the system of equations n= 2p+3 and n= 5+p is graphed what is the solution to the system of equations

Answers

Answer 1
It isn't graphed anywhere I can see it. If you can see the graph, read the coordinates of the point of intersection.

.. (p, n) = (2, 7)
Answer 2
The solution is n = 7 and p = 2

Step-by-step explanation:

Graph is not given.

We have

       n= 2 p+3

and

      n= 5+p

That is

     2 p+3 = 5 + p    

         p = 5 - 3

         p = 2

Substituting in n= 5+p

             n = 5 + 2 = 7

So the solution is n = 7 and p = 2    


Related Questions

PLEASE HELP FAST!!!!!!!!!!!! WILL GIVE BRAINILST OR WHATEVER :)))))))))))

let f(x)=4x+3 and g(x)=-2+5. find (fog) (5)

Answers

the correct question is
let f(x)=4x+3 and g(x)=-2x+5. find (fog) (5)

we have that
f(x)=4x+3
g(x)=-2x+5
(fog) (x)---------> f(g(x))------> 4*[-2x+5]+3---------> f(g(x))=-8x+20+3
f(g(x))=-8x+23
then 
(fog) (5)=-8*5+23---------> (fog) (5)=-40+23
(fog) (5)=-17

the answer is (fog) (5)=-17


which of the following is equivalent to the polynomial below

Answers

Try this solution:
1. to find the roots of the equation (D=-36):
[tex] \left[\begin{array}{ccc}x=5+6i\\ x=5-6i\end{array}\right[/tex]
2. to simplify the polinom:
x²-10x+61=(x-(5-6i))(x+(5+6i))
Answer: 1

A triangle has one 60 degree angle and one 20 degree angle. The third angle in the triangle must be
a.acute
b.obtuse
c.commplementary
d.straight

Answers

The 3rd angle has to be b. obtuse because a triangle's angles must add to 180°. 20° and 60° add to 80, and you must have a 100° for them to add to 180°. Any angle above 90° is known as an obtuse angle, so that's your answer.

HELP PLEASE
Translate the answer, T2 = A3, into words:

The BLANK of the orbital period, T, of a
planet is equal to the BLANK of the average distance, A, of the planet from the Sun.

Square
Square Root
Cube

Answers

SQUARE and CUBE are the answers i just did it.

Answer:  The square of the orbital period, T, of a  planet is equal to the cube of the average distance, A, of the planet from the Sun.

Step-by-step explanation:

In mathematics, A number or variable 'a' to its second power is said to be square of 'a' i.e. [tex]\ a^2[/tex] is the square of a.

A number or variable 'b' to its third power is said to be cube of 'b' i.e. [tex]\ b^3[/tex] is the cube of b.

In the given equation: [tex]T^2 = A^3[/tex]

Here,  [tex]T^2 [/tex] is square of T.

And  [tex]A^3[/tex] is cube of A.

Therefore, The square of the orbital period, T, of a  planet is equal to the cube of the average distance, A, of the planet from the Sun.

Find geometric mean of the pair of number 6 and 10

Answers

1st step: multiply the numbers
6 x 10 = 60

2nd step find the square root 

sqrt(60) = 7.745

 round the answer as needed.

The Geometric mean of the pair of number 6 and 10 is [tex]7.74[/tex]

Geometric mean :

The geometric mean of two number m and n is given as,

                       [tex]G.M=\sqrt{m*n}[/tex]

Geometric mean of the pair of number 6 and 10 is,

                    [tex]G.M=\sqrt{6*10} =\sqrt{60} \\\\G.M=7.74[/tex]

Learn more about the Geometric mean here:

https://brainly.com/question/47038

Can you answer this one for my plz I need before Monday ty

Answers

Since you need the vertex, and knowing the vertex will tell you the axis of symmetry, it is convenient to put the equation in vertex form.
.. -x^2 -4x +1
.. = -(x^2 +4x) +1
.. = -(x^2 +4x +(4/2)^2) +1 -(-(4/2)^2) . . . . complete the square
.. = -(x +2)^2 +5

The vertex is (-2, 5).
The axis of symmetry is x = -2.

How to start the problem off. (substitution)

Answers

Do you have to use substitution? 

The perimeter of a quilt is 34 ft. If the quilt is 8 ft long, what is the area

Answers

2l + 2w = 34 (l = 8) (Problem)
2 x 8 = 16 (Finding out the length)
16 + 2w = 34 (Problem with the length)
-16           -16 (Using the subtraction property of equality to isolate the variable)
       2w = 18 (New problem)
       /2      /2 (Using division property of equality)
         w = 9. (Width is found)

9 x 8 = 72. The area is 72 squared feet.
34-(8x2)=18
18÷2=9
8x9=72

The answer should be a fraction

Answers

ok so 40y2/50y3.... you are going to cancel out the common factor (10)  
 
4y2/5y3..
now apply the exponent rule, which is : xa /xb = 1/ xb-a

so...y2/y3 = 1/ y3 - 2 = 1/y

ANSWER : 4/5y
Hello! : )

The correct answer to your question is... [tex] 2^{3} y^{5} [/tex]

Evidence:
Step 1:     Simplify [tex] y^{2} [/tex]/5

( 40 multiplied by [tex] y^{2} [/tex]/5 multiplied by [tex] y^{3} [/tex] )


Step 2:     [tex] y^{2} [/tex] multiplied by [tex] ^{3} [/tex] = y(2 + 3) = [tex]y^{5} [/tex]


So the correct answer is... [tex] 2^{3} y^{5} [/tex]

I hope this helped! : )
Please Rate & Thank!
Please mark as Brainliest!

Have a wonderful day! : )

A triangle on a coordinate plane is translated according to the rule T–3, 5(x, y). Which is another way to write this rule?

(x, y) → (x – 3, y + 5)
(x, y) → (x – 3, y – 5)
(x, y) → (x + 3, y – 5)
(x, y) → (x + 3, y + 5)

Answers

we have that

 the original (x,y) coordinates are being moved to the left by 3 units and up by 5 units.

therefore 
the answer is the option 
(x, y) → (x – 3, y + 5)

Another way to write the given rule is (x, y) → (x – 3, y + 5).

Given that,

There are the original x and y coordinates that are being moved to the left-hand side by 3 units and go up by 5 units.

Based on the information, we can conclude that another way to write the given rule is (x, y) → (x – 3, y + 5).

Hence, the other options are incorrect.

Learn more: brainly.com/question/22264506

If the test scores of a class of 34 students have a mean of 73.1 and the test scores of another class of 26 students have a mean of 66.4, then the mean of the combined group is

Answers

Combined mean
= (73.1 * 34 + 66.4 * 26) / (34 + 26)
= (2485.4 + 1726.4) / 60
= 70.2 (rounded)

The Mean of the combined class is 70.19.

Mean

Mean is the average of a set of two or more numbers. The arithmetic and geometric mean are the types of mean that can be calculated.

Mean formula

[tex]\rm Mean = \dfrac{sum\ of\ the\ term}{total\ number\ of\ term}[/tex]

Given

The test scores of a class of 34 students have a mean of 73.1 and

The test scores of another class of 26 students have a mean of 66.4.

To find

The mean of the combined group.

How to get the mean of the combined group?

The sum of the total of the test score = Total number of students x Mean

Class 1 sum will be

The sum of the total test score = 34 x 73.1

The sum of the total test score = 2485.4

Class 2 sum will be

The sum of the total test score = 26 x 66.4

The sum of the total test score = 1726.4

Than Mean for the combine will be

[tex]\rm Mean = \dfrac{sum\ of\ the\ term}{total\ number\ of\ term}\\\\Mean = \dfrac{2485.4+1726.4}{34+26} \\\\Mean = \dfrac{4211.8}{60} \\\\Mean = 70.19[/tex]

Thus the Mean of the combined class is 70.19.

More about the Mean link is given below.

https://brainly.com/question/521501

Solve the equation by completing the square. Round to the nearest hundredth if necessary. x2 – 4x = 5

Answers

Solve for x over the real numbers:
x^2 - 4 x = 5

Subtract 5 from both sides:
x^2 - 4 x - 5 = 0

x = (4 ± sqrt((-4)^2 - 4 (-5)))/2 = (4 ± sqrt(16 + 20))/2 = (4 ± sqrt(36))/2:
x = (4 + sqrt(36))/2 or x = (4 - sqrt(36))/2

sqrt(36) = sqrt(4×9) = sqrt(2^2×3^2) = 2×3 = 6:
x = (4 + 6)/2 or x = (4 - 6)/2

(4 + 6)/2 = 10/2 = 5:
x = 5 or x = (4 - 6)/2

(4 - 6)/2 = -2/2 = -1:

Answer:  x = 5 or x = -1

Answer:

  x = 5 or x = -1

Step-by-step explanation:

x^2 – 4x = 5

Solve it by completing the square method

In completing the square method, we take the coefficient of x that is -4, divide it by 2 and then square it

-4/2 = -2  

square it (-2)^2 = 4

Now add 4 on both sides

x^2 – 4x +4 = 5+4

x^2 – 4x +4 = 9

Now factor the left hand side

(x-2)(x-2)=9

(x-2)^2 = 9

Take square root on both sides

x-2 = +-3

x-2 = 3 , so x= 5

x-2 = -3, so x= -1


8. The U.S. population was 309 million in 2010. If the U.S. had had the same firearm death rate as Australia in 2010, how many firearm deaths would the U.S. have expected to have that year? Australia’s population was 22.3 million people in 2010. Australia had 236 firearm deaths in 2010. (round to the nearest person)

Answers

To answer this question I would use ratios . I would set this up as 236 deaths/22.3 million people = x number of deaths/ 309 million people. You could use cross products to solve for x. 309 x 236= 22.3x. 72924= 22.3x. Divide both sides by 22.3 to solve for X, or the number of deaths in the US. X = 3270 deaths. Another way to figure this out would be to figure out how many groups of 22.3 million Australian people there are in 309 million Americans. This factor would then be multiplied by 236 to get the number of deaths in the United States. The answer would be the same.

As per linear equation, in 2010 the expected firearm death U.S. had is 3270.

What is a linear equation?

A linear equation represents an equation that has one or multiple variables with the highest power of the variable is 1.

Australia’s population was 22.3 million people in 2010.

Australia had 236 firearm deaths in 2010.

Therefore, portion of Australian population had firearm deaths is

[tex]= \frac{236}{22.3(10)^{6} } \\= 0.000011[/tex]

The U.S. population was 309 million in 2010.

Therefore, the expected firearm deaths in U.S. in 2010 was

[tex]= (309) (10^{6}) (0.000011)\\= 3270.13\\= 3270[/tex]

Learn more about linear equation here: https://brainly.com/question/5280825

#SPJ3

factor, x^4y+8x^3y-6x^2y^2-48xy^2

Answers

Hey there Ruben!

[tex]\boxed{\boxed{((((x^4)*y)+((8*(x^3))*y))-((6*(x^2))*(y^2)))-(24*3xy^2)}} \\ \\ (let's \ simplify \ some \ number's \ down) \\ \\ \boxed{\boxed{ ((((x4)*y)+((8*(x3))*y))-((2*3x2) *y2))-(24*3xy2)}} \\ \\ \\ Pull \ out \ like \ factors : \\ \\ \boxed{\boxed{ x4y + 8x^3y - 6x2y^2 - 48xy^2 = xy * (x3 + 8x^2 - 6xy - 48^y) }} \\ \\ \\ (TAKE \ NOTICE) \swarrow\swarrow\swarrow\swarrow \swarrow\swarrow\swarrow\swarrow\swarrow\swarrow \\ \\ \\ [/tex]

[tex]\boxed{\boxed{\boxed{ (((((x^4)*y)+(23x^3*y))-(2*3x2y2))}}} \\ \\ \\ \boxed{\boxed{\boxed{-(24*3xy2))-xy*(x3+8x2-6xy-48y) = \boxed{0}}}}}[/tex]

I hope this helps you!
the answer is xy(x+8)(x^2-6y)

see attached picture for steps:

Which simplified equation is equivalent to the equation shown below?
4x+x-3-9+4x=6

a.5x-8=6

b.-3x=6

c. 9x-12=6

d. 8x-12=6

Answers

4x+x-3-9+4x=6
9x-12=6
Answer C

We need to group the like terms and combine like terms to get the simplified equation.

[tex] 4x+x-3-9+4x=6\\ \\ Step \; 1: \; Group \; like\; terms\\ \\ 4x+x+4x-3-9=6\\ \\ Step \; 2: \; Combine \; like\; terms\\ \\ 9x-12=6 [/tex]

Conclusion:

Option C is the right answer !!


describe the graph of y=3/4x-12 as compared to the graph of y=1/x

Answers

Answer:

Parent function is compressed by a factor of 3/4 and shifted to right by 3 units.

Step-by-step explanation:

We are asked to describe the transformation of function [tex]y=\frac{3}{4x-12}[/tex] as compared to the graph of [tex]y=\frac{1}{x}[/tex].

We can write our transformed function as:

[tex]y=\frac{3}{4(x-3)}[/tex]

[tex]y=\frac{3}{4}*\frac{1}{(x-3)}[/tex]

Now let us compare our transformed function with parent function.

Let us see rules of transformation.  

[tex]f(x-a)\rightarrow\text{Graph shifted to the right by a units}[/tex],

[tex]f(x+a)\rightarrow\text{Graph shifted to the left by a units}[/tex],

Scaling of a function: [tex]a*f(x)[/tex]

If a>1 , so function is stretched vertically.

If 0<a<1 , so function is compressed vertically.

As our parent function is multiplied by a scale factor of 3/4 and 3/4 is less than 1, so our parent function is compressed vertically by a factor of 3/4.

As 3 is being subtracted from x, so our parent function is shifted to right by 3 units or a horizontal shift to right by 3 units.

Therefore, our parent graph is compressed by a factor of 3/4 and shifted to right by 3 units to get our new graph.

Final answer:

The equation y=3/4x-12 represents a linear function with a straight line graph, while y=1/x depicts a rectangular hyperbola with a curved graph showcasing an inverse relationship. These graphs exhibit fundamentally different behaviors, one being constant and the other varying.

Explanation:

The student's question involves comparing the graph of y=3/4x-12 to the graph of y=1/x. The first equation, y=3/4x-12, describes a linear function with a slope of 3/4 and a y-intercept of -12. This means it is a straight line that increases as x increases, crossing the y-axis at (0, -12).

On the other hand, the graph of y=1/x is a rectangular hyperbola. This curve approaches the x-axis and y-axis but never touches them, known as asymptotes. The hyperbola is divided into two parts, one in the first quadrant where both x and y are positive, and another in the third quadrant where both x and y are negative. This graph does not resemble a straight line at any part.

Comparatively, the key difference lies in the nature of their graphs - one is a straight line and the other a curved hyperbola, showcasing completely different behaviors. The linear equation reflects constant change, whereas the hyperbola’s rate of change varies with x, indicating an inverse relationship.

What is the following product? 3 sqrt d x 3 sqrt d x 3 sqrt d

Answers

[tex]\bf 3\sqrt{d}\times 3\sqrt{d}\times 3\sqrt{d}\implies (3)(3)(3)\sqrt{d\times d\times d}\\\\\\ 27\sqrt{d^2d}\implies 27d\sqrt{d}[/tex]

Answer: the first option, d.

Step-by-step explanation:

What is the value of x?



Enter your answer in the box.

x=

Answers

The angles have equal measure because they are vertically opposite angles.

3x + 50 = 6x - 10
3x - 6x = -10 - 50
-3x = -60
x = 20

The answer is x=20.


If you take out a loan that costs $130.50 over nine years at an interest rate of 10%, how much was the loan for?

Answers

Final answer:

The original loan amount for which the final amount payable is $130.50 over nine years at an interest rate of 10% was approximately $55.39.

Explanation:

To find out the original amount of the loan for which the final amount payable is $130.50 over nine years at an interest rate of 10%, we will use the formula for the present value of a loan.

The formula given is P = A / (1 + r/n)^nt, where P is the principal (initial loan amount), A is the final amount, r is the annual interest rate (expressed as a decimal), n is the number of times that interest is compounded per year, and t is the time the money is borrowed for in years.

As the question doesn't specify how many times the interest is compounded per year, we will assume it is compounded once a year (n=1).

We have:

A = $130.50,r = 10% or 0.10,n = 1,t = 9 years.

Plugging these values into the formula:

P = $130.50 / (1 + 0.10/1)^(1*9)

P = $130.50 / (1 + 0.10)^9

P = $130.50 / (1.10)^9

P = $130.50 / 2.35794769

P = $55.39 approximately

Therefore, the original loan amount was approximately $55.39.

3/4,19/20,1/6,3/5,8/15 what is lcd

Answers

You just have to find the lcm or least common factors of the denominators which is 60.
The least common multiple of denominators
.. 4 = 2^2
.. 5
.. 6 = 2*3
.. 15 = 3*5
.. 20 = 2^2*5
is 2^2*3*5 = 60

The lowest common denominator is 60.

A circular city park has a sidewolk directly through the rmiddle that is 111- feet long. I each bag of fertilizer covers 50 square feet, then determine how many bags of tertilizer the Parks and Recreation department needs to use to cover the circular park. Ignore oll the sidewalks around and through the park.

Answers

The area of a circle with a diameter of 111 ft is
.. A = (π/4)d^2
.. = (π/4)*(111 ft)^2 ≈ 9676.9 ft^2

The number of bags of fertilizer required will be
.. (9676.9 ft^2)*(1 bag)/(50 ft^2) = 193.5 bags

Parks & Rec needs to use 193.5 bags of fertilizer to cover the park.

_____
No doubt, P&R has half a bag left over from a previous use of fertilizer in the park, so they will not have to purchase a whole bag to cover the fraction.

A bank runs a contest to encourage new customers to open accounts. In the contest, each contestant draws a slip representing a different reward—$5, $3, or $x—from a jar. At the beginning of the contest the jar contains 60 slips for $5, 40 slips for $3, and 50 slips for $x.
If the expected value of the first draw from the jar is $5.8, the value of x is__
At one point in the contest, the jar contains 3 slips for $5, 7 slips for $3, and y slips for $x. If the expected value on the next draw is $6, the value of y is __

Answers

Part 2:


We'll use x = 9 from part 1.


Again let,
A = event that the $5 reward is drawn
B = event that the $3 reward is drawn
C = event that the $x reward is drawn (x is some positive number)

We can update event C to say
C = event that the $9 reward is drawn


The probabilities change to
P(A) = 3/(10+y)
P(B) = 7/(10+y)
P(C) = y/(10+y)
where y is some positive whole number. It represents the number of slips in jar C


The net values are
V(A) = 5
V(B) = 3
V(C) = x = 9


Like before, multiply the probabilities and net values to get
P(A)*V(A) = (3/(10+y))*5 = 15/(10+y)
P(B)*V(B) = (7/(10+y))*3 = 21/(10+y)
P(C)*V(C) = (y/(10+y))*9 = (9y)/(10+y)


The results add up to
[ 15/(10+y) ] + [ 21/(10+y) ] + [ (9y)/(10+y) ]
(15+21+9y)/(10+y)
(36+9y)/(10+y)


That last expression is the expected value. The expected value is also given to be 6, so set the two expressions equal to each other and solve for y.
(36+9y)/(10+y) = 6
36+9y = 6(10+y)
36+9y = 6(10)+6(y)
36+9y = 60+6y
9y-6y = 60-36
3y = 24
3y/3 = 24/3
y = 8


The statement "y slips of $x" turns into "8 slips of $9" since x = 9 and y = 8.
x=9                                                                                                                     and                                                                                                                         y =8.......................................

HELP ME ANSWER THIS QUESTION!

Boyd (B) is trapped in a soccer training circle. Albert (A) and Carlos (C) kick the ball to Boyd in rotation. Determine how far Boyd needs to kick the ball to Carlos if he is located in the center of his training circle and Carlos is located at the outer rim.

Answers

Here we have right-angle triangle. Sides are:
AB = 19+x
BC= x
AC= 30

From the picture we can see that side AB is hypothenuze. We are given number 19 as part of length of that hypothenuze. Other part is equal to distance from center to edge of circle. This length is same as side BC.

We will use Pythagorean theorem to solve this:
[tex] (AB)^{2} = (BC)^{2} + (AC)^{2} \\ (19+x)^{2} = x^{2} + 30^{2} \\ 361+38x+ x^{2} = x^{2} +900 \\ x^{2} - x^{2} +38x=900-361 \\ 38x=539 \\ x=14.2yard[/tex]

The scale on a map is 1 cm:35 mi. The distance on the map between Los Angeles, CA, and San Francisco, CA, is 10.8 cm. What is the actual distance between Los Angeles and San Francisco?

Answers

It is 378 miles. :)
this is answer

Step 1: Let us assign variable for the unknown that we need to find.

' x ' be the actual distance between Los Angeles and San Francisco

Step 2: Set up an equation based on the given statement "The scale on a map is 1 cm:35 mi. The distance on the map between Los Angeles, CA, and San Francisco, CA, is 10.8 cm."

[tex] \frac{distance \; in \; cm}{distance\; in\; miles}=\frac{1}{35}=\frac{10.8}{x} \\ \\ Cross \; Multiply\\ \\ 1 \cdot x = 35 \cdot 10.8\\ \\ x = 378 [/tex]

Conclusion:

The actual distance between Los Angeles and San Francisco is 378 miles.

Which triangle is it ?

Answers

the answer in attached figure

we know that
sin(30°)=0.5    cos(30°)=√3/2
sin(60°)=√3/2  cos(60°)=0.5

sin(60)=BC/AC=5√3/10=√3/2-------------- is ok
cos (60)=AB/AC=5/10=0.5---- is ok

sin(30)=BA/AC=5/10=0.5-------------- is ok
cos (30)=BC/AC=5√3/10=√3/2-------------- is ok

if angle B is 90°
then
AB²+BC²=AC²------------> 5²+(5√3)²=10²=(25+75)=100------------- > is ok



the solution in the attached figure

Which shows how the distributive property can be used to evaluate 7×84/5?

Answers

Well you have nothing here, so I'll take a guess.
84/5 gives 16 4/5. I don't know how much saving in work there is in doing this but you could do this.

7 ( 16 + 4/5)
You still have to do something with 28/5 when you get done, but it is one way to do it.

1. A rectangular prism is defined as the drawing shows. Note B at (0, 5, 0) and F (0, 0, 4). The prism is reflected over the xz-plane. The reflected image is then translated 2 units back, 3 units left, and 1 unit up.
a.) Show the results of your calculations for points A, B, C and D from the reflection.
b.) Show the results of your calculations for points A, B, C and D from the translation.

Answers

Initial coordinates:
A (0,0,0)
B (0,5,0)
C (3,5,0)
D (3,0,0)
E (3,0,4)
F (0,0,4)
G (0,5,4)
H (3,5,4)

a.) The prism is reflected over the xz-plane.
Reflection Point P(x,y,z) over the xz-plane is P'(x,-y,z):
Reflection P(x,y,z) over the xz-plane → P'(x,-y,z)

Reflection A(0,0,0) over the xz-plane → A'(0,-0,0) = A'(0,0,0)
Reflection B(0,5,0) over the xz-plane → B'(0,-5,0)
Reflection C(3,5,0) over the xz-plane → C'(3,-5,0)
Reflection D(3,0,0) over the xz-plane → D'(3,-0,0) = D'(3,0,0)

b.) The reflected image is then translated 2 units back, 3 units left, and 1 unit up.
Translation P'(x,-y,z) 2 units back, 3 units left, and 1 unit up is P''(x-2,-y-3,z+1):
Translation P'(x,-y,z) → P''(x-2,-y-3,z+1)

Translation A'(0,0,0) →A''(0-2,0-3,0+1) = A''(-2,-3,1)
Translation B'(0,-5,0) →B''(0-2,-5-3,0+1) = B''(-2,-8,1)
Translation C'(3,-5,0) →C''(3-2,-5-3,0+1) = C''(1,-8,1)
Translation D'(3,0,0) →D''(3-2,0-3,0+1) = D''(1,-3,1)


1.Write equatios to represent the distances the family drove on the given days.

2. construct a math argument to explain why your answer to 5 is correct.

3. How can you check that your answer is reasonable?

Answers

        equations are (174+106) (112+165) (121+168) (172+113)
i think this is correct because you need morning and evening combined to know a exact answer.  
you can check this by calculating you equations and u will end up with Wednesday as the longest amount of miles
  

Evaluate g(n-5) if g(x)=x^2-6/2x

Answers

g(x) = (x^2-6) / 2x 

g( n-5) = ( [n-5]^2 -6) / 2(n-5) 

= ( n^2 -10n +25 -6 ) / 2(n-5) or ( n^2 -10n +25 -6 ) / (2n-10) 
Your Answer 

I did foil first and got n^2-10n+25 
then did 25-6 to get 19. 
so n^2-10n+25 is on top.////// should have been n^2 -10n +19 
and the bottom is 2(n-5) so I distributed the 2 and got 2n-10 

so n^2-10n+25 
2n-10 
= (n^2 -10n +19) / 2(n-5)

Answer: We want to evaluate g(x) in x = n -5, where g(x) = (x^2-6)/2x

then, doing it step by step: [tex]g( n- 5)= \frac{(n-5)^{2} - 6 }{2*(n-5)}= \frac{(n^{2} - 2*5*n + 25) - 6 }{2n - 10} = \frac{n^{2} - 10n + 19 }{2n - 10}[/tex]

where i used that (a - b)^2 = a^2 -2ab + b^2

So the correct option is C.

Suppose given an isosceles triangle with a leg measuring 5 in. Two lines are drawn through some point on the base, each parallel to one of the legs. Find the perimeter of the constructed parallelogram.

Answers

Let ΔABC be isosceles triangle with legs AB=BC=5 in. Draw an arbitrary point D on the base AC and spend two lines DE and DF such that DE || BC and DF || AB.

You get the parallelogram BFDE.

1. Consider ΔAED. This triangle is isosceles, because ∠ADE≅∠ACB as corresponding angles at parallel lines. The legs of this triangle are AE=ED.

2. Consider ΔDFC. This triangle is isosceles, because ∠FDC≅∠BAC as corresponding angles at parallel lines. The legs of this triangle are DF=FC.

3. Find the perimeter of parallelogram BFDE.

[tex]P_{BFDE}=BF+FD+ED+BE.[/tex]

Since AE=ED and DF=FC, you have that

[tex]P_{BFDE}=BF+FC+AE+BE=AB+BC=5+5=10\ in.[/tex]

Answer: 10 in.

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