Which of the folllowing properties of matter is independent of its location.
A.Mass
B. Volume
C.Pressure
D.Weight

Your answer would be the;  NET  force on the object.   Refer to Newton's Laws of Forces and Motion.

Hope that helps!!!!!!!!!!!!!!!!                                        : )

Answer:

Net force

Explanation:

When a number of forces acting on a body, and then a non zero value of force is there. It is called net force acting on a body.

There are two types of forces.

1. Balanced forces

2. Unbalanced forces

When a number of forces acting on a body and then net force is zero, Then the forces are called balanced forces.

When a number of forces acting on a body and net force is non zero . Such forces are called unbalanced forces.

joule / second is the answer

Answer:

Option (A)

Explanation:

Watt is the SI unit of power.

The rate of doing work is defined as power.

Power = work/time

The SI unit of work is joule and the SI unit of time is second, so the SI unit of power is joule per second.

If joule of work is said to be done in second then we can say the power is watt.

By calculating the frictional force (0.25 * 50 N = 12.5 N), which is larger than the force of gravity on the book (10 N) we find that the book remains at rest against the wall. Hence, option c is correct.

This problem is about force and friction acting on a static object. To solve it, you first need to get the normal force acting on the book which is equal to the horizontal force pressing it against the wall (50 N). For a book to remain at rest the frictional force should be equal or greater than the weight of the book which is the mass times gravity, that is, 1 kg * 10 m/s^2 = 10 N.

The static frictional force between the book and the wall is calculated by multiplying the coefficient of static friction (0.25) and the normal force (50 N). This gives us a frictional force of 12.5 N which is greater than the weight of the book (10 N). Therefore the book remains at rest and doesn't slide along the wall. The correct statement hence is option c: The book remains at rest and the modulus of the frictional force between the book and the wall is 12.5N.

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Velocity = 278m/s

Distance = 7500m

Time = How long it takes?

Time = Distance/Velocity = 7500m ÷ 278m/s = 26.98 seconds (Rounded up to nearest two decimal places)

The formula is sum of the forces = Mass* Acceleration

If there is no friction (which i'm assuming not)

500N = 100 * A

A = 5 M/S/S (Or M/S^2)

her velocity is 0.82012

Answer:

Dina's velocity relative to the ground is 7.5 m/s.

Explanation:

Given that,

Velocity of Dina v = 0.5 m/s

Velocity of train v' = 8.0 m/s

We need to calculate the Dina's relative velocity

Using formula of relative velocity

Relative velocity=velocity of train - velocity of Dina

[tex]v_{r}=v'-v[/tex]

Where, v' = Velocity of train

v = Velocity of Dina

Put the value into the formula

[tex]v_{r}=8.0-0.5[/tex]

[tex]v_{r}=7.5\ m/s[/tex]

Hence, Dina's velocity relative to the ground is 7.5 m/s.

Final answer:

Density is a physical property of a substance, which can be observed and measured without changing the substance's chemical identity.

Explanation:

Density is a characteristic of a substance that refers to how much mass is contained in a given volume. It is considered a physical property because it can be observed and measured without changing the substance's chemical identity. Density can be particularly helpful in identifying substances and is measured in units such as grams per cubic centimeter (g/cm³) for solids and liquids or grams per liter (g/L) for gases.

Contrasting with physical properties are chemical properties, which describe how a substance can change or react to form new substances. These require a chemical change to be observed, such as rusting iron or burning wood, which both result in new chemical substances being formed.

Therefore, to answer the student's question, density is not a physical change, a chemical change, nor a chemical property; it is a physical property.

Answer:

Independent variable: washer detergent

Dependent varaible: cleaing power of effectivenes of the detergent.

Explanation:

When an experiiment is performed there exists one independent variable, one dependent variable, and some other variables that must be controlled.

The goal of the experiment is to test a hypothesis, which is a statement that relates an effect with a cause and that must be proved true or false.

The effect in the dependent variable, and the cause is the independent variable.

Jenny (the scientist) wants to show how an effect or phenomenun, the dependent variable, is explained by the explanatory, independent, variable.

In the stated experiment, Jenny wants to know how the effectiveness of a new brand detergent and an old one compare with each other. Therefore, she designs a test in which she will determine how the brand of detergent may  explain (explanatory or independent variable) the cleaning power or effectiveness, the dependent variable.

Jenny only can manipulate the independent variable and observe the effect on the dependent variable.

To be conclusive, other variables must be controlled, like the fabric and the amount of dirt of the t-shirts.

Answer:

The answer is A.

Explanation:

D = m/V  

Volume:  

3.00 x 3.00 x 3.00 = 27 cm³  

Answer A

The volume of the block is (3cm) · (3cm) · (3cm) = 27 cm³ .

That's how much water gets pushed out of the way when the block sinks in water. It makes no difference what the block is made of, or what its mass or density is.  Pick choice-A .

1. Define Newtons second law of motion (this will help put things into perspective)

2.Get the mass of the object (in this case 75 kg)

3.The net force acting on the object...find it (in this case 500 N)

4.Change the equation to F=ma (500=75a)

5.Divide both sides by 75 and that is the acceleration.

Answer:

Acceleration, [tex]a=6.66\ m/s^2[/tex]

Explanation:

Given that,

Force acting on the object, F = 500 N

Mass of the object, m = 75 kg

We need to find the acceleration of the object. The force acting on the object is given by :

[tex]a=\dfrac{F}{m}[/tex]

[tex]a=\dfrac{500\ N}{75\ kg}[/tex]

[tex]a=6.66\ m/s^2[/tex]

So, the acceleration of the object is [tex]6.66\ m/s^2[/tex]. Hence, this is the required solution.

Further Explanation:

As the dogs collectively full the sled on the wet snow surface, the sled will experience a net force due to all the dogs acting on it.

Part (a):

The net force applied by the 8 dogs on the sled is:

[tex]\begin{aligned}{F_{{\text{net}}}}&=8\timesF\\&=8\times185\\&=1480\,{\text{N}}\\\end{aligned}[/tex]

The net mass of the dog and the sled combined is:

[tex]\begin{aligned}M&=\left({8\times{m_d}}\right)+{m_s}\\&=\left({8\times19}\right)+210\\&=362\,{\text{kg}}\\\end{aligned}[/tex]

The net acceleration of the dogs and the sled combined is:

[tex]a=\frac{{{F_{net}}}}{M}[/tex]

Substitute the values of net force and mass in above expression.

[tex]\begin{aligned}a&=\frac{{1480}}{{362}}\\&=4.088\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\\&\approx4.09\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\\\end{aligned}[/tex]

Thus, the acceleration of the dogs as they pull the sled on the snow is [tex]\boxed{4.09\,{{\text{m}}\mathord{\left/{\vphantom {{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}}[/tex] .

Part (b):

Since the sled is moving with an acceleration of [tex]4.09\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}[/tex] , the net force experienced by the sled due to the pull of the dogs is:

[tex]{F_{sled}}={m_s}\times a[/tex]

Substitute the values in above expression:

[tex]\begin{aligned}{F_{sled}}&=210\times4.09\\&=858.9\,{\text{N}}\\&\approx{\text{859}}\,{\text{N}}\\\end{aligned}[/tex]

Thus, the force experienced by the sled due to the dogs is [tex]\boxed{859\,{\text{N}}}[/tex] .

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Answer Details:

Grade: High School

Subject: Physics

Chapter: Newton’s law of Motion

Keywords:

Team of eight dogs, waxed wood runners, loaded sled, with its rider, acceleration, average force 185 N, coupling between dog and sled, average masses of 19 kg each.

The kinetic energy of the object is 53775 Joules.

Given the following data:

To find the kinetic energy of the object:

Kinetic energy is an energy that is possessed by a physical object or body due to its motion.

Mathematically, kinetic energy is calculated by using the formula;

[tex]K.E = \frac{1}{2} MV^2[/tex]

Where:

Substituting the values, we have;

[tex]K.E = \frac{1}{2}[/tex] × [tex]478[/tex] × [tex]15^2[/tex]

[tex]K.E = 239[/tex] × [tex]225[/tex]

Kinetic energy = 53775 Joules

Therefore, the kinetic energy of the object is 53775 Joules.

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Answer:

 Terminal velocity of object = 12.58 m/s

Explanation:

 We know that the terminal velocity is attained when drag force and gravitational force are of the same magnitude.

Gravitational force = mg = 80 * 9.8 = 784 N

Drag force = [tex]12.0v+4.00v^2[/tex]

Equating both, we have

    [tex]784=12.0v+4.00v^2\\ \\ v^2+3v-196=0\\ \\ (v-12.58)(v+15.58)=0[/tex]

  So v = 12.58 m/s or v = -15.58 m/s ( not possible)

 So terminal velocity of object = 12.58 m/s    

Explanation :

Galileo studied Jupiter and its moons. Newton studied the gravitational force that held the planets in orbit.

Galileo constructed a telescope called Galileo's Telescopes. He also supported the Copernican theory.

Newton proposed the Universal law of gravitation. According to him, there exists a force between objects in the universe which is directly proportional to the product of masses and inversely proportional to the square of the distance between them.

i.e.

[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]

So, we can say that the two scientists proposed different theories about the solar system. This shows that they both had different interests.

oohhhhhhh i just figured this out

toxicity- B

heat of combustion- A

flammability- D

compressibility- C

Here are the matched terms with their corresponding definitions:

A) Compressibility: Measure of how much the volume of matter can decrease under pressure.

B) Flammability: How easily a substance can be set on fire.

C) Heat of combustion: Measure of how much heat is given off when a substance is burned.

D) Toxicity: The ability of a substance to damage or harm an organism.

Flammability is a property of a substance that refers to how easily it can catch fire or ignite when exposed to an open flame, heat, or other sources of ignition. It is a measure of the substance's susceptibility to burning. Substances with high flammability are more likely to ignite and sustain combustion, while those with low flammability are less likely to do so.

Flammability is an important characteristic to consider in various contexts, including safety regulations, the handling and storage of chemicals, and the development of fire-resistant materials.

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The most important characteristics that are exhibited by metals are-

1- Metals are ductile

2-Most metals are conductive in nature.

3-Most metals are malleable.

4- Metals have strong inter molecular force of attraction between the.

5-Metals have luster.

6-Metals are sonorous.

Here we are given Tungsten filament.

Tungsten is  a metal.So it must be conductive and as well as ductile in nature.

The electric filament that we are using in our electric bulb glows due to the heating effect of current.Hence the chosen substances for glowing electric bulb must have high melting point.

The melting point of tungsten is 1650 degree celsius which is very high.That's why it is used in electric bulb.

Hence the correct answer to the question is the third one i.e Tungsten is ductile,has a high melting point, and is electrically conductive.

Answer:

c) Tungsten is ductile, has a high melting point, and is electrically conductive.

Explanation:

i took the test

Answer:

 Position at t= 4 seconds is 144 m

Explanation:

 It is given that acceleration, a = 18 t, where t is the time.

 We know that Velocity, [tex]v = \int { a} \, dt[/tex]

  Substituting value of a,

           Velocity, [tex]v = \int {18t} \, dt=\frac{18t^2}{2} +c=9t^2+c[/tex]

 We know that at t = 0, v = -12 m/s

         So, [tex]9*0^2+c=-12\\ \\ c=-12m/s[/tex]

So velocity, [tex]v = (9t^2-12)m/s[/tex]

  We also know that displacement, [tex]x = \int { v} \, dt[/tex]

     Substituting value of v,  

        Displacement, [tex]x=\int {(9t^2-12)} \, dt=\frac{9t^3}{3} -12t+c=3t^3-12t+c[/tex]

  We know that at t = 0, particle is at origin, x =0.

               So,  [tex]0=3*0^3-12*0+c\\ \\ c=0[/tex]

   Displacement, [tex]x = 3t^3-12t[/tex]

At t = 4 seconds

   [tex]x = 3*4^3-12*4=192--48=144m[/tex]

Position at t= 4 seconds is 144 m  

]The particle is at 144 meters along the x-axis at t=4.0 seconds.

To find the position, we first need to integrate the acceleration to get the velocity as a function of time, and then integrate again to get the position.

We know that acceleration is the derivative of velocity with respect to time, so:

v(t) = ∫dt = ∫18t dt = 9t2 + C

Where C is the integration constant. Using the initial condition, v(0) = -12 m/s, we find that C = -12.

Now we integrate the velocity to find the position:

x(t) = ∫v(t) dt = ∫(9t2 - 12) dt = 3t3 - 12t + D

Where D is another constant of integration, since the particle is at the origin at time t=0, x(0) = 0, we find D = 0.

Finally, we plug t = 4.0 s into the position function:

x(4) = 3(4)3 - 12(4) = 192 - 48 = 144 meters.

The particle's position at t=4.0 seconds is 144 meters along the x-axis.

The acceleration of the car that when from rest to 30m/s in 1 minute is 0.5 m/s².

The first equation of motion is expressed as:

v = u + at

Given the data in the question:

Elapsed time t = 1 minutes = 1 × 60 = 60 seconds

Initial velocity u = 0

Final velocity = 30 m/s

Acceleration a =?

Plug the given values into the above formula and solve for the acceleration of the car.

v = u + at

30 = 0 + ( a × 60 )

30 = 0 + 60a

30 = 60a

a = 30/60

a = 3/6

a = 0.5 m/s²

Therefore, the acceleration is 0.5 m/s².

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It sounds like the ball's velocity along the [tex]y[/tex]-axis should be taken to be constant, in which case the ball has velocity vector

[tex]\mathbf v(t)=\left(2.10\,\dfrac{\mathrm m}{\mathrm s^2}\right)t\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)\,\hat{\jmath}[/tex]

We note that at [tex]t=t_0[/tex], we're told the ball is at the origin, so its position at this point is [tex]\mathbf r(t_0)=\mathbf 0[/tex]. We then integrate the velocity vector to find the position vector:

[tex]\mathbf r(t)=\mathbf r(t_0)+\displaystyle\int_{\tau=t_0}^{\tau=t}\mathbf v(\tau)\,\mathrm d\tau[/tex]

[tex]\mathbf r(t)=\displaystyle\int_{\tau=t_0}^{\tau=t}\left(2.10\,\dfrac{\mathrm m}{\mathrm s^2}\right)\tau\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)\,\hat{\jmath}\,\mathrm d\tau[/tex]

[tex]\mathbf r(t)=\left(1.05\,\dfrac{\mathrm m}{\mathrm s^2}\right)\tau^2\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)\tau\,\hat{\jmath}\bigg|_{\tau=t_0}^{\tau=t}[/tex]

[tex]\mathbf r(t)=\left(1.05\,\dfrac{\mathrm m}{\mathrm s^2}\right)(t^2-{t_0}^2)\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)(t-t_0)\,\hat{\jmath}[/tex]

For the sake of simplicity, I'll assume [tex]t_0=0[/tex], so that

[tex]\mathbf r(t)=\left(1.05\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)t\,\hat{\jmath}[/tex]

(a) Then at [tex]t=2.50\,\mathrm s[/tex], the ball's position in the plane is given by the vector

[tex]\mathbf r(2.50\,\mathrm m)=(6.56\,\mathrm m)\,\hat{\imath}+(3.25\,\mathrm m)\,\hat{\jmath}[/tex]

which is to say its position in the plane is at the point (6.56, 3.25).

(b) The ball's displacement is the same as its position, but in vector form (as above).

(c) The ball has velocity

[tex]\mathbf v(2.50\,\mathrm s)=\left(5.25\,\dfrac{\mathrm m}{\mathrm s}\right)\,\hat{\imath}+\left(1.3\,\dfrac{\mathrm m}{\mathrm s}\right)\,\hat{\jmath}[/tex]

That is, the ball has a speed of [tex]\|\mathbf v(2.50\,\mathrm s)\|=5.41\,\dfrac{\mathrm m}{\mathrm s}[/tex] and is traveling in a direction of about [tex]13.9^\circ[/tex] relative to the positive [tex]x[/tex]-axis.

At t=2.5s, the ball's position will be at coordinates (6.5625, 3.25), have a displacement of approximately 7.23 metres, and have a velocity of 5.25 m/s in the x direction and 1.3 m/s in the y direction.

The subject of this question is physics, specifically kinematics, and the topic is motion in two dimensions. We will calculate the x and y coordinates, the displacement, and the velocity for the given conditions. First we will calculate the x-coordinate using the equation of motion x = ut + 0.5at^2, where 'u' is initial velocity, 'a' is acceleration and 't' is time. Here, the initial velocity along x-axis is zero, acceleration is 2.10 m/s^2, and time is 2.5 s. Substituting these values, we get x = 0 + 0.5 * 2.1 * (2.5)^2 = 6.5625 m.

Next, for the y-coordinate, since there is no acceleration along y-axis, its position at any time is given by y = ut, where 'u' is initial velocity along y-axis, and 't' is time. So, y = 1.30 * 2.50 = 3.25 m.

Next, the displacement, which is the shortest distance from the initial to the final position, can be found using the Pythagorean theorem, d = sqrt(x^2 + y^2). Thus, d = sqrt((6.5625)^2 + (3.25)^2) = 7.23 m approximately.

Lastly, the velocity of the ball at any point is given by v = u + at, where 'a' is the acceleration along the x-axis, 't' is time and 'u' is the initial velocity (which is zero in this case along the x-axis). So, v = 0 + 2.1 * 2.5 = 5.25 m/s along the + x-direction. And, the velocity along the y-axis remains constant as 1.30 m/s because there's no acceleration in the y direction.

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The chemical symbol of an element is determined by its name in English or Latin, with the first letter used to create a one or two-letter symbol. The symbols are standardized by IUPAC.

The chemical symbol of an element is determined based on its name in English or Latin. The first letter of the element's English or Latin name is used to create a one or two-letter symbol. If the symbol has two letters, the first letter is capitalized and the second letter is lowercase.

For example, the symbol for Hydrogen is H, Oxygen is O, Carbon is C, and Gold is Au. In some cases, symbols are derived from the element's Latin name, such as Sodium (Na) from Natrium and Potassium (K) from Kalium.

This system of chemical symbols was established by the International Union of Pure and Applied Chemistry (IUPAC) to provide a standardized representation for elements across different languages and countries.

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If a person does aerobic exercise but does not work to build muscle, they may improve cardiovascular fitness and endurance, but may not see significant changes in muscle size or strength.

Doing aerobic exercise without working to build muscle can have several effects. Aerobic exercise primarily targets and improves cardiovascular fitness, which includes strengthening the heart and improving lung capacity. However, without resistance training, muscle mass and strength may not significantly increase. This means that while a person may improve their endurance and cardiovascular health, they may not see significant changes in muscle size or strength.

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Answer:

b

Explanation:

cuz i no

The slope of the position-time graph represents the corresponding velocity - this relationship forms the basis for the creation of a velocity-time graph. Positive slopes on the position-time graph mean forward motion and negative slopes mean backward motion which is graphically represented as positive and negative slopes on the velocity-time graph respectively.

The position-time graph and the velocity-time graph are closely related. The slope of the position-time graph at any given point represents the velocity at that point in time. For example, if you have a straight line on a position-time graph which has a positive slope, it means the object is moving in a positive direction or forward. Therefore, the velocity-time graph for the same object would also have a straight line with positive slope.

A similar concept applies if the slope on the position-time graph is zero, it means the velocity at that time is zero and this would be represented as horizontal line on the velocity-time graph. Another interesting aspect is, if the slope of a position-time graph is negative, it means the object is moving in a negative or backward direction and the corresponding a velocity-time graph would have a negative slope.

It’s notable that straight lines on velocity-time graphs indicate constant velocity, whereas lines with positive or negative slope indicate acceleration or deceleration respectively.

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That would be a conduction.

conduction

hope this helped

Hello!

Answer: Newton's Laws of Motion.

Explanation:

↓↓↓↓↓↓↓↓↓↓↓↓

Isaac Newton he performed many experiments involving light (optics). Then he published works on mathematics, history, calculus, and theology. And he published his most significant book, Philosophiae Naturalis Principia Mathematica, in 1687. Newton's first law of motion states that an object at rest stays at rest, and an object in motion stays in motion, unless acted on by an unbalanced force. This is also known as the law of inertia. Inertia is the natural tendency of objects to resist change in motion. Newton's second law of motion states that the total net force acting an object is equal to mass times acceleration. Newton's third law of motion states that for every action, there is an equal and opposite reaction. It considered action and reaction forces.

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All the bats living in a cave form a __colony__of bats in the cave ecosystem.

The bats living in a cave form a population of bats within that cave ecosystem. The term 'population' in biology refers to all individuals of a particular species inhabiting a specific area. Factors such as diseases and resource exploitation can though impact a population.

All the bats living in a cave form a population of bats in that cave ecosystem. A population refers to all individuals of a species living within a specific area. For instance, the bats in a cave represent the population of bats in that particular cave. It's important to note that populations aren't static - they can be affected by various factors such as disease. For instance, the tragedy of the commons principle suggests that resources held in common, such as a cave, could potentially be overexploited, leading to population decline. A specific example is white-nose syndrome, a disease impacting bat populations that inhabit caves in the eastern United States and Canada.

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