Therefore, the expected payoff (E) for each player is calculated by adding the product of each possible payout and its probability. For A, [tex]E(A) = (1/4)*$3 + (1/4)*$1 + (1/4)*$0 + (1/4)*$0 = $1.\\ For B, E(B) = (1/4)*$0 + (1/4)*$0 + (1/4)*$2 + (1/4)*$2 = $1.[/tex]

Given these calculations, we can see that the expected value of the game is equal for A and B, hence it doesn't matter who is A and who is B.

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Answer:  5

Step-by-step explanation:

Given : Jerome has two bags of different candies, one with 15 pieces of candy and one with 20 pieces.

Every prize will have one kind of candy, the same number of pieces.

Then to find the greatest number of pieces of candies possible in each price , we need to find the greatest common factor of 15 and 20.

Prime factorization of 15 and 20 :-

[tex]15=3\times5\\\\20=2\times2\times5[/tex]

∴ Greatest common factor of 15 and 20 = 5

Hence , the greatest number of pieces of candies possible in each prize = 5

Answer:

False.

Step-by-step explanation:

Two angles are complementary when added up, they give a result of 90°.

So, to this question to be true we have to do:

Angle 1 + Angle 2 = 90

But if we resolve 56° + 124° = 180, so this means that this question is false, as the addition of both angles doesn't have a result of 90°.

Answer:

3gallons (gal) = 11.35 liters

Step-by-step explanation:

This can be solved as a rule of three problem.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

Unit conversion problems, like this one, is an example of a direct relationship between measures.

Each gallon has 3.78L. So

1 gallon - 3.78L

3 gallons - xL

[tex]x = 3*3.78[/tex]

[tex]x = 11.35[/tex] liters

3gallons (gal) = 11.35 liters

Answer:

According to the Law of Absorption, these 2 expressions are equivalent:

p ∨ (p ∧ q) = p

Truth Table:

(see the image attached)

Step-by-step explanation:

To construct the Truth Table you can consider the 4 possible combinations of states that p and q could have, that is

1. p=T, q=T

2. p=T, q=F

3. p=F, q=T

4. p=F, q=F

Then you can calculate p ∨ (p ∧ q) = p for each combination

1. T ∨ (T ∧ T) = T

2. T ∨ (T ∧ F) = T

3. F ∨ (F ∧ T) = F

4. F ∨ (F ∧ F) = F

You can see that the previous values are the same states that p has, you can also see it in the table attached.

Answer:

The number of all possible subsets of D is 8.

Step-by-step explanation:

Consider the provided set D={c,a,t}

The subset of D contains no elements: {  }

The subset of D contains one element each: {c} {a} {t}

The subset of D contains two elements each: {c, a} {a, t} {c, t}

The subset of D contains three elements: {c, a, t)

Hence, all possible subsets of D are { }, {c}, {a}, {t}, {c, a}, {a, t}, {c, t}, {c, a, t}

Therefore, number of all possible subsets of D is 8.

Or we can use the formula:

The number of subsets of the set is [tex]2^n[/tex] If the set contains ‘n’ elements.

There are 3 elements in the provided set, thus use the above formula as shown:

2³=8

Hence, the number of all possible subsets of D is 8.

Answer:

Step-by-step explanation:

The average obtained at the end of the course will be:

[tex]\frac{85+78+84+x}{4} = av[/tex]

Where x is the grade obtained in the final examination and av is the final average. To obtain an A, av has to be at least 90, av≥90, and to obtain an B, av has to be at least 80, av≥80

So, if we get 100 on the final average:

x = 100,

av = (85+78+84+100)/4 = 86,75 and  86,75∠90.

Answer: No, the higher grade obtained would be 86,75.

To earn a B, av≥80:

[tex]av= \frac{85+78+84+x}{4 \ }\geq  80\\ \frac{247+x}{4}\geq80   \\247+x\geq 80*4\\ x\geq 320-247\\ x\geq 73[/tex]

Answer: I must have a 73 or MORE to earn a B in the course

Answer:

  16.4 million viewers

Step-by-step explanation:

The number of viewers increased by 8 million from 10 to 18 million when the number of ads increased by 10 ads from 15 to 25. If 23 ads are run, that represents an increase of 8 ads from 15, so we expect 8/10 of the increase in viewers.

  8/10 × 8 million = 6.4 million

The number we expect with 23 ads is 6.4 million more viewers than 10 million viewers, so is 16.4 million.

_____

Alternate solution

We can write a linear equation in 2-point form for the number of viewers expected for a given number of ads:

  y = (18 -10)/(25 -15)(x -15) +10

  y = (8/10)(x -15) +10

  y = 0.8x -2 . . . . . million viewers for x ads

For 23 ads, this gives ...

  y = 0.8×23 -2 = 18.4 -2 = 16.4 . . . . million viewers, as above

_____

Comment on 8/10

I consider it coincidence that the number 23 is 8/10 of the difference between 25 and 15, and the slope of the line is 8/10. The point we're trying to interpolate has no relationship to the slope of the line, and vice versa.

Linear interpolation illustrates the use of linear equation of several points

The number of viewers is 16.4 million, if a 23 one-minute ads runs on Friday.

Linear interpolation is represented as:

[tex]\frac{y_2 - y_1}{x_2 - x_1} = \frac{y - y_1}{x - x_1}[/tex]

Let:

[tex]x \to[/tex] Time

[tex]y \to[/tex] Viewers

So, we have:

[tex](x_1,y_1) = (15,10m)[/tex]

[tex](x_2,y_2) = (25,18m)[/tex]

[tex](x,y) = (23,y)[/tex]

Substitute the above points in:

[tex]\frac{y_2 - y_1}{x_2 - x_1} = \frac{y - y_1}{x - x_1}[/tex]

So, we have:

[tex]\frac{y_2 - y_1}{x_2 - x_1} = \frac{y - y_1}{x - x_1}[/tex]

[tex]\frac{18m - 10m}{25 -15} = \frac{y - 10m}{23 -15}[/tex]

[tex]\frac{8m}{10} = \frac{y - 10m}{8}[/tex]

Multiply both sides by 8

[tex]\frac{64m}{10} = y - 10m[/tex]

[tex]6.4m = y - 10m[/tex]

Collect like terms

[tex]y =10m + 6.4m[/tex]

[tex]y =16.4m[/tex]

Hence, the number of viewers is 16.4 million, if a 23 one-minute ads runs on Friday.

Read more about linear interpolation at:

https://brainly.com/question/4248868

Answer:

29 is answer.

Step-by-step explanation:

Given that the function​ s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237.

To find average velocity of the object over the interval of time [1,3]

We know that derivative of s is velocity and antiderivative of velocity is position vector .

Since moving along a line equation of s is

use two point formula

[tex]\frac{s-150}{237-150} =\frac{t-2}{5-2} \\s=29t-58+150\\s=29t+92[/tex] gives the position at time t.

Average velocity in interval (1,3)

=[tex]\frac{1}{3-1} (s(3)-s(1))\\=\frac{1}{2} [87+58-29-58]\\=29[/tex]

The average velocity of the object over the interval [1, 3] is 43.5 units of distance per unit of time.

The average velocity of an object over an interval of time is found by dividing the change in position by the change in time. In this case, we want to find the average velocity of the object over the interval [1, 3].

To do this, we first need to find the change in position during this interval. Given that s(2) = 150 and s(5) = 237, we can calculate the change in position as follows:

s(3) - s(1) = (s(5) - s(3)) + (s(3) - s(1))

Therefore, the average velocity is (s(3) - s(1)) / (3 - 1). By substituting the given values, we find that the average velocity is (237 - 150) / (3 - 1) = 87 / 2 = 43.5 units of distance per unit of time.

Answer:

150 units;

Maximum revenue: $62,500.

Step-by-step explanation:

We have been given that a company’s total revenue from manufacturing and selling x units of their product is given by [tex]y=-3x^2+900x-5,000[/tex]. We are asked to find the number of units sold that will maximize the revenue.

We can see that our given equation in a downward opening parabola as leading coefficient is negative.

We also know that maximum point of a downward opening parabola is ts vertex.

To find the number of units sold to maximize the revenue, we need to figure our x-coordinate of vertex.

We will use formula [tex]\frac{-b}{2a}[/tex] to find x-coordinate of vertex.

[tex]\frac{-900}{2(-3)}[/tex]

[tex]\frac{-900}{-6}[/tex]

[tex]150[/tex]

Therefore, 150 units should be sold in order to maximize revenue.

To find the maximum revenue, we will substitute [tex]x=150[/tex] in our given formula.

[tex]y=-3(150)^2+900(150)-5,000[/tex]

[tex]y=-3*22,500+135,000-5,000[/tex]

[tex]y=-67,500+135,000-5,000[/tex]

[tex]y=62,500[/tex]

Therefore, the maximum revenue would be $62,500.

Answer:

Part (A) True

Part (B) False

Part (C) True

Step-by-step explanation:

Consider the provided information.

If both the statements are either true or false then the biconditionals are true. Otherwise biconditionals are false.

Part (A) 1 + 1 = 3 if and only if monkeys can fly.

Consider the first statement: 1+1=3 (This is a False statement)

Consider the second statement: "monkeys can fly"  (This is also a False statement)

True: First statement is false and the second statement is also false, Thus, making the biconditional true.

Part (B) If birds can fly, then 1 + 1 = 3.

Consider the first statement: "birds can fly" (This is true statement)

Consider the second statement: 1 + 1 = 3 (This is a False statement)

False: First statement is true, but second statement is false, making everything false.

Part (C) If 1 + 1= 3, then pigs can fly.

Consider the first statement: 1+1=3 (This is a False statement)

Consider the second statement: "pigs can fly"  (This is also a False statement)

True: First statement is false and the second statement is also false, Thus, making the biconditional true.

Answer:

x1= 1

Step-by-step explanation:

The Cramer's rule say that x1=[tex]\frac{det(A1)}{det(A)}[/tex] where A1 is the matrix A change the column 1 by the vector b.

Then A1= [tex]\left[\begin{array}{cccc}31&6&-3&20\\2&2&-5&-7\\21&2&7&20\\11& 2&-11&-4\end{array}\right][/tex].

Using Octave we have that  det(A1)=-3840 and det(A)=-3840.

Then x1=[tex]\frac{-3840}{-3840}=1[/tex].

Answer:

a) must be met

Step-by-step explanation:

We have two conditions:

a) For every [tex]b\in B[/tex] and [tex]\epsilon>0[/tex], there exists [tex]a\in A[/tex], such that [tex]a<b+\epsilon[/tex].

b) There exists [tex]a\in A[/tex] and [tex]b\in B[/tex] such that  [tex]a<b[/tex].

We will prove that conditon a) is equivalent to [tex]inf(A)\leq inf(B)[/tex]

If a) is not satisfied, then it would exist [tex]b\in B[/tex] and [tex]\epsilon >0[/tex] such that, for every [tex]a\in A[/tex], [tex]a\geq b+\epsilon[/tex]. This implies that [tex]b+\epsilon[/tex] is a lower bound for A and in consequence

[tex]inf(A)\geq b+\epsilon > b\geq inf(B)[/tex]

Then, [tex]inf(A) \leq inf(B)[/tex] implies a).

If [tex]inf(A) \leq inf(B)[/tex] is not satisfied then, [tex]inf(A) > inf(B)[/tex] and in consequence exists [tex]b\inB[/tex] such that [tex]b-inf(A)=\epsilon >0[/tex]. Then [tex]b-\epsilon=inf(A)[/tex] and, for every [tex]a\in A[/tex],

[tex]b-\epsilon =inf(A)\leq a[/tex].

So, a) is not satisfied.

In conclusion, a) is equivalent to [tex]inf(A)\leq inf(B)[/tex]

Finally, observe that condition b) is not an appropiate condition to determine if [tex]inf(A)\leq inf(B)[/tex] or not. For example:

Answer:

D. $105

Step-by-step explanation:

Use definition:

[tex]\text{Average of }n\text{ numbers}=\dfrac{\text{The sum of }n\text{ numbers}}{n}[/tex]

The average wage for 15 consecutive days is $91, then by definition

[tex]\$91=\dfrac{\text{The sum of wages for 15 days}}{15}\Rightarrow \\ \\\text{The sum of wages for 15 days}=\$91\cdot 15=\$1,365[/tex]

The average wage for first 7 consecutive days is $87, then by definition

[tex]\$87=\dfrac{\text{The sum of wages for first 7 days}}{7}\Rightarrow \\ \\\text{The sum of wages for first 7 days}=\$87\cdot 7=\$609[/tex]

The average wage for last 7 consecutive days is $93, then by definition

[tex]\$93=\dfrac{\text{The sum of wages for last 7 days}}{7}\Rightarrow \\ \\\text{The sum of wages for last 7 days}=\$93\cdot 7=\$651[/tex]

Now,

[tex]\text{The sum of wages for 15 days}=\text{The sum of wages for first 7 days }+\\ \\+\text{ The wage for 8th day}+\text{The sum of wages for last 7 days}\\ \\\$1,365=\$609+\text{ The wage for 8th day}+\$651\\ \\\text{ The wage for 8th day}=\$1,365-\$609-\$651=\$105[/tex]

The given sequence :  0,4,18,48,100,180,......

We can write the terms of the sequence as :

[tex]\text{Ist term }:a_1=1(1^2-1)=0\\\\\text{IInd term }: a_2=2^2(2-1)=4(2-1)=4\\\\\text{IIIrd term }:a_3=3^2(3-1)=9(2)=18\\\\\text{IVth term }:a_4=4^2(4-1)=(16)(3)=48\\\\\text{Vth term }:a_5=5^2(5-1)=25(4)=100\\\\\text{VIth term }:a_6=6^2(6-1)=36(5)=180[/tex]

From the above presentation of the terms, the explicit formula in terms of n for the nth term will be :-

[tex]a_n=n^2(n-1)[/tex]

Put n= 7 , we get

[tex]a_7=7^2(7-1)=49(6)=294[/tex]

Therefore, the seventh term of the given sequence = 294

Answer:

The scale factor used to go from P to Q is 1/4

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If two figures are similar, then the ratio of its areas i equal to the scale factor squared

Let

z ----> the scale factor

x -----> area of polygon Q

y -----> area of polygon P

[tex]z^{2}=\frac{x}{y}[/tex]

we have

[tex]y=72\ units^2[/tex]

Find the area of polygon Q

Divide the the area of polygon Q in two triangles and three squares

The area of the polygon Q is equal to the area of two triangles plus the area of three squares

see the attached figure N 2

Find the area of triangle 1

[tex]A=(1/2)(1)(2)=1\ units^2[/tex]

Find the area of three squares (A2,A3 and A4)

[tex]A=3(1)^2=3\ units^2[/tex]

Find the area of triangle 5

[tex]A=(1/2)(1)(1)=0.5\ units^2[/tex]

The area of polygon Q is

[tex]x=1+3+0.5=4.5\ units^2[/tex]

Find the scale factor

[tex]z^{2}=\frac{x}{y}[/tex]

we have

[tex]y=72\ units^2[/tex]

[tex]x=4.5\ units^2[/tex]

substitute and solve for z

[tex]z^{2}=\frac{4.5}{72}[/tex]

[tex]z^{2}=\frac{1}{16}[/tex]

square root both sides

[tex]z=\frac{1}{4}[/tex]

therefore

The scale factor used to go from P to Q is 1/4

The scaled factor did Diego used to go from P to Q is 1/4.

Given

The area of polygon P is 72 square units.

If two figures are similar, then the ratio of its areas is equal to the scale factor squared.

[tex]\rm z^2=\dfrac{x}{y}[/tex]

Where; z is the scale factor, x = area of polygon Q, y = area of polygon P.

Therefore,

The area of the first triangle is;

[tex]\rm Area = \dfrac{1}{2} \times base \times height\\\\Area = \dfrac{1}{2} \times 1 \times 2\\\\Area = 1 \ units[/tex]

The area of three squares (A2, A3, and A4)

[tex]\rm Area = 3(1)^2\\\\Area = 3\ square \ units[/tex]

The area of the 5th triangle is;

[tex]\rm Area = \dfrac{1}{2} \times base \times height\\\\Area = \dfrac{1}{2} \times 1 \times 1\\\\Area = 0.5 \ units[/tex]

Then,

The area of the polygon is;

x = 1 + 3 + 0.5 = 4.5 units

Therefore,

The scaled factor did Diego used to go from P to Q is;

[tex]\rm z^2=\dfrac{4.5}{72}\\\\z^2=\dfrac{1}{16}\\\\z=\dfrac{1}{4}\\\\[/tex]

Hence, the scaled factor did Diego used to go from P to Q is 1/4.

To know more about the Scale factor click the link given below.

https://brainly.com/question/22644306

Answer:

[tex]x=\pm\sqrt{77n+53}[/tex]

Step-by-step explanation:

Given : [tex]x^2\equiv 53\mod 77[/tex]

To find : All the square roots ?

Solution :

The primitive roots modulo is defined as

[tex]a\equiv b\mod c[/tex]

Where, a is reminder

b is dividend

c is divisor  

Converting equivalent into equal,

[tex]a-b=nc[/tex]

Applying in [tex]x^2\equiv 53\mod 77[/tex],

[tex]x^2\equiv 53\mod 77[/tex]

[tex]x^2-53=77n[/tex]

[tex]x^2=77n+53[/tex]

[tex]x=\pm\sqrt{77n+53}[/tex]

We have to find the possible value in which the x appear to be integer.

The possible value of n is 4.

As [tex]x=\pm\sqrt{77(4)+53}[/tex]

[tex]x=\pm\sqrt{308+53}[/tex]

[tex]x=\pm\sqrt{361}[/tex]

[tex]x=\pm 9[/tex]

Answer:

Option B. 5 hours.

Step-by-step explanation:

Steve reads 80 pages in 2 hours and 40 minutes.

1 hour = 60 minutes

2 hour 40 minutes = (2 × 60) + 40 = 160 minutes

Speed of reading of Steve = [tex]\frac{80}{160}[/tex]

                                             = 0.5 page per minute

Cassandra reads twice as fast as Steve.

Therefore, speed of reading of Cassandra = 0.5 × 2

                                                                       = 1 page per minute

Therefore, time to read 300 pages by Cassandra = 300 × 1

                                                                                   = 300 minutes

Now convert minutes to hours

[tex]\frac{300}{60}[/tex]

= 5 hours

Cassandra will take 5 hours to read 300 page book.

Answer:

$20.9

Step-by-step explanation:

We have been given a formula [tex]C(x)=19x+1900[/tex], which represents the cost of x items.

First of all, we will find cost of 1000 items by substituting [tex]x=1000[/tex] in our given formula as:

[tex]C(1000)=19(1000)+1900[/tex]

[tex]C(1000)=19,000+1900[/tex]

[tex]C(1000)=20,900[/tex]

To find average cost per item, we will divide total cost by number of items as:

[tex]\text{Average cost per item}=\frac{\$20,900}{1000}[/tex]

[tex]\text{Average cost per item}=\$20.9[/tex]

Therefore, the average cost per item would be $20.9.