What variable is represented on the y-axis?



Question 1 options:

Position


Velocity


Distance


Time

Question 2 (Mandatory) (1 point)
What variable is represented on the x-axis?



Question 2 options:

Distance


Time


Position


Velocity

Question 3 (Mandatory) (1 point)
What variable is the dependent variable?



Question 3 options:

Velocity


Position


Distance


Time

Question 4 (Mandatory) (1 point)
What variable is the independent variable?



Question 4 options:

Position


Time


Velocity


Distance

Question 5 (Mandatory) (1 point)
What is the starting position of the object in the graph?



Question 5 options:

The object starts at position 0 at time 0.


The object starts south of position 0 at time 0.


The object starts slightly north of position 0 at time 0.


The object starts far north of position 0 at time 0

Question 6 (Mandatory) (1 point)
What is the direction of motion of the object in the graph?



Question 6 options:

The object moves in a northward direction away from the starting position.


The object moves in a positive direction away from position 0.


The object moves in a southward direction toward position 0.


The object moves in a northeast direction away from the starting position.

Question 7 (Mandatory) (1 point)
What is the type of motion and the relative speed of the object in the graph?



Question 7 options:

At first, the object is not moving. Then, the object begins to gain speed.


First the object begins slowing down at a slow rate. Then, the object begins slowing down at a fast rate.


First the object is moving at a slow and constant speed. Then, the object begins moving at a fast and constant speed.


First, the object is speeding up at a slow rate. Then, the object beings speeding up at a fast rate.

Question 8 (Mandatory) (1 point)
What is the starting position of the object in the graph?



Question 8 options:

The object starts far north of position 0 at time 0.


The object starts south of position 0 at time 0.


The object starts at position 0 at time 0.


The object starts slightly north of position 0 at time 0.

Question 9 (Mandatory) (1 point)
What is the direction of motion of the object in the graph?



Question 9 options:

At first, the object is not moving, then the object begins moving in a southward direction toward position 0. Finally, the object is not moving, again.


At first, the object is moving toward the right, then the object begins moving in a northward direction away from position 0. Finally, the object begins moving toward the right, again.


At first, the object is not moving, then the object begins moving in a negative direction toward position 0. Finally, the object is not moving again.


At first, the object is moving in an eastward direction, then the object begins moving southward toward position 0. Finally, the object begins moving in an eastward direction, again.

Question 10 (Mandatory) (1 point)
What is the type of motion and relative speed of the object in the graph?



Question 10 options:

At first, the object is moving at a slow and constant speed. Then, the object begins moving at a fast and constant speed. Finally, the object moves at a slow and constant speed, again.


At first, the object is moving at a constant speed. Then, the object begins gaining speed. Finally, the object is moving at a constant speed, again.


At first, the object is not moving. Then, the object begins moving at a fast and constant. Finally, the object is not moving again.


At first, the object is moving at a constant speed. Then, the object begins slowing down. Finally, the object begins moving at a constant speed, again.

Question 11 (Mandatory) (4 points)
Compare and contrast a scalar quantity and a vector quantity. Match each description to the correct term.

Question 11 options:

Speed


Has magnitude and direction


Velocity


Has magnitude only.

1.
Scalar Quantity

2.
Vector Quantity

Question 12 (Mandatory) (6 points)
Compare and contract speed and velocity. Match each description to the correct term.

Question 12 options:

The rate at which an object changes its position with respect to time


Equation: Change in position / elapsed time


The slope of a Position vs. Time graph


Equation: Distance traveled / elapsed time


A measure of how fast an object travels


The slope of a Distance vs. Time graph

1.
Speed

2.
Velocity

Question 13 (Mandatory) (2 points)
An object travels with a speed of 30 meters in 10 seconds. If average speed is calculated using the equation, "distance traveled / elapsed time," what is the speed of the object?

Question 13 options:

3 speed


3 seconds


3 meters per second


3 meters

In Physics, a reference direction denotes a clear direction related to motion. Options A, B, and C are valid reference directions, but '2 E' (option D) is not a clear reference direction.

In the context of Physics, a reference direction is an established direction, such as north, south, east, west, up, down, left, or right, used to describe the direction of a vector. These are often used in assessments of motion to delineate the path of an object. In your question, 'A. +', 'B. S', and 'C. down' can be considered as reference directions where '+' denotes a positive direction, 'S' represents South, and 'down' indicates a downward direction. However, 'D. 2 E' does not fit the criteria for a reference direction as '2 E' does not represent an established direction. Instead, it seems like a combination of a numeric value '2' and a directional reference 'E' (possibly East), but as a whole, it is not itself a clear direction.

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The force of gravity causes a volleyball to accelerate downwards when it rises in the air.

Initially, as the ball rises, gravity slows down its vertical velocity until it comes to a stop at its maximum height and then starts descending back to the ground due to the force of gravity.

An beta particle is a fast-moving electron.

An alpha particle and a helium nucleus are the same thing . . . a package composed of two protons and two neutrons.

An positron is a particle with the same mass as an electron but a positive charge.

The angle of incidence in glass is [tex]34.7^{\circ}[/tex]

Explanation:

We can solve this problem by applying Snell's law of refraction, which states that:

[tex]n_1 sin \theta_1 = n_2 sin \theta_2[/tex]

where

[tex]n_1, n_2[/tex] are the index of refraction of the first and second medium, respectively

[tex]\theta_1, \theta_2[/tex] are the angle of incidence and refraction, respectively

In this problem we have:

[tex]n_1 = 1.52[/tex] is the index of refraction of the first medium (glass)

[tex]n_2 = 1.00[/tex] is the index of refraction of the second medium (air)

[tex]\theta_2 =60^{\circ}[/tex] is the angle of refraction in glass

Solving for [tex]\theta_i[/tex], we find the angle of incidence:

[tex]\theta_1 = sin^{-1} (\frac{n_2 sin \theta_2}{n_1})=\sin^{-1}(\frac{(1.00)(sin 60^{\circ})}{1.52})=34.7^{\circ}[/tex]

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Final answer:

Using Snell's Law and the given indices of refraction for crown glass and air, as well as the angle of refraction in air, the angle of incidence within the crown glass is calculated to be approximately 41.14°.

Explanation:

To find the angle of incidence in glass when a ray of light exits the glass into air with a known angle of refraction, we use Snell's Law, which states that n1
*sin(θ1) = n2
*sin(θ2), where n1 and n2 are the refractive indices of the glass and air respectively, and θ1 and θ2 are the angles of incidence and refraction respectively. Given that the refractive index of crown glass is 1.52 (n1 = 1.52) and air is 1.00 (n2 = 1.00), with an angle of refraction of 60° in air (θ2 = 60°), we can rearrange Snell's Law to solve for the angle of incidence (θ1).

First, we plug in our known values:
1.52
*sin(θ1) = 1.00
*sin(60°)

Calculating the sine of 60 degrees and dividing by the refractive index of crown glass gives us the sine of the angle of incidence:

sin(θ1) = (1.00/1.52)
* sin(60°)

sin(θ1) ≈ 0.657

Using the inverse sine function, we find:

θ1 ≈ sin^−1(0.657)

θ1 ≈ 41.14°

Therefore, the angle of incidence in the crown glass is approximately 41.14°.

Answer:

Impossible to determine

Explanation:

In other words, no machine can be more than 100% efficient. Machines cannot multiply energy or work input. ... If a machine were 100% efficient then it can't have any energy losses to friction, so no friction can be present. In that case the theoretical and actual mechanical advantages would be equal.

D

The exact location of electrons in electron shells of atoms cannot be exactly ascertained. This is why VSPER atomic models represent the position of electrons (s, p, d, & f) using the probability of where they would most be expected to be found.

Explanation:

This is because merely observing electrons changes their behavior. Remember that to observe something one has to shine light on it so it bounces back to the eye. Due to the negligible mass of electrons, mere photons of light will change their direction of movement, spin or other behaviors/properties.

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Answer:

6

8

6

on edge

Explanation:

Answer:

R=50 meters

Explanation:

We'll use the Pythagoras's theorem

[tex]R^2=a^2+b^2[/tex]

A right triangle with legs of a=40 m and b=30 m has an hypotenuse of

[tex]R^2=30^2+40^2=900+1600[/tex]

[tex]R=\sqrt{2500} =50[/tex]

[tex]R=50\ meters[/tex]

Answer:

b 50

Explanation:

just did it

If an object is moving to the right in translational equilibrium, it means the sum of all the forces acting on the object is zero indicating a state of balanced forces. Translational equilibrium indicates the body is moving in a straight line at a constant speed or at rest. Equilibrium does not mean the absence of forces, but the balance of forces.

When an object is moving to the right in translational equilibrium, it means it is in a state of steady motion, either at rest or moving at a constant velocity, with no acceleration. This equilibrium occurs when the sum of all the forces acting on the object is zero, indicating the forces are balanced. If we consider three forces acting on the object: F1, F2, and F3, for it to be in translational equilibrium, the vector sum of the three forces must be zero. This can be represented mathematically as: F1 + F2 + F3 = 0. If any of the forces change its magnitude or direction, it would disrupt the equilibrium status.

Translational equilibrium stands for a body moving in a straight line at a constant speed or being at rest, while rotational equilibrium refers to objects rotating at a constant rotation or being steady.

An important point to remember is that an equilibrium state does not necessarily mean the absence of forces but signifies that forces are equally balanced.

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The mass of the water is 41.9 g

Explanation:

When an amount of energy Q is supplied to a sample of substance of mass m, the temperature of the substance increases by [tex]\Delta T[/tex], according to the equation :

[tex]Q=mC_s \Delta T[/tex]

where :

m is the mass of the substance

[tex]C_s[/tex] is the specific heat capacity of the substance

[tex]\Delta T[/tex] is the change in temperature

In this problem, we have:

Q = 525 J is the amount of heat supplied to the water

[tex]\Delta T = 3^{\circ}C[/tex] is the change in temperature of the water

[tex]C_s = 4.18 J/gC[/tex] is the specific heat capacity of the water

Solving for m, we find the mass of the water:

[tex]m=\frac{Q}{C_s \Delta T}=\frac{525}{(4.18)(3.0)}=41.9 g[/tex]

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Final answer:

Using the specific heat capacity formula, we calculate the mass of water that can have its temperature increased by 3.0° C with the addition of 525 J of heat.

Explanation:

To solve the problem presented, we need to use the concept of specific heat capacity, which is the amount of heat required to raise the temperature of one kilogram of a substance by one degree Celsius. The specific heat capacity of water is commonly accepted as 4,184 J/kg/
°C. We can use the formula q = mcΔT, where q is the heat added (in Joules), m is the mass of the water (in kilograms), c is the specific heat capacity, and ΔT is the change in temperature (in degrees Celsius).

We are given q = 525 J and ΔT = 3.0°C. We need to find the mass m. Rearranging the formula to solve for m, we get m = q / (cΔT). Substituting the given values:

m = 525 J / (4,184 J/kg/
°C
* 3.0°C)

By calculating this, we find the mass of water that can have its temperature raised by 3.0°C with 525 J of heat.

Answer:

S = 108m

Explanation:

According to Second Law of Motion:

S = Vi*t + 0.5*a*t^2

Vi = 21m/s

a = 3m/s^2

t = 4s

Putting all values in Equation

S = 21*4 + 0.5*3*4^2

S = 84 + 24

S = 108m

Answer:

The distance the hiker walked is, d = 13 km

The displacement of the hiker is, S = 9.4 km

Explanation:

Given data,

The displacement of towards east, d₁ = 1 km

The displacement of towards north, d₂ = 2 km

The displacement of towards east, d₃ = 4 km

The displacement of towards north, d₄ = 6 km

The total distance the hiker walked

                           d = d₁ + d₂ + d₃ + d₄

                              = 1 + 2 + 4 + 6

                              = 13 km

The distance the hiker walked is, d = 13 km

The resultant displacement of the hiker, S

                                S = √( A² + B² + 2 A B cosФ)

Where,

                         A = d₁ + d₃ = 5 km

                         B = d₂ + d₄ = 8 km

                         Ф = angle between A and B = 90°

Substituting in the displacement equation

                          S = √( 5² + 8²)

                              = 9.4 km

Hence, the displacement of the hiker is, S = 9.4 km

Answer:

gravity

Explanation:

gravity

Answer:

This is because the earth is already going very fast. This means the earth is constantly trying to leave orbit and hurtle off into space like a ball attached to a string would if you spun it around. The only thing keeping that ball from going into your face it the speed.

Explanation:

The gravity is the string.

The earth doesn't really slow down because space offers little resistance.

Answer:

A. 22 [tex]ms^{-1}[/tex]

B. NO

Explanation:

A.

During a collision , the net external force on the system is zero .

hence , the total momentum of the system can be CONSERVED .

let the mass of frosty and snowflake be m ;

therefore from principle of conservation of momentum ,

[tex]m*v_{F_{i} } +  m*v_{S_{i} } = m*v_{F_{f} } +  m*v_{S_{f} }[/tex]

so ,

[tex]m*25 + m*10 =m*13 +m*x[/tex]

[tex]x = 25+10-13 = 22 ms^{-1}[/tex]

answer for A. 22 [tex]ms^{-1}[/tex]

B.

The collision is NOT ELASTIC.

this is because if it had been elastic , the coefficient of restitution should have been 1 but it isnot i.e

[tex]e =\frac{ v_{F_{f} } - v_{S_{f} } }{ v_{S_{i} } - v_{F_{i} } } \\=\frac{13-22}{10-25} \\=\frac{9}{15} = \frac{3}{5} = 0.6[/tex] ≠ 1

thus it's an inelastic collision.

Answer:

Voltage difference causes charge to flow from higher potential to that of a lower potential.

Explanation:

Voltage Difference:

It is work done per unit charge in moving a charge from one point to another point.

V = Voltage difference

W = Work done

Q = Charge

Then,

[tex]V = \frac{W}{Q}[/tex]

unit : Volt or Joule/Coulomb

Flow of charge :

A free positive charge move from a region of higher potential to that of lower potential whereas a free negative charge moves from lower potential region to a higher potential.

Thus, a voltage difference is required for the flow of charge.

Direction of conventional current is from positive terminal to negative terminal.

Direction of electron is from negative to positive.

Voltage difference causes charge to flow from higher potential to that of a lower potential.

This is also known as Voltage difference and it is the difference in electric potential between two points.

V= W/Q

where v is potential difference, w is work done and q is charges.

This allows for charges to flow from higher potential to that of a lower potential.

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The gravitational force between the two objects A) It increases.

Explanation:

The gravitational force between two objects is given by:

[tex]F=G\frac{m_1 m_2}{r^2}[/tex] (1)

where

G is the gravitational constant

[tex]m_1, m_2[/tex] are the masses of the two objects

r is the separation between the objects

In this problem, object A and object B are initially at a distance of

r = 100 m

And at that distance, the force between them is

F

Later, object A gains some mass. We notice from eq.(1) that the gravitational force is directly proportional to the mass: therefore, if the mass of either of the two objects increases, then the gravitational force between them also increases. Therefore, the new force will be larger than the original force:

F' > F

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1) The ball's speed is 3 m/s

2) The final speed of the raft is 0.6 m/s

3) The collision is inelastic

Explanation:

1)

The momentum of an object is given by

[tex]p=mv[/tex]

where

p is the momentum

m is the mass of the object

v is its velocity

For the ball in this problem we have:

p = 12 kg m/s

m = 4 kg

Solving for v, we find its velocity (and so its speed):

[tex]v=\frac{p}{m}=\frac{12}{4}=3 m/s[/tex]

2)

We can solve this part by applying the law of conservation of momentum: in fact, the total momentum of an isolated system (=no external forces) must be conserved. Therefore we can write:

[tex]p_i = p_f[/tex] (1)

where

[tex]p_i = 0[/tex] is the total initial momentum (the swimmer and the raft are at rest at the beginning)

[tex]p_f = mv + MV[/tex] is the total final momentum, where

m = 75 kg is the mass of the swimmer

M = 500 kg is the mass of the raft

v = 4 m/s is the final velocity of the swimmer

V is the final velocity of the raft

And substituting into (1) we find:

[tex]0=mv+MV\\V=-\frac{mv}{M}=-\frac{(75)(4)}{500}=-0.6 m/s[/tex]

Where the negative sign indicates that the raft moves in the opposite direction to the swimmer: so, the speed of the raft is 0.6 m/s.

3)

In a collision between two objects, if the system is isolated the total momentum of the system is always conserved during the collision. However, this is not true for the total kinetic energy: in fact, due to the presence of internal frictions, part of the kinetic energy can be converted into thermal energy or other forms of energy.

Therefore, there are two types of collision:

- Elastic collision: in an elastic collision, also the total kinetic energy of the objects is conserved

- Inelastic collision: in an inelastic collision, the total kinetic energy is not conserved. The most extreme case is the perfectly inelastic collision, in which the two objects stick together after the collision, and in this case there is the maximum loss of kinetic energy.

Since in this problem the two objects stick together, the collision is inelastic.

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Particle A orbits the nucleus, and Particle B is located in the nucleus.

Explanation:

The atoms consists of three types of particle:

- Proton: it is located in the nucleus of the atom, its mass is approximately [tex]1.67\cdot 10^{-27}kg[/tex], and its charge is [tex]+e=1.6\cdot 10^{-19}C[/tex] (positive charge)

- Neutron: it is also located in the nucleus of the atom, its mass is similar to that of the proton, and it has no electric charge

- Electron: it orbits around the nucleus, it is much lighter than the proton and the neutron (mass: [tex]9.11\cdot 10^{-31}kg[/tex]), and it is negatively charged ([tex]q=-e=-1.6\cdot 10^{-19}C[/tex])

Looking at the definitions above, and since we know that particle A has very little mass in comparison to particle B (so, particle A must be an electron), we can only conclude the following:

Particle A orbits the nucleus, and Particle B is located in the nucleus.

In fact, we cannot determine whether particle B is a proton or a neutron, since we don't know anything about its charge.

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Answer: the correct answer would be Particle A orbits the nucleus, and Particle B is located in the nucleus. I think Particle A represents the electrons while B represents protons and neutrons.

Explanation:

Answer:

μ = 0.535

Explanation:

On a level floor, normal force = weight.

N = W

Friction force = normal force × coefficient of friction.

F = Nμ

Substitute:

F = Wμ

83 = 155μ

μ = 0.535

Round as needed.

Answer:

Mass 1

Explanation:

Take any set of points of the masses:

Let's say the masses in the acceleration 4 m/s (because it represents the points more clearer)

Force = mass × acceleration.

But we need to know the mass if force and acceleration is given.

So,

Mass = Force ÷ acceleration

Now back to the set of points

mass = force ÷ acceleration

For mass 1,

mass = 8 ÷ 4

mass = 2

For mass 2,

mass = 4 ÷ 4

mass = 1

For mass 3,

mass = 2 ÷ 4

mass = 1/2

As you can see from the results, mass 1 definitely has the largest.

Now that you have read through here and think, "we might as well depend on the graph". You are correct but sometimes you should not rely on the graph.

Answer:

Mass 1

Explanation:

I have done the test.

Answer:  600 kg-m/s

Explanation:

Momentum = mass x velocity

momentum of spaceship 1 = 200 x 2

= 400 kg-m/s

momentum of spaceship 2 = 200 x 2

= 200 kg-m/s

Their combine momentum = 400 + 200 = 600 kg-m/s

The Answer is 600 kg-m/s

Answer:

At the same time.

Explanation:

In the first case ,

intial velocity = 0

displacement = -h

acceleration = -g

Using second equation of motion,

s = ut + .5a[tex]t^{2} \\[/tex]

- h = - 0.5g[tex]t^{2} \\[/tex]

t = [tex]\sqrt{\frac{2h}{g} }[/tex]

In the second case, consider only motion along y axis,

intial velocity = 0 ( all the velocity is along x axis)

displacement = -h ( height is same in both cases)

acceleration = -g

Using second equation of motion,

s = ut + .5a[tex]t^{2} \\[/tex]

- h = - 0.5g[tex]t^{2} \\[/tex]

t = [tex]\sqrt{\frac{2h}{g} }[/tex]

In both cases time is same.

Hence, they will reach the ground simultaneously.

Answer:

Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward towards the center of rotation.

Explanation:

Definition of centripetal force:

Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward towards the center of rotation.

Example of centripetal force

A string on the end of which a stone is whirled about exerts a centripetal force on the stone.

The diagram is shown below

Where

The centripetal forces acting towards the centre C that is [tex]\vec {AC}[/tex]

and the direction is from A to C.

And the stone is moving in a circular motion with center as C.

Answer:

Explanation:

       A object dropped from a plane from a certain height will follow a parabolic trajectory because it has a horizontal velocity equal to plane's velocity.

       So, if supplies are to be dropped from a plane from a height of 160 m, let us calculate the time it takes to reach the ground.

       [tex]H=\frac{1}{2}gt^{2}\\160=\frac{1}{2}\times10\times t^{2}\\t=\sqrt{32}=4\sqrt{2}\text{ }sec[/tex]

       So, in this time, the supply moves a horizontal distance of [tex](4\sqrt{2}\text{ }sec)\times(45\text{ }\frac{m}{sec})=180\sqrt{2}\text{ }m=254.56\text{ }m[/tex].

∴ The supply must be dropped when the plane is 255 m away.

Final answer:

Division and subtraction are not associative operations, meaning that the grouping of numbers can affect the outcome of these operations.

Explanation:

An operation is considered associative if a change in the grouping of the elements does not change the result of the operation. For example, in addition, (a + b) + c = a + (b + c). This means that addition is associative. Similarly, multiplication is associative as well: (a × b) × c = a × (b × c).

Division and subtraction are operations that are not associative. The expression (a - b) - c does not necessarily equal a - (b - c), and similarly, (a / b) / c is not the same as a / (b / c). These operations cannot be regrouped without potentially changing the outcome.

Therefore, the answer to the question is C. division and subtraction are operations that are not associative.

The frequency of the wave is 4 Hz

Explanation:

The relationship between wave, frequency and speed of a wave is given by the equation:

[tex]v=f \lambda[/tex]

where

v is the speed of the wave

f is the frequency

[tex]\lambda[/tex] is the wavelength

For the wave in this problem, we have:

[tex]v=60 cm/s[/tex] is the speed

[tex]\lambda=15 cm[/tex] is the wavelength

Solving the equation for f, we find its frequency:

[tex]f=\frac{v}{\lambda}=\frac{60 cm/s}{15 s}=4 s^{-1} = 4 Hz[/tex]

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Answer:Kinetic Energy. Kinetic energy is motion — of waves, molecules, objects, substances, and objects. Chemical Energy is energy stored in the bonds of atoms and molecules.

please give me brainliest...

Answer:

Chemical Energy

Explanation:

Energy is the ability to perform work, it is usually stored in many forms. A body at rest has potential energy, a car moving has kinetic energy while  boiling water posses thermal energy. Energy is usually transformed from one form to another, it cant be destroyed.

Chemical energy is the type of energy that is stored in the bonds of the atom of chemical substances. This is the potential energy that is released when the bonds of molecules are broken. For example, the human digestive system breaks down a molecule of food and release mechanical energy for our day to day activities.

The energy stored in between bonds of atoms is chemical energy that are released  and converted to another form of energy when it is broken down.

Answer:

the mass of the object is 10 kg

Explanation:

In the image attached, we can see the free body diagram and using the newton's second law of movement, we will have one equation with one unknown value (the mass of the object).

where:

m [kg]

a [m/s^2]

F [N] or [kg*m/s^2]

Answer:

10kg

Explanation:

The information we have is:

Force: [tex]F=30N[/tex]

acceleration: [tex]a=3m/s^2[/tex]

What we need to know is the mass of the object. For this we can use Newton's second law:

[tex]F=ma[/tex]

Where F is the Force applied, m is the mass of the object, and a is its acceleration.

from this equation we clear for the mass [tex]m[/tex]:

[tex]m=\frac{F}{a}[/tex]

and we substitute the known values:

[tex]m=\frac{30N}{3m/s^2}=10kg[/tex]

The mass of the object is 10kg

The power is 833.3 W

Explanation:

First of all, we need to calculate the work done in lifting the barbell, which is equal to the change in gravitational potential energy of the barbell:

[tex]W=(mg)h[/tex]

where

mg = 1250 N is the weight of the barbell

h = 2 m is the change in height

Substituting,

[tex]W=(1250)(2)=2500 J[/tex]

Now we can calculate the power, which is equal to the work done per unit time:

[tex]P=\frac{W}{t}[/tex]

where

W = 2500 J is the work done

t = 3 s is the time taken

Substituting,

[tex]P=\frac{2500}{3}=833.3 W[/tex]

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Answer: A resultant vector

Explanation: Addition of two vectors can not be a scalar because vectors have a magnitude and a direction. so that they are explained by means of these two chacteristics. If addition is different from zero it will give a vector.

Answer:

2 m/s

Explanation: