there were 50 rabbits on an island. After three months the number of rabbits had increased to 70. If the number of rabbits increased exponentially, answer the questions that follow:

A. in the equation above (where t is in months:, find the value of the growth rate k. (round k to 4 decimal places)

For this case we have that by definition, the equation of a line in the standard form is given by:

[tex]ax + by = c[/tex]

According to the statement we have the following equation of the line:

[tex]y + 1 = \frac {2} {5} (x + 3)[/tex]

We manipulate algebraically to write in the standard form. To do this we follow the steps below:

We apply distributive property on the right side of the equation:[tex]y + 1 = \frac {2} {5} x + \frac {6} {5}[/tex]

We subtract [tex]\frac {6} {5}[/tex] on both sides of the equation:

[tex]y + 1- \frac {6} {5} = \frac {2} {5} x\\y- \frac {1} {5} = \frac {2} {5} x[/tex]

We multiply by 5 on both sides of the equation:

[tex]5y-1 = 2x[/tex]

We subtract 5y on both sides of the equation:

[tex]2x-5y = -1[/tex]

Finally, the equation in its standard form is:

[tex]2x-5y = -1[/tex]

Answer:

[tex]2x-5y = -1[/tex]

The last house on Oak Street has a house number 8 greater than the last house on Maple Street.

The correct answer is option C.

Let's denote the house numbers on Maple Street as M1, M2, M3, M4, and M5, where each house number is six more than the one to its left. Similarly, on Oak Street, denote the house numbers as O1, O2, O3, O4, and O5, where each house number is eight more than the one to its left.

For Maple Street:

M2 = M1 + 6

M3 = M2 + 6

M4 = M3 + 6

M5 = M4 + 6

For Oak Street:

O2 = O1 + 8

O3 = O2 + 8

O4 = O3 + 8

O5 = O4 + 8

Now, let's find the difference between the last house on Oak Street (O5) and the last house on Maple Street (M5):

The difference is (O4 + 8) - (M4 + 6) = (O3 + 8 + 8) - (M3 + 6 + 6) = (O2 + 8 + 8 + 8) - (M2 + 6 + 6 + 6) = (O1 + 8 + 8 + 8 + 8) - (M1 + 6 + 6 + 6 + 6).

Simplifying the expression, the constant terms cancel out, leaving:

The difference is O1 - M1 + (8 + 8 + 8 + 8) - (6 + 6 + 6 + 6) = O1 - M1 + 32 - 24 = O1 - M1 + 8.

So, the house number of the last house on Oak Street is 8 greater than the house number of the last house on Maple Street.

The question probable may be;

The picture below shows 5 houses on maple street anf the five houses on oak street.

Each house number on maple street is six more than the house number to its left. Each house number on oak street is eigth more than the house number to its left.

How much greater is the house number of the last house on oak street than the house number of the last house on maple street?

2

6

8

10

Answer:

The distance between the two buildings is 9.563 yards.

Step-by-step explanation:

See the diagram attached.

AB and CD are two buildings AC distance apart.

Now, AC = ED.

The angle of depression of clothesline BD is 17 Degrees.

Now, given that  BD = 10 yards.

And ∠ OBD = ∠ BDE = 17°  {Alternate angles}

Now, from the right triangle Δ BED, we have  

[tex]\cos 17 = \frac{ED}{BD} = \frac{ED}{10}[/tex]

⇒ ED = 10 cos 17 = 9.563 yards.

Therefore, the distance between the two buildings is 9.563 yards. (Answer)

The trampoline will attract a sales tax of $12 which will take its total price to $312.

The trampoline costs $300 without taxes being accounted for yet.

The tax is 4%. In dollar terms this is:

= Sales tax percentage x Cost of trampoline

= 4% x 300

= $12

The total price of the trampoline will therefore be:

= Cost of trampoline + sales tax

= 300 + 12

= $312

In conclusion, the sales tax would be $12 and the total price would be $312.

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Answer:

The correct answer is C = It gives reliable results

Answer:

D. it excludes those who are indifferent

Step-by-step explanation:

Answer:

$3.50

Step-by-step explanation:

15.00 - 7.00 = 8.00

6 x .75 = 4.50

8.00- 4.5 = 3.50

The equation for the total amount for the fair and rides is given by the relation y = 0.75n + 7  where n is the total number of rides

The amount left after purchasing 6 tokens is $ 3.50

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the total amount be represented as = y

Now , the number of rides be = n

The cost of entry fee = $ 7

The cost for each ride = $ 0.75

The total amount available = $ 15

So , the equation will be

total amount = cost for each ride x number of rides + cost of entry fee

Substituting the values in the equation , we get

Total amount y = 0.75n + 7

y = 0.75n + 7

So , the equation is y = 0.75n + 7

Now , when purchasing 6 tokens , we get the remaining amount as

Substituting the value of n = 6 in the equation , we get

y = 0.75 x 6 + 7

y = 4.5 + 7

y = $ 11.5

So , the amount left = 15 - y

The total amount left = 15 - 11.5

The total amount left = $ 3.50

Hence , The equation for the total amount for the fair and rides is given by the relation y = 0.75n + 7  where n is the total number of rides

The amount left after purchasing 6 tokens is $ 3.50

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Answer:

413 minutes of long distance calls

Step-by-step explanation:

$80.00 - $18.00 = $62.00

$62.00/$0.15 = 413.33

Answer:

i dont know

Step-by-step explanation:

i dont know

Answer:

Money spent on each student is $36.17

Step-by-step explanation:

$875.49 = 29 students & 4 teachers

33 people = $875.49

1 person = $26.53 (pass)

29 students = $279.56

1 student = $9.64 (lunch)

each student = $9.64 + $26.53

= $36.17

the amount spent on a pass and lunch for each student is approximately $26.56 + $9.63 = $36.19.

To find out how much money was spent on a pass and lunch for each student, we need to calculate the total amount spent on passes and lunch and then divide it by the total number of students.

Given:

- Total amount spent on passes for 29 students and 4 teachers: $875.49

- Total amount spent on lunch for just the students: $279.56

- Total number of students: 29

1. First, let's find the total amount spent on passes for just the students:

  Total amount spent on passes for students and teachers = $875.49

  Total amount spent on passes for 4 teachers = ?

  Total amount spent on passes for students = $875.49 - (amount spent on passes for teachers)

  Since each pass costs the same amount for students and teachers, we can divide the total amount spent on passes by the total number of passes (students + teachers) to find the cost per pass.

  Total number of passes (students + teachers) = 29 students + 4 teachers = 33 passes

  Cost per pass = Total amount spent on passes / Total number of passes

                = $875.49 / 33

                ≈ $26.56 (rounded to two decimal places)

2. Now, let's find out how much money was spent on lunch for each student:

  Total amount spent on lunch for students = $279.56

  Cost per student for lunch = Total amount spent on lunch for students / Total number of students

                              = $279.56 / 29

                              ≈ $9.63 (rounded to two decimal places)

So, the amount spent on a pass and lunch for each student is approximately $26.56 + $9.63 = $36.19.

Answer:

Step-by-step explanation:

16

The value of x in the equation 3x + 7x + 9 = 35 is 2.6 after simplification and carrying out the necessary algebraic steps.

The subject of your question is Mathematics, specifically algebra. Now, let's solve the equation: 3x + 7x + 9 = 35.

To start, combine like terms on the left side of the equation. That gives us 10x + 9 = 35. Next, subtract 9 from both sides to isolate the term with x. This gives us 10x = 26. Finally, divide both sides by 10 to find the value of x. So, x = 2.6.

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Answer:

13x-12 the last one

Step-by-step explanation:

Answer:

13x-12

Step-by-step explanation:

4(3x-5)+x+8

12x-20 +x+8

13x-12

The graph of the line that contains the point ( − 6 , 1 ) and has a slope of 5 is shown below in the attachment.

How to graph a line?

To graph a line with a given point (-6, 1) and a slope of 5 without explicitly finding the equation, you can start from the given point (-6, 1) and use the slope (5) to find other points.

Move up by 5 units (rise) and to the right by 1 unit (run) from the given point, and you'll get another point on the line. Repeat this process to plot multiple points and then connect them to graph the line.

The graph of the line is attached below.

Answer:

No Solution.

Step-by-step explanation:

-(6x-5)=-6x+13

-6x+5=-6x+13

-6x-(-6x)+5=13

-6x+6x+5=13

0+5=13

5=13

Answer:

Exact form : x=-1/3

Decimal form : x=-0.3 (line over the 3!!!)

Step-by-step explanation: Isolate the variable by divinding each side by factors that don't contain the variable.

Hope this helps you out! ☺

Answer: m = -120

Step-by-step explanation: In this equation, m is being multiplied by -0.06 so we will need to divide both sides of the equation in order to get m b itself.

On the left side of the equation, the -0.06's cancel and we are left with m. On the right side of the equation, we divide -7.2 by -0.06 and we get -120.

Now we have m = -120

Don't just do this problem in your head. It's extremely important to develop the habit of putting all your steps down on paper/or digitally too. It will really pay off for you down the line.

Image provided.

Answer:

They need to make 5 pies for 15 people.

Step-by-step explanation:

15*3=45 slices of pie in total,

each pie is cut into 9 slices,

45/9=5 pies

Answer:

b

Step-by-step explanation:

Answer:

8/13.

There's 12 face cards & 26 black cards. In the 26 black cards, theres 6 face cards. Theres 32 cards overall that is either a black card or a face card. So in conclusion the answer is 8/13 because 52 (the total amt in the deck) divided by 32 = 8/13.

The probability of randomly selecting either a face card or a spade from a standard deck of 52 playing cards is approximately 0.4231.

The question involves calculating the probability of selecting either a face card or a spade from a standard deck of 52 playing cards. A standard deck consists of four suits (spades, hearts, diamonds, clubs), each with 13 cards, making a total of 52 cards. Among these, 12 are face cards (Jacks, Queens, Kings across all suits), and 13 are spades (including the spade face cards).

First, note that there are 3 face cards (Jack, Queen, King) in each suit, resulting in 12 face cards in total. However, 3 of these face cards are spades, and we must avoid double-counting them when adding the spade cards. Therefore, we have 12 face cards and 10 non-face card spades (since 3 spades are already counted among face cards), giving us a total of 22 unique cards that fulfill the conditions.

The probability of drawing either a spade or a face card from a deck of 52 cards is calculated by dividing the number of favorable outcomes (22) by the total number of outcomes (52), which is 22/52 or approximately 0.4231.

Alright, so we have the difference = 4500-2800=1700. To find the percent increase, we do 1700/2800=around 0.61 = around 61% percent. Hope I helped! ☺☼

Answer:

○ A. Graph C

Step-by-step explanation:

Starting from the y-intercept of [tex]\displaystyle [0, -4],[/tex]you do [tex]\displaystyle \frac{rise}{run}[/tex]by either moving one block south over four blocks west or one block north over four blocks east. Now, you have to figure out which graph follows the inequality symbol in the inequality. In this case, two answer choices match this because the less than inequality will result in a dashed line, so we can automatically eliminate answer choices D. and B.. Now, to figure out our graph once in for all, we need to use the zero-interval test [test point [0, 0]] to ensure if we either shade the opposite portion [the portion that does NOT contain the origin] or the portion that DOES contain the origin. We then need to verify it as false or true:

[tex]\displaystyle 0 < \frac{1}{3}[0] - 4 → 0 ≮ -4[/tex]

This is a FALSE statement, so instead of shading above the dashed line, we shade below the dashed line, and that answer choice is A..

>, < → Dashed Line

≥, ≤ → Solid Line

I am joyous to assist you anytime.

Answer:

Step-by-step explanation:

y ≤ x − 5

1<10-5

1<5

Pair: (10,1)

y ≤ −x − 4

-10<-1-5

-10<-6

Pair: (1,-10)

Answer:

Step-by-step explanation:

If we graph this system of inequalities, we could find the solution.

From the graph you can deduct that the only right answer is the last one (1,-10), because the area of solution is only for negative values of y.

Therefore, the right choice is the last one.

If you can't graph, you can try another method. If we replace the value in the system, it should satisfy it, that is, it should gives us a true result like 0<1 for example. Let's try

For x=1 and y=-10, we have

-10 ≤ 1 − 5

-10 ≤ −1 − 4

-10 ≤ -4

-10 ≤ -5

As you can see, the result is true, because -10 is less than -4 and -5, so that's the right answer.

Mitch paid $ 33600 altogether

Given that mitch took out a school laon for $ 24000

The interest rate on the loan was 8%

Number of years = 5

To find: total amount paid altogether

We can use simple interest to calculate the total amount

Total amount paid altogether = simple interest + principal amount

The simple interest is calculated as:

[tex]\text { simple interest }=\frac{\text { principal } \times \text {rate of interest } \times \text {number of years}}{100}[/tex]

Plugging in values, we get

[tex]\text { simple interest }=\frac{24000 \times 8 \times 5}{100}=240 \times 8 \times 5=9600[/tex]

Total amount paid altogether = simple interest + principal amount

Total amount paid altogether = 9600 + 24000 = 33600

Thus Mitch paid $ 33600 altogether

Step-by-step explanation:

If [tex]mKg[/tex] of mass is placed on spring with spring constant [tex]k[/tex],

[tex]mg=kx[/tex]

where [tex]g[/tex] is universal gravitational constant

[tex]x[/tex] is the displacement in the spring.

In case 1:

[tex]25g=k(0.15)\\k=\frac{25g}{0.15}[/tex]

In case 2:

[tex]mg=k(0.23)[/tex]

Using  result from case 1,

[tex]mg=\frac{25g}{0.15}\times 0.23[/tex]

[tex]m=[/tex][tex]38.33Kg[/tex]

Step-by-step explanation:

1.-92%

2.40%

3.-76%

4.65%

The percent changes for each scenario is: 1. From 1000 to 80: -92% 2. From 45 to 63: +40% 3. From 250 to 60: -76% 4. From 60 to 99: +65%.

To calculate the percent change between two values, we use the formula:

[tex]\[ \text{Percent Change} = \left( \frac{\text{New Value} - \text{Original Value}}{\text{Original Value}} \right) \times 100\% \][/tex]

1. The percent change from 1000 to 80 is calculated as follows:

[tex]\[ \text{Percent Change} = \left( \frac{80 - 1000}{1000} \right) \times 100\% = \left( \frac{-920}{1000} \right) \times 100\% = -92\% \][/tex]

So, the percent change is a 92% decrease.

2. The percent change from 45 to 63 is calculated as follows:

[tex]\[ \text{Percent Change} = \left( \frac{63 - 45}{45} \right) \times 100\% = \left( \frac{18}{45} \right) \times 100\% = \frac{2}{5} \times 100\% = 40\% \][/tex]

So, the percent change is a 40% increase.

3. The percent change from 250 to 60 is calculated as follows:

[tex]\[ \text{Percent Change} = \left( \frac{60 - 250}{250} \right) \times 100\% = \left( \frac{-190}{250} \right) \times 100\% = -76\% \][/tex]

So, the percent change is a 76% decrease.

4. The percent change from 60 to 99 is calculated as follows:

[tex]\[ \text{Percent Change} = \left( \frac{99 - 60}{60} \right) \times 100\% = \left( \frac{39}{60} \right) \times 100\% = \frac{13}{20} \times 100\% = 65\% \][/tex]

So, the percent change is a 65% increase.

Answer:

g(x) = |x+3| - 5

Step-by-step explanation:

Let y = f(x)

⇒y = |x+3|

When y is replaced by Y + k, the graph of y = f(x) shifts k units down

⇒ y replaced by Y + 5 translates the graph of y = f(x) 5 units down

∴ Y = g(x) is represented by Y + 5 = |x+3|

⇒ Y = |x+3| - 5

or g(x) = |x+3| - 5

Answer:

2 scrapbook pages

I found the answer online

Aylin can create a maximum of 19 scrapbook pages by dividing the total number of items by the number of items on each page.

Aylin wants to set up all the pages of her scrapbook in the same way, with a combination of photos and newspaper clippings on every page.

She wants to make sure that no items are left over.

To find the greatest number of scrapbook pages Aylin can create, we need to divide the total number of items -

= 18 photos + 20 newspaper clippings

= 38 items

Now,

Since she wants each page to have the same combination, we can find the greatest common divisor (GCD) of 18 and 20, which is 2.

Therefore, Aylin can create a maximum of 38/2 = 19 scrapbook pages.

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Answer: Matt's rate is 2 pages per hour.

Step-by-step explanation:

25 hours = 45 pages

1. First, let's divide 45 by 25 to find how much it takes for one page to be done: [tex]\frac{45}{25}[/tex] = 1.8

2. This answer means it takes 1.8 hours to do one page.

3. Now, we can choose to round 1.8, which is 2.

Answer:

Area = 12 ft²

Step-by-step explanation:

Convert values to feet

12 inches = 1 foot

48 / 12 = 4 feet

36 / 12 = 3 feet

Area = l x w = 3 x 4 = 12 ft²

Answer: The answer is 1,728 in. squared

Step-by-step explanation:

All you do is multiply 48 by 36 because in order to get area,you multiply base and height.

Answer:

2462.4 square inches

Step-by-step explanation:

To find the length of the longer wall use the following ratio and solve for x.

x/36= 4.75/ 2.5

x= 68.4

Area of a rectangle = l(w)

68.4(36)= 2462.4 square inches

The area of the wall is the product of its dimension.

The area of the actual wall is  2462.4 square inches

The scale is given as:

[tex]\mathbf{Scale = 4.75 : 2.5}[/tex]

The shorter side of the actual wall is 36 inches.

So, we have:

[tex]\mathbf{Long : 36= 4.75 : 2.5}[/tex]

Express as fractions:

[tex]\mathbf{\frac{Long }{36}= \frac{4.75 }{ 2.5}}[/tex]

Multiply both sides by 36

[tex]\mathbf{Long= 36 \times \frac{4.75 }{ 2.5}}[/tex]

[tex]\mathbf{Long= 68.4}[/tex]

So, we have:

[tex]\mathbf{Long= 68.4}[/tex]

[tex]\mathbf{Short= 36}[/tex]

The area is then calculated as:

[tex]\mathbf{Area = 68.4 \times 36}[/tex]

[tex]\mathbf{Area = 2462.4in^2}[/tex]

Hence, the area of the actual wall is  2462.4 square inches

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