KHP has greater water solubility than fatty acids with long hydrocarbon chains due to its polar carboxylate anion that allows for strong hydrogen bonding with water, whereas fatty acids have a hydrophilic region that becomes less significant relative to the hydrophobic chain as the chain length increases, leading to decreased solubility.
Explanation:The solubility of potassium hydrogen phthalate (KHP) in water is greater than that of fatty acids with six or more carbons mainly due to the difference in the chemical structure and polarity of the molecules. KHP possesses a highly polar functional group (carboxylate anion) that can form strong hydrogen bonds with water molecules, whereas fatty acids have long hydrocarbon chains that exhibit a hydrophobic character and tend to be less soluble in polar solvents like water. As fatty acids increase in chain length, their solubility in water decreases because the proportion of the nonpolar, hydrophobic hydrocarbon chain relative to the polar carboxyl group becomes larger, resulting in weaker interactions with water molecules.
Fatty acids with long chains, such as those with more than eight carbons, are termed amphiphilic or amphipathic. These substances have both hydrophilic (water-attracting) and hydrophobic (water-repelling) regions, which makes them behave differently in water. For instance, fatty acids with ten or more carbon atoms are nearly insoluble in water but can form a monolayer on the water surface, displaying properties characteristic of surfactants.
The higher solubility of KHP in water compared to fatty acids with six or more carbons is due to its ionic nature and the larger proportion of hydrophobic regions in long-chain fatty acids which decrease their solubility.
The higher solubility of potassium hydrogen phthalate (KHP) in water compared to many fatty acids with six or more carbons is attributed to both its ionic nature and structural differences.
KHP is an ionic compound, meaning it dissociates into ions (potassium and hydrogen phthalate ions) in water.
These ions interact strongly with water molecules through ion-dipole interactions, facilitating its dissolution. In contrast, fatty acids remain as neutral molecules in water, lacking the strong electrostatic interactions that promote solubility.Additionally, KHP contains hydrophilic groups like the carboxylate group, which further enhance its solubility by forming hydrogen bonds with water molecules.
In contrast, the hydrophobic nature of fatty acids increases with longer carbon chains, leading to decreased solubility in water. The predominance of non-polar hydrocarbon chains in fatty acids reduces their ability to interact favorably with the polar solvent, further lowering their solubility.Therefore, the combination of KHP's ionic nature and its structural features that promote interactions with water molecules explains why it exhibits higher solubility in water compared to many fatty acids with longer carbon chains
Draw the two chair conformations of cis 1 chloro 2 methylcyclohexane
The two chair conformations of cis 1 chloro 2 methylcyclohexane are shown in the image attached.
Due to the cyclohexane ring's capacity for ring flipping, isopropyl chloro-2-methylcyclohexane displays two chair conformations. The methyl group is positioned equatorially in the first conformation, while the chlorine atom is located in the axial position.
The chlorine atom is in the equatorial position and the methyl group is in the axial position in the second conformation, which has the substituents arranged in reverse order. These conformations show the dynamic character of cyclohexane rings, where substituents can be positioned in either an axial or an equatorial orientation to minimize steric hindrance between them by ring flipping.
Describe how you would make 1.0 l of a supersaturated solution of cdi2
Final answer:
Creating a supersaturated solution of cadmium iodide involves dissolving as much solute as possible in water at an elevated temperature and then slowly cooling the solution to room temperature without disturbance.
Explanation:
To make 1.0 L of a supersaturated solution of cadmium iodide (CdI2), first a saturated solution must be prepared at a temperature higher than room temperature by dissolving as much CdI2 as possible. This can be done by gradually adding CdI2 to a liter of water with continuous stirring while heating the solution to increase the solubility. Once no more salt can dissolve, the solution is allowed to slowly cool to room temperature, making sure to avoid any disturbance that could cause premature crystallization. As the solution cools, it becomes supersaturated because the solubility of CdI2 decreases with temperature, allowing more solute to be contained in solution than is stable at the lower temperature.
If the solution remains undisturbed, the excess solute will stay dissolved, resulting in a supersaturated solution. However, any disturbance or addition of a seed crystal will cause the excess solute to precipitate out rapidly. Therefore, care must be taken to keep the solution free from dust and vibrations that can induce crystallization.
The rate constant for a second-order reaction is 0.54 m-1s-1. what is the half-life of this reaction if the initial concentration is 0.30 m?
The correct answer is: 6.173 seconds.
Explanation:
The formula for half life (of reaction) is:
Half-life = [tex]\frac{1}{K*I}[/tex] --- (A)
Where,
K = Rate constant = 0.54 [tex]\frac{1}{ms}[/tex]
I = Initial concentration = 0.30 m
Plug in the values in equation (A):
Half-life = [tex]\frac{1}{0.54*0.30} = 6.173[/tex]
Hence, the half life is 6.173 seconds.
The half-life of a second-order reaction is [tex]\boxed{{\text{6}}{\text{.173 seconds}}}[/tex]
Further explanation:
Second-order reaction:
A reaction is said to be of second-order if its rate is proportional to the square of the concentration of one reactant. The general example of second-order reaction is,
[tex]2{\text{A}}\to{\text{P}}[/tex]
Here,
A is the reactant.
P is the product.
The rate is calculated by using the following equation:
[tex]{\text{Rate}}={\text{k}}{\left[{\text{A}}\right]^2}[/tex]
Another form of second-order reaction is as follows:
[tex]{\text{A}}+{\text{B}}\to{\text{P}}[/tex]
Here,
A and B are the two different reactants.
P is the product.
The rate is calculated by using the following equation:
[tex]{\text{Rate}}={\text{k}}\left[{\text{A}}\right]\left[{\text{B}}\right][/tex]
Half-life:
Half-life is defined as the time required to reduce the concentration of reactant to half of its initial value. It is denoted by [tex]{{\text{t}}_{1/2}}[/tex] . The general expression to calculate [tex]{{\text{t}}_{1/2}}[/tex] of second-order reaction is,
[tex]{{\text{t}}_{1/2}}=\frac{1}{{{\text{k}}{{\left[{\text{A}}\right]}_{\text{0}}}}}[/tex] …… (1)
Here,
[tex]{{\text{t}}_{1/2}}[/tex] is the half-life of the reaction.
k is the rate constant for the reaction.
[tex]{\left[ {\text{A}}\right]_{\text{0}}}[/tex] is the initial concentration of the reactant.
The rate constant for the given reaction is [tex]0.54\;{{\text{M}}^{-1}}{{\text{s}}^{-1}}[/tex] .
The initial concentration of the given reaction is 0.30 M.
Substitute these values in equation (1).
[tex]\begin{aligned}{{\text{t}}_{1/2}}&=\frac{1}{{\left({0.54\;{{\text{M}}^{ - 1}}{{\text{s}}^{ - 1}}}\right)\left( {{\text{0}}{\text{.30 M}}}\right)}}\\&=\frac{1}{{0.162\;{{\text{s}}^{ - 1}}}}\\&=6.1728\;{\text{s}}\\&\approx 6.173\;{\text{s}}\\\end{aligned}[/tex]
So, the half-life of a second-order reaction is 6.173 seconds.
Learn more:
1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: https://brainly.com/question/3064603
2. Calculate the moles of ions in the solution: https://brainly.com/question/5950133
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Chemical Kinetics
Keywords: second-order reaction, half-life, initial, half, 6.173 seconds, 0.30 m, k, A0, A, B, P, 2A, reactant, product, t1/2.
A 15.0 kg chunk of ice falls off the top of an iceberg. If the chunk of ice falls 8.00m to to the surface of the water, what is the kinetic energy of the chunk of ice when it hits the water, and what is its velocity
When a stable diatomic molecule spontaneously forms from its atoms, what are the signs of δh°, δs°, and δg°?
The formation of a stable diatomic molecule from atoms typically results in a negative ">δH°<", a negative ">δS°<", and a negative ">δG°<". This reflects an exothermic reaction with decreased entropy, leading to spontaneity under the right temperature conditions.
When a stable diatomic molecule forms from its atoms, there are typical changes in enthalpy (">">δH°"), entropy (">">δS°"), and Gibbs free energy (">">δG°"). The formation of a stable molecule from atoms is typically exothermic, which means that energy is released, and ">">δH°" would be negative. As atoms come together to form a molecule, the system becomes more ordered, and thus, the change in entropy, ">δS°<", is negative.
According to the Gibbs free energy equation, ">δG° = δH° - TδS°<", and at a temperature (T) where this process is spontaneous, the sign of ">δG°<" would be negative because loss of heat (">">exothermic reaction") and orderliness in system (">">decreased entropy") favor the formation of the molecule.
What is the half-life (in seconds) of a zero-order reaction which has an initial reactant concentration of 0.884 M with a k value of 5.42 × 10–2 M/s?
Answer:
The half-life (in seconds) of a zero-order reaction is 8.15 seconds.
Explanation:
Initial concentration of the of the reactant = [tex][A_o]=0.884 M[/tex]
The value of rate constant = [tex]k=5.42\times 10^{-2} M/s[/tex]
The half life for zero order reaction is given as:
[tex]t-{\frac{1}{2}}=\frac{[A_o]}{2k}=\frac{0.884 M}{2\times 5.42\times 10^{-2} M/s}=8.15 s[/tex]
The half-life (in seconds) of a zero-order reaction is 8.15 seconds.
What is the structural formula of 2-methylbutan-2-ol (sometimes called 2-methyl-2-butanol)?
a solution is another name for
Answer:
A solution is another name for homogeneous mixture.
Explanation
Solution or homogeneous mixture are names for the classification of matter.
Matter is classified in 2 big groups: pure substances and mixtures.
Pure substances: are those that cannot be separated into more simple ones by physics methods, and are classified in compounds and elements.
Elements: these cannot be separated into more simple substances by chemical methods, e.g.: Au, Cu, Na, Cl, etc.Compounds: these are formed by two or more elements and can be separated into more simple substances by chemical methods, e.g: H₂O, CO₂, NaCl, etc.Mixtures: are those that can be separated into more simple ones by physics methods, and are classified in homogeneous and heterogeneous.
Homogeneous mixture (solution): has the same composition in the whole mixture and its components cannot be detected easily e.g: sugar dissolved in water.Heterogeneous mixture: has different compositions in the whole mixture and its components can be detected easily in different phases, e.g.: water and cooking oil.Match the formula for the following compound: iron (III) sulfate
FeSO4
Fe3SO4
Fe(SO4)3
Fe2(SO4)3
Answer:
D. Fe2(SO4)3
is the answer
Explanation:
Aluminum sulfate is formed when an aluminum cation that has a 3+ charge combines with a sulfate ion that has a 2- charge. Write the formula for the compound aluminum sulfate. Font Sizes
Answer : The formula for the compound aluminum sulfate is [tex]Al_2(SO_4)_3[/tex]
Explanation :
For formation of a neutral ionic compound, the charges on cation and anion must be balanced.
The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non-metals.
In the given question, the aluminum metal forms an ionic compound with polyatomic anion (sulfate) [tex]SO_4^{2-}[/tex].
Here, aluminum is having an oxidation state of +3 called as [tex]Al^{3+}[/tex] cation and sulfate [tex]SO_4^{2-}[/tex] is an anion with oxidation state of -2. The charges are not balanced. So, the charges are balanced by the cris-cross method. Thus, the compound formed will be, [tex]Al_2(SO_4)_3[/tex]
Hence, the formula for the compound aluminum sulfate is [tex]Al_2(SO_4)_3[/tex]
The formula for aluminum sulfate is Al₂(SO₄)₃. This is because two Al³+ ions balance three SO₄²⁻ ions to achieve electrical neutrality.
Explanation:The compound aluminum sulfate is formed when an aluminum cation (Al³+) combines with a sulfate ion (SO₄²⁻). Given that atoms strive to reach electrical neutrality, the formula for this ionic compound reflects the simplest ratio that can balance the positive and negative charges. In this case, two aluminum ions (2 x +3 for a total charge of +6) are needed to balance three sulfate ions (3 x -2 for a total charge of -6), resulting in the chemical formula Al₂(SO₄)₃.
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The process that changes a solid directly into a gas is called sublimation. A solid that begins with a mass of 450 g will sublime to give off a gas with a mass of _______ g.
Answer:
The answer is 450 g
Explanation:
When the solid sublimes, it gives the same mass of gas because sublimation is a physical change, and it is valid the energy and mass conservation law (mass cannot be destroyed or created in a chemical or physical process). If sublimation is complete, all the molecules changes its physical state from solid to gas.
Sublimation is the process where a solid changes directly into a gas without passing through the liquid phase. The mass of the substance remains unchanged, so a solid with a mass of 450 g will yield a gas with a mass of 450 g.
The process that changes a solid directly into a gas is called sublimation. In this process, a solid transitions to a gas phase without passing through the liquid phase. Importantly, the mass of the substance remains constant during this phase change. Therefore, if you start with a solid that has a mass of 450 g, the resulting gas will also have a mass of 450 g. This is in accordance with the law of conservation of mass which suggests that mass can neither be created nor be destroyed.
An example of sublimation occurs with dry ice (solid CO₂), which transitions directly from a solid to a gas at standard temperature and pressure.
Name the complex mncl2(en)2. the oxidation number of manganese is +2.
A fatty acid with 10 carbons will be absorbed via the
A sample of gas has a volume of 5.58 l at a pressure of 715 mm hg. what is the volume of the gas when the pressure of the gas is increased to 755 mm hg?
Balance the reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1." Pb(NO₃)₂ + NaI → PbI₂ + NaNO₃
Answer:
blank, 2, blank, 2
What was the resulting molarity of your primary standard solution of potassium iodate kio3?
How do chemical weathering and physical weathering affect each other?