Which chemical equation represents a precipitation reaction?

Answer:

1) Iron iodide and silver carbonate.

2) 6AgI + Fe(CO₃)₃ → 2FeI₃ + 3Ag₂CO₃

3)  double displacement reaction

Explanation:

Chemical equation:

AgI + Fe(CO₃)₃ → FeI₃ + Ag₂CO₃

Balanced chemical equation:

6AgI + Fe(CO₃)₃ → 2FeI₃ + 3Ag₂CO₃

The given reaction is double displacement reaction. The cation and anion of both reactants are interchanged and form iron iodide and silver carbonate.

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

Answer: four hydrogen atoms and one carbon atom to form methane (CH4)

Explanation: Study island

The elements most likely to form a covalent compound are four hydrogen atoms and one carbon atom to form methane (CH4). For an ionic compound, lithium and fluorine combine to form lithium fluoride (LiF).

Atoms of different elements can combine chemically to form compounds, primarily through ionic or covalent bonding. The elements most likely to form a compound bound tightly together with covalent bonds are none other than non-metals which share electrons. The answer to the question 'Which of the following elements would be most likely to form a compound bound tightly together with covalent bonding?' is C, which involves four hydrogen atoms and one carbon atom forming methane (CH4). Methane is an example of a molecule formed with covalent bonds where the central carbon atom shares electrons with four hydrogen atoms.

Regarding which two elements could form an ionic compound, the answer would be C: 3 lithium and 9 fluorine. Lithium, being a metal, tends to lose electrons, while fluorine, a non-metal, has a tendency to gain electrons. This transfer of electrons from lithium to fluorine forms an ionic compound known as lithium fluoride (LiF).

Answer:

[tex]\large \boxed{\text{E) 721 K; B) 86.7 g}}[/tex]

Explanation:

Question 7.

We can use the Combined Gas Laws to solve this question.

a) Data

p₁ = 1.88 atm; p₂ = 2.50 atm

V₁ = 285 mL;  V₂ = 435 mL

T₁ = 355 K;     T₂ = ?

b) Calculation

[tex]\begin{array}{rcl}\dfrac{p_{1}V_{1}}{T_{1}}& =&\dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{1.88\times285}{355} &= &\dfrac{2.50\times 435}{T_{2}}\\\\1.509& = &\dfrac{1088}{T_{2}}\\\\1.509T_{2} & = & 1088\\T_{2} & = & \dfrac{1088}{1.509}\\\\ & = & \textbf{721K}\\\end{array}\\\text{The gas must be heated to $\large \boxed{\textbf{721 K}}$}[/tex]

Question 8. I

We can use the Ideal Gas Law to solve this question.

pV = nRT

n = m/M

pV = (m/M)RT = mRT/M

a) Data:

p = 4.58 atm

V = 13.0 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 385 K

M = 46.01 g/mol

(b) Calculation

[tex]\begin{array}{rcl}pV & = & \dfrac{mRT}{M}\\\\4.58 \times 13.0 & = & \dfrac{m\times 0.08206\times 385}{46.01}\\\\59.54 & = & 0.6867m\\m & = & \dfrac{59.54}{0.6867 }\\\\ & = & \textbf{86.7 g}\\\end{array}\\\text{The mass of NO$_{2}$ is $\large \boxed{\textbf{86.7 g}}$}[/tex]

Final answer:

The calculated density of the water sample should be reported with two significant figures, which is the same as the measurement with the least number of significant figures used in the calculation (the volume in this case).

Explanation:

When determining the number of significant figures in a calculated density, you must look at the measurements used in the calculation. In this case, the mass of the water sample is given as 1.060 g which has four significant figures, and the volume is 1.0 mL which has two significant figures. According to the rules for significant figures, the number of significant figures in the result of a division should be the same as the measurement with the least number of significant figures. Therefore, the density calculated should be reported with two significant figures.

Answer:

(a) The rate at which ammonia being formed = 0.0493 M/s

(b) The rate at which molecular nitrogen reacting = 0.0247 M/s

Explanation:

[tex]N_{2}+3H_{2}\longrightarrow2NH_{3}[/tex]

The rate at which molecular hydrogen is reacting = [tex]\frac{d}{dt}[H_{2}]=0.074\:M/s[/tex]

The rate of the above reaction can be expressed as:

[tex]rate=-\frac{d}{dt}[N_{2}]=-\frac{1}{3} \frac{d}{dt}[H_{2}]=\frac{1}{2}\frac{d}{dt}[NH_{3}][/tex]

(a) [tex]\frac{d}{dt}[NH_{3}]=\frac{2}{3}(0.074)=0.0493[/tex]

The rate at which ammonia being formed = 0.0493 M/s

(b) [tex]-\frac{d}{dt}[N_{2}]=\frac{1}{3}(0.074)=0.0247[/tex]

The rate at which molecular nitrogen reacting = 0.0247 M/s

A fine powder dissolves quickly, this solution can more quickly be absorbed and begin working. Therefore, the correct option is option D.

The term "dissolution" refers to the action of dissolving or creating a solution. When a solute dissolves, it splits into atoms or molecules, with molecules of the solvent surrounding each ion or molecule. Solvation is the term used to describe interactions between solvent molecules and solute particle.

Solutes are the other elements of the solution that are present at comparatively lower concentrations. Several headache medications are consumed after being dissolved in water from fine powders. These drugs assert that they function more quickly than other drugs. This is true as  a fine powder dissolves quickly, this solution can more quickly be absorbed and begin working.

Therefore, the correct option is option D.

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#1. 50 g

#2. 25 g

#3. 4 half lives

We are given;

We need to answer the questions:

#a. Mass remaining after 10 years

Using the formula;

Remaining mass = Original mass × 0.5^n , where n is the number of lives.

In this case, since the half life is 10 years then n is 1

Therefore;

Remaining mass = 100 g × 0.5^1

                            = 50 g

Therefore, 50 g of the isotope will remain after 10 years

#b. Mass of the isotope that will remain after 20 years

Remember the formula;

Remaining mass = Original mass × 0.5^n

n = Time ÷ half life

n = 20 years ÷ 10 years

   = 2

Therefore;

Remaining mass = 100 g × 0.5^2

                           = 25 g

Thus, 25 g of the isotope will be left after 20 years

#3. Number of half lives in 40 years

1 half life = 10 years

But; n = time ÷ half life

          = 40 years ÷ 10 years

          = 4

Thus, the number of half lives in 40 years is 4.

We have that for the Question "What volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol)?" it can be said that The volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol) is

V=0.862L

From the question we are told

What volume of 0.20MNaCl (aq) contains 10.0g of NaCl (molar mass 58g/mol)?

Generally the equation for the  morality  is mathematically given as

[tex]M=\frac{moles of NaCl}{Volume of sol}\\\\0.20=\frac{10/58}{V}\\\\[/tex]

V=0.862L

Therefore

The volume of 0.20MNaCl(aq) contains 10.0g of NaCl (molar mass 58g/mol) is

V=0.862L

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To find the volume of 0.20 M NaCl solution containing 10.0 g of NaCl, calculate the number of moles of NaCl and divide by the molarity. It results in a volume of 0.862 liters.

To calculate the volume of 0.20 M NaCl solution that contains 10.0 g NaCl, we will begin by converting the mass of NaCl into moles. Next, we will use the molarity of the solution to find out the volume that contains these moles.

Using the molar mass of NaCl (58 g/mol), we calculate the number of moles of NaCl:

Number of moles of NaCl = mass (g) / Molar mass (g/mol)
Number of moles of NaCl = 10.0 g / 58 g/mol
Number of moles of NaCl = 0.1724 mol

Molarity (M) is defined as the number of moles of solute per liter of solution. We rearrange the molarity equation to solve for volume:

Volume (L) = Number of moles of solute / Molarity (M)
Volume (L) = 0.1724 mol / 0.20 M
Volume = 0.862 L

Therefore, 0.862 liters (or 862 milliliters) of 0.20 M NaCl solution contains 10.0 grams of NaCl.

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Answer:

1.heat evaporates water from oceans

2.rain falls, being trapped behind dams

3.potential energy of water behind dam converted into kinetic energy by turning turbines

4.turbines generate electrical energy

The sequence number with the energy transformations from the water behind a hydroelectric dam to the lighting of a light bulb is as follows:

1.Energy transferred to home to power light bulb

2.Rain falls, being trapped behind dams

3.Potential energy of water behind dam converted into kinetic energy by turning turbines

4.Turbines generate electrical energy

The term energy transformation is define as the conversion of one form of energy into another form, or the movement of energy from one place to another place.

The energy is a quantity that provides the tendency to perform work or moving, or provides heat.

Thus, Energy transferred to home to power light bulb, rain falls, being trapped behind dams,potential energy of water behind dam converted into kinetic energy by turning turbines, turbines generate electrical energy.

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Answer:

C. A metal ion takes the place of the hydrogen of an acid

Explanation:

When an acid react with base neutralization reaction take place.

During neutralization reaction water and salt are formed.

For example;

Base sodium hydroxide react with hydrochloric acid and form sodium chloride and water.

The sodium hydroxide consist of sodium metal ion in the form of Na⁺ and OH⁻. when it react with acid hydrogen atom of acid replace by sodium metal and react with anion of acid and form salt called sodium chloride.

Chemical equation:

NaOH + HCl  →  NaCl + H₂O

A salt is formed during a neutralization reaction when a hydrogen ion from an acid reacts with a hydroxide ion from a base to produce water and a salt.

During a neutralization reaction, a salt is formed when an acid and a base react chemically with each other. The correct answer to how a salt is formed is A: A hydrogen ion reacts with a hydroxide ion. This reaction typically produces water as well, following the general reaction: acid + base → water + salt. For example, when sodium hydroxide (NaOH) reacts with hydrochloric acid (HCl), they produce sodium chloride (NaCl) and water (H2O).

Answer:

NO₃⁻(aq) and Na⁺ (aq) are spectator ions.

Explanation:

Chemical equation:

AgNO₃(aq) + NaCl(aq)  → AgCl(s) + NaNO₃(aq)

Balanced Chemical equation:

AgNO₃(aq) + NaCl(aq)  → AgCl(s) + NaNO₃(aq)

Ionic equation:

Ag⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + Cl⁻(aq)  → AgCl(s) + Na⁺(aq) + NO₃⁻(aq)

Net ionic equation:

Ag⁺(aq) + Cl⁻(aq)  → AgCl(s)

The NO₃⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The AgCl can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

Answer:

0.077 M

Explanation:

Molarity is the representation of the solution.

Molarity:

It is amount of solute in moles per liter of solution and represented by M

Formula used for Molarity

                    M = moles of solute / Liter of solution . . . . . . . . . . (1)

Data Given :

The concentration of half normal (NaCl) saline = 0.45g / 100 g

So,

Volume of Solution =  100 g = 100 mL

Volume of Solution in L =  100 mL / 1000

Volume of Solution =  0.1 L

molar mass of NaCl = 58.44 g/mol

Now to find number of moles of Nacl

               no. of moles of NaCl = mass of NaCl / molar mass

               no. of moles of NaCl =  0.45g / 58.44 g/mol

               no. of moles of NaCl =  0.0077 g

Put values in the eq (1)

                  M = moles of solute / Liter of solution . . . . . . . . . . (1)

                  M = 0.0077 g / 0.1 L

                  M = 0.077 M

So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M

Answer:

8.2x10^22 molecules ( 1 mol / 6.022 x 10^23 molecules ) ( 789.44 g / 1 mol ) = 107.50 grams N2I6

Explanation:

Answer:

0.5 moles of HgO will produced 0.25 moles of oxygen

Explanation:

Given data:

Number of moles of HgO = 0.5 mol

Number of moles of oxygen = ?

Solution:

Chemical equation;

2HgO   →  2Hg + O₂

WE will compare the moles of HgO with oxygen from balance chemical equation.

                                HgO        :         O₂

                                   2           :          1

                                    0.5       :          1/2×0.5 =0.25 mol

So 0.5 moles of HgO will produced 0.25 moles of oxygen.

Cities located the same distance from the equator, one north and one south, will have similar climates in terms of temperature and average rainfall, due to the similar amount of sunlight they receive. However, their seasons will be inverted, as when it is summer in the Northern Hemisphere, it will be winter in the Southern Hemisphere, and vice versa.

Your question inquires about how the climates of two cities would compare if they were equidistant from the equator, one being to the north and the other to the south. The climates of these two cities would be similar because they're situated at the same distance from the equator. The equator receives an equal amount of sunshine throughout the year, contributing to relatively stable, warm temperatures. However, their seasons might differ due to the tilting of the earth's axis causing variations in the intensity of solar radiation at different times of the year in both hemispheres.

A region's long-term, predictable atmospheric conditions are referred to as its "climate." This includes regular seasonal variations in rainfall and temperature. However, the timing and nature of these seasons may differ between the northern and southern hemispheres. Where the Northern Hemisphere experiences summer, the Southern Hemisphere experiences winter, and vice versa.

Therefore, although the two cities might experience similar average rainfall and temperatures due to their similar distances from the equator, the timings of their seasons would be inverted.

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Answer:

T₂ = 16.7  °C

Explanation:

Given data:

Initial volume = 150.0 mL

Temperature = 25.0 °C

Final volume = 100 mL

Final temperature = ?

Solution:

V₁ /T₁ = V₂/T₂

T₂ = V₂ . T₁/V₁

T₂ = 100 mL .25 °C / 150.0 mL

T₂ = 2500 mL.  °C / 150.0 mL

T₂ = 16.7  °C

Final Answer:

Upon cooling from a volume of 150.0 mL to 100.0 mL at constant pressure, the temperature of the carbon monoxide gas is estimated to be approximately -74.4 °C, as determined using Charles's Law.

Explanation:

To ascertain the new temperature of carbon monoxide as it undergoes cooling from 150.0 mL to 100.0 mL at a constant pressure, Charles's Law is applied. Charles's Law asserts that the volume of a gas is directly proportional to its temperature when pressure remains constant, and this relationship can be expressed mathematically as V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

Given an initial temperature (T1) of 25.0 °C, it needs conversion into kelvins by adding 273.15 to the Celsius temperature, resulting in T1 = 25 + 273.15 = 298.15 K. The initial volume (V1) is 150.0 mL, and the final volume (V2) is 100.0 mL. Utilizing Charles's Law, we can now determine the final temperature (T2).

Applying Charles's Law, we derive:

V1/T1 = V2/T2

(150.0 mL) / (298.15 K) = (100.0 mL) / (T2)

T2 = (100.0 mL) * (298.15 K) / (150.0 mL)

T2 = 198.7667 K

To express the temperature in Celsius, we subtract 273.15 from the temperature in kelvins:

T2 = 198.7667 K - 273.15

T2 ≈ -74.3833 °C

Thus, the new temperature of the carbon monoxide after cooling is approximately -74.4 °C.

Answer:

d , before the molten rock becomes lava, it is first magma, and most people know that lava is ejected from volcanoes

Magma reaches the Earth's surface through volcanoes, then turns into lava.  The correct option is option D among all the given options.

A volcano is a crack inside this crust of a planet, including such Earth, that permits hot lava, volcanism, as well as gases to emerge from such a magma chamber under the surface.

Volcanoes are most commonly located where tectonic plates either diverging or converging on Earth, and the majority are found underwater. For example, the Mid-Atlantic Ridge is a mid-ocean ridge. Magma reaches the Earth's surface through volcanoes, then turns into lava.

Therefore, magma reaches the Earth's surface through volcanoes, then turns into lava. The correct option is option D  among all the given options.

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Answer:

1. Percent composition of  Al = 13.423 %

2.

3. The empirical formula is C₅O₁₆

4. Molecular Formula= P₄O₆

Explanation:

Part first :

Data Given

Formula of the Molecule = Al₂ (CrO₄)₃

% of Al₂ = ?

> First of all find the atomic masses of each component in a molecule

For Al₂ (CrO₄)₃ atomic masses are given below

Al = 27 g/mol

Cr = 52 g/mol

O = 16 g/mol

> Then find the total masses of each component

2 atoms of Al = 27 g/mol x 2

= 54 g/mol

3 atoms of Cr = 52 g/mol x 3

= 156 g/mol

12 atoms of O = 16 g/mol x 12

= 192 g/mol

> find total Molar Mass of Molecule:

Molar Mass of Al₂ (CrO₄)₃ = [27x2 + 52x3 + 16x12]

Molar Mass of Al₂ (CrO₄)₃ = 402

Now to find the mass percent of Al

Formula used to find the Mass percent of a component

Percent composition of  Al = mass of Al in Molecula / molar mass of Al₂(CrO₄)₃ x 100%

Put the values

Percent composition of  Al =  54 (g/mol) / 402 (g/mol) x 100%

Percent composition of  Al = 13.423 %

_______________________________________

Part 2

Data Given

Formula of the Molecule = Zn(ClO₃)₂

% Zn = ?

% Cl = ?

% O = ?

> First of all find the atomic masses of each component in a molecule

For Zn(ClO₃)₂ atomic masses are given below

Zn = 65 g/mol

Cl = 35.5 g/mol

O = 16 g/mol

> Then find the total masses of each component

1 atoms of Zn= 65 g/mol x 1

= 65 g/mol

2 atoms of Cl = 35.5 g/mol x  

= 71 g/mol

6 atoms of O = 16 g/mol x 6

= 96 g/mol

> find total Molar Mass of Molecule:

Molar Mass of Zn(ClO₃)₂ = [65x1 + 35.5x2 + 16x6]

Molar Mass of Zn(ClO₃)₂ = 232g/mol

Now to find the mass percent of of each component one by one

1.  Formula used to find the mass percent of Zn

Percent composition of  Zn= mass of Zn in Molecular / molar mass of Zn(ClO₃)₂ x 100%

Put the values

Percent composition of Zn = 65(g/mol) / 232 (g/mol) x 100%

Percent composition of Zn = 28.02 %

-------------------

2.  Formula used to find the mass percent of Cl

Percent composition of  Cl = mass of Cl in Molecular / molar mass of Zn(ClO₃)₂ x 100%

Put the values

Percent composition of Cl = 71 (g/mol) / 232 (g/mol) x 100%

Percent composition of Cl = 30.6 %

---------------------

3.  Formula used to find the mass percent of O

Percent composition of  O = mass of O in Molecular / molar mass of Zn(ClO₃)₂ x 100%

Put the values

Percent composition of O = 96 (g/mol) / 232 (g/mol) x 100%

Percent composition of O = 41.3 %

________________________________________

Part 3:

Data Given

Percentage of C = 27.3 %

Percentage of O = 72.7 %

Emperical Formula of the compound = ?

Solution:

So the compound has 27.3 % C and 72% O

First, find the mass of each of the elements in 100 g of the Compound.

C = 27.3 g

O = 72 g

Now find how many moles are there for each element in 100 g of compound

For this molar mass are required

That is

C = 12 g/mol

O = 16 g/mol

Formula Used

mole of C = mass of C / Molar mass of C

 mole of C = 27.3 / 12 g/mol

  mole of C = 2.275

Formula Used

mole of O = mass of O / Molar mass of O

 mole of O = 72g / 16 g/mol

  mole of O = 7.2

Divide each one by the smallest number of moles

C = 2.275 / 2.275

C = 1

O = 7.2 / 2.275

O = 3.2

Multiply the mole fraction to a number to get the whole number.

C = 1 x 5 = 5

O = 3.2 x 5 =  16

So, the empirical formula is C₅O₁₆

______________________________________

Part 4

Data Given

Percentage of P= 56.38 %

Percentage of O = 43.62%

Molar Mass = 219.9g

Molecular Formula of the compound = ?

Solution:

First, find the mass of each of the elements in 100 g of the Compound.

Mass of P= 56.38g

Mass of O = 43.62g

Now find how many moles are there for each element in 100 g of compound

find the moles in total compounds

Formula Used

mole of P = mass of  / Molar mass of P

 mole of P = 56.38 g / 31 g/mol

  mole of P = 1.818

Formula Used

mole of O = mass of O / Molar mass of O

 mole of O = 43. 62 / 16 g/mol

  mole of O = 2.7262

Now

first find the Emperical formula

Divide each one by the smallest number of moles

P = 1.818 /1.818

P= 1

for oxygen

O = 2.7262 / 1.818

O = 1.5

Multiply the mole fraction to a number to get the whole number.

P = 1 x 2 = 2

O = 1.5 x 2 =  3

So, the empirical formula is P₂O₃

Now  

Find molar mass of the empirical formula P₂O₃

2 (31) + 3 (16) = 62 + 48 = 110

Now find that how many empirical units are in a molecular unit.

(219.9 g/mol) / ( 110 g/mol) =  empirical units per molecular unit

empirical units per molecular unit = 1.999 =2

A here we get two empirical units in a molecular unit,

So the molecular formula is:

2 (P₂O₃) = P₄O₆

Answer:

Explanation:

Physical property:

Physical properties involve that property of matter which can be observed without changing the identity or undergoing chemical change or any other reaction. For example, taste, color, odor, density etc.

Chemical property:

Chemical properties observed during the chemical reaction. These properties changed the identity of substance.  For example, reactivity, stability, oxidation state, flammability etc.

A) Hydrogen is a colorless, tasteless, and odorless gas.

This statement shows the physical property of hydrogen.

B) Hydrogen is very combustible in the presence of oxygen.

This statement shows the chemical property of hydrogen

C) Hydrogen is very reactive with most elements.

This statement shows the chemical property of hydrogen

D) Hydrogen is the least dense of all elements.

This statement shows the physical property of hydrogen.

Answer:

for people doing ed

Explanation:

1. physical

2. chemical

3. chemical

4. physical

Answer:

The oxidation state of sodium is +1 and chlorine is -1.

Explanation:

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

2Na + Cl₂ → 2NaCl

The oxidation state of chlorine and sodium on left side is 0. After the reaction between them oxidation state is changed. Sodium is oxidized and chlorine is reduced. The oxidation sate of sodium is +1 while that of chlorine is -1. Sodium is reducing agent while chlorine is oxidizing agent.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

5175 Newtons

We are given;

We are required to calculate the work input;

Input force =Output force ÷ Mechanical advantage

Input force = 345 N × 15

                  = 5175 Newtons

Thus, the work input of a pulley system is 5175 N

Answer:

C. Blindness

Explanation:

Just took the test, hope I can help!

Shaken Baby Syndrome causes the death of many young children. Shaken infant syndrome survivors may need lifetime medical treatment for issues like Partial or complete blindness.

Developmental delays, academic difficulties, or behavioral concerns. intellectual handicap epilepsy diseases. Movement and muscle coordination are both impacted by cerebral palsy, a condition.

The brain and vision are severely injured by the shaken baby syndrome. Although retinal hemorrhages are very common, brain damage is more frequently the cause of vision loss. On presentation, the patient's pupillary response and visual response displayed a strong connection with survival.

This can happen when wounded nerve cells release chemicals that worsen your child's brain's lack of oxygen. Retinal bleeding: backward bleeding in your child's retinas

Thus, option C is correct.

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Structure of  2-methylpropane is CH₃─CH(CH₃)─CH₃.

to draw the structure of 2-methylpropane.

To draw the structure of 2-methylpropane:

1. Start with a propane backbone, which consists of a chain of three carbon atoms.

2. Identify the position of the methyl (CH₃) group at the second carbon atom in the chain.

3. Attach the methyl group to the second carbon atom to represent 2-methylpropane.

By following these steps, you can accurately draw the structure of 2-methylpropane.

Answer:

C)

Explanation:

Because The air up 3 Kilometers is too cold for raindrops and sleet. plus ozone is in the stratosphere

Answer:

Use the formula q = m·ΔHv in which q = heat energy, m = mass, and ΔHv = heat of vaporization.

Explanation:

:)

Final answer:

The formula used to find the heat energy for vaporization is heat = m × AHvap, and for fusion is heat = n × ΔΗfus. The heat energy for a liquid can be calculated using the equation q = mcAT.

Explanation:

The formula used to find the heat energy for vaporization is heat = m × AHvap, where m is the mass in grams and AHvap is expressed in energy/gram. The formula for the heat energy for fusion is heat = n × ΔΗfus, where n is the number of moles of material and ΔΗfus is the heat of fusion per mole. The heat energy for a liquid can be calculated using the equation q = mcAT, where q is the amount of heat transferred, m is the mass of the liquid, c is the specific heat capacity of the liquid, and AT is the change in temperature.

Answer:

2.1 M KOH is required.

Explanation:

It is an example of acid-base neutralization reaction.

KOH  +  HBr  ---->  KBr  +  [tex]H_{2}O[/tex]

Base     Acid           Salt        

When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .

Molarity= [tex]\frac{\textrm{No. of moles}}{\textrm{Volume of the particular solution}}[/tex]

No.of moles= Molarity × Volume of the Particular Solution

Therefore,

[tex]M_{1} V_{1} = M_{2} V_{2}[/tex]------------------------------(1)

where

[tex]M_{1}[/tex]= Molarity of Acid

[tex]V_{1}[/tex]= Volume of Acid

[tex]M_{2}[/tex]= Molarity of Base

[tex]V_{2}[/tex]= Volume of Base

[tex]M_{1}[/tex]=3.5 M

[tex]V_{1}[/tex]=15 mL

[tex]V_{2}[/tex]=25 mL

[tex]M_{2}[/tex]=??(in M)

Plugging in Equation 1,

3.5 × 15 = [tex]M_{2} [/tex] × 25

[tex]M_{2} [/tex]=[tex]\frac{3.5 * 15}{25}[/tex]

[tex]M_{2} [/tex]=2.1 M

Answer:

81.732KJ

Explanation:

Reaction : CaCO₃(s) → CaO(s) + CO₂(g), +556KJ

⇒To decompose 1 mole of CaCO₃, 556KJ of energy is required

The molecular weight of CaCO₃ is 40 + 12 + 3×16

⇒ molecular weight of CaCO₃ = 100 g

∴ 100 g of CaCO₃ requires 556KJ of energy

Need to find out how much energy is required by 14.7 g of CaCO₃

⇒ [tex]\frac{100}{14.7}[/tex] = [tex]\frac{556}{E}[/tex]

⇒ E = [tex]\frac{556}{100}[/tex]×14.7 KJ = 81.732 KJ

∴ Energy required to decompose 14.7 g of CaCO₃ is 81.732 KJ

Answer:

81.732 kilo Joules of energy is required to decompose 14.7 grams of calcium carbonate.

Explanation:

Moles of calcium carbonate = [tex]\frac{14.7 g}{100 g/mol}=0.147 mol[/tex]

[tex]CaCO_3(s) + 556 kJ\rightarrow CaO(s) + CO_2(g)[/tex]

According to reaction, 1 mole of calcium carbonate requires 556 kilo Joules of energy to decompose:

Then 0.147 moles of calcium carbonate will need:

[tex]0.147 \times 556 kJ=81.732 kJ[/tex]

81.732 kilo Joules of energy is required to decompose 14.7 grams of calcium carbonate.

Answer:

True

Explanation:

Answer:

Explanation:

1) How much would 1.34 moles of carbon weigh?

Given data:

Moles of carbon = 1.34 mol

Mass of carbon = ?

Solution:

Formula:

Molar mass of carbon = 12 g/mol

Number of moles = mass/molar mass

Mass =  moles × molar mass

Mass = 1.34 mol × 12 g/mol

Mass =  16.08 g

So 1.34 moles of carbon have 16.08 g mass.

2) How many  moles of magnesium in 24.32 g?

Given data:

Mass of magnesium = 24.32 g

Moles of magnesium = ?

Solution:

Molar mass of magnesium = 24.305 g/mol

Number of moles = mass/molar mass

Number of moles = 24.32 g/24.305 g/mol

Number of moles = 1 mol

Thus 24.32 g of magnesium have one mole of Mg.

3) How many atoms of lithium in 4.00 g of lithium?

Given data:

Mass of lithium = 4 g

Atoms of lithium = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

Moles of lithium:

Number of moles = mass/molar mass

Number of moles = 4 g / 6.9 g/mol

Number of moles = 0.6 mol

1 mole =  6.022 × 10²³  atoms

0.6 mol ×  6.022 × 10²³  atoms / 1 mol = 3.6 × 10²³  atoms

4) How much would 4.45 ×10²² atoms of U weigh?

Given data:

Number of atoms of uranium =  4.45 ×10²² atoms

Mass of uranium = ?

Solution:

one mole = 6.022 × 10²³  atoms

4.45 ×10²² atoms × 1 mol / 6.022 × 10²³  atoms

0.74 ×10⁻¹ mol

0.074 mol

Mass of uranium:

Mass = number of moles  × molar mass

Mass = 0.074 mol × 238 g/mol

Mass = 17.6 g

Answer:

If the electronegativity difference between bonded atoms are too much high ionic bonds are formed if the electronegativity diference is 0.4 or less than 0.4 non polar covalnet bond formed the difference greater than 0.4 polar covalent bond formed.

Explanation:

Ionic bond:

It is the bond which is formed by the transfer of electron from one atom to the atom of another element.  

Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.

For example:

Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion.

Covalent bond:

It is formed by the sharing of electron pair between bonded atoms.  

The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.