The peak wavelength of radiation emitted from human skin at 33.0°C is approximately 9465.7 nm or about 9.465 microns, calculated using Wien's displacement law.
Explanation:The student's question about the peak wavelength of radiation emitted from the skin at a certain temperature relates to Wien's displacement law. This law states that the peak wavelength of the radiation is inversely proportional to the temperature of the radiating body when the temperature is in Kelvin. Firstly, we need to convert the skin temperature from Celsius to Kelvin, which would be 33.0°C + 273.15 = 306.15 K. Using Wien's law (with a constant of approximately 2.898 x 10^6 nm·K), we can calculate the peak wavelength with the formula λ(max) = b / T. So, the peak wavelength would be λ(max) = 2.898 x 10^6 nm·K / 306.15 K, which gives us a peak wavelength of approximately 9465.7 nm or about 9.465 microns.
A satellite is in a circular orbit about the earth at a distance of one earth radius above the surface. what is the velocity of the satellite? (the radius of the earth is 6400 km and the mass of the earth is 5.98 * 1024 kg)
Rebekah finds that a solution of sugar in water has a volume of 1.32 fl. oz. How should she report this amount using the metric system? (1 fl. oz. = 29.6 mL)
What potential increase vac must an electron be accelerated through if the most energetic photon it can emit will scatter off of a stationary electron at an angle ϕ=60∘ with wavelength 8.4×10−12m?express your answer in kilovolts to two significant digits?
a screwdriver with a 1-cm shaft and a 4-cm handle is used to tighten a screw. calculate the ideal mechanical advantage.
Answer:
IMA = Distance of Effort/ Distance of resistance
Explanation:
M.A is the force amplification of a machine.
Ideally, a screw driver has varying diameters on two ends, the shaft and the handle, however, since the question does not provide those parameters, we will assume shaft and handle have the same diameter.
DE = 4
DR = 1
Therefore, IMA = [tex]\frac{4}{1} = 4[/tex]
If diameter is given, IMA is calculated by
Area of Effort/ Area of resistance i.e. AE/AR
If a chromosome on unfolds itself how is transcription enhanced
A gravitational field vector points toward the earth; an electric field vector points toward an electron. why do electric field vectors point away from protons? 1. protons have much larger mass. 2. unlike electrons, protons will produce an electric field of their own. 3. protons have more net charge than electrons. 4. protons are positively charged. 5. none of these
Electric field vectors point away from protons because protons are positively charged, and electric field lines always point away from positive charges and toward negative charges.
The direction of electric field vectors is determined by the nature of the charge that produces them. Specifically, electric field lines point away from positive charges and toward negative charges. This is because the electric field vector always points in the direction of the force that would be exerted on a positive test charge.
1. Gravitational fields always point towards the source of the field (like toward Earth) because gravity is an attractive force.
2. On the other hand, electric fields can be either attractive or repulsive. For a positive charge, the electric field vectors radiate outward because like charges repel, meaning if you place a positive test charge near a proton, it will be repelled outward.
Therefore, the correct answer is: protons are positively charged (option 4).
Which step in an investigation of arson helps insurance claims the most?
The step in an investigation of arson that help the insurance claims the most is the samples of ignition sources or the processing of evidence at the scene. The people with the insurance claims are careful in gathering investigation data for they will used it as a basis for their claim.
Answer:
Since it is for insurance purposes, inventory would be required.
Explanation: inventory is needed to file a claim. Also, I took the test and got it correct ;)
Newton believed that time and space are absolute, while Einstein believed that the _______ is absolute.
Curvation of Space-time
Speed of light
4th dememtion
Dilation of time
4th dememtion
Answer:
The answer is B. speed of light
Explanation:
Which listed property of alternating current is the MOST LIKELY reason it was chosen over direct current to provide electricity across the country? A) can power devices B) can be used in houses C) current changes direction D) can be transformed to different voltages
A battery charger delivers a current of 5.8 a for 2.9 h to a 12-v storage battery. what is the total charge that passes through the battery in that time
A canister containing air has a volume of 85 cm 3 and a pressure of 1.45 atm when the temperature is 310 k. what is the pressure when the volume is increased to 180 cm 3 and the temperature is reduced to 280 k?
Blow up a balloon and rub it against your shirt a number of times. In doing so you give the balloon a net electric charge. Now touch the balloon to the ceiling. On being released, the balloon will remain stuck to the ceiling. Why?
Final answer:
When you rub a balloon against your shirt, electrons are transferred from your shirt to the balloon, giving the balloon a negative charge. The negative charge on the balloon attracts the positive charges in the ceiling, causing it to stick.
Explanation:
When you rub a balloon against your shirt, electrons are transferred from your shirt to the balloon, giving the balloon a negative charge. The balloon becomes negatively charged and the shirt becomes positively charged. When you touch the negatively charged balloon to the ceiling, the positive charges in the ceiling are attracted to the balloon, causing it to stick.
What is the kinetic energy k of an electron with momentum 1.05×10−24 kilogram meters per second?
Answer:
K = 6.02 × 10⁻¹⁹ J
Explanation:
The momentum (p) of an electron is its mass (m) times its speed (v).
p = m × v
v = p / m = (1.05 × 10⁻²⁴ kg.m/s) / 9.11 × 10⁻³¹ kg = 1.15 × 10⁶ m/s
We can find the kinetic energy (K) using the following expression.
K = 1/2 × m × v²
K = 1/2 × 9.11 × 10⁻³¹ kg × (1.15 × 10⁶ m/s)²
K = 6.02 × 10⁻¹⁹ J
On a dry day, just after washing your hair to remove natural oils and drying it thoroughly, run a plastic comb through it. Small bits of paper will be attracted to the comb. Explain why.
Final answer:
A plastic comb can attract small bits of paper due to the electrostatic charge created by friction. This effect is reduced in moist air as humidity conducts the charge away.
Explanation:
When a plastic comb is run through hair, it can attract small bits of paper. This is due to the electrostatic charge that is created by friction when the comb is dragged against the hair. The comb becomes negatively charged as electrons are transferred from the hair to the comb, resulting in an electrostatic force that can attract neutral objects, such as pieces of paper.
If you repeat the experiment in a moist environment, such as a bathroom after a shower, you may observe that the electrostatic effect is reduced. This is because water molecules in the air increase the humidity, which conducts the charge away, thereby neutralizing the electrostatic effect more rapidly than in dry air.
Torn paper may be more effective than cut paper because the tearing process can create more irregularities and protrusions on the edges of the paper, providing more opportunities for the electric force to act upon these points compared to the relatively smooth edges of cut paper.
Even at such low fractions of the speed of light these stars are moving quite quickly (thousands of kilometers a second) compared to the standard velocity dispersion in the milky way galaxy (which is around 300km/s). suppose the star was actually moving toward the earth at a more reasonable 300km/s. what wavelength λ would the 656.46-nm line move to? use 299,792km/s for the speed of light. express your answer in nanometers to five significant figures.
The hydrogen line at 656.46 nm shifts to about 655.80 nm if a star is traveling 300 km/s toward Earth.
Using the Doppler Effect to Determine the Wavelength Shift
First, note the speed of light: c = 299,792 km/s.Original wavelength of the hydrogen line: λ₀ = 656.46 nm.Star's velocity towards Earth: v = -300 km/s (negative because the star is approaching).Use the Doppler shift formula for wavelengths:
[tex]\[\lambda = \lambda_0 \sqrt{\frac{c - v}{c + v}}\][/tex]Plugging in the values:
[tex]\[\lambda = 656.46 \, \text{nm} \sqrt{\frac{299,792 - 300}{299,792 + 300}}\][/tex]Calculate the ratio:
Ratio = √(299,492 / 300,092) ≈ √(0.998)Evaluate the square root:
[tex]\[\frac{299,492}{300,092} \approx 0.998\][/tex][tex]\[\sqrt{0.998} \approx 0.999\][/tex]Compute the shifted wavelength:
[tex]\[\lambda \approx 656.46 \, \text{nm} \times 0.999\][/tex] ≈ 655.80 nmThe 656.46-nm line would shift to approximately 655.80 nm if the star were moving towards Earth at 300 km/s.
Complete question:
Suppose that you'd like to find out if a distant star is moving relative to the earth. The star is much too far away to detect any change in its brightness as it moves toward or away from the earth. Instead we can use the Doppler effect to determine its relative speed. For this problem we are going to look at the spectral lines from hydrogen, specifically the one with a wavelength of 656.46 nm. Even at such low fractions of the speed of light these stars are moving quite quickly (thousands of kilometers a second) compared to the standard velocity dispersion in the Milky Way galaxy (which is around 300 km/s). Suppose the star was actually moving toward the earth at a more reasonable 300 km/s. What wavelength I would the 656.46-nm line move to? Use 299, 792 km/s for the speed of light. Express your answer in nanometers to five significant figures.
I will give you BRAINILIEST!!!!!!!!! AND 15 POINTS
Which of the following is a divergent boundary?
A. Rift valley
B. Transform
C. Oceanic-continental
D. Continental-continental
How long can the body maintain an anaerobic burst of energy
Picturing the way a volcano erupts to remember how a volcano functions is called a. Visualizing c. Keywording b. Categorizing d. All of these
Making a mental picture of the way a volcano erupts to remember how a volcano functions is called visualization.
What is visualization?Visualization is the process whereby a person makes or forms a mental picture of a particular situation or occurrence in order to better understand that occurrence.
Picturing the way a volcano erupts to remember how a volcano functions is a process of visualization.
A mental picture of the volcano is made by the individual.
Therefore, Picturing the way a volcano erupts to remember how a volcano functions is called visualization.
Learn more about visualization at: https://brainly.com/question/1569390
#SPJ2
Solar radiation falls on earth's surface at a rate of 1900 w/m2 . assuming that the radiation has an average wavelength of 560 nm, how many photons per square meter per second fall on the surfaces? the speed of light is 3 × 108 m/s and planck's constant is 6.62607 × 10−34 j · s. answer in units of photon/m2 · s.
The number of photons per square meter per second falling on the earth's surface, given the solar radiation rate and average wavelength is calculated to be 5.36 x 10²¹ photons/m2·s.
Explanation:The energy of the average visible photon is calculated using the formula E= hc/λ, where h is Planck's constant, c is the speed of light and λ is the wavelength. With the given values, we get the energy E by substituting h=6.62607 × 10⁻³⁴ J·s, c=3 × 108 m/s, and λ=560 × 10⁻⁹ m resulting in E= 3.546 × 10⁻¹⁹ J. The number of photons per meter square per second can be calculated by dividing the rate of solar radiation, 1900 W/m2 or 1900 J/s·m2 by the energy per photon, yielding 5.36 x 10²¹ photons/m2·s.
Learn more about Photon Count Calculation here:https://brainly.com/question/29038909
#SPJ3
When the angle of elevation of the sun is 64°, a pole that is tilted at an angle of 19° directly away from the sun casts a shadow 21 feet long on level ground. approximate the length of the pole to the nearest foot?
Answer:
Length of the pole is 27ft. ( rouding up to the nearest foot)
Explanation:
To solve this problem you need to understand that the the shadow cast by the pole on the ground connected to the pole itself and to the imaginary line of sun light forms a triangle with 3 different angles, please see the drawing to a better understanding.
* The sum of the internal angles of any triangle must be 180° then;
α: angle of the elevation of the sun= 64°
angle of the pole to the ground= (90-19)= 71°
β = 180 - ( 64+71) = 45°
*To find the length of the pole we can use the law of Sines;
|BC| / sin (α) = |AC| / sin (β)
|BC|= Length of the pole
|AC|= shadow of the pole on the ground which is known to be 21 ft
|BC| / sin (64°) = 21 / sin (45°)
|BC|= 21 x [sin (64°)/ sin (45°)]
|BC|= 21 x 1.27≅ 26.67 ft
A printer is connected to a 1.0 m cable. if the magnetic force is 9.1 × x10-5 n, and the magnetic field is 1.3 × 10-4 t, what is the current in the cable
A girl is running toward the front of a train at 10 m/s. If the train is going 75 m/s on the Southbound tracks, what is the speed of the train relative to the girl?
The speed of the train relative to the girl is 65 m/s.
Explanation:The speed of the train relative to the girl can be calculated by subtracting the girl's speed from the train's speed. In this case, the train is moving at 75 m/s and the girl is running towards the front of the train at 10 m/s. So the speed of the train relative to the girl would be 75 m/s - 10 m/s = 65 m/s.
Learn more about relative speed here:https://brainly.com/question/14362959
#SPJ12
The correct option is B. 65 m/s, South.
The given problem can be solved using concepts of relative motion.
Given that the girl is running toward the front of a train at 10 m/s and the train is going 75 m/s on the Southbound tracks. Hence, both the girl and the train are moving in the same direction, i.e. southwards.
So, the speed of the train relative to the girl can be given as:
[tex]v_{tg} = v_t - v_g[/tex]
where, [tex]v_{tg}[/tex] is the speed of train with respect to the girl
[tex]v_t[/tex] is the speed of train
[tex]v_g[/tex] is the speed of the girl
[tex]\therefore v_{tg} = 75 \hspace{0.8mm} m/s - 10 \hspace{0.8mm} m/s[/tex]
or, [tex]v_{tg} = 65 \hspace{0.8mm} m/s[/tex]
Hence, the speed of the train relative to the girl is 65 m/s due south.
The complete question is:
A girl is running toward the front of a train at 10 m/s. If the train is going 75 m/s on the Southbound tracks, what is the speed of the train relative to the girl?
A. 10 m/s, South
B. 65 m/s, South
C. 65 m/s, North
D. 10 m/s, North
A current of 5.0 a flows through an electrical device for 10 seconds. how many electrons flow through this device during this time?
Approximately [tex]\( 3.121 \times 10^{19} \)[/tex] electrons flow through the electrical device during the [tex]10\ seconds[/tex] when a current of [tex]5.0 \ A[/tex] is flowing.
To determine how many electrons flow through the electrical device, we can use the relationship between current, time, and the charge carried by electrons.
Given:
Current [tex]\( I = 5.0 \) A[/tex]
Time [tex]\( t = 10 \) seconds[/tex]First, calculate the total electric charge [tex]\( Q \)[/tex] that flows through the device using:
[tex]\[ Q = I \times t \][/tex]
Substitute the given values:
[tex]\[ Q = 5.0 \, \text{A} \times 10 \, \text{s} = 50 \, \text{C} \][/tex]
Now, we know that 1 Coulomb ([tex]C[/tex]) corresponds to approximately[tex]\( 6.242 \times 10^{18} \) electrons.[/tex]
To find out how many electrons [tex]\( N \)[/tex] flow through the device, convert the charge [tex]\( Q \)[/tex] into electrons:
[tex]\[ N = Q \times (6.242 \times 10^{18} \, \text{electrons/C}) \][/tex]
Substitute [tex]\( Q = 50 \, \text{C} \)[/tex]
[tex]\[ N = 50 \times 6.242 \times 10^{18} \, \text{electrons} \][/tex]
[tex]\[ N = 312.1 \times 10^{18} \, \text{electrons} \][/tex]
[tex]\[ N = 3.121 \times 10^{19} \, \text{electrons} \][/tex]
A proton and an electron are held in place on the x axis. The proton is at x = -d, while the electron is at x = +d. They are released simultaneously, and the only force that affects their motions is the electrostatic force of attraction that applies to the other. Which particle reaches the origin first? Give your reasoning.
The electron will reach the origin first due to its greater acceleration, which is a result of its much smaller mass compared to the proton, despite the forces on both particles being equal in magnitude.
Explanation:The question is asking which particle, a proton at x = -d or an electron at x = +d that are released simultaneously under the influence of electrostatic force, will reach the origin first. According to Newton's second law, force equals mass times acceleration (F = ma). Because the proton and the electron have equal and opposite charges, the magnitude of the force acting on them due to their electrical interaction will be the same. However, the mass of the proton is much greater than that of the electron, resulting in much smaller acceleration for the proton. Consequently, the electron, given its smaller mass and therefore larger acceleration, will reach the origin first.
Springfield's "classic rock" radio station broadcasts at a frequency of 102.1 mhz. what is the length of the radio wave in meters?
Using the equation for the speed of light, we find that the wavelength of a radio wave broadcasting at 102.1 MHz frequency in Springfield is approximately 2.94 meters.
Explanation:The length of a wave, often termed wavelength, can be deduced if the frequency is known, using the formula of the speed of light, which is wavelength times frequency (or c = λν). In this equation, 'c' signifies the speed of light (3 x 10^8 m/s), 'λ' is the wavelength, and 'ν' is the frequency. Given frequency = 102.1 MHz = 102.1 x 10^6 Hz, we can rearrange the formula to find the wavelength: λ = c/ν = 3 x 10^8 m/s / 102.1 x 10^6 Hz = 2.94 m. Therefore, the length of the wave is approximately 2.94 meters.
Learn more about Wavelength here:https://brainly.com/question/32900586
#SPJ3
In a physics laboratory experiment, a coil with 250 turns enclosing an area of 10.5 cm2 is rotated during the time interval 3.10×10−2 s from a position in which its plane is perpendicular to earth's magnetic field to one in which its plane is parallel to the field. the magnitude of earth's magnetic field at the lab location is 5.30×10−5 t .
Determine the absolute pressure on the bottom of a swimming pool 30.0 m by 9.0 m whose uniform depth is 1.9 m . express your answer using two significant figures.
The spool has a mass of 50 kg and a radius of gyration of ko = 0.280 m. if the 20-kg block a is released from rest, determine the velocity of the block when it descends 0.5 m.
To find the velocity of a 20-kg block descending 0.5 m, use conservation of energy, equating the potential energy lost by the block to the kinetic energy gained by the block and the rotational kinetic energy of the spool. Determine kinetic energy and rotational energy using the block's mass, spool's radius of gyration, and their shared velocity.
Explanation:To determine the velocity of the 20-kg block after it descends 0.5 m, we can use the principles of conservation of energy. The system consists of a spool and a block, and since the block is descending, gravitational potential energy is being converted into kinetic energy and rotational energy of the spool.
We know that the potential energy (PE) lost by the block is equal to the kinetic energy (KE) gained by the block plus the rotational kinetic energy (RKE) gained by the spool:
PE = KE + RKE
PE of the block = m·g·h, where m is the mass of the block, g is the acceleration due to gravity (9.81 m/s2), and h is the height descended (0.5 m).
KE of the block = 1/2 m·v2, where v is the velocity of the block we want to find.
RKE of the spool = 1/2 I·ω2, with I being the moment of inertia of the spool and ω the angular velocity. Since the spool and the block are connected, ω = v / r, where r is the radius of the spool.
Using the radius of gyration ko, the moment of inertia I for the spool is I = mspool·ko2. By substituting all these expressions into the energy conservation equation and solving for v, we can find the velocity of the block.
Learn more about Conservation of Energy here:https://brainly.com/question/35373077
#SPJ3
What did the early plants add to the atmosphere and why was that important? What else did they create?
early plants added oxygen to the atmosphere. They did this by photosynthesis process by absorbing the carbon dioxide from the atmosphere and giving away oxygen in return.
This was important because life is not possible without oxygen present in the atmosphere.
They consumed the carbon dioxide from the atmosphere and reduced the temperature of the planet also.
Earth is closest to the sun at what part of its orbit?