Use the function y=0.0875x^2 - `10.5x + 436.25 calculate the number of accidents that occur at 60 km/h? Select the right answer.

Answer:

60

Step-by-step explanation:

amount of money deposited for one week= $10

no. of weeks= 6

amount= 6*10=60

Jason will have saved $60 after 6 weeks by depositing $5 twice a week.

Jason deposits $5 into his savings account twice a week for 6 weeks. To calculate the total amount saved after 6 weeks, we can set up an equation where s stands for the amount of money saved:

s = number of deposits per week  * amount per deposit  * number of weeks

Plugging in the values we have:

s = 2 deposits/week * $5/deposit * 6 weeks

s = $60

Therefore, Jason will have saved $60 after 6 weeks.

Answer:

12 hours

Step-by-step explanation:

12.5 is 30 inches, at 2.5 inches per an hour you would do 30/2.5 = 12

Answer: $126.50

$230×.45= $103.5

$230-$103.5=126.50

Answer:

126.50

Step-by-step explanation:

If he spent 45% of the money, he still has 100% -45% = 55%

He will still he have 55% of his money

230* 55%

Changing to decimal form

230*.55

126.50

Answer:

[tex]8(2x^2 + x + 4)[/tex]

Step-by-step explanation:

Given:

We'd factor out 8:

[tex]8(2x^2 + x + 4)[/tex]

Our answer would be [tex]8(2x^2 + x + 4)[/tex]

The completely factored form of the expression 16x2 + 8x + 32 is 8(2x2 + x + 4), after factoring out the greatest common factor, 8.

The question asks for the completely factored form of the expression 16x2 + 8x + 32. To factor this expression completely, we look for a common factor in all the terms. Observing the coefficients (16, 8, and 32), we recognize that 8 is the greatest common factor (GCF). Factoring out the GCF, we get:

8(2x2 + x + 4).

This expression cannot be factored further since the quadratic inside the parentheses does not factor neatly over the integers. Thus, the completely factored form of 16x2 + 8x + 32 is 8(2x2 + x + 4).

Answer:

TRK=TUK

Step-by-step explanation:

the dashes or partial circles indicate the angle or lines are the same length/angle

Simple form of equation 3x – 5 + 23x – 9 = 26x-14

Linear Equation in One Variable is an equation that has a variable and the exponent number is one.

Can be stated in the form:

[tex] \large {\boxed {\bold {ax = b}} [/tex]

or

ax + b = c, where a, b, and c are constants, x is a variable

Whereas Linear Equation in two Variable is a linear equation that has 2 variables and the exponent is one

Can be stated in the form:

[tex] \large {\boxed {\bold {ax + bx = c}}} [/tex]

x, y = variable

There are several ways to solve an equation

• Add / Subtract / divide / multiply the same value on both sides

• Combine like terms

• Factoring

• Expanding

Like terms are terms whose variables and their exponents are the same.

You can combine and add terms

The algebraic form of 3x - 5 + 23x - 9 is a Linear Equation in One Variable, can be simplified:

• 1. Combine like terms

(3x + 23x) + (-5 - 9)

• 2. Add like terms:

26x -14

an algebraic expression

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[tex]\(3x - 5 + 23x - 9\)[/tex] simplifies to [tex]\(26x - 14\).[/tex]

To simplify the expression [tex]\(3x - 5 + 23x - 9\)[/tex], we can combine like terms

[tex]\[3x - 5 + 23x - 9 = (3x + 23x) + (-5 - 9)\][/tex]

[tex]\[= 26x - 14\][/tex]

Answer:

h < 14

Step-by-step explanation:

2h +8 > 3h - 6

2h - 3h >  - 6 - 8

-h > -14  (multiply both sides by -1; remember to flip the inequality sign!)

h < 14

Answer:

Step-by-step explanation:

No, the heights of the cones are not the same, so Cavalieri’s principle does not apply.

Answer:

[tex]x^2-7x-10[/tex] is consider prime (also known as not factorable over the rationals)

Step-by-step explanation:

[tex]x^2-7x-10[/tex] is consider prime.

[tex]x^2-7x-10[/tex] comparing to [tex]ax^2+bx+c[/tex] gives you [tex]a=1,b=-7,c=-10[/tex].

Since a=1, all you have to do is find two numbers that multiply to be -10 and add up to be -7.

Here are all the integer pairs that multiply to be -10:

-1(10)

1(-10)

2(-5)

-2(5)

Now you will see none of those pairs adds to be -7:

-1+10=9

1+(-10)=-9

2+(-5)=-3

-2+5=3

So this is not factorable over the real numbers.

Now if you had something like [tex]x^2-7x+10[/tex], that would be a different story.  You can find two numbers that multiply to be 10 and add up to be -7.  Those numbers are -2 and -5 since -2(-5)=10 and -2+(-5)=-7. So the factored form of [tex]x^2-7x+10[/tex] is [tex](x-2)(x-5)[/tex].

Answer:

[tex]\large\boxed{-\dfrac{23}{9}=-2\dfrac{5}{9}}[/tex]

Step-by-step explanation:

[tex]\text{Put}\ w=-\dfrac{5}{9}\ \text{and}\ x=\dfrac{4}{3}\ \text{to the expression}\ w+(-x)-\dfrac{2}{3}:\\\\-\dfrac{5}{9}-\dfrac{4}{3}-\dfrac{2}{3}=-\dfrac{5}{9}-\dfrac{4\cdot3}{3\cdot3}-\dfrac{2\cdot3}{3\cdot3}\\\\=-\dfrac{5}{9}-\dfrac{12}{9}-\dfrac{6}{9}=-\dfrac{23}{9}=-2\dfrac{5}{9}[/tex]

Step-by-step explanation:

y~x

y=kx

where

y=2,x=4

2=k*4

k=2/4

k=0.5//

find y when x =32

then

y=32*0.5

y=16//

[tex]\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\bf \textit{we also know that } \begin{cases} y=2\\ x=4 \end{cases}\implies 2=k(4)\implies \cfrac{2}{4}=k\implies \cfrac{1}{2}=k \\\\\\ therefore\qquad \boxed{y=\cfrac{1}{2}x} \\\\\\ \textit{when x = 32, what's \underline{y}?}\qquad y=\cfrac{1}{2}(32)\implies y=16[/tex]

Answer:

ALL REAL NUMBERS

Step-by-step explanation:

Any cubic function is ALWAYS R.

Answer:

So I did most of you table for you:

First blank:4

Second blank:-4

Third blank:-8

Fourth blank: Left to you: Just plug in 6 into 1/2x^2-5x+4 (I will check)

Fifth blank: Left to you: Just plug in 8 into 1/2x^2-5x+4 (I will check)

The graph is D.

Step-by-step explanation:

So they have a table to fill in and they tell you in the first row what they want you to plug in

So the table is asking us to answer this:

What is h(0),h(2),h(4),h(6), and h(8).

h(0) means to replace x with 0 in [tex]\frac{1}{2} x^2-5x+4[/tex].

[tex]\frac{1}{2}(0)^2-5(0)+4[/tex]

[tex]0-0+4[/tex]

[tex]0+4[/tex]

[tex]4[/tex]

So the first blank is 4 since h(0)=4.

h(2) means to replace x with 2 in [tex]\frac{1}{2} x^2-5x+4[/tex].

[tex]\frac{1}{2} (2)^2-5(2)+4[/tex]

[tex]\frac{1}{2} (4)-10+4[/tex]

[tex]2-10+4[/tex]

[tex]-8+4[/tex]

[tex]-4[/tex]

So the second blank is -4 since h(2)=-4.

h(4) means to replace x with 4 in [tex]\frac{1}{2} x^2-5x+4[/tex].

[tex]\frac{1}{2}(4)^2-5(4)+4[/tex]

[tex]\frac{1}{2}(16)-20+4[/tex]

[tex]8-20+4[/tex]

[tex]-12+4[/tex]

[tex]-8[/tex]

So the third blank is -8 since h(4)=-8

Maybe you can try the last 2 blanks in the table part. That is try computing h(6) and h(8). I will check it for you.

Now the points I have so far are (0,4) from the h(0)=4, (2,-4) from the h(2)=-4, and (4,-8) from the h(4)=-8.

I'm looking for a graph that goes through these points (0,4) , (2,-4) , and (4,-8).

By the way the only graphs that are worth looking at is C and D because they are open up.  I know my curve for h(x)=1/2x^2-5x+4 should be a parabola open up because 1/2 is positive and 1/2 is the coefficient of x^2.

So Graph C has y-intercept (0,10) not (0,4) so Graph C is not right.

Graph D has y-intercept (0,4).  It also goes through (2,-4) and (4,-8).  

I don't know if you notice but the x-axis and y-axis are going up by two's in each graph.

Answer:

Step-by-step explanation:

The formula of a volume of a prism:

[tex]V=BH[/tex]

B - base area

H - height

In the base we have the right triangle.

The formula of an area of a righ triangle

[tex]A=\dfrac{ab}{2}[/tex]

a, b - legs

We have a = 6.2m and b = 11m. Substitute:

[tex]B=\dfrac{(6.2)(11)}{2}=34.1\ m^2[/tex]

The height H = 9 m.

Substitute to the formula of a volume:

[tex]V=(34.1)(9)=306.9\ m^3[/tex]

For this case we have a function of the form [tex]y = f (x)[/tex]. Where:

[tex]f (x) = x-4[/tex]

By definition, the domain of a function is represented by the set of values of the independent variable, x, for which the value of the variable y can be calculated.

For its part, the range is represented by the values of "and".

So:

[tex]f (1) = 1-4 = -3\\f (5) = 5-4 = 1\\f (6) = 6-4 = 2[/tex]

Thus, the range is {-3,1,2}

Answer:

{-3,1,2}

Answer:

[tex]11\ aces[/tex]

Step-by-step explanation:

we know that

Pamela on average serves an ace 44% of the time

That means ----> Pamela serves 44 aces every 100 serves

Using proportion

Let

x -----> the number of aces

[tex]\frac{44}{100}=\frac{x}{25}\\ \\x=44*25/100\\ \\x= 11\ aces[/tex]

Answer:

[tex]y=5x[/tex]

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]y/x=k[/tex] or [tex]y=kx[/tex]

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

we have

For x=0, y=0 -----> the line passes through the origin

For x=1, y=5 ----> [tex]k=y/x=5/1=5[/tex]

For x=2, y=10 ----> [tex]k=y/x=10/2=5[/tex]

For x=3, y=15 ----> [tex]k=y/x=15/3=5[/tex]

so

The constant of proportionality is k=5

The table represent a direct variation

The equation is equal to [tex]y=kx[/tex]

substitute the value of k

[tex]y=5x[/tex]

Answer:

(-3,2)

Step-by-step explanation:

When the point P(x,y) is reflected in the line [tex]x=k[/tex], the mapping is

[tex]P(x,y)\to P'(2k-x,y)[/tex].

The image of (1,2) after a  reflection about x = 6 is

[tex](1,2)\to (2\times6-1,2)[/tex].

[tex](1,2)\to (12-1,2)[/tex].

[tex](1,2)\to (11,2)[/tex].

When the resulting point is again reflected in the line x=4, we obtain

[tex](11,2)\to (2\times4-11,2)[/tex].

[tex](11,2)\to (8-11,2)[/tex].

[tex](11,2)\to (-3,2)[/tex].

Therefore the image of (1,2) after a

reflection about x = 6 followed by a

reflection about x = 4 is (-3,2)

Answer:

x = 8

Step-by-step explanation:

log₅ (10x − 1) = log₅ (9x + 7)

10x − 1 = 9x + 7

x = 8

The domain of the function in the mapping given is: A. {x | x = -5, -3, 1, 2, 6}.

The domain of a function includes all the possible values of x (input) in a function.

The corresponding set of y-values (output) is the range of the function.

The set of x-values in the mapping are, -5, -3, 1, 2, 6.

Therefore, the domain of the function in the mapping given is: A. {x | x = -5, -3, 1, 2, 6}.

Learn more about domain of a function on:

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On a horizontal number line, -6 is located to the (left) of -4. So, -6 is (less than) 4.

Answer:

On a horizontal number line, -6 is located to the (left) of -4. So, -6 is (less than) 4.

Step-by-step explanation:

Answer:

c.

Step-by-step explanation:

the most that can be factored out is -1.5,

-1.5 * w = -1.5w

-1.5 * -5 = 7.5

-1.5w + 7.5, so it's

-1.5(w-5)

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept

[tex]61)\ m=3,\ b=-2\\\\\boxed{y=3x-2}\\\\62)\ m=\dfrac{4}{5},\ b=4\\\\\boxed{y=\dfrac{4}{5}x+4}\\\\63)\ m=-\dfrac{7}{4},\ b=-3\\\\\boxed{y=-\dfrac{7}{4}x-3}\\\\64)\ m=-\dfrac{3}{4},\ b=-2\\\\\boxed{y=-\dfrac{3}{4}x-2}[/tex]

Answer:

B. 4⁄5

Step-by-step explanation:

 7 1⁄5

– 6 2⁄5

-----------------

We need to borrow from the 7  since 1/5 is less than 2/5

7 becomes 6 and the one becomes 5/5

 6  5/5+1⁄5

– 6 2⁄5

-----------------

Combining the fraction

 6  6⁄5

– 6 2⁄5

-----------------

      4/5

Answer:

there is no picture for me to answer on

Answer:

[tex]Q_1=2[/tex]

[tex]Q_3=6[/tex]

Step-by-step explanation:

Notice that we already have the data sorted from least to greatest.

Now to find Q1 and Q3 we can use the following formulas

For a set of data ordered from least to greatest of the form [tex]X_1, X_2, ..., X_n[/tex]

Where n is the total number of data

[tex]Q_1=X_{\frac{1}{4}(n+1)}[/tex]

In this case [tex]n=10[/tex]

So:

[tex]Q_1=X_{\frac{1}{4}(10+1)}[/tex]

[tex]Q_1=X_{2.75}[/tex]

Round the nearest whole and get:

[tex]Q_1=X_{3}[/tex]

[tex]Q_1=3[/tex]

For Q3 we have:

[tex]Q_3=X_{\frac{3}{4}(n+1)}[/tex]

[tex]Q_3=X_{\frac{3}{4}(10+1)}[/tex]

[tex]Q_3=X_{8.25}[/tex]

Round the nearest whole and get:

[tex]Q_3=X_{8}[/tex]

[tex]Q_3=6[/tex]

Answer:

Q1: 2.5

Q3: 6

Step-by-step explanation:

The median area is 3 and 4.

The lower quartile is 3+2=5 5/2 2.5

The upper quartile is 6+6= 12 12/2 6

Answer:

2x^2+3

Step-by-step explanation:

(3x^2 + 2x+4) - (x^2 +2x+1)

I'm going to rewrite this using distributive propery and without parenthesis:

3x^2 + 2x + 4 - x^2 - 2x - 1

Now I'm going to pair up any like terms by use of the commutative property.

3x^2 - x^2 + 2x - 2x + 4 - 1

Now simplify:

2x^2 + 0 +3

2x^2+3

Answer:

The final value of subtraction is 2x² + 3

Step-by-step explanation:

It is given that (3x² + 2x + 4) - ( x² + 2x + 1)

To find the value of subtraction

(3x² + 2x + 4) - ( x² + 2x + 1) =  (3x² + 2x + 4 -  x² - 2x - 1)

 = 3x² - x² + 2x - 2x + 4 - 1

 = 2x² + 0 +3

 = 2x² + 3

Therefore the final value of subtraction is 2x² + 3

Using the Pythagorean theorem c^2 = a^2 + b^2

Where c is the hypotenuse and a and b are the side lengths.

c^2 = 12^2 + 16^2

c^2 = 144 + 256

c^2 = 400

c = √400

c = 20

The hypotenuse is 20 units.

Answer:

Hypotenuse = 20 units.

Step-by-step explanation:

Using the Pythagoras theorem:

h^2 = 12^2 + 16^2

h^2 = 144 + 256 = 400

h = 20.

Answer:

[tex](f+g)(x)=3^x+4x+8[/tex]

if [tex]f(x)=3^x+10[/tex] and [tex]g(x)=4x-2[/tex].

Step-by-step explanation:

We are given [tex]f(x)=3^x+10[/tex] and [tex]g(x)=4x-2[/tex].

We are asked to find [tex](f+g)(x)[/tex].

[tex](f+g)(x)[/tex] means [tex]f(x)+g(x)[/tex]

[tex](f+g)(x)=(3^x+10)+(4x-2)[/tex]

You only have one pair of like terms, that is the constants.

[tex](f+g)(x)=3^x+4x+10-2[/tex]

[tex](f+g)(x)=3^x+4x+8[/tex]