the answer is C. it increases by a factor of 110, i got 100 on the test
Which of the following is a dark sticky substance that is found in tobacco?
a.
tar
b.
nicotine
c.
nitrogen
d.
carbon monoxide
Which of the following is a useful tool in determining the genotype and phenotype of an organism?
Fossil Record
Punnett Square
Roots
Perfect Square
Which memory system provides us with a very brief representation of all the stimuli present at a particular moment?
As the distance increases, the electrical forces of attraction between oppositely charged particles _____.
Answer:
Decreases
Explanation:
Coulomb found that the electric force between two point charges is inversely proportional to the square of the distance that separates them. Therefore, in this case, when the distance increases the repulsion force decreases and when the distance decreases the repulsion force increases.
99 percent of the earth's atmosphere by mass is made up of only elements. These elements are
A)Carbon and oxygen
B)Nitrogen and oxygen
C)Hydrogen and oxygen
D) Helium and hydrogen
The correct answer is B) Nitrogen and oxygen
Explanation:
The atmosphere refers to the gaseous layer that covers a body such as a planet. The composition of the atmosphere varies according to the planet or body and therefore the elements found on it are different. In the case of our planet, the atmosphere is mainly composed of nitrogen and oxygen as these are 99% of the atmosphere, while other elements such as carbon dioxide represent the 1% missing. Also, the atmosphere is divided into different layers according to heigh this includes the troposphere, stratosphere, among others. Thus, 99 percent of the Earth's atmosphere is made up only of nitrogen and oxygen.
Question 4 of 10 (1 point) Jump to Question: Choose the word that best completes this sentence. A personal fall arrest system is the most ________ type of fall arrest in construction. A. Common B. Expensive C. Necessary D. Useful
Answer:
A. Common
Explanation:
A personal fall arrest system is the most common type of fall arrest in construction. Personal fall arrest systems are used as protection for OSHA workers who work on construction sites and are exposed to vertical drops of six feet or more. These systems consist of a body harness, anchorage and connector.
Maglev trains, like the one shown in the picture, use magnet fields to travel up to 600 miles per hour. Magnets on the bottom of the train and on the tops of the rails have similar magnetic poles. Based on properties of magnets, how do these magnets affect the train?
A)The two magnetic fields repel each other, causing the train to levitate, or hover, above the rails.
B)The powerful magnets greatly reduce the force of gravity, resulting in less friction and greater speed.
C)The train is able to stop immediately because the magnets on the rails attract the magnets on the train.
D)Maglev trains have extremely powerful magnets, greatly decreasing the force of gravity and allowing them to float.
Answer:
Its C
Explanation:
thank me later
Which of the following is an accurate statement?
A. AC Generators produce current that is pulsating, but always remains positive.
B. Step-up voltage transformers have a lower number of turns in the primary than in the secondary winding.
C. DC Generators produce current with a voltage that changes from positive to negative.
D. Step-down voltage transformers have a different number of turns in the primary than in the secondary winding, so they change the incoming voltage to a higher voltage.
A certain aircraft has a liftoff speed of 127 km/h.
(a) What minimum constant acceleration does the aircraft require if it is to be airborne after a takeoff run of 277 m?
Final answer:
The minimum constant acceleration required for an aircraft to become airborne after a takeoff run of 277 meters is [tex]2.25 m/s^2[/tex] when converting the liftoff speed from km/h to m/s and applying the kinematic equation.
Explanation:
To determine the minimum constant acceleration required for an aircraft to become airborne after a takeoff run of 277 meters, we can use the kinematic equation:
[tex]$$ v^2 = u^2 + 2as $$[/tex]
Where:
v is the final velocity (liftoff speed), which needs to be converted from 127 km/h to m/s.
u is the initial velocity, which is 0 m/s since the aircraft starts from rest.
a is the acceleration, which we are trying to find.
s is the displacement, which is the distance of the takeoff run (277 m).
First, we convert the liftoff speed to m/s:
[tex]$$ 127 km/hr \times \frac{1000 m}{1 km} \times \frac{1 h}{3600 s} = 35.28 m/s $$[/tex]
Now we can use the kinematic equation to solve for a:
[tex]$$ 35.28^2 = 0^2 + 2a \times 277 $$ $$ a = \frac{35.28^2}{2 \times 277} = \frac{1244.6784}{554} = 2.2465 \frac{m}{s^2} $$[/tex]
The minimum constant acceleration required for the aircraft to be airborne is [tex]2.25 m/s^2[/tex] (rounded to two decimal places).
An astronaut has a mass of 74.0 kg. 1) how much would the astronaut weigh on mars where surface gravity is 38.0% of that on earth? (express your answer to three significant figures.)
In which of the following is no work done A.climbing stairs B.lifting a book C.pushing a shopping cart D.none of the above
The correct answer is D. none of the above. In all of the given options, work is done.
Explanation:The correct answer is D. none of the above. In all of the given options, work is done.
A. Climbing stairs: When you climb stairs, you are doing work against gravity. You are exerting a force to move your body against the force of gravity.B. Lifting a book: When you lift a book, you are also doing work against gravity. You are exerting a force to move the book against the force of gravity.C. Pushing a shopping cart: Pushing a shopping cart requires you to apply a force to move the cart, which is considered work.D. None of the above: This option is incorrect because work is done in all of the given options.Learn more about Work and force here:https://brainly.com/question/758238
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What is an intron?
A.) A part of DNA that codes for a functional protein
B.) A part of DNA that does not code for a functional protein
C.) The beginning part of the DNA molecule
D.) The end of part of the DNA molecule
Which statement is true about the electromagnetic spectrum? The visible spectrum includes radio waves, light, and gamma rays. The colors you can see have the same wavelength. It has a range of visible and invisible forms of radiation. The waves travel at the speed of 2.998×105 meters/second.
Answer: It has a range of visible and invisible forms of radiation.
Explanation:
Electromagnetic wave is defined as the wave which is associated with both electrical and magnetic component associated with them. They can travel in vacuum as well and travel with the speed of light i.e [tex]2.998\times 10^8ms^{-1}[/tex]
The electromagnetic radiations consist of radio waves, microwaves, infrared ,Visible , ultraviolet, X rays and gamma rays arranged in order of increasing frequency and decreasing wavelengths.
Only visible light is visible to naked eyes.
The relationship between wavelength and frequency of the wave follows the equation:
[tex]\nu=\frac{c}{\lambda}[/tex]
where,
[tex]\nu[/tex] = frequency of the wave
c = speed of light
[tex]\lambda [/tex] = wavelength of the wave
From the above relation, it is visible that wavelength and frequency follow inverse relation. For increase in wavelength, the value of frequency decreases and vice-versa.
A dog pulls on it's leash with a 10-N force to the left, but doesn't move. Identify the reaction force.
Assuming atmospheric pressure to be 1.01 x 10^5 Pa and the density of sea water to be 1025 kg/m^3, what is the absolute pressure at a depth of 15.0 m below the surface of the ocean?
The absolute pressure at a depth of 15.0m below the surface of the ocean is 150975 Pa.
Explanation:To calculate the absolute pressure at a depth of 15.0m below the surface of the ocean, we need to consider the pressure due to the weight of the water column above that point.
The pressure due to the weight of a fluid is given by the equation P = ρgh, where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth.
Substituting the given values, we have P = (1025 kg/m3) × (9.8 m/s2) × (15.0m) = 150975 Pa.
Therefore, the absolute pressure at a depth of 15.0m below the surface of the ocean is 150975 Pa.
Suppose you have a 150-kg wooden crate resting on a wood floor. (a) what maximum force (in n) can you exert horizontally on the crate without moving it?
Final answer:
In physics, the maximum static frictional force equals the coefficient of static friction times the normal force. Once the crate starts slipping, the force of kinetic friction applies, and acceleration can be calculated using Newton's second law of motion.
Explanation:
The question involves concepts from Physics, specifically dealing with static friction and Newton's second law of motion. The maximum force that can be exerted on a wooden crate without moving it is equal to the maximum static frictional force. This force can be found by multiplying the coefficient of static friction (μ) between the wooden crate and the wood floor by the normal force, which, in this case, is equal to the gravitational force acting on the crate (mass × acceleration due to gravity, g).
If the static frictional force is overcome and the crate begins to slide, and assuming the applied force remains constant, we switch to dealing with kinetic friction. The magnitude of kinetic friction is usually lower than static friction. To find the acceleration of the crate once it starts moving, you would subtract the kinetic friction force from the applied force and then divide by the crate's mass, according to Newton's second law (F = ma).
For example, consider the question (a) What is the maximum force you can exert horizontally on a 120-kg wooden crate without moving it? The answer would be the product of the coefficient of static friction and the normal force, which equals the weight of the crate. If given (for example, μ=0.5), the calculation would be 588 N. For part (b), if the creates starts to slip, we then use Newton's second law to determine the magnitude of the crate's acceleration, which would be the net force divided by the crate's mass, resulting in an acceleration of 1.96 m/s².
A child bounces a 56 g superball on the sidewalk. the velocity change of the superball is from 20 m/s downward to 13 m/s upward. if the contact time with the sidewalk is 1 800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? answer in units of n.
A hair dryer draws 14.5 a when plugged into a 120-v line. assume direct current.
(a) What is its resistance? Express your answer to two significant figures and include the appropriate units."
(b) How much charge passes through it in 11 min ? Express your answer to two significant figures and include the appropriate units.
Solution
(a) We can calculate the resistance by using Ohm's law:
[tex]\Delta V= I R[/tex]
Since we know that [tex]\Delta V=120 V[/tex] and [tex]I=14.5 A[/tex], we can find R:
[tex]R= \frac{\Delta V}{I} = \frac{120 V}{14.5 A}=8.3 \Omega [/tex]
(b) The current is equal to the quantity of charge by unit of time:
[tex]I= \frac{Q}{t} [/tex]
In our problem, t=11min=660 s, so we can calculate the charge passed through the hair dryer:
[tex]Q=It=14.5 A \cdot 660 s = 9570 C[/tex]
You are the juror of a case involving a drunken driver whose 1041 kg sports car ran into a stationary 1928 kg station wagon stopped at a red traffic light. the cars stuck together and slid with locked wheels for 12.0 m before coming to rest. the coefficient of sliding friction on the dry road was 0.60. estimate the speed of the sports car when it hit the station wagon.
If a ball is given an initial speed of 15 m/s on a horizontal, frictionless surface, how fast will the ball be rolling in 5 seconds?
Answer:
15 m/s
Explanation:
A motorist is traveling at 20 m/s. He is 60 m from a stoplight when he sees it turn yellow. Is reaction time, before stepping on the brake, is 0.50 s. What steady acceleration (slowing down) while braking will bring him to a stop right at the light?
Final answer:
A motorist traveling at 20 m/s and located 60 m from a yellow stoplight needs a steady deceleration of 4 m/s², after a reaction time of 0.50 s, to stop precisely at the light.
Explanation:
A motorist is traveling at 20 m/s and is 60 m from a stoplight when it turns yellow. The motorist's reaction time is 0.50 s before stepping on the brake. We need to calculate the steady acceleration (slowing down) required to stop the car right at the light.
First, calculate the distance covered during the reaction time. Since the car continues at its initial speed during the motorist's reaction time, the distance covered is:
D_{reaction} = v × t = 20 m/s × 0.50 s = 10 m
This means the remaining distance to be covered under deceleration is 60 m - 10 m = 50 m.
Next, we use the kinematic equation v^2 = u^2 + 2as, where
v = final velocity (0 m/s, since the car stops),
u = initial velocity (20 m/s),
a = acceleration,
s = distance covered under deceleration (50 m).
Rearranging the equation for a, we get:
a = (v^2 - u^2) / (2s) = (0^2 - 20^2) / (2 × 50) = -400 / 100 = -4 m/s².
Therefore, a steady deceleration of 4 m/s² would be necessary for the motorist to stop right at the stoplight.
Which of the following occurs at the SLOWEST rate? A) deposition B) earthquake C) flood D) landslide
Suppose you had a parallel circuit with several identical light bulbs of equal resistance. if one bulb goes bad (or is disconnected), what happens to the brightness of the other bulbs?
In a parallel circuit, the brightness of the remaining bulbs isn't affected when one bulb goes bad or is disconnected. This is because each bulb has its own path to the voltage source, and neither the voltage nor the redistributed current through each bulb is affected by the removal of one bulb. Contrarily, in a series circuit, all bulbs would go dark.
Explanation:In a parallel circuit with several identical light bulbs of equal resistance, when one bulb goes bad or is disconnected, it doesn't affect the brightness of the other bulbs. This is because in a parallel circuit, each bulb has its own separate path to the voltage source. Therefore, the removal of one path (the bad or disconnected bulb) doesn't affect the potential difference or voltage across the other bulbs.
Let's take the two primary variables determining the brightness of a bulb - the voltage and current. In a parallel circuit, the voltage across each bulb remains the same, regardless of whether a bulb is removed or not. On the other hand, current, though different for each bulb depending on its resistance, isn't affected by the removal of one bulb because the total current just gets redistributed through the remaining paths, maintaining the original brightness of the other bulbs.
In contrast, if this were a series circuit, the scenario would be different. In a series circuit, the removal or failure of one bulb would disrupt the entire circuit (since there's only one path for the current to flow), causing all other bulbs to go dark.
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What is the frequency of a clock waveform whose period is 750 microseconds?
Water is to be pumped to the top of a building that is 366 m high. If the density of water is 1.00 x 10^3 kg/m^3, what amount of pressure is needed in the water line at the base of the building to raise the water to this height?
a.
1.26 x 10^6 Pa
b.
3.59 x 10^6 Pa
c.
5.39 x 10^6 Pa
d.
2.84 x 10^6 Pa
What is the purpose of the zigzag line on the periodic table
Answer : The purpose of the zigzag line on the periodic table is to separates the metal from the non-metal.
Explanation :
Metalloids : These are the elements that shows both the property of metals and non-metals.
For example : Boron, silicon, germanium, arsenic, antimony, tellurium, polonium and astatine are the metalloids.
Metalloids separates the metals from the non-metals.
The zigzag line on the periodic table represent the metalloids.
Non-metals are found to the right side of the zigzag line that gains electrons to attain stability.
Metals are found to the left side of the zigzag line that loses electrons to attain stability.
Hence, the purpose of the zigzag line on the periodic table is to separates the metal from the non-metal.
the planet jupiter revolves around the sun in a period of about 12 years (3.79 × 108 seconds). what is its mean distance from the center of the sun? the mass of the sun is 1.99 × 1030 kilograms.
The mean distance between the center of the Jupiter and the center of the Sun is "7.85 x 10¹¹ m"
The force of gravitation between the Sun and Jupiter must be equal to the centripetal force between them, for the equilibrium revolution of Jupiter around the Sun.
[tex]Centripeta\ Force\ on\ Jupiter = Gravitational\ Force\ of Attraction\ \\\\\frac{M_{Jupiter}v^2}{r} = \frac{GM_{Jupiter}M_{Sun}}{r^2}\\\\v^2 = \frac{GM_{Sun}}{r}\ -------- eqn(1)\\\\[/tex]
where,
G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
[tex]M_{Sun}[/tex] = Mass of Sun = 1.99 x 10³⁰ kg
r = mean distance between the center of the Jupiter and the Sun = ?
v = linear speed of the Jupiter around the Sun = [tex]\frac{Circumference\ of Jupiter's\ Path}{Time\ Period\ of\ Revolution}[/tex]
[tex]v = \frac{2\pi r}{3.79\ x\ 10^8\ s}\\\\v^2 = \frac{4\pi^2 r^2}{14.36\ x\ 10^{16}\ s^2}[/tex]
Using the values in eqn (1), we get:
[tex]\frac{4\pi^2 r^2}{14.36\ x\ 10^{16}\ s^2} = \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{r}\\\\r^3 = \frac{(14.36\ x\ 10^{16}\ s^2)(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{4\pi^2}\\\\r = \sqrt[3]{4.83\ x\ 10^{35}\ m^3}[/tex]
r = 7.85 x 10¹¹ m
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The attached picture shows the relationship between the centripetal force and the gravitational force acting on a planet (Jupiter) revolving around the sun.
Sound waves with large amplitudes push on the eardrum with more force and are heard as _______. Sound waves with small amplitudes push on the eardrum with less force and are heard as _______.
Alice and Marge are studying the properties of matter. The girls placed some an iron nail in a beaker containing water. Iron is a solid metal at room temperature. Iron is a shiny and malleable; it can be formed into shapes like the nails the girls used. Iron will turn reddish-brown in the presence of air or water as it rusts. Iron is a good conductor of electricity and heat. After 48 hours, the girls checked the nail in the water and compared it to the nail they left on the lab bench. Based on the girls' experiment, what is a chemical property of iron?
A) Iron is malleable. B) Iron rusts in water. C) Iron is a strong metal. D) Iron is a good conductor.
Answer: B) Iron rusts in water.
Explanation:
Physical property is defined as the property of a substance which becomes evident during physical changes. Example: Melting point , electrical conductivity, malleability,
Chemical property is defined as the property of a substance which becomes evident during chemical changes. Example: Reactivity with other substances
Rust is hydrated ferric oxide [tex](Fe_2O_3.xH_2O[/tex].
[tex]Fe\rightarrow Fe^{2+}+2e^-[/tex]
Corrosion of iron is called as rusting. Rust is hydrated ferric oxide [tex](Fe_2O_3.xH_2O[/tex].
[tex]Fe\righatarrow Fe^{2+}+2e^-[/tex]
[tex]O_2+4H^++4e^-\rightarrow 2H_2O[/tex]
[tex]4Fe^{2+}+O_2+4H_2O\rightarrow 2Fe_2O_3+8H^+[/tex]
Thus rusting of iron is a chemical property.
Answer: B) Iron rusts in water.
What are the magnitude and direction of the force the pitcher exerts on the ball? (enter your magnitude to at least one decimal place.)?
(a) Through what distance does it move before its release? (m)
(b) What are the magnitude and direction of the force the pitcher exerts on the ball? (Enter your magnitude to at least one decimal place.)"
Solution
(a) The pitcher accelerates the baseball from rest to a final velocity of [tex]v_f = 16.5 m/s[/tex], so [tex]\Delta v=16.5 m/s[/tex], in a time interval of [tex]\Delta t = 181 ms=0.181 s[/tex]. The acceleration of the ball in the horizontal direction (x-axis) is therefore
[tex]a_x = \frac{\Delta v}{\Delta t}= \frac{16.5 m/s}{0.181 s}=91.2 m/s^2 [/tex]
And the distance covered by the ball during this time interval, before it is released, is:
[tex]S= \frac{1}{2} a_x (\Delta t)^2 = \frac{1}{2} (91.2 m/s^2)(0.181 s)^2=1.49 m [/tex]
(b) For this part we need to consider also the weight of the ball, which is [tex]W=mg=2.28 N[/tex]
From this, we find its mass: [tex]m= \frac{W}{g}= \frac{2.28 N}{9.81 m/s^2}=0.23 Kg [/tex]
Now we can calculate the magnitude of the force the pitcher exerts on the ball. On the x-axis, we have
[tex]F_x = m a_x = (0.23 kg)(91.2 m/s^2)=20.98 N[/tex]
We also know that the ball is moving straight horizontally. This means that the vertical component of the force exerted by the pitcher must counterbalance the weight of the ball (acting downward), in order to have a net force of zero along the y-axis, and so:
[tex]F_y=W=mg=2.28 N[/tex] (upward)
So, the magnitude of the force is
[tex]F= \sqrt{F_x^2+F_y^2}= \sqrt{(20.98N)^2+(2.28N)^2}=21.2 N [/tex]
To find the direction, we should find the angle of F with respect to the horizontal. This is given by
[tex]\tan \alpha = \frac{F_y}{F_x}= \frac{2.28 N}{20.98 N}=0.11 [/tex]
From which we find [tex]\alpha=6.2^{\circ}[/tex]