Use ksp=4.87×10−17 to calculate the solubility of iron (ii) hydroxide in pure water in grams per 100.0 ml of solution. g

Final answer:

The correct IUPAC name for MgBr2 is 'magnesium bromide', where 'magnesium' denotes the metal cation and 'bromide' denotes the nonmetal anion with its ending changed to 'ide'.

Explanation:

The correct name for the compound MgBr2 is magnesium bromide. According to the International Union of Pure and Applied Chemistry (IUPAC) system of nomenclature, binary ionic compounds (compounds consisting of a metal and a nonmetal) are named by writing the name of the metal (the cation) followed by the name of the nonmetal (the anion) with its ending changed to 'ide'. In our case, 'Mg' stands for magnesium, and 'Br' stands for bromine; when combined in the compound MgBr2, the bromine becomes bromide. The prefix 'di' is not used in this name because the stoichiometry (the ratio of Mg to Br) is inferred by the charges on the ions; magnesium has a +2 charge and bromine has a -1 charge, so two bromine atoms are required to balance the charge of one magnesium atom.

Answer: The ratio of rate of effusion of helium and radon is 7.45

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

[tex]\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}[/tex]

We are given:

Molar mass of Helium = 4.00 g/mol

Molar mass of Radon = 222.1 g/mol

Taking their ratios, we get:

[tex]\frac{Rate_{He}}{Rate_{Rn}}=\sqrt{\frac{M_{Rn}}{M_{He}}}[/tex]

[tex]\frac{Rate_{He}}{Rate_{Rn}}=\sqrt{\frac{222.1}{4.00}}\\\\\frac{Rate_{He}}{Rate_{Rn}}=7.45[/tex]

Hence, the ratio of rate of effusion of helium and radon is 7.45

Neon (Ne) has a greater chance of forming a momentary dipole due to its completely filled outer electron shell.

The element with a greater chance of forming a momentary dipole is neon (Ne). Neon has a completely filled outer electron shell, which makes it inert and less likely to form chemical bonds. This means that when neon interacts with other elements, it can induce temporary dipole moments in the other atoms or molecules, creating momentary attractions between them.

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Answer:

That it's excessively amazing, that with one present-day atomic vitality the earth as we probably are aware it could be decimated.  

I trust this makes a difference!

Explanation:

In this problem, we are asked to find the new concentration.

So, we use the dilution equation;

M1V1 = M2V2

Where M1 = concentration in molarity (moles/Liters) of the concentrated solution,

V2 =volume of the concentrated solution,

M2 =concentration in molarity of the dilute solution, and

V2 = volume of the dilute solution.

Before substituting the formula, convert the given mL to L since the unit for molarity is (moles/Liter).

Use the conversion factor (1000 mL = 1 L), so:

10.0 mL = 0.01 L

100 mL= 0.1 L

Now, we substitute the given (in liters) to the formula.

(0.50 M) (0.01 L) = M2(0.1 L)

M2 = [(0.50 M) (0.01 L)] / 0.1 L

M2 = 0.05 M

Answer: 0.050

Explanation:

Answer : This chemical equation represents a single replacement reaction.

Explanation :

Single replacement reaction : It is defined as the reaction in which the most reactive metal displace the least reactive metal form its solution.

The given balanced chemical reaction is:

[tex]Fe(s)+CuSO_4(aq)\rightarrow FeSO_4(aq)+Cu(s)[/tex]

The given chemical reaction is a single replacement reaction because in this reaction, iron is most reactive metal than the copper. So, iron can displace the copper metal form its solution and it forms iron (II) sulfate and copper as a product.

Hence, the chemical equation represents a single replacement reaction.

Final answer:

To determine the mass of 0.40 mole of NaBH4, calculate the molar mass of NaBH4 and multiply by the number of moles, resulting in 15.136 grams.

Explanation:

To find out how many grams are in 0.40 mole of NaBH4, we need to first calculate the molar mass of NaBH4. This involves adding the atomic masses of sodium (Na), boron (B), and hydrogen (H). The atomic masses are 22.99 g/mol for Na, 10.81 g/mol for B, and 1.01 g/mol for each of the four hydrogen atoms, giving us:

Molar mass of NaBH4 = 22.99 + 10.81 + (4 × 1.01) = 37.84 g/mol.

Now we can calculate the mass by multiplying the number of moles by the molar mass:

Mass = 0.40 moles × 37.84 g/mol = 15.136 grams of NaBH4.

Answer:

               The Equilibrium will shift to the left.

Explanation:

                      The reaction at equilibrium is as follow,

                              CH₃COOH       ↔    CH3COO⁻ + H⁺

According to Le Chatelier's Principle," When a system (reaction) at equilibrium is subjected to any stress (like change in Concentration, Pressure, Temperature e.t.c) the system (reaction) tends to adjust itself in such a way so as to minimize the effect of that change".

Hence, in above reaction when Sodium Acetate (source of CH₃COO⁻) is added the equilibrium will shift in left side and will decrease the concentration of CH₃COO⁻ions.

Final answer:

The addition of CH₃COONa, which contributes more acetate ions, will result in a leftward shift of the chemical equilibrium of the reaction CH₃COOH ⇌ CH₃COO⁻ (aq) + H⁺(aq), as predicted by Le Chatelier's principle.

Explanation:

When CH₃COONa is added to the solution, the chemical equilibrium of the reaction CH₃COOH ⇌ CH₃COO− (aq) + H⁺(aq) will shift. This is because CH₃COONa disassociates in water to form sodium ions (Na⁺) and acetate ions (CH₃COO⁻). By Le Chatelier's principle, adding more of a product (in this case, CH₃COO⁻) will shift the equilibrium to the left, towards the reactants, to counteract the change. This results in a decrease in the H+ concentration and is known as the common ion effect.

The equilibrium will therefore shift toward the formation of CH₃COOH, causing the concentration of CH₃COO⁻ and H⁺ to be reduced, which is in line with Le Chatelier's principle of equilibrium adjustment.

The final volume of the balloon after adding oxygen is 21 L.

To find the new volume of the balloon after adding oxygen, we can use Avogadro's law, which states that at constant temperature and pressure, equal volumes of gases contain equal numbers of moles. Initially, the balloon is filled with 4.00 moles of hydrogen in a volume of 21 L. When 2.00 moles of oxygen are added, the total number of moles becomes 6.00 moles. Since the hydrogen and oxygen are now mixed together, their volumes must be equal, so the final volume of the balloon is also 21 L.

Answer: gasoline

Explanation:

Element is a pure substance which is composed of atoms of similar substances.It can not be decomposed into simpler constituents using chemical reactions.Example: Aluminium [tex]Al[/tex]

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.It can be decomposed into simpler constituents using chemical reactions. Example: carbon dioxide [tex]CO_2[/tex] and salt [tex]NaCl[/tex]

Mixture is a substance which has two or more components which do not combine chemically and do not have any fixed ratio in which they are present. Example: gasoline which is a mixture of different hydrocarbons.

Answer:

gasoline

Explanation:

Mendeleev left gaps in his periodic table predicting the discovery of unknown elements. These gaps ultimately validated the predictive power of the periodic table, as new elements were found that fitted these places which facilitated further advancements in chemistry and related fields.

Dmitri Mendeleev, a Russian chemist, organized the chemical elements into a table known as the periodic table. He left gaps in the table because he predicted that there were elements yet to be discovered that would fit into those spaces. Mendeleev even predicted some properties of these undiscovered elements based on their presumed placement on the table. His prediction was found to be extraordinary when later these gaps were filled by the discovery of elements like Gallium, Scandium, and Germanium.

The ultimate importance of these gaps can be found in the fact that it showed the predictive power of the periodic table. By having the elements arranged in such a way, it gave scientists a tool to predict and identify new elements, further expanding our understanding of the universe's atomic composition. This aspect of Mendeleev's periodic table has contributed significantly to the advancement of chemistry and related sciences.

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Hydrophobic molecules are nonpolar molecules that cluster away from water molecules. They have nonpolar covalent bonds and examples include oil, fats, and waxes.

Nonpolar molecules that cluster away from water molecules are called hydrophobic molecules. Hydrophobic molecules typically have nonpolar covalent bonds, which means the electronegativity difference between the bonded atoms is minimal. This leads to an absence of partial charges on the atoms, resulting in overall nonpolarity. Examples of hydrophobic molecules include oil, fats, and waxes.

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Answer:

130.1 x 10²³ molecules of sugar  

Explanation:

One dozen = 12 donuts

1 doughnut = 1.8 moles of sugar

12 doughnut = (1.8 x 12) moles of sugar = 21.6 moles of sugar

1 mole of any substance contains Avogadro’s number (6.023 x 10²³) of molecules.

1 mole of sugar = 6.023 x 10²³ molecules of sugar

21.6 moles of sugar = (6.023 x 10²³ x 21.6) molecules of sugar  

                                 = 130.1 x 10²³ molecules of sugar  

Answer:

A.) 130.032 x 10^23

Explanation:

I got it correct on founders edtell

The given balanced chemical equation is,

[tex] Fe_{2}O_{3} + 3CO -->2 Fe (s) + 3CO_{2}(g) [/tex]

Part A:

Converting 3.65 L CO to moles:

[tex] 3.65 L * \frac{1 mol}{22.4 L} = 0.163 mol CO [/tex]

Moles of Fe that will be produced from 0.163 mol CO:

[tex] 0.163 mol CO * \frac{2 mol Fe}{3 mol CO} = 0.1086 mol Fe [/tex]

Mass of Fe = [tex] 0.1086 mol Fe * \frac{55.85 g}{1 mol} = 6.07 g Fe [/tex]

Part B: Actual yield of Fe = 4.23 g Fe.

Theoretical yield = 6.07 g Fe

Percentage yield = [tex] \frac{Actual yield (g)}{Theoretical yield (g)}*100 [/tex]

=69.7 %

A weather map showing an advancing mass of cold air indicates the formation of a cold front with associated low pressure, resulting in rapid upward air movement, precipitation, and a significant drop in temperature and humidity after the front passes. Option D is correct.

Based on the weather map, the conditions that would be predicted involve an advancing mass of cold air that creates a cold front. This is typically associated with a low pressure area as the front approaches. The cold front often leads to a sudden change in weather, characterized by rapid upward movement of air.

This results in the formation of vertically-developed clouds such as cumulus and cumulonimbus, leading to intense, but short-lasting precipitation. After the cold front passes, there is usually a marked drop in temperature and humidity, along with a shift in wind direction from south or southwest to west or northwest.

Hence, D. is the correct option.

The complete question is:

What conditions would be predicted based on the information in the weather map?

A) The advancing mass of cold air creates a low pressure area.

B) The cold front advances without bringing any change in the weather.

C) The high pressure causes cold air to move toward the low pressure areas.

D) The cold front advances from an area of high temperature to an area of low pressure.

Final answer:

A protein's structure is determined by its amino acid sequence, which is encoded by the DNA sequence of a gene. The DNA sequence is translated into a protein through a process involving transcription and translation, followed by folding of the amino acid chain into its final structure.

Explanation:

The structure of a protein is critical to its function, and this structure is determined by the sequence of amino acids that make up the protein. This sequence of amino acids is directly dictated by the DNA sequence of a gene.

The process of translating DNA information into the structure of a protein follows the Central Dogma of Molecular Biology, which entails the conversion of DNA code into RNA (transcription), and then RNA into a protein (translation). The amino acid sequence then folds into a three-dimensional structure, which is essential for the protein's function.

Key to understanding this process is recognizing that the DNA sequence is comprised of codons, groups of three nucleotides that correspond to specific amino acids.

Through the actions of ribosomes and transfer RNA molecules, these codons are read and the appropriate amino acids are assembled in the correct order, resulting in a polypeptide chain.

This chain then undergoes folding, sometimes with assistance from other proteins called chaperones, to achieve its final functional form.

Final answer:

Ammonium carbonate decomposes when heated, resulting in water, ammonia, and carbon dioxide. The balanced chemical equation for this reaction is (NH4)2CO3(s) → 2 NH3(g) + CO2(g) + H2O(l). This is an example of a decomposition reaction.

Explanation:

When ammonium carbonate is heated, a decomposition reaction occurs, resulting in the formation of water (H2O), ammonia (NH3), and carbon dioxide (CO2). The balanced chemical equation for this reaction is:

(NH4)2CO3(s) → 2 NH3(g) + CO2(g) + H2O(l)

The formulas for the reaction products are ammonia (NH3), carbon dioxide (CO2), and water (H2O). This chemical equation shows that for each mole of ammonium carbonate heated, two moles of ammonia, one mole of carbon dioxide, and one mole of water are produced.

Explanation:

When there occurs sharing of electrons between two different atoms then bond formed between them is known as a covalent bond.

When only one electron is shared then a single covalent bond is formed.

When only two electrons are shared then a double covalent bond is formed.

When three electrons are shared then a triple covalent bond is formed.

Thus, we can conclude that a chemical bond formed when two atoms share six electrons is a triple bond; it is best described as a covalent bond.