For a machine, the output force is 20 N, and the output distance is 4 m. Which must be true about the work input? A. It equals 80 J. B. It must be greater than 80 J. C. It must be less than 80 J.
If 8900 is invested at 3.8%
A machine packs at a constant rate of 2/3 of a box every 1/2 minuet. What’s is the number of boxes per minute that’s the machine packs?
If a force of 60 N is exerted on a 15 kg object, calculate the acceleration that the object undergoes. ________ m/s2 4 900 0.25 40
Answer: The correct option is
(A) 4 m/s.
Step-by-step explanation: We are given that a force of 60 N is exerted on a 15 kg object.
We are to calculate the acceleration that the object undergoes.
From Newton's second law of motion, we have
[tex]F=ma,[/tex] where m is the mass of the object, a is the acceleration and F is the force exerted.
For the given object, we have
F = 60 N and m = 15 kg.
So, we get
[tex]F=ma\\\\\Rightarrow 60=15\times a\\\\\Rightarrow a=\dfrac{60}{15}\\\\\Rightarrow a=4.[/tex]
Thus, the required acceleration that the object undergoes is 4 m/sec.
Option (A) is CORRECT.
WILL MARK AS BRAINLIEST
Complete the general form of the equation of a sinusoidal function having an amplitude of 1, a period of [tex]\frac{ \pi }{2} [/tex], and a vertical shift up 3 units.
y=__________
Answer:
y = sin(4x) + 3
Step-by-step explanation:
5. (10.01 MC) If sin θ = 1 over 4 and tan θ > 0, what is the value of cos θ? (1 point)
To find the value of cos θ when sin θ = 1/4 and tan θ > 0, use the Pythagorean identity. As the angle is in the first quadrant, cos θ is positive and equals the square root of 15/16 or √15/4.
If sin θ = 1/4 and tan θ > 0, we need to determine the value of cos θ. When the sine of an angle is positive and the tangent is positive, we know the angle must be in the first quadrant, where all trigonometric functions are positive. To find cos θ, we utilize the Pythagorean identity sin2 θ + cos2 θ = 1. Rewriting this identity for cos θ, we get cos2 θ = 1 - sin2 θ.
Substituting the given value of sin θ, we have:
cos2 θ = 1 - (1/4)2
cos2 θ = 1 - 1/16
cos2 θ = 15/16
Since θ is in the first quadrant, and cos θ is positive, the value of cos θ is the positive square root of 15/16:
cos θ = √(15/16)
cos θ = √15/4 or approximately 0.9682
Simplify these 12 radicals:
1) √80 2) √64
3) √45 4) √54
5) √32 6) √36
7) √150 8) √20
9) √180 10) √72
11) √8 12) √50
A job applicant estimates that his chance of passing a qualifying examination is 2/3, and his chance of being appointed if he does pass is 1/4. What is the probability that he will receive the job?
Hence, the probability that he will receive job is:
1/6
Step-by-step explanation:It is given that:
chance of passing a qualifying examination is 2/3=P
and chance of being appointed if he does pass is 1/4=P'
Now, we are asked to find the probability that he will receive the job.
We are asked to find the probability that he will receive the job.
The probability is calculated as:
Probability that he qualify exam×Probability that he is being appointed.
=P×P'
=(2/3)×(1/4)
=1/6
PLEASE HELP QUICK!!!!
11PTS AND BRAINLIEST AVAILABLE TO CORRECT ANSWER
10 POINTS + BRAINLIEST ANSWER
A box contains 30 pieces of chocolate, distributed as shown in the table below. Each piece is made of either white chocolate or dark chocolate, and each piece contains either cream filling or no filling. If one piece is selected at random, what is the probability that the piece is either white chocolate with cream filling or dark chocolate with no filling? (10 POINTS + BRAINLIEST ANSWER)
A. 8/30
B. 12/30
C. 20/30
D. 22/30
The probability of selecting a chocolate at random that is either white chocolate with cream filling or dark chocolate with no filling is [tex]\frac{8}{30}[/tex].
What is probability?Probability is the chance of happening an event or incident.
Given, the box contains 30 chocolates.
The number of chocolates that are white chocolate with cream filling is 5.
Therefore, the probability of selecting a chocolate at random that is white chocolate with cream filling is [tex]= \frac{5}{30}[/tex].
The number of chocolates that are dark chocolate with no filling is 3.
Therefore, the probability of selecting a chocolate at random that is dark chocolate with no filling is [tex]= \frac{3}{30}[/tex].
Now, the probability of selecting a chocolate at random that is either white chocolate with cream filling or dark chocolate with no filling is
[tex]= \frac{5}{30} + \frac{3}{30} \\= \frac{8}{30}[/tex]
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how do graphs of y=1/x and y=5/(x+6) compare? I know the second graph shifts to left by 6 units but does it move down and how many units?
Answer:
y = 5/x +6 makes your raises your graph 6 units higher.
Step-by-step explanation:
Which group of measurements could be the side lengths of a right triangle?
A.
57 in, 86 in, 95 in
B.
47 in, 76 in, 95 in
C.
57 in, 76 in, 95 in
D.
57 in, 76 in, 105 in
The storage container below is in the shape of a rectangular prism with a height of 6 feet and a length that is 2 feet more than its width. recall that the formula for the volume of a rectangular prism is v = l · w · h, where l is the length, w is the width, and h is the height. write the equation that represents the volume of the storage container in terms of its width.
Answer:
V = 6w² + 12w
Step-by-step explanation:
Lena runs 2/3 mile each day she wants to know how many miles she has to run before she has has run a whole number
If cos thetha =-0.96 and (sec thetha)(sin thetha)>0 find the value of tan thetha
What is the reciprocal of 4 3/7? Please help!
The reciprocal of number 4 3/7 is 7/31.
What is a fraction?In such a fraction, the value that appears above the horizontal line is referred to as the numerator.
It represents the number of pieces removed from the whole. The denominator of a fraction is the numerical value that comes before the brings together various.
Given the mixed number
4 3/7 = (7×4 + 3)/7
⇒ 31/7
Now reciprocal is nothing but an interchange of numerator and denominator.
So
Reciprocal of 31/7 → 7/31
Hence "The reciprocal of number 4 3/7 is 7/31".
For more about fractions,
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find the solution of this system of equations shown on the graph.
Solve the system of equations
1.8x-0.5y=-6.4
0.6x+2.1y=2.4
_______________________
x= ??
y= ??
write an equation of the line that is parallel to the line y = -x + 4 and passes through the points 0, 10.
Please help me!
Jax solved an equation and justified his steps as shown below. What reason would justify step 2?
3x + 5 > 2 Step 1: Given
3x > -3 Step 2: ?
x> -1 Step 3: Division Property of Equality
a. Combine Like Terms
b. Division Property of Equality
c. Subtraction Property of Equality
d. Multiplication Property of Equality
Step 2 can be justified using the Multiplication Property of Equality. This property states that if we multiply or divide both sides of an inequality by the same number, the inequality will still hold true.
Explanation:Step 2 can be justified using the Multiplication Property of Equality. This property states that if we multiply or divide both sides of an inequality by the same number, the inequality will still hold true.
In this case, Jax divided both sides of the inequality by 3. This is a valid step because dividing both sides of the inequality by a positive number does not change the inequality. So, by dividing both sides by 3, Jax found that x > -1.
What are two solutions of 3 + 4 |x/2 + 3| = 11?
Two or more lines on a graph together is known as a
darren has 3/4 of a gallon of soil.he needs to plant 5 small plants.if he splits the soil evenly between the plants.how much soil will each plant get?
5x - 20 = 2x + 10 How do you solve this problem?
The population P(t) of a species satisfies the logistic differential equation dP/dt= P(2-(P/5000)) where the initial population 3,000 and t is the time in years. What is the lim t>infinity P(t)?
The lim t>infinity P(t) is 5,000, which is the carrying capacity of the species.
Explanation:The logistic differential equation dP/dt = P(2-(P/5000)) models the population growth of a species. To find the lim t>infinity P(t), we need to find the stable population when t becomes very large. In this equation, the population growth rate is initially exponential, but as the population approaches its carrying capacity (Q), the growth rate slows down and levels off to zero.
Solving the differential equation, we find that the equation represents logistic growth. The solution to the equation is P(t) = Q / (1 + (Q/Po)e^(-rt)), where Po is the initial population, Q is the carrying capacity, and r is the growth rate.
In this case, the initial population is given as 3,000. To find the carrying capacity (Q), we set dP/dt = 0 and solve for P. Substituting the values into the equation, we find Q = 5,000.
As t becomes very large, e^(-rt) approaches 0, and the equation simplifies to P(t) = Q. Therefore, the lim t>infinity P(t) is 5,000, which is the carrying capacity of the species.
20 POINTS!! EASY QUESTION! WILL MARK BRAINLIEST!! READ THE INFO! THEN FILL IN THE BLANKS!
The cost for a single class session for each dance class is below.
Clodagh’s Dance = $6.00
New Steps = $7.50
Stepping High = $6.50
The class hours are below.
Clodagh’s Dance = 3:00pm - 4:00pm
New Steps = 4:00pm - 5:30pm
Stepping High = 9:00am - 10:15am
How would these answers change if you were to write the unit rate in cost per hour?
Fill in the blanks!
Dance Classes | Total Hours for Each Payment | Cost Per Hour
| |
Clodagh’s Dance | $6.00 | $6.00
New Steps | $7.50 | _____
Stepping High | $6.50 | _____
To find the unit rate in cost per hour, you will write the amount of money over the total time for each class. Then divide the cost by the time to find the unit rate.
New Steps: $7.50/1.5 hours = $5 per hour
Stepping High: $6.50/1.25 hours = $5.20 per hour
Answer:
To find the unit rate in cost per hour, you will write the amount of money over the total time for each class. Then divide the cost by the time to find the unit rate.
New Steps: $7.50/1.5 hours = $5 per hour
Stepping High: $6.50/1.25 hours = $5.20 per hour
Please help ASAP!!!! 52 points and will give brainliest for RIGHT answer!
Find the slope of the line that contains the points named. C(3, 8), D(-2, 5) -3/5 3/5 5/3
Answer: [tex]\dfrac{3}{5}[/tex]
Step-by-step explanation:
The slope of a line passing through two points X(a,b) and Y(c,d) is given by :-
[tex]m=\dfrac{d-b}{c-a}[/tex]
Given points : C(3, 8) and D(-2, 5)
Then , the slope of a line passing through two points C(3, 8) and D(-2, 5) is given by :-
[tex]m=\dfrac{5-8}{-2-3}=\dfrac{-3}{-5}=\dfrac{3}{5}[/tex]
Hence, the slope of the line that contains the points C(3, 8) and D(-2, 5) is [tex]\dfrac{3}{5}[/tex]
.
People who reach retirement age will have accidents and health issues. True False
Answer:
Its FALSE on odyssey
Which term describes what a manufacturer spends for goods or services?
a)cost
b)price
c)markup
Pleas help. Willl fan and medal!!
The term describing what a manufacturer spends for goods or services is cost. Cost is the expenses incurred by the manufacturer as a result of his business or undertaking. There are two types of cost of a manufacturer. The cost of goods sold and the operating expenses. The cost of goods sold are those cost incurred directly as a result of manufacturing. The operating expenses are those other expenses not indirectly involved with the manufacture of goods or services.