A particle is moving in a straight line.at t second, it acceleration is (4-kt), where k is a constant. when t=6, the acceleration of a particle is zero determine its velocity as a function of time​

Answer:

1.yes

2.no

3.yes

4.no

5.yes

The type of energy belongs only in the Kinetic Energy category is thermal energy. The correct option is D.

The only type of energy that exclusively falls within the kinetic energy category is thermal energy. It stands for the energy generated from the movement of particles inside a substance, which produces temperature and heat.

Thermal energy is stored energy that directly corresponds to the movement of particles, causing them to vibrate and collide, as opposed to potential energy, which is stored energy based on an object's position or condition.

Depending on the situation, kinetic and potential components can be present in chemical, electromagnetic, mechanical, and nuclear energy.

In conclusion, because it has to do with particle motion and heat transfer, thermal energy is the only type of energy that specifically belongs to the kinetic energy category.

Thus, the correct option is D.

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Answer:

D. Newton's Third Law of Motion

Explanation:

Newton's law of gravity is definitely not applicable to your hands. So we can cross this bad boy out

Newton's First Law is F=MA (force equals mass times acceleration). This is basically the root of most physics but it isn't the reason for your hand being red after hitting a wall.

Newton's Second law deals with velocities and forces, so even though you are apply a force your are not changing the velocity of the wall much.

Newton's Third Law basically says that for whatever force you apply to an object, that object will apply an equal and opposite force back to you. This is why your hand gets red. When you slap the wall with all your strength, the wall hits your hand back with the same amount of force. The 2nd law can also be seen when you're trying to push a desk and it won't budge. You are pushing on it, but the desk is pushing back. (there are multiple other factors applicable like friction but we physicists like to ignore them :) )

I hope this helps!

Answer:

1- The lank with the least slope will be the easiest to climb because it will require the least force.

2- All three paths will require the same energy as the work done will be the same in all three cases.

Explanation:

1-  Work done W = Force x Displacement i.e. W = F × cosФ where 'Ф' is the angle between force and displacement. Smaller the angle least is the force required to climb. Hence the path with least slope will be easier to climb.

2- Since W = F × cosФ as the angle increase cos Ф decrease which means the slope is increase and consequently the force required also increases but the total work done remains the same. Hence the energy required to climb all three Lanks will be the same.

Answer:

In physical changes, substances might change in the form of the matter(the shape) but not in it's chemical composition.

Explanation:

The shape can change as well as the size and look but it's chemical composition does not change........which means a paper folded into a plane remains a paper and doesn't become anything else.

In chemical changes.......a wood burned changes to charcoal in this it's a new substance not the wood we burned.

The making of paper plane is a physical change and burning of wood is a chemical change. Chemical change gives new substance and is irreversible which means u can't get the wood back again. While physical changes don't give new substances and the plane can again be unfolded into a sheet of paper.

In physical changes, substances might change in form but not in chemical composition.

A physical change is a type of change in which the physical form of the substance is changed but not the chemical composition.

These physical changes affect the form of the chemical substance, but not the chemical composition.

Examples of physical changes;

Thus, we can conclude that in physical changes, substances might change in form but not in chemical composition.

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The final speed of the safe is 51.7 m/s

Explanation:

The motion of the safe is a free fall motion, which is a motion at constant acceleration ([tex]g=9.8 m/s^2[/tex], towards the ground). Therefore, we can apply the following suvat equation:

[tex]v^2-u^2=2as[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

In this problem we have (taking downward as positive direction):

u = 11.0 m/s

[tex]a=g=9.8 m/s^2[/tex]

[tex]s=1.3\cdot 10^2 m= 130 m[/tex] is the vertical displacement (the height of the building)

Solving for v, we find the final velocity (and so, the final speed):

[tex]v=\sqrt{u^2+2as}=\sqrt{11.0^2+2(9.8)(130)}=51.7 m/s[/tex]

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Answer:

The height of the cliff is, h = 78.4 m

Explanation:

Given,

The horizontal velocity of the projectile, Vx = 20 m/s

The range of the projectile, s = 80 m

The projectile projected from a height is given by the formula

                            S = Vx [Vy + √(Vy² + 2gh)] / g

Therefore,  

                            h = S²g/2Vx²

Substituting the values

                             h = 80² x 9.8/ (2 x 20²)

                                = 78.4 m

Hence, the height of the cliff is, h = 78.4 m

Answer:

The momentum of the object is, p = 400 kg m/s

Explanation:

Given data,

The mass of the object, m = 40 kg

The velocity of the object, v = 100 m/s

The momentum of the object is defined as the product of the object's mass and  its velocity. it is given by the formula,

                                     p = m v

Substituting the values,

                                     p = 40 kg x 100 m/s

                                         = 400 kg m/s

Hence, the momentum of the object is, p = 400 kg m/s

Answer:

The right answer is 160j

Dane is holding an 8 kg box 2 meters above the ground. The box's gravitational potential energy will be 160 joules.

The term gravitational potential energy refers to the energy that an item stores as a result of its elevation above the Earth's surface. This energy is a result of an object being subjected to gravity.

Potential energy is transformed into kinetic energy when a stone falling from a height impacts the earth's surface.

According to the question, the given values are :

Mass, m = 8 kg

Height, h = 2 meters above the ground and,

g = 10 N/kg

Gravitational potential energy = mgh

P = 8×10×2

P = 160 J.

Hence, gravitational potential energy is 160 J.

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Answer:

As the skydiver falls to the Earth, she experiences positive acceleration only due to gravity.

Explanation:

As the skydiver falls to the Earth, she experiences friction in the form of air resistance which tries to slow her down and is proportional to the her velocity. So it cannot have a positive acceleration as it acts in opposite direction to slow her down.

Inertia during skydiving is experienced when we open an parachute, the parachute slows down the speed of are descent hence changing our inertia of motion with a velocity.

Only the Earth's, gravitational field has an positive acceleration as it pulls us towards the Earth, hence increasing our velocity.

Answer: This is a single displacement reaction and the products are zinc chloride and hydrogen gas.

Explanation:

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

[tex]AB+C\rightarrow CB+A[/tex]

Element C is more reactive than element A.

Double displacement reaction is defined as the reaction in which exchange of ions takes place.

[tex]AB+CD\rightarrow CB+AD[/tex]

Synthesis reaction is defined as the reaction in which smaller substances combine in their elemental state to form a larger substance.

[tex]A+B\rightarrow AB[/tex]

Decomposition reaction is defined as the reaction in which a large substance breaks down into smaller substances.

[tex]AB\rightarrow A+B[/tex]

For the given chemical reaction:

[tex]Zn(s)+2HCl(aq.)\rightarrow ZnCl_2(aq.)+H_2(g)[/tex]

The reaction is considered as single displacement reaction.

By Stoichiometry of the reaction:

1 mole of zinc metal reacts with 2 moles of hydrochloric acid to produce 1 mole of zinc chloride and 1 mole of hydrogen gas.

Hence, this is a single displacement reaction and the products are zinc chloride and hydrogen gas.

The resistance of the lightbulb connected to a 60 Hz power source and using an average power of 38.8 W, with a maximum voltage of 156 V, is approximately 312.4 Ω.

To find the resistance of the lightbulb, we must first establish the effective value of the voltage, since the given voltage is the maximal one. For sinusoidal alternating currents (like the standard electrical supply), the effective or 'root mean square' voltage is the maximum voltage divided by the square root of 2 (approximately 1.414). So, the effective voltage (Vrms) is 156 V / √2 = 110.3 V.

Next, we use the formula for power P = V^2 / R, where V is the effective (rms) voltage and R is the resistance. Looking for R, we rearrange the equation to get R = V^2 / P. Substituting the given values we get R = (110.3 V)^2 / 38.8 W = 312.4 Ω. Therefore, the resistance of the light bulb is approximately 312.4 Ω.

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The resistance of a light bulb is approximately 313.57 Ω. This is calculated by converting maximum voltage to RMS voltage and applying the power formula P = V²/R.

To solve this, we need to follow these steps:

First, convert the maximum voltage (Vmax) to the root mean square (RMS) voltage (Vrms) using the formula [tex]V_{rms} = V_{max} / \sqrt2[/tex]. So, [tex]V_{rms} = 156 V / \sqrt2 = 110.3 V[/tex]

Use the power formula that relates power (P), voltage (V), and resistance (R):
[tex]P = V_{rms}^2 / R[/tex]
Rearrange it to solve for resistance (R):
[tex]R = V_{rms}^2 / P[/tex]

Substitute the values:
R = (110.3 V)² / 38.8 W
R ≈ 313.57 Ω

Thus, the resistance of the light bulb is approximately 313.57 Ω.

Answer: d

Explanation: Unscrew one light, if the others remain on it is a parallel circuit.

The energy stored in a spring is

E = 1/2 (k x²)

' k ' is the spring constant . . . the number of newtons of force it takes to stretch or compress the spring by one meter from its relaxed length

' x ' is the distance the spring is stretched or compressed

For this problem, we know ' E ' and ' x ', and we need to find ' k '.

E = 1/2 (k x²)

1,000 = 1/2 (k) (0.025²)

1,000 = 1/2 (k) (0.000625)

Multiply each side by 2 :  

2,000 = (k) (0.000625)

Divide each side by 0.000625:

(2,000) / (0.000625) = k

k = 3,200,000

The spring constant is 3.2 x 10⁶ Newtons per meter .

This is a very stiff spring !  My calculator says that if you want to stretch it just 1 inch, you have to pull it with a force of 18,285 pounds ! !  If such a spring exists, it might be used as part of the suspension for a tank or a concrete truck.

The spring constant of the given spring is equal to  3.2 × 10⁶ N/m.

Hooke's law can be explained as a law that states that the force (F) needed to extend or compress a spring by distance linearly with respect to that distance along a straight line.

The spring force can be expressed in the form of an equation:

F = -kx,

where k is a spring constant and x  is the possible deformation of the spring. The negative sign indicates that the spring will return to its original shape or position.

The energy stored in the spring when it is compressed is given by:

E = (1/2)kx²

Given, the energy stored in the spring when it is compressed, E = 1000J

The distance by which spring is compressed, x = 2.5 cm = 0.025 m

1000 =  (1/2)×k (0.025)²

k = 3.2 × 10⁶N/m

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46.67 m/s²

We are given;

we are supposed to calculate the acceleration of the rocket;

Therefore;

F = Ma

In this case;

Rearranging the formula

a = F ÷ m

  = 140 N ÷ 3 kg

  = 46.67 m/s²

Thus, the acceleration of the rocket is 46.67 m/s²

Answer:

No, the Sunlight won't get extinct.

Explanation:

It is not true as the sun will not be extinct due to the usage of sunlight by all the living creatures but definitely due to the climatic conditions and several bad activities of humans. It would become extinct or become a red big giant that would destroy the planet.

Scientists have estimated the life on the planet that is 1.5 billion years. Earth would get destroyed much prior to sun. After 7.5 billion years, sun would turn out to be as large as a big giant.

These are the reasons why sun will get extinct but not because of its usage.

The velocity of the brick is 39.2 m/s downward

Explanation:

The motion of the brick is a free fall motion, since the object is affected only by the force of gravity. Therefore, it has a uniformly accelerated motion towards the ground, with constant acceleration of [tex]g=9.8 m/s^2[/tex].

So, we can find its velocity using the suvat equation:

[tex]v=u+at[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

For the brick in this problem (taking downward as positive direction)

u = 0 (it is dropped from rest)

[tex]a=g=9.8 m/s^2[/tex]

Therefore, its velocity after t = 4.0 s is:

[tex]v=0+(9.8)(4.0)=39.2 m/s[/tex]

Downward, because the sign is positive.

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Answer:

A.28.52

B.3.52

C.35.55

D.10.55

just guessed and got it right lol

Answer:

A.28.52,   B.3.52,   C.35.55,  D.10.55

Explanation:

a) The net force on the system is 883.5 N

b) The tension in the rope is 505.5 N

c) The applied force on the snowmobile is 1875.7 N

Explanation:

a)

To solve this first part, we just analyze all the forces acting in the horizontal direction on the snowmobile+sled system, and we apply Newton's second law, which states that:

[tex]\sum F = (m+M)a[/tex]

where

[tex]\sum F[/tex] is the net force on the system

m = 150 kg is the mass of the sled

M = 315 kg is the mass of the snowmobile+rider

[tex]a=1.9 m/s^2[/tex] is the acceleration

Therefore, solving for [tex]\sum F[/tex], we find the net force on the system:

[tex]\sum F = (150+315)(1.9)=883.5 N[/tex]

b)

We can write now the equation of the forces acting on the sled only. We have:

[tex]T-F_f = ma[/tex]

where:

T is the tension in the rope between the sled and the snowmobile, which is pulling the sled forward

[tex]F_f[/tex] is the force of friction acting on the sled

m = 150 kg is the mass of the sled

[tex]a=1.9 m/s^2[/tex] is the acceleration

The force of friction can be written as

[tex]F_f = \mu_k mg[/tex]

where

[tex]\mu_k = 0.15[/tex] is the coefficient of kinetic friction of the sled on ice

Substituting into the previous equation and solving for T, we find the tension:

[tex]T-\mu_k mg = ma\\T=ma+\mu_k mg=(150)(1.9)+(0.15)(150)(9.8)=505.5 N[/tex]

c)

We can now write the equation of the forces acting on the snowmobile, and we have:

[tex]F_a - T - F_F = Ma[/tex]

where:

[tex]F_a[/tex] is the applied force

T = 505.5 N is the tension in the rope, which pulls the snowmobile backward

[tex]F_F[/tex] is the force of friction on the snowmobile

M = 315 kg is the mass of the snowmobile+rider

[tex]a=1.9 m/s^2[/tex] is the acceleration

The force of friction can be written as

[tex]F_F = \mu_k Mg[/tex]

where

[tex]\mu_k = 0.25[/tex] is the coefficient of kinetic friction of the snowmobile on ice

Substituting into the previous equation and solving for [tex]F_a[/tex], we find:

[tex]F_a = Ma+T+\mu_k Mg=(315)(1.9)+505.5+(0.25)(315)(9.8)=1875.7 N[/tex]

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Answer:

Not combustion

Explanation:

I just took a test and got it wrong

The answer is Decomposition

Thank god the answer was removed

I got it correct

The length of the side of the cube is 4 cm

Explanation:

The density of the cube is given by:

[tex]\rho=\frac{m}{V}[/tex]

where

m is the mass of the cube

V is its volume

Also, the volume of the cube is given by

[tex]V=L^3[/tex] (2)

where L is the length of each side.

For the cube in this problem we have:

m = 128 g

[tex]\rho=2 g/cm^3[/tex]

From the first equation, we find the volume of the cube:

[tex]V=\frac{m}{\rho}=\frac{128}{2}=64 cm^3[/tex]

And now we use eq.(2) to find the length of the side:

[tex]L=\sqrt[3]{V}=\sqrt[3]{64}=4 cm[/tex]

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The length of each side of a cube with a mass of 128 grams and a density of 2 grams per cubic centimeter is 4 centimeters.

To find the length of each side of a cube with a mass of 128 grams and a density of 2 grams per cubic centimeter, we can use the formula for density which is mass divided by volume. Since density is given in grams per cubic centimeter (g/cm3), we'll keep the mass in grams and calculate the volume in cubic centimeters. First, we calculate the volume of the cube by dividing the mass by the density (Volume = Mass / Density).

Volume = 128g / 2g/cm3 = 64 cm3

Because the volume of a cube is also the cubic of the length of its side (Volume = side3), we can now find the length of one side by taking the cube root of the volume.

Length of one side = \3\sqrt{64 cm3} = 4 cm

Therefore, each side of the cube is 4 centimeters in length.

The acceleration of gravity on the surface of Pluto is [tex]0.61 m/s^2[/tex]

Explanation:

The acceleration of gravity at the surface of a planet is given by the equation:

[tex]g=\frac{GM}{R^2}[/tex]

where

[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant

M is the mass of the planet

R is the radius of the planet

For Pluto, we have:

[tex]M=1.30\cdot 10^{22} kg[/tex] is the mass

[tex]R=1,188 km = 1.188\cdot 10^6 m[/tex] is the radius

Substituting, we find its gravitational acceleration:

[tex]g=\frac{(6.67\cdot 10^{-11})(1.30\cdot 10^{22})}{(1.188\cdot 10^6)^2}=0.61 m/s^2[/tex]

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The specific heat capacity of concrete is [tex]3.0 J/(g^{\circ}C)[/tex]

Explanation:

When a certain amount of energy Q is supplied/given off to/from a sample of substance with mass m, the temperature of the substance increases/decreases by an amount [tex]\Delta T[/tex], according to the equation

[tex]Q=mC_s \Delta T[/tex]

where

m is the mass of the substance

[tex]C_s[/tex] is the specific heat capacity of the substance

[tex]\Delta T[/tex] is the change in temperature of the substance

In this problem, we have:

m = 1 kg = 1000 g is the mass of the concrete slab

[tex]Q = -12,000 J[/tex] is the amount of energy lost by the slab

[tex]\Delta T = 30-26= -4^{\circ}C[/tex] is the change in temperature of the slab

Solving the equation for [tex]C_s[/tex], we find the specific heat capacity of concrete:

[tex]C_s = \frac{Q}{m \Delta T}=\frac{-12,000}{(1000)(-4)}=3.0 J/(g^{\circ}C)[/tex]

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Final answer:

The specific heat capacity of concrete is calculated using the heat transfer formula Q = mcΔT, and the given values of 1 kg mass, a temperature change of 4°C, and a heat loss of 12,000 J. The specific heat capacity is found to be 3,000 J/kg/°C.

Explanation:

To determine the specific heat capacity of concrete, we start by using the formula for heat transfer:

Q = mcΔT

where Q is the heat energy transferred (in joules, J), m is the mass (in kilograms, kg), c is the specific heat capacity (in J/kg/°C), and ΔT is the change in temperature (in °C). In this scenario, we are given that a 1kg slab of concrete loses 12,000J of heat when it cools from 30°C to 26°C.

The change in temperature (ΔT) is the final temperature minus the initial temperature, that's 26°C - 30°C = -4°C. We are solving for c, the specific heat capacity of concrete. It is possible to solve for c by rearranging the heat transfer equation:

c = Q / (mΔT)

We substitute the known values into this equation:

c = 12,000 J / (1 kg × -4°C)

c = 12,000 J / -4 kg°C

c = -3,000 J/kg/°C

The negative sign indicates that the concrete is losing heat, however, the specific heat capacity is a positive value. Therefore, the specific heat capacity of concrete is 3,000 J/kg/°C.

A force is described by its magnitude and direction.

Force is described in physics by its magnitude, which is the size or amount of the force, and its direction, which is where the force is heading.

In physics, force is described in terms of its magnitude and direction. Magnitude refers to the size or quantity of the force. It's measured in units like newtons. Direction, on the other hand, tells us where the force is heading or pointing to. For example, if you are pushing a box, the magnitude of the force would be how hard you are pushing and the direction would be the direction in which the box moves.

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The velocity of the rocket is 7.8 m/s

Explanation:

We can solve the problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the rocket+fuel system must be conserved.

Before the launch, the total momentum of the system is zero, since the rocket and the fuel are at rest:

[tex]p=0[/tex]

After the launch, the total momentum is

[tex]p=MV+mv[/tex]

where

M = 4.0 kg is the mass of the rocket

V is the velocity of the rocket

m = 50.0 g = 0.050 kg is the mass of the fuel ejected

v = -625 m/s is the velocity of the fuel (taking "backward" as negative direction)

Since the total momentum is conserved, we have

[tex]0=MV+mv[/tex]

So we can solve the equation to find V, the velocity of the rocket:

[tex]V=-\frac{mv}{M}=-\frac{(0.050)(625)}{4.0}=+7.8 m/s[/tex]

And the positive sign means the rocket moves forward.

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The velocity of the rocket after the fuel has burned is 7.81 m/s.          

From law of conservation of Momentum,

                         [tex]MV=mv[/tex]

Where M is mass of rocket and V is velocity of rocket

And m is mass of burned fuel and v is speed of fuel.

Given that, [tex]M=4Kg,m=50g=0.05Kg,v=625m/s[/tex]

Substitute values in above equation,

                  [tex]4*V=0.05*625\\\\V=\frac{0.05*625}{4} =7.81m/s[/tex]

Hence, the velocity of the rocket after the fuel has burned is 7.81 m/s.              

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Answer:

The kinetic energy

Explanation:

The potential energy (P) is the energy that the swing has due to its position, and it can be calculated with the expression

P = m . g . h

where,

m: mass

g: gravity

h: height

The higher is the swing, the more potential energy it has.

On the other hand, the kinetic energy (K) is the energy which a body possesses by virtue of being in motion, and it can be calculated using the expression

K = 1/2 . m . v²

where

v: speed

In B, the swing is virtually still (v = 0), while in A, v is maximum and so is its kinetic energy.

Then, as the swing moves from point B to point A, the kinetic energy increases and the potential energy decreases.

Because the action and the reaction forces act on different objects

Explanation:

Newton's third law of motion states that:

"When an object A exerts a force on an object B (action), then object B exerts an equal and opposite force (reaction) on object A"

From the statement above, we clearly see that the two forces mentioned in the law act on different objects. In fact, the action is exerted on object B, while the reaction is exerted on object A.

When we are considering the free-body diagram of an object, we just represent all the forces acting on that object, but not the forces exerted on other objects: this means that the action and the reaction never appear in the same free-body diagram of the same object, so they do not cancel out, simply because they are applied to different objects.

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Answer:

The potential energy is related to the mass and height of the object from the ground and to the acceleration due to gravity g, by the expression, PE = m g h. Thus, PE = 65 kg × 8800 m × 9.8 m/s² = 5.6 × 10⁶ Joules. Therefore, the potential energy of the climber will be 5.6 × 10⁶ Joules.

Explanation:

a) The net force on the system is 883.5 N

b) The tension in the rope is 505.5 N

c) The applied force is 1875.8 N

Explanation:

a)

We start by considering the whole system snowmobile+sled. We can apply Newton's second law:

[tex]\sum F = (m+M)a[/tex]

where

[tex]\sum F[/tex] is the net force on the system

m = 150 kg is the mass of the sled

M = 315 kg is the mass of the snowmobile+rider

[tex]a=1.9 m/s^2[/tex] is the acceleration

Substiting the values into the equation, we find the net force:

[tex]\sum F=(150+315)(1.9)=883.5 N[/tex]

b)

Now we consider only the forces acting on the sled. Again, we apply Newton's second law:

[tex]T-F_f = ma[/tex]

where:

T is the tension in the rope, which pulls the sled forward

[tex]F_f[/tex] is the frictional force acting on the sled, which acts backward

m = 150 kg is the mass of the sled

[tex]a=1.9 m/s^2[/tex] is the acceleration

The force of friction on the sled is given by

[tex]F_f = \mu mg[/tex]

where

[tex]\mu=0.15[/tex] is the coefficient of friction of the sled on ice

m = 150 kg

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

Substituting and solving for T, we find:

[tex]T-\mu mg = ma\\T=m(a+\mu g)=(150)(1.9+0.15 \cdot 9.8)=505.5 N[/tex]

c)

Now we consider instead the forces acting on the snowmobile+rider only. Applying again Newton's second law,

[tex]F-F_F-T = Ma[/tex]

where

F is the applied force, which pushes the snowmobile forward

[tex]F_F[/tex] is the force of friction acting backward on the snowmobile

T = 505.5 N is the tension in the rope, which pulls the snowmobile backward

M = 315 kg is the mass of the snowmobile+rider

[tex]a=1.9 m/s^2[/tex] is the acceleration

The force of friction on the snowmobile is given by

[tex]F_F = \mu Mg[/tex]

where

[tex]\mu=0.25[/tex] is the coefficient of friction of the snowmobile on ice

m = 315 kg

[tex]g=9.8 m/s^2[/tex]

Substituting and solving for F, we find the applied force:

[tex]F=Ma+\mu Mg+T=(315)(1.9)+(0.25)(315)(9.8)+505.5=1875.8 N[/tex]

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Answer:

D) a = 4m/s2

Explanation:

[tex]f = ma \\ a = \frac{f}{m} \\ a = \frac{8}{2} \\ a = 4[/tex]

where f = 8N and mass = 2kg

If you exert a net force of 8 N on a 2-kg object, the acceleration of the object would be [tex]4 m / s^{2}[/tex].

Answer: Option D

Explanation:

According to Newton second law, it states the relation between mass and the force required to accelerate the object. The mathematical expression can be given as follows,

               [tex]\text {Force}=\text {mass} \times \text {accelaration}[/tex]

The above expression shows that exerted force is equal to the product of mass and acceleration.

Where, in the given problem given the data as,

Force, F= 8 N

Mass, m = 2 kg

So, we can write the above equation as,

               [tex]\text {Acceleration, } a=\frac{F}{m}[/tex]

By substituting the given values in the above equation, we get,

          [tex]\text {acceleration, } a=\frac{8}{2}=4 \mathrm{m} / \mathrm{s}^{2}[/tex]

Therefore, the acceleration of the object would be [tex]4 m / s^{2}[/tex].