What integer is equivalent to 9 3/2

Answers

Answer 1
first off, we change the mixed fraction to "improper" and then we make it a decimal.

[tex]\bf \stackrel{mixed}{9\frac{3}{2}}\implies \cfrac{9\cdot 2+3}{2}\implies \stackrel{improper}{\cfrac{21}{2}}\implies 10.5 \ne \mathbb{Z}[/tex]

an integer is a "whole" number, with no decimals.

Related Questions

The cylinder shown has a volume of π in3. Find the volume of a cone with the same base and height as the cylinder.

Answers

The volume of a cylinder is 3 times larger than a cylinder. So find your answer for the cylinder and multiply it by 1/3 to get your answer. Hope this helps! Study on!

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose the height of cylinder is h and radius of base is r.

The volume of cylinder will be : [tex]\pi r^2h[/tex]

The cone is of same height means h and same base means radius will be r.

The formula of volume of cone is : [tex]\frac{1}{3} \pi r^2h[/tex]

It means the volume of cone is one third of the volume of cylinder.

The volume of cylinder is given as π.

So, the volume of cone will be : [tex]\frac{\pi }{3}[/tex]   :   Answer

Hope it will help :)

J is 25 more than 3 help???

Answers

j would equal 28!!!!!!!!!!!!!!!!!!!
I think the answer would be 28

You were just approved for a $32,000 car loan at an APR of 1.99% for 60 months. As you make payments over time: your payment is , the amount of interest you will pay each month , and the amount of principal you pay each month .

Answers

What it Means...

If you borrow $32,000 at 1.99% for 5 years, your monthly payment will be $560.75.

The payments do not change over time. The loan amortizes over the repayment period, meaning the proportion of interest paid vs. principal repaid changes each month. As the loan amortizes, the amount of monthly interest paid decreases while the amount of principal paid increases.

Loan Amount: $32,000
Term (years): 5     (60 Months)

Annual Interest Rate (%): 1.99% Monthly Payment = $560.75


Check out upload files 

Amortization Schedule

Find the points on the curve y = 2x3 + 3x2 − 12x + 9 where the tangent line is horizontal.

Answers

y = 2x^3 + 3x^2 − 12x + 9
y' = 6x^2 + 6x − 12

tangent line is horizontal y'=0
6x^2 + 6x − 12=0
x^2+x-2=0
(x+2)(x-1)=0
x=-2 or x=1
when x=-2, y=2x^3 + 3x^2 − 12x + 9 = -16 + 12 + 24 + 9 =29
when x=1, y=2x^3 + 3x^2 − 12x + 9 = 2 +3 -12 +9 =2
two points (-2,29),(1,2) 



2).  y = 2x^3 + 3x^2 − 12x + 9

slope of horizontal-tangent-line, y' = 6x^2+6x-12 = 0
SO,
6(x+2)(x-1) = 0,
x=1, and x=-2,
SO, for, x= 1, y= 2+3-12+9 = 2,
Hence,
the  1st. point is : Answer (1, 2)  

and, for, x=-2,
y = 2(-2)^3 +3(-2)^2 -12(-2) +9 = -16+12+24+9 = 29
Hence,
the 2nd-point is : Answer (-2, 29) 

the points on the curve [tex]y = 2x^3 + 3x^2 - 12x + 9 are (-2,29) \; and \; (1,2)[/tex]where the tangent line is horizontal.

Given :

The equation of the curve is [tex]y=2x^3\:+\:3x^2\:-\:12x\:+\:9[/tex]

Given tangent line is horizontal . Tangent line is horizontal when slope =0

Slope is nothing but the derivative.

So we find out x values where derivative =0

Lets take derivative for the given curve y

[tex]y=2x^3+3x^2-12x+9\\y'=2(3x^2)+3(2x)-12\\y'=6x^2+6x-12[/tex]

Now we set the derivative =0 and solve for

[tex]6x^2+6x-12=0\\Divide\; whole \; equation \; by \; 6\\x^2+x-2=0\\(x+2)(x-1)=0\\x+2=0, x=-2\\\\x-1=0, x=1[/tex]

So , the slope =0 when x=1 and x=-2

Now we find out the points . Use the original function

[tex]y=2x^3\:+\:3x^2\:-\:12x\:+\:9\\x=-2\\2\left(-2\right)^3+3\left(-2\right)^2-12\left(-2\right)+9=29\\(-2,29)\\\\x=1\\2\left(1\right)^3+3\left(1\right)^2-12\left(1\right)+9=2\\(1,2)[/tex]

the points on the curve [tex]y = 2x^3 + 3x^2 - 12x + 9 are (-2,29) \; and \; (1,2)[/tex]where the tangent line is horizontal.

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given right triangle XYZ what is the value of tan 60°

Answers

I have attached the image associated with this question

Answer:
tan (60) = √3

Explanation:
The given triangle is right-angled triangle, therefore, we will use Pythagorean theorem to get the length of the third side.
third side = sqrt [(hypotenuse)^2 + (second side)^2]
third side = 21√3 units

Since the given triangle is a right-angled triangle, we can apply the special trigonometric identities.
Therefore:
tan θ = opposite / adjacent
In the given triangle:
θ = 60°
The opposite side = 21√3
The adjacent side = 21

Substitute in the above equation to get tan 60 as follows:
tan (60) = (21√3) / (21) = √3

Hope this helps :)

Answer:

√3

Step-by-step explanation:

got 100%

Look at the figure. How can you prove ∆ABD and ∆ACD are congruent?


A. ∆ABD ≅ ∆ACD by the SAS Postulate.


B. It is not possible to determine if the triangles are congruent.


C. ∆ABD ≅ ∆ACD by the SSS Postulate.

Answers

I think its A. what does everybody else think?

Answer:  The correct option is (B).  It is not possible to determine if the triangles are congruent.

Step-by-step explanation:  We are given to select the correct option by which we can prove that ∆ABD and ∆ACD are congruent.

As shown in the figure,

In ∆ABD and ∆ACD, we have

∠ADB = ∠ADC = 90°,

AD is the common side.

So, one angle and the adjacent side of one triangle are congruent to the corresponding angle and the adjacent side of the other triangle.

That is, to prove that the two triangles are congruent, we need one of the following two conditions:

(i)  BD = CD

or

(ii) ∠BAD = ∠CAD.

Since none of these two are given, so we cannot determine the congruence of the two triangles.

Therefore, it is not possible to determine if the triangles are congruent.

Thus, option (B) is correct.

PLZZZZZZ HELPPPP

Solve the system of equations using the substitution method.
{2x+8y=4x=−3y+5 Enter your answers in the boxes.

Answers

2x + 8y = 4
x = -3y + 5

plug in the value of x, from the second equation, into the first
2(-3y + 5) + 8y = 4
-6y + 10 + 8y = 4
combine like terms
2y + 10 = 4
subtract 10
2y = -6
divide both sides by 2
y = -3

then, plug what you got for y into one of the equations
x = -3y + 5
x = -3(-3) + 5
x = 9 + 5
x = 14

Hope this helps! And yes, it's correct!

The method of substitution is a three step method to solve the equations. In this method , one equation for one of the variables is solved and in the first step.

The outcome is then substituted to the second equation in the second step for solving the equation.The value is re-substituted to the original equation to find the outcome in the third step.

On solving the equations by substitution method we get x=14 and y=-3

Calculation:

Given equations:

[tex]\rm 2x+8y = 4[/tex]                                                     (1)

[tex]\rm x=-3y+5[/tex]                                                    (2)

On substituting [tex]x=-3y+5[/tex] in equation 1:

[tex]\begin{aligned}\rm 2(-3y+5)+8y&=4\\\\-6y+10+8y&=4\\\\2y+10&=4\\\\2y&=4-10\\\\ 2y &= -6\\\\y&=\dfrac{-6}{2}\\\\y&=-3\end[/tex]

Substituting [tex]\rm y=-3[/tex] in equation 2:

[tex]\rm x&=-3y+5\\\\x&=-3(-3)+5\\\\x=9+5\\\\x=14[/tex]

Therefore the values of x and y for the given equations is 14 and -3 respectively.

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How much would $500 invested at 7% interest compounded annually be worth after 5 years?

Answers

interest compound= p(r+1)^t     A=interest compound

7%= 7/100=0.07
A=500(0.07+1)^5
A=701.28

if x2 = 49 the only possible answer for x is 7

Answers

Solve for x over the real numbers:
x^2 = 49

Take the square root of both sides:
Answer:  x = 7 or x = -7

While the equation x² = 49 suggests that x = 7, it also has a negative solution, x = -7. Both solutions can be verified by substitution into the original equation, proving they are correct through resulting identities.

The equation x² = 49 has two solutions in the realm of real numbers, not just x = 7. To find the values of x that satisfy the equation, we take the square root of both sides. Since the square root of a number has both a positive and a negative value, the solutions are x = 7 and x = -7. To verify these solutions, we can substitute them back into the original equation to confirm that they work, demonstrating identities such as 7² = 49 and (-7)² = 49.

The formula for the volume of a cube is V(s) = s3 where s is the side length of the cube. In which quadrant(s) is the graph of the function V(s)?

Answers

For this case what you should know is that we are in the presence of a cubic function that could take both positive and negative values.
 However, when talking about the volume of a figure, a cube specifically, so that there is a physical sense, it must be fulfilled:
 s> 0
 Thus:
 V (s)> 0
 Thus, the function V (s) = s3 belongs to the first quadrant.
 Answer:
 the graph of the function V (s) is in the first quadrant.

Answer:

The answer is A: Quadrant 1

Step-by-step explanation:

On Edge :)

how many rootes are in f(x)=(x^2-3x+1)^2
2
5
6
9

Answers

Since there is an x^2 inside the parenthesis, there will be only 2 roots.  so A

Robin randomly selects a number between 1 and 20. What is the probability that the number selected is the square of a natural number?

Answers

All of the natural squares from one to twenty are  1,4,9, and 16. This means there is 4 out of 20 which can be reduced to 1 out of 5 or 20%

The probability that the number selected is the square of a natural number will be 0.20.

What is probability?

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

Robin randomly selects a number between 1 and 20.

Then the total number of the events will be

Total events = 20 {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}

The probability that the number selected is the square of a natural number will be

We know that natural numbers 1, 2, 3, 4, 5, and so on.

Then the square of the natural  numbers will be

1, 4, 9, 16, 25, ....

Favorable event = 3 {1, 4, 9, 16}

Then the probability will be

P = 4 / 20

P = 1/5

P = 0.20

The probability that the number selected is the square of a natural number will be 0.20.

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Assume that when adults with smartphones are randomly​ selected, 48​% use them in meetings or classes. If 55 adult smartphone users are randomly​ selected, find the probability that at least 22 of them use their smartphones in meetings or classes.

Answers

This is a problem of Binomial Probability.

Success Rate = p = 0.48
Sample Size = n = 55
Number of success = x = 22

We are to find [tex]P(X \geq 22)[/tex] i.e. that probability that atleast 22 adults use the smartphone in meetings or class.

The probability can be calculated using the Binomial Calculators and it comes out to be 0.907.

This means there is 0.907 or 90.7% probability that there are atleast 22 adults among the 55 selected adults who use cell phones in meeting or class.

Determine if the functions are even, odd or neither. f(x) = -5x4 - 2 and g(x) = x3 + 2x

Answers

Try this option:
the rule: if f(-x)=f(x), then the function f(x) is even, if f(-x)=-f(x) then the function is odd.
1. f(x)=-5x⁴-2;
if to substitute x→(-x), then f(-x)=-5*(-x)⁴-2; ⇔ f(-x)=-5x⁴-2, in other words f(x)=f(-x), it means that this function is even.
2. f(x)=x³+2x.
if to substitute x→(-x), then f(-x)=(-x)³+2*(-x); ⇔ f(-x)=-(x³+2x), in other words f(-x)=-f(x), it means that this function is odd.

Write the explicit formula for the geometric sequence.

64, 32, 16, 8, ...
A) an = 8 · 4n-1
B) an = 8 · 2n-1
C) an = 32 · 0.5n-1
D) an = 64 · 0.5n-1

Answers

Answer:

D) [tex]a_{n}[/tex][tex]=64[/tex]×[tex]0.5^{n-1}[/tex]

Step-by-step explanation:

The answer is D because it is the only answer that has an=64 and a decimal, 64 is your first term and the sequence is getting smaller

AND OR

Answer:

D) [tex]a_{n}[/tex][tex]=64[/tex]×[tex]0.5^{n-1}[/tex]

Step-by-step explanation:

Explicit Formula: an = a1 · dn-1

a1 = 64, d = 0.5

an = 64 · 0.5n-1

For which k will the graph of f(x)=x^2−kx+k^2 cross the x-axis twice?

Answers

for the graph to cross the x axis twice, b²-4ac needs to be larger than 0
b=-k, a=1, c=k²
b²-4ac=k²-4k²=-3k²
-3k² will never be larger than 0. 

Evaluate the integral. (use c for the constant of integration.) 7 ln(x)/ x sqrt(5 + (ln(x))^2) dx

Answers

Okay, so we have 

[tex] \int\limits { \dfrac{7ln(x)}{x \sqrt{5+ln(x)^2}}} \, dx [/tex].

Substitute [tex]u=ln(x)^2+5[/tex] and differentiate.
[tex]dx= \dfrac{x}{2ln(x)}du[/tex]
[tex] \dfrac{7}{2} \int\limits { \dfrac{1}{ \sqrt{u}}} \, du [/tex]

[tex]\int\limits { \dfrac{1}{ \sqrt{u}}} \, du = 2 \sqrt{u} [/tex]

[tex] \dfrac{7}{2} \int\limits { \dfrac{1}{ \sqrt{u}} } \, du = 7 \sqrt{ln(x)^2+5}+C [/tex]

The expression for the integral [tex]\int\frac{7ln(x)}{x\sqrt{5+(ln(x))^2} } dx[/tex] after the evaluation is [tex]\text{I}=7\sqrt{5+(ln(x))^2} +C[/tex].

Given an integral expression:

[tex]\text{I}=\int\frac{7ln(x)}{x\sqrt{5+(ln(x))^2} } dx[/tex]

This can be written as:

[tex]\text{I}=7\int\frac{ln(x)}{x\sqrt{5+(ln(x))^2} } dx[/tex]

It is required to find the integral value.

Let u = 5 + (ln (x))²

Differentiate.

[tex]du=2ln(x)*\frac{1}{x} dx[/tex]

Or [tex]\frac{du}{2} =\frac{lnx}{x} dx[/tex]

Substitute the values.

[tex]\text{I}=7\int\frac{1}{\sqrt{u} } \frac{du}{2}[/tex]

[tex]\text{I}=\frac{7}{2} \int\frac{1}{\sqrt{u} }du[/tex]

[tex]\text{I}=\frac{7}{2} (2\sqrt{u} )+C[/tex]

Substitute back the value of u.

[tex]\text{I}=7\sqrt{5+(ln(x))^2} +C[/tex]

Hence the value of the integral is [tex]\text{I}=7\sqrt{5+(ln(x))^2} +C[/tex].

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What is the volume of the figure below if a = 3.9 units, b = 5.7 units, and c = 3 units?

A. 157.95 cubic units
B. 351.351 cubic units
C. 124.605 cubic units
D. 113.49 cubic units

Answers

a x a x c = 3.9 * 3.9 * 3 =45.63
45.63 * 2 = 91.26

a x b x c = 3.9 * 5.7 * 3 = 66.69

66.69 + 91.26 = 157.95 cubic units

Final answer:

The volume of the parallelepiped with sides of lengths a = 3.9 units, b = 5.7 units, and c = 3 units is given by the formula V = a × b × c. After performing the calculation, the volume comes out to be 66.87 cubic units.

Explanation:

To find the volume of the parallelepiped with edges of lengths a, b, and c, you can multiply the length of each edge together. The volume (V) of a parallelepiped (a three-dimensional figure formed by six parallelograms) is given by the product of the lengths of its three dimensions. In this case, the formula to calculate the volume is V = a × b × c.

By plugging in the values provided:

a = 3.9 units

b = 5.7 units

c = 3 units

We get:

V = 3.9 units × 5.7 units × 3 units

Doing the multiplication:

V = 66.87 cubic units

Therefore, the volume of the figure is 66.87 cubic units.

Treys online music club charges a monthly rate of $20 plus $0.80 per song download. Debs online music club charges a monthly rate of $21 plus $0.60 per song download. For what number of songs will the monthly charge be the same for both clubs? How much will it cost?

Answers

 For this case, the first thing we must do is define variables.
 We have then:
 x: number of songs.
 y: total charge
 For Treys online music club:
 [tex]y = 0.80x + 20 [/tex]
 For Debs online music club:
 [tex]y = 0.60x + 21 [/tex]
 Equaling both equations we have:
 [tex]0.80x + 20 = 0.60x + 21 [/tex]
 Clearing x we have:
 [tex]0.80x - 0.60x = 21 - 20 0.20x = 1 x = 1 / 0.20 x = 5 songs[/tex]
 Substituting the value of x for any of the equations we have:
 [tex]y = 0.60 (5) + 21 y = 3 + 21 y = 24 $[/tex]
 Answer:
 The monthly charge will be the same for 5 songs in both clubs.
the cost will be $ 24

Answer:

For 5 songs the monthly charge be the same for both clubs.

It will cost $ 24.

Step-by-step explanation:

Let, for x songs, the monthly charges are same for both clubs,

Given,

For Treys online music club,

Monthly rate = $ 20,

Additional Charges for a song = $ 0.80,

⇒ Additional Charges for x song = $ 0.80x,

Thus, the total monthly charges for x songs = Monthly rate + Additional Charges for x song

= 20 + 0.80x

Now, for Debs online music club,

Monthly rate = $ 21,

Additional Charges for a song = $ 0.60,

⇒ Additional Charges for x song = $ 0.60x,

Thus, the total monthly charges for x songs = Monthly rate + Additional Charges for x song

= 21 + 0.60x

Hence, we can write,

[tex]20 + 0.80x = 21 + 0.60x[/tex]

[tex]0.80x - 0.60x = 21 - 20[/tex]

[tex]0.20x = 1[/tex]

[tex]\implies x = \frac{1}{0.20}=5[/tex]

Hence, for 5 songs the monthly charge be the same for both clubs.

Also, the cost for 5 songs = 20 + 0.80 × 5 = 20 + 4 = $ 24

tickets for a football match are sold at $30 for adults and $15 for children a company bought 28 tickets if x of these tickets were for adults, write in terms of x a. the number of tickets for children b. the amount spent on tickets for adults c. the amount spent on tickets ...

Answers

Final answer:

The number of tickets for children is represented by '28-x' and the amount spent on tickets for adults is '$30x'. The amount spent on tickets for children is '$15*(28-x)'.

Explanation:

We will use the concept of algebraic expressions to solve this question. If we represent the number of adult tickets as x, we know that the total number of tickets is 28. Hence, the number of children tickets can be represented as 28-x. The cost of a ticket for adults is $30, so the amount spent on adult tickets can be represented as $30x. Similarly, as the cost of a ticket for children is $15, the amount spent on children tickets can be represented as $15*(28-x).

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Final answer:

The number of ticket for children is (28 - x), the amount spent on tickets for adults would be $30x, and the total amount spent on tickets would be $30x + $15(28 - x).

Explanation:

If a company bought 28 tickets and x of these tickets were for adults, then:

a. The number of tickets for children would be 28 - x. This is because from the total number of tickets purchased, we subtract the number of adult tickets to find the number of children's tickets.

b. The amount spent on tickets for adults would be $30x. This is because each adult ticket costs $30 and there are x number of adults.

c. To find out the total amount spent by the company, we will multiply the number of adult tickets by the price of an adult ticket ($30x) and add this to the product of the number of children tickets (28 - x) and the price of a child's ticket ($15). Therefore, the total spent would be $30x + $15(28 - x).

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226Ra has a half-life of 1599 years. How much is left after 1000 years if the initial amount was 10 g?

Answers

[tex]\bf \textit{Amount for Exponential Decay using Half-Life}\\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\to &10\\ t=\textit{elapsed time}\to &1000\\ h=\textit{half-life}\to &1599 \end{cases} \\\\\\ A=10\left( \frac{1}{2} \right)^{\frac{1000}{1599}}[/tex]

Find the inverse of this 3x3 matrix. [1 5 2]
[ 1 1 7]
[0 -3 7]

Answers

Lets say the 3x3 Matrix is 

M =   [1   5   2 ]
         [1   1   7 ]
         [0  -3   7 ]

We apply the Gauss-Jordan elimination method (Procedure and result shown in the image below)

Answer:

A

Step-by-step explanation:

⎡−25 26 −33⎤

⎥  4   −4    5  ⎥

⎥  3   −3    4  ⎦

What the complement of 54.6 degree

Answers

complementary angles add up to 90°, if say the angle is "x", then 

x + 54.6° = 90°

x = 90° - 54.6°.

I WILL GIVE U BRAINLY!!!



Which substance has been changed most over time from its original plant material?



A.

peat



B.

anthracite coal



C.

bituminous coal




D.

lignite

Answers

lignite . . . .......... ............. .......... ............. .
.
...
Lignite, is the correct answer hope this helps

2x - y + 3z = -9
x + 3y - z = 10
3x + y - z = 8

find the ordered triple

Answers

Try the suggested option, note, that the used method is Gauss' method.

PLEASE HELPS NEED THIS DONE BEFORE 3 O CLOCK

1)Jerome noticed the following house numbers on his street:

305, 318, 331, 344

The house numbers follow a pattern. Which expression can be used to determine the nthnth house number on his street?

A) 292 +13n

B) 292n

C) 292n + 13

D) 13(n + 292)

2) A polynomial expression is shown below.

(mx+8)(2x−4)

The expression is simplified to:

−6x2+28x−32-6x2+28x-32

What is the value of m?


A) 3

B) 4

C) -3

D) -4

3) What is the domain of the function shown below? (PICTURE AT BOTTOM)

A) 2
B) −8 ≤ x <3and 4 ≤ x <8

C) −8 ≤ x < 8

D) −7 ≤ x ≤ 7







Answers

1) Put n=2 in each of the offered expressions and see which one gives you 318 (the second house number).
  A) 292 + 13*2 = 318 . . . . a good candidate
  B) 292*2 = 584 (nope)
  C) 292*2 + 13 = 597 (nope)
  D) 13(2 + 292) = 3822 (nope)
The appropriate choice is ...
  A) 292 +13n

2)The squared term in the product is 2mx^2. The squared term in the given expression is -6x^2. Comparing the coefficients, we have
  2m = -6
  m = -3
The appropriate choice for the value of m is ...
  C) -3

3) The end point of one segment matches up with the beginning of the next except in the region 3 ≤ x < 4.
The appropriate choice is ...
  B) -8 ≤ x < 3 and 4 ≤ x < 8

Answer:

Jerome noticed the following house numbers on his street:

Answer 292 +13n

A polynomial expression is shown below. What is the value of m?

Answer -3

What is the domain of the function shown below

Answer −8 ≤ x <3and 4 ≤ x <8

Quadrilateral ABCD ​ is inscribed in a circle. What is the measure of angle A? Enter your answer in the box. m∠A= ° A quadrilateral inscribed in a circle. The vertices of the quadrilateral lie on the edge of the circle and are labeled as A, B, C, D. The interior angle A is labeled as left parenthesis 3 x plus 6 right parenthesis degrees. The angle C is labeled as left parenthesis x plus 2 right parenthesis degrees.

Answers

Since the quadrilateral is inscribed in the circle, the two angles add to a 180 degrees angle. 
We deduce the following equation:
[tex](3x+6)+(x+2)=180[/tex]
Solve for x like  this:
[tex](3x+x)+(6+2)=180\\4x=180-8\\4x=172\\x=43.[/tex]

Now we deduce the measure of A:
[tex]A=3x+6=3\times(43)+6=135[/tex]
Final answer:

The measure of angle A in a cyclic quadrilateral ABCD, where the measure of angle A is (3x + 6) degrees and the measure of angle C is (x + 2) degrees, is determined to be 135 degrees.

Explanation:

Given that quadrilateral ABCD is inscribed in a circle, it follows from the properties of cyclic quadrilaterals that the sum of the opposite angles of such a quadrilateral is always 180 degrees. Therefore, if the measure of angle A is represented by the expression (3x + 6) degrees and the measure of angle C is represented by the expression (x + 2) degrees, then we can set up an equation that   (3x + 6) + (x + 2) = 180. Solving this equation gives x = 43. Using x = 43, substitute it into 3x + 6 to get the value of angle A, which is equal to 135 degrees.

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Please try this, I forget absolutely everything about rhombuses. Thanks for all the help, shouldn't be too hard

Answers

so, check the picture below.  It has four sections.

the volume of a pyramid is, 1/3 ( base area)(height).

well, we know the base is a rhombus, and rhombuses diagonals meet at right-angles, therefore the center O has 4 right-angles where they meet.

since we know the angle at A, 50°, and since rhombuses are quadrilaterals with all equal sides, we know all the sides are 6 long, and the angle at C is 50° as well, and the remaining angles are 130°, as shown there.

now, if we tease out one of those triangles from the rhombus, as shown on the 1st section in the picture, we can say use the angle of 65° to get "x" and "y" lengths

[tex]\bf cos(65^o)=\cfrac{x}{6}\implies 6cos(65^o)=x \\\\\\ sin(65^o)=\cfrac{y}{6}\implies 6sin(65^o)=y[/tex]

now, we'll use those to get the area of the rhombic base.

and then onto the second section

is a right-triangle with a perpendicular line through it, which creates 3 similar triangles, by using the "geometric mean" of "w" there.

anyhow, we used the medium-sized and large-sized triangles there, to draw proportions and get what the "w" distance is, and you can see there what "w" is.

and onto the 3rd section

now that we know how long "w" is, we can use the triangle containing the 40° angle, in order to get the pyramid's height of "h", by using the tangent function, as you see there.

and we also use the same triangle, to get the "z" distance, which is namely the slant-height of the pyramid, however, is also the "altitude" of the triangular faces.

and onto the 4 and last section in the picture

that's a triangular face by herself, it has a base of 6, and an altitude of "z".



now, all that said, let's plug those values to get the volume, and then the surface area, keeping in mind the surface area is just the area of the rhombus plus the area of all four triangles.


[tex]\bf V=\cfrac{1}{3}\left[ \stackrel{\textit{area of the rhombic base}}{4\left( \frac{1}{2}xy \right)} \right](h) \\\\\\ SA=\left[ \stackrel{\textit{area of the rhombic base}}{4\left( \frac{1}{2}xy \right)} \right]~~+~~\left[ \stackrel{\textit{area of the four triangles}}{4\left[ \frac{1}{2}(6)(z) \right]} \right][/tex]

x ≈ 2.54     y ≈ 5.44    w ≈ 2.298    h ≈ 1.93    z = 3

V ≈ 17.7265                         SA ≈ 63.58 

Suppose that the probabilities of a customer purchasing​ 0, 1, or 2 books at a book store are 0.2​, 0.4​, and 0.4​, respectively. what is the expected number of books a customer will​ purchase? the standard deviation of the​ customer's book purchases is

Answers

Porobability distribution of X
x      P(x)
0       0.2
1       0.4
2       0.4
Total .1.0
i] Expectation
Mean=Σxp
Variance=x²p-(∑xp)²
thus:
Mean=(0*0.2)+(1*0.4)+(2*0.4)
=0+0.4+0.8
=1.2

ii] Variance
Variance=[(0²*0.2)+(1²*0.4)+(2²*0.4)]-(1.2)²
=[0+0.4+1.6]-1.44
=0.56
hence:
standard deviation=sqrt(0.56)=0.74833

The expected number of books a customer will purchase is 1.2 books, and the standard deviation of their book purchases is approximately 0.78 books.

To find the expected number of books a customer will purchase,

use the formula for the expected value (also known as the mean) of a random variable:

Expected Value (μ) = Σ (x × P(x))

Where:

μ is the expected value.

x represents the possible values of the random variable (in this case, 0, 1, and 2).

P(x) is the probability associated with each value of x.

Probability of purchasing 0 books (P(0)) = 0.2

Probability of purchasing 1 book (P(1)) = 0.4

Probability of purchasing 2 books (P(2)) = 0.4

Now, calculate the expected value:

μ = (0 × 0.2) + (1 ×0.4) + (2 × 0.4)

μ = 0 + 0.4 + 0.8

μ = 1.2

To find the standard deviation (σ) of the customer's book purchases,

use the formula for the standard deviation of a discrete random variable:

Standard Deviation (σ) = √[Σ((x - μ)² × P(x))]

Where:

σ is the standard deviation.

x represents the possible values of the random variable.

μ is the expected value.

P(x) is the probability associated with each value of x.

In this case, you already calculated μ as 1.2, and you have the probabilities P(0), P(1), and P(2).

Now, calculate the standard deviation:

σ = √[((0 - 1.2)² × 0.2) + ((1 - 1.2)² × 0.4) + ((2 - 1.2)² × 0.4)]

σ = √[(1.44 ×0.2) + (0.16 × 0.4) + (0.64 × 0.4)]

σ = √[0.288 + 0.064 + 0.256]

σ = √0.608

σ ≈ 0.78

Therefore, the expected number and the standard deviation of books a customer will purchase is 1.2 books and approximately 0.78 books respectively.

Learn more about expected number here

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Complete the square to form a perfect square trinomial x^2-14x+

Answers

Answer: x^2 - 14x + 49

Explanation:

1) Divide the coefficient of x by 2:

14 / 2 = 7

2) so you have to add 7^2 = 49

x^2 - 14x + 49

3) that trinomial is equivalent to:

=> (x - 7)^2

4) prove that using the formula (a - b)^2 = a^2 - 2ab + b^2

(x - 7)^2  = x^2 - 14x + 49

Then you have to add 49 to complete the square. and form a perfect square trinomial.
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