Answers
6 days = 1 shed
1 day = 1/6 shed
Mark:
8 days = 1 shed
1 day = 1/8 shed
Together:
1 day = 1/6 + 1/8 shed
Ans: 1/6d + 1/8d = 1
Kaitlyn = 1/6
Mark = 1/8
Then,
d = number of days.
The equation then if they work together is:
1 / 6d + 1 / 8d = 1
answer:
the equation for number of days it would take to build the sheld together is
1 / 6d + 1 / 8d = 1
Related Questions
a pyramid has a square base. Its volume is 48 cubic centimeters and its height 4 centimeters. What is the length of one side og the base?
Answers
B = ???
h = 4 cm
V = 48 cm^3
48 = 1/3 * B * 4 Multiply both sides by 3
48 * 3 = B * 4
144 = B * 4 Divide by 4
144/4 = B
36 = B
Since the base is a square the area of the base = s^2
s^2 = 36
Sqrt(s^2) = sqrt(36)
s = 6 cm <<<<==== answer.
simplify the complex fraction
Answers
the final answer is (y+z)/(y-z)
What is 3^2/3 equal to? A.3√9 B.2√9 C.3√27 D.2√27
Answers
[tex] 3^{\frac{2}{3}} = \sqrt[3] {3^2} = \sqrt[3] {9} [/tex]
At noon, ship a is 60 km west of ship
b. ship a is sailing south at 15 km/h and ship b is sailing north at 5 km/h. how fast is the distance between the ships changing at 4:00 pm?
Answers
base of our triangle if drawn is 60 km
to find dD/dt when t=4 hours we shall have:
(A+B)²+60²=D²
d/dt[(A+B)²+60²]=d/dt(D²)
[d(A+B)]/dt*2(A+B)(2)=dD/dt*2D
B=5km/h*4hr=20km
A=15km/hr*4=60km
20²+60²=D²
D=√4000
(15+5)*(2)*80*(2)=2*√4000*dD/dt
dD/dt=6400/√4000=101.192 km/hr
The two ships are sailing in opposite sides, Hence, the resultant speed is given by 15+5 = 20 km/hr.
Therefore, from the below triangle, we have
[tex]\frac{dx}{dt} = 20 \text{ km/hr}[/tex]
Let the distance between the ships is y. On applying Pythagorous theorem, we have
[tex]y^2=x^2+60^2\\ \text{On differentiating, we get}\\ 2y\frac{dy}{dt} =2x\frac{dx}{dt}\\\frac{dy}{dt}= \frac{x}{y} \frac{dx}{dt}[/tex]
On substituting the value of y as [tex]y=\sqrt{60^2+x^2}[/tex]
[tex]\frac{dy}{dt} =\frac{x}{\sqrt{60^2+x^2}} \frac{dx}{dt}[/tex]
Since, the at noon the ship is 60 km to each other. Hence, for 4 PM, i.e. t=4, we have
[tex]x=4 \times \frac{dx}{dt} \\ x= 4 \times 20 \\x=80[/tex]
On substituting the value in above, we get
[tex]\frac{dy}{dt} =\frac{80}{\sqrt{60^2+80^2}} (20[/tex]
[tex]\frac{dy}{dt} = 16.0 \text{ km/hr}[/tex]
Therefore, the distance between the ships changing at a rate of 16 km/hr at 4:00 pm
Consider a binomial experiment with n = 7 trials where the probability of success on a single trial is p = 0.35. (round your answers to three decimal places.) (a) find p(r = 0). (b) find p(r ≥ 1) by using the complement rule.
Answers
b) If the result does NOT have zero successes, then we automatically know that there must have been at least 1 successful result (it could be anything from 1 to 7). Therefore if the probability of having 0 successes is 0.0490, then the probability of having at least 1 is 1 - 0.0490 = 0.951.
Answer:
yes
Step-by-step explanation:
The Bureau of Justice Statistics reports that the number of Americans on probation increased 76% from 1980 to 1995 and that 3.09 million Americans were on probation in 1995. If the rate of increase continues in the same way for the next 15-year period, what might be the number of Americans on probation in 2010?
Answers
x: current number of Americans.
y: number of Americans after the next 15 years.
We now write the expression to model the problem, assuming:
"the rate of increase continues in the same way for the next 15-year period".
We have then:
y = 1.76 * x
y = 1.76 * (3.09)
y = 5.44 million Americans
Answer:
the number of Americans on probation in 2010 might be:
y = 5.44 million Americans
3^2•3^n simplifies to 3^20 what is the value of the exponent n?
Answers
[tex]3^2 \times 3^n = 3^20 [/tex]
Solving for n.
Divide both sides by 3²
[tex] \frac{3^2 \times 3^n}{3^2} = \frac{3^{20}}{3^2} [/tex]
Simplify
[tex]3^n= 3^{20-2} \\ 3^n=3^{18} \\[/tex]
[tex]if \ a^{f(x)}=a^{g(x)} , \ then \ f(x)=g(x)[/tex]
So, n=18
Answer: n=18
and are similar. Find the value of x. A. 5 B. 15 C. 60 D. 240
Answers
Alicia buys a 5 pound bag of rocks for fish tank. She uses 1 1/8 pounds for a small fish bowl. How much is left
Answers
Here is your answer:
The proper answer to this question is "4".
Here is how:
First convert the mix number into a fraction:
1 1/8=9/8
5*8=40
1*8=8
-
9*1=9
8*1=8
40-8=32
32/8=4
8/8=1
Which means your answer is 4/1 or 4!
If you need anymore help feel free to ask me!
Hope this helps!
how much difference is there between investing $5,000 at 4% simple interest for 5 years and investing that same amount at 4% compounded quarterly
Answers
- Simple interest formula: [tex]A=P(1+rt)[/tex]
where
[tex]A[/tex] is the final investment value
[tex]P[/tex] is the initial investment
[tex]r[/tex] is the interest rate in decimal form
[tex]t[/tex] is the time in years
For our problem we know that [tex]P=5000[/tex], [tex]r= \frac{4}{100} =0.04[/tex], and [tex]t=5[/tex], so lets replace those values in our simple interest formula to find [tex]A[/tex]:
[tex]A=5000(1+(0.04)(5))[/tex]
[tex]A=5000(1.2)[/tex]
[tex]A=6000[/tex]
Now that we know the final investment value of our simple interest investment, lets use the compound interest formula to find the final investment value of the other one:
- Compound interest formula: [tex]A=P(1+ \frac{r}{n})^{nt} [/tex]
where
[tex]A[/tex] is the final investment value
[tex]P[/tex] is the initial investment
[tex]r[/tex] is the interest rate in decimal form
[tex]n[/tex] is the number of times the interest is compounded per year
[tex]t[/tex] is the time in years
For our problem we know that [tex]P=5000[/tex], [tex]r= \frac{4}{100} =0.04[/tex], and [tex]t=5[/tex]. Since we know that the interest is compounded quarterly (each 4 months), it mean that is compounded [tex] \frac{12months}{4months} =3[/tex] times per year, so [tex]n=3[/tex]. Now that we have all the vales, lets replace them in our formula:
[tex]A=5000(1+ \frac{0.04}{3} )^{(3)(5)} [/tex]
[tex]A=5000(1+ \frac{0.04}{3} )^{15} [/tex]
[tex]A=6098.95[/tex]
now that we know the final amounts of our investments, lets find how much difference is between them:
[tex]6098.95-6000=98.95[/tex]
We can conclude that the difference between invest $5000 in a compound interest investment vs a simple interest investment is $98.95.
Can somebody please help me out ?
Answers
A = (1/2) * b * h
Where
b: base
h: height.
For the lower triangle we have:
A = (1/2) * (10) * (root ((8) ^ 2- (5) ^ 2))
A = 31 in ^ 2
We add this area with the area of the upper triangle:
31 in ^ 2 + 17 in ^ 2 = 48 in ^ 2
Answer:
The quadrilateral area will be:
48 in ^ 2 (option 3)
A square playground has an area of 175 m2. What is the approximate length of each side of the playground? Round your answer to the nearest meter
Answers
Therefore, for a known area A, the side length is
side = √ (area)
= √ (175)
= 13.2288 (to 4 places of decimals).
If the area of a square playground is 175 [tex]m^{2}[/tex] then the approximate length is 13 meters.
What is square?A square is a two dimensional figure having four vertices, four edges, four angles and all the sides are equal to each other. The perimeter is equal is equal to 4*side and the area is side*side.
How to find side of square?We have been given the area of the square playground equal to 175 meter square. We know that the area of a square is side*side means [tex]side^{2}[/tex].
Put the value of 175 equal to side square and we will get the value of slide.
Area =[tex]side^{2}[/tex]
175=[tex]side^{2}[/tex]
side=[tex]\sqrt{175}[/tex]
Side=13.22m
If we round to nearest meter then it will be equal to 13m.
Hence if the area of a square playground is 175 meter square then the side will be equal to 13m.
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EXPERTS/ACE/GENIUSES
Answers
Rob cuts a 15-foot wire into 8 equal pieces. about how long is each piece?
Answers
15/8 = 1.875
Each piece is 1.875 foot long
hope this helps
I hope this helped! :-)
find the product 3012 and 4
Answers
Two forces with magnitudes of 25 and 30 pounds act on an object at angles of 10° and 100°, respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer.
Answers
It is best presented in the form of a table, where
x-component = Fcos(theta)
y-component = Fsin(theta)
For F=25 pounds, angle = 30
25cos(30)=21.65
Force angle x-component y-component
25 30 25cos(30)=21.65 25sin(30)=12.5
30 100 30cos(100)=-5.21 30sin(100)=29.54
Total Fx=16.44 Fy=42.04
Therefore angle = tan^(-1)(Fy/Fx)=tan^(-1)(42.04/16.44) = 68.64 °
magnitude = sqrt(Fx^2+Fy^2)=sqrt(16.44^2+42.04^2)=45.15 pounds
A slice is made perpendicular to the base of a right rectangular prism as shown.
What is the area of the resulting two-dimensional cross section?
Drag and drop the answer into the box.
mm²
48
28
84
144
16
Answers
Answer:
The correct option is 1. The area of cross section area is 48 mm².
Step-by-step explanation:
From the find it is noticed that the cross section is a rectangle with length 4 mm and width is 12 mm.
The area of a rectangle is the product of its dimensions.
[tex]A=l\times w[/tex]
Where, l is length of the rectangle and w is width of the rectangle.
The area of cross section is
[tex]A=4\times 12[/tex]
[tex]A=48[/tex]
Therefore the area of cross section area is 48 mm². Option 1 is correct.
Shelly has a photo that is 7 1/3 inches tall. she wants to shrink it down to fit in a picture frame that is only 5 1/3 inches tall. the photo shop can only reduce photos by certin fractions. they can reduce it to 2/3 the original size, 3/4 the original size, or 5/9 the original size. which reduction should she use so the picture fills as much of the frame as possible, without being too large?
Answers
the photo is 7 1/3 inches tall-----> 7 1/3=(7*3+1)/3=22/3 in ----- > (7.33 in)
the picture frame is 5 1/3 inches tall--> 5 1/3=(5*3+1)/3=16/3 in----> (5.33 in)
a) case A reduce 2/3 the original size------> (22/3)*(2/3)=44/9 in-----> (4.89 in)
b) case B reduce 3/4 the original size---> (22/3)*(3/4)=66/12 in-----> (5.5 in)
this is not solution because 66/12 (5.5 ) in >16/3 (5.33) in ( picture frame)
c) case C reduce 5/9 the original size---> (22/3)*(5/9)=110/27 in-----> (4.07 in)
the answer is the case A reduce 2/3 the original size----> 44/9 in (4.89 in)
The prism is completely filled with 1750 cubes that have edge length of 1/5 feet. What is the volume of the prism,
Answers
the volume one cube=(1/5)*(1/5)*(1/5)=(1/125) ft³
the volume of prism=1750*(1/125)=14 ft³
the answer is 14 ft³
A zoo has three panda bears and five giraffes. What is the ratio of panda bears to giraffes at that zoo?
Answers
This is a ratio:
x:y
The ratio asks for panda bears to giraffes.
panda bears= 3
giraffes= 5
3:5 <== the ratio
I hope this helps!
~kaikers
The answer is 3:5
Hope this helps!
Always remember, you are a Work Of Art!
- Nicole <3 :)
plz help ill give u branlist
Answers
so...
48 + 7(x + 1) = 90
7(x + 1) = 42
x + 1 = 6
x = 5
can someone please help me with this equation? thank you.
Answers
.. x +2y = 3 . . . . . . . . divide the given equation by 3
Now, the perpendicular line is easily written as
.. 2(x -(-4)) -(y -2) = 0 . . . . . swap x, y coefficients, negate one. Translate to the given point
Simplifying, we have
.. 2x -y +10 = 0
Solving for y gives
.. y = 2x +10 . . . . . . . . . . . . corresponds to selection B
Derek ran 3/8 of a race before he had to stop for a break. If the race is 6 miles long, did Derek run more than, less than, or equal to 6 miles before he took a break?
Answers
Find a vector equation and parametric equations for the line segment that joins p to q. p(1, −1, 7), q(7, 6, 1) vector equation r(t) = <1+6t,−1+7t,7−6t> parametric equations (x(t), y(t), z(t)) =
Answers
- vector equation: r(t) = <1 + 6t, -1 + 7t, 7 - 6t>
- parametric equations:
x = 1 + 6t
y = -1 + 7t
z = 7 - 6t
Explanation:
To obtain the vector equation, we first get a vector v that is parallel to the line. To get the vector v, we subtract p from q. So,
v = q - p
= (7,6,1) - (1,-1,7)
v = (6, 7, -6)
The vector equation of the line is given by
[tex]r(t) = v_0 + tv[/tex]
Where
[tex]v_0[/tex] = a point in the line (we choose point p(1,-1,7))
So, the equation of the line joining p and q is given by
[tex]r(t) = v_0 + tv \\ \indent = \left \langle 1, -1, 7 \right \rangle + t\left \langle 6, 7, -6 \right \rangle \\ \indent = \left \langle 1, -1, 7 \right \rangle + \left \langle 6t, 7t, -6t \right \rangle \\ \indent \boxed{r(t) = \left \langle 1 + 6t, 1 + 7t, 7 - 6t \right \rangle }[/tex]
In the parametric equation of the line, we just need to get the x, y and z coordinates in the vector equation.
Since the vector equation is given by
[tex]r(t) = \left \langle 1 + 6t, 1 + 7t, 7 - 6t \right \rangle[/tex]
The parametric equations of the line are given by:
[tex]x(t) = 1 + 6t \\y(t) = 1 + 7t \\z(t) = 7 - 6t[/tex]
The vector equation for the line segment joining the points p(1, -1, 7) and q(7, 6, 1) is r(t) = <1+6t, -1+7t, 7-6t> and the corresponding parametric equations are x(t) = 1 + 6t, y(t) = -1 + 7t, z(t) = 7 - 6t.
Explanation:To find the vector and parametric equations for the line segment joining two points p(1, -1, 7) and q(7, 6, 1), we first need to understand that the vector equation for a line segment in space is given by r(t) = p + t (q - p), where 0 ≤ t ≤ 1, and p and q are the coordinates of the points. The parametric equations are obtained by expressing the x, y, and z coordinates of r(t) as individual functions of t.
Substituting the given points into the vector equation we get: r(t) = <1+6t, -1+7t, 7-6t>. Then, the corresponding parametric equations will be x(t) = 1 + 6t, y(t) = -1 + 7t, and z(t) = 7 - 6t.
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6 Bands were going to play at a concert. How many ways can the concert manager send them on stage?
Answers
there are two ways to resolve this task:
1. the 1st in this sequence is for 6 bands, the 2d in this sequence is for 5 rest bands, the 3d in this sequence is for 4 rest bands, the 4th in this sequence is for rest 3 bands, the 5th in this sequence is for rest 2 bands and the 6th in this sequence is for the last 1 band. Using the logical rule 'AND': A=6*5*4*3*2*1=720.
2. According to arrangement rules it is the formula: A=n!, where n - number of bands.
A=6!=720.
answer: 720.
Please help me with this question
Answers
1. S=12²-10²=44 sq. ft.
2. S=10*12-6*8=120-48=72 sq. ft.
answers: 1-C; 2-C.
How many different possible outcomes are there when Jillana spins the spinner below and then flips the coin?
The spinner is from 1-6.
Answers
Answer:
There are total 12 outcomes
Step-by-step explanation:
The number of outcomes in spinning a spinner is 6 (getting a number from 1 to 6)
The number of outcomes in flipping a coin=2 (head or tail)
Hence, total 12 outcomes are possible which are:
(1,H) (2,H) (3,H) (4,H) (5,H) (6,H)
(1,T) (2,T) (3,T) (4,T) (5,T) (6,T)
The region r is bounded by the parabola y = x2 and the line y = 4. set up definite integrals to find the moment mx of r about the x-axis and the area a of the region r. then find (x, y )
Answers
Volume is 256π/5, area is 32/3.
Details are in the attachment.
P.S. intersection points are (-2;4) and (2;4).
A math test took 50 minutes to complete. The test ended at 3:55. What time did the test begin?
Answers
A math test ended at 3:55 and it took 50 minutes to complete. What time did the math test start?
The math test started at 3:05.
If we know that the math test ended at 3:55 and lasted 50 minutes, we can subtract 50 minutes from 3:55 and we will get an answer of 3:05.
Therefore, the math test started at 3:05.
how to do this 24:96 = 5:?
Answers
In that case, x=20