this math problem is hard

This Math Problem Is Hard

Answers

Answer 1
The answer is c. because ½ square + ½ square is 1 square.

Related Questions

Find the common ratio of the sequence
-125,-25,-5,-1.....

1/5

5

-100

100

Answers

common ratio  = -25/-125  = 1/5  answer

Answer:

Step-by-step explanation:

common ratio of a Geometric series can be found by dividing the second term by first term of the series .

we are given that first term a1= -125 and second term a2 =-25

so the common ratio must be

[tex]r=\frac{a2}{a1}[/tex]

[tex]r=\frac{-25}{-125}[/tex]

[tex]r= \frac{1}{5}[/tex]

Hence the common ratio is 1/5.

Jack and Jill are 20m apart. Jack sees the top of the building at 30 degrees and Jill sees the top of the building at 40 degrees. What is the height of the building

Answers

The height of the building seen by both Jack and Jill is 37m to the nearest whole metre.

Let the distance of Jill from the base of the building be represented with x while the height of the building be y so that by observation we get two right triangles with same opposite sides to the angles formed by Jack and Jill. We can solve for x and y using tangent of the angles as follows:

tan 40 = y/x {opposite/adjacent}

y = xtan40 {cross multiplication}

tan 30 = y/(20 + x)

y = tan30(20 + x)

Thus;

xtan40 = tan30(20 + x)

xtan40 = 20tan30 + xtan30

xtan40 - xtan30 = 20tan30 {collect like terms}

x(tan40 - tan30) = 20tan30

x = 20tan30/(tan40 - tan30)

x = 44.1230m

Putting the 44.1230m for x in y = xtan40 we have;

y = 44.1230m × tan40

y = 37.0236m.

Therefore, the height of the building approximately to the nearest whole metre is 37.

what is -10-6=?. Please I need an answer and it's my grade

Answers

-10 -6= -16
Because it’s like an opposite. 10+6=16 just add the - sign.
r=-4. -10-6 is -16.:)

Mr Thomas shoveled 12 1/2 yards of sand in 2 1/2 hours . At that rate how many yards did he shovel in one hour ?

Answers

1 hour is 2/5ths of 2 1/2 hours so multiply 12 1/2 by 2/5 = 5 yards
Five yards= 1 hour
1 hr + 1 hr = 10 yards
1/2 hr= 2.5 yards

solving radical equations
check for extraneous solutions
[tex] \sqrt{2x + 30} = x + 3[/tex]

Answers

I don’t know this question
[tex]\bf \sqrt{2x+30}=x+3\impliedby \textit{we'll squares both sides} \\\\\\ (\sqrt{2x+30})^2=(x+3)^2\implies 2x+30=x^2+6x+9 \\\\\\ 0=x^2+4x-21\implies 0=(x+7)(x-3)\implies x= \begin{cases} -7\\ 3 \end{cases}[/tex]

I don't see  an extraneous value there, -7 checks out well if you plug it in the original equation, and so does 3.

write a doubles fact that can help you solve 6+5=11

Answers

3X2+ 2.5X2 divide them by 2

51 divided by 3 is k

Answers

51 ÷ 3 = 17
K is 17

Have a nice day!

51 divided by 3 is k, the value of k is 17.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

Given;

51 divided by 3 is k

51/3=k

17=k

Therefore, by algebra the answer will be 17

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Vicki started jogging. The first time she ran she ran 3/16 mile. The second time, she ran 3/8 Mile, and the third time, she ran 9/16 mile. If she continue this pattern, when was the first time she ran more than one mile explain

Answers

Answer:

In seventh time she ran more than one mile from first time she ran.

Step-by-step explanation:

Given Vicki started jogging. The first time she ran she ran 3/16 mile. The second time, she ran 3/8 Mile, and the third time, she ran 9/16 mile.

We have to find when was the first time she ran more than one mile.

The sequence followed is

[tex]\frac{3}{16}, \frac{6}{16}, \frac{9}{16}, \frac{12}{16}, \frac{15}{16}, \frac{18}{16}, \frac{21}{16}....[/tex]

First time she ran more than 1 mile is [tex]\frac{3}{16}+1=\frac{19}{16}[/tex]

In the seventh time she ran [tex]\frac{21}{16}[/tex] miles which is more than one mile from the first time.

Hence, in seventh time she ran more than one mile from first time she ran.


Express in exponential form. log100.001 = -3

Answers

Answer:

I believe you meant to put " log10 (0.001)= -3

10^-3=0.001

The expression log100.001 = -3 in exponential form is 10^-3 = 0.001. This demonstrates that 10 raised to the power of -3 equals 0.001, showing the inverse relationship between logarithms and exponents.

To express log100.001 = -3 in exponential form, recall that the logarithm is the exponent to which the base, in this case, 10, must be raised to produce the given number. The equation log10(0.001) = -3 tells us that the base 10 raised to the power of -3 equals 0.001.

In exponential form, this can be written as 10-3 = 0.001.The concept of converting a decimal to a negative power of 10 involves moving the decimal point to make the number into a whole number, and the negative exponent indicates how many places the decimal point needs to move to the left. In our case, 10-3 means we move the decimal three places to the left: 1 becomes 0.001.

Two people taking the test are chosen at random. what is the probability that at least one of them scores more than 500 points?

Answers

It depends what their IQ level is.

a skateboard that cost $53 was put on sale for 25% discount. What was the sale price of the skateboard?

Answers

53(.25)=13.25
53-13.25=39.75
The sale price was $39.75
53 is 100% of the price. If you remove 25% of the price you have 100%-25%=75%. so you multiply 53 by 75% or .75 therefore: 53*.75=$39.75

Identify all the real roots of 4x^4+31x^3-4x^2-89x+22=0

Answers

Solve for x over the real numbers:
4 x^4 + 31 x^3 - 4 x^2 - 89 x + 22 = 0

The left hand side factors into a product with three terms:
(x + 2) (4 x - 1) (x^2 + 6 x - 11) = 0

Split into three equations:
x + 2 = 0 or 4 x - 1 = 0 or x^2 + 6 x - 11 = 0

Subtract 2 from both sides:
x = -2 or 4 x - 1 = 0 or x^2 + 6 x - 11 = 0

Add 1 to both sides:
x = -2 or 4 x = 1 or x^2 + 6 x - 11 = 0

Divide both sides by 4:
x = -2 or x = 1/4 or x^2 + 6 x - 11 = 0

Add 11 to both sides:
x = -2 or x = 1/4 or x^2 + 6 x = 11

Add 9 to both sides:
x = -2 or x = 1/4 or x^2 + 6 x + 9 = 20

Write the left hand side as a square:
x = -2 or x = 1/4 or (x + 3)^2 = 20

Take the square root of both sides:
x = -2 or x = 1/4 or x + 3 = 2 sqrt(5) or x + 3 = -2 sqrt(5)

Subtract 3 from both sides:
x = -2 or x = 1/4 or x = 2 sqrt(5) - 3 or x + 3 = -2 sqrt(5)

Subtract 3 from both sides:
Answer:  x = -2 or x = 1/4 or x = 2 sqrt(5) - 3 or x = -3 - 2 sqrt(5)

The real roots of a function are the rational and the irrational roots of the function

The real roots are: [tex]\mathbf{x = -2}[/tex], [tex]\mathbf{x = \frac 14}[/tex], [tex]\mathbf{x = -3 - 2\sqrt{5}}[/tex] and [tex]\mathbf{x = -3 + 2\sqrt{5}}[/tex]

The equation is given as:

[tex]\mathbf{ 4x^4+31x^3-4x^2-89x+22=0}[/tex]

Factorize

[tex]\mathbf{(x + 2) (4 x - 1) (x^2 + 6 x - 11) = 0}[/tex]

Split

[tex]\mathbf{x + 2 = 0\ or\ 4 x - 1 = 0 \ or\ x^2 + 6 x - 11 = 0}[/tex]

Solve for x

[tex]\mathbf{x = -2\ or\ x = \frac 14 \ or\ x^2 + 6 x - 11 = 0}[/tex]

Solve

[tex]\mathbf{x^2 + 6 x - 11 = 0}[/tex] using the following quadratic formula:

[tex]\mathbf{x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}}[/tex]

So, we have:

[tex]\mathbf{x = \frac{-6 \pm \sqrt{6^2 - 4 \times 1 \times -11}}{2 \times 1}}[/tex]

[tex]\mathbf{x = \frac{-6 \pm \sqrt{80}}{2}}[/tex]

[tex]\mathbf{x = \frac{-6 \pm 4\sqrt{5}}{2}}[/tex]

[tex]\mathbf{x = -3 \pm 2\sqrt{5}}[/tex]

Hence, the real roots are:

[tex]\mathbf{x = -2}[/tex], [tex]\mathbf{x = \frac 14}[/tex], [tex]\mathbf{x = -3 - 2\sqrt{5}}[/tex] and [tex]\mathbf{x = -3 + 2\sqrt{5}}[/tex]

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Given two vectors a⃗ = 4.60 i^+ 7.20 j^ and b⃗ = 5.10 i^− 2.70 j^ , find the scalar product of the two vectors a⃗ and b⃗ .

Answers

a=<4.60,7.20>
b=<5.10,2.70>
The scalar product, or the inner product, or the dot-product, is by summing the products of the respective directions, 
a.b=4.6*5.1+7.2*2.7
=23.46+19.44
=42.9

In this exercise we have to use the knowledge of vectors to find the dot product between them, in this way we can say that:

[tex]|a|*|b|=42.9[/tex]

Knowing that it was stated by the text that the vectors have the value of :

[tex]a=<4.60,7.20>\\ b=<5.10,2.70> [/tex]

The scalar product, or the inner product, or the dot-product, is by summing the products of the respective directions, will be:

[tex]|a|*|b|=4.6*5.1+7.2*2.7\\ =23.46+19.44\\ =42.9 [/tex]

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Tom was saving $3000 for a trip. He initially deposited $200 in a savings account and then deposited a fixed amount every month in the account for the next 5 months. Then he received a check in the mail. The check was three times as much as the total amount he had saved so far. When he deposited the check in his savings account, he had $200 more than he needed. What was the fixed amount he deposited in the savings account during the 5 months?

Answers

The answer is $120. To determine this, you will represent the situation as an equation:

4(200 + 5x) = 3200. I came up with this because it says he started with 200 and added a fixed amount every month for 5 months (5x). If the check was 3 times the amount he already had saved, then he has 4 times what he started with.

His goal was $3000, but he has $200 more than that, so $3200 would be the amount he has.

I have attached the work showing how to solve for x, the amount he depositors each month.

The contour plot of is shown below. determine if the given quantity in each part is positive, negative, or zero.

Answers

There is no contour plot shown below.

Helps with this math problem please

Answers

First we are going to express both equation in terms of  [tex]y[/tex] to compare their slopes:
For our first equation:
[tex]-x=1-y[/tex]
[tex]-x-1=-y[/tex]
[tex]y=x+1[/tex]
For our second equation:
[tex]-1+y=x+2[/tex]
[tex]y=x+3[/tex]
So now we have our system of equations in terms of y:
[tex] \left \{ {{y=x+1} \atop {y=x+3}} \right. [/tex]
Notice that the slope, the coefficient of [tex]x[/tex], in both equations is the same: 1, and if tow linear equations have the same slope, they are parallel.

We can conclude that we can classify the system of equations as parallel.

List 3 values that would make this inequality true 43 < y -30

Answers

43 < y - 30
add 30 to both sides
73 < y

y can be anything that is greater than 73
so it could be...
101, 74, 90, 75, 980767, 5674, etc.

Hope this helps!

Final answer:

To make the inequality 43 < y - 30 true, add 30 to both sides to get 73 < y. Any number greater than 73, such as 74, 80, or 90, will satisfy the inequality.

Explanation:

To find values that make the inequality 43 < y - 30 true, you simply need to add 30 to both sides of the inequality. This gives you:

73 < y

This means that any value greater than 73 will make the inequality true. Here are three examples:

y = 74 (since 74 is greater than 73)y = 80 (since 80 is greater than 73)y = 90 (since 90 is greater than 73)

You can choose any three numbers greater than 73, and they will satisfy the inequality 43 < y - 30.

2.4.5 journal: graphs of exponential functions

Answers

This is a net diagram of a room showing the floor and 4 walls (ceiling not included).
What is the measurement at x? m

factor 64a^2b^36-1
1. (8ab6 + 1)(8ab6 – 1)
2. (8ab18 – 1)
3. (8ab18 + 1)(8ab18 – 1)
4. (8ab6 – 1)

Answers

[tex] 64a^2b^{36} -1 [/tex]

[tex]= (8ab^{18})^{2} - (1)^2 [/tex]

[tex]=(8ab^{18} - 1)(8ab^{18} + 1)[/tex]

----------------------------------------------------------
Answer: (8ab¹⁸ - 1)(8ab¹⁸ + 1) (Answer 3)
----------------------------------------------------------

Let be the linear transformation that first reflects points through the -axis and then then reflects points through the line . find the standard matrix for

Answers

In the case above, the standard matrix A for T:

T= [0 1]

    [-1 0]

What is  linear transformation  about?

A linear transformation is known to be a kind of a function that exist from one vector point to another and it is one that often respects the linear) structure of all of vector space.

Note that in the linear transformation;

T: R² R²

T=  (x, y), (-x, y)

Since:

(x,y) - (x,-y) - (y,-x)

A= [-1 0]

   [0 1]

A= [-1 0]    =       A= [-x]

   [0 1]                    [y]

Then [tex]T_{b}[/tex] is the reflection of (x- y); Since;

B = [0 1]

    [1 0]

Then [tex]T_{B} (T_{a}(x) )[/tex]  =  [0 1]        =      A= [-x]

                              [0 1]                     [y]

  = [-x]

    [y]

Then: T: = [0 1]                  [x]

                [0 1]                   [y]

           

   

Therefore, In the case above, the standard matrix A for T:

T= [0 1]

    [-1 0]

           

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Ron is taking an inventory at his store. Based on previous sales, he predicted sales of 25 folders and 230 erasers. He actually sold 30 folders and 200 erasers. What is the percent error for the erasers?

Answers

Answer: There is 15% error for the erasers

Step-by-step explanation:

Since we have given that

Number of folders he predicted = 25

Number of erasers he predicted = 230

Total number of inventories he predicted is given by

[tex]230+25=255[/tex]

Number of erasers he actually sold = 200

Number of folders he actually sold = 30

Total number of inventories he actually sold is given by

[tex]200+30=230[/tex]

Error in estimation is given by

[tex]230-200=30[/tex]

Percentage of error for the erasers only  

[tex]\frac{30}{200}\times 100\\\\=\frac{30}{2}\\\\=15\%[/tex]

Hence, there is 15% error for the erasers.

Answer:

15 %

Step-by-step explanation:

Please help me with the question 15 POINTS

Answers

Each of these questions is substantially the same as the others. The answer is, "it depends" on what you want a random sample of. If you want random people in the country, you will not get that from these protocols.

If you want random people that meet certain criteria (have phones, shop in eyeglasses stores, use specific venues), then these protocols will deliver.

Jill sold half of her comic books and then bought sixteen more. she now has 43. how many comic books did she begin with?

Answers

43-16 = 27

27 x 2 = 54

 she had 54

Answer: 54

Step-by-step explanation: 43-16=27 times 2 =54

The level of nitrogen oxides (nox) in the exhaust after 50,000 miles or fewer of driving of cars of a particular model varies normally with mean 0.03 g/mi and standard deviation 0.01 g/mi. a company has 64 cars of this model in its fleet. what is the level l such that the probability that the average nox level x for the fleet is greater than l is only 0.01? (hint: this requires a backward normal calculation. round your answer to three decimal places.)

Answers

Final answer:

We can use the z-score formula with the known z-score corresponding to a probability of 0.01 to calculate the exhaust NOx emission level. This gives us approximately 0.001 g/mi.

Explanation:

In this scenario, we're dealing with a normal distribution problem wherein we use the formula for z-score to answer it. The z-score formula is =(−)/(/√), where x is the data point, μ is the population mean, n is the size of the data set, and σ is the standard deviation.

In this case, we want to find x, or the NOx emission level, such that the probability of finding an automobile with a level greater than x is 0.01. So, we need to find the z-score that corresponds to a probability of 0.01 and then use it in our formula to solve for x.

Using standard z-score tables or an online z-score calculator, we find that a probability of 0.01 corresponds to a z-score of approximately -2.33 (p and z have opposite signs). We then substitute this z-score, along with the given mean μ=0.03 and standard deviation σ=0.01 into the z-score formula, solving for x. The value of n is 64 (number of vehicles in the fleet).

Inserting these values into the formula gives us = + z/√ =0.03 + (-2.33)*(0.01/√64), which simplifies to =0.03 - (2.33/80) = 0.03 - 0.029125= 0.000875 g/mi. Therefore, the NOx emission level, such that the probability of finding an automobile with a level greater than it, is 0.01 for this fleet is approximately 0.001 g/mi when rounded to three decimal places.

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Final answer:

To find the level l such that the probability that the average NOx level x for the fleet is greater than l is only 0.01, we can use the z-score formula and the properties of the normal distribution. The z-score formula allows us to convert a probability into a corresponding value on the distribution. Rearranging the z-score formula, we can find the value of l.

Explanation:

To find the level l such that the probability that the average NOx level x for the fleet is greater than l is only 0.01, we can use the z-score formula and the properties of the normal distribution. The z-score formula is z = (x - µ) / (σ / √n), where x is the average NOx level, µ is the mean, σ is the standard deviation, and n is the sample size. We want to find the value of l such that the area to the right of l under the normal curve is 0.01.

First, we need to find the z-score corresponding to a right-tail probability of 0.01. This can be done using a z-table or a calculator. In this case, the z-score is approximately 2.326. Now we can use the z-score formula to find the value of l. Rearranging the formula, we have l = µ + (z * σ / √n). Substituting the given values, l = 0.03 + (2.326 * 0.01 / √64). Calculating this, we get l ≈ 0.031.

Therefore, the level l such that the probability that the average NOx level x for the fleet is greater than l is only 0.01 is approximately 0.031 g/mi.

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Huey works 175 hours each month and earns $14.25 per hour after taxes. His monthly budget is shown. How much money is left over in his budget for unplanned expenses?

Answers

For this case we have the following equation:
 y = 14.25x
 Where,
 x: number of hours
 y: total salary
 For x = 175 we have:
 y = 14.25 * (175)
 y = 2493.75
 The amount of money for unexpected expenses is:
 unplanned expenses = 2493.75 - 1250 - 200 - 350 - 400 - 225 - 300
 unplanned expenses = -231.25 <0
 We note that there is no money left for unexpected expenses
 Answer:
 
there is nothing left over

Answer:

Nothing will be left over.

Step-by-step explanation:

You need to multiply the 175 by 14.25 to get his total income each month.

Then you add all of the expenses of 1250, 200, 350, 400, 225, 300.

Huey earns 2,493.75 every month, and his expenses are 2,725.

2,493.75 - 2725 = a negative rational number

I ain't gonna do it, because he ain't got no money in his wallet.

(I don't talk like that above, I'm just pretending to be an official Texan.)

If he has negative money left over, I don't think he would spend some more tbh, so the answer would be nothing would be left over.

Hope this helps someone in the future!

When filled, a particular round balloon has a diameter of 14 inches. What is the approximate volume of air needed to fill this balloon?

Answers

Hi the answer you are looking for is 1436.76.

Hope this helps! Study on!

Answer:

the answer is  1,437

Step-by-step explanation:

The amount of a chemical solution is measured to be 2 liters. What is the percent error of the measurement?

Answers

The amount of a chemical solution is measured to be 2 liters. What is the percent error of the measurement?

25%


At 6 1/2¢ per pound of string beans, how much does 7 pounds cost?

Answers

if we have 
6.50 cents lb of string beans............................1 lb
? cents..............................................................7 lb
(6.50*7)/1=45.50 cents for 7 lb of beans

<5 and <6 are complementary angles m<5=13 what is the measure of <6

Answers

The measure of angle 6 can be found by subtracting the measure of angle 13 from 90.

90-13 = 77

67 ,73 ,77,82,86,,86,91,98 find the median

Answers

Hard to tell if a number is missing or not. We'll assume this is the entire data set.

The median of a set that has an even number of numbers is the average of the middle two after they are sorted into order.
.. (82 +86)/2 = 84

Your median is 84.
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