Answer: (c) Gluconeogenesis
Explanation:
Gluconeogenesis (“new formation of glucose”) uses amino acids and lactic acid obtained from muscle proteins to convert into glucose. The glucocorticoids stimulate the liver to produce the enzymes needed for gluconeogenesis, the conversion of amino acids into glucose. This creation of glucose from protein is particularly important during very long periods of fasting or exercise when blood glucose levels might otherwise become dangerously low.
What is Grave's disease?
Answer:
Graves´ disease is an autoinmmune disease that is caused when the immune system attacks the cells of the thyroid gland, which leads to an overproduction of the hormones secreted by the thyroid gland. This constant attack and destruction on the part of the immune cells causes the thyroid to increase in size, a condition that is commonly known as hyperthyroidism.
Hyperthyroidism can become a really serious issue because the excessive production of the hormones of the thyroid gland will increase the metabolic activity of all parts of the body and can, if left untreated, cause such serious conditions as blood clotting problems, type 1 diabetes, among others.
How does each of the following molecule pass through the plasma membrane in the described scenarios?
A. Both simple diffusion and facilitated diffusion
B. facilitated diffusion
C. active transport
D. simple diffusion
selectABCD 1.
Molecular oxygen (O2) and carbon dioxide (CO2) traveling down their concentration gradient.
selectABCD 2.
inorganic ions traveling down their concentration gradient
selectABCD 3.
glucose traveling against its concentration gradient
selectABCD 4.
water molecules (H2O) traveling down their concentration gradient
Answer:
1. simple diffusion.
2. facilitated diffusion.
3. active transport.
4. both simple and facilitated diffusion.
Explanation:
1. Simple diffusion can be defined as transport of small, non-polar, uncharged molecules, such as urea, gases, water through the lipid bilayer without the help of transport proteins.
As molecular oxygen and carbon dioxide are gases, these molecules would be transported by simple diffusion.
Thus, statement 1 correctly matches with option (D).
2. Facilitated diffusion involves transport of polar, charged, and large molecules, such as ions, glucose, and amino acids with the help of membrane proteins, known as transport proteins.
Passive transport is an example of of facilitated diffusion, which includes transport of molecules from higher to lower concentration (along their concentration gradient) without use of energy.
As ions are travelling down their concentration gradient, it is an example of facilitated transport.
Thus, statement 2 correctly matches with option (B).
3. Active transport is a type of facilitated diffusion that involves transport of molecules against their concentration (from lower to higher) with the help of energy. As glucose is travelling against its concentration, it is an example of active transport.
Thus, statement 3 correctly matches with option (C).
4. Water molecules are small, charged molecules that can be transported by both simple diffusion through lipid bilayer or facilitated diffusion through transport proteins, aquaporins.
Thus, statement 4 correctly matches with option (A).
Final answer:
The transport methods for various molecules across the plasma membrane are specific to their nature and include simple diffusion for O2 and CO2 (D), facilitated diffusion for inorganic ions (B), active transport for glucose against its concentration gradient (C), and osmosis/simple diffusion or through aquaporins for water (A).
Explanation:
Transport across the plasma membrane includes various mechanisms such as simple diffusion, facilitated diffusion, active transport, and osmosis. These mechanisms depend on the nature of the molecule being transported and the direction relative to the concentration gradient.
Molecular oxygen (O2) and carbon dioxide (CO2) traveling down their concentration gradient can move through the plasma membrane by simple diffusion (Choice D).
Inorganic ions traveling down their concentration gradient typically require facilitated diffusion through channel or carrier proteins (Choice B).
Glucose, when traveling against its concentration gradient, is transported by active transport mechanisms that require energy (Choice C).
Water molecules (H2O) traveling down their concentration gradient generally pass through the membrane by means of osmosis, which can occur via simple diffusion or through aquaporins (Choice A).
Walking alone late one night, you are startled by a moving shadow that you glimpse out of the corner of your eye. The _______ division of the autonomic nervous system is activated. When you realize it is just the neighbor’s pet, the _______ division lessens your physiological arousal.
Answer:
Walking alone late one night, you are startled by a moving shadow that you glimpse out of the corner of your eye. The sympathetic division of the autonomic nervous system is activated. When you realize it is just the neighbor’s pet, the parasympathetic division lessens your physiological arousal.
The sympathetic division of the autonomic nervous system activates when you're startled, initiating the 'fight or flight' response. Once the danger has passed, the parasympathetic division lessens physiological arousal, returning the body to a restful state.
Explanation:The autonomic nervous system (ANS) is a part of the peripheral nervous system that acts primarily unconsciously and regulates bodily functions. When you were startled by a moving shadow, the sympathetic division of the ANS was activated, stimulating your 'fight or flight' response and increasing your heart rate, dilating the pupils, and halting digestion. Then, after realizing it was just the neighbor's pet, the parasympathetic division stepped in, reducing your physiological arousal by slowing your heart rate, constricting your pupils, and resuming digestion, thus restabalizing your body conditions.
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What are the three types of body membranes?
The body contains two main types of tissue membranes: connective tissue and epithelial membranes. The three types of epithelial membranes are mucous membranes, serous membranes, and the cutaneous membrane (skin), each serving unique protective and functional roles in the body's operation.
Explanation:There are two broad categories of tissue membranes in the human body: connective tissue membranes and epithelial membranes. Among these, three specific types of epithelial membranes exist, playing critical roles in the body's function and structure. These are:
Mucous membranes: These are found lining the body cavities and hollow passageways that open to the external environment. They secrete mucus, which is essential for keeping these surfaces moist and protected.Serous membranes: These line body cavities that are closed to the exterior, such as the peritoneal, pleural, and pericardial cavities. Serous membranes secrete a lubricating fluid that reduces friction between the organs they envelop.Cutaneous membrane: More commonly known as the skin, it covers the body's exterior. The skin is a complex organ vital for protection, temperature regulation, and sensation.Lastly, connective tissue membranes include synovial membranes, which line the moveable joint cavities, facilitating smooth joint movements. Understanding these membranes is essential for comprehending how the body protects, separates, and ensures the smooth operation of its internal mechanisms.
3. Which of the following situations is least likely to lead to geographic isolation and allopatric speciation?
a. An eight-lane highway divides a population of snails with limited mobility.
b. A deep, narrow river divides a population of hummingbirds.
c. A deep, narrow river divides a population of white-footed mice (not known for their swimming ability).
d. A patch of land bisects a river and divides a population of minnows.
e. A mountain range divides a population of moths.
Answer:
b. A deep, narrow river divides a population of hummingbirds.
Explanation:
Hummingbirds can fly across the river. The deep and narrow river can not separate a population of hummingbirds into two patches since hummingbirds from one side of the river can fly and reach to the other side of the river.
Without any geographical isolation, hummingbirds can continue to interbreed among themselves. The continued interbreeding would not allow their reproductive isolation and thereby would prevent the allopatric speciation.
2. All of the following are true of crossing over, EXCEPT
crossing over occurs immediately after an egg is fertilized.
homologous chromosomes exchange genetic material.
crossing over results in unique combinations of alleles.
crossing over occurs during meiosis I.
crossing over occurs only in cells destined to become sperm or egg.
Answer:
Option (1)
Explanation:
Meiosis is also known as reduction division. Meiosis is the process of cell division by which a parent cell divides to give four daughter cells each with half number of chromosomes.
Crossing over may occur during meiosis I of the cell cycle. Crossing over will not occur in the cells immediately after the fertilization of egg and zygote restores the original number of chromosomes.
Thus, the correct answer is option (1).
The statement 'crossing over occurs immediately after an egg is fertilized' is NOT true.
Crossing over, also called recombination, occurs in meiosis, a type of reductional cell division by which one parental cell divides to produce four gametes (germinal cells) having half of the genetic material.Crossing over specifically occurs during the first phase of Meiosis I i.e., during Prophase I.This process (crossing over) increases the genetic variation of the resulting germinal cells (either spermatic or egg cells).In conclusion, the statement 'crossing over occurs immediately after an egg is fertilized' is NOT true.
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Where is the origin of the rectus femoris?
Answer:
Explanation:
Rectus femoris can be define as a bulk of muscle that is located in the anterior and superior compartment of the thigh. These muscles originates from the anterior illiac spine and from the parts of the alar illium that is superior to the acetabulum that is the part of the hip bone.
The growth of skeletal bones is controlled by a hormone from the:
Answer:
a hormone from the pituitary gland, or part of the brain.
Explanation:
the pituitary gland in the brain and the thyroid gland contribute 2 growth between the age of 13-25...
In the small intestines, a process called ____________ aids in mixing. During this process the contents ____________ move along the tract.
Answer: Segmentation;do not
Explanation:
The food that we ingest through mouth and the food moves from mouth to esophagus and then from esophagus to intestine followed by stomach.
Segmentation can be defined as the contraction that occurs in large and small intestine. In this process contraction moves the chyme in both directions which allows a better of the secretions with the chyme. This process do not takes place along the tract.
The correct answers are segmentation and do not.
In guinea pigs, black fur is an autosomal dominant trait, and white is the alternative recessive trait. A Hardy-Weinberg population of 400 guinea pigs was found to contain 64 white individuals. In this population, what percentage of BLACK animals is expected to be HETEROZYGOUS?
Answer:
49.14%
Explanation:
The frequency of the heterozygous individuals in the population is therefore: 64/400 = 0.32
Using the Hardy Weingburg equation of a population is equilibrium = p2 + 2pq + q2 = 1
q2 = 0.32; Therefore q = 0.5657 –> alellic frequencies
If p + q = 1; Then p 1 – q = 1 – 0.5657 = 0.4343
Heterozygous individuals are represented by 2pq = 2 * 0.4343 * 0.5657 = 0.4914
0.4914 * 100 = 49.14% of the population which translates to 0.4914 * 400 = 196.56 (197) individuals
Can the genotype for a gray-bodied fly be determined? Why or why not? Describe all of the possible genotypes for a fly with that phenotype
Answer:
The genotype of a fly can be determined gray bodied is dominant over black body flies. The possible genotype of a fly is either YY or Yy.
Explanation:
The genotype of a gray bodied fly can be determined with the help of punnett square. The gray bodied fly is crossed with black bodied fly, the original genotype of the fly can be determined. This type of cross is known as test cross.
If the cross results in the formation of all gray bodied progeny, the fly is homozygous dominant with the genotype YY. The cross results in the mixture of progeny with gray and black body , then the genotype of a fly is heterozygous dominant Yy.
Thus, the genotype of a fly can be determined by the test cross. The fly may have genotype either YY or Yy.
Over time, some plants growing in an area are crowded out by other plants. The new plants use up water and nutrients needed by the previous plants. The disappearance of the first plants is due to:
Answer:
Competitive exclusion
Explanation:
According to competitive exclusion principle two species cannot exist together if these species share the same habitat and resources. This principle was given by the scientist Georgy Gause.
Some plants that are growing in an area are crowded by other plants over time. The new plants use water, nutrients and the first plants are disappeared because both plant species share same resources and habitat. These two species cannot co exist and the second plant causes the disappearance of plant because of competitive exclusion.
Defecation
a. is initiated by distension of the wall of the colon.
b. depends on voluntary control of the external sphincter of the anus.
c. depends on the motor impulses from sympathetic pathways.
d. decreases pressure in the rectum.
Answer:
A. is initiated by distension of the wall of the colon
Explanation:
not sure
Saddle joints have concave and convex surfaces. Name the two bones of the hand that articulate to form a saddle joint. A. The trapezium of the carpal bone and the thumb's metacarpal. B. The scaphoid of the index finger and the triquetrum of the middle finger. C. The trapezium of the ring finger and the capitate of the fourth finger. D. The scaphoid of the middle finger and lunate of the index finger.
Answer:
Option (A).
Explanation:
Saddle joint is a type of synovial joint and also known as sellar joint. These joints are present in thumb, shoulder and inner ear.
The bone has one part concave inward and other part is convex outward. This bone can articulate with thumb's metacarpal and trapezium of the carpal bone. Saddle joints show abduction and adduction movements.
Thus, the correct answer is option (A).
The saddle joint in the hand is the first carpometacarpal joint, located between the trapezium carpal bone and the first metacarpal bone of the thumb, allowing for the distinct opposability of the thumb.
Explanation:The saddle joints in the human body are a type of synovial joint where the articulating bone surfaces each resemble a saddle, which is concave in one direction and convex in the other. This design allows for a wide range of movements.
Specifically, in the hand, the saddle joint is found at the first carpometacarpal joint, which is between the trapezium, one of the carpal bones, and the first metacarpal bone that forms the base of the thumb. This versatile joint enables the thumb to move across two planes, allowing for the distinctive human ability to oppose the thumb against the other fingers.
Based on this description, the correct answer to which two bones articulate to form a saddle joint in the hand is: A. The trapezium of the carpal bone and the thumb's metacarpal.
Old cultures of bacteria that have lost their ability to cause disease are said to be
Select one:
a. impotent.
b. virulent.
c. pathogenic.
Explanation:
thats all that I could find I hope it helps a little bit :)
Compare parasympathetic nervous system vs sympathetic nervous system
Answer:
The nervous system together with the endocrine system enables the organism to perceive the variations of the (internal and external) to disseminate modifications that these variations produce and execute the answers appropriate to maintain the internal body balance (homeostasis). The autonomic nervous system divides into the sympathetic nervous system and parasympathetic nervous system. In general, these two systems have opposite (antagonistic) functions, they correct the excesses of the other.
For example, if the sympathetic system speeds up too much the heartbeat, the parasympathetic system kicks in, slowing down the heart rate. If the sympathetic system speeds up stomach work and intestines, the parasympathetic comes into action to reduce the contractions of these organs. The sympathetic generally stimulate actions that mobilize energy, allowing the body to respond to stressful situations. For example, the sympathetic system is responsible for the acceleration of heart rate, by increasing the blood pressure, the concentration of blood sugar and by activating the general metabolism of the body. On the other hand, parasympathetic mainly stimulates relaxing activities, such as reductions in the heart rate pace and blood pressure. One of the main differences between the sympathetic nerves and parasympathetic is that the postganglionic fibers of the two systems usually secrete different hormones.
Other nutrients will require a transporter in the membrane, as well as a concentration gradient. This process of ____________ is the process by which some monosaccharides are absorbed.
Answer:
Facilitated diffusion
Explanation:
Facilitated diffusion is the process of diffusion in which ion or some substances are transported across the membrane by a specific carrier membrane protein. The process does not require the input of energy and is driven by a concentration gradient.
The absorption of simple sugars in small intestine occurs through facilitated diffusion. The polar sugar molecules can not cross the nonpolar inner core of the membrane. Hence, the membrane proteins transport the sugars down the concentration gradients without any input of energy.
In bones, a layer of osteoblasts and osteoclasts line the interior of the bone (this cellular layer covers all trabeculae, is adjacent to the medullary cavity and lines the inside of osteons). This layer is called the endosteum. What is its role in bone?
Answer:
Endosteum plays an important role in bone repair, bone remodelling and appositional bone growth.
Explanation:
Endosteum consists of a soft and thin connective tissue that lines the cavity of femur and humerus. Some of the major functions of endosteum are as follows:
Bone remodelling: Endosteum can stimulate the bone resorption that leads to the formation of new bone from the outside.
Bone repair: Hematoma, at the time of bone injury causes the division of endosteal cells and helps in bone repair.
Appositional bone growth: Endosteum that line the osteoblast cell can secrete bone matrix and increases the bone diameter.
2. Why is differential media typically inoculated with isolated colonies that have been previously cultured on general growth media?
General growth media serves the purpose of generating more bacteria colonies to create enough samples to identify to perform other tests. Differential media is used to differentiate species or subspecies of bacteria by how they differentially react to the dyes of chemicals in the media due to differences in metabolic properties of the different bacteria species. An example of differential media is MacConkey agar.
Differential media enable the differentiation of bacteria based on their metabolic activities. Isolated colonies are used to avoid mixing different types, with initial growth on general media enhancing bacterial cultivation. Subsequent inoculation onto differential media allows for identification through unique characteristics exhibited.
Explanation:Differential media are typically inoculated with isolated colonies that have been previously cultured on general growth media to ensure the accuracy of the identification process. This is done primarily because some media, particularly differential media, are designed to differentiate between different types of bacteria based on their metabolic activities. The appearance of the bacterial colonies on differential media, such as change in color, can provide crucial insights into the identity of the bacteria.
It's important that only isolated colonies are used to prevent a mix-up of different types of bacteria, which could make interpretation of results challenging. Initially cultivating these bacteria on general growth media also helps enhance the growth of the bacteria, as it provides all the necessary nutrients required for bacterial growth. Their subsequent transfer to the differential media then allows for easy identification based on the unique characteristics they exhibit on these media.
For example, on MacConkey agar, a type of differential medium, bacteria that ferment lactose will cause the medium to turn pink due to acid production. This acid production causes a pH change, which is demonstrated by a color change because of a pH indicator in the medium. Such visible changes make it easier to identify specific types of bacteria.
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Identify the major weight bearing part of a vertebra
Answer:
Vertebral body
Explanation:
The vertebral body serves as weight-bearing part of a vertebra. The vertebral body is the thick and disc-shaped structure and forms the anterior portion of the vertebrae. A vertebral body has rough inferior and superior surfaces. Being disc-shaped, the vertebral bodies of subsequent vertebrae are stacked upon each other and thereby, serve to carry the weight.
The major weight bearing part of a vertebra is the vertebral body, which progressively increases in size and thickness going down the vertebral column. Lumbar vertebrae carry the greatest amount of body weight and have specific characteristics to support this.
Explanation:The major weight bearing part of a vertebra is the vertebral body. The vertebral bodies progressively increase in size and thickness going down the vertebral column, with the lumbar vertebrae supporting the greatest amount of body weight due to their large size and thickness. They have short transverse processes and a short, blunt spinous process that projects posteriorly.
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The mitotic spindle consists of two types of microtubules: kinetochore microtubules and nonkinetochore microtubules. In animal cells, these two types of microtubules function differently in the stages of mitosis.
Complete the sentences by dragging the labels to the appropriate locations. Labels may be used once, more than once, or not at all.
OPTIONS: Shorten, Lengthen, Disassemble
1) During prophase, the microtubules of the mitotic spindle________.
2) During anaphase, the nonkinetochore microtubules _______ and move past each other, and the kinetochore microtubules________.
3) During telophase, the nonkinetochore microtubules______.
Answer:
The correct answer will be
1. Lengthen
2. Lengthen, shortens
3. Disassemble
Explanation:
There are three types of microtubules present during cell division: kinetochore, aster and polar microtubules.
1. During prophase: all types of microtubules grow out at their positive(+) ends which functions to pull and push the sister chromatids apart towards opposite poles so they lengthen.
2. During anaphase : non-kinetochore microtubules- polar microtubules polymerization takes place at their (+) ends which causes the spindle fibres to move apart while kinetochore microtubules which have been attached to the kinetochores of chromosomes shorten at their (+) ends and motor proteins travel to (-) end because of which sister chromatids move towards the spindle poles.
3. During telophase: non-kinetochore microtubules depolymerize or disassembles.
Thus, 1. Lengthen, 2. Lengthen, shortens and 3. Disassemble are the correct options.
In mitosis, the microtubules of the mitotic spindle lengthen during prophase. In anaphase, nonkinetochore microtubules lengthen while kinetochore microtubules shorten. During telophase, nonkinetochore microtubules disassemble.
Explanation:The mitotic spindle plays crucial roles during the process of cell division called mitosis in animal cells. The spindle consists of two types of microtubules, namely, kinetochore and nonkinetochore microtubules, each having unique functions during different stages of mitosis. Let's understand these functions to complete your sentences:
During prophase, the microtubules of the mitotic spindle lengthen.During anaphase, the nonkinetochore microtubules lengthen and move past each other, and the kinetochore microtubules shorten.During telophase, the nonkinetochore microtubules disassemble.Learn more about Microtubules Functions in Mitosis here:https://brainly.com/question/22044734
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A period of sustained skeletal muscle contraction in which individual twitches cannot be detected is called
Complete tetanus represents a period of sustained skeletal muscle contraction without detectable individual twitches, occurring at high frequencies of motor neuron signals that fuse contractions into a continuous state.
A period of sustained skeletal muscle contraction in which individual twitches cannot be detected is called complete tetanus. This occurs when the frequency of motor neuron signaling is so high that muscle fibers respond with continuous contractions. A single twitch doesn't produce significant muscle activity in a living body, rather a series of action potentials is necessary for a graded muscle response. During incomplete tetanus, the muscle experiences quick cycles of contraction with short relaxation phases. However, in complete tetanus, the stimulus frequency is high enough that the relaxation phase is eliminated, and the contractions fuse into one sustained contraction.
Which of the following are primary lymphoid organs?
a.bone marrow and thymus
b.appendix and spleen
c.lymph nodes and tonsils
d.spleen and thymus
Answer:
a.bone marrow and thymus
Final answer:
The primary lymphoid organs are the bone marrow and thymus, where lymphocytes mature and are selected. The secondary lymphoid organs, such as tonsils, spleen, and lymph nodes, store lymphocytes and filter lymph for pathogen encounters and immune responses.
Explanation:
The primary lymphoid organs are the bone marrow and thymus. B cells mature in the bone marrow, while T cells mature in the thymus. These organs are where lymphocytes go through maturation and selection processes to enable them to attack pathogens without harming the body's own cells.
The secondary lymphoid organs include the tonsils, spleen, and lymph nodes. Tonsils, spleen, and lymph nodes store lymphocytes and filter lymph, allowing for pathogen encounters and initiation of adaptive immune responses.
The correct option is a. bone marrow and thymus.
Parasympathetic stimulation
a. causes chief cells to stop the production of H+ and Cl-.
b. causes the gastric glands to increase production of gastric juice.
c. leads to a decrease in the secretion of gastrin.
d. causes a decrease in salivation.
Answer: b. causes the gastric glands to increase production of gastric juice.
Explanation:
The parasympathetic nerves are part of the autonomous nervous system. The parasympathetic predominates mainly during "passive responses" of the organism, such as satiety, rest and digestion. Its functions are: Promotes energy conservation, Reduces heart rate, Promotes glandular secretion, Protects the retina from excess light, Promotes emptying of cavities, Promotes rest and repair, Physiologically antagonizes sympathetic nervous system.
Answer:
b. causes the gastric glands to increase production of gastric juice
Explanation:
Parasympathetic stimulation is a function that is carried out by the Parasympathetic Nervous System which is a part of the Autonomic Nervous System.
Parasympathetic stimulation results in the process of digestion, production of saliva, production of urine, Production of tears, decrease in the heart rate and blood pressure.
Parasympathetic stimulation is involves in the process of digestion because after the injection of food , when the body is at rest, Parasympathetic stimulation increase the rate of the digestion process by, stimulating the gastric glands so that they can produce more gastric juice. This gastric juice contains enzymes and some other substances such as
a. Pepsin for the digestion of protein.
b. Renin
c. Hydrochloric acid (HCl) in other to deactivate any bacteria found food present in the stomach.
d. Mucus which helps to protect the lining of the digestive system.
Frutose’s molecular weight is 180 g/mole. A can of coke cola (330ml) contains 35 g fructose. The molar concentration fructose in coke cola is
Answer:
The molar concentration of [tex]35[/tex] g fructose in [tex]330 ml[/tex] solution is [tex]0.589[/tex]moles/litre
Explanation:
Given -
Molecular weight of fructose [tex]= 180 \frac{g}{mole}[/tex]
Can of coka coal has fructose [tex]= 35[/tex] gram
Volume of can of coke [tex]= 330[/tex] ml
Number of moles in [tex]35[/tex] grams of Fructose
[tex] = \frac{35}{180} \\= 0.194[/tex]
Molar concentration
[tex] = \frac{0.194}{0.33l} \\= 0.589\\[/tex] moles/litre
Hence, the molar concentration of [tex]35[/tex] g fructose in [tex]330 ml[/tex] solution is [tex]0.589[/tex]moles/litre
Final answer:
The molar concentration of fructose in a can of Coca-Cola is determined by dividing the mass of fructose by its molecular weight to find the moles, and then dividing by the volume in liters to find the concentration, which is 0.589 mol/L.
Explanation:
The molar concentration of fructose in coke cola can be calculated using the formula for molarity, which is moles of solute per liter of solution (mol/L). The moles of fructose are found by dividing the mass of fructose by its molecular weight. In this case, 35 g of fructose is divided by 180 g/mole to find the moles of fructose. To find the volume in liters, we convert 330 mL to liters by dividing by 1000, since there are 1000 mL in a liter.
We calculate the moles of fructose:
moles of fructose = 35 g / 180 g/mole = 0.1944 moles.
Then we convert the volume of Coca-Cola to liters:
volume in liters = 330 mL / 1000 = 0.33 L.
Finally, the molar concentration of fructose in Coca-Cola is:
molar concentration = 0.1944 moles / 0.33 L = 0.589 mol/L.
Protection from infection known as species resistance is a result of
Answer:
Protection from infection known as species resistance is a result of both the absence of necessary receptors and lack of suitable environment in the body.
34. Which of the following types of nucleic acid is NOT a pyrimidine, a type of biomolecule, which makes up an organism’s genome?
a. Adenine
b. Uracil
c. Cytosine
d. Thyomine
Answer: a. Adenine
Explanation:
Two types of chemically similar nucleic acids, DNA (deoxyribonucleic acid) and RNA (ribonucleic acid), are the principal information-carrying molecules of the cell. The bases adenine, guanine, and cytosine are detected in both DNA and RNA while thymine is observed only in DNA, and uracil is located only in RNA. When it comes to defining the nucleic acid-based in the nature of its nitrogen- and carbon-containing ring structure we have the variation that answers the question. While b. Uracil, c. Cytosine, and d. Thymine only contains a single ring, which we call pyrimidines, the biomolecule a. Adenine contains a pair of fused rings that we call purines, the right answer for the question.
What are the possible reason for no colonies to grow on agarose plate?
How does inefficient ligation result in no colony growth on agarose plate?
Answer: Possible Reasons- Low concentration of DNA fragments, reaction volume more than 10μl, unequal concentration of control and experiment for transformation.
Incorrect ligation and poor ligase activity result in no colony growth on agarose plate.
Explanation:
Low concentration of DNA will not allow colonies to grow on agarose plate. Reaction volume must be less than 10μl. Different concentration of control and experiment will also affect growth of colonies.
Inefficient ligation result in no colony growth on agarose plate. This could be due to incorrect ligation between blunt and sticky ends. T4 DNA ligase joins the ends of DNA. Ligase poor activity will not allow colonies to grow on agarose plate.
You are told that the cells on a microscope slide are plant, animal, or bacterial. You look at them through a microscope and see cell walls and membrane-bound organelles. You conclude that the cells A) are plant cells. B) could be either plant or bacterial. C) are animal cells. D) could be plant, animal, or bacterial. E) are bacteria.
Answer:
A
Explanation:
I think it is A because of there being cell walls
A phenotypically normal prospective couple seeks genetic counseling because the man knows that he has a translocation of a portion of his chromosome 4, which has been exchanged with a portion of his chromosome 12. Although his translocation is balanced, he and his wife want to know the probability that his sperm will be abnormal. What is your prognosis regarding his sperm?
Final answer:
A translocation between chromosome 4 and chromosome 12 in the man's genetic makeup can affect his sperm by increasing the likelihood of producing abnormal sperm. Consulting with a genetic counselor is recommended to assess the specific risks and make informed decisions.
Explanation:
A translocation occurs when a portion of one chromosome breaks off and attaches to a different chromosome. In the case of the prospective couple, the man has a balanced translocation between chromosome 4 and chromosome 12. This means that the genetic material is exchanged between these two chromosomes without any material being lost or gained.
However, translocations can still affect fertility because they can cause problems during meiosis, the process of cell division that produces sperm and eggs. During meiosis, chromosomes need to pair up and separate properly to produce healthy gametes. In the case of a translocation, the rearrangement of genetic material can disrupt the pairing of chromosomes, leading to a higher likelihood of producing abnormal sperm or eggs.
Therefore, while the translocation itself may not cause any noticeable physical abnormalities in the man, there is a higher chance that his sperm might be abnormal due to the rearrangement of chromosomes. It is important for the couple to consult with a genetic counselor to assess the specific risks and make informed decisions about their reproductive options.